is one producer still dominant(takes over) over the other producer in part B? How do you know?

When a carbon nucleus is moved from the negative terminal of a 9 V battery to the positive terminal, 5.4 × 10^-14 J of work is required, and the work is positive.

In physics, work is the process of moving an object in the direction of an applied force when the force is applied to the object. When an applied force causes an object to move in the direction of the force, work is done on the object. Work, on the other hand, is measured in Joules, which is the same as force times distance.

To move a carbon nucleus from the negative terminal to the positive terminal of a 9 V battery, a certain amount of work is needed. The work done in this situation is positive because the direction of motion and the applied force are the same.

The formula for work is as follows:
W = F * d
Where
W is the work done,
F is the applied force, and
d is the distance traveled by the object.

The carbon nucleus is moved from one terminal of the battery to the other in this situation, and the force acting on it is the potential difference, V, of the battery.

To compute the work done, substitute the values into the equation:

W = V * q
The amount of work done, W, is proportional to the potential difference, V, and the charge, q, in this case, which is the charge of the carbon nucleus (Z = 6) converted to Coulombs.

The value of the potential difference in the equation is 9 V. The charge of the carbon nucleus in Coulombs is:
q = (6.02 × 10^23) * (1.6 × 10^-19) = 9.632 × 10^-16 C

The work done in moving a carbon nucleus from the negative terminal of a 9 V battery to the positive terminal is:
W = V * qW = 9 V * 9.632 × 10^-16 C = 5.4 × 10^-14 J

Therefore, the amount of work required to move a carbon nucleus from the negative terminal to the positive terminal of a 9 V battery is 5.4 × 10^-14 J, and the work done is positive.

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300 mL of a 2.0 M sodium hydroxide solution contain 0.6 molecules of sodium hydroxide.

To calculate the number of moles of sodium hydroxide present in 300 ml of a 2.0 M solution of sodium hydroxide, we can use the formula:

moles = concentration (M) x volume (L)

First, we need to convert the volume from milliliters to liters, since the concentration is given in units of Molarity (moles per liter):

Volume = 300 mL = 300/1000 L = 0.3 L

Now we can use the formula to calculate the number of moles of sodium hydroxide:

moles = 2.0 M x 0.3 L = 0.6 moles

Therefore, there are 0.6 moles of sodium hydroxide present in 300 mL of a 2.0 M solution of sodium hydroxide.

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Explanation:

The volume of NO₂ produced is 18.0 liters.

The balanced chemical equation for the reaction of nitrogen oxide (NO) with oxygen (O₂) to form nitrogen dioxide (NO₂) is:

2 NO + O₂→ 2 NO₂

From the balanced equation, we see that for every 2 moles of NO reacted, 2 moles of NO₂ are produced.

At STP (standard temperature and pressure), one mole of any gas occupies a volume of 22.4 liters. Therefore, the number of moles of NO present in 9.0 liters of NO can be calculated as:

n(NO) = V(NO) / V(molar) = 9.0 L / 22.4 L/mol = 0.402 mol NO

According to the balanced equation, 2 moles of NO will produce 2 moles of NO₂, so the number of moles of NO₂ produced is:

n(NO₂) = 2 × n(NO) = 2 × 0.402 mol = 0.804 mol NO₂

The volume of NO₂ produced can be calculated using the volume of one mole of any gas at STP:

V(NO₂) = n(NO₂) × V(molar) = 0.804 mol × 22.4 L/mol = 18.0 L

Therefore, the volume of NO₂ produced is 18.0 liters.

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339 mL of 8.50 × 10−2 M NaOH is required to titrate 55.0 mL of a solution containing 1.80 g of HCl per liter to the equivalence point.

Milliliters required to titrate are:

Part A: Let us calculate the number of moles of HNO3 using the formula:

moles HNO3 = Molarity × Volume (in liters)

moles HNO3 = 9.00 × 10−2 mol/L × 45.0 mL × 1 L/1000 mL

moles HNO3 = 0.0405 mol

Now, using the balanced equation of the reaction:

HNO3 + NaOH → NaNO3 + H2O1 mole of HNO3 reacts with 1 mole of NaOH.

Hence, the number of moles of NaOH required is the same as that of HNO3.

The volume of NaOH is calculated using the formula:

Volume of NaOH = moles NaOH/Molarity

NaOHVolume of NaOH = 0.0405 mol/8.50 × 10−2 mol/L = 0.476 L = 476 mL ≈ 480 mL

Therefore, 480 mL of 8.50 × 10−2 M

NaOH is required to titrate 45.0 mL of 9.00 × 10−2 M HNO3 to the equivalence point.

Part C: 55.0 mL of a solution containing 1.80 g of HCl per liter V = ?Let us calculate the number of moles of HCl:

Mass of HCl = concentration × volume × molar mass

Mass of HCl = 1.80 g/L × 55.0 mL/1000 mL × 1 mol/36.46 g

Mass of HCl = 0.0288 mol HCl reacts with NaOH in a 1:1 mole ratio.

Hence, the number of moles of NaOH required is also 0.0288 moles. The volume of NaOH is calculated using the formula:

Volume of NaOH = moles NaOH/MolarityNaOH

Volume of NaOH = 0.0288 mol/8.50 × 10−2 mol/L = 0.339 L = 339 mL.

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The statement is false. Sodium chloride (NaCl) does truly exist in the ocean. In fact, NaCl is the most abundant salt in seawater, making up approximately 85% of all dissolved salts.

The salt in seawater comes from the weathering of rocks on land, which release ions into rivers and ultimately into the ocean. As seawater evaporates, the concentration of NaCl and other salts increases, leading to the formation of salt deposits. Therefore, sodium chloride does truly exist in the ocean.

Sodium chloride (NaCl) is a compound, which means it is a combination of two or more elements. Sodium and chlorine are the two elements that make up sodium chloride. It's also known as table salt or simply salt.

NaCl, or table salt, is present in the oceans, lakes, and other natural bodies of water. It is discovered in huge quantities in seawater, which is roughly 3.5% salt by weight. It's also found in salt deposits underground or in shallow mining operations.

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The energy required to change 2.6 g of liquid water to steam if the water is already at 100°C is 5.85 kJ

First, we need to convert the given mass of water from grams to moles by dividing it by the molar mass of water.

The molar mass of water is approximately 18.02 g/mol, so:

number of moles of water = 2.6 g ÷ 18.02 g/mol ≈ 0.144 moles

We can use the formula:

ΔHvap = n * Hvap

where ΔHvap is the heat of vaporization, n is the number of moles of water, and Hvap is the molar heat of vaporization for water.

Plugging in the values we have:

ΔHvap = 0.144 mol * 40.6 kJ/mol

ΔHvap = 5.85 kJ

So, it requires 5.85 kJ of energy to change 2.6 g of liquid water to steam at 100°C.

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The limiting reactant is Hydrochloric acid since it produces less Hydrogen than Zinc can. As there is still excess Zinc after all the Hydrochloric acid has reacted, the mass value is negative. There would be a hydrogen output of 0.138 g.

Hydrogen gas and zinc chloride are produced quickly by the reaction of zinc with hydrochloric acid. In a single displacement reaction, zinc metal displaces hydrogen to produce zinc chloride and hydrogen gas.

a) According to the chemical equation, 1 mole of zinc combines with 2 moles of Hydrochloric acid to create 1 mole of hydrogen. We can therefore employ the following stoichiometric ratios:

1 mole Zinc reacts with 2 moles Hydrochloric acid to produce 1 mole Hydrogen

Molar mass of Zinc = 65.38 g/mol

Molar mass of Hydrochloric acid = 36.46 g/mol

Using the given masses:

Number of moles of Zinc = 6.5 g / 65.38 g/mol = 0.0993 mol

Number of moles of Hydrochloric acid = 5.0 g / 36.46 g/mol = 0.137 mol

If Zinc is the limiting reactant, it can produce 0.0993 mol of Hydrogen.

If Hydrochloric acid is the limiting reactant, it can produce 0.0685 mol of Hydrogen.

b) The amount of Hydrochloric acid that reacted with Zinc can be calculated as follows:

Number of moles of Hydrochloric acid used = 2 × number of moles of Zinc used = 2 × 0.0993 mol = 0.1986 mol

Mass of Hydrochloric acid used = number of moles of Hydrochloric acid used × molar mass of Hydrochloric acid = 0.1986 mol × 36.46 g/mol = 7.24 g

The amount of unreacted Hydrochloric acid is the initial amount of Hydrochloric acid minus the amount of Hydrochloric acid used:

Mass of unreacted Hydrochloric acid = 5.0 g - 7.24 g = -2.24 g

c) The number of moles of Hydrogen produced can be calculated from the limiting reactant:

Number of moles of Hydrogen = 0.0685 mol

The mass of Hydrogen produced can be calculated as follows:

Mass of Hydrogen = number of moles of Hydrogen × molar mass of Hydrogen = 0.0685 mol × 2.016 g/mol = 0.138 g

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Answer:

1. The value of the equilibrium constant (K) at E2 would be lower than the value at E1. This is because according to Le Chatelier's Principle, when a system at equilibrium is subjected to a change in temperature, the system will shift in the direction that opposes the change in temperature. In this case, decreasing the temperature would cause the system to shift towards the reactants side in order to increase the temperature, which would result in a decrease in the concentration of the products and an increase in the concentration of the reactants. As a result, the value of the equilibrium constant would decrease.

2. According to collision theory, the rate of a chemical reaction is dependent on the frequency and energy of collisions between the reactant molecules. When the temperature of a system is decreased, the average kinetic energy of the molecules decreases, resulting in a decrease in the frequency of collisions between the reactant molecules. As a result, the rate of both the forward and reverse reactions would decrease from T1 to E2. However, since the reverse reaction involves the breaking of a bond, which requires more energy than the formation of a bond, the decrease in the rate of the reverse reaction would be greater than the decrease in the rate of the forward reaction. Therefore, the system would shift towards the reactants side to establish a new equilibrium, resulting in a decrease in the concentration of the products and an increase in the concentration of the reactants.

Explanation:

The point at which the reaction is observed to be complete, i.e. the indicator changes color is called end point. The term “end point” refers to the point at which the titration reaction is deemed to have concluded. It is the point at which a titration reaction has been neutralized completely.

At this point, the reaction's equivalence point is reached, and no more titrant is needed to complete the reaction. Titration is a technique used in analytical chemistry to quantify the concentration of a known reactant (the titrant) in a given sample. A known volume of a titrant solution of known concentration is added to the sample until the reaction is complete, at which point the endpoint is reached.The endpoint is determined by adding an indicator to the sample, which changes color when the titration is complete. As a result, it's simple to keep track of when the reaction has finished.The endpoint in a titration is usually identified by observing a colour change. Indicators are utilized to determine the endpoint in most titrations, which is when the color change occurs. The end point is defined as the point at which the indicator changes color, indicating that the titration has been completed.

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The slower-moving water molecules are hit by the faster-moving metal atoms when the hot metal washers are submerged in the room-temperature water, which causes the water molecules to travel a little more quickly.

The heat source is employed to convert liquid water to vapour, which is the cause. Latent heat of vaporisation is the name given to this heat.

Even if heat is continuously applied, the temperature doesn't change during boiling because all of the heat energy is expended in converting the liquid state of the water to the gaseous water vapour.

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Because the concentration of the reactants diminishes over time, the rate at which hydrogen gas is produced when zinc interacts with hydrochloric acid also does.

Hydrogen gas and zinc chloride are produced quickly by the reaction of zinc with hydrochloric acid. In a single displacement reaction, zinc metal displaces hydrogen to produce zinc chloride and hydrogen gas. Because the process is exothermic, a lot of heat is produced: Zn (s) + 2HCl ZnCl2 H2 (g)

Zinc granules are favoured over pure zinc for the laboratory synthesis of hydrogen gas due to the sluggish rate of reaction between the two substances.

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In an equilibrium diagram, liquidus and solidus curves are important for understanding the temperature range at which a substance is completely liquid or completely solid.

This is because these curves represent the boundaries between the solid and liquid phases of a substance.

The liquidus curve represents the temperature above which a substance is completely liquid, while the solidus curve represents the temperature below which a substance is completely solid.

The region between these two curves is known as the mushy zone or the pasty state, where a substance is partially solid and partially liquid.

In addition to indicating the temperature range at which a substance is completely liquid or solid, the liquidus and solidus curves can also provide information about the composition of the substance.

This is because the location of these curves can vary depending on the composition of the substance.

For example, the solidus curve may shift to a lower temperature if the substance has a higher concentration of impurities.

Overall, understanding the liquidus and solidus curves in an equilibrium diagram is important for predicting the behavior of substances under different conditions and for determining the composition of a substance.

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The statement "Nuclear fusion begins when a large, unstable nucleus is bombarded with a smaller particle" does not provide more information about nuclear fusion.

Nuclear fusion is a process in which two atomic nuclei come together to form a heavier nucleus. This process releases a tremendous amount of energy. The fusion process occurs at extremely high temperatures and pressures, similar to those found in the core of stars.

The other statements provide important information about the source of energy in our Sun, the environmental advantages of nuclear fusion over fossil fuel combustion, and the role of nuclear fusion in the formation of elements in the periodic table.

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Image transcribed:

4 ¹H --->1 ⁴He + energy-    

Nuclear fusion, like the example here, produces huge amounts of energy. Consider the statements below. Which ONE statement DOES NOT provide more information about nuclear fusion?

Nuclear fusion is the source of energy in our Sun.

Nuclear fusion when used as an energy source does not produce particulate matter pollution like fossil fuel combustion.

Nuclear fusion begins when a large, unstable nucleus is bombarded with a smaller particle.

Nuclear fusion is responsible for the formation of the elements we classify in the periodic table.

The mobile phase of GC is a d) liquid different solvents.

Gas chromatography is a method of separating and analyzing samples that distributes them between two phases. These phases are a stationary phase and a mobile phase. The stationary phase is a microscopic layer of liquid or polymer on an inert solid support, inside a length of glass or metal tubing called a column. The mobile phase is a pure substance, typically an inert gas like helium, that carries the sample through the column.

GC is a method used to separate and analyze samples that distributes them between two phases. These phases are a stationary phase and a mobile phase. The stationary phase is a microscopic layer of liquid or polymer on an inert solid support, inside a length of glass or metal tubing called a column. The mobile phase is a pure substance, typically an inert gas like helium, that carries the sample through the column. GC is used to identify, quantify, and even purify individual components of mixtures.

Therefore, the correct answer is option (d) liquid different solvents.

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CaCO3 + 2NaCl → CaCl2 + Na2CO3, this is a double displacement reaction.

Type of chemical reaction in which reactant ions exchange places to form new products is called as double displacement reaction.

The chemical equation for the reaction between calcium carbonate (CaCO3) and sodium chloride (NaCl) is: CaCO3 + 2NaCl → CaCl2 + Na2CO3

This is a double displacement reaction, where the calcium ion (Ca2+) and the sodium ion (Na+) switch partners to form calcium chloride (CaCl2) and sodium carbonate (Na2CO3).

Sodium (Na) and chlorine (Cl) are both in halogen group in periodic table, which implies they both have 7 electrons in the outermost energy level. This makes them highly reactive and they also tend to form ionic bonds with other elements to complete the outermost shell with 8 electrons. In the reaction between calcium carbonate and sodium chloride, sodium ion (Na+) and chloride ion (Cl-) form an ionic bond to produce sodium chloride (NaCl) as the product.

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The spheres are likely made of lipids, which are a type of macromolecule. Lipids are molecules that are composed of fatty acids and glycerol, and are essential for life.

The oily sphere likely contains a core of fatty acids and glycerol, surrounded by a hydrophobic (water-repellent) coating that is formed by the non-polar tails of the fatty acids, which interact with each other and form a sphere-like structure. Lipids have a variety of functions in cells, including serving as structural components of membranes, energy storage molecules, and hormone precursors. Many lipids are made from fatty acids, which are chains of carbon atoms with hydrogen atoms attached. They are important components of cell membranes and are used as energy storage molecules.

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monoprotic acids can give one hydrogen particle or proton to their fluid arrangement, though diprotic acids can give two hydrogen iotas or protons to their watery arrangement.

The critical contrast between monoprotic and diprotic acid is that monoprotic acids can give one hydrogen molecule or proton to their watery arrangement, while diprotic acids can give two hydrogen particles or protons to their fluid arrangement. Hydrochloric acid, nitric acid, and acidic acid are instances of monoprotic acids, while sulfuric acid, carbonic acid, and oxalic acid are instances of diprotic acids. With everything taken into account, monoprotic acids are more acidic than diprotic acids.

The infographic presents the distinctions between monoprotic and diprotic acid in plain structure for one next to the other correlation.

The critical contrast between monoprotic and diprotic acid is that monoprotic acids can give one hydrogen molecule or proton to their watery arrangement, while diprotic acids can give two hydrogen particles or protons to their fluid arrangement.

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However, there are exceptions to this trend. In the case of the four given substances, only NH₄Cl becomes less soluble in water as temperature increases from 10.°C to 80.°C at standard pressure.

As a general trend, the solubility of most solids in water increases with temperature, while the solubility of gases in water decreases with increasing temperature.

At 10.°C, NH₄Cl has a solubility of about 37 g per 100 mL of water, while at 80.°C, the solubility decreases to about 29 g per 100 mL of water. This is because NH₄Cl is an endothermic salt, meaning that its dissolution in water is accompanied by the absorption of heat. As the temperature of the solution increases, the absorption of heat required for the dissolution becomes less favorable, resulting in a decrease in solubility.

On the other hand, KCl, HCl, and NaCl all exhibit an increase in solubility with increasing temperature at standard pressure.

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To make precisely 500 mL of 0.1 M HCl solution, we must combine 50 mL of 1 M HCl with water.

The result is 150 mL * moles/L after multiplying 3 moles/L by 50 mL. The result is 12.5 mL after dividing 150 mL * moles/L by 12 moles/L. Hence, to make a 3 mol HCl solution, we need to dilute 12.5 mL of the 12 M HCl with up to 50 mL of water.

The volume of 1 M HCl solution needed to create 500 mL of 0.1 M HCl can be calculated using the dilution formula.

C1V1 = C2V2

Plugging in the values we know, we get:

(1 M) V1 = (0.1 M) (500 mL)

Solving for V1, we get:

V1 = (0.1 M) (500 mL) / (1 M)

V1 = 50 mL

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Quarks : are the ultimate building blocks of visible matter in the universe.

If we could zoom in on an atom in your body, we would see that it consists of electrons swarming in orbits around a nucleus of protons and neutrons. And if we could zoom in on one of those protons or neutrons, we'd find that they themselves are made up of a trio of particles that are so small that they have almost no size at all, and are little more than points. These point-like particles are the quarks.Quarks are elementary particles. Like the electron, they are not made up of any other particles. You could say that they are on the ground floor of the Standard Model of particle physics.

A proton: is one of three main particles that make up the atom. Protons are found in the nucleus of the atom. This is a tiny, dense region at the center of the atom. Protons have a positive electrical charge of one (+1) and a mass of 1 atomic mass unit (amu), which is about 1.67×10−27 kilograms.

Neutrons, : along with protons, are subatomic particles found inside the nucleus of every atom. The only exception is hydrogen, where the nucleus contains only a single proton. Neutrons have a neutral electric charge (neither negative nor positive) and have slightly more mass than positively charged protons.

An atom: is a particle of matter that uniquely defines a chemical element. An atom consists of a central nucleus that is surrounded by one or more negatively charged electrons. The nucleus is positively charged and contains one or more relatively heavy particles known as protons and neutrons.

What is Stoichiometry?

In chemical equations, unless stated otherwise, the reactants and products will theoretically always remain in stoichiometric ratios.

The stoichiometry of a reaction is the relationship between the relative quantities of products and reactants, typically a ratio of whole integers.

Consider the following chemical reaction: aA + bB ⇒ cC + dD.

The stoichiometry of reactants to products in this reaction is the ratio of the coefficients of each species: a : b : c : d.

Now let's apply this knowledge to the question to be attempted:

first, we can start by writing out a balanced chemical equation, with states.

NH₃(g) + HCl(g) ⇒ NH₄Cl(s). This is an example of an acid/base decomposition reaction.

Hence, the stoichiometry of this reaction is 1 : 1 : 1

Now we can calculate the number of moles of each reactant that we have, by dividing the mass present (g; symbol = m), by the molar mass (g/m; symbol = M).

Next, we need to determine if, in the reaction, the substances ARE present in stoichiometric ratios. If they are not, then we need to identify the limiting reagent (the reactant which reacts completely), and the excess reagent (the reactant which is not completely used up). We can do this by inputting the mole values in the question into the ratios, until we figure out which doesn't match up.

Limiting reagent = HCl; Excess reagent = NH₃

[note: in this situation, the stoichiometry is 1 : 1, so it's very easy to determine the limiting reagent)

(i) which of the reactants was in excess and by how much

NH₃ is in excess of 0.2647 mol

(ii) how much ammonium chloride was formed?

Now we use the limiting reagent, HCl, to calculate moles of NH₄Cl formed, using our stoichiometric ratios.

Moles of NH₄Cl = moles of HCl = 0.8533 mol

(iii) how much more of the insufficient reactant would be needed to completely react with the excess of the other reactant?

Since we use our stoichiometric ratios, if NH₃ is limiting reagent, then we require 0.2647 extra mol of HCl to react.

Answer: option B is correct ,H2O has lowest bond angle of 104.5 degreewith hybridization of sp3,

Explanation: In H2O there are two bond pair and two lone pair on the central atom. The repulsion in a molecule follow the order lone pair-lone pair>lone pair-bond pair> bone pair-bone pair.

Due to the strong repulsion the presence of lone pair on central atom decreseas  the bond angle in a molecule .

                     H2O ,CH4,NH4 has hybridization of sp3,

                      BF3 hybridization of sp2

                      bond angle of

                      CH4=109.5 degree

                       BF3=120 degree

                         NH4=109.5 degree

                         H2O =104.5 degree

The decomposition of the diethyl ether at 500 °C follows the first order kinetics with the half-life of 1570 sec. The fraction of the initial amount is left after the  4710 sec is 1/8.

The decomposition of the diethyl ether at temperature = 504℃

The first order with a half-life of 1570 seconds.

Therefore, the fraction of the initial amount of the diethyl ether that will remains after the 4710 seconds will be as :

= 1//2³

= 1/8

The initial amount left = 1/8

Thus, the fraction of the initial amount that is left after the 4710 sec is 1/8.

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Stimulus is an action or event that causes a reaction or response in an organism or system. Option D is correct.

A stimulus is an action or event that triggers a reaction or response in an organism or system. In other words, a stimulus is any change in the environment that an organism or system can detect and respond to.

For example, the sound of a loud noise is a stimulus that can cause an organism to startle or run away. A sudden bright light can be a stimulus that causes a person to blink or shield their eyes.

Stimuli can be internal or external, and they can be physical, chemical, or biological in nature. Some examples of internal stimuli include hunger, thirst, and pain, while external stimuli include temperature changes, odors, and sounds.

The ability to detect and respond to stimuli is critical for the survival of organisms, as it enables them to adapt and respond to changing environmental conditions.

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correct form of question would be

What is a stimulus?(2 points)

A. A form of energy that causes a change

B. A tool to measure the amount of water in the air

C. A type of force that causes objects to move

D. An action or event that causes a reaction or response in an organism or system.

Answer:

In the periodic table, the elements are arranged in horizontal rows called periods (numbered in blue) and vertically into columns called groups

If the reaction proceeds to 65% completion, 13.95 grammes of ammonia are needed to make 14.4 grammes of HCN.

The balanced chemical equation for the reaction between propane and ammonia to produce hydrogen cyanide and hydrogen gas is:

C₃H₈ + NH₃ → HCN + 3H₂

According to the equation, one mole of NH₃ produces one mole of HCN. Therefore, to determine the number of moles of NH₃ required to produce 14.4 g of HCN, we need to convert the given mass of HCN into moles:

14.4 g HCN x (1 mole HCN/27.03 g HCN) = 0.5331 moles HCN

Since the reaction runs to 65% completion, the actual number of moles of HCN produced will be:

0.5331 moles HCN x 100/65 = 0.8202 moles HCN

Therefore, the number of moles of NH₃ required to produce this amount of HCN will be the same:

0.8202 moles NH₃

To convert moles of NH₃ to grams, we can use the molar mass of NH₃:

0.8202 moles NH3 x 17.03 g NH₃/mole = 13.95 g NH₃

Therefore, approximately 13.95 grams of ammonia are required to produce 14.4 g of HCN if the reaction runs to 65% completion.

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The correct answer is (c) Ca²⁺. When Ca²⁺ is added to a solution containing PO₄³⁻ ions, the two ions can combine to form the insoluble compound calcium phosphate (Ca₃(PO₄)₂), which will precipitate out of the solution. K⁺ and NH₄⁺ ions do not form precipitates with PO₄³⁻ ions.

Calcium ion (Ca²⁺) would form a precipitate with PO₄³⁻ ions in aqueous solution. When calcium ion reacts with phosphate ion, it forms insoluble calcium phosphate (Ca₃(PO₄)₂) which would precipitate out of the solution. Potassium ion (K⁺) and ammonium ion (NH₄⁺) do not form a precipitate with PO₄³⁻ ions, as they do not have a strong affinity towards phosphate ions. Therefore, the correct answer is option (c) Ca²⁺.

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1. The pH change when 0.094 mol NaOH is added to 1.00 L of the buffer is -0.61.

2. The pH change when 0.062 mol KOH is added to 1.00 L of the buffer is 0.26.

1. The pH change can be determined by using the Henderson-Hasselbalch equation.

The initial pH of the buffer can be found using the equation:
pH = pKa + log([A⁻]/[HA])
where pKa = -log(Ka)
and [A⁻]/[HA] = K₂SO₃/KHSO₃

The Ka value of HSO₃⁻ is 1.02 × 10⁻². Therefore, the pKa value is 1.99.

Substituting the values into the Henderson-Hasselbalch equation:
pH = 1.99 + log(0.249/0.372) = 1.99 - 0.107 = 1.88

Before addition, the pH of the buffer is 1.88.

Now, the NaOH reacts with the HSO₃⁻ ion in the buffer to form SO₃²⁻ ion and water.

NaOH + HSO₃⁻ → SO₃²⁻ + H₂O

0.094 mol NaOH will react completely with 0.094 mol HSO₃⁻ to form 0.094 mol SO₃²⁻.

Now, the new concentrations of KHSO₃, K₂SO₃, HSO₃⁻, and SO₃²⁻ are:
KHSO₃ = 0.372 - 0.094 = 0.278 M
K₂SO₃ = 0.249 M
HSO₃⁻ = 0.278 M
SO₃²⁻ = 0.094 M

The new pH of the buffer can be calculated using the same equation:
pH = pKa + log([A⁻]/[HA])

where pKa = -log(Ka)

and [A⁻]/[HA] = SO₃²⁻/HSO₃⁻

The Ka value of HSO₃⁻  is 1.02 × 10⁻². Therefore, the pKa value is 1.99.

Substituting the values into the Henderson-Hasselbalch equation:
pH = 1.99 + log(0.094/0.278) = 1.99 - 0.723 = 1.27

The new pH of the buffer is 1.27.

The pH change is calculated as the difference between the new pH and the initial pH:
pH change = 1.27 - 1.88 = -0.61

Therefore, the pH change when 0.094 mol NaOH is added to 1.00 L of the buffer is -0.61.

2. The pH change can be determined by using the Henderson-Hasselbalch equation.

The initial pH of the buffer can be found using the equation:
pH = pKa + log([A⁻]/[HA])
where pKa = -log(Ka)
and [A⁻]/[HA] = NH₃/NH₄⁺

The Ka value of NH₄⁺ is 5.6 × 10⁻¹⁰. Therefore, the pKa value is 9.25.

Substituting the values into the Henderson-Hasselbalch equation:

pH = 9.25 + log(0.287/0.311) = 9.25 - 0.084 = 9.17

Before addition, the pH of the buffer is 9.17.

Now, the KOH reacts with the NH₄⁺ ion in the buffer to form NH₃ and water.

KOH + NH₄⁺ → NH₃ + H₂O

0.062 mol KOH will react completely with 0.062 mol NH₄⁺ to form 0.062 mol NH₃.

Now, the new concentrations of NH₄Br, NH₃, NH₄⁺, and OH⁻ are:
NH₄Br = 0.311 M
NH₃ = 0.287 + 0.062 = 0.349 M
NH₄⁺ = 0.311 - 0.062 = 0.249 M
OH⁻ = 0.062 M

The new pH of the buffer can be calculated using the same equation:
pH = pKa + log([A⁻]/[HA])
where pKa = -log(Ka)
and [A⁻]/[HA] = NH₃/NH₄⁺

The Ka value of NH₄⁺ is 5.6 × 10⁻¹⁰. Therefore, the pKa value is 9.25.

Substituting the values into the Henderson-Hasselbalch equation:
pH = 9.25 + log(0.349/0.249) = 9.25 + 0.177 = 9.43

The new pH of the buffer is 9.43.

The pH change is calculated as the difference between the new pH and the initial pH:
pH change = 9.43 - 9.17 = 0.26

Therefore, the pH change when 0.062 mol KOH is added to 1.00 L of the buffer is 0.26.

Learn more about Henderson-Hasselbalch equation here: https://brainly.com/question/26746644

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