It is asking for the perimeter and area

The slope of this graph is equal to 25.

In Mathematics and Geometry, the slope of any straight line can be determined by using this mathematical equation;

Slope (m) = (Change in y-axis, Δy)/(Change in x-axis, Δx)

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Based on the information provided above, we can reasonably infer and logically deduce that Alyssa made $200 for every 8 hour shift she works as a personal trainer. Additionally, the amount of money Alyssa earned would be plotted on the y-axis while the number of hours she work would be plotted on the x-axis of a graph;

Slope (m) = 200/8

Slope (m) = 25.

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The area of the triangle is 20 square meters.

The formula to find the area of a triangle is A = 1/2 * base * height. In this case, the base of the triangle is 8 meters and the height is 5 meters. Therefore, the area of the triangle is A = 1/2 * 8 m * 5 m = 20 m^2.

We can also check our answer by using the formula A = (b * h) / 2, where b is the base and h is the height of the triangle. Substituting the values given in the question, we get A = (8 m * 5 m) / 2 = 20 m^2. Therefore, the area of the triangle is 20 square meters.

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The difference in the sample proportions of likely voters who said they will vote for this candidate is 0.025.

The range of the 95% confidence interval for the actual difference between the proportions of probable voters who would support this candidate before and after the debate was (-0.014, 0.064). To find the difference (pre-debate minus post-debate) in the sample proportions of likely voters who said they will vote for this candidate, we need to find the midpoint of the confidence interval, which is the point estimate of the true difference.

In the given question, the interval is (-0.014, 0.064), then the expression for the likely difference is

(0.064 + (-0.014))/2 = 0.050/2

= 0.025

Hence, the difference in the sample proportions of likely voters who said they will vote for this candidate is 0.025.

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Answer:

Annual % Rate: 26.43%

Amount of time it takes to double: 2.62yr

Step-by-step explanation:

Solving for r(Annual%Rate)

A=P⋅e^(r⋅t)

1405=100⋅^(r⋅10)

1405=100⋅e(^10r)

1405/100=100/100⋅e^(10r)

14.05 = e^(10r)

log(14.05) = log(e^10r)

1.1476 = 10r⋅log(e)

1.1476/log(e) = 10r

1.1476/10⋅log(e) = r

r = 0.26426

=26.43%

Now we have r=26.43%. We can use this information to solve for t, the time period to double the initial investment:

2P = Pe^(rt)

2 = e^(0.2643t)

ln(2) = 0.2643t

t = ln(2)/0.2643

t = 2.62yr

The measure of ∠L in Triangle JKL is 56.1 degrees.

In geometry, the measures in triangles refer to the angles and sides within a triangle. Triangles are three-sided polygons, and the measures of their angles and sides are important properties that determine their shape and characteristics.

In a triangle, the sum of the measures of all three angles is always 180 degrees. Therefore, to find the measure of ∠L in Triangle JKL, we can use the information given:

∠J is congruent to ∠L, which means they have the same measure.

∠K is given as 67.8 degrees.

Since ∠J is congruent to ∠L, we can denote their measure as "x".

So, the sum of the measures of ∠J, ∠K, and ∠L is 180 degrees:

∠J + ∠K + ∠L = 180

Substituting the given values:

x + 67.8 + x = 180

Simplifying the equation:

2x + 67.8 = 180

Subtracting 67.8 from both sides:

2x = 180 - 67.8

2x = 112.2

Dividing both sides by 2:

x = 112.2 / 2

x = 56.1

Hence, the measure of ∠L in Triangle JKL is 56.1 degrees.

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Answer:

1) 15.625% increase. 1850-1600=250. 250/1600=0.15625. 0.15625x100= 15.625.

2) 50%

Step-by-step explanation:

1) 1850-1600=250. 250/1600=0.15625. 0.15625x100= 15.625.

2) 75-50=25. 25/50=0.5. 0.5x100=50

Hello!

This shape is a "Strange" shape, but if you look closer at it, you can see that it can be divided into "normal shapes" like rectangles and squares

On the bottom on the "polygon" we can dived it into 2 squares

One square would have the dimensions of 6 and 6

The other one would have 4 and 6

The formula of area is: Base*Height

So the first square would have an area of 36

The second square would have an area of 24

Now we solve for the big rectangle

On first thought, it may seem like the dimensions are 16 and 25, but it is actually 10 and 25. Because 16 is the whole height of the polygon.

So we subtract it by 6

So the big rectangle is 250

=================

Now we add the areas together to get a total result of 310

If you have questions, feel free to ask

Answer:

48

Step-by-step explanation:

can be divided into two 4x6 rectangles. Therefore, the area is 4x6 + 4x6 = 48

The number of ways to travel the route is given as follows:

18 ways.

The Fundamental Counting Theorem states that if there are m ways to do one thing and n ways to do another, then there are m x n ways to do both.

This can be extended to more than two events, where the number of ways to do all the events is the product of the number of ways to do each individual event, according to the equation presented as follows:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

The options for this problem are given as follows:

Hence the total number of ways is given as follows:

3 x 3 x 2 = 18 ways.

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Answer:

92°

Step-by-step explanation:

All angles should add up to 360°

Opposite angles are equal so that means two angles are 88°

88+88=176

360 - 176 = 184

184 / 2 = 95

Measure of angle A is 92°

The Taylor series for f centered at 9, given f^(n)(9) = (-1)^n n!/6^n (n + 2), is f(x) = f(9) - (x-9)/2 + (x-9)^2/12 - (x-9)^3/432 + (x-9)^4/10368 - ... .

To find the Taylor series for f centered at 9, we need to use the formula

f(x) = f(a) + f'(a)(x-a)/1! + f''(a)(x-a)^2/2! + f'''(a)(x-a)^3/3! + ...

where f'(x) represents the first derivative of f(x) with respect to x, f''(x) represents the second derivative of f(x) with respect to x, and so on.

In this case, we are given the nth derivative of f(x) evaluated at x = 9, so we can plug in the values and simplify the formula

f(9) = f(9) (since we're centering the series at 9)

f'(9) = (-1)^1 (1!/6^1)(1 + 2) = -1/2

f''(9) = (-1)^2 (2!/6^2)(2 + 2) = 1/6

f'''(9) = (-1)^3 (3!/6^3)(3 + 2) = -1/36

f''''(9) = (-1)^4 (4!/6^4)(4 + 2) = 1/216

and so on. So the Taylor series for f centered at 9 is

f(x) = f(9) - (x-9)/2 + (x-9)^2/2! * 1/6 - (x-9)^3/3! * 1/36 + (x-9)^4/4! * 1/216 - ...

or, simplifying the coefficients

f(x) = f(9) - (x-9)/2 + (x-9)^2/12 - (x-9)^3/432 + (x-9)^4/10368 - ...

This is the Taylor series for f centered at 9, based on the given information.

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The given question is incomplete, the complete question is:

Find the Taylor series for f centered at 9 if f^(n)(9) = (-1)^n n!/6^n (n + 2)

The percentage of males attending the sporting events that are adults is:

65.10%.

A percentage is one example of a proportion, as it is obtained by the number of desired outcomes divided by the number of total outcomes, and then multiplied by 100%.

The number of males attending sporting events is given as follows:

1235.

Of those 1235 males, 804 are adults, hence the percentage of males attending the sporting events that are adults is given as follows:

p = 804/1235 x 100%

p = 65.10%.

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Answer: 3/8

Step-by-step explanation:

7/8-1/2

Find common denominator which is 8 and you get that from 1/2 by multiplying 4 on the top and bottom and so you wind up with 4/8 and 7/8-4/8 is 3/8

Step-by-step explanation:

18 m = hypotenuse = c

5 m = b

a² + b² = c²

a² + (5)² = (18)²

a² + 25 = 324

a² = 324 - 25

a² = 299

a = √299

a = 17.29 or 17.3 m

perimeter = a + b + c

= 17.3 + 18 + 5

= 40.3 m

The relation is not an equivalence relation. (a) {(2,2),(2,3),(2,4),(3,2),(3,3),(3,4)}:

Reflexive: (2,2), (3,3) are present, but (1,1) and (4,4) are not present. Hence, not reflexive.

Symmetric: (2,3) is present, but (3,2) is also present. Hence, not symmetric.

Transitive: No counterexample to transitivity exists. Hence, it is transitive.

Therefore, the relation is not an equivalence relation.

(b) {(1,1),(1,2),(2,1),(2,2),(3,3),(4,4)}:

Reflexive: (1,1), (2,2), (3,3), (4,4) are present. Hence, reflexive.

Symmetric: (1,2) is present, but (2,1) is also present. Hence, symmetric.

Transitive: No counterexample to transitivity exists. Hence, it is transitive.

Therefore, the relation is an equivalence relation.

(c) {(2,4),(4,2)}:

Reflexive: (2,2) and (4,4) are not present. Hence, not reflexive.

Symmetric: (2,4) is present, but (4,2) is not present. Hence, not symmetric.

Transitive: No counterexample to transitivity exists. Hence, it is transitive.

Therefore, the relation is not an equivalence relation.

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The density of deer for 400 square miles is around 1:4 based on stated number of deers.

The density of deer will be given by the formula -

Population density of deer = number of deer/ area

Population density is the amount or number of individuals of a population on land per unit area.

Keep the value in formula to find the population density

Population density = 100/400

Cancelling zero as common in both numerator and denominator

Population density = 1:4

Thus, there is 1 deer for every 4 square mile.

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The LCM of 8 and 9 is 72. The GCF of 35 and 63 is 7.35 + 63 can also be written as 7 X 14.

Part A

Here we have been given 2 numbers 8 and 9. We need to find the LCM. LCM is the Lowest Common Multiple. It is the smallest number which can be divided by all the mentioned number. To take the LCM of 8 and 9 we first will factorize them

8 = 2 X 2 X 2

9 = 3 X 3

Here we see that 8 and 9 do not have any common factor. Hence we need to simply multiply them together to get

8 X 9 = 72

Part B.

We need to find GCF of 35 and 63. GCF or the Greatest common factor is the highest number that can divide all the given numbers. Here too we will first factorize 35 and 63.

35 = 5 X 7

63 = 3 X 3 X 7

Here we see that between the numbers, 7 is the only common factor

Hence, 7 is the GCF.

63 can also be written as 63 = 7 X 9

Hence we can write 35 + 3

= (7 X 5) + (7 X 9)

Taking 7 common we get

7(5 + 9)

= 7 X 14

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The particle's velocity vector at t=5 is v(5) = 1i + 30j, and the acceleration vector at t=5 is a(5) = 0i + 6j.

To find the particle's velocity, we take the derivative of the path r(t) with respect to time:

v(t) = r'(t) = i + 6t j

Substituting t=5, we get:

v(5) = 1i + 30j

To find the particle's acceleration, we take the derivative of the velocity with respect to time:

a(t) = v'(t) = 0i + 6j

Substituting t=5, we get:

a(5) = 0i + 6j

Note that the acceleration vector is constant, which is expected since the particle is moving along a parabolic path, and the curvature of the path remains constant.

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There is no fixed number of trials, so X is not a binomial variable. (Choice B) B is the right response.

Discrete random variables are within the category of binomial random variables. A binomial random variable keeps track of how frequently an event occurs over a predetermined number of trials. ALL of the following prerequisites have to be satisfied for a variable to qualify as a binomial random variable:

A predetermined sample size (number of trials) is used.

The relevant occurrence either takes place or doesn't in every trial.

On each trial, the likelihood of occurrence (or not) is the same.

Trials run separately from one another.

While Yoshi has a 30% chance of success for each shot and the trials are independent, the number of attempts is not fixed, as he continues until he makes the shot.

Thus, the correct answer is (Choice B) B. There is no fixed number of trials, so X is not a binomial variable.

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Power is the rate at which work is done or energy is transferred. In this case, the girl used a force of 98 N to lift the painting to a height of 0.5 m in 0.75 seconds, resulting in 49 J of work done. The power used was calculated to be approximately 65.33 watts.

To calculate the power used by the girl while lifting the painting, we need to use the formula: Power (P) = Work (W) / time (t).

Firstly, we need to calculate the work done by the girl in lifting the painting. Work is defined as the product of force and distance. As there is no information about the force applied, we will assume that the girl lifted the painting with a constant force. Therefore, the work done can be calculated as:

Work (W) = force x distance

Here, the distance is 0.5 m, and we can use the formula for weight to calculate the force required to lift the painting. As we know that the mass of the painting is not given, we can assume it to be 10 kg (a medium-sized painting).

Weight (Wt) = mass x acceleration due to gravity
Wt = 10 kg x 9.8 m/s² = 98 N

Therefore, the work done by the girl is:

W = 98 N x 0.5 m = 49 J

Now, we can use the formula for power to calculate the power used by the girl.

P = W / t
P = 49 J / 0.75 s
P = 65.33 W (approx.)

Therefore, the girl used approximately 65.33 watts of power while lifting the painting.

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The girl used 65.3 watts of power to lift the painting.

To calculate power, we need to know the work done and the time taken.

We can use the formula:

power = work/time

The work done is equal to the force applied multiplied by the distance moved. Since we don't know the force, we can use the formula for work in terms of mass, gravity, and height:

work = mgh

where m is the mass, g is the acceleration due to gravity, and h is the height lifted.

Assuming the painting has a mass of 10 kg and the acceleration due to gravity is 9.8 m/s², the work done is:

work = (10 kg) x (9.8 m/s²) x (0.5 m) = 49 J

The time taken is 0.75 seconds.

So the power used is:

power = work/time = 49 J / 0.75 s = 65.3 watts

Therefore, the girl used 65.3 watts of power to lift the painting.

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The option that represents the resulting transformation is: Option C

A reflection over line is defined as a transformation in which each point of the original figure which is also called the pre-image possesses an image that is the essentially the same distance from the reflection line as the original point, but then is on the opposite side of the line. In a reflection, the image is the same size and shape as the pre-image.

Now, looking at the letter Q, when we reflect it once, it should be the mirror image but when reflect it the second time about same line, it becomes exactly the original copy.

Thus, we can conclude that Option C represents the resulting transformation.

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Using the compounding interest formula:

a) His ending balance after the year will be $7,658.91.

b) The amount of interest he will earn is $358.91.

c) His annual percentage yield is 4.9166%.

a) To calculate the ending balance after one year, we'll use the compound interest formula: A = P(1 + r/n)^(nt), where A is the ending balance, P is the principal ($7,300), r is the interest rate (4.85% or 0.0485), n is the number of compounding periods per year (4 for quarterly), and t is the number of years (1).

A = 7300(1 + 0.0485/4)^(4*1) = 7300(1.012125)⁴ = 7300*1.049166 = $7,658.91

b) To find the interest earned, subtract the principal from the ending balance: Interest = A - P

Interest = $7,658.91 - $7,300 = $358.91

c) To calculate the annual percentage yield (APY), we'll use the formula: APY = (1 + r/n)^(n) - 1

APY = (1 + 0.0485/4)⁴ - 1 = 1.049166 - 1 = 0.049166 or 4.9166%

Paul's ending balance after one year is $7,658.91, he earns $358.91 in interest, and his annual percentage yield is 4.9166%.

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The area of the regular hexagon with a side length of 12.7 and apothem length of 11 is approximately 416.61 square units.

To find the area of a regular hexagon, you can use the formula , where A is the [tex]A =\frac{3\sqrt{3} }{2} (s^{2} )[/tex]area, s is the length of one side, and √3 is the square root of 3.

However, since the apothem length is given, you can also use the formula , where ap is the apothem length and p is the perimeter of the hexagon.

First, let's find the perimeter of the hexagon. Since a hexagon has six sides, the perimeter will be 6 x 12.7 = 76.2.

Next, we can use the apothem length of 11 and the side length of 12.7 to find the length of the radius of the circle inscribed in the hexagon. This is because the apothem is the distance from the center of the hexagon to the midpoint of any side, and the radius is the distance from the center to any vertex.

Using the Pythagorean theorem, we can find the radius:
[tex]r^2 = ap^2 + (\frac{s}{2} )^{2}[/tex]
[tex]r^2 = 11^2 + (\frac{12.2}{7} )^{2}[/tex]
[tex]r^2 = 121 + 40.1225[/tex]
[tex]r^2 = 161.1225[/tex]
[tex]r = \sqrt{161.1225}[/tex]
[tex]r = 12.69[/tex]

Now that we know the radius, we can use the formula for the area of a regular polygon in terms of the radius: A = (1/2) x r x ap x n, where n is the number of sides (which is 6 for a hexagon).

Plugging in the values we have:
[tex]A = \frac{1}{2} (12.69)(11)(6)[/tex]
[tex]A = 416.61[/tex]

Therefore, the area of the regular hexagon with a side length of 12.7 and apothem length of 11 is approximately 416.61 square units.

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The probability of this random list is therefore the same as the example's random list, which is 25%.

To determine the number of groups containing at least three girls, we need to count the number of groups where there are at least 3 numbers between 0 and 4.

We can do this by counting the number of groups that have 0, 1, or 2 numbers between 0 and 4, and subtracting this from the total number of groups:

Number of groups with 0, 1, or 2 numbers between 0 and 4:

Number of groups with 0 numbers between 0 and 4 = 6 choose 0 * 94 choose 4 = 5,414,200

Number of groups with 1 number between 0 and 4 = 6 choose 1 * 94 choose 3 = 291,301,200

Number of groups with 2 numbers between 0 and 4 = 6 choose 2 * 94 choose 2 = 5,111,640

Total number of groups = 100 choose 5 = 75,287,520

Number of groups with at least 3 numbers between 0 and 4:

= Total number of groups - Number of groups with 0, 1, or 2 numbers between 0 and 4

= 75,287,520 - (5,414,200 + 291,301,200 + 5,111,640)

= 64,460,480

The amount of groups of this random list is the same as the example's random list (both have 100 groups).

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The decomposition of  713 × 49 has been provided below

To multiply 713 and 49, we can use the distributive property and decompose the second number as follows:

49 = 40 + 9

Then, we can multiply each part of the sum by 713:

713 × 40 + 713 × 9

To calculate this, we can use the multiplication table and then add the results:

713

x 40

28520

713

x 9

6417

Then, we add the two results:

713 × 40 = 28520

713 × 9 = 6417

34997

Therefore, the multiplication 713 × 49, decomposed as 713 × 40 + 713 × 9, equals 34,997.

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The number of cubes of dimensions of [tex]\frac{1}{8}[/tex] foot that can fit into a rectangular prism of a length of 1 foot, a width of 1 [tex]\frac{3}{8}[/tex] foot, and a height of [tex]\frac{5}{8}[/tex] foot is 55.

Volume of cuboid = l * b * h

where l is the length

b is the breadth

h is the height

l = 1 foot

b = 1 [tex]\frac{3}{8}[/tex] foot = [tex]\frac{11}{8}[/tex] foot

h = [tex]\frac{5}{8}[/tex] foot

Volume of cuboid = 1 * [tex]\frac{11}{8}[/tex] * [tex]\frac{5}{8}[/tex]

= [tex]\frac{55}{64}[/tex] cubic foot

Volume of cube = [tex]s^3[/tex]

where s is the side

s = [tex]\frac{1}{8}[/tex] foot

Volume = [tex]\frac{1}{8}^3[/tex]

= [tex]\frac{1}{64}[/tex] cubic foot

Number of cubes = [tex]\frac{\frac{55}{64} }{\frac{1}{64} }[/tex]

= 55

The number of cubes that fit into the prism is 55.

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The maximum volume of the box is 5/49, which occurs at vertex 3.

Let the length, width, and height of the box be x, y, and z respectively. Then the volume of the box is given by V = xyz.

The tetrahedron is bounded by the coordinate planes and the plane x + 1/7y + 1/6z = 1. We can find the vertices of the tetrahedron as follows:

(0, 0, 0)

(7, 0, 0)

(0, 6, 0)

(0, 0, 6)

We can see that the maximum values of x, y, and z occur at different vertices of the tetrahedron.

Therefore, we need to find the coordinates of the vertices of the box at each vertex of the tetrahedron.

At vertex 1, we have x = 0, y = 0, and z = 0. The distance from this vertex to the plane is 1, so the maximum value of x is 1.

Therefore, we set x = 1 and solve for y and z:

1 + 1/7y + 1/6z = 1

y = 0

z = 0

At vertex 2, we have x = 7, y = 0, and z = 0. The distance from this vertex to the plane is 6/7, so the maximum value of y is 6/7.

Therefore, we set y = 6/7 and solve for x and z:

x + 1/7(6/7) + 1/6z = 1

x = 5/6

z = 1/7

At vertex 3, we have x = 0, y = 6, and z = 0. The distance from this vertex to the plane is 5/6, so the maximum value of z is 5/6.

Therefore, we set z = 5/6 and solve for x and y:

x + 1/7y + 1/6(5/6) = 1

x = 4/7

y = 3/7

At vertex 4, we have x = 0, y = 0, and z = 6. The distance from this vertex to the plane is 1/7, so the maximum value of x is 7.

Therefore, we set x = 7 and solve for y and z:

7 + 1/7y + 1/6(6) = 1

y = -42/7

z = 1/6

Now we can calculate the volume of the box at each vertex of the tetrahedron:

V1 = 1(0)(0) = 0

V2 = 5/6(6/7)(1/7) = 5/294

V3 = 4/7(3/7)(5/6) = 5/49

V4 = 7(-42/7)(1/6) = -49/6

Therefore, the maximum volume of the box is 5/49, which occurs at vertex 3.

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Anita will take 5 more weeks to save enough money for the snowboard. when she saved $43. 75 of the $112. 50 that she needs for a new snowboard.

Given data :

Total money needs for a new snowboard = $112. 50

Anita saved money = $43. 75

Money saved each week = $13. 75

From the given data we can write the equation to find the number of weeks  as,

13. 75w + 43. 75 = 112. 50

By solving the equation 13.75w + 43.75 = 112.50 we can find out how many more weeks it will take Anita to save enough money for the snowboard by using the elimination method.

Subtracting 43.75 from both sides of the equation, we get:

13.75w + 43.75 - 43.75 = 112.50 - 43.75

13.75w = 68.75

w = 68.75 / 13.75

w = 5

Therefore, Anita will take 5 more weeks to save enough money for the snowboard.

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It should be noted that to craft a triangle with an edge measuring 5 units of length, another side 7 units in magnitude, we can get underway by sketching an uninterrupted line of 7-units duration.

Subsequently, draw an additional segment arriving at a peak of 5-units from the starting point of the former line. From the end-point of the line calculated as 7 units, draw a joined line towards the conclusion of the 5 unit-length section. This enables two distinctive triangles:

Also, to guarantee that just a single triangle can be drawn, it is imperative to recognize the angle resting between the two assigned sides. In case we are endowed with the inclination between both varying lengths of five and seven units, then only an original composition of triangle can be constructed.

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