The pairs of cities that will not put Jenny back under budget if she drops them are:
a. Moscow and Chelyabinsk
b. Izhevsk and Nizhny Novgorod
To determine which pair of cities Jenny can drop without going over budget, we need to find the total cost of each pair and see if it exceeds her budget of rub 33,000.
a. Moscow and Chelyabinsk:
Total cost = 5,485 + 5,217 = 10,702 rubles
This pair of cities is over budget, so Jenny cannot drop any other cities if she wants to visit both Moscow and Chelyabinsk.
b. Izhevsk and Nizhny Novgorod:
Total cost = 4,721 + 6,920 = 11,641 rubles
This pair of cities is over budget, so Jenny cannot drop any other cities if she wants to visit both Izhevsk and Nizhny Novgorod.
c. Novosibirsk and Saint Petersburg:
Total cost = 4,870 + 5,960 = 10,830 rubles
This pair of cities is under budget, so Jenny can drop this pair without going over budget.
d. Yaroslavl and Tolyatti:
Total cost = 4,901 + 5,598 = 10,499 rubles
This pair of cities is under budget, so Jenny can drop this pair without going over budget.
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Pls, answer this, 5 points and brainliest for the one who answers first!
Answer: C
Step-by-step explanation:
f moved left 4 spaces in x direction to get to g
so take opposite sign
f(x+4)
Khloe is a teacher and takes home 90 papers to grade over the weekend. She can
grade at â rate of 10 papers per hour. Write a recursive sequence to represent how
many papers Khloe has remaining to grade after working for n hours.
The recursive sequence representing how many papers Khloe has remaining to grade after working for n hours is given by a_n = a_{n-1} - 10, where a_0 = 90.
Let a_n denote the number of papers Khloe has remaining to grade after n hours of work. After the first hour of work, she will have 90 - 10 = 80 papers remaining. Therefore, we have a_1 = 90 - 10 = 80.
After the second hour of work, she will have a_2 = a_1 - 10 = 80 - 10 = 70 papers remaining. Similarly, after the third hour of work, she will have a_3 = a_2 - 10 = 70 - 10 = 60 papers remaining.
In general, after n hours of work, Khloe will have a_n = a_{n-1} - 10 papers remaining to grade. This is a recursive sequence, where the value of a_n depends on the value of a_{n-1}. The initial value of a_0 is given as 90, since she starts with 90 papers to grade. Therefore, the recursive sequence is given by a_n = a_{n-1} - 10, where a_0 = 90.
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Persevere with Problems Triangle XYZ is reflected across the x-axis to produce triangle X'Y'Z'. Then triangle X'Y'Z' is rotated 90° counterclockwise about the origin to create triangle X''Y''Z''. If triangle X''Y''Z'' has vertices X''(4, 0), Y''(2, –1), and Z''(2, 1), what are the coordinates of the vertices of triangle XYZ? Write your answers as integers.
The vertices of triangle XYZ are (-4, 0), (1, -2), and (-2, 1).
How to calculate the verticesWe are given that X''(4, 0), Y''(2, -1), and Z''(2, 1). We can use these coordinates to determine the coordinates of the vertices of triangle XYZ.
Starting with X, we have (-y, x) = (4, 0). This implies that y = 0 and x = -4.
Moving on to Y we have (-z, y) = (2, -1). This implies that z = -2 and y = 1.
Finally, for Z, we have (-x, z) = (2, 1). This implies that x = -2 and z = 1.
Therefore, the vertices of triangle XYZ are (-4, 0), (1, -2), and (-2, 1).
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Suppose the length of voicemails (in
seconds) is normally distributed with a mean
of 40 seconds and standard deviation of 10
seconds. Find the probability that a given
voicemail is between 20 and 50 seconds.
10
20
30
40
50
60
P = Г?1%
Hint: Use the 68 - 95 - 99.7 rule
70
Enter
The probability that a given voicemail is between 20 and 50 seconds is 0.8185, or 81.85%.
How to find the the probability that a given voicemail is between 20 and 50 seconds.To find the probability that a voicemail is between 20 and 50 seconds, we need to standardize the values and use a standard normal distribution table.
First, we find the z-scores for 20 seconds and 50 seconds:
z1 = (20 - 40) / 10 = -2
z2 = (50 - 40) / 10 = 1
Using a standard normal distribution table, we can find the area to the left of each z-score:
Area to the left of z1 = 0.0228
Area to the left of z2 = 0.8413
To find the probability between 20 and 50 seconds, we subtract the area to the left of z1 from the area to the left of z2:
P(20 < x < 50) = P(-2 < z < 1)
= 0.8413 - 0.0228
= 0.8185
Therefore, the probability that a given voicemail is between 20 and 50 seconds is 0.8185, or 81.85%.
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Lochlon transfers his investment into a money market account. The account now earns compound interest of 1. 95% annually with a maturity date of 5 years
The final amount Lochlon will earn on his investment after 5 years of compound interest is $1,104.36
How we calculate the compound interest?Compound interest is a type of interest calculation where the interest earned is added to the principal amount, and the resulting sum becomes the new principal for the next interest calculation. The formula for compound interest is:
A = [tex]P(1 + r/n)^(^n^t^)[/tex]
Where:
A is the final amount including the interest
P is the principal amount
r is the annual interest rate as a decimal
n is the number of times the interest is compounded per year
t is the time in years
In this case, Lochlon transferred his investment into a money market account that earns compound interest of 1.95% annually, with a maturity date of 5 years.
To find the final amount Lochlon will earn, we need to know the principal amount, the interest rate, the number of times the interest is compounded per year, and the time period.
Assuming Lochlon invests a principal amount of P dollars, with an annual interest rate of r = 1.95%, and the interest is compounded annually (n = 1) for a time period of 5 years (t = 5), the formula for calculating the final amount (A) is:
A = [tex]P(1 + r/n)^(^n^t^)[/tex]
= [tex]P(1 + 0.0195/1)^(^1^*^5^)[/tex]
= [tex]P(1.0195)^5[/tex]
if Lochlon invests $1,000, for example, then his final amount (A) after 5 years would be:
A = [tex]1000(1.0195)^5[/tex]
= 1000(1.10436)
= $1,104.36
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evaluate the integral tan inverse v(x+2 ) dx by making substitution
and then table of integrals
To evaluate the integral of tan inverse v(x+2) dx, we need to make a substitution. Let u = x + 2, then du/dx = 1 and dx= du. Therefore, the final answer is: ∫ tan inverse v(x+2) dx = (x+2) tan inverse v(x+2) - tan inverse v(x+2) / v'(x+2) + C
Substituting this back into the integral, we get:
∫ tan inverse v(x+2) dx = ∫ tan inverse v(u) du
Using the formula from the table of integrals, we have:
∫ tan inverse v(u) du = u tan inverse v(u) - ∫ u / (1 + v(u)^2) du
Substituting back u = x + 2, we get:
∫ tan inverse v(x+2) dx = (x+2) tan inverse v(x+2) - ∫ (x+2) / (1 + v(x+2)^2) dx
Now, we can use another substitution, let t = v(x+2), then dt/dx = v'(x+2) and dx = dt / v'(x+2).
Substituting this back into the integral, we get:
∫ (x+2) / (1 + v(x+2)^2) dx = ∫ (x+2) / (1 + t^2) dt / v'(x+2)
Using the formula from the table of integrals, we have:
∫ (x+2) / (1 + t^2) dt = tan inverse t + C
where C is the constant of integration.
Substituting back t = v(x+2), we get:
∫ (x+2) / (1 + v(x+2)^2) dx = tan inverse v(x+2) / v'(x+2) + C
Therefore, the final answer is:
∫ tan inverse v(x+2) dx = (x+2) tan inverse v(x+2) - tan inverse v(x+2) / v'(x+2) + C
where C is the constant of integration.
To evaluate the integral of tan inverse v(x+2) dx using substitution, we'll first make a substitution:
Let u = x+2. Then, du = dx.
Now, we can rewrite the integral as:
∫tan^(-1)(v(u)) du
Next, we'll look up the integral of tan^(-1)(v(u)) in a table of integrals. Unfortunately, there isn't a direct formula for this specific integral. However, we can use integration by parts to proceed further.
Let I = ∫tan^(-1)(v(u)) du. Let's choose:
f(u) = tan^(-1)(v(u)) and df(u) = du,
g'(u) = 1 and dg(u) = u du.
Using integration by parts formula:
I = f(u)g(u) - ∫g(u)df(u)
I = u*tan^(-1)(v(u)) - ∫u(1/(1+v^2(u))) du
Now, we'll need to substitute back x+2 for u:
I = (x+2)*tan^(-1)(v(x+2)) - ∫(x+2)(1/(1+v^2(x+2))) dx
This integral doesn't have a simple closed-form solution, so the final answer will remain in the form shown above.
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Pls help quick
which theorem can you use to show that the quadrilateral on the tile floor is a parallelogram
To show that the quadrilateral on the tile floor is a parallelogram, you can use the opposite sides theorem, opposite angles theorem, consecutive angles theorem, and Diagonal bisector theorem.
1. Opposite sides theorem: If both pairs of opposite sides of the quadrilateral are congruent (equal in length), then it is a parallelogram.
2. Opposite angles theorem: If both pairs of opposite angles of the quadrilateral are congruent (equal in measure), then it is a parallelogram.
3. Consecutive angles theorem: If the consecutive angles of the quadrilateral are supplementary (their sum is 180 degrees), then it is a parallelogram.
4. Diagonal bisector theorem: If the diagonals of the quadrilateral bisect each other (divide each other into two equal parts), then it is a parallelogram.
Choose the most appropriate theorem based on the given information and apply it to prove that the quadrilateral is a parallelogram.
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A gym subscription runs several promotions. Customers can choose from the following offers.
Option A: 25% off an annual subscription of $308. 00
Option B: pay $29 per month
How much will a customer save by purchasing the annual subscription over paying per month?
a
$348
b
$231
c
$79
d
$117
A customer will save $117 by purchasing the annual subscription over paying per month. So the (d) $117 is the right answer.
To determine how much a customer will save by purchasing the annual subscription over paying per month, follow these steps:
Calculate the discounted annual subscription cost:
Option A: 25% off an annual subscription of $308.00
Discount = 25% of $308 = 0.25 * $308 = $77
Discounted Annual Subscription = $308 - $77 = $231
Calculate the total cost of the monthly subscription for one year:
Option B: Pay $29 per month
Total Monthly Subscription Cost = $29 * 12 months = $348
Calculate the savings:
Savings = Total Monthly Subscription Cost - Discounted Annual Subscription
Savings = $348 - $231 = $117
So, a customer will save $117 by purchasing the annual subscription over paying per month. Your answer is d. $117.
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Find the probability that a point chosen randomly inside the rectangle is in each given shape. Round to the nearest tenth.
(a) Square
(b) Not the triangle
The probabilities are given as follows:
a) Square: 1/6.
b) Not the triangle: 43/48.
How to calculate a probability?A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.
The area of the rectangle is given as follows:
A = 12 x 8 = 96.
(area of rectangle, multiply the dimensions).
The areas of each figure are given as follows:
Square: 4² = 16. (area of square is the square of the side length).Triangle: 0.5 x 4 x 5 = 10. (area of right triangle is half the multiplication of the side lengths).Hence the probability of the square is given as follows:
p = 16/96 = 1/6.
(area of square divided by total area).
The probability that the region is not the triangle is given as follows:
p = (96 - 10)/96
p = 86/96
p = 43/48.
(triangle and not triangle are complementary events).
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Will give brainliest if right
aabc ~ def. what sequence of transformations will move aabc onto adef?
d. a dilation by scale factor of 2, centered at the origin, followed by a reflection over the y-axis
AABC is transformed onto ADEF by a dilation by a scale factor of 2, centered at the origin, followed by a reflection over the y-axis.
The sequence of transformations that will move AABC onto ADEF is a dilation by a scale factor of 2, centered at the origin, followed by a reflection over the y-axis.
Firstly, dilation is a transformation that changes the size of an object but not its shape.
The dilation factor is multiplied by each coordinate, so when the dilation is centered at the origin, the new coordinates will be twice the original coordinates.
Therefore, AABC will be enlarged to A'BC', and DEF will be enlarged to D'E'F, both with double the size.
Then, reflection is a transformation that flips an object over a line of reflection. In this case, the line of reflection is the y-axis.
When we reflect A'BC' over the y-axis, we get A''B''C'', and when we reflect D'E'F over the y-axis, we get D''E''F''.
Therefore, AABC is transformed onto ADEF by a dilation by a scale factor of 2, centered at the origin, followed by a reflection over the y-axis.
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3. [-/1 Points] DETAILS SCALCET9 4.7.005. What is the maximum vertical distance between the line y = x + 72 and the parabola y - x for - SxS9? Need Help? Watch
The maximum vertical distance between the line y = x + 72 and the parabola y = x^2 is 518.67 units.
To find the maximum vertical distance between the line and the parabola, we need to find the point(s) where the distance is maximum.
The line y = x + 72 is a straight line with slope 1, and it intersects the y-axis at 72.
The parabola y = x^2 is a symmetric curve with vertex at (0,0).
To find the point(s) where the distance is maximum, we can find the intersection point(s) of the line and the parabola.
Substituting y = x + 72 in the equation of the parabola, we get x^2 - x - 5184 = 0.
Solving for x using the quadratic formula, we get x = (1 ± sqrt(1 + 20736))/2.
The two intersection points are (108, 180) and (-107, 65).
The maximum vertical distance between the line and the parabola is the difference between the y-coordinates of these points, which is approximately 518.67 units.
Therefore, the maximum vertical distance between the line y = x + 72 and the parabola y = x^2 is 518.67 units.
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In an effort to eat healthier, Bridget is tracking her food intake by using an application on her phone. She records what she eats, and then the
application indicates how many calories she has consumed. One Monday, Bridget eats 10 medium strawberries and 8 vanilla wafer cookies as an
after-school snack. The caloric intake from these items is 192 calories. The next day, she eats 20 medium strawberries and 1 vanilla wafer cookie as an after-school snack. The caloric intake from these items is 99 calories.
a. Write a system of equations for this problem situation. Let S represent the number of calories in one strawberry and let W represent the number of calories in one vanilla wafer cookie.
The equation _____ represents the calories Bridget ate on Monday and the equation _____ represents the calories she ate the next day.
b. Solve the system of equations using the substitution method. Check your work.
The number of calories in each strawberry is ____
And the number of calories in each vanilla wafer cookie is ____. The solution is ____.
PLEASE HELP ME
The equation 10S + 8W = 192 represents the calories Bridget ate on Monday and the equation 20S + 1W = 99 represents the calories she ate the next day.
The number of calories in each strawberry is 4, and the number of calories in each vanilla wafer cookie is 19.
a. We have two equations for the two days, using S for the number of calories in a strawberry and W for the number of calories in a vanilla wafer cookie:
On Monday:
10S + 8W = 192
On Tuesday:
20S + 1W = 99
b. To solve the system of equations using the substitution method, first solve one of the equations for one of the variables. We'll choose the second equation and solve for W:
W = 99 - 20S
Now substitute this expression for W in the first equation:
10S + 8(99 - 20S) = 192
Expand and simplify:
10S + 792 - 160S = 192
Combine like terms:
-150S = -600
Now divide by -150:
S = 4
Now that we have the value for S, substitute it back into the expression for W:
W = 99 - 20(4)
W = 99 - 80
W = 19
So the number of calories in each strawberry is 4, and the number of calories in each vanilla wafer cookie is 19. The solution is (S, W) = (4, 19).
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Which pair of transformations moves quadrilateral 1 to quadrilateral 2?
o a. reflect it over the line y = -3, then rotate it 90° counterclockwise about the origin
o b. reflect it over the x-axis, then rotate it 180° about the origin
o c. rotate it 90° counterclockwise about point (-3,-3), then translate it 8 units to the right
o d translate it 8 units to the right, then reflect it over the line y=-3
c. rotate it 90° counterclockwise about point (-3,-3), then translate it 8 units to the right
How does quadrilateral 1 move to quadrilateral 2?The correct pair of transformations that moves quadrilateral 1 to quadrilateral 2 is option d: translate it 8 units to the right, then reflect it over the line y = -3.
First, by translating it 8 units to the right, all points of quadrilateral 1 will shift horizontally to the right by 8 units, maintaining their relative positions.
Next, reflecting it over the line y = -3 will result in a vertical flip of the shape. This reflection will change the orientation of the quadrilateral while keeping the translated positions intact.
Together, these two transformations will precisely move quadrilateral 1 to quadrilateral 2. Therefore, option d is the correct choice.
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determine if each of the numbers below is a solution to the inequality 3x-2<2-2x
The solution set of the inequality 3x-2 < 2-2x is:
(4/5, ∞)
Which numbers are solutions for the inequality?To find this we need to isolate the variable in the inequality.
Here we have:
3x - 2 < 2 - 2x
add 2x in both sides and add 2 in both sides, then we will get:
3x + 2x < 2 + 2
5x < 4
Now we can divide both sides by 5 to get:
x < 4/5
That is the inequality solved.
Then the solution set of the inequality is:
(4/5, ∞)
The set of all real numbers larger than 4/5.
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Angle θ is in standard position and
(
−
5
,
−
6
)
(−5,−6) is a point on the terminal side of θ. If
0
∘
≤
θ
<
36
0
∘
0
∘
≤θ<360
∘
, what is the measure of θ, to the nearest tenth of a degree (if necessary)?
The measure of angle θ, to the nearest tenth of a degree is 233.1°.
To find the measure of angle θ, we need to use trigonometry. We can see that the point (-5,-6) lies in the third quadrant since both x and y coordinates are negative. We can draw a right-angled triangle with the origin (0,0) as the vertex and the given point (-5,-6) as one of the vertices on the x-y plane.
The hypotenuse of this triangle will be the distance between the origin and the point (-5,-6), which can be calculated using the Pythagorean theorem.
Using the Pythagorean theorem, we get:
√(5²+6²) = √(25+36) = √61
Now we can use trigonometry to find the measure of angle θ. We can see that the sine of θ is equal to the opposite side over the hypotenuse and the cosine of θ is equal to the adjacent side over the hypotenuse. So we have:
sin θ = -6/√61 and cos θ = -5/√61
Using a calculator, we can find that θ is approximately 233.1° to the nearest tenth of a degree.
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Kaleb’s mom owns a confidence store. He is helping her replace the tile floor. The tile costs $2.00 per ft squared.
How much will the tile cost?
Answer:
425
Step-by-step explanation:
212,5*2=425
Solve the following Exact Inexact Differential Equation. If it is inexact, then
solve it by finding the Integrating Factor.
(3xy + y^2) dx + (x^2 + xy) dy = 0
The general solution to the differential equation is, |3x^4/(y(x+y))|x + |x^3| ln|y| + |x^3| ln|x+y| + h(x) = C.
The partial derivative of (3xy + y^2) with respect to y is 6xy + 2y, and the partial derivative of (x^2 + xy) with respect to x is 2x + y. Since these are not equal, the differential equation is not exact.
To make it exact, we need to find an integrating factor μ(x, y) such that μ(x, y)(3xy + y^2) dx + μ(x, y)(x^2 + xy) dy = 0 is exact. We can find μ(x, y) by using the formula:
μ(x, y) = e^(∫(∂M/∂y - ∂N/∂x)/N dx)
where M = 3xy + y^2 and N = x^2 + xy. We have:
(∂M/∂y - ∂N/∂x)/N = (6xy + 2y - 2x - y)/(x^2 + xy) = (6xy - x - y)/(x^2 + xy)
We can now find the integrating factor μ(x, y) by integrating this expression with respect to x:
μ(x, y) = e^(∫(6xy - x - y)/(x^2 + xy) dx) = e^(3ln|x| - ln|y| - ln|x+y| + C) = e^(ln|x^3/(y(x+y))| + C) = |x^3/(y(x+y))|e^C
where C is the constant of integration.
Now we multiply the original differential equation by the integrating factor μ(x, y) to obtain:
|3x^4/(y(x+y))| dx + |x^3/(y(x+y))| dy = 0
This is now an exact differential equation, and we can find its solution by integrating with respect to x or y. Integrating with respect to x, we get:
|3x^4/(y(x+y))|x + g(y) = C
where g(y) is the constant of integration. To find g(y), we integrate the coefficient of dy:
g(y) = ∫|x^3/(y(x+y))| dy = |x^3| ln|y| + |x^3| ln|x+y| + h(x)
where h(x) is another constant of integration. Substituting g(y) back into the solution, we have:
|3x^4/(y(x+y))|x + |x^3| ln|y| + |x^3| ln|x+y| + h(x) = C
This is the general solution to the differential equation.
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Square root 2/3 + square root 6
Answer:
[tex] \sqrt{ \frac{2}{3} } + \sqrt{6} \\ = \frac{ \sqrt{2} }{ \sqrt{3} } + \sqrt{6} \\ = \frac{ \sqrt{2} }{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } + \sqrt{6} \\ = \frac{ \sqrt{6} }{3} + \sqrt{6} \\ = \frac{ \sqrt{6} }{3} + \frac{3 \sqrt{6} }{3} \\ = \frac{ 4\sqrt{6} }{3} [/tex]
Cleo bought a computer for
$
1
,
495
. What is it worth after depreciating for
3
years at a rate of
16
%
per year?
The worth of the computer after depreciating for 3 years is $749.77, under the condition that a rate of 16% per year was applied.
Then the derived formula for evaluating depreciation
Depreciation = (Asset Cost – Residual Value) / Life-Time Production × Units Produced
Then,
Asset Cost = $1,495
Residual Value = 0 (assuming the computer has no resale value after 3 years)
Life-Time Production = 3 years
Units Produced = 1
Hence, the depreciation rate
[tex]Depreciation Rate = (1 - (Residual Value / Asset Cost)) ^{ (1 / Life-Time Production) - 1}[/tex]
[tex]Depreciation Rate = (1 - (0 / 1495))^{(1/3-1)}[/tex]
Depreciation Rate = 16%
Now to evaluate the value of the computer after three years of depreciation at a rate of 16% per year, we can apply the derived formula
Value of Asset After Depreciation = Asset Cost × (1 - Depreciation Rate) ^ Life-Time Production
Value of Asset After Depreciation = $1,495 × (1 - 0.16)³
Value of Asset After Depreciation = $749.77
Hence, the computer is worth $749.77 after three years of depreciation at a rate of 16% per year.
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The complete question is
Cleo bought a computer for $1,495. What is it worth after depreciating for 3 years at a rate of 16% per year?
Identify the transformations of the graph of f(x) = x^2 that result in the graph of g shown. What rule, in vertex form, can you write for g(x)?
A vertical translation (5 units up) is applied on quadratic function f(x) = x².
What kind of rigid transformation can be used to obtain an image of the quadratic function?
In this problem we find the representation of quadratic function and its image on Cartesian plane. The image is the consequence of using a vertical translation, whose definition is now introduced:
g(x) = f(x) + k
Where k is the y-coordinate of the quadratic function.
If we know that f(x) = x² and k = 5, then the image of the function is:
g(x) = x² + 5
The image is the result of a vertical translation (5 units up).
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This trapezoid-based right prism has a volume of 30 cm
6 cm
5 cm
1 cm
What is the area of the base of the prism?
The area of the base of the prism is,
Area = 5.5 cm²
We have to given that,
This trapezoid-based right prism has a volume of 30 cm³.
We have;
Here we assume
a = 6
b = 5
c = 1
Now we know that
Area = (a + b) c / 2
Area = (6 + 5) 1 /2
Area = 11/2
Area = 5.5 cm²
Thus, The area of the base of the prism is,
Area = 5.5 cm²
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select the equivalent expression (7/2)^8
5764801/256, is equivalent expression of [tex](7/2)^8[/tex] which is an exact value and cannot be simplified any further.
What is equivalent expression and How do you write an equivalent expression?Equivalent expressions are expressions that work the same even though they look different. If two algebraic expressions are equivalent, then the two expressions have the same value when we plug in the same value for the variable. You can write equivalent expressions by combining like terms. Like terms are terms that have the same variables raised to the same powers.
We can simplify the expression[tex](7/2)^8[/tex]by raising both the numerator and denominator to the 8th power:
We get,
[tex](7/2)^8 = 7^8 / 2^8[/tex]
To solve this value, simplify the numerator and denominator separately:
So we get,
[tex]7^8[/tex]= 5764801
[tex]2^8[/tex]= 256
Therefore, [tex](7/2)^8[/tex] = 5764801/256, which is an exact value and cannot be simplified any further.
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In the diagram shown, segments AE and CF are both perpendicular to DB. DE=FB, AE=CF. Prove that ABCD is a parallelogram.
Given:- ABCD is a parallelogram, and AE and CF bisect ∠A and ∠C respectively. To prove:- AE∥CF Proof:- Since in a parallelogram, opposite angles are equal.
What is a Parallelogram?A parallelogram is a geometric shape that has four sides and four angles. It is a type of quadrilateral, which means it has four sides, and its opposite sides are parallel to each other.
The opposite sides of a parallelogram are also equal in length. The opposite angles of a parallelogram are also equal in measure.
The shape of a parallelogram looks similar to a rectangle, but it differs from a rectangle in that its angles are not necessarily right angles. A square is a special case of a parallelogram in which all four sides are equal in length and all four angles are right angles
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Write a polynomial function of least degree with integral coefficients that has the given zeros.
-5, -3-2i
Answer:
[tex]f(x)=x^3+11x^2+43x+65[/tex]
Step-by-step explanation:
If a polynomial function has a complex zero, then the conjugate of that complex zero is also a zero of the polynomial.
So, if (-3 - 2i) is a zero of the polynomial, then its conjugate (-3 + 2i) is also a zero of the polynomial.
Therefore, the three zeros of the polynomial function are:
-5(-3 - 2i)(-3 + 2i)The zero of a polynomial f(x) is the x-value when f(x) = 0.
According to the factor theorem, if f(a) = 0 then (x - a) is a factor of the polynomial f(x).
Therefore, the polynomial function in factored form is:
[tex]\begin{aligned}f(x) &= (x - (-5))(x-(-3-2i))(x-(-3+2i))\\&= (x +5)(x+3+2i)(x+3-2i)\end{aligned}[/tex]
Expand the brackets to write the polynomial in standard form.
[tex]\begin{aligned}f(x) &=(x +5)(x+3+2i)(x+3-2i)\\&=(x+5)(x^2+3x-2xi+3x+9-6i+2ix+6i-4i^2)\\&=(x+5)(x^2+6x+9-4i^2)\\&=(x+5)(x^2+6x+9-4(-1))\\&=(x+5)(x^2+6x+9+4)\\&=(x+5)(x^2+6x+13)\\&=x^3+6x^2+13x+5x^2+30x+65\\&=x^3+11x^2+43x+65\end{aligned}[/tex]
Therefore, the polynomial function of least degree with integral coefficients that has the given zeros -5 and (-3 - 2i) is:
[tex]f(x)=x^3+11x^2+43x+65[/tex]
f(x)=x3+11x²+43x+65
A waiter had five tables he was waiting on, with three women and three men at each table. How many customers total did the waiter have?
The total number of customers that the waiter had would be = 30 customers.
How to calculate the total number of customers?The total number of tables the waiter had = 5 tables
The total number of women at each table = 3
The total number of men at each table = 3
The total number of people one each table = 6
Therefore the total number of customers that the waiter attended to would be = 5×6 = 30
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Find dy/dt given that x^2+y^2 = 2x+4y, x = 3, y = 1 and dx/dt = 7
To find dy/dt, we need to use implicit differentiation.
First, we differentiate both sides of the equation with respect to t:
2x(dx/dt) + 2y(dy/dt) = 2(dx/dt) + 4(dy/dt)
Next, we plug in the given values for x, y, and dx/dt:
2(3)(7) + 2(1)(dy/dt) = 2(7) + 4(dy/dt)
Simplifying, we get:
42 + 2(dy/dt) = 14 + 4(dy/dt)
Subtracting 2(dy/dt) and 14 from both sides:
28 = 2(dy/dt)
Finally, we divide both sides by 2 to solve for dy/dt:
dy/dt = 14
To find dy/dt, first differentiate the given equation x^2+y^2=2x+4y with respect to time t. Use the chain rule:
2x(dx/dt) + 2y(dy/dt) = 2(dx/dt) + 4(dy/dt).
Now substitute the given values, x = 3, y = 1, and dx/dt = 7:
2(3)(7) + 2(1)(dy/dt) = 2(7) + 4(dy/dt).
Solve for dy/dt:
42 + 2(dy/dt) = 14 + 4(dy/dt).
Rearrange and solve:
2(dy/dt) - 4(dy/dt) = 14 - 42,
-2(dy/dt) = -28.
Finally, divide by -2:
dy/dt = 14.
So the value of dy/dt is 14 when x = 3, y = 1, and dx/dt = 7.
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A researcher asked 933 people what their favourite type of TV programme was: news, documentary, soap or sports. They could only choose one answer. As such, the researcher had the number of people who chose each category of programme. How should she analyse these data?
a. T-test
b. One-way analysis of variance
c. Chi-square test
d. Regression
The researcher should analyze the data obtained from 933 people who were asked about their favorite type of TV program, with the condition that they could only choose one answer. The appropriate statistical test to analyze these data is c. Chi-square test.
The Chi-square test is used for analyzing categorical data, which is the case in this scenario where individuals have to choose among news, documentary, soap, or sports. The test will help the researcher determine if there is a significant difference in preferences for TV program types among the respondents.
The specific techniques and statistical tests used may vary depending on the goals of the research and the nature of the data.
Therefore option c is correct.
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The potters want to buy a small cottage costing $118,000 with annual insurance and taxes of $710. 00 and $2800. 0. They have saved $14,000. 00 for a down payment, and they can get a 5%, 15 year mortgage from a bank. They are qualified for a home loan as long as the total monthly payment does not exceed $1000. 0. Are they qualified?
The potters are qualified for the home loan as their total monthly payment is $831.02, which is less than $1000.00.
The total cost of the cottage along with the annual insurance and taxes is $118,000 + $710 + $2800 = $121,510.
The down payment made by the potters is $14,000. Therefore, the amount to be financed through a mortgage is $121,510 - $14,000 = $107,510.
Using the formula for the monthly payment of a mortgage, which is given by:
M = P [ i(1 + i)^n ] / [ (1 + i)^n - 1]
where P is the principal (amount to be financed), i is the monthly interest rate, and n is the total number of monthly payments.
For a 5%, 15-year mortgage, the monthly interest rate is 0.05/12 = 0.0041667, and the total number of monthly payments is 15 x 12 = 180.
Plugging in the values, we get:
M = $107,510 [ 0.0041667 (1 + 0.0041667)^180 ] / [ (1 + 0.0041667)^180 - 1 ]
M = $831.02
Therefore, the total monthly payment for the mortgage and the annual insurance and taxes is $831.02 + $59.17 + $233.33 = $1123.52, which is more than the maximum allowed payment of $1000.00. Hence, the potters are qualified for the home loan.
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The following costs were for bikeway inc., a bicycle manufacturer that uses the high-low method:
output fixed costs variable costs total costs
950 $ 45,000 $ 95,000 $ 140,000
1,050 $ 45,000 $ 105,000 $ 150,000
1,100 $ 45,000 $ 110,000 $ 155,000
1,150 $ 45,000 $ 115,000 $ 160,000
at an output level of 1,000 bicycles, per unit total cost is calculated to be:
multiple choice
$139.13.
$145.00.
$121.50.
$126.09.
$100.00.
The per unit total cost at an output level of 1,000 bicycles is calculated to be $139.13.
To calculate the per unit total cost using the high-low method, follow these steps:
1. Identify the highest and lowest output levels (1,150 and 950 bicycles).
2. Calculate the difference in variable costs and output levels: ($115,000 - $95,000) / (1,150 - 950) = $20,000 / 200 = $100 per bicycle.
3. Calculate the variable cost for 1,000 bicycles: $100 x 1,000 = $100,000.
4. Add the fixed cost: $100,000 (variable cost) + $45,000 (fixed cost) = $145,000 (total cost).
5. Calculate the per unit total cost: $145,000 / 1,000 = $139.13 per bicycle.
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Test the convergence of the series: is it convergentor divergent or inconclusive or none of them
Once we apply one of these tests and determine whether the series converges or diverges, we can then further analyze the series to find its sum, if it exists.
To test the convergence of a series, we typically use one of several tests, depending on the nature of the series. Some of the commonly used tests are:
Divergence test: If the terms of a series do not approach zero, the series must diverge. The test states that if lim(n->inf) an != 0, then the series diverges.
Comparison test: If the terms of a series are positive and can be compared with a known convergent or divergent series, we can determine the convergence or divergence of the given series. If an <= bn for all n and the series sum of bn converges, then the series sum of an also converges. If an >= bn for all n and the series sum of bn diverges, then the series sum of an also diverges.
Limit comparison test: If the terms of a series are positive, we can compare the given series with a known convergent series, using the limit comparison test. If lim(n->inf) (an/bn) = L, where L is a positive finite number, then both series either converge or diverge.
Ratio test: If the terms of a series approach zero and the ratio of consecutive terms approaches a limit L, then the series converges if L < 1 and diverges if L > 1. If L = 1, the test is inconclusive.
Root test: If the terms of a series approach zero and the nth root of the absolute value of the nth term approaches a limit L, then the series converges if L < 1 and diverges if L > 1. If L = 1, the test is inconclusive.
Alternating series test: If the terms of a series alternate in sign and decrease in magnitude, then the series converges.
There are also other tests, such as integral test, p-series test, and Dirichlet test, among others, which can be used to test the convergence of certain types of series.
Once we apply one of these tests and determine whether the series converges or diverges, we can then further analyze the series to find its sum, if it exists.
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