Joe bought a house for $370,000. The assessed value of
the house is $280,000. The property tax rate is 2.9%. What
is Joe's annual property tax bill for this house?

Answer:

The walking distance that is saved by cutting across the lot is approximately 18 feet.

The values of m and b after evaluation is -2 and 23 under the condition that If x=3t+t² and y=7−2t, and  tangent to the curve at t=2.

In orde to evaluate the equation of the tangent to the curve at t=2, we have to calculate the slope of the curve at t=2.
The slope of the curve at t=2 is presented by the derivative of y with respect to x at t=2.
y = 7 - 2t
x = 3t + t²
dy/dx = -2
Then, the slope of the tangent to the curve at t=2 is -2.
Now we have to evaluate the point on the curve at t=2.
x = 3(2) + (2)² = 10
y = 7 - 2(2) = 3
So, the point on the curve at t=2 is (10,3).
Applying  point-slope form of equation of line:
y - y₁ = m(x -x₁)
Here,
m = slope and (x₁,y1) is a point on the line.
Staging m=-2 and (x₁,y₁)=(10,3),
y - 3 = -2(x - 10)
Applying simplification
y = -2x + 23
Then, the equation of the tangent to the curve at t=2 is y=-2x+23.
So, m=-2 and b=23.
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The comparison data is shown below.

Based on the information provided, we can infer that:

Without more information about the specific data and the context of the study, it is difficult to make further comparisons or draw any conclusions about the relationship between completing homework and exam scores. However, it is interesting to note that completing homework did not seem to have an impact on the average exam score or the variability of exam scores.

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Answer:

C

Step-by-step explanation:

It mentions that they charge 1.20 per kg of lettuce

The speed in miles per hour is 111.2 and the direction angle in degrees is 260.2.

We are given the speed of a plane on a bearing of N [tex]75^\circ[/tex] E and its ground speed. We have to find its speed in miles per hour and the direction angle in degrees. We will apply the formula of projection for both the x-axis and y-axis.

As we know, projection, R = V + W

Now, the x-axis projection will be R cos[tex]15^\circ[/tex] according to the angle given to us. Therefore, R cos [tex]15^\circ[/tex] = V cos[tex]30^\circ[/tex] + [tex]W_{x}[/tex]

The y-axis projection,

R sin [tex]15^\circ[/tex] = V sin [tex]30^\circ[/tex] + [tex]W_{y}[/tex]

From here, now we will find [tex]W_{x}{[/tex] and [tex]W_{y}[/tex]

[tex]W_{x}{[/tex] = 330 cos[tex]15^\circ[/tex] - 390 cos[tex]30^\circ[/tex]

[tex]W_{x}[/tex] = -19 miles/hour

[tex]W_{y}[/tex] = 330 sin[tex]15^\circ[/tex] - 390 sin[tex]30^\circ[/tex]

[tex]W_{y}{[/tex] = -109.6 miles per hour

Now, W = [tex]\sqrt{(W_{x})^{2} + (W_{y})^{2{}}[/tex]

W = [tex]\sqrt{(-19.0)^{2} + (-109.6})^{2{}}[/tex]

W = 111.2 miles/hour

Now, we will find the angle with the help of tan θ.

tan θ = [tex]\frac{W_{y}}{W_{x}}[/tex]

tan θ = [tex]\frac{-109.6}{-19.0}[/tex]

θ =  [tex]tan ^{-1} (\frac{109.6}{19.0})[/tex]

θ = 260.[tex]2^\circ[/tex]

Therefore, the speed in miles per hour is 111.2 and the direction angle in degrees is 260.2.

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Answer:

the answer is C

Step-by-step explanation:

the answer is C it converges

Answer: To find the actual perimeter and area of the square, we need to use the scale given in the problem, which is 1 inch on the drawing represents 7 miles in real life.

The side length of the square on the drawing is 9 inches, so in real life, the side length would be:

9 inches x 7 miles/inch = 63 miles

Therefore, the actual perimeter of the square would be:

4 x 63 miles = 252 miles

To find the actual area of the square, we can use the formula:

area = side length x side length

In this case, the side length is 63 miles, so:

area = 63 miles x 63 miles = 3,969 square miles

So the actual perimeter of the square is 252 miles, and the actual area of the square is 3,969 square miles.

Step-by-step explanation:  can i get brainliest :D

The hexagon with sides of length 5 inches, 4 inches, 4 inches, 5 inches, 3 inches, and 3 inches has a perimeter of 24 inches.

A hexagon is a regular polygon, meaning all sides and angles are equal in size. It is a symmetrical shape, which means it can be divided into two equal halves.

To calculate the perimeter of this hexagon, we must first identify the length of each side.

All sides of the hexagon have a length of either 5 inches, 4 inches, or 3 inches, as there are two sides of each length.

The perimeter of the hexagon is the sum of the length of all its sides. Adding the length of all the sides, we get

5 + 4 + 4 + 5 + 3 + 3 = 24.

Thus, the perimeter of the hexagon is 24 inches.

Hence, the sum of the length of the sides of a hexagon is always greater than the length of any one of its sides.

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A word problem that matches the inequality -2.75 > x is:

John has a balance of $25 in his bank account and wants to withdraw some money and he needs to withdraw at least x dollars, but not more than $2.75.

A word problem that matches the inequality -2.75 > x is:

John has a balance of $25 in his bank account and wants to withdraw some money. He needs to withdraw at least x dollars, but not more than $2.75.

What is the largest possible value of x that John can withdraw and still have a positive balance in his account?

In this scenario, the variable x represents the amount that John can withdraw from his account, and the inequality -2.75 > x means that x must be less than -2.75 (i.e., negative and greater in magnitude than 2.75)

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The percentage of time that the machine will dispense from 7. 5 oz to 7. 9 oz is 62.47% of the time.

Find the Z-scores for both 7. 5 oz and 7. 9 oz :

Z = ( X - μ ) / σ

For 7. 5 oz :

Z = ( 7.5 - 7.6 ) / 0.2

Z = -0. 1 / 0. 2

Z = -0. 5

For 7.9 oz:

Z =  (7. 9 - 7.6 ) / 0.2

Z = 0. 3 / 0. 2

Z = 1. 5

Using the z - values from the table, the percentage of time is:

0.9332 - 0.3085 = 0.6247

= 62. 47 %

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Answer:

S = 2π(10^2) + 2π(10)(3)

= (200 + 60)π = 260π cm^2

So 250 cm^2 is not a reasonable answer for the surface area of this cylinder.

The length of the square with a diagonal of 32 cm is 22.6 cm.

A square is a plane shape with all sides and angles equal.

To calculate the length of the square from its diagonal, we use Pythagoras formula

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1 and solve for l

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Answer:

h=5

Step-by-step explanation:

Substituting in 92 for s,
92=4lw+2wh
Substituting in 9 for l,
92=4(9)(w)+2wh

Substituting 2 for w,

92=4(9)(2)+2(2)(h)

Simplifying by multiplying terms

92=72+4h

Subtract 72 on both sides

20=4h

Divide by 4 on both sides

5=h

Answer: Let's start by using algebra to represent the problem.

Let X be the amount of money that Kyle started with.

Then we can create the following equations:

And we know that he's out of money, so:

Substitute the first equation into the second equation to get:

Substitute the first two equations into the third equation to get:

Substitute all three equations into the fourth equation to get:

(0.5X + 36.50) + (0.25X + 9.25) + (0.25X + 4.75) = X

Simplify and solve for X:

Therefore, Kyle started with $101.

Answer:  To determine if the relationship between x and y is linear, we need to graph the data and look for a straight-line pattern.

If the graph shows a straight-line pattern, then the relationship is linear. If the graph shows a curve or a non-linear pattern, then the relationship is not linear. So it is linear

Step-by-step explanation: can i get brainliest :D

Answer:

  (a)  7(x +3.5x) = 56

Step-by-step explanation:

You want an equation to solve for x, the length of a morning run, if the evening run is 3.5 times as long, and these runs total 56 miles when done every day of the week.

The morning run is given as x.

The evening run is 3.5 times as long, so is 3.5x

The total mileage each day is (x +3.5x).

In 7 days, the mileage will be 7 times the daily mileage. That total is given as 56 miles:

  7(x +3.5x) = 56

the vertical asymptotes are x = -1 and x = 4, and there is no horizontal asymptote.

what is  vertical asymptotes  ?

Vertical asymptotes are vertical lines on a graph where a function approaches infinity or negative infinity as the input (x) approaches a certain value. In other words, vertical asymptotes occur when the denominator of a function becomes zero and the function is undefined at that point

In the given question,

To find the horizontal and vertical asymptotes of the function f(x) = 3x²/[(x+1)(x-4)], we need to analyze the behavior of the function as x approaches infinity or negative infinity and as x approaches the vertical asymptotes (if any).

Vertical asymptotes occur at the values of x that make the denominator of the fraction equal to zero. In this case, we have vertical asymptotes at x = -1 and x = 4.

To find the horizontal asymptote, we need to divide the leading term of the numerator by the leading term of the denominator when x approaches infinity or negative infinity. Since the degree of the numerator is greater than the degree of the denominator, there is no horizontal asymptote. However, we can use long division or synthetic division to write the function in the form of a polynomial plus a proper fraction:

f(x) = 3x²/[(x+1)(x-4)] = (3x + 15)/(x² - 3x - 4)

As x approaches infinity or negative infinity, the fraction approaches the value of 3/1 (the ratio of the leading terms of the numerator and denominator), but there is no horizontal asymptote.

Therefore, the vertical asymptotes are x = -1 and x = 4, and there is no horizontal asymptote.

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Answer:

The mean absolute deviation of 8,2,7,8,6,10,2,1,10,6 is 2.24.

To calculate the mean absolute deviation, we first need to find the mean of the data set. The mean is the sum of all the values in the data set divided by the number of values. In this case, the mean is 7.

Once we have the mean, we can find the mean absolute deviation by finding the absolute value of the difference between each value in the data set and the mean. For example, the absolute value of the difference between 8 and 7 is 1. We then add up all of the absolute values and divide by the number of values in the data set. In this case, the mean absolute deviation is 2.24.

Here is the formula for the mean absolute deviation:

```

MAD = (|x1 - μ| + |x2 - μ| + ... + |xn - μ|) / n

```

Where:

* MAD is the mean absolute deviation

* x1, x2, ..., xn are the values in the data set

* μ is the mean of the data set

* n is the number of values in the data set

Step-by-step explanation:

The distance from town A that they will be,  when they will pass each other is  44 4/9 .

It should be noted that time traveled in each segment is constant, which implies that in this case the average speed can be regarded as the simple mean of speeds. An in the case whereby the distance traveled in each segment is constant, average speed can be described to be the reciprocal of simple mean .

This can be expressed mathematically as

Average speed = Reciprocal [ 1/40 & 1/50].

Average speed = Reciprocal of (1/40 + 1/50)/2

= Reciprocal of [(5+4)/400]

= 44 4/9 .

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The measures of the trigonometric relations and reference angles are solved

Given data ,

Let the measure of the angle be θ = 2π/3

Now , from the trigonometric relation ,

The tangent of the function tan ( 2π/3 ) = -√3

And , the reference angle of the θ = 2π/3  is given by A = π/3

So , A = 60°

Hence , the reference angle is 60°

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Answer:

complex

Step-by-step explanation:

The given sentence "Although Kevin has money, he is not spending it." is a complex sentence.

This is because it contains one independent clause, "he is not spending it," which can stand alone as a complete sentence. The other part of the sentence, "Although Kevin has money," is a dependent clause because it cannot stand alone as a complete sentence.

The dependent clause "Although Kevin has money" introduces a contrast or concession to the independent clause that follows it. Therefore, this sentence is an example of a complex sentence that uses a dependent clause to add meaning and complexity to the independent clause.

Bisector of the angle is the line that divides the angle into two angles with the same measure. In the image attached, the bisector of the angle is represented by the green line.

Here, we have,

The next steps show you how to construct the bisector of the angle from a ruler and a compass.

Draw an arc using the vertex of the angle (O) as the center;

Mark the points A and B;

Draw an arc using the point (A) as the center;

Draw an arc, with the same radius, using the point (B) as the center. This arc should intersect the arc that you draw in the previous step.

Draw a line connecting the point C to the vertex O.

Finally, you have the bisector of the angle that is represented by the green line.

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Answer:

(x + 3)(x - 15)

Step-by-step explanation:

To factor the expression x^2 - 12x - 45, we need to find two numbers that multiply to -45 and add to -12. Let's use the method of decomposition to find these two numbers:

x^2 - 12x - 45

We need to find two numbers that multiply to -45 and add to -12. Let's try -15 and 3:

x^2 - 12x - 45 = x^2 - 15x + 3x - 45

Now we can group the first two terms and the last two terms:

x^2 - 15x + 3x - 45 = x(x - 15) + 3(x - 15)

We can see that both terms have a common factor of (x - 15), so we can factor this out:

x(x - 15) + 3(x - 15) = (x + 3)(x - 15)

Therefore, the expression x^2 - 12x - 45 can be factored as (x + 3)(x - 15).

Refer to the attachment ^-^

Hope Helpful ~

Answer:

{3, 6, 9, 12, 15}

Each of these numbers is divisible by 3

Step-by-step explanation:

Answer:

  see below

Step-by-step explanation:

Given a $3500 net income per month and a list of budget percentages, you want to know the budget amounts for each item, and the amount left over.

Each budget amount is the product of the net income and the associated budget percentage. Those products are ...

The sum of these amounts is $3500, so there will be $0 left over.

__

Additional comment

The list is stored in the variable 'b' by the first line in the calculator. Then these values are multiplied by the net income to get the budget amounts.

Answer:

711 L 936 mL

Step-by-step explanation:

3 L 456 ml times 206=711L 936mL

I hope this helps

Next, using the matching x and y values for each row of the table, we can place a point for each row and connect it to the other points using a line.

A line represents a one-dimensional straight figure that can go on forever in both directions in geometry. To separate it from a curved or an angle-filled line, it is frequently referred to as a "straight line." Two points on a line define the line, while every other position on the line may be discovered by tracing the line through the two defined points. A line can be made with a pencils or another non-thick tool, and it can have any width or depth. Shape and figures are described and analysed using lines, which are a basic building block of geometry.

given

Minutes Taught Dollars Earned (30, 12, 60, 24)

90 36

120 48

We may plot the minutes taught on the x-axis and the money made on the y-axis to graph the data from the table.

Next, using the matching x and y values for each row of the table, we can place a point for each row and connect it to the other points using a line.

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Answer:

[tex]\dfrac{\left(12x-56\right)x}{\left(x-4\right)\left(-x^2+20x-32\right)}[/tex]

Step-by-step explanation:

Simplify

[tex]\dfrac{\dfrac{16}{x-2}-\dfrac{4}{x-4}}{\dfrac{16}{x}-\dfrac{x-4}{x-2}}[/tex]

The first-level numerator is
[tex]\dfrac{16}{x-4}-\dfrac{4}{x-2}\\\\\\= \dfrac{16(x-4) - 4(x - 2)}{(x-2)(x-4)}\\\\\\= \dfrac{16x -64 - 4x + 8}{(x-2)(x-4)}\\\\\\= \dfrac{12x -56}{(x-2)(x-4)}[/tex]

The first-level denominator is
[tex]\dfrac{16}{x}-\dfrac{x-4}{x-2}\\\\\\= \dfrac{16(x-2) - x(x-4)}{x(x-2)}\\\\\\\\= \dfrac{16x - 32 -x^2 +4x}{x(x-2)}[/tex]

[tex]= \dfrac{-x^2+20x-32}{x\left(x-2\right)}[/tex]

Therefore
[tex]\dfrac{\dfrac{16}{x-2}-\dfrac{4}{x-4}}{\dfrac{16}{x}-\dfrac{x-4}{x-2}}\\\\\\= \dfrac{12x -56}{(x-2)(x-4)} \div\dfrac{-x^2+20x-32}{x\left(x-2\right)} \\\\\\[/tex]

Use the fraction rule: [tex]\dfrac{a}{b} \div \dfrac{d}{c} = \dfrac{a}{b} \cdot \dfrac{d}{c}[/tex]

[tex]= \dfrac{12x -56}{(x-2)(x-4)} \cdot \dfrac{x(x-2)}{-x^2 +20x -32}}[/tex]

The (x-2) term cancels out resulting in:
[tex]\dfrac{\left(12x-56\right)x}{\left(x-4\right)\left(-x^2+20x-32\right)}[/tex]