Answer:
5.3Km/hr
Explanation:
Velocity=Displacement/Time
D=4km;T=0.75hr
V=4/0.75=5.33..
John traveled at a speed of 5.3 km/h to get to his grandmother's house.
How is the rate of position change in relation to time measured?While velocity is the rate of change of an object's position with respect to time in a specific direction, speed is the rate of change of an object's position with respect to time overall. The speed of an item moving in a certain direction is referred to as its velocity. When there is a change in speed, direction, or both, the velocity also changes.
Given:
Time taken to travel, t = 0.75 h
Total distance travelled = 4 km
Let's imagine that John traveled to his grandmother's house in a single direction at a constant pace.
Velocity = Distance travelled in a given direction/Time
So, Velocity = 4 km/0.75 h = 5.3 ≈ 5km/h
John's speed in getting to his grandmother's residence was thus 5 km/h.
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multiples and submultiples of kg
Answer:
Submultiples of kilogram are decagram ,centigram etc. And multiples of kilogram is megagram(1 tonne) , gigagram etc.
hope this helps you:)
Two long straight parallel wires seperated by 20cm apart carry current of 20A and 1OA in opposite directions. What is the magnitude of the force on 1m length of the 20A wire
Answer:
Force is 2 × 10^-4 N
Explanation:
[tex]{ \bf{F = \frac{ \gamma_{o} I _{1} I _{2} l}{2\pi r} }}[/tex]
F is force
I is current
r is separation distance
gamma is a constant
l is wire length
[tex]F = \frac{(4\pi \times {10}^{ - 7}) \times (20) \times (10) \times 1 }{2\pi \times 0.2} \\ \\ F = 2 \times {10}^{ - 4} \: \: newtons[/tex]
The magnitude of the force on 1m length of the 20A wire is 2×10⁻⁴N.
To determine the answer, we need to know about magnetic field due to a current carrying wire and magnetic force.
What is the magnetic field produced due to a straight current carrying wire of current I₁?The magnetic field due to a straight wire having current I₁ at a perpendicular distance (say) 'd' is μ₀I₁ / 2[tex]\pi[/tex]d.
What is the magnetic force experienced by a straight wire of current I₂?Magnetic force on a current carrying wire of length 'L' and having current I₂ is I₂(L×B). Where B is the magnetic field at that wire.
What is the magnetic field on 20A wire due to 10A wire?d= 0.2m and I₁= 10AB= μ₀I₁ / 2[tex]\pi[/tex]d = 4[tex]\pi[/tex] ×10⁻⁷× 10/ 2[tex]\pi \\[/tex]×0.2 = 10⁻⁵ TWhat is the force on 20A wire?Current (I₂) = 20A, B = 10⁻⁵T and L= 1mMagnitude of force on the 20 A wire of length 1m = I₂×L×B( Here L and B are perpenicular to each other so L×B= L·B)
= 20×1×10⁻⁵
=2×10⁻⁴N
Thus, we can conclude that the magnitude of the force on 1m length of the 20A wire is 2×10⁻⁴N.
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Hey any physicist or engineer around. am giving brainliest to anyone who will answer this question.
Answer:
N = 167 Newtons
R = 727 Newtons
Explanation:
i) For static equilibrium, moments about any convenient point must sum to zero.
A moment is the product of a force and a moment arm length. Only the force acting perpendicular to a moment arm passing through the pivot point makes a moment.
ii) I will ASSUME the two moment arms are 0.05m and 0.15 m
CCW moments about the fulcrum are
190 N(0.2 m) + 280 N(0.05 m) = 52 N•m
CW moments are (N)N(0.15 m + 90 N(0.3 m) = 27 + 0.15N N•m
For static equilibrium, these must be equal
27 + 0.15N = 52
0.15N = 25
N = 166.6666666...
Sum moments about N to zero
(Same as saying CW and CCW moments must balance)
190(0.2 + 0.15) + 280(0.05 + 0.15) - R(0.15) - 90(0.3 - 0.15) = 0
R = 726.6666666...
We could verify this by summing vertical forces to zero.
R - 190 - 280 - 166.666666 - 90 = 0
R = 726.6666666...
If a horse can trot with an average velocity of 13 km/h, how far can it travel in
8 hours?
A. 2 km
B. 104 km
C. 35 km
D. 78 k
Answer:
104 km
Explanation:
Displacement = Velocity x Time
= 13 x 8
= 104 km
1. A car moving with a velocity of 10 m s-1 accelerates uniformly at 1 m s-2 until it reaches a velocity of 15 m s-1. Calculate (i) the time taken (ii) the distance traveled during the acceleration (ui) the velocity reached 100 m from the place where the acceleration began. m/sec
An astronaut floating in space is trying to use her jetpack to get back to her space station, but she is being pulled away by a nearby planet, as shown in the image below. Her jetpack provides a constant thrust of 165 N. If she angles her jetpack in such a way that it cancels out the vertical force due to the planet's gravity, what is her net horizontal force?
A. 132.6 N toward the space station
B. 53.3 N away from the space station
C. 98.5 N toward the space station
D. 112.8 N away from the space station
Answer:
C. 98.5N toward the space station
Explanation:
Fx= Fjet×cos(20) - Fplanet × cos(45) = 98.5
Because the result is positive so she is going toward the space station
Convert each of the following speed into m/sec:
(i) 72 km/h
(ii) 12.6 km/h
(iii) 23.4 km/h
(iv) 306 km/h
Answer:
(i) 20 m/s
(ii) 3.5 m/s
(iii) 6.5 m/s
(iv) 85 m/s
Explanation:
1(kilometer/hour) = 1000(meters) / 3600(seconds) can also be expressed as 1(kilometer/hour) = 5/18 (meters/second), which is its simplified form. To convert km/h to m/s, directly multiply the given value of speed by the fraction 5/18.
This information is from: https://www.cuemath.com/measurement/km-h-to-m-s/
A pulse has a speed of 5cm.s^-1. How far does it travel in 2,5s?
Answer:
12.5
Explanation:
Its 5m per second times 2.5 seconds so it's 12.5m
Answer:
[tex]\boxed {\boxed {\sf 12.5 \ centimeters}}[/tex]
Explanation:
We are asked to find how far a pulse travels or the distance. Distance is the product of speed and time.
[tex]d= s \times t[/tex]
The speed of the plus is 5 centimeters per second and the time is 2.5 seconds.
s= 5 cm/s t= 2.5 sSubstitute the values into the formula.
[tex]d= 5 \ cm/s \times 2.5 \ s[/tex]
Multiply. Note that the units of seconds will cancel each other out.
[tex]d= 12.5 \ cm[/tex]
The pulse travels 12.5 centimeters.
A plane leaves Houston and flies 400 km north to Dallas. The pilot realizes he has forgotten his
golf clubs and returns to Houston to pick them up on the way back to Houston, the plane runs
out of gas and is forced to land in Huntsville, 100 km North of Houston. The trip from Houston to
Dallas took 120 min and the trip from Dallas to Huntsville took 70 min.
A. What is the total distance (in meters) covered by the airplane?
B. What is the plane's total displacement (in meters)?
C What is the average velocity for: 190 MM
i Houston to Dallas
ii. Dallas to Huntsville
(A) The total distance covered by the plane is 500,000 m
(B) The plane's total displacement is 300,000 m
(C) The average velocity of the plane is 100 m/s
The given parameters:
initial displacement of the plane = 400 km Dallas
final displacement of the train = 100 km Huntsville
the time taken for the initial displacement = 120 min
final time for the second trip = 70 min
A sketch of the plane's trip is as follows:
Dallas
400 km ↑ ↓
↑ ↓ Huntsville 100 km
↑
↑
Houston
(A) The total distance covered by the plane:
The total distance is the total path travelled by the plane.
Total distance = 400 km + 100 km = 500 km, = 500,000 m
(B) The plane's total displacement:
The total displacement is the change in the position of the plane.
The displacement = 400 km - 100 km = 300 km = 300,000 m
(C) The average velocity of the plane
[tex]Average \ velocity = \frac{change \ in \ displacement }{change \ in \ time} \\\\Average \ velocity = \frac{400 \ km - 100 \ km}{120 \ \min - \ 70 \ \min} \\\\Average \ velocity =\frac{300 \ km}{2\ hr - 1.167 \ hr} \\\\Average \ velocity = \frac{300 \ km}{0.833 \ hr} \\\\Average \ velocity = 360.14 \ km/hr\\\\Average \ velocity = \frac{360.14 \ km/h}{3.6 \times \frac{km/hr}{m/s} } = 100 \ m/s[/tex]
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the value of mass of a body is everywhere
Explanation:
The value of mass of a body is not same everywhere.
Because it depends on gravity and the gravity isn't same at every places.
Answer:
Mass is the quantity of matter contained in a body, while weight is the force by which the body is pulled to the earth's center. Mass is an intrinsic property of a body, as it remains the same everywhere in the universe. Weight is variable due to change in the magnitude of the gravitational force applied by the earth.
Stella's respiratory system is not working well why is this a problem for her ability to exercise
Explanation:
Her cells will not work well when they have low levels of oxygen.
explain fundamental quantities in
physics
Answer:
fundamental quanties are mass , time, length, temperature , amount of substance and luminous intensity. All other physical quantity are derived quantity and be made from fundamental quanties.
Explanation:
hope it helps u
Answer:
The other person answered
Explanation:
An eccentric emu runs 20 m/s for 5 minutes for the first part of his trip to Hollywood. Once tired, the emu runs slower speed for the next hour. The average velocity of the emu is 15 m/s. what speed was the emu running when he was tired?
Answer:
14.6 m/s
Explanation:
The total run time was 5 + 60 = 65 minute or 65(60) = 3900 s
At his average velocity, emu ran 15 m/s(3900 s) = 58,500 m
Which is a heck of a running distance for ANY emu.
In the first 5 minutes the emu traveled 20 m/s(5 min)(60 s/min) = 6000 m
So in the last hour (3600 s) the emu traveled 58,500 - 6000 = 52,500 m
at a speed of 52,500 m /3600 s = 14.583333333... m/s
The emu was running at a speed of 14.58 m/s when he was tired.
To solve this question, we'll begin by calculating the distance travelled in the first part of the trip. This can be obtained as follow:
Time (t₁) = 5 min = 5 × 60 = 300 s
Speed 1 (S₁) = 20 m/s
Distance 1 (d₁) =?Speed = distance / time
S₁ = d₁ / t₁
20 = d₁ / 300
Cross multiply
d₁ = 20 × 300
Distance 1 (d₁) = 6000 mNext, we shall determine the total distance travelled by the emu.
Average speed = 15 m/s
Time 1 (t₁) = 300 s
Time 2 (t₂) = 1 h = 60 mins = 60 × 60 = 3600 s
Total time (T) = t₁ + t₂ = 300 + 3600 = 3900 s
Total distance (D) =?Average speed = Total distance / total time
15 = D / 3900
Cross multiply
D = 15 × 3900
Total distance (D) = 58500 mNext, we shall determine the distance travelled in the second part (i.e when he was tired) of the trip.
Total distance (D) = 58500 m
Distance 1 (d₁) = 6000 m
Distance 2 (d₂) =?D = d₁ + d₂
58500 = 6000 + d₂
Collect like terms
58500 – 6000 = d₂
Distance 2 (d₂) = 52500 mFinally, we shall determine the speed of the emu in the second part of the trip.
Distance 2 (d₂) = 52500 m
Time 2 (t₂) = 3600 s
Speed 2 (S₂) =?Speed = distance / time
S₂ = 52500 / 3600
S₂ = 14.58 m/sTherefore, the emu was running at a speed of 14.58 m/s when he was tired.
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Encontrar el peso de un elefante cuya masa es de 4500kg. Recordar que la gravedad es de 9.8m/s2
la respuesta es 459.183673 kg s2 / m
Answer:
44,100 N
Explanation:
4500(9.8) = 44,100
of a ball traveling 24 m in 0.6 seconds.
A baseball pitcher throws a fastball across home plate. Calculate the speed of a
baseball that takes 0.01 seconds to travel 0.30 meters across the entire length of home
plate.
Answer:
Below
Explanation:
To find the speed of an object you can use this formula
speed = displacement / elapsed time
For the first one
24 m / 0.6 seconds = 40 m/s
For the second one
0.3 m / 0.01 seconds = 30 m/s
Hope that helped
calculate the volume that 42g of nitrogen gas (N2)occupies at standard temperature and pressure.
Nitrogen gas has a molar mass of about 28.0134 g/mol. Then we have a starting amount of
(42 g) / (28.0134 g/mol) ≈ 1.4993 mol
of N₂.
At standard temperature and pressure, one mole of an ideal gas occupies a volume of about 22.4 L. Then 42 g, or 1.4993 mol, of N₂ takes up
(1.4993 mol) × (22.4 L/mol) ≈ 33.6 L
A car has four tires that are each inflated to an absolute pressure of 2.0 x 10^5 Pa. Each tire has an area of 0.024 m^2 in contact with the ground. How much does the car weigh?
a.
1.9 x 10^3 N
b.
2.9 x 10^4 N
c.
1.2 x 10^3 N
d.
1.9 x 10^4 N
Answer:
If u dig a hole 3 feet how big is that hole
Explanation:
It’s about 20 feet
Consider the mass-on-a-spring system as shown in the figure below. The spring has a spring constant of 1.81e+3 N/m, and the block has a mass of 0.988 kg. There is a constant force of kinetic friction between the mass and the floor of 1.79 N. Starting with the spring compressed by 0.172 m from its equilibrium position, how far will the block travel once it leaves the spring? (Assume that block leaves the spring at at the spring's equilibrium position, marked x=0 in the figure.
K1Answer:
s= 6.5cm
Explanation:
Point 1: just right before the block leaves the spring
Point 2: the block has v2=0 (stops moving)
Apply Kinetic-Work Theorem:
K1 + U1 + Wother = K2 + U2
K1=0
U1= 1/2×k×x² (k= 1.81e+3 N/m and x= -0.172 m)
Wother = F×s= 1.79×s
K2=0
U2=0
=> s= 6.5cm
This is my attempt to solve. Let me know if this isn't right
the precision of interferometer of wavelength of light 800 nm would be: (a) 200 nm (b) 100 nm (c) 400 nm (d) 800 nm
Answer:
Explanation:
Did this come with a Picture?
Help meh in this question plzzz
The Moment of Inertia of the Disc is represented by [tex]I = \frac{15}{32}\cdot M\cdot R^{2}[/tex]. (Correct answer: A)
Let suppose that the Disk is a Rigid Body whose mass is uniformly distributed. The Moment of Inertia of the element is equal to the Moment of Inertia of the entire Disk minus the Moment of Inertia of the Hole, that is to say:
[tex]I = I_{D} - I_{H}[/tex] (1)
Where:
[tex]I_{D}[/tex] - Moment of inertia of the Disk.[tex]I_{H}[/tex] - Moment of inertia of the Hole.Then, this formula is expanded as follows:
[tex]I = \frac{1}{2}\cdot M\cdot R^{2} - \frac{1}{2}\cdot m\cdot \left(\frac{1}{2}\cdot R^{2} \right)[/tex] (1b)
Dimensionally speaking, Mass is directly proportional to the square of the Radius, then we derive the following expression for the Mass removed by the Hole ([tex]m[/tex]):
[tex]\frac{m}{M} = \frac{R^{2}}{4\cdot R^{2}}[/tex]
[tex]m = \frac{1}{2}\cdot M[/tex]
And the resulting equation is:
[tex]I = \frac{1}{2}\cdot M\cdot R^{2} -\frac{1}{2}\cdot \left(\frac{1}{4}\cdot M \right) \cdot \left(\frac{1}{4}\cdot R^{2} \right)[/tex]
[tex]I = \frac{1}{2} \cdot M\cdot R^{2} - \frac{1}{32}\cdot M\cdot R^{2}[/tex]
[tex]I = \frac{15}{32}\cdot M\cdot R^{2}[/tex]
The moment of inertia of the Disc is represented by [tex]I = \frac{15}{32}\cdot M\cdot R^{2}[/tex]. (Correct answer: A)
Please see this question related to Moments of Inertia: https://brainly.com/question/15246709
Answer:
Help meh in this question
Explanation:
If Leslie has a hang time of 0.2 seconds, what distance did she jump?
Answer:
um.......I don't know soory
do humans have the right to alter and colonize unique environments on another planet? explain your answer.
Answer:
We may have people making habitats on asteroids ... I know that humans will colonize the solar system and one day go beyond. Richard Gott has estimated that the human race could survive for another 7.8 million years, but it is not likely to ever colonize other planets.
To be sure there are many daunting challenges facing prospective space colonists such as protection from exposure to deadly radiation levels, the impact on the human body while living and working in cramped, low-gravity environments for extended periods of time and the psychological toll of isolation and confinement.
According to me we can't colonize other planets which is against humanity
Water is flowing in a pipe with a varying cross-sectional area, and at all points the water completely fills the pipe. At point 1 the cross-sectional area of the pipe is 0.070 m^2, and the magnitude of the fluid velocity is 3.50 m/s.
Required:
a. What is the fluid speed at point in the pipe where the cross-sectional area is 0.105m^2?
b. What is the fluid speed at point in the pipe where the cross-sectional area is 0.047m^2?
c. Calculate the volume of water discharged from the open end of the pipe in 1.00hour.
Answer:
b
Explanation:
What are two benefits of scientists using a diagram to model the water cycle?
A. It can show changes that occur in many different parts of Earth at
the same time.
B. It can be used to show how the parts of the cycle relate to one
another.
C. It can be used to show as much detail as is present in the actual
water cycle.
OD. Only a few factors in the water cycle can be shown on the
diagram.
Explanation:
it can be used to show how the parts of the cycle relate to one another
a ball is thrown straight up into the air with an initial speed of 3.1 m/s. a. After 0.24 seconds what is the ball's velocity and b. what is it's acceleration?
a. The ball's velocity after 0.24 s is 0.75 m/s
b. The acceleration of the ball is given by the acceleration due to gravity
a. The ball's velocity can be calculated with the following equation:
[tex] v_{f} = v_{0} - gt [/tex]
Where:
[tex] v_{f} [/tex]: is the final speed =?
[tex]v_{0}[/tex]: is the initial speed = 3.1 m/s
g: is the acceleration due to gravity = 9.81 m/s²
t: is the time = 0.24 s
The minus sign is because the acceleration is in the opposite direction (downward) of the motion of the ball (upward).
The final speed is:
[tex] v_{f} = v_{0} - gt = 3.1 m/s - 9.81 m/s^{2}*0.24 s = 0.75 m/s [/tex]
Hence, the ball's velocity after 0.24 s is 0.75 m/s.
b. The acceleration of the ball is given by the acceleration due to gravity because the ball is thrown straight up (the motion of the ball is in the y-direction). The velocity of the ball in the x-direction is zero so the acceleration in the same direction is also zero.
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What is the average velocity of the particle from rest to 9 seconds?
OA.
1 meter/second
OB.
2 meters/second
OC.
3 meters/second
OD.
4 meters/second
Answer:
B 2m\s
Explanation:
18 m of displacement over the course of 9 seconds
18/9 = 2 m\s
The speed of light will be minimum while passing through
A) water
B) vaccum
C) air
D) glass
Answer:
The correct choice is option D. glass
Glass's optical density is very great. Which is why speed of light will be minimum when passing glass.
Answer:
glass
Explanation:
i think, sana makatulong
□: the action of an object spinning around on its □
Answer:
head gyxicjcurgcugxgox6r
A positively charged glass rod is bought close to a suspended metal needle. What
can we say about the charge on the needle given that the needle is
a) attracted ?
b) repelled ?
Answer:
attracted
Explanation:
opposite charges attract each other when the rub against each other
Answer:
This depends because the electrostatic force obeys the principle that states that force between both of the particles does not get affected by the charges of the other thus if the needle is getting attracted it possess negative charges( the opposite charge) .And if they repel it means they have the same charges ( positive charges).
A rocket of mass 40,000kg propelled by a force 10⁶N acquires a speed of 3000m/s. determine the power extended
Answer:
3×10⁹ W
Explanation:
Power = work / time
Power = force × distance / time
Power = force × velocity
P = Fv
P = (10⁶ N) (3000 m/s)
P = 3×10⁹ W