Kent multiplies both sides of the equation below by an expression. k startfraction 12 over k endfraction = 8 then he moves all the terms to one side of the equal sign in the resulting equation. which equation must he solve now? k squared minus 8 k minus 12 = 0 k squared 8 k 12 = 0 k squared minus 8 12 = 0 k squared minus 8 k 12 = 0

Answer:

OB. y= 3x - 14

Step-by-step explanation:

I'm not good at explaining, but I'm right.

Answer:

Step-by-step explanation:

Let's solve for f.

fx=

1

3

x−2

Step 1: Divide both sides by x.

fx

x

=

1

3

x−2

x

f=

x−6

3x

Answer:

f=

x−6

3x

Answer:

$52.5

Step-by-step explanation:

Since 25% is the sale, we subtract 100% (the whole) by the discount, 25%. That leads us to say that we are paying for 75% of the product's price.

We multiply $70 by 0.75 and you get $52.5!

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Answer:

I didn't understood your question. But,

I×100/P×T

Answer:

[tex]10 \frac{5}{6}\\\\5 \frac{5}{6}[/tex]

Step-by-step explanation:

[tex]5 \times 2 \frac{1}{6} \\ \\ = 5 \times \frac{13}{6} \\ \\ = \frac{65}{6} \\ \\ = 10 \frac{5}{6} \\ \\ \\ 3 \frac{1}{2} \times 1 \frac{2}{3} \\ \\ = \frac{7}{2} \times \frac{5}{3} \\ \\ = \frac{35}{6} \\ \\ = 5 \frac{5}{6} [/tex]

Consider the first radical :

[tex]{:\implies \quad \sf 5\times 2\dfrac16}[/tex]

Using the properties of mixed fraction, writing the mixed fraction as an improper fraction, we will be having

[tex]{:\implies \quad \sf 5\times \bigg(\dfrac{6\times 2+1}{6}\bigg)}[/tex]

[tex]{:\implies \quad \sf 5\times \bigg(\dfrac{12+1}{6}\bigg)}[/tex]

[tex]{:\implies \quad \sf 5\times \dfrac{13}{6}}[/tex]

[tex]{:\implies \quad \sf \dfrac{65}{6}}[/tex]

[tex]{:\implies \quad \boxed{\bf{10\dfrac56}}}[/tex]

Hence, Option D) is correct

Now, coming to the 2nd question :

[tex]{:\implies \quad \sf 3\dfrac{1}{2}\times 1\dfrac{2}{3}}[/tex]

[tex]{:\implies \quad \sf \bigg(\dfrac{3\times 2+1}{2}\bigg)\times \bigg(\dfrac{3\times 1+2}{3}\bigg)}[/tex]

[tex]{:\implies \quad \sf \bigg(\dfrac{6+1}{2}\bigg)\times \bigg(\dfrac{3+2}{3}\bigg)}[/tex]

[tex]{:\implies \quad \sf \dfrac{7}{2}\times \dfrac{5}{3}}[/tex]

[tex]{:\implies \quad \sf \dfrac{35}{6}}[/tex]

Now, Rewriting this improper fraction as mixed fraction, we will be having :

[tex]{:\implies \quad \boxed{\bf{5\dfrac56}}}[/tex]

Hence, Option C) is correct

Answer:

Step-by-step explanation:

1 is in the tenth place

[tex]\sf 1's \ value = \dfrac{1}{10}[/tex]

Answer:

Emmanuel will need 8 scoops to get 2 tablespoons

you need 12 1/2 tablespoons for 6 tablespoons

Step-by-step explanation:

Answer:

Step-by-step explanation:

I think the answer is 0-1, but i will have to see the answers to determine.

Hope it helps!

Answer:

If it is x squrared the answer would be (x+3)²+5. If it is 2 times x then it would be (2x+3)+5

Step-by-step explanation:

Answer:

50 000

Step-by-step explanation:

5 x 10 000

Answer:

22 vegetables

Step-by-step explanation:

Set the #number of molded vegatables in dumpster 1 as X

The number of molded vegetables in 2 is x + 45 and the number of molded vegies in 3 is x + 45 + 80

x + x + 45 + x + 45 + 80 = 236 (combine similar terms)

         Thats 3x = 66

Which equas 22

The value of b for the quadratic equation x2 bx 5 = 0 to have two real number solutions is -5.

The standard form of the quadratic equation is,

[tex]ax^2+bx+c=0[/tex]

The quadratic equation has two real number solutions when the value of the following equation is positive.

[tex]b^2-4ac[/tex]

The quadratic equation given in the problem is,

[tex]x^2 +bx+ 5 = 0[/tex]

The value of b has to be found out such that the equation have two real number solutions. For this equation,

[tex]a=1\\c=5[/tex]

Put this value in the above equation as,

[tex]b^2-4\times1\times5\\b^2-20[/tex]

The value of the above expression to be positive, the value of b should be at least 5 or -5.

[tex](-5)^2-20\\25-20\\5[/tex]

Thus, the value of b for the quadratic equation x2 bx 5 = 0 to have two real number solutions is -5.

Learn more about the quadratic equation here;

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Answer:

Which value of [tex]b[/tex] will cause the quadratic equation [tex]x^2 + bx + 5 = 0[/tex] to have two real number solutions?

B) -3

C) 3

D) 4

There one Thing That would got to 0 so it A) -5

Have a Nice Day .

Answer:

Step-by-step explanation:

(i) a^a + b^b

for a=3 and b= -2

3^3 + -2^(-2)

          -2^(-2) = -(1/2^2)

3^3  -(1/2^2)

27 - (1/4)

26 3/4

ii) a^b + b^a

a^b + b^a

for a=3 and b= -2

3^(-2) + (-2)^3

1/3^2 + (-2)(-2)(-2)

1/9 - 8

-7 8/9

Answer: Ken has 22 coins, some of which are dimes and the rest are quarters

Step-by-step explanation:Step 1. Let x be the number of dimes and let 25-x be the number of quarters.

Step 2. Let 0.10x be the total cost for x number of dimes

Step 3. Let 0.25(25-x) be the total cost for 25-x number of quarters.

Step 4. Since the man has $4.60, then 4.60=0.10x+0.25(25-x). Solving for x yields the following steps

By using Pythagoras theorem.

Therefore ML= 17...

Step-by-step explanation:

Hope it helps....Mark me brilliant

The area of a trapezium with the given dimensions is: 198 cm²

Area of a trapezium = 1/2(a + b)h, where h is the heght of the trapezium and a and b are the length of its bases.

Given the following:

Area of a trapezium = 1/2(12 + 21)12

Area of a trapezium = 198 cm²

Learn more about the area of trapezium on:

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Expand the target expression:

A sin(x + ϕ) = A (sin(x) cos(ϕ) + cos(x) sin(ϕ)) = -2 sin(x) + 4 cos(x)

Then we have

A cos(ϕ) = -2

A sin(ϕ) = 4

Recall that sin²(x) + cos²(x) = 1 for all x. Then

(A cos(ϕ))² + (A sin(ϕ))² = (-2)² + 4²

A² (cos²(ϕ) + sin²(ϕ)) = 4 + 16

A² = 20

A = √20 = 2√5

Also recall that tan(x) = sin(x)/cos(x) by definition. Then

(A sin(ϕ)) / (A cos(ϕ)) = 4 / (-2)

tan(ϕ) = -2

ϕ = arctan(-2) = -arctan(2)

Answer:

Range:-4 is less then Y is less then 9. Domain: -5 is less then x is less then 4

Step-by-step explanation:

Look at where the lines end. That will help you find where the domain and ranges are.

Answer:

The eagle by 130 feet

Step-by-step explanation:

you plug it in and then find the difference

Answer:

the patters is that they are multiple of 7.. so next number is 42.

which means option D The missing number is even is correct..

Answer:

23.5

Step-by-step explanation:

So this is a parallelogram so the area formlula is b*h=47? That's a no go. It is saying that if the base is 1/4th and the height is increasing by 2 so basically 1/4b*2h=1/2bh bh so it will be represented as 47 so 1/2*47=23.5

Answer:

14 is the discount

56 is discounted price.

Answer:

4(5+8)

Step-by-step explanation:

The GCF of 20 and 32 is 4. Then you divide 20 and 34 by 4.

Answer:

1.7507

Step-by-step explanation:

See Image

Answer:

8xy³(2y²+7)

Step-by-step explanation:

[tex]( \frac{16 {x}^{2} \times 2 {y}^{5} }{4x {y}^{2} } + 28xy) \times 2 {y}^{2} \\ = (8x {y}^{3} + 28xy) \times 2 {y}^{2} \\ = (4xy(2 {y}^{2} + 7)) \times 2 {y}^{2} \\ = 8x {y}^{3} (2 {y}^{2} + 7)[/tex]

Answer:

i think 31

Step-by-step explanation:

Tamora’s total finance charge was $3,403.53 if Tamora paid in addition of $939.25 in service charges option (c) is correct.

It is defined as the interest on the principal value or deposit and the interest which is gained on the principal value in the previous year.

We have:

Principal amount(Loan principal) = $10,675

Interest rate  = 4.75 %

Monthly rate = 4.75/12% ⇒0.39583% ⇒ 0.00395

Additional amount she paid in service charge = $939.25

Number of months = 9×12 = 108 months

We can find the total finance charge as follows:

Finance charge = Total amount repaid +service charge - Loan principal

The formula for the monthly payment of the loan is given by:

[tex]\rm Monthly \ payment = \frac{Loan \ principal }{\frac{(1-(1+r)^-^n)}{r} }[/tex]

[tex]\rm Monthly \ payment = \frac{10675}{\frac{(1-(1+0.00395)^-^{108})}{0.00395} }[/tex]    

After calculating, we get:

Monthly payment = $121.66

For 108 months, Tamora paid:

= 121.66×108

= $13,139.23

The finance charge will be:

= $13,139.23+$939.25-$10,675

= $3,403.53

Thus, Tamora’s total finance charge was $3,403.53 if Tamora paid in addition of $939.25 in service charges option (c) is correct.

Learn more about the compound interest here:

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Area of the figure is 171 cm²

See the attachment......

Area of triangle:-

Area of square:-

Area of rectangle:

Total:-