Answer:
it must be 2983548×2............
If 3,k,w,18 are in AP. Find the value of 3k + 4W
9514 1404 393
Answer:
76
Step-by-step explanation:
For some common difference d, the terms of the progression are ...
k = 3 +d
w = k +d = 3 +2d
18 = w +d = 3 +3d
Solving for d, we get ...
15 = 3d . . . . subtract 3
5 = d . . . . . . divide by 3
Now, we can find ...
3k +4w = 3(3 +d) +4(3 +2d) = 9 +3d +12 +8d = 21 +11d
3k +4w = 21 +11(5) . . . . substitute for d
3k +4w = 76
Find the area of the sector of a circle with diameter 32 feet and an angle of 7Pi/4
radians.Round your answer to four decimal places.
Answer:
703.7168 ft²
Step-by-step explanation:
Use the sector area formula, a = 1/2r²θ
If the diameter is 32 feet, then the radius is 16 feet.
Plug in the radius and angle measure into the formula, and solve:
a = 1/2r²θ
a = 1/2(16)²(7[tex]\pi[/tex]/4)
a = 703.7168
So, the area of the sector is 703.7168 ft²
68 rounded to the nearest hundred
Answer:
100
Step-by-step explanation:
anything lower then 4 stays anythiing 5 or higher is rounded
so this also works with 40 50 400 500 4000 5000, you gte the point
oodluck on your test or homework! :)
please help and show work pls!!!
9514 1404 393
Answer:
a) see attached
b) Each successive figure has one more tile at the end of each leg.
c) 201, the number of tiles is 2n+1 for figure n.
Step-by-step explanation:
a) The attachment shows the next two figures
__
b) The pattern adds one more tile at the end of each leg than the previous figure had. This rule matches the figures shown.
__
c) The rule found in part B means that Figure N will have 2N+1 tiles, the N tiles in each leg plus the one where the legs meet.
Figure 100 will have 2(100) +1 = 201 tiles
Please answer maths question! Photo is easier to read
Answer:
Step-by-step explanation:
152
Johannesburg is is 3/5 as tall as his sister. Johannesburg is 90cm tall. How tall is his sister
Johannesburg's sister is 54cm tall
Explanation:
3/5 = 0.6
0.6 * 90 = 54
54 is 3/5 of 90, therefore Johannesburg's sister is 54cm tall
Select all of the answers below that are equivalent to G = {Nelson, Niven, Lazenby, Dalton, Moore, Brosnan, Connery, Craig}
Answer:
Step-by-step explanation:
Can we get the Answer's to see. Thanks.
Write the fraction 16/28 in simplest form.
Answer:
1/4
Step-by-step explanation:
the numeral 16 is a _____ of 4 because it is the product of a given number sbd any whole number
Answer:
perfect square
Step-by-step explanation:
A perfect square is a number multiplied by itself:
16 = 4^2 = 4 * 4
Hello i need help please
Find two points points on x-axis which are at a distance of 5 units from (5,5).
Answer: (10,5) and (0,5)
Step-by-step explanation:
In a class of 80 students in Debre Berhan University, 45 are good in mathematics, 15 are good in both mathematics and English, 13 are good in both Mathematics and Psychology, 16 are good in both English and Psychology only,20 are good in Psychology and 9 are good in both of the three course,then how many students are good in mathematics?
Step-by-step explanation:
No of Student in Debre Berhan University - 80 students
No of student good in mathematics - 45 student'sNo of students good in mathematics and English -15
No of students good in mathematics and psychology -13No of students good in English and psychology -16No of students good in psychology -20no of student good in mathematics -45+15+13
-75therefore no of student good in math is 75 .
pls mark me branilest
-5 देखि+5सम्म कतिवटा पुर्ण सङ्ख्याहरु छन् ?
Answer:
-5,-4,-3,-2,-1,0,1,2,3,4,5
-5 देखि+5सम्म 11 पुर्ण सङ्ख्याहरु छन्
mark me as brainliest
It takes 60 pounds of seed to completely plant a 7-acre field. How many acres can be planted per pound of seed?
Answer:
7/60 acres
Step-by-step explanation:
60 pounds of seed = 7 acres
We want to find acres per pound of seed, so we want to make one side of the equation equal to 1 pound of seed. To do this, we can divide both sides by 60, as anything divided by itself equals 1. We thus have
60/60 pounds of seed = 7/60 acres
1 pound of seed = 7/60 acres
Calculate the perimeter of a triangle with the following measurements: 200 mm, 40 cm and 400 dm Please HELP
Answer:
640 dm
Step-by-step explanation:
200+40+400=640dm
Reduce 6x /12x is it 1/2
Answer:
tero bau ko tauko got it sjdhhrurjrbr
Answer:
LHS=6x/12x=6/12=1/2
RHS=1/2
LHS=RHS
Which three of the paper strips can be used to form a triangle?
Question 1. 2cm, 3cm, 5cm, 7cm
Question 2. 7cm, 7cm, 12cm, 19cm
Step-by-step explanation:
1. 3cm, 5cm, 7cm
2. 7cm, 7cm, 12cm
Miguel's coffee shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Miguel $5.95 per pound, and Type B coffee costs $4.65 per pound. This month's blend used three times as many pounds of Type B coffee as Type A, for a total cost of $796.00. How many pounds of Type A coffee were used?
Answer: 40 lb of Type A
Step-by-step explanation:3 pounds of Type B and 1 pound of Type A will give 4 pounds of mix at a cost of ... 3($4.65) +($5.95) = $19.90Then $796 is the cost equivalent of 796/19.90 = 40 times that 4-lb mix. Since each instance of that 4-lb mix has 1 lb of Type A, $796 worth of blend has 40 lb of Type A coffee._____Additional commentIf you'd like to do this using a variable, you can let 'a' represent the amount of Type A coffee used. Then (3a) is the amount of Type B, and the total cost is ... 5.95a +4.65(3a) = 796 19.90a = 796 . . . . . . . . simplify a = 796/19.90 = 40 . . . as above___There will be 120 lb of Type B coffee in that amount of blend.
The amount of Type A coffee that were used is 40 pounds.
What are word problems in Algebra?Word problems in Algebra can be solved by correctly identifying the parameters given and the one(s) meant to be solved with the appropriate use of arithmetic operations.
From the given information;
Type A coffee costs Miguel $5.95 per poundType B coffee costs $4.65 per pound.For this month, the equation can be expressed as:
A + 3AThus;
5.95A + 3(4.65)A = 796.005.95A +13.95A = 796.0019.9A = 796.00A = 796.00/19.9A = 40Therefore, we can conclude that the amount of pounds of type A coffee that were used is 40 pounds.
Learn more about word problems here:
https://brainly.com/question/21405634
Need help with solving please
Answer:
x=8
Step-by-step explanation:
4 ^(1/2x) = 256
Rewriting 256 as a power of 4
4 ^(1/2x) = 4^4
Since the bases are the same, the exponents are the same
1/2x = 4
Multiply each side by 2
1/2x *2 = 4*2
x=8
If there are 2.54 centimeters in 1 inch, how long in inches is a meter stick? Hint: There are 100 centimeters in 1 meter. Round your answer to the nearest hundredth.
Answer:
i dont know that well but i do know 1 meter is roughly 2ft, so id say about 25.5 inches
0.01 inch is the length of a meter stick.
To find the length of a meter stick in inches, we can use the conversion factor:
1 meter = 100 centimeters
1 inch = 2.54 centimeters
We can set up the proportion:
1 meter / 100 centimeters = x inches / 1 inch
Cross-multiplying:
1 meter × 1 inch = 100 centimeters × x inches
x = (1 meter × 1 inch) / (100 centimeters)
x = 1 inch / 100
x = 0.01 inch
To learn more on Conversion factor click:
https://brainly.com/question/32020768
#SPJ6
Any recurring sequence of points above and below the trend line lasting less than one year can be attributed to the cyclical component of the time series.
a. True
b. False
a number is multipilied by 6, and that the sum is equal to the product of 2 and 19. find the number
Answer:
[tex]take \: the \: number = x \\ thenx \times 6 = 2 \times 19 \\ \\ 6x = 38 \\ x = \frac{38}{6} \\ x = 6.33 \\ thank \: you[/tex]
You share Packet of 56 jelly beans with your sister in the ratio 4:3 how many jelly beans will you get?
I'll get 32 jelly beans
Amount of jelly beans shared = 56
My fraction = 4/(4+3) = 4/7
My sister's fraction = 3/(4+3) = 3/7
The number of jelly beans that I'll get will then be:
= My fraction × Number of jelly beans
= 4/7 × 56
= 4 × 8
= 32
Therefore, I'll get 32 jelly beans
Read related link on:
https://brainly.com/question/24159535
R varies directly as S and inversely as T. if R = 8 when S = 4 and T = 3, then R is equal to
Answer:
R = 6S/T
Step-by-step explanation:
R ∝ S/ T
》R = kS/ T
》k = RT/ S
If R = 8 when S = 4 and T = 3
then, k = (8 × 3)/ 4
k = 6
∴ R = (6 × S)/ T
Find the value of x.
How would you write 5x5x5x5x5x5 in exponential form
Answer:
5^6
Step-by-step explanation:
This is because the exponent is how many numbers are in the multiplication equation, in this case, five. Because there are six five's being multiplied together, our exponent is six.
please solve this question i need help
Answer:
a=50
b=130
c=130
Step-by-step explanation:
2a-50=a(vertically opposite angles)
a=50
a+c=180(angles on straight line)
50+c=180
c=180-50=130
b=c(vertically opposite angles)
b=130
3- 22
Choose the expressions which are equivalent to the given expression
A. 3- (-22)
B. 3- (+22)
C. 3 + (-22)
D. 22 - 3
E. 22 + 3
F. -22-3
G. - 22 + 3
H. 22 +(-3)
Answer:
» B. 3- (+22) and C. 3 + (-22)
» A. 3- (-22) and E. 22 + 3
» D. 22 - 3 and H. 22 +(-3)
Step-by-step explanation:
[tex].[/tex]
Answer:
3 - (+22)
3 + (-22)
-22 + 3
Step-by-step explanation:
38) The length of a rectangle is 15.6 cm correct to 1 decimal place.
The width of a rectangle is 3.8 cm correct to 1 decimal place.
Calculate the lower bound for the perimeter of the rectangle.
Answer:
38.75
Step-by-step explanation:
perimeter = 2(15.6+3.8) =38.8
lower bound = the smallest value that would round up to the estimated value =38.75
Find the curl of ~V
~V
= sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k
Given
[tex]\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k[/tex]
the curl of [tex]\vec v[/tex] is
[tex]\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k[/tex]
[tex]\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k[/tex]
[tex]\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k[/tex]