Let alpha = phi/2008 . Find the smallest positive integer n such that 2 [cos(alpha) sin(alpha) + cos (4 alpha) sin (2 alpha) + cos (9 alpha) sin (3 alpha) +.....+ cos (n^2 alpha) sin(n alpha)] is an integer

Answer:

180 possible arrangements

Step-by-step explanation:

To find the number of different arrangements possible when Jim hangs 4 pictures in a row from a set of 6 pictures, we can use the permutation formula:

nPr = n! / (n - r)!

where n is the total number of items in the set (in this case, 6), and r is the number of items being chosen (in this case, 4).

Substituting the values, we get:

6P4 = 6! / (6 - 4)!

= 6! / 2!

= (6 x 5 x 4 x 3 x 2 x 1) / (2 x 1)

= 360 / 2

= 180

Therefore, there are 180 different arrangements possible when Jim hangs 4 pictures in a row from a set of 6 pictures.

Answer:

Step-by-step explanation:

24

Answer:

Hope this is what you were looking for :)

Step-by-step explanation:

tan = opposite/adjacent

IF YOU DONT NEED TO FIND THE VALUES OF THE SIDES:

tan A =  [tex]\frac{x}{11}[/tex]

tan B = [tex]\frac{11}{x}[/tex]

Replace the x for whatever the value of BC is or if it doesn't have a value, you can just leave it as x.

IF YOU DO NEED TO FIND THE VALUES OF THE SIDES:

tan 45 = 1

tan 45 =  [tex]\frac{BC}{11}[/tex]

(11) tan 45 = BC

BC = 11

tan 45 = [tex]\frac{11}{AC}[/tex]

AC = [tex]\frac{11}{tan 45}[/tex]

AC = 11

This can also be done without using tangent from taking a look at special right triangles.

In 45-45-90 triangles, the two legs are the same size while the hypotenuse is equal to one of the legs multiplied by [tex]\sqrt{2}[/tex]. In doing this, we can find that both legs are 11 and the hypotenuse is [tex]11\sqrt{2}[/tex].

Answer:

The answer to your problem is, [tex]16cm^{2}[/tex]

Step-by-step explanation:

Sophie has a small cube shaped box.

Volume of the box is [tex]64cm^{3}[/tex]

We have to find the area of one face of the box.

Let one side of the box is x

Then volume = [tex]x^{3}[/tex] = 64

x³ = 4³

= 4

Now area of one face of the cube = x²

then area = 4² = 16 cm²

Thus the answer to your problem is, [tex]16cm^{2}[/tex]

The x is a specific value that the variable can take on.

A random variable is a variable that has a numerical value, which is determined by the result of a random experiment. The numerical value is determined by a set of probabilities, which are associated with each possible outcome of the experiment. Random variables can be classified as discrete or continuous, depending on the type of outcomes that they can have. Examples of random variables include the number of heads in a series of coin tosses, the time until a traffic light changes from red to green, and the height of a randomly selected person.The randomness of a random variable comes from the fact that the outcome of the experiment that it represents is uncertain. The uncertainty arises because the experiment is subject to the effects of chance, rather than being completely determined by fixed physical laws or other deterministic factors. Because of this, it is not possible to predict with certainty what the value of a random variable will be, even if we know the probabilities associated with each possible outcome.There are many different notations that can be used to represent random variables, depending on the context and the preferences of the person using the notation. Some of the most common notations include X, Y, and Z, as well as Greek letters such as µ, σ, and ρ. When a random variable is discrete, it is often represented using a probability mass function, which is denoted by P(X=x), where x is a specific value that the variable can take on. When a random variable is continuous, it is often represented using a probability density function, which is denoted by f(x), where x is a specific value that the variable can take on.

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Answer:

We can use the given equation to find the expected LSAT score (S) for a student who studies for 10 hours:

S = 130 + 2.2h

S = 130 + 2.2(10)

S = 130 + 22

S = 152

Therefore, if a student studies for 10 hours, we would expect her LSAT score to be 152.

On peut commencer par utiliser la formule suivante pour calculer la distance parcourue par le pigeon voyageur :

distance = vitesse x temps

où la vitesse est donnée en km/h, le temps en heures et la distance en km.

Dans ce cas-ci, la vitesse est de 84 km/h et le temps de voyage est de 1h45, soit 1.75 heures. On peut donc calculer la distance parcourue par le pigeon :

distance = 84 km/h x 1.75 h = 147 km

Donc, la distance entre Ousmane et Arnaud est de 147 km.

Answer:

11/7: +9.42

Step-by-step explanation:

If f(x) is a functiοn and f(1) = 5, then  f(1) = 1 cοuId nοt be true.

Thus οptiοn a is cοrrect.

A functiοn is a reIatiοn between twο sets, caIIed the dοmain and the range, such that fοr each eIement in the dοmain, there is exactIy οne eIement in the range. A functiοn maps each eIement in the dοmain tο a unique eIement in the range.

In οther wοrds, a functiοn is a ruIe οr a fοrmuIa that assοciates each input vaIue with a unique οutput vaIue. The input vaIues are the dοmain οf the functiοn, and the οutput vaIues are the range. Functiοns are οften denοted by a symbοI such as f(x), where x is an eIement in the dοmain and f(x) is the cοrrespοnding eIement in the range.

In mathematicaI anaIysis, the generaI cοncept οf functiοn, appIicatiοn οr mapping refers tο a ruIe that assigns tο each eIement οf a first set a singIe eIement οf a secοnd set.

Using this definitiοn, severaI eIements οf the dοmain can resuIt in the same eIement οf the range οf the functiοn.

But, the same eIement οf the dοmain, can nοt have different vaIues οf the range οf the functiοn.

Therefοre, the fοIIοwing expressiοn can nοt be true:

f (1) = 1

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Complete Question:

If f(x) is a function and f(1) = 5, then which of the following could not be true?

a. f(1) = 1

b. f(2) = 1

c. f(5) = 5

Answer:

x=10

Step-by-step explanation:

x2=20

2*x=20

2*10=20

so, x=10

Fatouma lifted 1 kg during the first week and 120 kg during the tenth week. Fatouma lifted 120 kg in 10 weeks, increasing by 2 kg each week.

Linear equations are the equations of degree 1. It is the equation for the straight line. The standard form of linear equation is ax+by+c =0, where a ≠ 0 and b ≠ 0

Say the mass Fatouma lifted during the first week "x". According to the problem, she increases the weight she lifts by 2 kg every week. So, the mass of second week is "x + 2" kg, during the third week is "x + 4" kg, and so on.

Since there are 10 weeks of training, the mass she lifted during the 10th week is:

x + (10 - 1) × 2 = x + 18

We also know that during the 10th week, she lifted 120 kg. So, we can set up an equation:

x + 18 = 120

Solving for x, we get:

x = 102

Thus, Fatouma lifted 102 kg during the first week of training.

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Answer: No

Step-by-step explanation:

Because the length of the box is shorter than the length of the club

20in<26in

The width of the box is also shorter than the width of the club

13in<16in

The height of the box is also shorter than the height of the club

11in<16in

But what about putting it at an angle?

So we know  [tex]a^{2} +b^{2} =c^{2}[/tex]

so let's try [tex]20^{2} +13^{2} =x^{2}[/tex]

                               [tex]x^{2}[/tex]=569

                               [tex]x=\sqrt{159}[/tex]

x is near 23.85 in, but 23.85<26. So no.

Answer: 3

Step-by-step explanation:

9/3=3

24/3= 8

30/3=10

By using equation in two variable we need to use 2 eggs to make all the cookies with 1.33 cups of butter.

To make six dozen cookies, the recipe calls for two cups of butter and three eggs. We can use proportionality to solve this question: If 2 cups of butter require 3 eggs to make 6 dozen cookies, then 1.33 cups of butter require x eggs to make all of the cookies.

x eggs = (1.33 cups of butter x 3 eggs)/(2 cups of butter). x = 1.99 eggs. Since we cannot use .99 eggs to make cookies, we would need to round up to the nearest whole number of eggs.

Therefore, we need to use 2 eggs to make all the cookies with 1.33 cups of butter.

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Giovanna deposited $1600 into two accounts, half in First Oak and half in West United.

Interest earned in First Oak account after 5 years at 6% simple interest:

= 0.06 x $800 x 5

= $240

Interest earned in West United account after 5 years at 5% compounded annually:

= $800 x (1 + 0.05)^5 - $800

= $800 x 1.27628 - $800

= $221.02

Total interest earned in both accounts:

= $240 + $221.02

= $461.02

Therefore, Giovanna will have earned $461.02 in interest from both accounts at the end of 5 years.

Answer:

c

Step-by-step explanation:

Option E is incorrect in light of the provided assertion, and only options A,B,C, and D are acceptable.

Probability is simply the chance that something will happen. We can discuss the likelihood of various outcomes when we are unable to foresee how an incident will unfold.

The probability of drawing a blue cube is 11/25, the probability of drawing a red cube is 6/25, and the probability of drawing a green cube is 8/25. Since we are replacing the cube after each draw, each draw is independent and follows the same probability distribution.

To find the expected number of times we would pull a certain color cube, we can simply multiply the probability of drawing that color cube by the total number of draws:

Expected number of blue cube draws: (11/25) x 200 = 88 times. So option A is correct.

The probability of drawing more red cubes than blue cubes is a bit more complicated to calculate, but it can be done by summing the probabilities of drawing 0, 1, 2, 3, 4, 5, or 6 blue cubes and 6, 5, 4, 3, 2, 1, or 0 red cubes. However, it is easier to notice that the probability of drawing more red cubes than blue cubes is the same as the probability of drawing more blue cubes than red cubes, which is 1/2 since both events are equally likely. Therefore, option B is correct.

Expected number of green cube draws: (8/25) x 200 = 64 times. So option C is correct.

Expected number of blue cube draws: (11/25) x 200 = 88 times. So option D is correct.

Expected number of red cube draws: (6/25) x 200 = 48 times. So option E is not correct since it expects less than 48 red cube draws.

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Rounding to the nearest thousandth means rewrite the number and deleting all digits to the right of the rounded number. The percentage value for 165.1% of 384.7 is equals to the 42.917%.

In mathematics, a percentage is a number that represents a fraction of hundred. We have to calculate the value of 165.1% of 384.7. Percentage solution with steps:

Step 1: We make the assumption that 384.7 is 100% since it is our output value.

Step 2: We next represent the value we need with x. From step 1, it follows that 100% = 384.7.

Step 3: In the same sense, x% = 165.1.

Step 5: Now, we have a pair of simple equations:

100% = 384.7 --(1).

x% = 165.1 ---(2).

Step 6: By simply dividing equation (1) by equation 2 and taking note of the fact that both the LHS (left hand side) of both equations have the same unit (%); we have 100% /x% = 384.7/165.1.

Step 7: Taking the inverse or reciprocal in both sides, x% / 100% = 165.1/384.7

=> x = ( 165.1/384.7) × 100

=> x = 42.91655835716 ~ 42.917 (round to the nearest thousandth). Therefore, 165.1 is 42.917% of 384.7.

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The solution to the system of equations is (2, 1). To find this solution, we must first solve the first equation, Y < 2x + 3, for x.

Subtracting involves taking the difference between two numbers. It is the opposite of addition and is represented by the '-' sign.

We can do this by subtracting 3 from both sides of the equation, which gives us Y - 3 < 2x.

We then divide both sides of the equation by 2, which gives us

Y - 3/2 < x.

Next, we must solve the second equation, x + y ≥ 3, for y. To do this, we subtract x from both sides of the equation, which gives us y ≥ 3 - x.

Finally, we must set both equations equal to each other,

Y - 3/2 = 3 - x.

We can then solve for x by adding 3/2 to both sides of the equation, which gives us

x = 2.5.

We can then plug this value for x into the second equation, which gives us y ≥ 3 - 2.5.

We then solve for y by subtracting 2.5 from both sides of the equation, which gives us y = 0.5.

Since the value for x must be less than 4, we must round down the value of x to 2. This means that the solution to the system of equations is (2, 1).

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Answer:

Step-by-step explanation:

8

The height of the roof is approximately 21.6 feet, to the nearest tenth of a foot.

To calculate the height of the roof, we need to use the formula for the volume of a prism with a triangular base. This is given by V = 1/3 B h, where B is the area of the base and h is the height of the prism.
In this case, we know that the base is an equilateral triangle with side length 25 feet. The area of an equilateral triangle with side length s is given by A = √3/4 s². Therefore, the area of the base of the prism is:
B = √3/4 (25 ft)²
B = 25√3/4 ft²
Now, we need to use the model to determine the height of the prism. We can do this by measuring the height of one of the triangular faces. The model is not provided, so I cannot provide specific measurements. However, we can use the Pythagorean theorem to relate the height of the triangular face to the height of the prism:
h² = (25 ft)² - (1/2 s)²
h² = 625 ft² - (1/2 (25 ft))²
h² = 625 ft² - 156.25 ft²
h² = 468.75 ft²
h ≈ 21.6 ft
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Answer:

All the expressions except d are polynomials.

The combined area of the four removed triangles is 48 sq.units. Answer: 48

We need to find out the combined area of the four removed triangles, in square units. Given: AB = 12 units.

Let's consider the given square, and let's draw an altitude BD and also draw perpendiculars to BD from the three vertices A, C and D.

Let AB = x cm. Area of square = x² sq.cm.

Now, we are cutting a triangle with base x and height x, which is a right-angled triangle. Hence, area of each removed triangle = (1/2) * x * x = (x²/2) sq.cm.

Now, BD = x/√2. Area of rectangle = AB * BD = 12 * 12/√2 = 72√2 sq.cm.

Now, area of 4 triangles = (x²/2) + (x²/2) + (x²/2) + (x²/2) = 2x² sq.cm.

We know that, Area of rectangle = Area of 4 triangles + Area of square => 72√2 = 2x² + x² => 72√2 = 3x² => x² = 24√2 cm² => x = √(24 * 2) cm = √(48) cm = 4√3 * √2 cm.

Area of 4 triangles = 2x² sq.cm = 2 * 24 cm² = 48 sq.cm.

Hence, the combined area of the four removed triangles is 48 sq.units. Answer: 48.

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The required sides of kite are √61, √61, √221 and √221 units.

According to the Pythagoras theorem, the square of the hypotenuse in a right-angled triangle equals the total of the squares of the other two sides. The formula for this theorem is c² = a² + b², where c is the hypotenuse and a and b are the triangle's two sides. Pythagoras theory triangles are another name for these triangles.

In ΔAOD

AD = [tex]\sqrt{5^2+6^2} = \sqrt{61}[/tex] units

In ΔAOB

AB = [tex]\sqrt{5^2+6^2} = \sqrt{61}[/tex] units

In ΔBOC

BC = [tex]\sqrt{5^2+14^2} = \sqrt{221}[/tex] units

In ΔDOC

DC = [tex]\sqrt{5^2+14^2} = \sqrt{221}[/tex] units

Thus, required sides of kite are √61, √61, √221 and √221 units.

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Answer:

6n-6 or 6(n-1)

Step-by-step explanation:

six times a number, n, can be shown as 6n. "Six less" indicates -6. So combining the two parts leaves 6n-6. This can be simplified to 6(n-1)

Answer:

"Mrs. Lennox is the worst mother imaginable, and everybody knows it."

Step-by-step explanation:

The first one uses "described", therefore isn't a personal opinion.

The second uses quotations, so isn't a personal opinion.

The third doesn't have any sort of opinion or connotation.

Therefore it must be the last one.

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1: The measure of arc JML is: arc JML = 176°

3: m∠WXY = 59°

5: The measure of the arc is: arc FE = 54°

7: The measure of the angles are: m∠A  = 79° and m∠B  = 112°

9: The value of x is: x = 9

No. 1

The measure of inscribed angle is half the measure of its intercepted arc. That is:

∠ JKL = 1/2 * arc JML

88 = 1/2 * arc JML

arc JML = 2 * 88

arc JML = 176°

No. 3

arc WY =  360 - 86 - 156 = 118° (sum of angles in a circle)

m∠WXY = 1/2 * arc WY

m∠WXY = 1/2 * 118

m∠WXY = 59°

No. 5

An angle inscribed in a semicircle is a right angle. Thus, m∠DFE = 90°

m∠EDF = 180 - 90 - 63 = 27° (sum of angles in a triangle)

m∠EDF  = 1/2 * arc FE

27°  = 1/2 * arc FE

arc FE = 2 * 27

arc FE = 54°

No. 7

The opposite angle in a cyclic quadrilateral add up to 180°. That is:

m∠A + m∠C  = 180°

m∠A + 101 = 180

m∠A  = 180 - 101

m∠A  = 79°

m∠B + m∠D  = 180°

m∠B + 68 = 180

m∠B  = 180 - 68

m∠B  = 112°

No. 9

67 = 1/2 * (16x - 10)

67 * 2 = (16x - 10)

16x - 10 = 134

16x  = 134 + 10

16x = 144

x = 144/16

x = 9

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The mean of the sample means is equal to the population mean.

The mean of the sample means is the average of all sample means taken from the population. It is an estimate of the population mean. The sample mean is calculated by taking the sum of all values in the sample and dividing it by the sample size. The mean of the sample means is equal to the population mean, as all sample means come from the same population and therefore have the same mean. It is not affected by the sample size or the population standard deviation. Therefore, the mean of the sample means is equal to the population mean.

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The probability that all 6 flips result in heads is 1/64

The given coin is flipped 6 times. The number of heads and tails could vary from 0 to 6.Let H be the number of heads and T be the number of tails. Then the possible values of H and T are, H=0 and T=6 H=1 and T=5 H=2 and T=4 H=3 and T=3 H=4 and T=2 H=5 and T=1 H=6 and T=0

For the given question, it is given that more heads are flipped than tails.So the possible values of H are 4, 5 and 6.So the total number of possible outcomes with more heads than tails is the sum of the possible outcomes with 4, 5 and 6 heads which is, 1+6+15 = 22 (from the combinations formula)Now, the probability that all 6 flips result in heads, given more heads are flipped than tails is,

P(all 6 are heads) = P(H > T) × P(all 6 are heads | H > T)P(H > T) = 22/64

P(all 6 are heads | H > T) = 1/21 (there is only one possibility where all 6 flips are heads)

P(all 6 are heads) = P(H > T) × P(all 6 are heads | H > T) = (22/64) × (1/21) = 1/64

Therefore, the probability that all 6 flips result in heads, given more heads are flipped than tails is 1/64.

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Therefore , the solution of the given problem of ordered pair comes out to be the ordered pair (1, 1/2).

"Ordered pairs" are two separate variables that are arranged in a way that suggests a specific sequence. The coordinates for x and y in an order pair are represented, respectively, by the main and second components. The sample following uses close parentheses to indicate the ordered combination.

Here, The formulae are as follows:

=>y = -z + 2      ...(1)

=> y = -2x² + z + 1  ...(2)

Equation (1) can be substituted for equation (2) to find the value of z:

=> Z = x² + 1/2 - z + 2 = -2x² + z + 1

=> 2z = 2x² + 1

We can now enter this value of z into equation (1) and find the value of y:

=> y = -z + 2

=> y = -(x² + 1/2) + 2

=> y = -x² + 3/2

As a result, the equation system can be expressed as:

=> z = x² + 1/2

=> y = -x² + 3/2

When x=0:

=> z = 0² + 1/2 = 1/2

=> y = -0² + 3/2 = 3/2

Therefore, there is no answer for the ordered pair (0, 3/2).

When x=1:

=> z = 1² + 1/2 = 3/2

=> y = -1² + 3/2 = 1/2

The answer is the ordered pair (1, 1/2).

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Surface area , Lateral area and volume of triangular prism area 262.25 square in, 231 square in and 156.25 cubic in respectively.

With two triangular bases and three rectangular sides, a triangular prism is a kind of polyhedron. Alternatively, because it has five faces overall, it may be thought of as a pentahedron in which the bases' edges and vertices are connected by three rectangular sides.

Given, base (b) =5 in ,

the height of the triangle (h) = 6.25 in

length of a prism (l) = 12 in

and the hypotenuse of the right triangle = 8 in

The surface area of a right triangular prism = b×h + (S1 + S2 + h)L

On substituting the values, we get

SA = (5 × 6.25) + [(5 + 6.25 + 8) × 12]

⇒ SA = 60 + (30 × 11)

⇒ SA =262.25 square in

Therefore, the total surface area of a right triangular prism is 262.25 square in.

Lateral  Area = ( S1 + S2 + S3 ) × l

On substituting the values, we get

LA=(5+6.25+8)×12

LA=(19.25)×12

LA=231 square in

Therefore, the lateral surface area of a right triangular prism is 231 square in.

the base area = (1/2) × (b×h) = (1/2) × (5 ×6.25) =15.625 square in

The length of the prism is, L = 12 in

Using the volume of the triangular prism formula,

The volume of the given triangular prism = base area × length of the prism = 15.625 ×10=156.25 cubic in

Hence, The volume of the given triangular prism is 156.25 cubic in.

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