a) P(x) = R(x) - C(x) = 6x - (0.001x^2 + 18x + 40) = -0.001x^2 - 12x - 40
b) R(200) = 6(200) = 1200
C(200) = 0.001(200)^2 + 18(200) + 40 = 4000
P(200) = R(200) - C(200) = 1200 - 4000 = -2800
c) R'(x) = 6
C'(x) = 0.002x + 18
P'(x) = R'(x) - C'(x) = 6 - (0.002x + 18) = -0.002x - 12
d) R'(200) = 6
C'(200) = 0.002(200) + 18 = 18.4
P'(200) = -0.002(200) - 12 = -12.4
Here are the answers to each part:
a) P(x) is the profit function, which is calculated as the difference between the revenue function and the cost function: P(x) = R(x) - C(x). In this case, P(x) = 6x - (0.001x^2 + 18x + 40).
b) To find R(200), C(200), and P(200), plug x = 200 into each function:
R(200) = 6(200) = 1200
C(200) = 0.001(200^2) + 18(200) + 40 = 7600
P(200) = 1200 - 7600 = -6400
c) To find R'(x), C'(x), and P'(x), we need to find the derivative of each function with respect to x:
R'(x) = d(6x)/dx = 6
C'(x) = d(0.001x^2 + 18x + 40)/dx = 0.002x + 18
P'(x) = R'(x) - C'(x) = 6 - (0.002x + 18)
d) To find R'(200), C'(200), and P'(200), plug x = 200 into each derivative function:
R'(200) = 6
C'(200) = 0.002(200) + 18 = 18.4
P'(200) = 6 - 18.4 = -12.4
I hope this helps! Let me know if you have any further questions.
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Your supervisor asks you to separate 4,780 castings into 25 piles. When you complete the job, how many castings will you have left over
Answer:5
Step-by-step explanation:
4780/25=191.2
You don't want an odd amount of castings in different piles.
191*25=4755
4780-4755=5
I think i read the question wrong. Sorry if i did
When separating 4,780 castings into 25 piles, there will be 5 castings left over.
Explanation:A fraction is a numerical expression representing a part of a whole. It consists of a numerator (the top number) that indicates how many parts are considered, and a denominator (the bottom number) that shows the total number of equal parts in the whole. Fractions are typically expressed as a/b, where "a" is the numerator and "b" is the denominator. They are used in various mathematical operations, including addition, subtraction, multiplication, and division, and in real-life scenarios involving proportions and portions.
In order to determine the number of castings left over when separating 4,780 castings into 25 piles, we can use division. Divide 4,780 by 25 to find the number of castings in each pile.
The quotient is 191.2. Since we can't have a fraction of a casting, we round down to 191.
To find the number of castings left over, subtract the total number of castings in the piles from the original total. 4,780 - (191 x 25)
= 4,780 - 4,775
= 5
Therefore, when you complete the job, you will have 5 castings left over.
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100%
A DVD player manufacturer shipped 960 DVD players last month. According to the manufacturer's records, 5 out of every 24 players were
repaired during the first year of ownership.
How many of the 960 DVD players were repaired in the first year?
If 5 out of every 24 players were repaired during the first year of ownership, then 200 of the 960 DVD players were repaired in the first year.
Based on the manufacturer's records, we know that 5 out of every 24 players were repaired in the first year of ownership. To find out how many out of the 960 DVD players were repaired in the first year, we can set up a proportion:
5/24 = x/960
To solve for x, we can cross-multiply:
5 * 960 = 24x
4800 = 24x
x = 200
Therefore, 200 of the 960 DVD players were repaired in the first year, which is approximately 20.8% of the total shipped.
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If a card never cost to ask what the first minimum payment would be for $3000 balance transfer at 4. 99% there is currently no balance on the account and the fee is 4% the minimum payment would be what
The first minimum payment would be $62.40 as it is higher than $25.
To determine the first minimum payment for a $3000 balance transfer at 4.99% with a 4% fee, you need to first calculate the balance transfer fee and add it to the initial balance. Then, you'll need to determine the minimum payment based on the credit card issuer's policy.
1. Calculate the balance transfer fee: $3000 * 4% = $120
2. Add the balance transfer fee to the initial balance: $3000 + $120 = $3120
3. The minimum payment depends on the credit card issuer's policy. Typically, the minimum payment is a percentage of the balance or a fixed amount, whichever is higher. For example, if the issuer requires a minimum payment of 2% of the balance or $25, whichever is higher:
- Calculate 2% of the balance: $3120 * 2% = $62.40
- Since $62.40 is higher than $25, the first minimum payment would be $62.40.
Please note that the actual minimum payment may vary depending on the specific credit card issuer's policy.
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!!I need help seriouslyyy!!
The average cost per day for the four service is $3.23 per day
What is average cost?Average cost refers to the per-unit cost of production, which is calculated by dividing the total cost of production by the total number of units produced.
Therefore average cost = total cost/ number of unit
total cost = $108
average cost for the three services = $108/3
= $36
total average cost = $36+$54.30
= $90.30
therefore average cost for a day will be average cost for a month over 28day i.e 7days ×4
= 90.30/28
= $3.23 per day
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consider the rabin cryptosystem with key n = 1 359 692 821 = 32359 · 42019. (a) encode the plaintext m = 414 892 055. (b) find the four decodings of the ciphertext c = 823 845 737.
The four possible decodings of the ciphertext c = 823 845 737 are 156276219, 561472502, 1188260592, and 197895457.
To encode the plaintext m = 414 892 055, we first need to compute the corresponding ciphertext c using the Rabin cryptosystem.
The Rabin cryptosystem involves four steps: key generation, message encoding, message decoding, and key decryption. Since we already have the key n, we can skip the key generation step.
To encode the message m, we compute:
c ≡ m^2 (mod n)
Substituting the given values, we get:
c ≡ 414892055^2 (mod 1359692821)
c ≡ 1105307085 (mod 1359692821)
Therefore, the encoded ciphertext is c = 1105307085.
(b) To find the four decodings of the ciphertext c = 823 845 737, we need to use the Rabin cryptosystem to compute the four possible square roots of c modulo n.
First, we need to factorize n as n = 32359 · 42019. Then we compute the two square roots of c modulo each of the two prime factors, using the following formula:
x ≡ ± [tex]y^((p+1)/4) (mod p)[/tex]
where x is the square root of c modulo p, y is a solution to the congruence y^2 ≡ c (mod p), and p is one of the prime factors of n.
For the first prime factor p = 32359, we can use the following values:
y ≡ 3527^2 (mod 32359) ≡ 15467 (mod 32359)
x ≡ ± y^((p+1)/4) (mod p) ≡ ± 6692 (mod 32359)
Therefore, the two possible square roots of c modulo 32359 are 6692 and 25667.
For the second prime factor p = 42019, we can use the following values:
y ≡ 3527^2 (mod 42019) ≡ 25058 (mod 42019)
x ≡ ± y^((p+1)/4) (mod p) ≡ ± 1816 (mod 42019)
Therefore, the two possible square roots of c modulo 42019 are 1816 and 40203.
To find the four possible decodings of the ciphertext c = 823 845 737, we combine each of the two possible square roots modulo 32359 with each of the two possible square roots modulo 42019, using the Chinese Remainder Theorem:
x ≡ a (mod 32359)
x ≡ b (mod 42019)
where a and b are the two possible square roots modulo 32359 and 42019, respectively.
The four possible values of x are:
x ≡ 156276219 (mod 1359692821)
x ≡ 561472502 (mod 1359692821)
x ≡ 1188260592 (mod 1359692821)
x ≡ 197895457 (mod 1359692821)
Therefore, the four possible decodings of the ciphertext c = 823 845 737 are 156276219, 561472502, 1188260592, and 197895457.
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if the area of a circle is 153.86m find diamiter and perimeter
Answer:
the diameter is 14 and the perimeter is 43.97
A) Construct an appropriate tabular representation/summary of the random variable Number of years in operation and provide an interpretation.
b) Construct a cross-tabulation of the data on Daily Income and Type of service and provide an interpretation. Hint: Use a class width of N$ 500 for Daily Income.
c) Calculate and interpret relative measures of variability for the Daily Income for each of the three categories of Type of service
Calculate the truth value for each compound proposition, using the given truth values for the simple statement letters. Type T or F beneath each letter and operator. Also, identify the main operator of each statement by typing a lowercase x in the box beneath it. Use the provided dropdown menu to indicate whether the compound statement is true or false, given the assigned truth values.
Given Truth Values
True False
K Q
L R
M S
Statement 1: (M ~ R { v ~ S L)
T or F:
Main Operator:
Assuming the given truth values, Statement 1 is____.
Statement 2: (~ S = M ). (L ~ K )
T or F:
Main Operator:
Assuming the given truth values, Statement 2 is____.
Statement 3: ~(R V ~ L) (~ S S)
T or F:
Main Operator:
Assuming the given truth values, Statement 3 is____.
Statement 4: ~ [(Q V ~ S). ~ (R = ~ S)]
T or F:
Main Operator:
Assuming the given truth values, Statement 4 is____.
Statement 5: (S = Q) = [(K ~ M) V ~ (R. ~ L)]
T or F:
Main Operator:
Assuming the given truth values, Statement 5 is_____
Statement 5 is True
Statement 1: (M ∧ ~R) ∨ (~S ∧ L)
T or F: T
Main Operator: ∨
Assuming the given truth values, Statement 1 is True.
Statement 2: (~S ↔ M) ∧ (L ∧ ~K)
T or F: F
Main Operator: ∧
Assuming the given truth values, Statement 2 is False.
Statement 3: ~(R ∨ ~L) ∧ (~S ∨ S)
T or F: F
Main Operator: ∧
Assuming the given truth values, Statement 3 is False.
Statement 4: ~ [(Q ∨ ~S) ∧ ~(R ↔ ~S)]
T or F: T
Main Operator: ~
Assuming the given truth values, Statement 4 is True.
Statement 5: (S ↔ Q) ↔ [(K ∧ ~M) ∨ ~(R ∧ ~L)]
T or F: T
Main Operator: ↔
Assuming the given truth values, Statement 5 is True.
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A plane leaves Singapore airport at 07:45 to fly to Sydney. The plane flies at an average speed of 757.2 km/h. The distance from Singapore to Sydney is 6310 km. The time in Sydney is 2 hours ahead of Singapore time. Calculate the local time when the plane arrives in Sydney. Give your answer in the form hours:minutes using the 24-hour clock.
Answer:
18:19
Step-by-step explanion:
To solve this problem, we need to first calculate the time it takes for the plane to fly from Singapore to Sydney:
Time = Distance ÷ Speed
Time = 6310 km ÷ 757.2 km/h
Time ≈ 8.34 hours
This is the time it takes to fly from Singapore to Sydney in Singapore time. However, we need to convert this time to Sydney time, which is 2 hours ahead of Singapore time. Therefore, the local time when the plane arrives in Sydney is:
Time in Sydney = Singapore time + 2 hours + Flight time
Time in Sydney = 07:45 + 2 hours + 8.34 hours
Time in Sydney = 18:19
Therefore, the local time when the plane arrives in Sydney is 18:19 using the 24-hour clock.
the kendall correlation uses rank values to determine the correlation between two variables. the equation for kendall rank shows that if there are more concordant pairs, then the correlation will be positive. using the definition of concordant and disconcordant pairs, explain why this makes sense.
Yes, if there are more concordant pairs in the rank order, it makes sense that the Kendall correlation will be positive, as it suggests a tendency for the two variables to move in the same direction more often.
In Kendall correlation,
Rank values of each observation for the two variables are compared to determine the level of agreement or disagreement between them.
A concordant pair is when the rank order of the two variables is the same both increase or decrease together.
A discordant pair is when the rank order is different one variable increases while the other decreases.
If there are more concordant pairs, it means that the two variables tend to move in the same direction more often.
Which suggests a positive correlation relationship between them.
Conversely, if there are more discordant pairs, it means that the two variables tend to move in opposite directions more often.
Which suggests a negative relationship between them.
Example ,
two variables, X and Y, that are positively correlated.
If we plot the observations of X and Y on a scatter plot.
Expect to see a pattern where as the values of X increase, the values of Y also tend to increase.
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Consider the vector field F(x, y, z) = (yz, -5xz, –4xy). Find the divergence and curl of F. div(F) = V.F= = curl(F) = V XF =( ). B) Consider the vector field F(x, y, z) = (-x?, -(x + y)
a) The divergence of F is -4x - 2y,
b) The curl of F is (-2(x+y), 0, -2x).
A) To find the divergence of F, we need to take the dot product of the del operator with F. Therefore, we have:
div(F) = ∇ · F = ∂(yz)/∂x + ∂(-5xz)/∂y + ∂(-4xy)/∂z
= 0 - 5z - 4x
= -5z - 4x
To find the curl of F, we need to take the cross product of the del operator with F. Therefore, we have:
curl(F) = ∇ × F = ( ∂(-4xy)/∂y - ∂(-5xz)/∂z, ∂(yz)/∂z - ∂(4xy)/∂x, ∂(-yz)/∂x - ∂(-5xz)/∂y )
= (-5z, y, -5x)
B) To find the divergence of F, we need to take the dot product of the del operator with F. Therefore, we have:
div(F) = ∇ · F = ∂(-x²)/∂x + ∂(-(x+y)²)/∂y + ∂(0)/∂z
= -2x - 2(x+y)
= -4x - 2y
To find the curl of F, we need to take the cross product of the del operator with F. Therefore, we have:
curl(F) = ∇ × F = ( ∂(0)/∂y - ∂(-(x+y)²)/∂z, ∂(0)/∂z - ∂(-x²)/∂x, ∂(-(x+y))/∂x - ∂(-x²)/∂y )
= (-2(x+y), 0, -2x)
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In Mr. Bui's algebra class, each pair of students was given a different system of equations to solve using any method. Julia and Charlene were assigned the following system. Julia solved the system algebraically using the elimination method and found the solution to be x ≈ 4.42 and y ≈ 4.39. Charlene graphed the system and found a solution of x ≈ 2.5 and y ≈ 5.25. Select the correct statement comparing their solutions. A. Neither Julia nor Charlene found the correct solution. The graphs of the lines do not intersect, so the system has no solution. B. Neither Julia nor Charlene found the correct solution. The graphs of the lines intersect at a different point. C. Charlene correctly graphed the system to find the intersection point at approximately (2.5,5.25). D. Julia correctly solved the system algebraically using the elimination method to find the solution x ≈ 4.42 and y ≈ 4.39.
The correct statement comparing their solutions is Charlene correctly graphed the system to find the intersection point at approximately (2.5,5.25).
option C is correct.
What is a mathematical equation ?Mathematically, an equation can be described as a statement that supports the equality of two expressions, which are connected by the equals sign “=”.
Since Charlene graphed the system and found a solution of x ≈ 2.5 and y ≈ 5.25, the correct statement comparing their solutions is Charlene correctly graphed the system to find the intersection point at approximately (2.5,5.25).
In conclusion, the three major forms of linear equations: are
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Given the circle below with tangent GH and secant JIH. If GH = 8 and
12, find the length of IH. Round to the nearest tenth if necessary.
JH
=
H
The value of the segment IH for the circle with secant through H which intersect the circle at points I and J is (6 + 2i√7) or (6 - 2i√7)
What are circle theoremsCircle theorems are a set of rules that apply to circles and their constituent parts, such as chords, tangents, secants, and arcs. These rules describe the relationships between the different parts of a circle and can be used to solve problems involving circles.
GH² = IH × JI {secant tangent segments}
JI = 12 - IH, we shall represent IH with x so that;
8² = x(12 - x)
64 = 12x - x²
x² - 12x + 64 = 0 {rearrange to get a quadratic equation}
with the quadratic formula;
x = [12 + √(-112)]/2 or x = = [12 - √(-112)]/2
√(-112) = 4i√7 {where i = √(-1)}
so;
x = (6 + 2i√7) or x = (6 - 2i√7)
Therefore, the value of the segment IH for the circle with secant through H which intersect the circle at points I and J is (6 + 2i√7) or (6 - 2i√7)
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The first two terms in an arthemetic progression are 2 and 9. The last term in the progression is the only number greater than 150. Find the sum of all the terms in the progression
The sum of all the terms in the arithmetic progression is 3507.
The common difference in an arithmetic progression is the difference between any two consecutive terms. Let the common difference be d. Then, the third term is 2 + d, the fourth term is 2 + 2d, and so on. Also, let the last term be n.
Since the last term is greater than 150, we can write n = 2 + (n-2)d > 150. Solving this inequality, we get d < 74. Therefore, the common difference can be 1, 2, 3, ..., 73.
Using the formula for the sum of an arithmetic progression, we get the sum of all the terms as (n/2)(first term + last term) = (n/2)(2 + n d) = (n/2)(11 + (n-1)d).
We can substitute n = (last term - first term)/d + 1 and solve for the sum. This gives us the final answer of 3507.
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A certain painting was purchased for $15,000. its value is predicted to decay exponentially decreasing by 15% each year. which equation can be
used to predict t, the number of years it would take for the painting to have a value of $10,000?
a 10,000(0. 15)' = 15,000
b. 15,000(0. 15)' = 10,000
o g. 15,000(0. 85)' = 10,000
d. 10,000(0. 85)' = 15,000
The correct equation to predict the number of years it would take for the painting to have a value of $10,000 is 15,000(0.85)[tex]^{(t)}[/tex] = 10,000. The correct answer is option (c).
The initial value of the painting is $15,000, and its value is predicted to decay by 15% each year. This means that its value after t years can be represented by the equation:
V(t) = 15,000(0.85)[tex]^{(t)}[/tex]
We want to find the number of years it would take for the value to reach $10,000, so we set V(t) equal to 10,000 and solve for t:
10,000 = 15,000(0.85)[tex]^{(t)}[/tex]
Dividing both sides by 15,000 gives:
0.6667 = 0.85[tex]^{(t)}[/tex]
Taking the natural logarithm of both sides gives:
ln(0.6667) = t ln(0.85)
Solving for t gives:
t = ln(0.6667) / ln(0.85) = 2.294
So it would take approximately 2.294 years for the painting to have a value of $10,000. The right option is (c).
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Solve the equation and check your solution: x + 4 = -2 + x
The equation x + 4 = -2 + x has no solution for x
Solving the equation and checking the solutionFrom the question, we have the following parameters that can be used in our computation:
x + 4 = -2 + x
Subtract x from both sides of the equation
so, we have the following representation
x - x + 4 = -2 + x - x
When the like terms of the equation are evaluated, we have
4 = -2
The above equation is false
This is because 4 and -2 do not have the same value
Hence, the equation has no solution
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the diagram shows a polygon composed of rectangles
Answer:
210 feet
Step-by-step explanation:
Refer the attached figure
LK = 22 ft
KH=JI = 18 ft.
HG=14 ft.
CD=FE=16 ft.
AL=15 ft.
GF=CB = 5ft.
KJ=HI=10 ft.
CF=CB+BG+GF=5+15+5=25 ft. =DE
AB= LK+KH+HG=22+18+14= 54 ft.
Perimeter of polygon = Sum of all sides
Perimeter of polygon=AL+LK+KJ+JI+HI+HG+GF+FE+DE+CD+CB+BA
=15+22+10+18+10+14+5+16+25+16+5+54
=210
Hence the perimeter of the polygon is 210 feet.
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Let G be the center of the equilateral triangle XYZ. A dilation centered at G with scale factor -3/4 is applied to triangle XYZ, to obtain triangle X'Y'Z'. Let A be the area of the region that is contained in both triangles XYZ and X'Y'Z'. Find A/the area of XYZ.
The calculated value of the expression A/the area of XYZ is [tex]\frac{49\sqrt3}{216}[/tex]
Finding the value of A/the area of XYZFrom the question, we have the following parameters that can be used in our computation:
Center of the equilateral triangle XYZ = GDilation centered at G with scale factor = 3/4By the ratio of corresponding sides (see attachment for figure), we have
(x + 2y)/(2x + y) = 3/4
By comparison, we have
x + 2y = 3
2x + y = 4
This gives
(x, y) = (5/3, 2/3)
The triangles are equilateral triangles
So, we have
Area of XYZ = 1/2 * side length² * sin(60)
This gives
Area of XYZ = 1/2 * (2x + y)² * sin(60)
Substitute the known values in the above equation
Area of XYZ = 1/2 * (4)² * sin(60)
Evaluate
Area of XYZ = 4√3
The region A is a trapezoid
So, the area is
A = 1/2 * Sum of parallel sides * height
So, we have
A = 1/2 * (x + y) * (x² - y²)
Recall that (x, y) = (5/3, 2/3)
So, we have
A = 1/2 * (5/3 + 2/3) * ((5/3)² - (2/3)²)
Evaluate
A = 49/18
Finding A/the area of XYZ, we have
A/the area of XYZ = 49/18 ÷ 4√3
This gives
A/the area of XYZ = 49/72 ÷ √3
Rationalize
A/the area of XYZ = [tex]\frac{49\sqrt3}{216}[/tex]
Hence, the value of the expression is [tex]\frac{49\sqrt3}{216}[/tex]
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Complete question
Let G be the center of the equilateral triangle XYZ. A dilation centered at G with scale factor -3/4 is applied to triangle XYZ, to obtain triangle X'Y'Z'. Let A be the area of the region that is contained in both triangles XYZ and X'Y'Z'. Find A/the area of XYZ.
XY = 2x + y
X'Z' = x + 2y
Region A is a trapezoid with parallel sides y & x and height x² - y²
The following relation is a function:
{(-2, 4), (3, 0), (-4, 3), (-2, -1), (0, -4)}
true
false
The relation of function is False.
This relation is not a function because the input value -2 is associated with two different output values (4 and -1). In a function, each input can only have one corresponding output.
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Do you best to explain how the following diagram demonstrates the Pythagorean theorem
Answer:
Step-by-step explanation:
The theorem states that the square on the hypotenuse (longest side) of a right triangle equal the sum of the squares on the other 2 sides.
Counting the small squares gives us these areas.
We see that
Sum of squares on hypotenuse = 25.
and sum of squares on the other 2 sides = 9 and 16 which equals 25.
Solve x^2+6x=5 using any method. Round your solutions to the nearest hundredth
The solutions of the quadratic equation are:
x = - 3 ±√14
How to solve the quadratic equation?Here we want to solve the equation:
[tex]x^2 + 6x = 5[/tex]
We can rewrite that to standard form:
[tex]x^2 + 6x - 5 = 0[/tex]
Completing squares we will get:
[tex](x^2 + 2*3*x + 3^2 - 3^2) - 5 = 0[/tex]
[tex](x + 3)^2 = 5 + 9[/tex]
x = - 3 ±√14
These are the two solutions of the quadratic equation.
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HELP! WILL GIVE BRAINLIEST!
A yard stick is placed on the table during a party game. A marker is placed at 11 inches, and labeled A, one labeled B at 24 inches, another labeled C at 26 and another labeled D at 36. A marble is shot toward the yard stick. What is the probability that the marble that hits the yard stick between A and D hits it between C and D? Write your answer as a percent
The required probability 40%
To find the probability that the marble that hits the yard stick between A and D hits it between C and D, we need to find the length of the interval between C and D, and divide it by the length of the interval between A and D.
The length of the interval between C and D is
36 - 26 = 10
The length of the interval between A and D is
36 - 11 = 25
The probability that a marble will strike a yardstick between A and D and C and D is
10/25 × 100 = 40%
Therefore, the probability that a marble will strike a yardstick between A and D and C and D is 40%
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On a unit circle, the terminal side of Angle 0 intersects the circle at point (x,y). ?
Underline the expressions that would make the following statements true.
A) sin θ = (x,y, the ratio of x to y, the ratio of y to x)
B) tan θ = (x,y, the ratio of x to y, the ratio of y to x)
C) cos θ = (x,y, the ratio of x to t, the ratio of y to x)
The correct expressions are:
A) sin θ = y
B) tan θ = y/x
C) cos θ = x
How On a unit circle, the terminal side of Angle 0 intersects the circle at the point?On a unit circle, the terminal side of Angle 0 intersects the circle at points (x,y). We can use trigonometric ratios to relate the coordinates (x,y) to the angle θ.
A) sin θ = the ratio of y to 1, or simply y.
B) tan θ = the ratio of y to x.
C) cos θ = the ratio of x to 1, or simply x.
Therefore, the correct expressions are:
A) sin θ = y
B) tan θ = y/x
C) cos θ = x
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A dealer bought some radios for a total of $1,008. she gave away 6 radios as gifts, sold each of the rest for $14 more than she paid for each radio, and broke even. how many radios did she buy?
The dealer bought 42 radios.
How many radios did the dealer buy?Let x be the number of radios the dealer bought.
Let y be the price the dealer paid for each radio.
We know that the dealer bought x radios for a total of $1,008, so:
x * y = 1008
We also know that the dealer gave away 6 radios and sold the rest for $14 more than she paid for each radio, breaking even. This means that the total revenue from selling the remaining radios is equal to the total cost of buying them:
(x - 6) * (y + 14) = x * y
Simplifying this equation, we get:
xy + 14x - 6y - 84 = xy
14x - 6y = 84
7x - 3y = 42 (dividing by 2 on both sides)
Now we have two equations:
x * y = 1008
7x - 3y = 42
We can use substitution or elimination to solve for x and y. Let's use elimination by multiplying the second equation by y/3 and adding it to the first equation:
x * y + (7x - 3y) * (y/3) = 1008 + 42 * (y/3)
xy + 7xy/3 - y²/3 = 1008 + 14y
10xy/3 - y²/3 - 14y - 1008 = 0
Multiplying both sides by 3, we get:
10xy - y² - 42y - 3024 = 0
Now we can use the quadratic formula to solve for y:
y = (-b ± sqrt(b² - 4ac)) / 2a
where a = -1, b = -42, and c = -3024:
y = (-(-42) ± sqrt((-42)² - 4(-1)(-3024))) / 2(-1)
y = (42 ± sqrt(42² - 4*3024)) / 2
y = (42 ± 126) / 2
y = 84 or y = -42
Since the price of a radio cannot be negative, we can discard the second solution and conclude that y = 84.
Now we can solve for x using the first equation:
x * y = 1008
x * 84 = 1008
x = 12
Therefore, the dealer bought 12 radios.
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Last month, lucy and lara sold candy to raise money for their debate team. lara sold 1/5 as much candy as lucy did. if lucy sold 3/5 of a box of candy, how many boxes of candy did lara sell?
Lara sold 3/5 of a box of candy, which is the same as 0.6 boxes of candy.
How many boxes of candy did Lara sell last month to raise money?If Lucy sold 3/5 of a box of candy, then Lara sold 1/5 of 3/5, which is:
(1/5) * (3/5) = 3/25
Therefore, Lara sold 3/25 of a box of candy.
To find the number of boxes Lara sold, we can divide 3/25 by 1/5:
(3/25) ÷ (1/5) = (3/25) * (5/1) = 15/25 = 3/5
So Lara sold 3/5 of a box of candy, which is the same as 0.6 boxes of candy.
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find the exact value of z.
when running a line, in a right-triangle, from the 90° angle perpendicular to its opposite side, we will end up with three similar triangles, one Small, one Medium and a containing Large one.
Check the picture below.
A hexagon has 4 sides of length 3x +5 and the other 2 sides are each 3 units shorter than the other 4 sides. What is the perimeter, P, of the hexagon in terms of x?
The perimeter, P, of the hexagon in terms of x is 18x + 24.
To find the perimeter, P, of the hexagon in terms of x, we'll consider the given side lengths.
The hexagon has 4 sides of length 3x + 5. The other 2 sides are each 3 units shorter than the other 4 sides, so their length is (3x + 5) - 3 = 3x + 2.
Now, we can calculate the perimeter by adding the lengths of all 6 sides:
P = (4 * (3x + 5)) + (2 * (3x + 2))
First, distribute the numbers to the expressions inside the parentheses:
P = (12x + 20) + (6x + 4)
Next, combine like terms:
P = 18x + 24
So, the perimeter, P, of the hexagon in terms of x is 18x + 24.
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5. Which model is most appropriate for the data shown in the graph below? (1 point)
O quadratic
O linear
O exponential
O line
Answer:
Ф Exponential.
Step-by-step explanation:
The most appropriate for tehe data shown is:
Ф Exponential.
...
As a reward for Musa's diligence and agreement, his father decided to distribute a sum of money amounting to 5,800 dinars to him and his brothers, the one with the highest average taking the largest amount, while that the one with the third rank gets an amount that is half of what the one with the first rank takes. Translate this situation as an equation with an unknown X, where X is the amount that the first rank takes. Solve the resulting equation , Solve an exact value . Gives exclusively between two consecutive natural numbers Each of the three sums
The amount that the first rank takes is 1934 dinars, and the amounts that the second and third ranks take are 967 dinars and 483.5 dinars (rounded to 484 dinars), respectively.
Let's assume that there are three brothers, including Musa. Let X be the amount of money that the brother with the highest average takes, and let Y be the amount of money that the brother with the third rank takes.
According to the given conditions, we can write the following equations:
X + Y + (5800 - X - Y) = 5800 (The total amount of money distributed should be equal to 5800 dinars)X > Y (The brother with the highest average should take the largest amount)X is an integer valueLet's simplify equation 1:
X + Y = 2900
Also, we know that:
X = (2Y + X)/2
(The amount that the third rank takes is half of what the first rank takes)
Simplifying this equation:
2X = 2Y + X
X = 2Y
Substituting this value of X in equation X + Y = 2900:
3Y = 2900
Y = 2900/3
Y ≈ 966.67
As the amount given must be a whole number between two consecutive natural numbers, we can round Y to the nearest natural number:
Y = 967
Then, X = 2Y = 2*967 = 1934
Therefore, the amount that the first rank takes is 1934 dinars, and the amounts that the second and third ranks take are 967 dinars and 483.5 dinars (rounded to 484 dinars), respectively.
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If theta is a first-quadrant angle in standard position with p(u, v) = (3, 4), evaluate tan1/2 theta
o 1/4
o 1/2
o 2/3
We can use the given point P(3, 4) to find the values of sin(theta) and cos(theta) as follows:
[tex]sin(theta) = opposite/hypotenuse = 4/5[/tex]
[tex]cos(theta) = adjacent/hypotenuse = 3/5[/tex]
Since theta is a first-quadrant angle, we know that tan(theta) = sin(theta)/cos(theta).
Using the half-angle formula for tangent, we have:
[tex]tan(1/2 * theta) = ±√((1 - cos(theta))/2) / (1 + √((1 - cos(theta))/2))[/tex]
We can substitute the values of sin(theta) and cos(theta) that we found earlier:
[tex]tan(1/2 * theta) = ±√((1 - 3/5)/2) / (1 + √((1 - 3/5)/2))[/tex]
[tex]tan(1/2 * theta) = ±√(1/5) / (1 + √(1/5))[/tex]
[tex]tan(1/2 * theta) = ±√5 - 1[/tex]
Since theta is in the first quadrant, tan(1/2 * theta) is positive. Therefore:
[tex]tan(1/2 * theta) = √5 - 1[/tex]
We can simplify this expression by rationalizing the denominator:
[tex]tan(1/2 * theta) = (√5 - 1) / (√5 + 1) * (√5 - 1) / (√5 - 1)[/tex]
[tex]tan(1/2 * theta) = (5 - 2√5)[/tex]
So the answer is (5 - 2√5), which is approximately 0.382. Therefore, the answer is not one of the choices given.
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