Lim (x,y)->(0,0) f (x,y) = L if f (x,y) gets close to l as we approach (0,0) along the x-axis (y = 0) and along the y-axis (x = 0)?

3/5 divided by 2/3 is equal to 9/10. We can also simplify this fraction by dividing both the numerator and the denominator by their greatest common factor, which is 1 in this case.

To divide fractions, we need to invert the second fraction and then multiply the two fractions together. This can be written as:

(a/b) ÷ (c/d) = (a/b) × (d/c)

In this case, a = 3, b = 5, c = 2, and d = 3. Substituting these values into the above equation, we get:

(3/5) ÷ (2/3) = (3/5) × (3/2)

To multiply fractions, we simply multiply their numerators together and their denominators together. So, we can rewrite the above equation as:

(3/5) × (3/2) = (3 × 3) / (5 × 2) = 9/10

Therefore, 3/5 divided by 2/3 is equal to 9/10. We can also simplify this fraction by dividing both the numerator and the denominator by their greatest common factor, which is 1 in this case. Therefore, the final answer is 9/10.

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The compound interest on $15000  for 2 years at 6% p. a is $1956 .

To calculate the compound interest on 15000 $ for 2 years at 6% p.a., we can use the formula

A = P(1 + r/n)^(nt)

where:

A = the final amount (including interest)

P = the principal amount (initial investment)

r = the annual interest rate (as a decimal)

n = the number of times the interest is compounded per year

t = the time period (in years)

Here, P = $15000 , r = 6% = 0.06, n = 1 (compounded annually), and t = 2 years.

So, A = 15000 (1 + 0.06/1)^(1*2)

= 15000 (1.06)^2

= $16956

Therefore, the compound interest on $15000  for 2 years at 6% p.a. is $16956 - $15000 = $1956 .

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81 must be the bare minimum acceptable sample size for a real-world computation.

The mean of a group of two or more integers is the straightforward mathematical average. The geometric mean approach, which uses the average of a set of products, and the arithmetic mean technique, which uses the sum of the series' values, are only two of the techniques available to calculate the mean for a given set of data.

Given: For the population of healthy people, the mean IQ score is μ =100 and the standard deviation is б =14.

Significance level : 1-0.99=.01

Critical value : zₐ/2=2.576

Margin of error : E=4

Standard deviation : б =14

The following equation determines the sample size:

n=( zₐ/2×б /E)²

n=(2.576×14/4)²

n=81.288≈81

Hence, the minimum reasonable sample size for a real world calculation must be 81.

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Answer: #4 = Non-Linear & #3 = Linear

Step-by-step explanation: Non-Linear lines create curves and not straight lines. As the term non-"line"ar defines not as a line, linear represent straight lines. Hence, #4 is non-linear and #3 is linear in terms of graphing.

Answer:

2100 km

Step-by-step explanation:

If the entire trip was 2400 km, then we can note that x km was flown by plane, and 2400 - x km by bus

The whole trip took 8 hours and we know that t = s/v:

[tex]t(by \: plane) = \frac{x}{700} [/tex]

[tex]t(by \: bus) = \frac{2400 - x}{60} [/tex]

Now we can form an equation:

[tex] \frac{x}{700} + \frac{2400 - x}{60} = 8 [/tex]

[tex] \frac{60x + 1680000 - 700x}{42000} = 8[/tex]

[tex] \frac{ - 640x + 1680000}{42000} = 8 [/tex]

Use the property of the proportion:

-640x + 1680000 = 336000

-640x = 336000 - 1680000

-640 x = -1344000 / : (-640)

x = 2100

Since we've noted that x is a path flew by the plane, we have the answer already

4. CE is a median of triangle ADF,  BF is the midpoint of AC.

5. CE = 3√3 cm and AG = 18√3 cm

6. AM is a median of right triangle ABC.

In mathematics, a triangle is a geometric shape that consists of three line segments that intersect at three endpoints. These endpoints are called vertices, and the line segments are called sides.

Triangles are one of the most basic shapes in geometry and are used in many areas of mathematics, science, engineering, and everyday life. They can be classified based on the length of their sides and the measure of their angles.

4. CE is a median of triangle ADF.

BF is the midpoint of AC.

Since C is the midpoint of segment AD and E is the midpoint of segment FD, CE is a median of triangle ADF. This is because CE passes through D and divides the opposite side A F into two equal halves.

Similarly, since B is the midpoint of segment AC, BF is a midpoint of AC. This is because BF passes through A and divides the opposite side AC into two equal halves.

5. To find CE and AG, we can use the fact that BF = 24 cm. Let's start by finding CE.

Since BF is the midpoint of AC, we have:

AC = 2 BF = 2(24 cm) = 48 cm.

Since C is the midpoint of AD, we have:

AD = 2 CD = 2 CE (by definition of midpoint)

Therefore, CE = AD/2

To find AD, we can use the fact that E is the midpoint of FD, so:

FD = 2 FE = 2 FG (by definition of midpoint)

Since F is the midpoint of GE, we have:

GE = 2 GF (by definition of midpoint)

Therefore, AG = AE + GE = AE + 2GF

Now, since AM is a median of triangle ABC, we have:

AM² = (AB² + BC²)/2 - (AC²/4)

Since triangle ABC is a right-angled triangle with angle B = 90 degrees, we have:

AB² + BC² = AC²

Therefore, we can simplify the equation for AM² as follows:

AM² = AC²/2 - AC²/4

AM² = AC²/4

Substituting the value we found for AC, we get:

AM² = 48²/4 = 576

Therefore, AM = 24 cm.

Now, we can use the Pythagorean theorem to find AE:

AE² + EM² = AM²

AE² + (AC/2)² = AM²

AE² + 24² = 576

AE² = 576 - 576/4 = 432

AE = √432 = 12√3 cm

Finally, we can find AG as:

AG = AE + 2GF = AE + 2(AD/4) (since G is the midpoint of EF)

AG = 12√3 + AD/2

But we know that AD = 2CE, so:

AG = 12√3 + CE

Therefore, to find AG, we just need to add the value of CE that we found earlier:

AG = 12√3 + CE = 12√3 + (AD/2) = 12√3 + (CE/2) = 12√3 + 6√3 = 18√3 cm.

Therefore, CE = AD/2 = (AG - 12√3)/2 = (18√3 - 12√3)/2 = 3√3 cm.

So, CE = 3√3 cm and AG = 18√3 cm.

6. Statement: AM is a median of right triangle ABC.

A median of a triangle is a line segment that joins a vertex to the midpoint of the opposite side. In right triangle ABC, the median AM joins the right angle vertex A to the midpoint of the hypotenuse BC.

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4). Section AC's midpoint is B, and section BF's midpoint is BF. Because BF cuts through A and splits the opposing side AC into two equal halves, this is the case.

5). CE = AD/2 = (AG - 12√3)/2 = (18√3 - 12√3)/2 = 3√3 cm.

So, CE = 3√3 cm and AG = 18√3 cm.

6). The middle of the hypotenuse BC is connected to the right angle vertex A by the median AM.

One of the most fundamental geometric shapes, triangles are used frequently in mathematics, science, engineering, and daily living. They can be categorized based on the dimensions of their edges and sides.

4). ADF's triangle's middle is CE.

BF sits in the middle of AC.

Triangle ADF's median is CE because C is the midway of segment AD and E is the midpoint of segment FD. This is the case because CE passes through D and divides the opposite side A F into two equal halves.

BF functions as an AC midpoint in a manner similar to how B acts as the segment's halfway point. This is the case because BF cuts through A and divides the opposite side AC into two equal halves.

5). We can use the knowledge that BF = 24 centimeters to determine CE and AG. Let's begin by locating CE.

Because BF is AC's middle, we have:

AC = 2 BF = 2(24 cm) = 48 cm.

Since C is the midpoint of AD, we have:

AD = 2 CD = 2 CE (by definition of midpoint)

Therefore, CE = AD/2

To find AD, we can use the fact that E is the midpoint of FD, so:

FD = 2 FE = 2 FG (by definition of midpoint)

Since F is the midpoint of GE, we have:

GE = 2 GF (by definition of midpoint)

Therefore, AG = AE + GE = AE + 2GF

Now that triangle ABC's middle is AM, we have:

AM² = (AB² + BC²)/2 - (AC²/4)

Triangle ABC has a right angle of 90 degrees, so we have:

AB² + BC² = AC²

As a result, we can simplify the AM² equation as follows:

AM² = AC²/2 - AC²/4

AM² = AC²/4

When we substitute the AC number we discovered, we obtain:

AM² = 48²/4 = 576

Therefore, AM = 24 cm.

We can now determine AE using the Pythagorean theorem:

AE² + EM² = AM²

AE² + (AC/2)² = AM²

AE² + 24² = 576

AE² = 576 - 576/4 = 432

AE = √432 = 12√3 cm

Finally, we can find AG as:

AG = AE + 2GF = AE + 2(AD/4) (since G is the midpoint of EF)

AG = 12√3 + AD/2

But we know that AD = 2CE, so:

AG = 12√3 + CE

The value of CE that we previously discovered can therefore simply be added to obtain AG:

AG = 12√3 + CE = 12√3 + (AD/2) = 12√3 + (CE/2) = 12√3 + 6√3 = 18√3 cm.

Therefore, CE = AD/2 = (AG - 12√3)/2 = (18√3 - 12√3)/2 = 3√3 cm.

So, CE = 3√3 cm and AG = 18√3 cm.

6). AM is the middle of the right triangle ABC.

A line section connecting a triangle's vertex to the middle of the other side is the triangle's median. The median AM connects the right angle vertex A to the middle of the hypotenuse BC in the right triangle ABC.

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the total number of coins in the museum's collection is:-144 + 90 + 60 + 30 + 10 + 5 = 339 coins.

What is histogram ?

A histogram is a graphical representation of the distribution of a dataset. It is commonly used in statistics to represent the frequency distribution of a set of continuous or discrete data. In a histogram, the data is divided into intervals, or bins, and the frequency of the data falling into each bin is represented by the height of a bar.

The x-axis of a histogram represents the range of values in the dataset, while the y-axis represents the frequency or count of data points falling within each bin. The bars of a histogram are usually drawn touching each other, as the data is continuous and there are no gaps between the bins.

To determine the total number of Roman coins in the museum's collection, we need to know the area under the histogram.

Since we know that 144 coins each weigh between 8 g and 17 g, we can calculate the total weight of those coins:

144 coins x ((17 g - 8 g)/2) = 144 coins x 4.5 g = 648 g

This means that the area of the rectangle representing those coins in the histogram is:

144 coins x 9 g = 1296 g

To find the total number of coins, we need to calculate the area of the remaining rectangles in the histogram. Since the width of each rectangle is 9 g, we can calculate the height of each rectangle by dividing its area by 9 g.

The second rectangle has an area of:

90 coins x 9 g = 810 g

So its height is:

810 g / 9 g = 90 coins

The third rectangle has an area of:

60 coins x 9 g = 540 g

So its height is:

540 g / 9 g = 60 coins

The fourth rectangle has an area of:

30 coins x 9 g = 270 g

So its height is:

270 g / 9 g = 30 coins

The fifth rectangle has an area of:

10 coins x 9 g = 90 g

So its height is:

90 g / 9 g = 10 coins

Finally, the sixth rectangle has an area of:

5 coins x 9 g = 45 g

So its height is:

45 g / 9 g = 5 coins

Therefore, the total number of coins in the museum's collection is:

144 + 90 + 60 + 30 + 10 + 5 = 339 coins.

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1) The line number and the plot of the numbers are shown in the graph that is attached.

2) The opposite of an integer is offset by the same amount from zero.

The three numerals on the number line and their corresponding opposites are shown in the pictures that are attached.

We must determine the number of places on the scale starting at zero to determine a number's opposite. The same amount of places is then counted starting from zero in the opposite direction.

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Complete question:

Draw a number line, and create a scale for the number line to plot the points −2, 4, and 6.

a. Graph each point and its opposite on the number line.

b. Explain how you found the opposite of each point.

16.15 is the value of ZY in triangle .

What is known as a triangle?

The three vertices of a triangle make it a three-sided polygon. The angles of the triangle are formed by the connection of the three sides end to end at a single point.

                        The triangle's three angles add up to 180 degrees. There are three straight sides to this two-dimensional shape. An example of a 3-sided polygon is a triangle. Three triangle angles added together equal 180 degrees.

In ΔUST and ΔZXY

     UT/ZY =  UA/ZB

     8.5/ZY =  6/11.4

     6 *  ZY =  11.4 * 8.5

            ZY = 96.9/6

                  = 16.15

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As I became more experienced playing the game, I began to adjust my budgeting process to account for my changing needs.

Budgeting is a financial planning process that involves creating a plan to manage your income and expenses over a specific period of time.

My budgeting process involved taking the total amount of money I had to spend and splitting it up into different categories based on my needs.

I allocated a portion of the money for food, transportation, entertainment, and other expenses.

As I became more experienced playing the game, I began to adjust my budgeting process to account for my changing needs.

For example, I started to prioritize saving for a larger expense, such as a trip, over smaller items like eating out or entertainment.

I also re-evaluated my spending habits regularly to see if I could be saving money in any area or if I could be spending it more efficiently.

This process helped me to become more mindful and intentional with my spending and allowed me to make smart decisions with my money.

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Answer: A. Let's use x to represent the number of hours Opal works for the photographer, and y to represent the number of hours she coaches soccer. Then we can create the following system of inequalities to represent the situation:

12x + 7y ≥ 150 (Opal needs to earn at least $150 per week)

x + y ≤ 20 (Opal cannot work more than 20 hours per week)

B. There are different ways Opal can meet her goals, but here are two possible solutions:

Solution 1: Opal works for the photographer for 10 hours and coaches soccer for 10 hours. Then her total earnings for the week would be:

12(10) + 7(10) = 120 + 70 = $190

This meets her goal of earning at least $150 per week, and it also satisfies the constraint that she cannot work more than 20 hours per week.

Solution 2: Opal works for the photographer for 15 hours and coaches soccer for 5 hours. Then her total earnings for the week would be:

12(15) + 7(5) = 180 + 35 = $215

This also meets her goal of earning at least $150 per week, and it satisfies the constraint that she cannot work more than 20 hours per week.

C. To check if (10,6) is a solution to the system of inequalities, we need to substitute x = 10 and y = 6 into both inequalities and see if they are true:

12(10) + 7(6) ≥ 150

120 + 42 ≥ 150

162 ≥ 150 (true)

10 + 6 ≤ 20 (true)

Since both inequalities are true, (10,6) is a solution to the system. However, this solution does not meet Opal's goal of earning at least $150 per week, as her total earnings would be:

12(10) + 7(6) = 120 + 42 = $162

So, while (10,6) satisfies the constraints of the system, it is not a valid solution to the problem.

Step-by-step explanation:

Answer:

[tex]x=\frac{6}{5}[/tex]

Step-by-step explanation:

Solve for x:

[tex]8x+6 < 18-2x[/tex]

Add 2x to both sides

[tex]10x+6 < 18[/tex]

Subtract 6 on both sides

[tex]10x < 12[/tex]

Divide by 10

[tex]x=\frac{12}{10}[/tex]

Simplify fraction

[tex]x=\frac{6}{5}[/tex]

A sample of 312 bacteria would be needed to estimate the mean lifespan of the species of bacteria within a margin of error of 0.75 hours with 95% confidence.

To determine the sample size required to estimate the mean lifespan of a certain species of bacteria within a margin of error of 0.75 hours with a 95% level of confidence, we can use the following formula:

n = [Z*(σ/ME)]^2

where:

n = sample size

Z = the z-score corresponding to the desired level of confidence, which is 1.96 for a 95% level of confidence

σ = the population standard deviation

ME = the desired margin of error

From the given information, we have:

sample mean = Xbar = hours

sample size = n = 35

sample standard deviation = s = hours

desired margin of error = ME = 0.75 hours

level of confidence = 95%, which corresponds to a z-score of 1.96

We do not know the population standard deviation, but we can use the sample standard deviation as an estimate since the sample size is greater than 30. Thus, we have:

σ ≈ s = hours

Substituting the values into the formula, we get:

n = [1.96*(6.81/0.75)]^2 ≈ 311.84

Rounding up to the nearest whole number, we get a sample size of 312 bacteria.

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The value of x, considering the similar triangles, is given as follows:

x = 26.

Similar triangles are triangles that share these two features listed as follows:

The two triangles in this problem are similar, due to the bisection, hence the equivalent side lengths are given as follows:

Then the proportional relationship is given as follows:

x/13 = 10/5.

Meaning that the value of x is given as follows:

x/13 = 2

x = 26.

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The equations of the functions are x = -10, y = x + 5 and y = x² + 6x + 10, and the identities are shown below

Constant function

This function remains constant regardless of the input and/or output.

The graph shows a vertical line located at x = -10.

The function represented by this graph is constant, with a domain of x = -10 and a range of y [0, 12.25]

Linear function

The function varies continuously in relation to both x and y.

We can observe two points on the graph, which are (-4, 1) and (-2, 3).

From the point, we can see that y is more than x by 5

This means that the function is y = x + 5

The following identities of the functions are Domain: [-4, -2] and Range: [1, 3]

Quadratic function

This function can be represented as

y = a(x - h)² + k

From the graph, we have

(h, k) = (-3, 1) and (x, y) = (-2, 2)

By substitution, we have

y = a(x + 3)² + 1

By substitution, we have

2 = a(-2 + 3)² + 1

Solving for a, we have

a = 1

So, we have

y = (x + 3)² + 1

y = x² + 6x + 10

This means that the function is y = x² + 6x + 10 with the following identities

Domain: [-4, -2]

Range: [1. 2]

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The probability that the student selected to work on a problem on the board is C. 0. 20.

The total number of students in Junior grade can be found to be 11 by the graph. Out of this 11, the number of female students is:

= 11 - 6

= 5 students

The total number of students in the survey is:

= 7 sophomore + 11 junior + 7 senior

= 25 students

The probability that a female junior student is chosen is:

= 5 / 25 x 100 %

= 1 / 5 x 100 %

= 0. 20

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The required fencing feet. for the right triangle lot, is given as 560.84.

Perimeter is the measure of the figure on its circumference. Here, the two sides of the lot is known, we have to evaluate the third side before calculating the perimeter.

Measure of the third side = √[200² + 125²]

The measure of the third side = 235.84

Now, the total fencing required = Perimeter of the triangle

= 200 + 125 + 235.84

= 560.84 ft

Thus, the required fencing for the right triangle lot is 560.84.

Full question "David must install fencing around a lot that is shaped like a right triangle. The side of the lot that runs east-west is 200 ft long. The side of the lot that runs north-south is 125 ft long."

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The required mean and the standard deviation of the given data based on number of tickets is equal to 111.2 and 32.84 respectively.

Calculate the mean,

Add up all the values in the set and divide by the total number of values,

Mean

= ( Sum of all the observations ) / ( Total number of observations )

= (135 + 71 + 69 + 80 + 158 + 152 + 161 + 96 + 122 + 118 + 87 + 85) / 12

= 1334 / 12

= 111.2

So the mean number of tickets sold is 111.2.

Standard deviation,

Calculate the standard deviation,

First need to calculate the variance.

The difference between each value and the mean, squaring those differences, adding them up, and dividing by the total number of values,

= ((135 - 111.2)^2 + (71 - 111.2)^2 + (69 - 111.2)^2 + (80 - 111.2)^2 + (158 - 111.2)^2 + (152 - 111.2)^2 + (161 - 111.2)^2 + (96 - 111.2)^2 + (122 - 111.2)^2 + (118 - 111.2)^2 + (87 - 111.2)^2 + (85 - 111.2)^2) / 12

= (566.44 + 1616.04 + 1780.84 + 973.44 + 2190.24 + 1664.64 + 2480.04 + 231.04 + 116.64 + 46.24 + 585.64+ 686.44) / 12

= 12937.68 /12

= 1078.14

Square root of the variance to get the standard deviation,

√1078.14= 32.84

So the standard deviation is approximately 32.84.

Therefore, the mean and the standard deviation is equal to 111.2 and 32.84 respectively.

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The above question is incomplete, the complete question is:

Susan keeps track of the number of tickets sold for each play presented at the community theater. within how many standard deviations of the mean do all the values fall?

135, 71, 69, 80, 158, 152, 161, 96, 122, 118, 87, 85.

The head circumference of a newborn boy who marks the start of the 75th percentile is approximately 35.38 cm.

To find the head circumference of a newborn boy who marks the start of the 75th percentile, we need to first find the z-score corresponding to the 75th percentile using the standard normal distribution.

The z-score formula is

z = (x - μ) / σ

where x is the observed value, μ is the mean, and σ is the standard deviation.

To find the z-score that corresponds to the 75th percentile, we need to look up the z-score associated with a cumulative area of 0.75 under the standard normal distribution curve. This value can be found using a table or calculator and is approximately 0.674.

Now we can use the formula for the z-score to solve for the head circumference of a newborn boy at the 75th percentile

z = (x - μ) / σ

0.674 = (x - 34.5) / 1.3

0.674 × 1.3 = x - 34.5

0.8762 + 34.5 = x

x = 35.3762

x ≈ 35.38 cm

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The probability that the maximum speed of a randomly selected moped differs from the mean value by at most 1.5 standard deviations is 0.8664

We know that the maximum speed of a moped is normally distributed with mean μ = 46.8 km/h and standard deviation σ = 1.75 km/h. We want to find the probability that the maximum speed differs from the mean value by at most 1.5 standard deviations, i.e., we want to find P(|X - μ| ≤ 1.5σ), where X is the maximum speed of a moped.

Using the properties of the normal distribution, we can standardize X to get a standard normal distribution

Z = (X - μ) / σ

Substituting the values of μ and σ, we get

Z = (X - 46.8) / 1.75

We want to find P(|Z| ≤ 1.5), which is the probability that Z lies between -1.5 and 1.5.

Using a standard normal distribution table or a calculator with a normal distribution function, we can find that P(|Z| ≤ 1.5) = 0.8664.

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The given question is incomplete, the complete question is:

Mopeds (small motorcycles with an engine capacity below 50 cm3) are very popular in Europe because of their mobility, ease of operation, and low cost. Suppose the maximum speed of a moped is normally distributed with mean value 46.8 km/h and standard deviation 1.75 km/h. Consider randomly selecting a single such moped. What is the probability that maximum speed differs from the mean value by at most 1.5 standard deviations?

Two functions that satisfy the given condition and are linearly independent on (-∞,∞) are f1(x) = e^(x) and f2(x) = e^(x)

Let's start by recalling the definition of the Wronskian for two functions f1(x) and f2(x):

W(f1,f2)(x) = f1(x)f2'(x) - f1'(x)f2(x)

Given the Wronskian W(f1,f2)(x) = e^(2x), we can try to find functions f1(x) and f2(x) that satisfy this condition. One possible solution is:

f1(x) = e^(x)

f2(x) = e^(x + C)

where C is a constant. We can now calculate the Wronskian of f1(x) and f2(x):

W(f1,f2)(x) = f1(x)f2'(x) - f1'(x)f2(x)

= e^(x) [e^(x + C)]' - [e^(x)]' e^(x + C)

= e^(x) e^(x + C) - e^(x) e^(x + C)

= 0

This means that f1(x) and f2(x) are linearly dependent. However, we can modify our choice of f2(x) by setting C= -x, which gives:

f2(x) = e^(2x - x) = e^(x)

Now we can calculate the Wronskian again:

W(f1,f2)(x) = f1(x)f2'(x) - f1'(x)f2(x)

= e^(x) [e^(x)]' - [e^(x)]' e^(x)

= e^(2x)

Since the Wronskian is non-zero, this means that f1(x) and f2(x) are linearly independent on (-∞,∞).

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The given question is incomplete, the complete question is:

Determine two functions, defined on the interval (−∞,∞), whose Wronskian is given by W(f 1 ,f 2)=e ^2x. Are the functions that you found linearly independent on (−∞,∞)

Answer:1 hour 15 Minutes

Step-by-step explanation:The glider begins its flight mile above the ground.

Distance above the ground after 45 minutes =

Change in height of the glider

Next, we determine how long the entire descent last.

Expressing the distance moved as a ratio of time taken

Therefore: Total Time taken =45+30=75 Minutes

=1 hour 15 Minutes

the greatest common factor of the given expressions is -5xy.

To find the greatest common factor of the given expressions, we need to factor them first.

[tex]-15x^2y - 10xy^3 + 5xy^4 = -5xy(3x^2 + 2y^2 - y^3)\\5xy = 5xy(1)\\5x^2y^4 = 5xy^4(x^2)\\5xy^2 = 5xy^2(1)[/tex]

xy = xy(1)

Now, we can find the common factors by taking the minimum exponent of each variable in the factors:

The common factors are:5xy

Therefore, the greatest common factor of the given expressions is -5xy.

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Answer:

If 2inches= 20 miles then 1inches =10miles

5.6 inches=5.6*10

=56miles

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Answer:

56 miles

Step-by-step explanation:

Use a proportion.

2 inches is to 20 miles as 5.6 inches is to x miles.

2:20 = 5.6:x

2/20 = 5.6/x

1/10 = 5.6/x

1 × x = 10 × 5.6

Cross multiply.

x = 56

Answer: 56 miles

Answer:

Step-by-step explanation:

Part A: To create a triangle: a ≤ b+c and a ≥ b−c.

Part B: Three side lengths form a triangle: A.10, 20, 15 ; B.8, 4, 12 and D.20, 10, 30.

The triangle inequality, written as a + b c, states that any two triangle sides added together must be greater than or equal to the third side a + b ≥ c. The basic tenet of the theorem is that a straight line connects any two places.

Part A: a__b+c and a __b−c.

By using the  triangle inequality,

The longest side is less than equal to the other sum of other two sides:

Thus,

a ≤ b+c and a ≥ b−c.

Part B: Three side lengths form a triangle.

A.10, 20, 15

10 + 15 ≥ 20 (longest side) (correct option.)

B.8, 4, 12

8 + 4 ≥ 12 (longest side) (correct option.)

C.8, 8,20

8 + 8 ≥ 20 (longest side) (incorrect option.)

But 16 < 20 (incorrect option.)

D.20, 10, 30

10 + 20 ≥ 30 (longest side) (correct option.)

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Answer:

[tex]\frac{2xx^{\frac{1}{4} } }{y^{\frac{11}{3} } }[/tex]

Step-by-step explanation:

The first term of the geometric progression is 1.

What is geometric progression?

Each term in the sequence preceding it is multiplied by a fixed number called a common ratio to produce the next phrase in a series known as a geometric progression (GP). A geometric number sequence that follows a pattern is another name for this progression.

We are given a geometric progression as b₁, b₂, 4, -8, ....

From this, we get the common ratio as [tex]\frac{-8}{4}[/tex], which is -2.

Now, we know that

a₃ = 4 and r = -2

So,

⇒a₃ = a₁ [tex]r^{n-1}[/tex]

⇒4 = a₁ * [tex]-2^ {3-1}[/tex]

⇒4 = 4a₁

⇒a₁ = 1

Hence, the first term of the geometric progression is 1.

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Since, there are multiple questions, so the question answered above is:

Question: Find the first term of the geometric progression:

b₁, b₂, 4, -8, ...

a) 1; b) -1; c) 28; d) [tex]\frac{1}{2}[/tex]

In one hour, Ben would have completed 9/10 or 90% of his assignment.

Let us assume that the total assignment stands as x. Ben finished 3/5x in 2/3 of 60 minutes. 2/3 of 60 minutes is 40 minutes. So, 3/5x was finished in 40 minutes.

If 3.5x was finished in 40 minutes, in 60 minutes, Ben would have completed 90% of his assignment. This can be represented thus:

3/5x = 40 min

?       = 60 min

3/5x × 60 min/40 min

36xmin/40 min

x = 9/10

In summary, we can conclude that Ben would have completed 90% of his assignment in one hour. The same result will be obtained with visual models like the Tape diagram.

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Answer:

It cannot be in the sequence because counting back in 0.4 will give you even numbers and not odd hence 1.5 cannnot be in the sequence.

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