Na2CO3(s)+2HNO3(aq) complete and balance the reaction.

The amount of energy for the reaction using Hess's Law is -459.82 kJ/mol.

Based on the calculation, the formation is exothermic.

To use Hess' Law, we need to rearrange and multiply the given chemical equations to get the desired equation:

2 Mg + 2 HCl → 2 MgCl₂ + H₂ (multiply Equation 1 by 2)

2 MgO + 4 HCl → 2 MgCl2 + 2 H₂O (multiply Equation 2 by 2)

2 H₂ + O₂ → 2 H₂O (multiply Equation 3 by 2)

2 Mg + O₂ + 4 HCl → 2 MgCl₂ + 2 H₂O (add the above equations)

The enthalpy change of the desired equation can be calculated as follows:

AH = [AH₁ × 2] + [AH₂ × 2] + [AH₃ × (-2)]

AH = [(Answer to #5 -1) × 2] + [(-125 kJ/mol) × 2] + [(-285.82 kJ/mol) × (-2)]

AH = [-457.82 - 2] kJ/mol

AH = -459.82 kJ/mol

Since the value of AH is negative, the formation of MgO is exothermic. This means that energy is released during the formation of MgO.

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Answer:

simplified-74400000000000000000000000x

Explanation:

The minimum mass of hydrochloric acid that could be left over by the chemical reaction is 18.23 g.

Moles in chemistry is a unit of measurement for the amount of a substance. It is equal to the number of atoms or molecules in a given mass of a substance, and is represented by the symbol ‘mol’. The molar mass of a substance is the mass of one mole of that substance, expressed in grams. It is important for calculating the amount of energy or reactants needed for a reaction. Moles can also be used to measure the concentration of a solution.

The minimum mass of hydrochloric acid that could be left over by this chemical reaction can be calculated using the following equation:

Moles of HCl = Mass HCl / Molar Mass HCl

Moles of NaOH = Mass NaOH / Molar Mass NaOH

Moles of HCl must equal moles of NaOH in the reaction, so:

Moles HCl = Moles NaOH

Mass HCl / Molar Mass HCl = Mass NaOH / Molar Mass NaOH

Rearranging for mass HCl:

Mass HCl = Molar Mass HCl x Mass NaOH / Molar Mass NaOH

Given:

Mass HCl = 28.8 g
Molar Mass HCl = 36.46 g/mol
Mass NaOH = 20.0 g
Molar Mass NaOH = 40.0 g/mol

Substituting values:

Mass HCl = 36.46 g/mol x 20.0 g / 40.0 g/mol

Mass HCl = 18.23 g

Therefore, the minimum mass of hydrochloric acid that could be left over by the chemical reaction is 18.23 g.

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Simple atomic models called Bohr-Rutherford diagrams display how many electrons are present in each of an atom's outermost shells.

The Bohr theory only applies to organisms with a single electron. Three electrons make up the lithium atom. Hence, the lithium atom does not fit into Bohr's hypothesis.

Lithium is an air-reactive alkali metal that tarnishes quickly to a dull silvery-grey and finally black. It is a silvery-white to grey alkali metal with a metal-lic lustre when new. At 20 °C, it is the least dense and lightest metal of all the elements that are not gases, and it floats on water.

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The mass of the water that is going to be produced from the balanced reaction equation is 84 g.

Stoichiometry is the branch of chemistry that deals with the quantitative relationship between the reactants and products in a chemical reaction. It involves the calculation of the amounts of reactants needed to produce a certain amount of product, or the amount of product produced from a given amount of reactants.

Number of moles of Fe = 195.9 g/56 g/mol

= 3.5 moles

If 3 moles of Fe is produced when 4 moles of water is produced

3.5 moles of Fe is produced when 3.5 * 4/3

= 4.7 moles

Now we have that the mas of water is;

4.7 moles * 18 g/mol

= 84 g

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The pH of the buffer after the addition of 0.020 mol of NaOH is 4.83.

Henderson-Hasselbalch equation: pH = pKa + log([A^-]/[HA]),

[CH3COOH] = 0.300 mol/1.00 L = 0.300 M

[CH3COO^-] = 0.300 mol/1.00 L = 0.300 M

CH3COOH + NaOH → CH3COO^- + H2O

[CH3COOH] = (0.300 mol - 0.020 mol)/1.00 L = 0.280 M

CH3COO^-] = (0.300 mol + 0.020 mol)/1.00 L = 0.320 M

pH = pKa + log([CH3COO^-]/[CH3COOH])

pH = 4.74 + log(0.320/0.280)

pH = 4.83

The pH of a solution can be measured using a pH meter or pH paper, which changes color based on the pH of the solution. It is a dimensionless quantity that indicates the concentration of hydrogen ions (H+) in a solution. pH stands for "power of hydrogen" and is defined as the negative logarithm of the hydrogen ion concentration. A pH of 7 is considered neutral, pH values below 7 indicate acidity, and pH values above 7 indicate alkalinity.

pH is an important parameter in many chemical and biological processes, as it can affect the behavior and properties of molecules and ions in solution. Maintaining the correct pH in biological systems is critical for many physiological processes, and pH control is important in many industrial processes as well.

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The level of acidity or alkalinity of aqueous solutions can be conveniently expressed using the pH scale, also known as the pOH scale.

"The negative of the logarithm of the molar hydronium-ion concentration" is how pH is defined. The pH formula is written as. P H equals l o g [H 3 0 +] You can alternatively write the pH Formula as. l o g [H +] = p H

The pH of a solution is equal to the solution's hydrogen ion concentration divided by its negative logarithm to base 10:

   pH = -log₁₀[H⁺]

     pOH = -log₁₀[OH⁻]

For any aqueous solution, the sum of the pH and pOH is 14. That is;

                    pH + pOH = 14

Now solving for [OH⁻]:

              HNO₃ + H₂O → H₃O⁺ + NO₃⁻

   Since pH + pOH = 14

              pOH = 14 - pH = 14 -3.75 = 10.25

 since pOH = -log₁₀[OH⁻]

             10.25 = -log₁₀(OH⁻)

             [OH⁻] = inverse log₁₀(-pOH)

             [OH⁻] = inverse log₁₀(-10.25) = 5.62 x 10⁻¹¹moldm⁻³

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Answer:

[OH− ] = 5.62

n = -11

pOH = 10.25

Explanation:

I did it not too long ago

Answer:

human error , random error .

The percent of C in Ca(C2H3O2)2 is 27.28%.

The formula mass of Ca(C2H3O2)2 is 158.17 g/mol.

The percent of H in Ca(C2H3O2)2 is 2.54% and the percent of O is 54.50%.

To find the percent of C in Ca(C2H3O2)2, we first need to calculate the molar mass of the compound:

Molar mass of Ca(C2H3O2)2 = (1 × 40.08) + (2 × (2 × 12.01 + 3 × 1.01 + 2 × 16.00)) = 2 × 158.17 = 316.34 g/mol

Now we can calculate the percent of C:

Mass of C in Ca(C2H3O2)2 = 2 × (2 × 12.01) = 48.04 g/mol

Percent of C in Ca(C2H3O2)2 = (48.04 g/mol ÷ 316.34 g/mol) × 100% = 15.19%

Therefore, the percent of C in Ca(C2H3O2)2 is 15.19%, rounded to the hundredths place.

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Because it demonstrated how the atoms of copper and silver were changed by oxidation and reduction, the experiment achieved its goal. The presence of a specific halogen in a presumed halogenoalkane can be determined using silver nitrate solution.

Calculating the products and reactants of a chemical process is what we mean by stoichiometry. Numbers are essentially its main focus. When using balanced formulas to determine the proportions of reactants and products, stoichiometry is a key concept in chemistry.

The study of quantifiable correlations found in chemical equations and reactions is known as stoichiometry. The terms stoicheion, which means element, and metron, which means measure, are the origins of the name.

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The reaction between C2H4 (ethylene) and H2O (water) to form CH3CH2OH (ethanol) is a type of hydration reaction. For this reaction to occur, two conditions need to be met:

The presence of a suitable catalyst: The reaction is catalyzed by an acid catalyst, such as phosphoric acid (H3PO4). The acid catalyst helps to break the double bond in C2H4 and promotes the addition of water to form ethanol.

The reaction requires high pressure and temperature to proceed. The typical reaction conditions involve a temperature range of 300-400 °C and a pressure range of 60-70 atm. These conditions are necessary to overcome the high activation energy of the reaction and promote the formation of the desired product, ethanol.

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The mass of butane needed to produce 67.5 g of carbon dioxide is 22.27 g.

The balanced chemical equation for the combustion of butane (C4H10) is:

2 C4H10 + 13 O2 → 8 CO2 + 10 H2O

This equation shows that 2 moles of butane react with 13 moles of oxygen to produce 8 moles of carbon dioxide. The molar mass of butane is 58.12 g/mol, and the molar mass of carbon dioxide is 44.01 g/mol.

To calculate the mass of butane needed to produce 67.5 g of carbon dioxide, we can use the following steps:

Calculate the number of moles of carbon dioxide produced:

67.5 g CO2 x (1 mol CO2 / 44.01 g CO2) = 1.534 mol CO2

Use the mole ratio from the balanced chemical equation to find the number of moles of butane needed:

1.534 mol CO2 x (2 mol C4H10 / 8 mol CO2) = 0.3835 mol C4H10

Calculate the mass of butane needed:

0.3835 mol C4H10 x 58.12 g/mol = 22.27 g C4H10

Therefore, the mass of butane needed to produce 67.5 g of carbon dioxide is 22.27 g.

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Answer:

Explanation:

The balanced chemical equation for the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is:

HCl(aq) + NaOH(s) → NaCl(aq) + H2O(l)

From the balanced equation, we can see that one mole of hydrochloric acid reacts with one mole of sodium hydroxide to produce one mole of sodium chloride and one mole of water.

First, we need to determine which reactant is limiting, i.e., which reactant is completely consumed in the reaction. To do this, we need to compare the number of moles of each reactant, using their respective molar masses:

Molar mass of HCl = 1.008 g/mol (atomic weight of hydrogen) + 35.45 g/mol (atomic weight of chlorine) = 36.46 g/mol

Molar mass of NaOH = 22.99 g/mol (atomic weight of sodium) + 16.00 g/mol (atomic weight of oxygen) + 1.008 g/mol (atomic weight of hydrogen) = 39.99 g/mol

Number of moles of HCl = mass / molar mass = 30.0 g / 36.46 g/mol ≈ 0.823 mol

Number of moles of NaOH = mass / molar mass = 14.3 g / 39.99 g/mol ≈ 0.358 mol

Since the stoichiometric ratio between HCl and NaOH is 1:1, NaOH is the limiting reactant because it has fewer moles than HCl.

Therefore, we can calculate the maximum mass of NaCl that can be produced by the reaction using the number of moles of NaOH:

Number of moles of NaCl produced = number of moles of NaOH used in the reaction = 0.358 mol

Mass of NaCl produced = number of moles of NaCl produced x molar mass of NaCl

Molar mass of NaCl = 22.99 g/mol (atomic weight of sodium) + 35.45 g/mol (atomic weight of chlorine) = 58.44 g/mol

Mass of NaCl produced = 0.358 mol x 58.44 g/mol = 20.9 g

Therefore, the maximum mass of NaCl that can be produced by the reaction is approximately 20.9 g

The ideal gas law can be used to solve this issue:

PV = nRT

where R is the universal gas constant, n is the number of moles, P is the gas's pressure, V is its volume, and T is its temperature.

The following expression can be used to link the starting and final volumes and moles under the assumption that the gas's pressure and temperature don't change:

V1 / n1 = V2 / n2

where V1 and n1 represent the volume and number of moles at the beginning, and V2 and n2 represent the volume and number of moles at the end.

Inputting the specified values results in:

15 L/n2 = 3 L / 3 mol

When we simplify and account for n2, we obtain:

n2 = 3 mol (15 L / 3 L)

n2 = 15

As a result, 15 mol of the gas are present when the volume is changed to 15 L.

Using the equation V = nV m, where V is the volume in liters, n is the amount of gas in moles, and V m is the molar gas volume in liters per mole, is another technique to determine the solution. We may substitute the volume and molar gas volume from the question into this equation.

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A sample lab report that measures pH levels is given below:

Introduction:

In this experiment, we measured the pH levels of various substances using a pH meter. The pH meter measures the acidity or basicity of a substance on a scale of 0 to 14, with 0 being extremely acidic, 7 being neutral, and 14 being extremely basic.

Materials:

pH meter

Distilled water

Hydrochloric acid (HCl)

Sodium hydroxide (NaOH)

Vinegar

Lemon juice

Baking soda

Tap water

Procedure:

Calibrated the pH meter according to the manufacturer's instructions using distilled water.

Prepared five test solutions in beakers:

50 mL of 0.1 M HCl

50 mL of 0.1 M NaOH

50 mL of vinegar

50 mL of lemon juice

50 mL of baking soda

Rinsed the pH meter probe with distilled water and then dipped it into each test solution, making sure that the probe did not touch the bottom or sides of the beaker.

Recorded the pH measurement for each solution and compared it to the expected pH range based on the known properties of the substances.

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Answer:

I have attached my interpretation of the pH measuring lab.  All I ask is that you at least change some of the answers, please  

Explanation:

Several everyday items, such as incandescent light bulbs (60 joules/s) and gasoline (130 million joules/gallon), use or release energy in varying amounts. Chemical reactions are predicted to change in energy by Hess' Law.

The Hess law is most commonly used in business to measure how much energy an engine produces and consumes, as well as in our bodies' responses to food consumption.

For instance, carbon and extra oxygen can react to generate carbon dioxide. Directly or indirectly, when carbon and oxygen combine, carbon dioxide is produced, either first as carbon monoxide and later as carbon dioxide.

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The theoretical yield of ammonia is 40.8 grams. Rounded to the tenths place, the answer is 40.8 g.

To determine the theoretical yield of ammonia (NH3), we first need to balance the chemical equation:

N2 + 3H2 → 2NH3

Now we can use the balanced equation to calculate the theoretical yield of NH3. Since we know that 29 L of N2 reacts with 14 g of H2, we need to determine which reactant is limiting and calculate the amount of NH3 that can be formed from that limiting reactant.

First, let's convert the volume of N2 to moles using the ideal gas law:

PV = nRT

n = PV/RT = (1 atm)(29 L)/(0.0821 L·atm/mol·K)(298 K) = 1.2 mol N2

Next, let's convert the mass of H2 to moles:

m = n·M

n = m/M = 14 g / 2.0 g/mol = 7.0 mol H2

Now we can compare the mole ratios of N2 and H2 in the balanced equation to determine which reactant is limiting:

N2:H2 = 1:3

1.2 mol N2 × (3 mol H2/1 mol N2) = 3.6 mol H2

Since we only have 7.0 mol of H2, H2 is not limiting and N2 is limiting. Therefore, we will use the mole ratio between N2 and NH3 to calculate the theoretical yield of NH3:

N2:NH3 = 1:2

1.2 mol N2 × (2 mol NH3/1 mol N2) = 2.4 mol NH3

Finally, we can convert moles of NH3 to grams using the molar mass of NH3:

m = n·M

m = 2.4 mol · 17.0 g/mol = 40.8 g NH3

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When 50.0 mL of distilled water is added to 100.0 mL of a saturated solution of copper (I) chloride (KSP = 1.72x10-7) with some solid present, the answer becomes diluted.

When 50.0 mL of distilled water is added to 100.0 mL of a saturated solution of copper (I) chloride (KSP = 1.72x10-7) with some solid present, the [Cu+] will decrease because the answer is now less concentrated. The solid in the beaker will remain the same because the solution is still saturated.

The first beaker will expand when heat is applied because it will absorb the heat. Therefore the water level will first decrease due to the beaker's increased volume. Water will eventually warm up and expand as its temperature rises. Water level will consequently rise later.

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Answer:

zinc + hydrochloric acid = zinc chloride + hydrogen

copper carbonate + sulfuric acid = copper sulfate + carbon dioxide + water

copper + nitric acid = copper nitrate + nitrogen dioxide + water

Explanation:

Zn + 2HCl → ZnCl2 + H2

CuCO3 + H2SO4 → CuSO4 + CO2 + H2O

Cu + 4HNO3 → Cu(NO3)2 + 2NO2 + 2H2O

Answer:

zinc + hydrochloric acid = zinc chloride + hydrogen

copper carbonate + sulfuric acid = copper sulfate + carbon dioxide + water

zinc + nitric acid = zinc nitrate + hydrogen gas + water

To calculate the volume of 0.300M solution that contains 1.5g of the solute, we need to use the following formula:

moles of solute = mass of solute / molar mass of solute

moles of solute = (1.5g) / (1 x H + 1 x S + 3 x O) g/mol

moles of solute = (1.5g) / (1 + 32 + 3x16) g/mol

moles of solute = (1.5g) / 98 g/mol

moles of solute = 0.015306 moles

Now, we can use the following formula to calculate the volume of the solution:

moles of solute = molarity x volume (in liters)

0.015306 moles = 0.300 M x volume (in liters)

volume (in liters) = 0.015306 moles / 0.300 M

volume (in liters) = 0.05102 L

Finally, we can convert the volume from liters to milliliters (mL):

volume (in mL) = 0.05102 L x 1000 mL/L

volume (in mL) = 51.02 mL

Therefore, 51.02 mL of 0.300M solution would contain 1.5g of solute.

Answer:

204.8 K

Explanation:

(P1 * V1)/T1 = (P2 * V2)/T2

"If the pressure remains constant" means

you can cancel the pressure part of the equation

T2 = (V2 * T1)/(V1)

T2 = (2.64 L * 453 K)/(5.82 L)

T2 = 204.8 K

chatgpt

A sample of xenon gas occupies a volume of 5.82 L at 453 K. If the pressure remains constant, the temperature that will make this same xenon gas sample have a volume of 2.64 L is 220K.

The combined gas law is the law of of gaseous state which is made by combination of Boyle's law, Charle's law, Avogadro's law and Gay Lussac's law.

It is a mathematical expression that relates Pressure, Volume and Temperature.

(P1 × V1)÷T1 = (P2 × V2)÷T2

We can also use the following relation-

PV = nRT

At constant pressure,

V1÷T1 = V2÷T2

This is Charles's law.

V1 = 5.82L

T1 = 453K

V2 = 2.64L

T2 = ?

T2 = 220K

Therefore, A sample of xenon gas occupies a volume of 5.82 L at 453 K. If the pressure remains constant, the temperature that will make this same xenon gas sample have a volume of 2.64 L is 220K.

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The ball will sink because its weight is greater than the amount of water it displaces. Since their weight is less than the amount of water they displace, objects made of aluminium foil like a boat, paper and cups will float on water.

Whether an item will float or sink in another material depends on its density. If an object's density is lower than the liquid it is placed in, it will float. If an object is heavier than the liquid it is immersed in, it will sink.

While individuals may create their goods or aluminium foils with the aluminium, beating the metal to form aluminium foil is a physical change.

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According to the Heisenberg Uncertainty Principle, we can only know one of two things at once: either the speed (momentum) or the position.

The uncertainty principle can also be explained in terms of a particle's momentum and position. The momentum of a particle is calculated by dividing its mass by its speed.

Heisenberg's Uncertainty Principle states that there is some uncertainty when measuring a particle's variable. a term frequently used to describe the position and momentum of a particle.

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The final molarity of the acetate anion in the solution is 0.06148 M.

The balanced chemical equation for the reaction between lead(II) acetate and ammonium sulfate is:

[tex]Pb(CH_3COO)_2 + (NH_4)_2SO_4 -- > PbSO_4 + 2NH_4CH_3COO[/tex]

So, if we dissolve 1 mole of Pb(CH₃COO)₂, it will produce 2 moles of acetate anion.

Moles of Pb(CH₃COO)₂ = (mass of Pb(CH₃COO)₂) / (molar mass of Pb(CH₃COO)₂)

Assuming the mass of Pb(CH₃COO)₂ is given, let's say it is 5 g, then:

Moles of Pb(CH₃COO)₂ = (5 g) / (Pb(CH₃COO)₂ molar mass)

The molar mass of Pb(CH₃COO)₂ is:

207.2 g/mol (molar mass of Pb) + 2(16.00 g/mol) + 2(12.01 g/mol) = 325.27 g/mol

Substituting the values, we get:

Moles of Pb(CH₃COO)₂ = (5 g) / (325.27 g/mol) = 0.01537 mol

Since 1 mole of Pb(CH3COO)₂ produces 2 moles of acetate anion, the total number of moles of acetate anion in the solution is:

Moles of acetate anion = 2 x 0.01537 mol = 0.03074 mol

We can calculate the final molarity of the acetate anion in the solution:

Molarity of acetate anion = Moles of acetate anion / Volume of solution

Molarity of acetate anion = 0.03074 mol / 0.5 L = 0.06148 M

The final molarity of the acetate anion in the solution is 0.06148 M.

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The pH of the solution is equal to the pKa of the acid when the concentrations of the conjugate acid and base are equal.

The Henderson-Hasselbalch equation is given by:

pH = pKa + log([A-]/[HA])

Where:

pH = the pH of the solution

pKa = the acid dissociation constant of the acid

[A-] = the concentration of the conjugate base

[HA] = the concentration of the acid

When the concentrations of the conjugate acid and base are equal, [A-] = [HA], and the Henderson-Hasselbalch equation can be simplified to:

pH = pKa + log(1)

log(1) = 0, so:

pH = pKa

Therefore, when the concentrations of the conjugate acid and base are equal, the pH of the solution is equal to the pKa of the acid. This can be used to determine the acid dissociation constant (Ka) of the acid by measuring the pH of the solution when the concentrations of the conjugate acid and base are equal.

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Answer:

At STP (standard temperature and pressure), the conditions are:

Temperature (T) = 273.15 K

Pressure (P) = 1 atm = 101.3 kPa

Volume (V) = 22.4 L (for one mole of gas)

So, for a gas at STP with a volume of 5 L, we can use the following formula to calculate the number of moles present:

n = V / Vm

where:

n = number of moles

V = volume of gas (in liters)

Vm = molar volume of gas at STP (22.4 L/mol)

Plugging in the values, we get:

n = 5 L / 22.4 L/mol

n = 0.2232 mol (rounded to four significant figures)

Therefore, there are approximately 0.2232 moles of the gas present.

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