Number two and three please asap

Answer:

The zeros are -2 and 8, because the factors of g are (x+2) and (x-8).

Step-by-step explanation:

Answer:

0

Step-by-step explanation:

5^2-4(5)-5=2(5)-10

0=0

Answer:

(3)   {5,7}

Step-by-step explanation

135 people voted for it on gauth math

Step-by-step explanation:

take it again, it's so blur

Answer:

[tex]\textsf{a)}\quad y=8x^2+2x-3[/tex]

[tex]\textsf{b)}\quad y=x^2-2x-4[/tex]

Step-by-step explanation:

Given information:

[tex]x^2+bx+c=0[/tex]

[tex]x_1+x_2=-b[/tex]

[tex]x_1x_2=c[/tex]

Part (a)

[tex]\textsf{If}\quad x_1=\dfrac12\quad\textsf{and}\quad x_2=-\dfrac34[/tex]

[tex]\begin{aligned}\implies -b & =\dfrac12+\left(-\dfrac34\right)\\ & = \dfrac24-\dfrac34\\ & =-\dfrac14\end{aligned}[/tex]

[tex]\begin{aligned}\implies c & =\dfrac12 \cdot \left(-\dfrac34\right)\\ & = \dfrac{1 (-3)}{2 \cdot 4}\\ & =-\dfrac38\end{aligned}[/tex]

Substituting the found values of b and c into [tex]x^2+bx+c=0[/tex]

[tex]\implies x^2+\dfrac14x-\dfrac38=0[/tex]

Multiply both sides by 8 so that coefficients are integers:

[tex]\implies 8x^2+2x-3=0[/tex]

Therefore, the final quadratic equation is:

[tex]y=8x^2+2x-3[/tex]

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Part (b)

[tex]\textsf{If}\quad x_1=1+\sqrt{5}\quad\textsf{and}\quad x_2=1-\sqrt{5}[/tex]

[tex]\begin{aligned}\implies -b & =(1+\sqrt{5})+(1-\sqrt{5})\\ & = 1+1+\sqrt{5}-\sqrt{5}\\ & =2\end{aligned}[/tex]

[tex]\begin{aligned}\implies c & =(1+\sqrt{5})(1-\sqrt{5})\\ & = 1-\sqrt{5}+\sqrt{5}-5\\ & =-4\end{aligned}[/tex]

Substituting the found values of b and c into [tex]x^2+bx+c=0[/tex]

[tex]\implies x^2-2x-4=0[/tex]

Therefore, the final quadratic equation is:

[tex]y=x^2-2x-4[/tex]

Answer:

275.63 mm^2

Step-by-step explanation:

The measurements of the pyramids are

Edge length: 10
Egde width: 8.66 (because 10x8.66/2 = 43.3)
Height: 9

To find the surface area, use this formula, and you will get 275.63:

[tex]\huge\fcolorbox{blue}{aqua}{Answer:}[/tex]

═════════════════════

1.[tex]- 5x - y = 8[/tex]

[tex]-5x-y=8[/tex]

[tex]-5x=8+y [/tex]

[tex]-5x=y+8 [/tex]

[tex]\frac{-5x}{-5}=\frac{y+8}{-5} [/tex]

[tex]x=\frac{y+8}{-5} [/tex]

[tex]x=\frac{-y-8}{5} [/tex]

[tex]-5x-y=8[/tex]

[tex]-y=8+5x [/tex]

[tex]-y=5x+8 [/tex]

[tex]\frac{-y}{-1}=\frac{5x+8}{-1} [/tex]

[tex]y=\frac{5x+8}{-1} [/tex]

[tex]y=-5x-8 [/tex]

────────────────────

2.[tex]-4x-y=2 [/tex]

[tex]-4x-y=2 [/tex]

[tex]-4x=2+y [/tex]

[tex]-4x=y+2 [/tex]

[tex]\frac{-4x}{-4}=\frac{y+2}{-4} [/tex]

[tex]x=\frac{y+2}{-4} [/tex]

[tex]x=-\frac{y}{4}-\frac{1}{2} [/tex]

[tex]-4x-y=2[/tex]

[tex]-y=2+4x [/tex]

[tex]-y=4x+2 [/tex]

[tex]\frac{-y}{-1}=\frac{4x+2}{-1} [/tex]

[tex]y=\frac{4x+2}{-1} [/tex]

[tex]y=-4x-2 [/tex]

════════════════════

Explanation:

#Carry on learning

The standard form of the expression (4 × 10) + (3 × 1/100) + (5 × 1/1000) is 40.035

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.

We have expression:

= (4 × 10) + (3 × 1/100) + (5 × 1/1000)

= 40 + 0.03 + 0.005

= 40.035

Thus, the standard form of the expression (4 × 10) + (3 × 1/100) + (5 × 1/1000) is 40.035

Learn more about the arithmetic operation here:

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Answer:

problem 8= 769.3

problem 16=A

problem 11= independent-x , dependent-y

problem 12= independent- s , dependent- v

problem 17= C

Answer:

The question has some missing details such as ; Use cylindrical shells to find the volume of the remaining solid if the remaining solid is 8cm high. I have however solved it using the value of 8cm, you can use the same approach to solve for the volume irrespective of the value of the height you are given.

Step-by-step explanation:

The detailed step by step analysis and appropriate Integration by susbtitution in order to get the volume of the remaining solid is as shown in the attached file.

Answer:

126

Step-by-step explanation:

[tex]V = A * h = \frac{1}{4} * \pi * d^{2} * h = A * h = \frac{1}{4} * 3.14 * 36 * 5 = 141.3\\ \\V_{empty} = A * h = \frac{1}{4} * \pi * d^{2} * h = \frac{1}{4} * \pi * 4 * 5 = 15.7[/tex]

[tex]V_{full} = V - V_{empty} = 141.3 - 15.7 = 125.6 \approx 126[/tex]

i believe it is called a parameter

Step-by-step explanation:

y=mx+c

2=2(1)+c

c=2-2

c=0

Answer:

the answer is 90 degrees

Answer:

E) None of the above

Step-by-step explanation:

Given [tex]f(x)=\sqrt{x}[/tex] and [tex]g(x)=x+2[/tex], then [tex]f(g(x))=\sqrt{x+2}[/tex]. This shifts the graph of the parent function [tex]f(x)=\sqrt{x}[/tex] 2 units to the left. Thus, the domain of the function is [tex][-2,\infty)[/tex], making none of the above true.

The domain of f(g(x)) is all real numbers x such that x ≥ -2.

Hence, Option e is correct.

A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

Now, To find the domain of f(g(x)), we need to first determine the domain of g(x).

Since, g(x) is a polynomial function,

And, we know that it is defined for all real numbers.

Therefore, the domain of g(x) is (-∞, ∞).

Next, we need to find the domain of f(g(x)), which means we need to determine which values of x make g(x) a valid input for f(x).

Since, f(x) is defined only for non-negative real numbers, we need to ensure that g(x) is a non-negative real number.

Therefore, we set the inequality g(x) ≥ 0 and solve for x:

x + 2 ≥ 0

x ≥ -2

So, The domain of f(g(x)) is all real numbers x such that x ≥ -2.

Learn more about the function visit:

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Answer:

Step-by-step explanation:

Original coordinates of F

It is reflected across the y-axis.

Transformation of coordinates across y-axis

Therefore, on reflection, the coordinates of F' will be :

Answer:

Joaquin Phoenix Has the Fastest Joker Makeup at Just 15 Minutes.

Answer:

Range :24

Mode: No mode

Median:13

Mean:46.5 OR 13.30

Answer:

it’s 8 and 2 and 4 and 0

Step-by-step explanation:

this is because when you multiply 2x the x is an 8 so 2 times 8 is 16 then minus 2 is 14 which is greater than -4 same for my other answer

Step-by-step explanation:

green = surface area

volume = 9/5 × 2/3

= 18/15

= 6/5 = 1.2 or 1 1/5

Answer:

y = 0

Step-by-step explanation:

Plug 10 in for x, and solve for y.

10 + 5y = 10

5y = 0

y = 0

Answer:

Step-by-step explanation:

radius = 16/2 = 8

Then you can apply the formula to calculate the base area, lateral surface or surface or even perimeter

Answer:

Step-by-step explanation:

Here are the steps to solve this equation:

Given:

First step: 2(y+6)-4y

Use the distributive property.

Distributive property:

2(y+6)

2*y=2y

2*6=12

2y+12

Isolate the term of y from one side of the equations.

2y+12=4y

Subtract by 12 from both sides.

2y+12-12=4y-12

Solve.

2y=4y-12

Then, you subtract by 4y from both sides.

2y-4y=4y-12-4y

Solve.

2y-4y=-2y

-2y=-12

Divide by -2 from both sides.

[tex]\sf{\dfrac{-2y}{-2}=\dfrac{-12}{-2}}[/tex]

Solve.

Divide the numbers from left to right.

Solutions:

-12/-2=6

[tex]\Longrightarrow: \boxed{\sf{y=6}}[/tex]

I hope this helps. Let me know if you have any questions.

Answer:

c. $750

Step-by-step explanation:

the perimeter is 80m

80÷8=10

10*75=750

Answer:

Yes

Step-by-step explanation:

put point (3,28) in the above equation

28=19+3(3)

28=28

[tex]\LARGE{\text{please\:refer\:to\:the\:"explanation"\:section\:of\:this\:ans}}[/tex]

An easy way to check whether or not a point lies on a line is to plug in the x-coordinate in lieu of x and the y - coordinate in lieu of y As follows :

x - coordinate : 3

y=19+3(3)

y - coordinate : 28

28 = 19 + 9

28 = 28 [tex]\Large\checkmark[/tex]

LHS = RHS

[tex]\footnotesize{\text{hope\:helpful}}[/tex]

Answer:

291.

Step-by-step explanation:

(x - 147) / 12 = 12

x - 147 = 144

x = 144 + 147

x = 291.

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's solve ~

[tex]\qquad \tt \dashrightarrow \:6 < 4x + 8 < 14[/tex]

[tex]\qquad \tt \dashrightarrow \:6 - 8 < 4x + 8 - 8 < 14 - 8[/tex]

[tex]\qquad \tt \dashrightarrow \: - 2 < 4x < 6[/tex]

[tex]\qquad \tt \dashrightarrow \: \dfrac{ - 2}{4} < \dfrac{4x}{4} < \dfrac{6}{4} [/tex]

[tex]\qquad \tt \dashrightarrow \: \dfrac{ - 1}{2} < {x}{} < \dfrac{3}{2} [/tex]

hope it helps ~