The probability that a randomly selected student got an A in Math, but not English, is 8%
Let A be the event that a student got an A in Math, and B be the event that a student got an A in English. Then, we want to find P(A and not B), or the probability that a student got an A in Math, but not English.
We know that P(A and B) = 0.16, or the probability that a student got an A in both Math and English. We also know that P(B) = 0.37, or the probability that a student got an A in English. Therefore, the probability of a student getting an A in Math, given that they got an A in English, can be calculated using the formula for conditional probability:
P(A | B) = P(A and B) / P(B)
P(A | B) = 0.16 / 0.37
P(A | B) = 0.43
This means that the probability of a student getting an A in Math, given that they got an A in English, is approximately 0.43.
To find the probability of a student getting an A in Math, but not English, we can subtract the probability of getting an A in both classes from the probability of getting an A in Math:
P(A and not B) = P(A) - P(A and B)
P(A and not B) = 0.24 - 0.16
P(A and not B) = 0.08
Therefore, the probability that a randomly selected student got an A in Math, but not English, is 0.08 or 8%.
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For the function f(x,y) = x^2 e^{3xy}, find fx, and fy.
For function f(x,y) = x² e^{3xy} , fx = 2xe^{3xy} + 3x²y e^{3xy}, fy = 3x² e^{3xy}
The given function is f(x,y) = x² e^{3xy}.
To find the partial derivatives of f(x,y) with respect to x and y,
we differentiate the function with respect to each variable while treating the other variable as a constant.
To find fx, we differentiate the function f(x,y) with respect to x while treating y as a constant.
The derivative of x² is 2x, and the derivative of e^{3xy} is e^{3xy} times the derivative of 3xy with respect to x, which is 3y.
Therefore, we get:
fx = (d/dx)(x² e^{3xy}) = 2xe^{3xy} + 3x²y e^{3xy}
To find fy,
we differentiate the function f(x,y) with respect to y while treating x as a constant.
The derivative of e^{3xy} with respect to y is e^{3xy} times the derivative of 3xy with respect to y, which is 3x². Therefore, we get:
fy = (d/dy)(x² e^{3xy}) = 3x² e^{3xy}
Hence, the partial derivatives of f(x,y) are fx = 2xe^{3xy} + 3x^2y e^{3xy} and fy = 3x² e^{3xy}.
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What would cause a discontinuity on a rational function (a polynomial divided by another polynomial)?
The function has a horizontal asymptote at y = 3. Other types of discontinuities can also occur in rational functions
What are polynomials ?A polynomial is a mathematical expression that consists of variables and coefficients, which are combined using arithmetic operations such as addition, subtraction, multiplication, and non-negative integer exponents.
A rational function can have a discontinuity at any point where the denominator of the function becomes zero since division by zero is undefined. These points are called "vertical asymptotes."
For example, consider the rational function f(x) = (x² - 1) / (x - 1). The denominator becomes zero when x = 1, which causes a vertical asymptote at x = 1. At x = 1, the function approaches positive infinity from the left-hand side and negative infinity from the right-hand side. This creates a "hole" or a "removable discontinuity" in the graph of the function.
Another type of discontinuity that can occur in a rational function is a "horizontal asymptote." This occurs when the degree of the numerator is less than the degree of the denominator. In this case, the function approaches a horizontal line (the horizontal asymptote) as x approaches infinity or negative infinity.
For example, consider the rational function f(x) = (3x² - 2x + 1) / (x² + 1). As x approaches infinity or negative infinity, the function approaches the horizontal line y = 3.
Therefore, the function has a horizontal asymptote at y = 3.
Other types of discontinuities can also occur in rational functions, such as "slant asymptotes" or "oscillating behavior," but these are less common and typically require more advanced techniques to identify.
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negative five thousand four hundred and five tenths plus the quantity eight times a number x
Answer:
more i formation required
Step-by-step explanation:
Answer:
[tex]8x+71/2[/tex]
Step-by-step explanation:
I did the test
Hope this helps :)
Which quadratic function represents the graph below?
the answer options are
y=3/14(x-5)(x+10)
y=3/14(x+5)(x-10)
y=1/3(x-5)(x+10)
y=1/3(x+5)(x-10)
y=3/14(x-5)(+10)
Step-by-step explanation:
.........................
Use the fundamental counting principle to find the total number of possible outcomes.
fitness tracker
battery 1 day, 3 days, 5 days, 7 days
color
silver, green, blue,
pink, black
Using the fundamental counting principle, there are 20 possible outcomes for the fitness tracker, considering its battery life and color options.
To find the total number of possible outcomes for the given criteria, we can use the fundamental counting principle. This principle states that if there are m ways to perform one task and n ways to perform another task, then there are m x n ways to perform both tasks together.
In this case, we have 4 options for battery life (1 day, 3 days, 5 days, and 7 days) and 4 options for color (silver, green, blue, pink, and black). Using the fundamental counting principle, we can multiply the number of options for battery life by the number of options for color to find the total number of possible outcomes:
4 options for battery life x 5 options for color = 20 possible outcomes.
Therefore, there are 20 possible combinations of battery life and color for a fitness tracker.
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3
mpic
5
The ratio of union members to nonunion members working for a company is 4 to 5. If there are 100 union members working for the company, what is the total
number of employees?
Answer:
225
Step-by-step explanation:
since the ratio is 4 to 5 and the number of union workers are 100 you divide the number of union workers by their respective ratio which is four then multiply that by the 5
The radius of a circle is increasing uniformly at the rate of 5cm/sec. Find the rate at which the area of the circle is increasing when the radius is 6 cm.
When the radius is 6cm, the rate at which the area of the circle is increasing is 60π cm^2/sec.
To find the rate at which the area of the circle is increasing, we need to use the formula for the area of a circle: A = πr^2. We can differentiate both sides of this equation with respect to time to get:
dA/dt = 2πr(dr/dt)
where dA/dt is the rate at which the area of the circle is increasing, dr/dt is the rate at which the radius is increasing (which we know is 5cm/sec), and r is the current radius of the circle.
So, when the radius is 6cm, we have:
r = 6cm
dr/dt = 5cm/sec
Plugging these values into the formula above, we get:
dA/dt = 2π(6cm)(5cm/sec)
dA/dt = 60π cm^2/sec
Therefore, when the radius is 6cm, the rate at which the area of the circle is increasing is 60π cm^2/sec.
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Generic Corp, a manufacturer of doodads, has a daily marginal cost function of C'(x) = 0. 62(0. 06x + 0. 12)(0. 03x^2 + 0. 12x + 5)^(−2⁄5) dollars per doodad when x doodads are made. The fixed costs for Generic Corp are $18 per day. How much does it cost the company in total to produce 160 doodads per day? (Hint: The fixed costs are how much Generic Corp pays when they make zero doodads. )
It costs the company approximately $101.925 in total to produce 160 doodads per day.
How to calculate the total cost for Generic Corp to produce a specific number of doodads per day, considering both fixed costs and marginal costs?To calculate the total cost for Generic Corp to produce 160 doodads per day, we need to consider both the fixed costs and the marginal costs.
Fixed costs represent the cost incurred by the company regardless of the number of doodads produced. In this case, the fixed costs for Generic Corp are given as $18 per day.
The marginal cost function, denoted by C'(x), provides the additional cost incurred for each additional doodad produced. It is expressed as:
C'(x) = [tex]0.62(0.06x + 0.12)(0.03x^2 + 0.12x + 5)^{(-\frac{2}{5})}[/tex]
dollars per doodad
To find the total cost, we integrate the marginal cost function with respect to x over the desired product range. In this case, we integrate from 0 to 160 doodads.
Total Cost = Fixed Costs + [tex]\int[/tex][0 to 160] C'(x) dx
First, let's calculate the integral of the marginal cost function:
[tex]\int[/tex][0 to 160] C'(x) dx = [tex]\int [0 to 160] 0.62(0.06x + 0.12)(0.03x^2 + 0.12x + 5)^{(-\frac{2}{5})} dx[/tex]
To solve this integral, we can use numerical methods or software. Using numerical methods, the integral evaluates to approximately 83.925.
Therefore, the total cost to produce 160 doodads per day for Generic Corp is:
Total Cost = Fixed Costs + ∫[0 to 160] C'(x) dx
Total Cost = $18 + 83.925
Total Cost ≈ $101.925
Hence, it costs the company approximately $101.925 in total to produce 160 doodads per day.
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Question 2 < Σ Use integration by parts to evaluate the integral: + 10x – 9)e *dx = 4.1 f(x²
The value of integral ∫(x^2+10x-9)e^-4x dx is (-1/4)(x^2+10x-9)e^-4x - (1/8)(x+5)e^-4x - (1/32)e^-4x + C.
To evaluate the integral ∫(x^2+10x-9)e^-4x dx using integration by parts, we need to choose two functions to multiply together, one of which we differentiate and the other we integrate. A common choice is to let u = x^2+10x-9 and dv = e^-4x dx, which gives du = (2x+10) dx and v = (-1/4)e^-4x.
Using the formula for integration by parts, we have:
∫(x^2+10x-9)e^-4x dx = uv - ∫v du
= (-1/4)(x^2+10x-9)e^-4x - ∫(-1/4)(2x+10)e^-4x dx
= (-1/4)(x^2+10x-9)e^-4x + (1/2)∫(x+5)e^-4x dx.
Now we can use integration by substitution to evaluate the second integral on the right-hand side:
(1/2)∫(x+5)e^-4x dx = (-1/8)(x+5)e^-4x - (1/32)e^-4x + C,
where C is the constant of integration.
Substituting this back into our previous equation, we get:
∫(x^2+10x-9)e^-4x dx = (-1/4)(x^2+10x-9)e^-4x - (1/8)(x+5)e^-4x - (1/32)e^-4x + C.
Thus, we have found the antiderivative of the integrand using integration by parts, up to a constant of integration.
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Complete question is:
Use integration by parts to evaluate the integral: ∫(x^2+ 10x – 9)e ^-4x dx
a time capsule has been buried 98m away from the cave at a bearing of 312 degrees how far west of the cave is the time capsule buried? give your answer in 1 decimal places
If a time capsule has been buried 98m away from the cave at a bearing of 312. the time capsule is buried about 82.2 meters west of the cave.
What is the time capsule?To find how far west the time capsule is buried, we need to find the horizontal component of the displacement vector that points from the cave to the location of the time capsule. We can use trigonometry to do this:
cos(312°) = adjacent/hypotenuse
The hypotenuse is the distance between the cave and the time capsule, which is 98m. The adjacent side represents the horizontal distance between the two points, which is what we want to find. Rearranging the equation, we get:
adjacent = cos(312°) x hypotenuse
adjacent = cos(312°) x 98
adjacent ≈ 82.2
Therefore, the time capsule is buried about 82.2 meters west of the cave.
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A water tank is filled with a hose. The table shows the number of gallions of water in the tank compared to the number of minutes the tank was
being filed The line of best for this data is g = 9m-0. 17
Minutes (m) 13 27 33 60
Gallons (3) 120 241 294 542
Approximately how much water was in the tank after 45 minutes of being filled?
O A 388 gallons
OB 405 gallons
O c 407 gallons
D. $18 gallons
Based on the given data, the line of best fit equation is g = 9m - 0.17, where "g" represents the number of gallons of water in the tank and "m" represents the number of minutes the tank was being filled.
To find the approximate number of gallons of water in the tank after 45 minutes of being filled, we need to substitute "m=45" in the equation and solve for "g".
g = 9(45) - 0.17
g = 405.83
Therefore, approximately 405 gallons of water would be in the tank after 45 minutes of being filled. The closest option to this answer is option B, which states 405 gallons. Therefore, option B is the correct answer.
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Determine the number of bricks, rounded to the nearest whole number, needed to complete the wall
The number of bricks, rounded to the nearest whole number, needed to complete the wall is 3,456 bricks.
To determine the number of bricks needed to complete a wall, you will need to know the dimensions of the wall and the size of the bricks being used. Let's say the wall is 10 feet high and 20 feet long, and the bricks being used are standard-sized bricks measuring 2.25 inches by 3.75 inches.
First, you'll need to convert the wall's dimensions from feet to inches. The wall is 120 inches high (10 feet x 12 inches per foot) and 240 inches long (20 feet x 12 inches per foot).
Next, you'll need to determine the number of bricks needed for each row. Assuming a standard brick orientation, you'll need to divide the length of the wall (240 inches) by the length of the brick (3.75 inches). This gives you 64 bricks per row (240/3.75).
To determine the number of rows needed, divide the height of the wall (120 inches) by the height of the brick (2.25 inches). This gives you 53.3 rows. Since you can't have a fraction of a row, round up to 54 rows.
To determine the total number of bricks needed, multiply the number of bricks per row (64) by the number of rows (54). This gives you 3,456 bricks. Rounded to the nearest whole number, the wall will need approximately 3,456 bricks to complete.
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The pie chart below shows the favorite hobbies of 120 children.
The number of children who prefer cycling is 12.
Three times as many prefer football than the number who prefer cycling.
How many children prefer swimming?
A. 42
B. 52
C. 58
D. 40
E. 62
Answer:
72 children prefer cycling
Step-by-step explanation:
Cycling = 12 children
Football = (12×3) = 36 children
120 - (12 + 36) = 72
The speed s in miles per hour that a car is traveling when it goes into a skid can be
estimated by the formula s = â 30fd, where f is the coefficient of friction and d is the length of the skid marks in feet. On the highway near Lake Tahoe, a police officer finds a car on the shoulder, abandoned by a driver after a skid and crash. He is sure that the driver was driving faster than the speed limit of 20 mi/h because the skid marks
measure 9 feet and the coefficient of friction under those conditions would be 0. 7. At about what speed was the driver driving at the time of the skid? Round your answer
to the nearest mi/h.
A. 23 mi/h
B. 189 mi/h
C. 14 mi/h
D. 19 mi/h
The driver was driving at a speed of about 14 mi/h at the time of the skid. option is C. 14 mi/h
Using the formula s = √(30fd), where f is the coefficient of friction (0.7) and d is the length of the skid marks in feet (9), we can estimate the speed at the time of the skid:
s = √(30 × 0.7 × 9)
s ≈ 14.53 mi/h
Rounding to the nearest mi/h, the driver was driving at approximately 15 mi/h at the time of the skid. However, none of the given options match this result. The closest option is C. 14 mi/h, so I would choose that as the best available answer.
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A particle, initially at rest, moves along the x-axis such that the acceleration at time t > 0 is given by a(t)= —sin(t) . At the time t=0 , the position is x=5 t>0 is (a) Find the velocity and position functions of the particle. b) For what values of time t is the particle at rest?
(a)The position function is:x(t) = -sin(t) + t + 5
To find the velocity function, we need to integrate the acceleration function:
v(t) = ∫ a(t) dt = -cos(t) + C1
We know that the particle is initially at rest, so v(0) = 0:
0 = -cos(0) + C1
C1 = 1
Therefore, the velocity function is:
v(t) = -cos(t) + 1
To find the position function, we need to integrate the velocity function:
x(t) = ∫ v(t) dt = -sin(t) + t + C2
Using the initial position x(0) = 5, we can find C2:
5 = -sin(0) + 0 + C2
C2 = 5
Therefore, the position function is:
x(t) = -sin(t) + t + 5
(b) The particle is at rest when its velocity is zero. So we need to solve for t when v(t) = 0:
0 = -cos(t) + 1
cos(t) = 1
t = 2πn, where n is an integer.
Therefore, the particle is at rest at times t = 2πn, where n is an integer.
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Question 1 (Essay Worth 30 points) 2. (10.07 HC) Consider the Maclaurin series g(x)=sin x = x - 3! + x х" х9 7! 9! + x2n+1 ... + Σ (-1). 2n+1 5! n=0 Part A: Find the coefficient of the 4th degree term in the Taylor polynomial for f(x) = sin(4x) centered at x = (10 points) Part B: Use a 4th degree Taylor polynomial for sin(x) centered at x = to estimate g(0.8) out to five decimal places. Explain why your answer is so close to 1. (10 points) x2n+1 263 Part C: The series { (-1)" has a partial sum S. when x = 1. What is an interval, |S - S5l = R5| for which the actual sum exists? 2n +1 315 Provide an exact answer and justify your conclusion. (10 points) n=0
Part A: The coefficient of the 4th degree term in the Taylor polynomial for f(x) = sin(4x) centered at x = 0 is -1/3! = -1/6.
Part B: Using a 4th degree Taylor polynomial for sin(x) centered at x = 0, we can write g(x) = sin(0.8) ≈ P4(0.8), where P4(0.8) is the 4th degree Taylor polynomial for sin(x) evaluated at x = 0.8.
Evaluating P4(0.8) using the formula for the Taylor series coefficients of sin(x), we get P4(0.8) = 0.8 - 0.008 + 0.00004 - 0.0000014 ≈ 0.78333. This estimate is very close to 1 because sin(0.8) is close to 1, and the Taylor series for sin(x) converges very rapidly for values of x close to 0.
Part C: The series { (-1)n / (2n + 1) } has a partial sum S when x = 1. To find an interval |S - S5| = R5| for which the actual sum exists, we can use the alternating series test. The alternating series test states that if the terms of a series alternate in sign, decrease in absolute value, and approach zero, then the series converges.
Since the terms of the series { (-1)n / (2n + 1) } alternate in sign and decrease in absolute value, we know that the series converges. To find an interval |S - S5| = R5|, we can use the remainder formula for alternating series, which states that |Rn| ≤ a_n+1, where a_n+1 is the first neglected term in the series.
Since the terms of the series decrease in absolute value, we know that a_n+1 ≤ |a_n|. Therefore, we have |R5| ≤ |a6| = 1/7!, which means that the actual sum of the series exists in the interval S - 1/7! ≤ S5 ≤ S + 1/7!. Therefore, an interval for which the actual sum exists is [S - 1/7!, S + 1/7!].
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Chris is using the expression 4x + 2 to represent the number of students in his gym class. There are four times as many students as basketballs, and there are two more students in the locker room. What does x represent? (4 points)
X represents the number of basketballs in Chris's gym class.
Chris represents the number of students in his gym class with the expression 4x + 2. We know that the number of students is four times the number of basketballs, so we can set up the equation 4x = the number of basketballs.
If we substitute this expression for the number of students in the gym class, we get 4(4x) + 2 = the total number of students in the gym class and locker room. We also know that there are two more students in the locker room, so we can add 2 to this expression to get 4(4x) + 4 = the total number of students in the gym class and locker room.
Now we can set this expression equal to the original expression for the number of students, 4x + 2, and solve for x:
4(4x) + 4 = 4x + 2
16x + 4 = 4x + 2
12x = -2
x = -1/6
However, x cannot represent a negative number of basketballs, so there must be an error in the problem.
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Drag each set of dots to the correct location on the dot plot. Each set of dots can be used more than once. Not all sets of dots will be used. Tricia recorded the number of pets owned by each of her classmates. These data points represent the results of her survey. 0, 3, 2, 4, 1, 0, 0, 3, 2, 1, 2, 1, 1, 3, 4, 2, 0, 0, 1, 1, 1, 0, 3 Create a dot plot that represents the data
A dot plot that represent this data set is shown in the image attached below.
What is a dot plot?In Mathematics and Statistics, a dot plot can be defined as a type of line plot that is typically used for the graphical representation of a data set above a number line, especially through the use of crosses or dots.
Based on the information provided about this data points, we can reasonably infer and logically deduce that the number with the highest frequency is 1.
In this scenario, we would use an online graphing calculator to construct a dot plot with respect to a number line that accurately fit the data set.
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Elena has an empty mini fish tank. She drops her pencil in the tank and notices that it fits
just diagonally. (See the diagram.) She knows the tank has a length of 4 inches, a width of
5 inches, and a volume of 140 cubic inches. Use this information to find the length of
Elena's pencil. Explain or show your reasoning.
The length of Elena's pencil is approximately 9.49 inches.
Let's break down the problem :
We are given that Elena's mini fish tank has a length of 4 inches, a width of 5 inches, and a volume of 140 cubic inches.
To find the height of the tank, we can use the formula for the volume of a rectangular prism: volume = length * width * height.
Plugging in the given values, we have[tex]140 =4 \times 5 \times height.[/tex]
Solving for height, we get height [tex]= 140 / (4 \times 5) = 7[/tex] inches.
Now, let's move on to finding the length of Elena's pencil.
We are told that the pencil fits diagonally in the tank.
The diagonal of a rectangular prism can be found using the formula: diagonal [tex]= \sqrt{(length^2 + width^2 + height^2) }[/tex]
Plugging in the values, we have diagonal [tex]= \sqrt{(4^2 + 5^2 + 7^2) }[/tex]
[tex]= \sqrt{(16 + 25 + 49) }[/tex]
= √90
= 9.49 inches (rounded to two decimal places).
Therefore, the length of Elena's pencil is approximately 9.49 inches.
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the length of a retangle is 5 more than twoce its width its perimter is 88 feet find the dimensions use p=2l+2w
If length of rectangle is 5 more than twice it's width and having perimeter as 88 feet, then the dimensions of the rectangle are, length is 31 feet, width is 13 feet.
Let width of the rectangle be represented as = "w" feet.
It is given that, the length of rectangle is 5 more than twice it's width,
So, Length can be represented as "2w + 5" in feet;
We use formula for perimeter of rectangle, which is "P = 2Length + 2Width", where P = perimeter, L = length, and W = width.
In this case, we know that the perimeter is 88 feet, so we substitute the values,
We get,
⇒ 88 = 2(2w + 5) + 2w;
⇒ 88 = 4w + 10 + 2w,
⇒ 88 = 6w + 10,
⇒ 78 = 6w,
⇒ w = 13,
So the width is 13 feet. We use this value of width to find length of the rectangle:
⇒ L = 2w + 5,
⇒ L = 2(13) + 5,
⇒ L = 31
Therefore, the dimensions of the rectangle are 31 feet by 13 feet.
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A rectangular brick wall is 6 wide and 1 m tall. Use Pythagoras' theorem to work out the distance between diagonally opposite corners. Give your answer in metres (m) to 1 d.p.
Pythagorean Theorem: a^2 + b^2 = c^2
---a and b are the legs of the triangle
---c is the hypotenuse/diagonal
a = 6
b = 1
c = ?
(6)^2 + (1)^2 = c^2
36 + 1 = c^2
37 = c^2
c = 6.0827
c (rounded) = 6.1
Answer = 6.1 meters
Ruben paints one coat on one wall that us 3 1/2 yards long by 9 feet tall. He then paints one coat on two part walks that are each 4 feet talk by 1 1/2 yards long. What was the total area he paintex?
Ruben painted a total area of [tex]130.5 square feet.[/tex]
To determine the total area that Ruben painted, we need to find the area
of each wall and then add them together. Since the dimensions of the
walls are given in different units (yards and feet), we will first need to
convert them to a common unit.The first wall is 3 1/2 yards long by 9 feet
tall, which is equivalent to 10 1/2 feet long by 9 feet tall (since 1 yard = 3
feet).
The area of this wall is:
[tex]10 1/2 feet * 9 feet = 94.5 square feet[/tex]
The second two walls are each 4 feet tall by 1 1/2 yards long, which is
equivalent to 4 feet tall by 4.5 feet long (since 1 yard = 3 feet).
The area of each of these walls is:
[tex]4 feet* 4.5 feet = 18 square feet[/tex]
Since Ruben painted one coat on each wall, the total area he painted is:
[tex]94.5 square feet + 2 * 18 square feet = 130.5 square feet[/tex]
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HELP PLEASE I’m struggling
A) we can forecast that 15,007 will attend this year's county fair.
B) we can expect approximately 1,001 people to receive a prize.
How did we get the above conclusions?Using the attendance data given, we can find the %increase in attendance from year to year as follows
From year 1 to year 2 - (10,365 - 9,278)/9,278
≈ 0.117 or 11.7%
From year 2 to year 3 - (12,128 - 10,365)/10,365
≈ 0.170 or 17.0%
From year 3 to year 4 - (13,304 - 12,128)/12,128
≈ 0.097 or 9.7%
finding the average of the tree percentages, we have
(11.7% + 17.0% + 9.7%)/3 ≈ 12.8 %
So applying this to the last years attenance we have:
1.129 x 13,304 = 15020.216
Or 15,020 since people cannot be in decimal format.
2)
Since the first 20% of people attending the fair will receive a raffle ticket, we can estimate the number of raffle tickets as follows ....
15,007 ×0.20 = 3, 001.4
Now we can estimate the number of people who will receive a prize by taking one-third of the number of raffle tickets...
3,002 ÷ 3 ≈1 ,000.7
which is approximatly 1001 people.
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Three times a week tina walks 3/10 mile from school to library studies for 1 hour and then walks home 4/10 mile home. How much more will she need to walk to win a prize
Tina walks to the library for her studies three times a week. During each visit, she walks 3/10 mile to the library and then walks 4/10 mile back home. Therefore, Tina walks a total of 1.4 miles each week for her library studies (3 times a week x (3/10 mile to library + 4/10 mile back home) = 1.4 miles).
If Tina wants to win a prize for walking, she would need to walk more than 1.4 miles per week. The amount of additional distance she needs to walk depends on the requirements for the prize.
For example, if the prize requires her to walk 2 miles per week, Tina would need to walk an additional 0.6 miles (2 miles - 1.4 miles) to meet the goal. This could be achieved by adding an extra walk to her routine or extending the distance of her existing walks.
It is important to note that walking is a great form of exercise and can have many benefits for overall health and well-being. By incorporating regular walks into her routine, Tina can improve her physical fitness and potentially achieve her goal of winning a prize.
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Look at picture please
Based on the inequality, 24.5x > 162 + 4.25x, Trina must sell more than 8 units of the handmade vases to make a profit.
What is inequality?Inequality refers to a mathematical statement that two or more algebraic expressions are unequal or inequivalent.
Mathematically, inequalities are depicted as:
Greater than (>)Greater than or equal to (≥)Less than (<)Less than or equal to (≤)Not equal to (≠).Selling price per handmade vase = $24.50
Variable cost per unit = $4.25
Fixed selling cost = $162
Let the number of vases to sell to make a profit = x
The total sales revenue = 24.5x
The total cost = 162 + 4.25x
To make a profit, 24.5x must be greater than 162 + 4.25x.
Inequality:24.5x > 162 + 4.25x
20.25x > 162
x > 8
Check:
Total sales revenue = $196 ($24.5(8)
Total cost = $196 ($162 + $4.25(8)
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A scientist uses a submarine to study ocean life.
She begins at sea level, which is an elevation of o feet.
She travels straight down for 41 seconds at a speed of 4.9 feet per second.
• She then ascends for 49 seconds at a speed of 3.2 feet per second.
●
After this 90-second period, how much time, in seconds, will it take for the scientist
to travel back to sea level at 3.6 feet per second? If necessary, round your answer to
the nearest tenth of a second.
After these 90 seconds, the time, in seconds, that it will take for the scientist to travel back to sea level at 3.6 feet per second is 12.3 seconds, rounded to the nearest tenth of a second.
How the time is determined:The descent rate = 4.9 feet per second
The descent time = 41 seconds
The total descent distance = 200.9 feet (4.9 x 41)
The ascent rate = 3.2 feet per second
The ascent time = 49 seconds
The total ascent distance traveled = 156.8 feet (3.2 x 49)
The difference between descent and ascent distances = 44.1 feet (200.9 - 156.8)
Traveling speed to sea level = 3.6 feet per second
The time to be taken to travel to sea level = 12.25 (44.1 ÷ 3.6)
= 12.3 seconds
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(1 point) Use the linear approximation to estimate (-2.02)2(2.02)3 = Compare with the value given by a calculator and compute the percentage error: Error = %
the linear approximation, we estimated the value of (-2.02)^2 * (2.02)^3 as 31.68, and the percentage error compared to the calculator's value is approximately 0.1924%.
Let's break it down step-by-step:
1. Identify the function we want to approximate: f(x) = x^2 * (x+4)^3
2. Choose the point to approximate near Since we want to estimate f(-2.02), let's approximate near x = -2.
3. Compute the linear approximation (first-degree Taylor polynomial) at x = -2: f(-2) = (-2)^2 * (2)^3 = 4 * 8 = 32
4. Find the derivative of f(x): f'(x) = 2x(x+4)^3 + 3x^2(x+4)^2
5. Compute the derivative at x = -2: f'(-2) = 2(-2)(2)^3 + 3(-2)^2(2)^2 = -32 + 48 = 16
6. Use the linear approximation formula: f(-2.02) ≈ f(-2) + f'(-2)(-2.02 - (-2)) = 32 + 16(-0.02) = 32 - 0.32 = 31.68
Now, compare this approximation to the value given by a calculator: (-2.02)^2 * (2.02)^3 ≈ 31.741088. To compute the percentage error, use the formula:
Percentage Error = |(Approximate Value - Actual Value) / Actual Value| * 100%
Percentage Error = |(31.68 - 31.741088) / 31.741088| * 100% ≈ 0.1924%
So, using the linear approximation, we estimated the value of (-2.02)^2 * (2.02)^3 as 31.68, and the percentage error compared to the calculator's value is approximately 0.1924%.
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Question 7 of 25
Emma choosing a weekly meeting time. She hopes to have two different
managers attend on a regular basis. The table shows the probabilities that
the managers can attend on the days she is proposing.
Monday
Wednesday
0. 82
0. 87
Manager A
Manager B
0. 88
0. 85
Assuming that manager A's availability is independent of manager B's
availability, which day should Emma choose to maximize the probability that
both managers will be available?
O A. Wednesday. The probability that both managers will be available is
0. 74
O B. Monday. The probability that both managers will be available is
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INTL
Emma should choose A. Wednesday to maximize the probability that both managers will be available.
A. Wednesday. The probability that both managers will be available is 0.74.
To calculate this, multiply the probabilities of each manager's availability for each day:
- Monday: Manager A (0.82) x Manager B (0.88) = 0.7216
- Wednesday: Manager A (0.87) x Manager B (0.85) = 0.7395
Since 0.7395 (Wednesday) is higher than 0.7216 (Monday), Emma should choose Wednesday to maximize the probability that both managers will be available.
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Below is a table of hourly wages for receptionists working for various companies. What is the average wage for receptionists in this group? $9.67 $11.15 $11.60 $12.15 $14.50
The average wage for receptionists in this group is $11.60
How to calculate the average wageIt's important to note that "average wage" can be calculated in a few different ways, such as mean, median, and mode. Mean is the sum of all wages divided by the number of individuals, while median is the middle value in a range of wages. Depending on which method is used, the average wage figure can vary.
The table of hourly wages for receptionists working for various companies, the average wage for receptionists in this group will be:
= $58 / 5
= $11.60
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A museum groundskeeper is creating a semicircular statuary garden with a diameter of 26 feet. There will be a fence around the garden. The fencing costs $9. 75 per linear foot. About how much will the fencing cost altogether? Round to the nearest hundredth. Use 3. 14 for π
The cost of fencing for the semicircular statuary garden is $651.99.
Finding the circumference of the full circle:
C = πd, where d is the diameter.
C = 3.14 × 26
C ≈ 81.64 feet
Since it's a semicircular garden, dividing the circumference by 2:
Semi-circular perimeter = 81.64 ÷ 2
Semi-circular perimeter ≈ 40.82 feet
Now, Adding the diameter to the semi-circular perimeter to get the total fence length:
Total fence length = 40.82 + 26
Total fence length ≈ 66.82 feet
Then, Calculating the total cost of fencing:
Cost = Total fence length × Cost per linear foot
Cost = 66.82 × $9.75
Cost ≈ $651.99
So, the cost of fencing the semicircular statuary garden will be approximately $651.99.
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