Answer: 1/4
Given : On average, Carson spends about 26% of his allowance each month on candy and soft drinks.
To Find : When creating a circle graph of what Carson does with his money, which of the following fractions would be the best to represent how much he spends on food?
If these are your Choices:
A) 1/4
B) 1/3
C) 3/4
D) 1/2
Solution:
To Convert fraction into % multiply by 100
(1/4) * 100 = 25 %
(1/3) * 100 = 33.33 %
(3/4) * 100 = 75 %
(1/2) * 100 = 50 %
Therefore 1/4 fraction best represent how much he spends on food
what quadrant is 4,6 in?
Answer:
1st quadrant
PLZ HELP MEEEEEE
Kaltin will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $75 and costs an additional $0.70 per mile driven. The second plan has no initial fee but costs $0.90 per mile driven. How many mlles would Kaltlin need to drive for the two plans to cost the same?
Answer:
x equals 375
Step-by-step explanation:
75+0.70x=0.90x
There are 35 boys in 6th grade. The number of girls in 6th grade is 40. Emma says that means the ratio of the number of boys in 6th grade to the number of girls in 6th grade is 3:4. Is Emma correct? If not, what is the correct answer? it is the answer
correct ratio
7:8
5:8
8:7
Answer:
The correct ratio is 7:8, so no, Emma is not correct.
Hello cayleahm253!
[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]
There are 35 boys in 6th grade. The number of girls in 6th grade is 40. Emma says that means the ratio of the number of boys in 6th grade to the number of girls in 6th grade is 3:4. Is Emma correct? If not, what is the correct answer?
[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]
Okay, so we can see from the question that there are 35 boys & 40 girls in the 6th grade. So the ratio of boys is to girls will be 35:40.
__________________
Solving...
[tex]35 : 40 \\ = \frac{35}{40} \\ \\ \sf \: Cancel \: out \: 35 \: and \: 40 \: to \: get \: 7 \: and \: 8.\\ \\ = \frac{7}{8} \\ = \huge \boxed{\boxed{\bf \: 7 : 8}}[/tex]
__________________
So, the correct ratio is not 3:4. Instead it's 7:8.__________________
Hope it'll help you ッ
ℓucαzz
find the missing number so that the equation has no solutions. _x-18=-3(x+4)
Answer:X=5
Step-by-step explanation:took the test
[tex]\frac{1}{1+\sqrt{2} } +\frac{1}{\sqrt{2} +\sqrt{3} } +...+\frac{1}{\sqrt{99} +\sqrt{100} }[/tex]
Answer:
9
Step-by-step explanation:
the given expression can be re-written:
[tex]\frac{\sqrt{2} -1}{(\sqrt{2}-1)(\sqrt{2}+1)} +\frac{\sqrt{3} -\sqrt{2}}{(\sqrt{3} +\sqrt{2})(\sqrt{3} -\sqrt{2})} + ...+\frac{\sqrt{100} -\sqrt{99}}{(\sqrt{100} -\sqrt{99})(\sqrt{100} +\sqrt{99})};[/tex]
then
[tex]\sqrt{2} -1+\sqrt{3} -\sqrt{2} +\sqrt{4} -\sqrt{3}+\sqrt{5} -\sqrt{4}+...+\sqrt{100}-\sqrt{99}= -1+\sqrt{100}=9.[/tex]
HELP
Convert log xy = 1/2 to exponential form
a. x^y=1/2
b. y^x=1/2
c. square root of x=y
d. square root of y=x
Answer:
Logxy =1/2
Step-by-step explanation:
Can someone tell me the answer to this please I got this wrong on my first attempt .-.
Answer:
B
Step-by-step explanation:
In similar triangles corresponding sides are in same ratio
[tex]\dfrac{CV}{CE}=\dfrac{CU}{CD}\\\\\\\dfrac{CV}{54}=\dfrac{14}{98}\\\\CV=\dfrac{14}{98}*84\\\\CV = \dfrac{1}{7}*84\\\\CV = 12[/tex]
Answer:
B) 12
Step-by-step explanation:
CD - 98
CE - 84
~
CU - 14
CV = 12
-
You set up a proportion: 98/84 = 14/x
x=12
01.01 LC)Look at the following numbers: −4, −5, 0, 5 Which pair of numbers has a sum of zero? 5, −5 −5, 0 −4, 5 −4, 0
Answer:
5, -5
hope this helps
Answer:
Train to BaDussy
Step-by-step explanation:
Solve the equation. Prove that it makes the equation true.
3b-8=d-6
Answer:
um just one question are you sure it's supposed to be d-6 instead of b-6
Step-by-step explanation:
if it's b-6 instead of d then the answer is 1
HELP PLEASE
Write each number as a logarthm with base 3.
0
1
-2
4
Answer:
See belowStep-by-step explanation:
Let the number is x in each case.
Use the property below:
logₐc = b ⇒ aᵇ = c or vice versaWe have:
[tex]log_3x = 0 -->x = 3^0=1 -->log_31=0[/tex][tex]log_3x = 1 -->x = 3^1=3 -->log_33=1[/tex][tex]log_3x = -2 -->x = 3^{-2}=1/9 -->log_3(1/9)=-2[/tex][tex]log_3x = 4 -->x = 3^4=81 -->log_381=4[/tex]Answer:
[tex]\log_31=0[/tex]
[tex]\log_33=1[/tex]
[tex]\log_3\left(\frac{1}{9}\right)=-2[/tex]
[tex]\log_{3}81=4[/tex]
Step-by-step explanation:
[tex]\textsf{Apply log law}: \quad \log_ax=c \iff x=a^c[/tex]
Therefore:
[tex]\log_3x=0 \implies x=3^0=1[/tex]
[tex]\log_3x=1 \implies x=3^1=3[/tex]
[tex]\log_3x=-2\implies x=3^{-2}=\dfrac{1}{3^2}=\dfrac{1}{9}[/tex]
[tex]\log_3x=4 \implies x=3^4=81[/tex]
Additionally, the logarithm of 1 with any base is always zero:
[tex]\log_a1=0[/tex]
The logarithm of the same number as the base is always 1:
[tex]\log_aa=1[/tex]
Today, both the soccer team and the basketball team had games. The soccer team plays every 4 days and the basketball team plays every 5 days.
Answer:
20
Step-by-step explanation:
Assuming you are referring to the day that both teams would play on the same day, it would be the 20th.
There are two ways you can do it.
1. List out the multiples of each number
2. multiply the two days together
If you want to do it the first way it would look like this...
5 10 15 20
4 8 12 16 20
When you do it like this it shows you that the 20th day is the day they would both play together
If you want to do it the second way it would look like this...
4th day X 5th day = 20th day
Either way you solve the problem you get the same answer, this may not work for every problem like this, but it works for this particular one
Can anyone help with this equation? PLS
I need this for right now!
Answer: [tex]5^{3}[/tex]
Step-by-step explanation:
What is y-b=ms, solving for b?
Answer:
b=y-ms
Step-by-step explanation:
Subtract y from both sides,
-b=ms-y
Divide through by -1,
b=-ms+y
Rearrange the equation.
b=y-ms
6x — 5y = 15
x = y + 3
х =
y =
Replace all occurrences of x with y + 3 in each equation.
Replace all occurences of x in 6x - 5y = 15 with y + 3.
6 (y+3) -5y = 15
x = y + 3
Simplify 6 (y + 3) - 5y.
Simplify each term.
Apply the distributive property.
6y + 6 · 3 - 5y = 15
x = y + 3
Multiply 6 by 3.
6y + 18 - 5y = 15
x = y + 3
Subtract 5y from 6y.
y + 18 = 15
x = y + 3
Move all terms not containing y to the right side of the equation.
Subtract 18 from both sides of the equation.
y = 15 - 18
x = y + 3
Subtract 18 from 15.
y = -3
x = y + 3
Replace all occurences with y with -3 in each equation.
Replace all occurences of y in x = y + 3 with -3.
x = (-3) + 3
y = -3
Add -3 and 3.
x = 0
y = -3
The solution to the system is the complete set of ordered pairs that are valid solutions.
(0,-3)
The result can be shown in multiple forms.
Point Form:
(0,-3)
Equation Form:
x = 0, y = -3
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
The required values are :
[tex]x = 0[/tex][tex]y = - 3[/tex]Refer to the attachment for solution ~
guys pls help me!!!!!!
Answer:
126°
Step-by-step explanation:
1. We know that 54 degrees and its adjacent are a linear pair, meaning that they add up to 180 degrees. To find the measure of the adjacent angle, we subtract 54 from 180.
[tex]180 - 54[/tex] [tex]126[/tex]2. Now, we know that adjacent of 54 is 126. Also, we know that [tex]l[/tex] ║ [tex]m[/tex] ║ n, and x and 126 degrees are corresponding angles. Corresponding angles are congruent within angle measures, so x = 126 degrees.
12 can someone please explain this
Answer:
B = x = 44 degrees
Step-by-step explanation:
Interior angles of a triangle = 180 degrees.
There are 2 congruent sides so the angle to the right of 67 degrees is also 67 degrees
180 - 2(67) = 46 degrees (the third angle of the triangle)
x + 46 degrees = 90 degrees ( complementary angles)
x = 44 degrees
2/3 = 4/x+3 what is x?
Answer:
-12/7
Step-by-step explanation:
2/3=4/x+3
2/3-3=4/x Subtract 3 from both sides
2/3-9/3=4/x Make them have a common denominator
-7/3=4/x
-7/3x=4
x=(4)/(-7/3)
x=[tex]\frac{-12}{7}[/tex]
Simplify (5 +3i)+(-7-4i)
Can someone please help
Answer:
<ABC = 70 degrees
<AMC = 60 degrees
< AMB = 60 degrees
Step-by-step explanation:
<ABC = 180-110 = 70 degrees
<AMC = 2x + 60 = 180
2x = 180 - 60
x = 120/2
x = 60
<AMB = 180/3 = 60
A function f(x) is graphed on the coordinate plane at is the function rule in siope-intercept form? Enter your answer in the box f(x) =
9514 1404 393
Answer:
y = 2x +1
Step-by-step explanation:
The line rises 2 units for each 1 unit to the right, so its slope is ...
m = rise/run = 2/1 = 2
The line crosses the y-axis at y = 1, so the y-intercept is ...
b = 1
Then the slope-intercept form equation is ...
y = mx + b . . . . . . . for slope m and y-intercept b
y = 2x + 1 . . . . . . . . fill in the known values
8.
(a) Rowena buys and sells clothes.
(1)
She buys a jacket for $40 and sells it for $45.40.
Calculate the percentage profit.
Work Shown:
45.40 - 40 = 5.40
She made $5.40 in profit. Divide this over the original price to find the percentage profit
(5.40)/(40) = 0.135 = 13.5%
a contractor is given a scale drawing of a rectangular patio. the scale from the patio to the drawing is 4 feet to 1 inch. what is the area of the actual patio?
Proportions: If 7.5 cups sugar to make 14 dozen cookies, find K please
Answer:
8987678
Step-by-step explanation:
In Triangle ABC with vertices A(-5,-4), B(3,-2), and C(-1,6), M is the midpoint of AB and N is the midpoint of BC. Show that MN = 1/2 AC. Provide your complete solutions and proofs in your paper homework and enter the numeric answers online
The midpoint of a line divides the line into equal segments.
See below for the proof of [tex]\mathbf{MN = \frac{1}{2}AC}[/tex]
The given parameters are:
[tex]\mathbf{A = (-5,-4)}[/tex]
[tex]\mathbf{B = (3,-2)}[/tex]
[tex]\mathbf{C = (-1,6)}[/tex]
The coordinates of M (midpoint of AB) are calculated as follows:
[tex]\mathbf{M = \frac{1}{2}(x_1 + x_2, y_1+y_2)}[/tex]
So, we have:
[tex]\mathbf{M = \frac{1}{2}(-5 + 3, -4-2)}[/tex]
[tex]\mathbf{M = \frac{1}{2}(-2, -6)}[/tex]
[tex]\mathbf{M = (-1, -3)}[/tex]
The coordinates of N (midpoint of BC) are calculated as follows:
[tex]\mathbf{N = \frac{1}{2}(x_1 + x_2, y_1+y_2)}[/tex]
So, we have:
[tex]\mathbf{N = \frac{1}{2}(3 - 1, -2 +6)}[/tex]
[tex]\mathbf{N = \frac{1}{2}(2, 4)}[/tex]
[tex]\mathbf{N = (1, 2)}[/tex]
Distance MN is:
[tex]\mathbf{MN = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}[/tex]
So, we have:
[tex]\mathbf{MN = \sqrt{(-1 - 1)^2 + (-3 - 2)^2}}[/tex]
[tex]\mathbf{MN = \sqrt{29}}[/tex]
Distance AC is calculated as follows:
[tex]\mathbf{AC= \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}[/tex]
So, we have:
[tex]\mathbf{AC= \sqrt{(-5 - -1)^2 + (-4 - 6)^2}}[/tex]
[tex]\mathbf{AC= \sqrt{116}}[/tex]
Split
[tex]\mathbf{AC= \sqrt{4 \times 29}}[/tex]
Take positive square root of 4
[tex]\mathbf{AC= 2\sqrt{29}}[/tex]
To prove that:
[tex]\mathbf{MN = \frac{1}{2}AC}[/tex]
We have:
[tex]\mathbf{\sqrt{29} = \frac{1}{2} \times 2\sqrt{29}}[/tex]
[tex]\mathbf{\sqrt{29} = \sqrt{29}}[/tex]
The above equation is true.
Hence. [tex]\mathbf{MN = \frac{1}{2}AC}[/tex]
Read more about midpoints and distance at:
https://brainly.com/question/11231122
5x-10=20
Would the answer be 6
________
[tex] \: [/tex]
5x - 10 = 20
5x = 20 + 10
5x = 30
x = 30 ÷ 5
x = 6✔
Como parte de un ejercicio topográfico, Salma debe hacer un registro del terreno donde está construido el Taj Mahal que es de 580m de largo x 300m de ancho. Y suponiendo que 9 ayudantes trabajarán junto con ella, ¿cuántos metros cuadrados le toca registrar a cada quién POR DÍA durante un mes? Supongamos que el mes tiene 30 días.
cual es la respuesta? porfa urge
Queremos ver cuantos metros cuadrados debe registrar cada integrante del grupo por día.
Veremos que cada integrante debe registrar 580m^2 por día.
La informacion que se nos da es:
Sabemos que los integrantes son 10, Salma y sus 9 ayudantes.El área que deben investigar esta dada por: 580m*300m = 174,000 m^2Disponen de un total de 30 días para trabajar.Conociendo el área y el número de integrantes, el área que le tocara a cada integrante está dada por:
a = 174,000 m^2/10 = 17,400 m^2
Y sabemos que tendran 30 días para registrar esa área, entonces asumiendo que en cada día registran una cantidad fija de superficie, lo que deben registrar cada día está dado por:
d = a/30 = 17,400 m^2/30 = 580m^2
Eso es lo que cada integrante debe registrar por día,
Sí quieres aprender más, puedes leer:
https://brainly.com/question/16512349
Someone help me I will mark you as brain
Step-by-step explanation:
that is really, really simple.
h(-3) means that we put the argument (-3) into the formula of the function everywhere where there is x.
h(x) = -3x - 10
so,
h(-3) = -3×-3 - 10 = 9 - 10 = -1
Answer:
-1
Step-by-step explanation:
h(x) = -3x - 10
h(-3) means to replace the x in the problem with the value of -3 and
solve.
h(-3) = -3(-3) - 10
h(-3) = 9 - 10
h(3) = -1
6 friends go strawberry picking. They pick 30 strawberries on Friday and 12 strawberries on Saturday. How many strawberries dose each person get?
The graph shown below expresses a radical function that can be written in the for f(x)=a(x+6)
Answer:
Step-by-step explanation:
MY SISTER HAVE DIS EQUETION I TELL YOU
Problem:
Report Error
On Tuesday, a radio store reduces all of its prices by 20% from what they were on Monday.
On Wednesday, the store again reduces all of its prices by some percentage from what they were on Tuesday. If the resulting price of a radio is half of the original Monday price,
then by what percentage did the store reduce its prices from Tuesday to Wednesday?
Answer/Step-by-step explanation:
Call Monday's price, P
Tuesday's price must just be .80P [ 20% reduction]
Call Wednesday's price reduction ( 1 - R)
So...we have that
Tuesday's price * Wednesday's reduction = (1/2)P
(.80)P *( 1 - R) = (1/2)P divide through by P and note that 1/2 = .50
.80 (1 - R) = .50 divide both sides by .80
1 - R = .50/.80
1 - R = 5/8
1 - 5/8 = R
3/8 = R = .375 = 37.5% = the reduction from Tues. to Wed.
Proof of this...let Monday's price = 100
Tuesdays price = .80 * 100 = 80
Wed price = 80 (1 - R) = 80 (1 - .375) = 50 = half of Mon. price