On Monday it snowed 8 in. On Tuesday the
snow melted 3 in. On Wensday it showed
another 5 in. How much snow
was on the
ground after it snowed on Wednesday?

Answers

Answer 1

Answer:

10in

Step-by-step explanation:

8-3=5

5+5=10

Answer 2

Answer:

10 inches.

Step-by-step explanation:

Assuming that before Monday, there was no snow.

On Monday, it snowed 8 inches, which is a net positive of 8:

0 + 8 = 8in total.

On Tuesday, it melted 3 inches, which is a net negative of 3:

8 - 3 = 5in total.

On Wednsday, it snowed another 5 inches, which is a net positive of 5:

5 + 5 = 10in total.

10 inches total of snow was on the ground on Wednesday.

~


Related Questions

How do you translate "Twelve decreased by a quarter of a number, x. in a variable expression​

Answers

Answer:

12 - (1/4)x

Step-by-step explanation:

quarter of x is (1/4)x

Now, minus that from twelve.

Use a real number to represent the situation.
The temperature falls 14°F.

Answers

Answer:

-14°F

Step-by-step explanation:

Hey there!

if n=4 and m=3 find 2n-3m

Answers

Answer:

hope it helps you........

Answer:

2n-3m

=2(4)-3(3)

=8 - 9

= -1

suppose the two vertical angles are measuring 6x + 15 and 4x + 32. what is the measure of each angle?

Answers

Answer:

measure of both angle is 66

Step-by-step explanation:

vertical angles are equal so,

6x+15=4x+32

6x-4x=32-15

2x= 17

X=8.5

now,

4X+32

= 4×8.5 +32

= 66

Triangle ABC with coordinates A (3,-2), B (5,5), and C (-4, 2) is reflected across
the x-axis. State the coordinates of the resulting triangle, A'B'C.

Answers

Step-by-step explanation:

the formula of coordinates (x, y) that reflected across the x-axis : (x, y) => (x, -y)

so,

A(3, -2) => A'(3, 2)

B(5, 5) => B'(5, -5)

C(-4, 2) => C'(-4, -2)

Coordinates of ∆ABC

A(3,-2)B(5,5)C(-4,2)

Now co-ordibates of ∆A'B'C'

[tex]\\ \rm\longmapsto A'=(3,2)[/tex]

[tex]\\ \rm\longmapsto B'=(5,-5)[/tex]

[tex]\\ \rm\longmapsto C'=(-4,-2)[/tex]

*Plz it due today HELP!!!!!!Justin has been collecting baseball cards for years. He bought 137 cards the first year
and 143 cards the second year. He plans on putting them in a binder that will hold seven
cards per page. How many pages must the binder have to hold Justin's collection? *Plz tell me what the math action word is I need to box it*

Answers

Answer:

40

Step-by-step explanation:

137+143=280

280/7= 40

Answer:

Division/dividing/divide

Step-by-step explanation:

If Justin has 280 baseball cards, and if each page will only hold 7 cards per page, then by dividing 280 by 7 (280÷7) would equal to 40 pages.

Help me plz snsnsns sn

Answers

Answer:

If the exponent is 0 the answer is 224/y^2

Step-by-step explanation:

Suppose the function H(t) gives the heart rate of a runner at various points in time during a 20 mile run. Describe an appropriate domain of this function. Include a description of the kinds of numbers in the domain as well as any limitations on their values.

Answers

.....................

Please help me
Find this value ​

Answers

Answer:

<CAB =30°

Step-by-step explanation:

<DAB=80°

<DAC=50°

<DAB=<DAC+<CAB

<CAB=<DAB-<DAC

=80°-50°

=30°

Express each mixed number as a percent 2 1/2 can someone please tell me the awnser​

Answers

Answer:

im pretty sure its 250%

Step-by-step explanation:

Answer:

250%

Step-by-step explanation:

1 is 100% and double that is 200%

1/5 of 100% is 50%

200% + 50% = 250%

can someone please give me an example of a position and motion of objects in space​

Answers

Answer:

position of objects in space

for example: up, down, in front, behind, between, left, right.

motion of objects in space

for example: Stars, planets, moons.

In x² , what is the 2 called?

a radical

a subscript

an exponent

an imaginary number

none of these

Answers

Answer:

an exponent

Step-by-step explanation:

In x², here the 2 is exponent while x is base.

Answer:

an exponent

Step-by-step explanation:

hope it helps:)

What is the period of the function y=tan (n/4(x-n/3)? 3 units 4 units 6 units 8 units

Answers

Answer:

8

Step-by-step explanation:

The function u given me is

[tex] \tan( \frac{\pi}{4} (x - \frac{\pi}{3} ) )[/tex]

The period of a function is represented by

[tex] \frac{2\pi}{ |b| } [/tex]

where b is the coefficient of the x variable.

The coefficient is pi/4 so

[tex] \frac{2\pi}{ \frac{\pi}{4} } = 8[/tex]

8 is the answer.

Answer: 4 units

Step-by-step explanation:


What is the area of the figure?
A. 22 m2
B. 30 m2
O C. 33 m²
O D. 42 m2
E. 50 m2

Answers

Answer:

B. 30m2

Hope it helps you..

0.6m=____mm . answer the question

Answers

Answer:

600

Step-by-step explanation:

since 1m=1000mm

It’s 600mm
If you need an explanation how ill explain in the comments

Which of the following represents the relationship
between h and C ?
A) C = 5h
3
B) C = - +5
4
C= +5
C) C = 3h + 5
D) h = 3C

Answers

Answer:

I think its c I hope I'm right

) P is a set of prime numbers --- State it’s type.
A) Null set B) singleton set C) infinite set
E) A,B,C are correct.

Answers

Answer:

null set

Step-by-step explanation:

i am not sure but i hope it will help you

Answer:

singleton set is correct

ANSWER THIS ASAP PLEASE

Answers

Answer: 12 and -12

Step-by-step explanation:

Absolute value is the distance to zero (0)

Equation 1:

|(12) - 2| = 10

= 12-2

=10

Equation 2:

|(-12) - 2| = 10

= 12 - 2

= 10

multiply : (5x+3a) (5x-3a)​

Answers

(a+b)(a-b)=a²-b²

(5x+3a)(5x-3a)
=(5x)²-(3a)²
=25x²-9a²

Hope my answer helped u :)

Find the orthogonal decomposition of vector b = 9, 0, 0 with respect to vector a = 4, −5, 0 . (Your instructors prefer angle bracket notation < > for vectors.)

Answers

The orthogonal decomposition of vector [tex]\vec b = <9, 0, 0>[/tex] with respect to vector [tex]\vec a = <4, -5, 0>[/tex]  is

[tex]b'=<\frac{16}{5},\frac{8}{5},0>[/tex]

From the Question we are told that

Vector [tex]\vec b = <9, 0, 0>[/tex]

Vector [tex]\vec a = <4, -5, 0>[/tex]

Generally in the orthogonal decomposition of b to a we have

[tex]\vec b=\vec b"+\vec b'[/tex]

Where

[tex]\vec b"=(\frac{\vec b*\vec a}{\vec *\vec a})*\vec a[/tex]

[tex]\vec b"=(\frac{ <9, 0, 0>*<4, -5, 0>}{<4, -5, 0>*<4, -5, 0>})*<4, -5, 0>[/tex]

[tex]\vec b"=<\frac{4}{5},\frac{-8}{5},0>[/tex]

Therefore

[tex]b'= \vec b- \vec b"\\\\b'=<4,0,0>-<\frac{4}{5},\frac{-8}{5},0>[/tex]

[tex]b'=<\frac{16}{5},\frac{8}{5},0>[/tex]

in Conclusion

The orthogonal decomposition of vector [tex]\vec b = <9, 0, 0>[/tex] with respect to vector [tex]\vec a = <4, -5, 0>[/tex]  is

[tex]b'=<\frac{16}{5},\frac{8}{5},0>[/tex]

For more information on this visit

https://brainly.com/question/17412861

Guys help me in this question pls

Answers

Answer:

40+x+5 = 3x +15

2x= 30

x=15

Their present ages are 15 and 55

Determine the type and number of solutions of 4x - 4x + 1 = 0.

two real solutions
one real solution
two imaginary solutions​

Answers

Answer:

1 real solution

Step-by-step explanation:

Use discramint formula.

[tex]b {}^{2} - 4ac[/tex]

If the discramint >0, the equation is going to have 2 real solutions

If the discramint =0, we going to have one real solution.

If the discramint<0, we going to have two imaginary solution

B is -4, A is 4 and C is 1 so

[tex] { - 4}^{2} - 4( 4)(1) = 0[/tex]

So the equation had one real solution.

What do you call the set of numbers that
includes the whole numbers, their opposites and
zero?
Imaginary Numbers
Negatives
Integers
Positives

Answers

Answer:

integers

Step-by-step explanation:

so negative and positive are numbers in questions so no.

and def not Imaginary numbers

Help me pls i have to finish my homework i have more questions to post too

Answers

Answer:

17) 19

19) 8

Step-by-step explanation:

17)

(6 +6² -4)÷2

(6 +36 -4)÷2

(38)÷2

19

19)

3³ ÷3 - 1

27 ÷3 -1

9 -1

8

Problem 11
Six friends who enjoy tennis decide to play a game of singles and a game
of doubles every day of the 7-week school holidays.
(a) Show that at least four of the games of singles will be between friends
playing each other for the fourth time.
(b) Show that at least four of the games of doubles will be between pairs
playing the same opposing pair for the second time.

Answers

Number combination can be used to find the number of selecting n  items from m items

The known parameters are;

Number of days the six friends play a game of tennis = Every day = 7 days

Number of weeks the six friends the friends play for = 7 weeks

Therefore the total number of days = 7 × 7 days = 49 days

Required:

(a) The number of ways the friends can play with each other once is given as follows;

[tex]The \ number \ of \ 2 \ combinations \ in \ 6 \ options, C_6^2 = \dfrac{6!}{2!\times (6-2)!} = 15[/tex]

The number of ways the six friends can play with each other once is 15 ways

Therefore, minimum number of singles games that will be between the same friends playing each other is given as follows;

[tex]\mathbf{Number \ of \ games = \dfrac{7 \times 7}{C_6^2} }=3.2\overline 6[/tex]

Therefore, more than 3 of the games or four games will be between pairs playing the game more than four times together, and when at least four of the games of singles are counted it will be between friends playing each other for the fourth time

(b) The number of ways the friends can play game of doubles is given as follows;

[tex]C_6^4 = \dfrac{6!}{4! \times (6 - 4)!} = 15[/tex]

The number of pairs = ₆C₂ = 15

The number of games of doubles = 49

In 49 games, we have;

The number of times the same opposing  will play a game of doubles where a member of the pair can be on either side of the court will given as follows;

[tex]\mathbf{Number \ of \ games \ of \ doubles \ between \ same \ pair} = \dfrac{7 \times 7}{15 } =3.2\overline 6[/tex]

Therefore, at least four of the of the games of doubles will be between the same set of four friends playing for the 4th time, which gives; at least four games of doubles between the same set of four friends, two of which are playing (as a pair) the same opposing pair for the 4/2 = second time

Learn more about combination here:

https://brainly.com/question/22692807

s= zh - 2zt^3 solve for z

Answers

Hi ;-)

[tex]s=zh-2zt^3\\\\z(h-2t^3)=s \ \ /:(h-2t^3)\\\\z=\dfrac{s}{h-2t^3}[/tex]

Answer:

z = [tex]\frac{s}{h-2t^3}[/tex]

Step-by-step explanation:

Given

s = zh - 2zt³ ← factor out z from each term

s = z(h - 2t³ ) ← divide both sides by h - 2t³

[tex]\frac{s}{h-2t^3}[/tex] = z

The gradient of the line joining (4, q) to (6, 5) is twice the gradient
of the line joining (0, 0) to (4, q). Find q.

Answers

Answer:

q is 4

Step-by-step explanation:

[tex]gradient = \frac{y_{2} - y_{1} }{x _{2} - x _{1} } \\ [/tex]

let gradient of the line joining (4, q) to (6, 5) be x

let gradient of the line joining (0, 0) to (4, q) be y

[tex]y = 2x[/tex]

therefore:

[tex]( \frac{q - 0}{4 - 0} ) = 2( \frac{5 - q}{6 - 4} ) \\ \\ \frac{q}{4} = \frac{2(5 - q)}{2} \\ \\ \frac{q}{4} = 5 - q \\ \\ q = 4(5 - q) \\ q = 20 - 4q[/tex]

collect like terms:

[tex]q + 4q = 20 \\ 5q = 20 \\ q = \frac{20}{5} \\ \\ q = 4[/tex]

The value of q will be "4".

Let,

The gradient of line joining (4, q) to (6, 5) be "x".The gradient of line joining (0, 0) to (4, q) be "y".

As we know,

[tex]Gradient = \frac{y_2-y_1}{x_2-x_1}[/tex][tex]y = 2x[/tex]

then,

→ [tex]\frac{q-0}{4-0} = 2(\frac{5-q}{6-4} )[/tex]

      [tex]\frac{q}{4} = \frac{2(5-q)}{2}[/tex]

      [tex]\frac{q}{4} = 5-q[/tex]

By applying cross-multiplication, we get

      [tex]q = 4(5-q)[/tex]

      [tex]q = 20-4q[/tex]

By adding "4q" both sides, we get

[tex]q+4q= 20-4q+4q[/tex]

     [tex]5q = 20[/tex]

       [tex]q = \frac{20}{5}[/tex]

       [tex]q = 4[/tex]

Thus the above value is correct.

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y - 4 = 3. what is y = ???

Answers

Hi ;-)

[tex]y-4=3\\\\y=3+4\\\\\boxed{y=7}[/tex]

Answer:  7  

.....7-4=3

Solve each equation V/8=13

Answers

Answer:

v = 114

Step-by-step explanation:

[tex] \frac{v}{8} = 13[/tex]

=> v = 13 × 8

=> v = 114 (Ans)

Find the value of x.

A. 5.58
B. 9.14
C. 15.2
D. 10

PLEASE HELP!!! :(

Answers

Answer:

D. 10

Step-by-step explanation:

[tex]{ \sf{(12x + 12) \degree = 79\degree + (5x + 3)\degree}} \\ { \sf{ \{outer \: angle \: is \: equal \: to \: sum \: of \: inner \: angles \}}} \\ { \sf{12x - 5x = 79 + 3 - 12}} \\ { \sf{7x = 70}} \\ { \sf{x = 10}}[/tex]

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