Part A
The distance that Eric can travel by driving to work can be represented by a linear equation because he sets his cruise control and is moving at a constant rate. He drives at a rate of 75 mph on the interstate for a total of 1.5 hours.
What is the linear equation that can be used to find the distance that Eric travels each day? In the equations d = distance traveled, r = rate and t = time taken.
A. d = rt
B. d = t/r
C. d = r/t
D. d = r + t
E. d = r/75
Part B
What is the total distance that Eric travels each day?
A. 37.5 miles
B. 75 miles
C. 112.5 miles
D. 150 miles
E. 187.5 miles
WILL GIVE BRAINLIEST AND 40 POINTS

Answer: C

Step-by-step explanation:

[tex]5\left(4x+5\right)[/tex]

[tex]\mathrm{Apply\:the\:distributive\:property}:\quad \:a\left(b+c\right)=ab+ac[/tex]

[tex]=5\cdot \:4x+5\cdot \:5[/tex]

[tex]\bf=20x+25[/tex]

Answer:

-7

Step-by-step explanation:

^

Answer:

-7

Step-by-step explanation:

Answer:

152 cups

Step-by-step explanation:

1. 44 quarts are in 11 gallons.

2. 44-6=38.

3. There are 152 cups in 38 quarts.

Step-by-step explanation:

the word kilo means thousand. By that logic we know that 2200 grams are in 2.2 kilograms

This looks like a system of differential equations.

[tex]\begin{cases}x' + 2y' + x = 0 \\ x' - y' + y = 0 \\x(0)=0, y(0)=1\end{cases}[/tex]

Eliminating x' gives

[tex](x'+2y'+x)-(x'-y'+y) = 0 - 0 \implies 3y' - y + x = 0[/tex]

and eliminating y' gives

[tex](x'+2y'+x) + 2(x'-y'+y)=0+2\times0 \implies 3x' + x + 2y = 0[/tex]

so that we can rewrite the system as

[tex]\begin{cases}3x' = -x - 2y \\ 3y' = -x + y\end{cases}[/tex]

or equivalently in matrix form as

[tex]\begin{bmatrix}x\\y\end{bmatrix}' = \dfrac13 \begin{bmatrix}-1&-2\\-1&1\end{bmatrix} \begin{bmatrix}x\\y\end{bmatrix}[/tex]

Compute the eigenvalues for the coefficient matrix:

[tex]\det\begin{bmatrix}-1-\lambda&-2\\-1&1-\lambda\end{bmatrix} = (-1-\lambda)(1-\lambda) - 2 = \lambda^2 -3 = 0 \implies \lambda=\pm\sqrt3[/tex]

Compute the corresponding eigenvectors:

[tex]\lambda=\sqrt3 \implies \begin{bmatrix}-1-\sqrt3&-2\\-1&1-\sqrt3\end{bmatrix}\begin{bmatrix}v_1\\v_2\end{bmatrix}=\begin{bmatrix}0\\0\end{bmatrix} \\\\ \implies v_1=(1-\sqrt3)v_2 \implies \vec v = \begin{bmatrix}1-\sqrt3\\1\end{bmatrix}[/tex]

[tex]\lambda=-\sqrt3 \implies \begin{bmatrix}-1+\sqrt3&-2\\-1&1+\sqrt3\end{bmatrix}\begin{bmatrix}v_1\\v_2\end{bmatrix}=\begin{bmatrix}0\\0\end{bmatrix} \\\\ \implies v_1 = (1+\sqrt3)v_2 \implies \vec v = \begin{bmatrix}1+\sqrt3\\1\end{bmatrix}[/tex]

We end up multiplying the matrix by 1/3, so the eigenvalues also get scaled by 1/3 and λ = ±1/√3. The eigenvectors stay the same.

Then the characteristic solution to the system is

[tex]\begin{bmatrix}x\\y\end{bmatrix} = C_1 e^{t/\sqrt3} \begin{bmatrix}\frac{1-\sqrt3}3\\\frac13\end{bmatrix} + C_2 e^{-t/\sqrt3} \begin{bmatrix}\frac{1+\sqrt3}3\\\frac13\end{bmatrix}[/tex]

Use the initial conditions to solve for the constants.

[tex]\begin{bmatrix}0\\1\end{bmatrix} = C_1 \begin{bmatrix}\frac{1-\sqrt3}3\\\frac13\end{bmatrix} + C_2 \begin{bmatrix}\frac{1+\sqrt3}3\\\frac13\end{bmatrix}[/tex]

[tex]\implies \begin{cases}(1-\sqrt3) C_1 + (1+\sqrt3) C_2 = 0 \\ C_1 + C_2 = 3\end{cases}[/tex]

[tex]\implies C_1=\dfrac{3+\sqrt3}2, C_2=\dfrac{3-\sqrt3}2[/tex]

Then the particular solution is

[tex]\begin{bmatrix}x\\y\end{bmatrix} = \dfrac{3+\sqrt3}6 e^{t/\sqrt3} \begin{bmatrix}1-\sqrt3\\1\end{bmatrix} + \dfrac{3-\sqrt3}6 e^{-t/\sqrt3} \begin{bmatrix}1+\sqrt3\\1\end{bmatrix}[/tex]

or

[tex]\begin{cases}x(t) = -\dfrac1{\sqrt3} e^{\sqrt3 \, t} + \dfrac1{\sqrt3} e^{-\sqrt3\,t} \\\\ y(t) = \dfrac{3+\sqrt3}6 e^{\sqrt3\,t} + \dfrac{3-\sqrt3}6 e^{-\sqrt3\,t}\end{cases}[/tex]

To find the missing angle's measure

 ⇒ important to understand the sum of the angles of a triangle

    ⇒ the sum of every angle of any triangle in all cases equal to 180

         degrees

What is the information given:

 ⇒ one angle is of 94 degrees and the other of 46 degrees

Using the information in the first section and the information given in the diagram, let's set up an equation:

  [tex]94+46+x = 180\\140+x = 180\\x = 40[/tex]

The measure of the missing angle is 40 degrees

Hope that helps!

Answer:

43.96

Step-by-step explanation:

2 x 7 x 3.14 = 43.96

Answer:

44 rounded to nearest whole.

[tex]C = 2\pi r = 2 * \pi * r(7) = 44~in[/tex]

Answer:

Now plot those points in graph and find intersection hope it helps you.......

Answer:

400

Step-by-step explanation:

Division cancels multiplication. Divide by 0.17 to isolate "x" on the right side of the equation.

68 = 0.17 * x

divide both sides by 0.17

400 = x

68 is 17 percentage of the number 400.

To find the number that 68 is 17% of, we can set up the equation:

17% of x = 68

To solve for x, we need to divide both sides of the equation by 17% (or 0.17 as a decimal):

x = 68 / 0.17

Evaluating the division:

x=400

Therefore, 68 is 17% of 400.

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Answer:

Give two equivalent ratios of 6 : 4. 6 : 4 = 6/4 So, equivalent ratios are 6/4 × 2/2 = 12/8 = 12:8 6/4 × 3/3 = 18/12 = 18:12 So, 6 : 4 = 12 : 8 = 18 : 12

Step-by-step explanation:

Answer:

Edna had $510 more amount of money than Toby in the end.

Step-by-step explanation:

LET :-

Edna's amount of money - x

Fatimah's amount of money - y

Toby's amount of money - z

Now,

By the question,

x = 4y

y : (y + z) = 5 : 8

y - 30 = z + 30

Now,

y : (y + z) = 5 :8

or, y/(y + z) = 5/8

or, 8y = 5y + 5z

or, 3y = 5z

so, y = 5z/3

Now,

y - 30 = z + 30

or, 5z/3 - 30 = z + 30

or, (5z - 90)/3 = z + 30

or, 5z - 90 = 3z + 90

or, 5z - 3z = 90 + 90

or, 2z = 180

so, z = 90

Toby's amount of money - $90

Now,

y = 5z/3

or, y = 5 * 90/3

or, y = 5 * 30

so, y = 150

Fatimah's amount of money - $150

Again,

x = 4y

or, x = 4*150

or, x = 600

Edna's amount of money - $600

Now,

$600 - $90

= $510

Therefore,Edna had $510 more amount of money than Toby in the end.

Using proportions, it is found that the total purchase price of the bracelet is of $10,769.

A proportion is a fraction of a total amount.

In this problem, we consider the two taxes, of 6% and 11%, hence the price suffers an increase of 17%, that is, the price is multiplied by 117% = 1.17 to reach $12,600, hence:

1.17p = 12600

p = 12600/1.17

p = 10769.

The total purchase price of the bracelet is of $10,769.

More can be learned about proportions at https://brainly.com/question/24372153

Answer:

x = 2     y = -12

Step-by-step explanation:

x+ y = -10

2 + y = -10

      y = -10 -2 = -12

Answer:

Step-by-step explanation:

Total paycheck before taking out taxes and insurance :

38×15 = 570

Left Amount of money after applying taxes :

570 - 570×(p/100)

= 570×[1 - (p/100)]

= 570×[(100-p)/100]

= (570/100) × [100 - p]

= 5.7 × [100 - p]

After taking out  the insurance amounts we can write this equation:

.,7 × [100 - p] - (35+4) = 462.6

⇔ 5.7 × [100 - p] - 39 = 462.6

⇔ 5,7 × [100 - p] = 462.6 + 39

⇔ 5,7 × [100 - p] = 501.6

⇔ 100 - p = 501.6/5.7

⇔ 100 - p = 88

⇔ p = 100 - 88

⇔ p = 12

Answer:

72.5% out of 100%

Step-by-step explanation:

0.725 is 72.5% of 1. 100% technically counts as 1. so 72.5%

Answer:

  $7045.82

Step-by-step explanation:

The formula for the balance of an account earning interest at rate r compounded continuously for t years is ...

  A = Pe^(rt)

We want to find P, given the other parameters in this formula.

__

  38956.06 = P(e^(0.09×19)) = P(5.52896148)

  P = 38956.06/5.52896148 ≈ 7045.82

The amount of the initial investment was about $7045.82.

Answer:

the answer for this one it should be the probability or chances that the event b occurs when the event a has occured.

Step-by-step explanation: I hope this help you pal or folk and have a great day.

to get the equation of any straight line, we simply need two points off of it, hmmm let's use (0 , 10) and (8 , 30) from the table

[tex](\stackrel{x_1}{0}~,~\stackrel{y_1}{10})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{30}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{30}-\stackrel{y1}{10}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{0}}}\implies \cfrac{20}{8}\implies \cfrac{5}{2}[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{\cfrac{5}{2}}(x-\stackrel{x_1}{0}) \\\\\\ y-10=\cfrac{5}{2}x\implies y=\cfrac{5}{2}x+10[/tex]

Answer:

Step-by-step explanation:

Finding the center.

The general formula for a circle is

(x - a)^2 + (y - b)^2 = r^2

The center is a and b. The center is marked as (6,5)

So the equation becomes

(x - 6)^2 + (y - 5)^2 = r^2

Finding the radius

The radius is found by calculating the distance between the center and any point on the circumference.

The point given on the circumference is (8,8)

x1 = 8

x2 = 6

y1 = 8

y2 = 5

r^2 = (8 - 6)^2 + (8 - 5)^2

r^2 = 2^2 + 3^2

r^2 = 4 + 9

r^2 = 13                            

Answer

(x - 6)^2 + (y - 5)^2 = 13

base = 4 units

height = 2 units

(1/2).base.height = (1/2).4.2 = 4

area = 4 sq. units

hope it helps...!!!

Answer:

Expert's answer

let x denote the number of tires.

x~N(36500,50002)

z=\frac{x-\mu}{\sigma}

σ

x−μ

a) P(x>40000)

z=\frac {40000-36500}{5000}

5000

40000−36500

=0.7

we check the value of p(z>0.7) from the z tables.

=0.24196

24.2% of the tires can be expected to last more than 40000 miles.

b) P(z<0.1)

the value of \phi ^{-1}(0.1)ϕ

−1

(0.1) =-1.28

z=\frac{x-\mu}{\sigma}z=

σ

x−μ

-1.28=\frac{x-36500}{5000}−1.28=

5000

x−36500

=30100 miles

BRAIN LESS ANSWER IS CORRECT

Answer: -310

Step-by-step explanation:

-1240÷4

The accounting rate of return is 7.6%, the payback period is 5.755 years, the Net present value is $58,072, and the net present value(11%) is $3611.

The Net Present Value (NPV) is a corporate finance technique for analyzing the viability of an investment or a firm. It's the disparity between the anticipated cash flows and the initial investment. Let's look more closely at NPV.

We can calculate the accounting rate of return as follows:

Accounting rate of return = (Annual net Income/ Average Investment)×100

=(30,324/399,000)×100

= 7.6%

For Payback period:

Payback = Initial investment/ Annul cash flow

Annual cash flow = Annual net income + Depreciation

Deprecition = cost - salvage value/useful life

= (399,000-48,000)/9

= $39,000

Annual cash flow = 30,324 + 39,000 = 69324

Payback= 399,000/69324

= 5.755 years

For NPV:

NPV = Total present value of investment - initial investment

= 69324×PVIFA(8%, 9 years)+48,000×PV(8%, 9 years) - 399,000

= 69324×6.2469+24,011.95 - 399,000

= $58,072

For Net value recalculate if the cost of capital is 11%

NPV = Total present value of investment - initial investment

= 69324×PVIFA(11%, 9 years)+48,000×PV(11%, 9 years) - 399,000

= 69324×5.5370+18,764.39 - 399,000

= 3610.988

= $3611

Thus, the accounting rate of return is 7.6%, the payback period is 5.755 years, the Net present value is $58,072, and the net present value(11%) is $3611.

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The rational function shown in the graph is:

[tex]y = \frac{x - 6}{x - 5}[/tex]

First, we can see that we have an asymptote at x = 5, so the denominator becomes equal to zero when x = 5.

Then the rational function is something like:

[tex]y = \frac{g(x)}{x - 5}[/tex]

We also can see that when x = 6, the function intercepts the x-axis, then we must have that:

g(6) = 0

So we can define:

g(x) = x - 6

So the rational function is:

[tex]y = \frac{x - 6}{x - 5}[/tex]

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Answer:D

Step-by-step explanation: Multiply the expression