Please answer now! Please show the Example

Answer:36

Step-by-step explanation:

3 a minute
18 in 6 minutes
36 in 12
3:1

x is approximately 20.5 degrees when rounded to the nearest degree. Therefore, x ≈ 21 degrees.

General process of solving for an unknown angle.

1. Determine the type of angle: Determine whether the angle is a right angle (90 degrees), acute (less than 90 degrees), or obtuse (greater than 90 degrees).

2. Use geometric properties: If there are geometric properties or relationships given in the problem, such as angles formed by parallel lines or within a triangle, apply those properties to find the value of x.

3. Apply trigonometric functions: If the problem involves trigonometry, use sine, cosine, or tangent functions along with the given information to solve for x.

4. Apply algebraic equations: If there is an algebraic equation involving x, set up the equation and solve for x by isolating it on one side of the equation.

To find the value of x in the given triangle, we can use the inverse tangent function, which is tan^-1.

tan(x) = opposite/adjacent

tan(x) = 5/14

To isolate x, we take the inverse tangent of both sides:

x = tan^-1(5/14)

Using a calculator, we can find that x is approximately 20.5 degrees when rounded to the nearest degree. Therefore, x ≈ 21 degrees.

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Therefore, the probability that a randomly selected point within the square falls in the red-shaded area is 68%.

Probability is a measure of the likelihood or chance of an event occurring. It is a number between 0 and 1, where 0 represents an impossible event and 1 represents a certain event. The probability of an event A is denoted as P(A). To calculate the probability of an event, we divide the number of favorable outcomes by the total number of possible outcomes.

Here,

The area of the red-shaded region is the area of the square minus the area of the white right-angled triangle. The area of the square is the length of one side squared, which is:

Area of square = 5 cm × 5 cm

= 25 cm²

The area of the right-angled triangle is one-half the base times the perpendicular height, which is:

Area of triangle = (1/2) × base × height

= (1/2) × 4 cm × 4 cm

= 8 cm²

Therefore, the area of the red-shaded region is:

Area of red-shaded region = Area of square - Area of triangle

= 25 cm² - 8 cm²

= 17 cm²

To find the probability that a randomly selected point within the square falls in the red-shaded area, we need to divide the area of the red-shaded region by the total area of the square, which is:

Probability = Area of red-shaded region / Area of square

Probability = 17 cm² / 25 cm²

= 0.68 or 68%

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Minimum

-11

Main concepts:

Concept 1: Identify the type of equation

Concept 2: Identify the concavity (opens up/down)

Concept 3: Finding a vertex of a parabola

Concept 1: Identify the type of equation

First, observe that the equation is a polynomial.  This is a type of equation where there may be multiple terms containing an x, where each term with an x is raised to a whole number power, and may be multiplied by a real number.  Additionally, there may be a constant term added (or subtracted).

For our equation, [tex]y=3x^2-12x+1[/tex], the first two terms contain an x, each raised to a whole number power, and are multiplied by a number.  Additionally, there is a constant added to the end of the equation.  Therefore, this is a polynomial.

The largest power of x in a polynomial is called the "degree" of the polynomial.  Since the largest power of x is 2, this is called a second degree polynomial.  Another common name for a second degree polynomial is a quadratic equation.

This quadratic equation is already in what is known as "Standard form" [tex]y=ax^2+bx+c[/tex]

Concept 2: Identify the concavity (opens up/down)

For quadratic equations, the graph of the equation will be a sort of "U" shape" called a parabola.  The parabola either opens up or down depending on the "leading coefficient" in the quadratic equation.

The "leading coefficient" of any polynomial is the constant number that is multiplied to x in the term with the highest power.  In this case, the leading coefficient is 3.

A parabola opens up or down in correspondence with the sign of the leading coefficient.  If the leading coefficient is positive, the parabola opens upward.  If the leading coefficient is negative, the parabola opens downward.

Since the leading coefficient is 3, the parabola for our example opens upward.  The branches of the "U" will go upward forever, without a maximum.  However, the bottom of the "U" will have a minimum value.  We are assigned to find this minimum value (how low it goes).

Concept 3: Finding a vertex of a parabola

To find the vertex of a parabola, with an equation in standard form, there are a few methods, but the most straightforward is to use the vertex formula:

[tex]h=\dfrac{-b}{2a}[/tex]

Where "h" is the x-coordinate of the vertex, and "a" and "b" are the coefficients from the quadratic equation: [tex]y=ax^2+bx+c[/tex]

[tex]h=\dfrac{-(-12)}{2(3)}[/tex]

[tex]h=\dfrac{12}{6}[/tex]

[tex]h=2[/tex]

So, the parabola will have a vertex with an x-coordinate of "2", meaning that the lowest point will be at a position that is 2 units to the right of the origin... however, we still don't know how high that minimum is.  Fortunately, the equation [tex]y=3x^2-12x+1[/tex] itself gives the relationship between any x-value and the y-value that is associated with it.

[tex]y=3x^2-12x+1[/tex]

[tex]y=3(2)^2-12(2)+1[/tex]

[tex]y=3*4+(-12)*2+1[/tex]

[tex]y=12+-24+1[/tex]

[tex]y=-11[/tex]

So, the vertex of the parabola is (2,-11).

The height of the vertex is -11, so the value of the minimum is -11.

Side note: "What is the value of the minimum" is a different question that "where is the minimum at".  The minimum is at 2.  The actual value of the minimum is -11.

a. In the geometric series for f(x) to be convergent, x < - 1

b.  When x =  1¹/₂, the sum to infinity of the geometric series is f(x) = -1.4

A geometric series is the sum of terms of a geometric sequence.

a. Given the series f(x) = ∑ₙ = ₁⁰⁰(x + 2)ⁿ, we want to determine the value of x for which f(x) converges.

Now, let the general term of the sequence be Uₙ = (x + 2)ⁿ, to determine the value of x for which the series is convergent, we use the D'alembert ratio test which states that for a series to be convergent, then

Uₙ₊₁/Uₙ < 1.

So, we have that Uₙ₊₁ = (x + 2)ⁿ⁺¹

So, Uₙ₊₁/Uₙ =  (x + 2)ⁿ⁺¹/ (x + 2)ⁿ

= x + 2

For convergence

Uₙ₊₁/Uₙ < 1

So,

x + 2 < 1

x < 1 - 2

x < - 1

So, for f(x) to be convergent, x < - 1

b. To find the value of f(x) when x = 1¹/₂, we proceed as folows

Since  f(x) = ∑ₙ = ₁⁰⁰(x + 2)ⁿ, substituting x =  1¹/₂ = 1.5 into the equation, we have

 f(x) = ∑ₙ = ₁⁰⁰(1.5 + 2)ⁿ

f(x) = ∑ₙ = ₁⁰⁰(3.5)ⁿ

= 3.5 + 3.5² + 3.5³ + ...

Since this is a geometric progression with sum to infinity, we see that the first term is a = 3.5 and the common ratio is r = ar/a = 3.5²/3.5 = 3.5

Since the sum to infinity of a geometric progression is

S₀₀ = a/(1 - r)

So, substituting the values of the variables into the equation, we have that

S₀₀ = a/(1 - r)

S₀₀ = 3.5/(1 - 3.5)

S₀₀ = 3.5/-2.5

S₀₀ = -1.4

So, when x =  1¹/₂, f(x) = -1.4

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Hi! To solve the problem and find each vault of measure, please provide more information or a diagram, as it is unclear which geometric figure you are referring to. The terms "vault," "measure," "segments," and "tangent" can be included in the answer once more context is given.

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Let's break down the information given in the problem:

- Jane became a real estate agent in 1990.

- She sold a house 8 years later (in 1998) for $144,000.

- She sold the same house 11 years after that sale (in 2009), which is 19 years after she became an agent, for $245,000.

To write an equation that represents the value of the house (V) related to the number of years (t) since Jane became a real estate agent, we can use the information from the two sales to find the rate of change in the value of the house over time. We can use this rate of change to write an equation in point-slope form:

V - V1 = m(t - t1)

where V1 is the value of the house at time t1, m is the rate of change in the value of the house, and t is the time since Jane became a real estate agent.

Using the two sales, we can find the rate of change in the value of the house as follows:

m = (V2 - V1) / (t2 - t1)

where V2 is the value of the house at the second sale, t2 is the time of the second sale (19 years after Jane became an agent), V1 is the value of the house at the first sale, and t1 is the time of the first sale (8 years after Jane became an agent).

Substituting the given values, we get:

m = ($245,000 - $144,000) / (19 - 8) = $10,100 per year

Now we can use the point-slope form equation to find the value of the house at any time t since Jane became a real estate agent. Let's choose 1990 as our initial time (t1), so V1 = $0:

V - 0 = $10,100 (t - 0)

Simplifying, we get:

V = $10,100t

Therefore, the equation that represents the value of the house (V) related to the number of years (t) since Jane became a real estate agent is V = $10,100t. Note that this equation assumes a constant rate of change in the value of the house over time, which may not be accurate in real life.

Julia will use 10 groups to arrange all of the CDs.

To determine the number of groups Julia will use to arrange all of the CDs, we need to find the greatest common divisor of the numbers 215, 125, and 330.

First, we can check if any of the numbers are divisible by 5:

215 is not divisible by 5

125 is divisible by 5 (125 ÷ 5 = 25)

330 is divisible by 5 (330 ÷ 5 = 66)

Now we divide 125 and 330 by 5:

125 ÷ 5 = 25

330 ÷ 5 = 66

Next, we check if any of the numbers are divisible by 2:

25 is not divisible by 2

66 is divisible by 2 (66 ÷ 2 = 33)

Now we divide 66 by 2:

66 ÷ 2 = 33

Therefore, the greatest common divisor of 215, 125, and 330 is 5 × 2 = 10.

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So basically you have to drag an angle to the box, example drag DFA to the box, then add what angle it is equal to. You have to calculate the angle and drag it opposite to the DFA. For DFA, it will be 58.

The appropriate null and alternative hypotheses for the experiment are:

Null hypothesis (H0): According to null hypothesis, the average time it takes for a person to experience pain relief from the new pain reliever is not beyond 15 minutes.

Alternative hypothesis (Ha): According to Alternative hypothesis, the average time it takes for a person to experience pain relief from the new pain reliever is significantly less than 15 minutes, indicating that the new ingredient does speed up pain relief.

The alternative and null hypotheses can be written as follows in symbols:

H0: = 15 (where μ is the population mean time for pain relief from the new pain reliever)

Ha: μ < 15

The one-tailed hypothesis test assumes that the new component of the painkiller can only reduce the duration of pain alleviation, not lengthen it. As a result, the rejection region will be in the left tail of the distribution, while the alternative hypothesis is one-tailed to the left.

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If an 'I' statement is true, then the truth value of its corresponding E statement is equals to the true. So, option(a) is right answer of this problem.

Truth value : The truth value of a statement is either true or false, depending on whether the logic makes sense or not. Let us assume two statements, p : Ram goes to school daily

q : Ram will get good marks

We use implication for determining value. In logic, implication is relationship between different propositions in which the second proposition is a logical consequence of the first.

first case : If Ram does not go to school daily then he will get good marks. That is p is false and q is true, ¬ p --> q ⇒ true ( using implication rule)

second case : If Ram does not go to school daily then he will not get good marks. That is p is false and q is false , ¬ p --> ¬ q ⇒ true ( using implication rule)

Hence, required value of statement is true.

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o find the coordinates of the gates in the third quadrant, we need to find the points where the circle and the line intersect in the third quadrant.

Substituting y = 2x into x² + y² - 4x = 9, we get:

x² + (2x)² - 4x = 9

5x² - 4x - 9 = 0

Using the quadratic formula, we find:

x = (-(-4) ± √((-4)² - 4(5)(-9))) / (2(5))

x = (4 ± √136) / 10

We can discard the positive root since it is in the first quadrant. The negative root corresponds to the x-coordinate of the point of intersection in the third quadrant:

x = (4 - √136) / 10 ≈ -0.433

Substituting this value into y = 2x, we get:

y = 2(-0.433) ≈ -0.866

Therefore, the ordered pair that represents the location of the gates in the third quadrant is (-0.433, -0.866).

Following shows (sin 7x)/sin x = 64(cos x)^6 - 80(cos x)^4 +24(cos x)^2 - 1:

12sin^3 x - 8sin^

To show that (sin 7x)/sin x is equal to 64(cos x)^6 - 80(cos x)^4 + 24(cos x)^2 - 1, we can use trigonometric identities and algebraic manipulation.

Let's start with the left-hand side of the equation:

(sin 7x)/sin x

Using the trigonometric identity for sin(A + B):

sin(A + B) = sin A cos B + cos A sin B

We can rewrite sin 7x as sin (6x + x):

sin (6x + x) = sin 6x cos x + cos 6x sin x

Now we can substitute sin 7x with sin 6x cos x + cos 6x sin x:

(sin 6x cos x + cos 6x sin x)/sin x

Next, we can simplify this expression by dividing both terms by sin x:

(sin 6x cos x)/sin x + (cos 6x sin x)/sin x

The sin x term cancels out, leaving us with:

sin 6x cos x + cos 6x

Now, we can use the double-angle identity for sin 2A:

sin 2A = 2sin A cos A

To rewrite sin 6x cos x, we can treat it as sin 2A with A = 3x:

sin 6x cos x = 2sin 3x cos 3x

Next, we can use the triple-angle identity for sin 3A:

sin 3A = 3sin A - 4sin^3 A

To rewrite sin 3x, we can treat it as sin A with A = x:

sin 3x = 3sin x - 4sin^3 x

Substituting this into our expression:

2sin 3x cos 3x = 2(3sin x - 4sin^3 x) cos 3x

Expanding further:

= 6sin x cos 3x - 8sin^3 x cos 3x

Now, we can use the double-angle identity for cos 2A:

cos 2A = cos^2 A - sin^2 A

To rewrite cos 3x, we can treat it as cos A with A = x:

cos 3x = cos^2 x - sin^2 x

Substituting this into our expression:

6sin x cos 3x - 8sin^3 x cos 3x = 6sin x (cos^2 x - sin^2 x) - 8sin^3 x (cos^2 x - sin^2 x)

Expanding further:

= 6sin x cos^2 x - 6sin x sin^2 x - 8sin^3 x cos^2 x + 8sin^3 x sin^2 x

Now, we can use the Pythagorean identity for sin^2 x + cos^2 x:

sin^2 x + cos^2 x = 1

To rewrite sin^2 x, we can subtract cos^2 x from both sides:

sin^2 x = 1 - cos^2 x

Substituting this back into our expression:

= 6sin x (cos^2 x - (1 - sin^2 x)) - 8sin^3 x cos^2 x + 8sin^3 x sin^2 x

= 6sin x (2sin^2 x) - 8sin^3 x cos^2 x + 8sin^3 x sin^2 x

= 12sin^3 x - 8sin^

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Answer:

a) The number of groups are 11.

b) For Aadya, there are 12 stamps in each group. For Sumit, there are 19 stamps per group.

Step-by-step explanation:

Aadya: 143 - 11 = 132 stamps.

Sumit: 220 - 11 = 209 stamps.

Greatest Common Factor of 132 and 209 = 11 group for both

Aadya: Let a = # of stamps in each group.; 11a = 132; a = 12 stamps per group

Sumit: Let s = # of stamps in each group.; 11s = 209; s = 19 stamps per group.

The width of the rectangular playing field is approximately 50 yards if the width is located 15 yards from either vertex.

To solve the problem, we can draw a diagram and use the properties of ellipses.

First, we note that the major axis of the ellipse is 110 yards and the minor axis is 50 yards. We can find the distance between the two foci of the ellipse using the formula c^2 = a^2 - b^2, where c is the distance between the foci, and a and b are the lengths of the semi-major and semi-minor axes.

c^2 = 110^2 - 50^2

c^2 = 10800

c ≈ 104.0

Next, we draw the two foci of the ellipse and the rectangle as shown in the diagram below. We are given that the width of the rectangle is 30 yards (15 yards from either vertex). x be the length of the rectangle.

      A          B

   +-------+-------+

  /                  \

 /                    \

/                      \

C                        D

\                      /

 \                    /

  \                  /

   +-------+-------+

      E          F

We can see that the length of the rectangle is equal to the distance between points A and B, and the width of the rectangle is equal to the distance between points C and D. Using the Pythagorean theorem, we can find the length of the rectangle.

AB^2 = AE^2 + EB^2

AB^2 = (a/2)^2 + (c - b/2)^2

AB^2 = (55)^2 + (104 - 15)^2

AB^2 = 3025 + 7225

AB = sqrt(10250)

AB ≈ 101.2

Therefore, the length of the rectangle is approximately 101.2 yards.

To find the width of the rectangle, we can use the fact that the distance between points C and D is equal to twice the distance between the center of the ellipse and the minor axis. The center of the ellipse is the midpoint of the major axis, and the distance from the center to the minor axis is 25 yards.

CD = 2 * 25 = 50

Therefore, the width of the rectangle is approximately 50 yards.

In summary, the width of the rectangular playing field is approximately 50 yards if the width is located 15 yards from either vertex.

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Answer:

10 outcome is the answer

Using the nth-term test for divergence on the series ∑ 1/n+13 is inconclusive. However, by comparing the series to the divergent harmonic series, we can conclude that ∑ 1/n+13 is also divergent.

We can use the nth-term test for divergence to determine the convergence or divergence of the series

lim n → ∞ (1/n+13) = 0

Since the limit of the nth term is 0, the nth-term test is inconclusive, and we cannot determine the convergence or divergence of the series using this test.

However, we can use the comparison test to show that the series diverges. We can compare the given series to the harmonic series, which we know diverges

1/1 + 1/2 + 1/3 + ...

Since each term of the given series is less than the corresponding term of the harmonic series, the given series must also diverge. Therefore, the series ∑ 1/n+13 is divergent.

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To solve exercise 3 on the first page of the handout, we need to first isolate y in the given equation 2.23 - 3y = 8, which gives us y = -1.59.

To find y", we need to differentiate both sides of the equation with respect to x twice. The first derivative gives us:
-3(dy/dx) = 0
Simplifying, we get dy/dx = 0.
Differentiating again, we get:
-3d^2y/dx^2) = 0
Simplifying, we get d^2y/dx^2 = 0.

Therefore, the equation we obtain after differentiating both sides of the given equation with respect to x is d^2y/dx^2 = 0, which is the second derivative of y with respect to x.
To solve the equation given on the first page of the handout, 2.23 - 3y = 8, first isolate y:
1. Subtract 2.23 from both sides: -3y = 5.77
2. Divide both sides by -3: y = -5.77/3
Your answer: y = -5.77/3

The original equation doesn't have any x terms, so differentiation with respect to x is not applicable in this case.

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The two types of transformations that are produced by the matrix include:

We can see that a 90° counter-clockwise rotation followed by a dilation produces a transformation that stretches and rotates the figure.

On the other hand, a 90° counter-clockwise rotation followed by a reflection in the vertical axis produces a transformation that reflects and rotates the figure.

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Answer: Si la emisión de gases de efecto invernadero aumenta en un 5% anual, ¿cuánto aumentará la temperatura global en 20 años?

Solución: Dado que cada

Step-by-step explanation:

Una empresa produce 400 toneladas de dióxido de carbono al año. Si cada tonelada de dióxido de carbono contribuye al calentamiento global en 0.05 grados Celsius, ¿cuál será el aumento de temperatura causado por la empresa en un año?

Solución: 400 x 0.05 = 20 grados Celsius

La temperatura media de la Tierra ha aumentado en 1 grado Celsius desde la era preindustrial.

Si el aumento de temperatura está directamente relacionado con la cantidad de dióxido de carbono en la atmósfera, ¿cuánto dióxido de carbono adicional se ha emitido desde la era preindustrial hasta ahora?

Solución: Dado que cada tonelada de dióxido de carbono contribuye a un aumento de 0.05 grados Celsius, 1 / 0.05 = 20. Por lo tanto, se han emitido 20 veces la cantidad de dióxido de carbono necesario para contribuir a un aumento de 1 grado Celsius.

Una central térmica produce 1000 megavatios de electricidad al día. Si la eficiencia de conversión de la central térmica es del 30%, ¿cuántas toneladas de dióxido de carbono se emiten al día?

Solución: La eficiencia de conversión de la central térmica es del 30%, lo que significa que se pierde el 70% de la energía.

Por lo tanto, la cantidad de energía producida por la central térmica es de 1000 x 0.3 = 300 megavatios. Si cada megavatio produce 0.5 toneladas de dióxido de carbono, entonces la central térmica emite 300 x 0.5 = 150 toneladas de dióxido de carbono al día.

Si se reduce la emisión de dióxido de carbono en un 20%, ¿en qué medida se reducirá el aumento de temperatura global?

Solución: Si se reduce la emisión de dióxido de carbono en un 20%, se reducirá el aumento de temperatura global en un 20% x 0.05 = 0.01 grados Celsius.

Si la temperatura media en una ciudad ha aumentado en 0.5 grados Celsius en los últimos 10 años, ¿cuál es la tasa de aumento de temperatura por año?

Solución: La tasa de aumento de temperatura por año es de 0.5 grados Celsius / 10 años = 0.05 grados Celsius por año.

Si la concentración de dióxido de carbono en la atmósfera es de 400 partes por millón (ppm) y se espera que aumente en un 2% anual, ¿cuál será la concentración de dióxido de carbono en 10 años?

Solución: El aumento anual de la concentración de dióxido de carbono es de 400 x 0.02 = 8 ppm. Por lo tanto, la concentración de dióxido de carbono en 10 años será de 400 + 8 x 10 = 480 ppm.

Si la emisión de gases de efecto invernadero aumenta en un 5% anual, ¿cuánto aumentará la temperatura global en 20 años?

Solución: Dado que cada

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If the number of minutes used is less than 625 per month, it is more affordable to use International Links if not, you can go for World Connections.

Let us assume that the number of minutes used = x

Cost per minute =  18 cents

Total cost for International calls = 0.18x

Basci cahrge =  50 per month

If we use x number of minutes for calls for world connections then the total cost will be:

50 + 0.10x

To find the value of x where International Links cost is less than the total cost for World Connections

0.18x < 50 + 0.10x

0.08 < 50

8x < 50

x < 625

Therefore, we can infer that if the number of minutes used is less than 625 per month, it is cheaper to use International Links.

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The closest answer choice is  [tex]27.52 units^2.[/tex]

The area of the circle, we need to find the area of one sector and then multiply it by 16 since there are 16 congruent sectors.

To find the area of one sector, we use the formula:

[tex]Area of sector = (angle/360) * \pi*r^2[/tex]

Since we know the base and height of the highlighted sector, we can use the Pythagorean theorem to find the radius of the circle:

[tex]r^2 = (1.56/2)^2 + (3.92)^2[/tex]

r ≈ 3.969 units

Now we can find the angle of one sector using the formula:

angle = (base/radius) x 180/π

angle ≈ 22.5 degrees

Plugging in the values for angle and radius in the area of sector formula, we get:

[tex]Area of sector =(22.5/360) *\pi (3.969)^2[/tex]

Area of sector ≈ 0.491π

Multiplying this by 16, we get the approximate area of the circle:

Approximate area of circle ≈ 16 x 0.491π

Approximate area of circle ≈ 7.8π

Using a calculator to approximate π as 3.14, we get:

Approximate area of circle ≈ [tex]24.46 units^2[/tex]

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The oil spill is increasing by approximately 0.58% per hour.

An oil spill is spreading such that its area is given by the exponential function A(t) = 250(1.15)^t, where A is the area in square feet and t is the time that has elapsed in days. To find the percent increase per hour, first convert the time from days to hours by replacing t with (t/24), since there are 24 hours in a day.

A(t) = 250(1.15)^(t/24)

To determine the hourly percent increase, find the growth factor for one hour (t=1) and subtract 1 to get the percentage:

A(1) = 250(1.15)^(1/24) ≈ 250(1.0058)

The growth factor for one hour is approximately 1.0058. To find the percent increase, subtract 1 and multiply by 100:

(1.0058 - 1) × 100 ≈ 0.58%

The oil spill is increasing by approximately 0.58% per hour.

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The surface area of the square base pyramid is calculated to be equal to 460 square millimetres.

area of one triangle face = 1/2 × 10 mm × 18 = 90 mm² mm

area of the four triangle faces = 4 × 90 mm² = 360 mm²

area of the square base = 10 mm × 10 mm = 100 mm²

surface area of the square base pyramid = 360 mm² + 100 mm²

surface area of the square base pyramid = 460 mm²

Therefore, the surface area of the square base pyramid is calculated to be equal to 460 square millimetres.

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The result of applying the square root property of equality to this equation is x = (-b ± √(b² - 4ac)) / (2a)

If we apply the square root property of equality to the equation (x + (b/2a))² = (-4ac + b²)/(4a²), we get:

x + (b/2a) = ±√[(-4ac + b²)/(4a²)]

Next, we can simplify the expression under the square root:

√[(-4ac + b²)/(4a²)] = √(-4ac + b²)/2a

Now, we can substitute this expression back into our original equation:

x + (b/2a) = ±√(-4ac + b²)/2a

Finally, we can isolate x by subtracting (b/2a) from both sides:

x = (-b ± √(b² - 4ac)) / (2a)

This is the quadratic formula, which gives us the solutions for the quadratic equation ax² + bx + c = 0. By completing the square, we have derived this formula from the original quadratic equation.

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Complete question is:

In the derivation of the quadratic formula by completing the square, the equation (x+ (b/2a))² =(-4ac+b²)/(4a²) is created by forming a perfect square trinomial What is the result of applying the square root property of equality to this equation?

The mean is 725.7 and the standard deviation is 13.55.

To find the mean and standard deviation using the normal approximation to the binomial, we will use the following formulas in Excel:

Mean = np

Standard Deviation = sqrt(np(1-p))

Where n = sample size, p = proportion of success, and sqrt = square root.

Using the information given in the question, we can plug in the values:

n = 1230
p = 0.59

Mean = np = 1230*0.59 = 725.7

Standard Deviation = sqrt(np(1-p)) = sqrt(1230*0.59*(1-0.59)) = 13.55

Therefore, the mean is 725.7 and the standard deviation is 13.55.

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The price of one cubic yard of sand is $33.75, then the price of one cubic foot of sand should be  $1.25.

To determine the price of one cubic foot of sand, we need to convert cubic yards to cubic feet. One cubic yard is equal to 27 cubic feet (3 feet x 3 feet x 3 feet). Therefore, if the price of one cubic yard of sand is $33.75, then the price of one cubic foot of sand should be $33.75/27 = $1.25.

This makes sense because one cubic yard contains 27 cubic feet. So, if the price of one cubic yard is $33.75, then the price per cubic foot should be 1/27th of that price.

It is important to note that this assumes the price per unit of sand remains constant regardless of the quantity purchased. In reality, bulk purchases may result in a discounted price per unit. Additionally, factors such as transportation costs and demand may also affect the price of sand.

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0.135 or 13.5%  is the probability that he had 3 âhits

The probability that the player had 3 hits in 5 at-bats can be calculated using the binomial probability formula, which is:

P(x) = (nCx) * p^x * (1-p)^(n-x)

where:
- P(x) is the probability of getting x hits
- n is the number of at-bats (in this case, 5)
- x is the number of hits we want to find the probability for (in this case, 3)
- p is the probability of getting a hit in one at-bat (in this case, 0.343)
- (1-p) is the probability of not getting a hit in one at-bat (in this case, 0.657)

Plugging in the values, we get:

P(3) = (5C3) * 0.343^3 * 0.657^(5-3)
P(3) = (10) * 0.039304527 * 0.4305961
P(3) = 0.134912947

Therefore, the probability that the player had 3 hits in 5 at-bats is approximately 0.135 or 13.5%.

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The expression that shows the temperature at sunset in terms of T is 3T/2.

Let's call the temperature at sunrise T. According to the problem statement, the temperature tripled from sunrise to noon, so the temperature at noon is 3T.

Then, from noon to sunset, the temperature halved, so the temperature at sunset is (1/2) of the temperature at noon, or (1/2)(3T), which simplifies to 3T/2. Therefore, the expression that shows the temperature at sunset in terms of T is 3T/2.

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