please help AFAP........................

Answer:

150N

Explanation:

To find the force applied remember that force equals to Mass multiply by the Acceleration.

F=Ma

=30*5

=150N

Answer:

150N

Explanation:

F = m*a = 30 * 5 = 150 N

The relation between a frog's maximum height and maximum range is that when the frog jumps at an angle of 45°, its maximum height is half of the horizontal range.

The maximum height refers to the maximum vertical distance that an object can travel.

The maximum range is the maximum horizontal distance that an object can travel.

The maximum height, H that the projectile reaches when the range, R, is at its greatest is H = Rmax /4.

R = 4Hcot is the relationship between the horizontal range and maximum height.

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Answer:

Amplitud (dinámica)

Explanation:

La amplitud de una onda de sonido determina su volumen relativo. En música, el volumen de una nota se denomina nivel dinámico.

Answer:

Polarized light waves are light waves in which the vibrations occur in a single plane. The process of transforming unpolarized light into polarized light is known as polarization. There are a variety of methods of polarizing light.

Explanation:

Answer:

f = 4 Hz

Explanation:

Given that,

The speed of a wave, v = 12 m/s

The wavelength of a wave, [tex]\lambda=3\ m[/tex]

We need to find the frequency of the wave. We know that the speed of wave is equal to the product of wavelength and frequency. So,

[tex]v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{12}{3}\\\\f=4\ Hz[/tex]

So, the frequency of the wave is equal to 4 Hz.

Answer:

Fault

Explanation:

it only carries a current if there is a fault.

Answer:

[tex]V=9.2565m/s[/tex]

Explanation:

From the question we are told that:

Force [tex]F = 34 N[/tex]  

Time [tex]t = 0.6 s[/tex]

Length of pedal [tex]l_p=16.5cm \approx0.165m[/tex]

Radius of wheel [tex]r = 33 cm = 0.33 m[/tex]

Moment of inertia, [tex]I = 1200 kgcm2 = 0.12 kg.m2[/tex]

Generally the equation for Torque on pedal [tex]\mu[/tex] is mathematically given by

[tex]\mu=F*L\\\mu=34*0.165[/tex]

[tex]\mu=5.61N.m[/tex]

Generally the equation for  angular acceleration [tex]\alpha[/tex] is mathematically given by

 [tex]\alpha=\frac{\mu}{l}[/tex]

 [tex]\alpha=\frac{5.61}{0.12}[/tex]

 [tex]\alpha=46.75[/tex]

Therefore Angular speed is \omega

[tex]\omega=\alpha*t[/tex]

[tex]\omega=(46.75)*(0.6)[/tex]

[tex]\omega=28.05rad/s[/tex]

Generally the equation for  Tangential velocity V is mathematically given by

[tex]V=r\omega[/tex]

[tex]V=(0.33)(28.05)[/tex]

[tex]V=9.2565m/s[/tex]

Answer:

0.00296

Explanation: This answer works for Acellus! :)

The voltage applied to the capacitor is approximately 2.964 x 10⁻³ C/F.

Capacitance is a fundamental electrical property that measures the ability of a system to store an electric charge when a potential difference (voltage) is applied across it. It is denoted by the symbol "C" and is measured in farads (F). A capacitor is a device commonly used to create capacitance in an electrical circuit.

In simple terms, capacitance is a measure of how much electric charge can be stored on an object (usually a capacitor) for a given electric potential difference. It is directly proportional to the amount of charge stored and inversely proportional to the applied voltage. Capacitance plays a crucial role in various electronic circuits and systems, including filtering, energy storage, and timing applications.

To calculate the voltage applied to the capacitor, we can use the formula:

Q = C × V

Where:

Q is the charge on the plates of the capacitor

C is the capacitance

V is the voltage applied to the capacitor

Given:

Capacitance (C) = 3.89 x [tex]10^{(-8)[/tex] F

Charge on the plates (Q) = 1.15 x [tex]10^{(-10)[/tex]C

Rearranging the formula, we can solve for V:

V = Q / C

Substituting the given values:

V = (1.15 x [tex]10^{(-10)[/tex] C) / (3.89 x [tex]10^{(-8)[/tex] F)

Dividing the numerator and denominator by [tex]10^{(-8)[/tex]:

V = (1.15 / 3.89) x [tex]10^{(-10 - (-8))[/tex] C/F

V = (1.15 / 3.89) x [tex]10^{(-2)[/tex] C/F

V = 0.2964 x [tex]10^{(-2)[/tex] C/F

Using scientific notation, we can express the voltage as:

V = 2.964 x [tex]10^{(-3)[/tex]C/F

Therefore, the voltage applied to the capacitor is approximately 2.964 x [tex]10^{(-3)[/tex] C/F.

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the ball have no mechanical kinetic energy:

This refers to the energy that an object possessed due to its motion or due to its position. It is calculated by getting the product of the mass of the object and its velocity and dividing it by two. It is measured in joules, J.

if a referee tosses a basketball in the air, the ball will not  have mechanical kinetic energy:

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Answer:

P = 1936 W

Explanation:

Given that,

Voltage, V = 220 V

The resistance of the heater, R = 25 ohms

We need to find the power dissipated in the heater. We know that the power dissipated by the electric appliances is given by :

[tex]P=\dfrac{V^2}{R}\\\\P=\dfrac{(220)^2}{25}\\\\P=1936\ W[/tex]

So, the required power is equal to 1936 W.

Explanation:

This is because of a phenomenon called refraction which effects the direction of sound.

Answer:

Bonjour! Mon francais est assez rouillé, mais faire de mon mieux pour traduire la page; voici les principaux points:

1. (Une) Le rôle de la boule de flotteur dans le circuit électrique est qu'il permet à la pompe d'arrêter lorsque l'eau n'est pas le bon niveau en venant en contact avec deux conducteurs et la fermeture du circuit électrique.

2. (Deux) Je veux dire que le matériau qui constitue la balle en isolant, car il maintient l'eau et hors de blocage force active de la machine.

3. (Trois) Le courant électrique continuera aussi longtemps que la pompe est branchée sur une prise électrique, je crois.

Encore une fois, s'il vous plaît pardonnez-moi, je suis mieux à la lecture de français que de l'écrire! J'espère que cela a pu aider. Si vous avez plus de questions, je vais faire de mon mieux pour y répondre!

Salut!

Answer:

Imag distance = 28.9 cm

Explanation:

Given that,

Object distance, u = -65 cm

The focal length of the convex les, f = +20 cm

We need to find the image distance. The lens formula gives the relation between focal length, object distance and image distance is given by :

[tex]\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{20}+\dfrac{1}{-65}\\\\v=28.9\ cm[/tex]

So, the image distance is 28.9 cm

The distance travel while accelerating is 90m

The initial velocity of the particle is 15m/s and the final velocity is 45m/s, so the change in velocity is 45m/s - 15m/s = 30m/s. The particle accelerates uniformly for 3.0s, so the acceleration is 30m/s / 3.0s >>30/3=10 that is 10m/s^2.

The distance traveled during the acceleration is equal to the average velocity times the time elapsed, so the distance traveled is (15m/s + 45m/s)/2 * 3.0s = (15+45)/2*3= 90m .

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Answer:

c

Explanation:

Newton's subsequent law expresses that power is corresponding to what exactly is needed for an object of consistent mass to change its speed. This is equivalent to that item's mass increased by its speed increase. We use Newtons, kilograms, and meters each second squared as our default units, albeit any proper units for mass (grams, ounces, and so forth) or speed (miles each hour out of every second, millimeters per second2, and so on) could unquestionably be utilized also - the estimation is the equivalent notwithstanding.

Hence, the appropriate answer will be 399,532.

Net Force = 399532

Answer: [tex]243.10\ mm\ \text{of}\ Hg[/tex]

Explanation:

Given

The initial volume of gas [tex]V_1=5\ ml[/tex]

Initial pressure is [tex]P_1=141\ mm\ \text{of}\ Hg[/tex]

Final volume is [tex]V_2=2.9\ ml[/tex]

As it is given [tex]P_1V_1=P_2V_2[/tex]

insert the values

[tex]141\times 5=P_2\cdot 2.9\\P_2=243.10\ mm\ \text{of}\ Hg[/tex]

The net work that is needed to accelerate a 2.0 kg mass from rest to velocity 2v is 4.0 m/s.

When a force acts on a body at rest or at uniform motion in a straight line, then it starts to accelerate.

Given that, the velocity is 5.0

Time is 2 sec

The given mass is 2.0 kg

First, we calculate the acceleration

Acceleration = v / t = 10 / 5.0 = 2

From Newton's second law, we know that

force = mass x acceleration

F = ma

F = 2.0 x 2 = 4.0 m/s

Therefore, the net work that is needed to accelerate a 2.0 kg mass from rest to velocity 2v is 4.0 m/s.

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The question is incomplete. Your most probably complete question is given below:

What net force is needed to accelerate a 2.0 kg mass from rest to a velocity of 10 m/s in 5.0 s?

Answer:

Explanation:

In a quiet forest, you can sometimes hear a single leaf fall to the ground. ... greater its pressure amplitude, the more the air is compressed in the sound it creates. ... Graphs of the gauge pressures in two sound waves of different intensities. ... The sound intensity level β in decibels of a sound having an intensity I in watts per .

Altitude and Air

but mainly altitude, Air is just depending on the situation.

Air does not always influence an object's fall, but Altitude always influences it.

The force is 196 N (20kg x 9.8 m/s2)

Force is an action or influence that causes an object to change its state of motion or rest. Force can be exerted by a single object or by two or more objects interacting with each other. Examples of force include friction, gravity, magnetism, electricity, and pressure. The magnitude of a force is usually measured in newtons (N) and is determined by the amount of mass and acceleration of the object it is acting upon.

The force exerted on the coyote by the ground is equal to the mass of the coyote multiplied by the acceleration due to gravity, which is 9.8 m/s2.

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Answer:

C

Explanation:

it depends only on the forces acting along the y- axis

Answer:

The statement that is true for the motion of sliding the object on the table is : its independent of all forces acting on the object

Explanation:

Answer:

What is the mass tho?

You need the mass to answer this question

Answer:

[tex]distance = ut + \frac{1}{2} g {t}^{2} \\since \: the \: fruit \: is \: from \: rest : \: initial \: velocity \: is \: 0 \: (u = 0) \\ 5 = (0 \times t) + ( \frac{1}{2} \times 9.81 \times {t}^{2} ) \\ 5 = 4.905 {t}^{2} \\ t = \sqrt{1.0194} \\ t = 1 \: second[/tex]

Answer:

a) 1.1418 kg

b) 0.9135 kg/s

Explanation:

Given data :

spring constant ( k ) = 3 kg/s^2

amplitude of vibrations will decay like :  

The mass of the object will be 1.418 kg and the value of the friction coefficient, b is 0.9135 kg/s.

In physics, a periodic motion is a movement that repeats at regular intervals. A swing in motion, a rocking chair, a bouncing ball, a tuning fork vibrating, the Earth orbiting the Sun, and a water wave are all examples of periodic motion. The time interval for repetition, or cycle, of the motion, is referred to in each case as a period, and the frequency is the number of periods per unit of time.

According to the question, the given values are :

Spring constant, k = 3 kg/s²,

Time, T₁ = 4 sec

r = 0.4

The formula for damped oscillation is : [tex]e^-^r^t[/tex]

r = b / 2 m

w₁ = [tex]\sqrt{w_0^2-r^2}[/tex]

T₁ = 2π / w₁

= 2 π /        [tex]\sqrt{w_0^2-r^2}[/tex]

w₀ = [tex]\sqrt{4 \pi^2/T_1 +r^2}[/tex]

[tex]\sqrt{k/m}[/tex] = [tex]\sqrt{4 \pi^2/T_1 +r^2}[/tex]

M = k / [tex]{4 \pi^2/T_1 +r^2}[/tex]

M = 3/ (4π/4² +(0.4)²)

M = 1.1418 kg

b = 2 Mr = 2 × 1.1418 × 0.4

b = 0.9135 kg/s

Hence, the mass of the object is 1.1418 kg and the friction coefficient is 0.9135 kg/s.

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I think the answer is b but im not really sure

Answer:

The net force is equal to zero.

Explanation:

Two equal forces going in opposite directions will always result in a net force of 0.

Answer:

The net force would be 0.

Explanation:

If you have equal amounts of force on each side it is 0. If you had different amounts of force on each side the side you would subtract the greater one form the smaller one equalling your net force.

Answer:

Explanation:

Emf induced e = nBAω sinωt where n is no of turns , B is magnetic field, A is area of the coil ω is angular frequency of rotation .

maximum emf =  nBAω

Given n = 27 , B = 74 x 10⁻⁶ T , A = .12 m x .09 m = 108 x 10⁻⁴ m²

ω = 2π x 57/60 = 5.966 rad/s .

Putting the values

maximum emf  = 27 x 74 x 10⁻⁶ T x 108 x 10⁻⁴ m² x 5.966 rad/s .

= 1.29 x 10⁻⁴ V  .

Answer:

0.15 m/s²

Explanation:

Acceleration is rate of change of velocity-time function. We can find acceleration by finding the slope. The slope of graph can be found by:

[tex] \displaystyle{a = \dfrac{ \Delta v}{ \Delta t} \: \to \: \dfrac{v_f - v_i}{t_f- t_i}}[/tex]

Substitute in:

[tex] \displaystyle{a = \dfrac{5 - 2}{40 - 20}} \\ \\ \displaystyle{a = \dfrac{3}{20}} \\ \\ \displaystyle{a = 0.15 \: \text{m/s}^{2} }[/tex]

Therefore, the acceleration is 0.15 m/s²