Please help! No links! Thanks!!

Please Help! No Links! Thanks!!

Answers

Answer 1

Answer: 30

Step-by-step explanation:

3 times 2 is 6 and divided by 2 is 3 and 3 times 10 is 30


Related Questions

someone help with this please

Answers

Answer:

V ≈ 5144.9 cubic units

Step-by-step explanation:

SA(sphere) = 4πr²

1156π = 4πr²

π's cancel out

1156 = 4r²

r² = 1156/4

r² = 289

r = √289

r = 17

V(sphere) = 4/3πr³

= 4/3 × π × 17³

= 4/3π × 4913

V ≈ 5144.9 cubic units

HELP ASAP!!!!


A person is standing 19 feet from the base of a tree and there is a bird's nest in the tree 10 feet above the groundWhat is the angle off elevation from the person to the bird's nest? Round to the nearest tenth of a degree

Answers

Answer:

do your own work don't ask any question

Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!

Answers

Answer:

Everything seems correct, I'm assuming you wanted confirmation

Marla is four years less than twice as old as Darla. If the sum of their age is 47, how old is Marla?

Answers

According to the given algebra Darla is 17 years old and Maria is 30 years old.

What algebraic fundamentals are there?

Numbers, parameters, constants, expressions, equations, linear equations, and quadratic equations are all part of the fundamentals of algebra. Additionally, the algebraic expressions contain the fundamental arithmetic operations of addition, subtraction, multiplication, as well as division.

According to the given information.

Maria is 4 years younger than Don,

thus if Don is x years old, then Maria is x years younger. (2x-4)

If their ages added together equal 47,

then x + (2x-4) = 47

Solving for x, then determining Maria's age (2x-4)

3x=47+4

3x=51

x=51/3

x=17 years

Maria's age=2*17-4=30 years

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HELP ASAP WILL MARK BRAINLIEST AREA OF FIGURES

Answers

Answer:

1. 170.083 in³

2. 126π in³

3. 92.106 m³

4. 2412.74 in³

5. 612π m³ and 1922 m³

Step-by-step explanation:

1.

Cylinder:

[tex]V = \pi r^{2}h[/tex]               *Plug in numbers*

[tex](3.14)(2.5)^{2}(7)[/tex]         *Square 2.5*

[tex](3.14)(6.25)(7)[/tex]        *Solve*

≈ [tex]137.375in^{3}[/tex]

Sphere:

[tex]V = \frac{4}{3}\pi r^{3}[/tex]              *Plug in numbers*

[tex]\frac{4}{3} (3.14)(2.5)^{3}[/tex]         *Cube 2.5*

[tex]\frac{\frac{4}{3}(3.14)(15.625)}{2}[/tex]         *Divide by 2 and Solve*

≈ [tex]32.7083 in^{3}[/tex]

Add both volumes

[tex]137.375 + 32.7083[/tex] ≈ [tex]170.083in^{3}[/tex]

2.

Cylinder:

[tex]V = \pi r^{2}h[/tex]         *Plug in numbers*

[tex]\pi (3)^{2}(10)[/tex]            *Square 3*

[tex]\pi (9)(10)[/tex]             *Multiply*

[tex]90\pi[/tex]

Sphere:

[tex]V = \frac{4}{3}[/tex] π [tex]r^{3}[/tex]            *Plug in numbers*

[tex]\frac{4}{3}\pi (3)^{3}[/tex]                   *Cube 3*

[tex]\frac{4}{3} \pi (27)[/tex]                   *Multiply*

[tex]36\pi[/tex]

Add both Volumes to get total

[tex]90\pi + 36\pi = 126in^{3}[/tex]

3.

Sphere:

[tex]V = \frac{4}{3}\pi r^{3}[/tex]              *Plug in numbers*

[tex]\frac{4}{3} (3.14)(3)^{3}[/tex]            *Cube 3*

[tex]\frac{4}{3} (3.14)(27)[/tex]            *Multiply*

[tex]113.04m^{3}[/tex]

Cone:

[tex]V = \frac{\pi r^{2}h}{3}[/tex]             *Plug in numbers*

[tex]\frac{(3.14)(2)^{2}(5)}{3}[/tex]           *Square 2*

[tex]\frac{(3.14)(4)(5)}{3}[/tex]             *Solve*

[tex]20.93m^{3}[/tex]

Subtract the volumes to get the volume of the blue area

[tex]113.04 - 20.93 = 92.106m^{3}[/tex]

4.

Sphere:

[tex]V = \frac{4}{3} \pi r^{3}[/tex]            *Plug in numbers*

[tex]\frac{4}{3}\pi (8)^{3}[/tex]                 *Cube 8*

[tex]\\\frac{4}{3}\pi (512)[/tex]               *Multiply*

[tex]\\\\\pi (682.6)[/tex]              *Solve*

[tex]2133.66in^{3}[/tex]           *Divide by 2 since it's a hemisphere*

Cone:

[tex]V = \frac{\pi r^{2}h}{3}[/tex]            *Plug in numbers*

[tex]\frac{\pi (8)^{2}(20)}{3}[/tex]              *Square 8*

[tex]\frac{\pi (64)(20)}{3}[/tex]              *Multiply and Divide*

[tex]1340.41 in^{3}[/tex]

Add both volumes

[tex]1072.33 + 1340.41 = 2412.74in^{3}[/tex]

5.

Cylinder:

[tex]V = \pi r^{2}h[/tex]            *Plug in numbers*

[tex]\pi (6)^{2}(16)[/tex]              *Square 6*

[tex]\pi (36)(16)[/tex]             *Multiply*

[tex]576\pi[/tex]

Cone:

[tex]V = \frac{\pi r^{2}h}{3}[/tex]            *Plug in numbers*

[tex]\frac{\pi (6)^{2}3}{3}[/tex]                  *Square 6*

[tex]36\pi[/tex]

Add both volumes

[tex]576\pi + 36\pi = 612\pi m^{3}[/tex]

Alternative: *Multiply π*

[tex]1922m^{3}[/tex]

Answer:

1) 175 [tex]in^2[/tex]

2) 1st option

3) 92 [tex]m^2[/tex]

4) 2412 [tex]in^3\\[/tex]

5) 2nd option

Step-by-step explanation:

[tex]1)\ A = D * Pi = 5 * 3.14 = 15.7\\[/tex]

[tex]2)\ V_{1} = 15.7 * 7 = 109.9[/tex]

[tex]3)\ V_{2} = 4Pi*\frac{R^3}{3} = 12.56*\frac{15.625}{3} = 65.41(6)[/tex]

[tex]4)\ V_1 + V_2 = 65.4 + 109.9 = 175.3[/tex] which is close to 175

[tex]1)\ A = Pi * R^2 = 3.14 * (\frac{6}{2})^2 = 3.14 * 3^2 = 28.26\\[/tex]

[tex]2)\ V_1 = A * h = 28.26 * 10 = 282.6[/tex]

[tex]3)\ V_2 = \frac{4}{3} * Pi * R^3 = \frac{4}{3} * 3.14 * (\frac{6}{2})^3 = 113.04[/tex]

[tex]4)\ V_1 + V_2 = 282.6 + 113 = 395.6[/tex] which is very close to 396

[tex]5)\ 396 = 126 * pi[/tex]

[tex]1) V_1 = \frac{1}{3} * Pi * R^2 * h = \frac{1}{3} * 3.14 * 2^2 * 5 = 20.9(3)[/tex] =

[tex]2)\ V_2 = \frac{4}{3} * Pi * R^3 = \frac{4}{3} * 3.14 * 3^3 = 113.04\\[/tex]

[tex]3)\ V_2 - V_1 = 113.04 - 20.93 = 92.14[/tex] which is very close to 92

[tex]1)\ V_1 = \frac{\frac{4}{3} * Pi * R^3}{2} = \frac{\frac{4}{3} * 3.14 * 512}{2} = 1,071.786\\[/tex]

[tex]2)\ V_2 = \frac{1}{3} * Pi * R^2 * h = \frac{1}{3} * 3.14 * 64 * 20 = 1,339.733[/tex]

[tex]3)\ V_1 + V_2 = 1072 + 1340 = 2,411 = 2412[/tex]

[tex]1)\ A = Pi * R^2 = 36*Pi\\[/tex]

[tex]2)\ V_1 = 36*Pi * 16 = 576 * Pi\\[/tex]

[tex]3)\ V_2 = \frac{1}{3} * Pi * R^2 * h = \frac{1}{3} * Pi * 36 * 3 = 36 * Pi[/tex]

[tex]4) V_1 + V_2 = 576Pi + 36Pi = 612Pi[/tex]

Solve for x: 3(x + 1) = 2(x − 1)

Answers

Answer:

x= -5

Step-by-step explanation:

3x+3=2x-2

3x-2x=-3-2

x=-5

Answer:

x = -5

Step-by-step explanation:

First Expand the equation

3x+3 = 2x-2

Subtract 2x from both sides

x+3=-2

subtract 3 from both sides

x = -5

Hope this helps :)

Can someone help me with this?

Answers

Answer:11 weekends

Step-by-step explanation:

it will take 11 weekends


A cube of total area 150 cm?, then the length of its edge

Answers

Each edge is 5 cm
A cube has 6 sides.
Divide 150 by 6 and get 25, that’s area of each side
Get square root and that’s 5

Use the diagram to help you solve the equation 4x-12=16 how to do it

Answers

32 because if you -32+16 it would be 16

[tex]h + 54 = 4 {}^{2} - 16 \div 4[/tex]

Value of h = ???​

Answers

Answer:

[tex]h = -42[/tex]

Step-by-step explanation:

First, subtract 54 from both sides.

[tex]h = 4^2 - 16 \div 4 - 54[/tex]

Then, evaluate the right-hand expression using the order of operations:

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

We'll first evaluate the exponent in 4²:

[tex]4^2 = 4 \times 4 = 16[/tex]

[tex]h = 16 - 16 \div 4 - 54[/tex]

Next, we can evaluate the division:

[tex]16 \div 4 = 4[/tex]

[tex]h = 16 - 4 - 54[/tex]

Finally, perform the subtraction.

[tex]16 - 4 - 54 = -42[/tex]

[tex]h = -42[/tex]

Answer:

[tex] \sf \: h = - 42[/tex]

Step-by-step explanation:

Given equation,

→ h + 54 = 4² - 16 ÷ 4

Now the value of h will be,

→ h + 54 = 4² - 16 ÷ 4

→ h + 54 = 16 - 4

→ h + 54 = 12

→ h = 12 - 54

→ [ h = -42 ]

Hence, value of h is -42.

Can I get help in number 6?

Answers

Answer:

Trim A

Inches = 36

Feet = 3

Yards = 1

Trim B

Inches = 216

Feet = 18

Yards = 6

which answer is this
A.43
B.38
C.61
D.81

Answers

it is 61 the angles should add up to 180
C.61

A triangle always has 180 degrees total so 81+38 = 119 and 180 - 119 = 61z

find the value of X pls help!!

Answers

Answer:

B

Step-by-step explanation:

the sum of the two angles is 180

30 + 15x = 180

15x =150

x = 10 degrees

How many incas did the spanish kill on november 16 1532 o 100 o 600 o 1000 6000?

Answers

Spanish killed nearly 6000 Incas.

The Spanish conquistador and explorer Francisco Pizarro springs a trap on Atahualpa, the monarch of the Incas, in the year 1532. Atahualpa allowed roughly 6,000 unarmed men to attend the feast despite having almost 80,000 soldiers with him in the mountains. It took the Spanish a long time and much violence to conquer the Inca Empire. Pizarro's soldiers massacred the 6,000 Incans in approximately one hour.

The lone Spanish wounded were received by Pizarro himself, who injured his hand while saving Atahualpa's life. Pizarro retained Atahualpa in captivity while he prepared plans to conquer his empire because he understood that the emperor was worthy alive than dead. Atahualpa responded by appealing to his hostages' avarice and supplying them with money and silver in exchange for their release.

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What is the area of the figure, pls hurry 100 points

Answers

Answer:

25 1/6 square yards

Step-by-step explanation:

I am assuming you mean the area of the shaded figure.

So, let's do it this way.

Let's subtract the total area from the unshaded area:

7 1/4 x 6 = 43 1/2

Area of non-shaded = 18 1/3

Area of shaded = 43 1/2 - 18 1/3 = 25 1/6

Hope that helps! :)

-Aphrodite

ILL BRAINLIEST YOU PLEASE HELP ME

Answers

Answer:

B

Step-by-step explanation:

Theorem: If a quadrilateral has 2 sets of opposite sides congruent, 2 sets of opposite angles congruent, and has consecutive angles which are supplementary, then it is a parallelogram.

Hope this helps!

Each side of a square office is 8 yards long. It will cost $65.00 per square yard to replace the carpet in the office. What would be the total cost replace the carpet?

Answers

Answer:

520 because 65 x 8 is 520

Step-by-step explanation:

Hundredths

2347

whole hundredths

:) How many tenths are in 2,347? How many whole tenths

tenths

whole tenths

D) How many tenths are in 234. 7? How many whole tenths

Answers

C) The whole hundredths of 2347 is 234700 hundredths.  Zero-tenths are in 2,347. The whole tenth of 2347 is 2470tenth.

D) The tenth in 234. 7 are 7. The whole tenth of 234. 7 is 2347.

What is the tenth?

The tenth place is represented by the first digit following the decimal. The hundredth place is represented by the digit that follows the decimal.

Given number is 2347.

To find the whole hundredth, multiply the number by 100.

The whole hundredth in 2347 is 2347 × 100 = 234700.

The given number can be written as 2347.0.

Thus tenth of 2347 is 0.

To find the whole tenth, multiply the number by 10.

The whole tenth in 2347 is 2347 × 10 = 23470.

Thousand     Hundred       Ten      decimal point     Tenth

     2                      3              4                   .                    7

The tenth of in 234. 7 is 7.

The whole tenth in 234. 7 is 234.7 × 10 = 2347.

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Use the quadratic formula to find the exact solutions of x2 − 5x − 2 = 0.

Answers

Answer:

Solutions given:

given equation is

x²-5x-2=0

comparing above equation with ax²+bx+c,we get

a=1

b=-5

c=-2

By using quadratic equation

x=[tex] \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} [/tex]

x=[tex] \frac{ 5± \sqrt{ {-5}^{2} - 4*1*-2}}{2*1} [/tex]

x=[tex] \frac{ 5± \sqrt{ 25+8}}{2*1} [/tex]

x=[tex] \frac{ 5± \sqrt{ 33 }}{2} [/tex] is a required answer.

Answer:

[tex]x=\dfrac{5 \pm \sqrt{33}}{2}[/tex]

Step-by-step explanation:

Quadratic Formula

[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0[/tex]

Given equation:

[tex]x^2-5x-2=0[/tex]

Comparing the given equation with [tex]ax^2+bx+c=0[/tex] to find the values of a, b and c:

a = 1b = -5c = -2

Substitute these values into the quadratic formula and solve for x:

[tex]\implies x=\dfrac{-(-5) \pm \sqrt{(-5)^2-4(1)(-2)}}{2(1)}[/tex]

[tex]\implies x=\dfrac{5 \pm \sqrt{25+8}}{2}[/tex]

[tex]\implies x=\dfrac{5 \pm \sqrt{33}}{2}[/tex]

Don’t judge :|
help pls:p

Answers

Answer:

5x−4y

Step-by-step explanation:

:D

Answer: 5x - 4y

Step-by-step explanation: combining like terms means to combine the terms that have the same letter. so since the 3 and 2 have an x you combine them and the 3 and -7 have a y you combine them. hope this helped:)

find the y intercept of y=4x-2

Answers

Answer:

y intercept:  -2

Step-by-step explanation:

hope this helps :)

Answer:

Slope=4 and the intercept on the y-axis is -2

Step-by-step explanation:

Use the formula y=mx+c

m=slope

c is the intercept on the y-axis

y=4x-2 can be like this

Y=4x+(-2)

That is why slope is 4 and intercept on y-axis is -2

:)

16 POINTS! NO LINKS! SHOW ALL WORK!
given the function f(x)=3x-1, what is f(3)
a)5
b)32
c)9
d)8
-------------------------------
evaluate f(x) = x^2 - 3x + 2 given f (x+1)
a) x^2 - x
b) 3x^2 - 4
c) x^2 + x - 3
d) 2x^2 + x - 2

Answers

Answer:

d

a

Step-by-step explanation:

f(3)= 3(3)-1

f(3)=9-1=8

f(x+1)= (x+1)^2-3(x+1)+2

=x^2+2x+1-3x-3+2

=x^2-x


4. Nicole uses 2.5 meters of ribbon to decorate
door wreaths. There are 20 meters of ribbon on a
spool. Write an equation that could be used to
determine the number of wreaths that Nicole
could decorate using one spool of ribbon. Solve.
Equation:

Answers

An equation that could be used to determine the number of wreaths that Nicole could decorate using one spool of ribbon is:

                           W = S / R

Define Equation.

The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions. For instance, the equation 3x + 5 = 14 consists of the two equations 3x + 5 and 14, which are separated by the 'equal' sign.

Define Algebraic expression.

An algebraic expression in mathematics is an expression created using variables, constant algebraic numbers, and algebraic operations. A good example of an algebraic expression is 3x2 2xy + c.

An equation that could be used to determine the number of wreaths that Nicole could decorate using one spool of ribbon is:

W = S / R

where W is the number of wreaths, S is the total length of ribbon on the spool, and R is the length of ribbon used per wreath.

Plugging in the given values, we get:

W = 20 / 2.5

Solving for W, we get:

W = 8

So Nicole could decorate 8 wreaths using one spool of ribbon.

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Carl deposited $1220 in a bank that pays 9% interest, compounded monthly. Find the amount he will have at the end of 3 years.
a.
$3431.45
c.
$1549.40
b.
$1596.55
d.
$1334.44

Answers

The amount he will have at the end of 3 years is $1596.55.

Option B is the correct answer.

What is compound interest?

It is the interest we earned on the interest.

The formula for the amount earned with compound interest after n years is given as:

A = P [tex](1 + r/n)^{nt}[/tex]

P = principal

R = rate

t = time in years

n = number of times compounded in a year.

We have,

P = $1220

r = 9%

n = 12

t = 3 years

Amount = P [tex](1 + r/n)^{nt}[/tex]

A = 1220 [tex](1 + 9/12)^{36}[/tex]

A = 1220 [tex](1 + 0.75)^{36}[/tex]

A = 1220 x [tex]1.75^{36}[/tex]

A = $1,596.55

Thus,

The amount after 3 years is $1596.55.

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A principal of $1800 is invested at 8.5% interest, compounded annually. How much will the investment be worth after 11 years?

Answers

calc= 1800 times (0.085 ^11)

The diagram shows two rectangles.



The combined area of both rectangles is

By considering the areas of the two rectangles, find an equation in the form that satisfies .

Answers

We know that :

⊕   Area of a Rectangle is given by : Length × Width

Let us calculate the Area of the Rectangle in the Left side of the figure

⇒   Area of Left Rectangle : (x - 3) (x + 2x)

⇒   Area of Left Rectangle : (x - 3) (3x)

⇒   Area of Left Rectangle : 3x² - 9x

Let us calculate the Area of the Rectangle in the right side of the figure

⇒   Area of the Right Rectangle : (x - 1)(x)

⇒   Area of the Right Rectangle : x² - x

Given : Combined area of both rectangles is 50 cm²

⇒   3x² - 9x + x² - x = 50

⇒   4x² - 10x = 50

⇒   2x² - 5x - 25 = 0

Comparing the above equation with ax² + bx + c = 0,

we can notice that :

→   a = 2

→   b = -5

→   c = -25

SinA + cosA = √2, prove that tanA + cotA = 2

Answers

[tex]sin(A)+cos(A)=\sqrt{2}\hspace{10em}tan(A)+cot(A)=2 \\\\[-0.35em] ~\dotfill\\\\ tan(A)+cot(A)=2\implies \cfrac{sin(A)}{cos(A)}+\cfrac{cos(A)}{sin(A)}=2 \\\\\\ \cfrac{sin^2(A)+cos^2(A)}{cos(A)sin(A)}=2\implies \boxed{\cfrac{1}{cos(A)sin(A)}=2} \\\\[-0.35em] ~\dotfill[/tex]

[tex]sin(A)+cos(A)=\sqrt{2}\implies (~~sin(A)+cos(A)~~)^2=(\sqrt{2})^2 \\\\\\ sin^2(A)+2sin(A)cos(A)+cos^2(A)=2 \\\\\\ 2sin(A)cos(A)+sin^2(A)+cos^2(A)=2\implies 2sin(A)+1=2 \\\\\\ 2sin(A)cos(A)=1\implies \boxed{2=\cfrac{1}{cos(A)sin(A)}}[/tex]

now, another way to look at this identity will  be as a unified system of equations

[tex]\begin{cases} (~~sin(A)+cos(A)~~)^2=2\\\\ ~~ ~tan(A)+cot(A)=2 \end{cases}\implies (~~sin(A)+cos(A)~~)^2=tan(A)+cot(A)[/tex]

and we'd end up with the same rigamarole.

a+ 1 1/6 = 11 7/9
...........................

Answers

Answer:

a = 191/81

Step-by-step explanation:

a+ 1 1/6 = 11 7/9

1 1/6 = 7/6

11 7/9 = 106/9

So, our equation is

a + 7/6 = 106/9

Subtract 7/6 from both sides

a = 191/81

So, the answer is

a = 191/81

=D I have been stuck on this omg

Answers

Answer:

rectangular prism maybe

Step-by-step explanation:

Suppose you invest $2000 at an annual interest rate of 8.2% compounded continuously. How much will you have in the account after 10 years

Answers

Answer:

$3,640

Step-by-step explanation:

8.2% as a decimal is 0.082. multiply 2000 by 0.082, and you get your interest rate/the interest you pay each year, which would be 162. multiply 162 by ten to get your interest for all ten years, since 162 was simply the rate, and you get 1,640. add the original 2000 onto that, and you get 3,640.

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