please help solveeeeee

Answer:

Option A, [tex]x =[/tex] ± [tex]7.75[/tex]

Step-by-step explanation:

Step 1:  Add 60 to both sides

[tex]x^2 - 60 = 0[/tex]

[tex]x^2 - 60 + 60 = 0 + 60[/tex]

[tex]x^2 = 60[/tex]

Step 2:  Square root both sides

[tex]\sqrt{x^2} = \sqrt{60}[/tex]

[tex]x =[/tex] ± [tex]7.75[/tex]

Answer:  Option A, [tex]x =[/tex] ± [tex]7.75[/tex]

Answer:

The length for the edge should be 6.

Step-by-step explanation:

Hope this helps

Answer:

79500.00

Step-by-step explanation:

75000(1 + .06) = 79500

Answer:

7

Step-by-step explanation:

first you input the -1 into all the spots where the xs are so the new equation would be f(-1)=4(-1)(-1) +5(-1)+8

then when you simplify its 4-5+8

which is equal to 7

Answer:

20

Step-by-step explanation:

To find the area, separate the unique shape into 3 rectangles. Then, solve for the area of those three rectangles:

2 x 4 = 8
2 x 3 = 6
6 x 1 = 6

Then, add up all of those areas to find the total area of the unique shape:

8 + 6 + 6 = 20

The area of the unique shape is 20.

The number of apples there are in the basket as described in the task content is; 20 apples.

Inference drawn from the task content show that;

On this note, we must identify a number divisible by 9 between 30 and 40.

The number is 36 and once divided by 9 is 4 units per partition.

On this note, the total number of apples in the basket is; 4 × 5 = 20 apples.

Read more on ratios;

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Step-by-step explanation:

Vertex form is: [tex]a(x-h)^2+k[/tex]

a) [tex]a(x+2)^2+3=y[/tex]

To find a, plug (-4,1) in for x and y.

[tex]a(-4+2)^2+3=1[/tex]

[tex]4a=-2[/tex]

[tex]a=-1/2[/tex]

so a) is [tex]\frac{-1}{2} (x+2)^2+3[/tex]

b) .... I'm not sure what the second coordinate is.

c) [tex]a(x+2)^2-3[/tex]

Plug in (-5,6) for x and y.

[tex]6=a(-5+2)^2-3[/tex]

[tex]9=9a[/tex]

[tex]a=1[/tex]

so c) is [tex](x+2)^2-3[/tex]

d) [tex]a(x+2)^2+5[/tex]

Plug (1,-4) in for x and y.

[tex]-4=a(1+2)^2+5[/tex]

[tex]-9=9a[/tex]

[tex]a=-1[/tex]

so d) is [tex]-(x+2)^2+5[/tex]

Answer:

[tex]\textsf{(a)}\quad y=-\dfrac{1}{2}(x+2)^2+3[/tex]

[tex]\textsf{(b)}\quad y=a(x+1)^2-1[/tex]

[tex]\textsf{(c)}\quad y=(x+2)^2-3[/tex]

[tex]\textsf{(d)}\quad y=-(x+2)^2+5[/tex]

Step-by-step explanation:

Vertex form

[tex]y=a(x-h)^2+k[/tex]

where (h, k) is the vertex

-------------------------------------------------------------------------------------------

Part (a)

Given:  vertex at (-2, 3) passes through (-4 ,1)

Substituting the given vertex into the equation:

[tex]\implies y=a(x-(-2))^2+3[/tex]

[tex]\implies y=a(x+2)^2+3[/tex]

Substitute the given point into the equation to find a:

[tex]\implies 1=a(-4+2)^2+3[/tex]

[tex]\implies 1=4a+3[/tex]

[tex]\implies a=-\dfrac{1}{2}[/tex]

Substitute the found value of a to form the final equation:

[tex]y=-\dfrac{1}{2}(x+2)^2+3[/tex]

-------------------------------------------------------------------------------------------

Part (b)

Given:  vertex at (-1, -1) passes through ?)

Substituting the given vertex into the equation:

[tex]\implies y=a(x-(-1))^2+(-1)[/tex]

[tex]\implies y=a(x+1)^2-1[/tex]

Substitute the given point into the equation to find a:

**no point given**

-------------------------------------------------------------------------------------------

Part (c)

Given:  vertex at (-2, -3) passes through (-5, 6)

Substituting the given vertex into the equation:

[tex]\implies y=a(x-(-2))^2+(-3)[/tex]

[tex]\implies y=a(x+2)^2-3[/tex]

Substitute the given point into the equation to find a:

[tex]\implies 6=a(-5+2)^2-3[/tex]

[tex]\implies 6=9a-3[/tex]

[tex]\implies a=1[/tex]

Substitute the given point into the equation to find a:

[tex]y=(x+2)^2-3[/tex]

-------------------------------------------------------------------------------------------

Part (d)

Given:  vertex at (-2, 5) passes through (1, -4)

Substituting the given vertex into the equation:

[tex]\implies y=a(x-(-2))^2+5[/tex]

[tex]\implies y=a(x+2)^2+5[/tex]

Substitute the given point into the equation to find a:

[tex]\implies -4=a(1+2)^2+5[/tex]

[tex]\implies -4=9a+5[/tex]

[tex]\implies a=-1[/tex]

Substitute the given point into the equation to find a:

[tex]y=-(x+2)^2+5[/tex]

Answer:

perimeter=4×length

so 72= 4l

divide through by 4

length=18

Answer:

Step-by-step explanation:

Perimeter

Area

From the perimeter

Substituting in the area formula

The greater value of the two will be the length, and lesser value will be the width.

Dimensions are : 24 inches x 12 inches

Answer:

0.1

Step-by-step explanation:

1 is in the tenths place and 2 is in the hundredths place

Since the digit in the hundredths place (2) is less than 5, the digit in the tenths place (1) does not change

The digit in the hundredths place is dropped

0.12 rounded to the nearest tenth (one decimal place) = 0.1

Answer:

  N(t) = -192t² +240t +48

Step-by-step explanation:

The composition of functions will be created by using the height function as the argument of the units conversion function.

__

  N(f) = N(h(t)) = 12(-16t² +20t +4) . . . replace f with h(t)

  N(t) = -192t² +240t +48 . . . . . simplify

A ratio shows us the number of times a number contains another number. The cost of cheese that is needed to make 6000g of potato cake is £12.86.

A ratio shows us the number of times a number contains another number.

Given that the ratio of the ingredients is,

weight of potato: weight of cheese: weight of onion = 9: 2:1

Let the ingredients be mixed in the quantity 9x, 2x, and 1x, for 6000g of potato cake. Therefore, the value of x can be written as,

[tex]9x+2x+1x = 6000\\\\12x = 6000\\\\x = 500[/tex]

Hence, the value of x is 500.

Thus, the amount of cheese that will be needed is 2x,

[tex]2x = 2 \times (500) = 1000g[/tex]

Given that the cost of 175g of cheese is  £2.25, therefore, the cost of 1g of cheese will be,

[tex]\text{Cost of 1g cheese} = \£\dfrac{ 2.25}{175}[/tex]

Now, the cost of 1000g of cheese will be,

[tex]\text{Cost of 1000g cheese} = 1000\times \£\dfrac{ 2.25}{175} = \£12.86[/tex]

Hence, the cost of cheese that is needed to make 6000g of potato cake is £12.86.

Learn more about Ratios:

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Answer:

Elon Musk 269.7 B
Jeff Bezos: 170.15 B
Bill Gates: 130.23 B

Step-by-step explanation:

If you had a trail of 1 billion 1 dollar bills, it would stretch out to 96,900 miles.

If you did that with 100 billion 1 dollar bills, that would be 9,690,000 miles.

That is more than 300 times the circumference of the Earth.

The field of view for an owl is about 110 degrees, with about 70 degrees being binocular vision. By comparison, humans have a field of view that covers 180 degrees, with 140 degrees being binocular. A woodcock has an amazing 360 degree field of view, because its eyes are on the side of its head.

Answer:

An airline claims that the no-show rate for passengers is less than 5%. In a sample of 420 randomly selected reservations, 19 were no-shows. At α=0.01, test the airline's claim. State the sample percentage and round it to three decimal places.

State the hypotheses.

State the critical value(s).

State the test statistics.

State the decision

State the conclusion.

Answer:

121/16

Step-by-step explanation:

Here given that

So

Every person has one and only mouth

Means

So

Answer:

0.75.

Step-by-step explanation:

1) the required vertical distance is the distance between two vertexes.

2) according to the item 1, the coordinates of the vertexes are:

(y=x²+1): x₀=0; y₀=1;

(y=x-x²): x₀=0.5; y₀=0.25;

3) according to the item 2, the distance between 1 and 0.25 is 0.75.

Answer:

[tex]5 {6y6494y5y5yx \sqrt[454x54 {149 { \\ \\ }^{ \\ } }^{2} ]{?} }^{?} [/tex]

Because the sum of the internal angles must be equal to 180°, we will see that x =  43.75

Here we need to remember that the sum of the internal angles of a triangle always gives 180°, so we can write:

(x + 10)° + (3x - 5°) + x°  = 180°

Now we need to solve this linear equation for x.

4x + 5= 180

4x = 180 - 5 = 175

x = 175/4 = 43.75

The value of x is 43.75

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Answer:

what's the question? we need to know in order to help

To find the density:

 ⇒ must find the relationship between the density, mass, and volume

    ⇒ [tex]Density = \frac{mass}{volume}[/tex]

Let's examine the information given:

Let's first find the volume:

   ⇒ the volume is the dimensions multiplied together

      [tex]Volume = 8cm * 5cm * 5cm = 200cm^3[/tex]

LEt's calculate the density now:

  [tex]Density = \frac{1890g}{200cm^3} =9.45g/cm^3[/tex]

Answer: The density of the copper is 9.45g/cm^3 or Choice (A)

Hope that helps!

Answer:

84x

Step-by-step explanation:

Answer:

y=2x+9

Step-by-step explanation:

point slope form

y-y1=m(x-x1)

y-3=2(x+7)

m=2

y intercept: b=9

y=mx+b where m=2 b=9

y=2x+9

Answer:

a , c and d

Step-by-step explanation:

a , c and d are correct

Answer:

1.5x - 32

Step-by-step explanation:

friday = x

0.5x = monday

and

x-32 = friday

in total

1.5x-32

Answer:

[tex]\implies \dfrac{80}{90}-\sqrt{50} \times 19^2 \div 23^2[/tex]

Order of operations (PEDMAS)

Following the order of operations,
Carry out the exponents (and radicals) first:

[tex]\implies \dfrac{80}{90}-\sqrt{25 \cdot 2} \times 361 \div 529[/tex]

[tex]\implies \dfrac{80}{90}-5\sqrt{2} \times 361 \div 529[/tex]

Now the multiplication and division (from left to right):

[tex]\implies \dfrac{8}{9}-1805\sqrt{2} \div 529[/tex]

[tex]\implies \dfrac{8}{9}-\dfrac{1805\sqrt{2}}{529}[/tex]

Convert the fractions so that their denominators are the same:

[tex]\implies \dfrac{8 \times 529}{9 \times 529}-\dfrac{1805\sqrt{2} \times 9}{529 \times9}[/tex]

[tex]\implies \dfrac{4232}{4761}-\dfrac{16245\sqrt{2}}{4761}[/tex]

Answer as a fraction:

[tex]\implies \dfrac{4232-16245\sqrt{2}}{4761}[/tex]

Answer as a number:

[tex]\implies -3.936546801... = -3.9\: \textsf{(nearest tenth)}[/tex]

Answer:

Second option

Step-by-step explanation:

convert  [tex]1\frac{1}{2}[/tex]  to improper fraction:

[tex]1\frac{1}{2} =\frac{2(1)+1}{2} =\frac{3}{2}[/tex]

The second opcion:

[tex]V = (2)(2)(\frac{3}{2} )=\frac{12}{2} =6[/tex]

Hope this helps

Multiply assets by ratio

200,000 x 0.29 = $58,000

answer: c. $58,000