PLEASE HELP TIMED!
1. By the end of the 2nd trimester, the baby's skeleton is:
A. Hard
B. Soft
C. Just beginning to form
D. None of the above

2. When is the baby called an embryo
A. 7-9 months
B. 4-6 months
C. 1-7 days
D. 10 days to 8 weeks

3. Which of the following stages is a blastula/ blastocyst?
A. 0-4 days
B. 9-40 weeks
C. 7-9 days
D. 5-7 days

3. Which of the following stages is a morula?
A. 0-4 days
B. 9-40 weeks
C. 7-9 days
D. 5-7 days

4. When does the placenta begin to form?
A. 10-15 days
B. 9-40 weeks
C. 7-9 days
D. 5-7 days

Answers

Answer 1

Answer:

B. Soft

D. 10 days to 8 weeks

C. 7-9 days

D.5-7

A. 10-15

Explanation:


Related Questions

The animals known as a mountain lion, panther, puma, and cougar are actually the same animal, puma concolor. because of their large range, the animal has acquired different names around the globe. scientists most likely determined that these organisms are the same species by comparing and noting the similarities between the

Answers

Mountain lions, panthers, pumas, and cougars are all names for the same species: Puma concolor. Scientists have been able to determine that these animals are the same species by comparing and noting the similarities between them.

For example, all of these animals have a tawny coloration and a characteristic black tip on their tails, as well as similar physical features, such as a muscular body, long tail, and a round head. Additionally, they all inhabit similar geographic ranges and share the same dietary habits.

Furthermore, the genetic data collected from these animals has revealed that they are all closely related and possess the same DNA structure. This data has allowed scientists to correctly classify this species and finally settle the debate of whether these animals are one and the same.

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complete question is :

The animals known as a mountain lion, panther, puma, and cougar are actually the same animal, puma concolor. because of their large range, the animal has acquired different names around the globe. scientists most likely determined that these organisms are the same species by comparing and noting the similarities between them. explain.

Select all that apply for the following alternative pathway: C4 plants.



Multiple select question.



A)


mostly everywhere



B)


very hot, dry habitats



C)


sunny, tropical habitats



D)


occurs in sugarcane and corn



E)


occurs in cacti, jade plants, and pineapple



F)


fixes carbon dioxide into three-carbon molecules



G)


fixes carbon dioxide into four-carbon molecules



H)


fixes carbon dioxide into organic molecules at night



I)


allows for regular carbon dioxide uptake and water loss



J)


allows for sufficient carbon dioxide uptake and minimizes water loss

Answers

The alternative pathway in C4 plants involves several important characteristics that allow for efficient photosynthesis in arid environments. The correct option are B) very hot, dry habitats, C) sunny, tropical habitats , D) occurs in sugarcane and corn. G) fixes carbon dioxide into four-carbon molecules H) fixes carbon dioxide into organic molecules at night and J) allows for sufficient carbon dioxide uptake and minimizes water loss.

First, C4 plants are commonly found in plants such as cacti, jade plants, and pineapples that are adapted to dry conditions. Secondly, the pathway involves fixing carbon dioxide into organic molecules at night, which is known as crassulacean acid metabolism (CAM). This allows for plants to minimize water loss during the day by keeping their stomata closed and still be able to fix carbon dioxide for photosynthesis.

The alternative pathway in C4 plants also allows for sufficient carbon dioxide uptake. This is due to the presence of specialized mesophyll cells that have high levels of the enzyme PEP carboxylase, which can capture carbon dioxide even when levels are low. The captured carbon dioxide is then transported to the bundle sheath cells, where it is further processed through the Calvin cycle. This process allows for efficient use of carbon dioxide and minimal water loss through transpiration.

Overall, the alternative pathway in C4 plants is an important adaptation that allows for efficient photosynthesis in arid environments. It involves several important characteristics, including fixing carbon dioxide into organic molecules at night, specialized mesophyll cells, and efficient use of carbon dioxide. These adaptations help plants to survive and thrive in harsh, dry environments.

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Luther Burbank bred potatoes that combined a variety of useful traits. One of Burbank's breeding techniques was hybridization. Which cross of


potato plants would have been MOST USEFUL for producing a useful strain by hybridization?


O A a disease-resistant plant crossed with a plant that is not disease resistant


O B. A plant that is not disease resistant crossed with a plant that produces a low volume of food


O c. A disease-resistant plant crossed with a plant that produced a low volume of food


O D. A disease-resistant plant crossed with a plant that produced a high volume of food

Answers

The most useful cross of potato plants for producing a useful strain by hybridization would be a disease-resistant plant crossed with a plant that produced a high volume of food.

Here, correct option is D.

Luther Burbank, a renowned plant breeder, developed this hybridization technique to combine a variety of useful traits in the plants he bred. By crossing a disease-resistant plant with one that produced a high volume of food, Burbank was able to create a plant that provided both disease resistance and high yield potential.

This combination of traits was invaluable for increasing the food production of potatoes and making them more accessible and affordable for people around the world. With this hybridization technique, Luther Burbank was able to improve the quality and yield of potato production, making potatoes an important part of the global food system.

Therefore, correct option is D.

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How do the chromosomes at the end of meiosis i compare with the chromosomes at the end of meiosis ii?

Answers

At the end of meiosis I, each chromosome still consists of two sister chromatids, but the number of chromosomes is reduced by half.

This reduction is due to the separation of homologous chromosomes, which are pulled to opposite poles of the cell during the first division. At the end of meiosis II, the sister chromatids finally separate, resulting in four haploid daughter cells, each containing a single chromosome. So, at the end of meiosis II, the chromosomes are in their haploid form, with only one chromatid per chromosome. In summary, the chromosomes at the end of Meiosis I are still composed of sister chromatids, while the chromosomes at the end of Meiosis II are single chromatids in each of the four haploid cells.

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What prevents backwards flow of urine from the bladder into the ureters?.

Answers

The ureters enter the bladder obliquely and are surrounded by a muscular valve called the ureterovesical junction, which prevents the backwards flow of urine from the bladder into the ureters.

The ureters are muscular tubes that carry urine from the kidneys to the bladder. They enter the bladder obliquely, meaning that they do not enter the bladder at a right angle but at an angle that causes the ureter to be compressed when the bladder fills with urine.

Additionally, the ureterovesical junction, or the point at which the ureter meets the bladder, is surrounded by a muscular valve that contracts to prevent urine from flowing backwards into the ureters.

This valve, called the vesicoureteral valve, is made up of smooth muscle and is under autonomic control, meaning that it is regulated by the nervous system. The combination of the oblique angle of the ureter and the muscular valve at the ureterovesical junction helps to ensure that urine flows in one direction, from the kidneys to the bladder, and does not flow backwards into the ureters.

However, in some cases, such as with vesicoureteral reflux, the valve may not function properly, leading to the backwards flow of urine and potentially causing urinary tract infections and other complications.

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63 Identify the bird represented by the foot labeled W.

64 Explain how the webbing between the toes of bird Y could help a coastal bird survive. ​

Answers

Answer: The webbed toes on a coastal bird could help the bird if it needed to swim to find food or fall in the water since it is you know COASTAL Hope it helps:)

Explanation:

Your colleague designed a common garden experiment to determine if desiccation (drying out) influences competition between a native alga and an exotic alga. The design includes four plot types: dry with native only, dry with exotic only, dry with both algae, and wet with both algae.



When grown together on dry plots, the native grew well while the exotic went extinct. When grown together on wet plots, the exotic grew well while the native went extinct. Both algae grew in dry plots when grown alone. You note that his experimental design is incomplete and, as a result, he cannot support one of the following conclusions. Which conclusion is NOT supported?



a. Dry habitats are part of the fundamental niche of the native alga.


b. Dry habitats are part of the fundamental niche of the exotic alga.


c. The native alga competitively excludes the exotic alga in dry habitats.


d. The exotic alga competitively excludes the native alga in wet habitats

Answers

These findings have crucial implications for understanding the effects of desiccation on competition among algae species. The correct option is d. The exotic alga competitively excludes the native alga in wet habitats

Based on the design of the experiment, it appears that your colleague is interested in understanding how desiccation, or drying out, affects competition between a native alga and an exotic alga. The experiment includes four different plot types, each with different combinations of the two types of algae and varying levels of moisture. Specifically, dry habitats are part of the fundamental niche of the exotic alga, meaning that this species is adapted to thrive in dry conditions.

Interestingly, the results of the experiment suggest that the exotic alga is actually better able to compete with the native alga in wet habitats, where both species are present. This means that in these conditions, the exotic alga is able to outcompete the native species and establish dominance.

Overall, these findings have important implications for understanding the impact of desiccation on competition between different algal species. They suggest that the exotic alga may have a competitive advantage in certain conditions, and that efforts to control its spread may need to take into account the effects of moisture levels on its growth and spread.

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Some breeds of beef cattle have two color options, red and black, where the black version of the gene (B) is dominant over the red version (b).



The different forms of the beef cattle color gene are called ___

Answers

The different forms of the beef cattle color gene are called alleles. Alleles are alternate forms of the same gene, and they can be either dominant or recessive.

In the case of the beef cattle color gene, the black version of the gene (B) is dominant over the red version (b). This means that if both the dominant and the recessive alleles are present, the black color will be expressed in the cow. However, if two recessive alleles are present, then the red color will be expressed in the cow.

Dominant alleles are always expressed in an organism, while recessive alleles are only expressed when two of them are present. Dominant alleles can also be passed on to offspring, while recessive alleles can only be passed on if two of them are present.

This is why it is important to understand the genetic makeup of a breed before breeding. By studying the alleles and their expression, breeders can ensure that the desired phenotype is expressed in the offspring.

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In three to five sentences, compare the geological processes we observe today to those that would have taken place throughout history.

It say its for biology but its not its for sciences

Please i need this fast if anyone can help me i will me alot for me

Answers

Geological processes that we observe today, such as volcanic eruptions, earthquakes, and erosion, are similar to those that would have taken place throughout history.

However, the scale and frequency of these processes may have varied over time.

For example, some geological processes, such as plate tectonics, have been ongoing for billions of years, while others, such as large-scale volcanic eruptions, may have been more frequent during certain periods in Earth's history.

Additionally, human activity has introduced new geological processes, such as pollution and climate change, that did not exist in the same way in the past.

Overall, the basic geological processes that shape our planet have been operating throughout Earth's history, but the specific details and intensity of these processes have changed over time.

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organisms show slowed growth during the:


spring

summer

autumn

winter

Answers

During the spring, microorganisms experience slowed growth due to the decrease in temperature and the increase in precipitation.

Here, correct option is A.

Cold temperatures can inhibit growth, while heavy rainfall can reduce the amount of available nutrients in the environment. During the summer, increased temperatures can cause microorganisms to slow their growth rate due to the lack of available energy for metabolism.

Additionally, the higher temperatures can also cause some microorganisms to become dormant or die. During the autumn, microorganisms may experience slowed growth due to the lower temperatures, which can inhibit the metabolic rate of the microorganisms, as well as the decrease in sunlight, which can reduce the amount of energy available for photosynthesis.

Therefore, correct option is A.

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Essay writer
A gene helps determine how the pigment melanin is distributed on human skin.
Having freckles or not having freckles are traits determined in part by this gene.
Write an explanation for why some people have one trait and other people have
the other. Be sure to use the terms allele and chromosome in your answer.

Answers

Answer:

Genes have different versions, called alleles. Alleles are one reason some people have freckles and others do not. A person who has freckles inherited alleles that produce freckles. A person with no freckles inherited different alleles that don't produce freckles.

Explanation:

That was the sample answer.

What parts of a cell is the sem most useful for examining?.

Answers

The Scanning Electron Microscope (SEM) is a powerful tool used to study the surface of a specimen in great detail. It is most useful for examining the exterior features of a cell, including the cell membrane, cytoskeleton, and extracellular matrix.

One of the major advantages of the SEM is its ability to provide high-resolution, three-dimensional images of a specimen. This allows researchers to study the surface features of cells and to visualize the spatial organization of subcellular structures. In addition, the SEM can be used to study the interactions between cells and their environment, such as the formation of cell adhesions or the uptake of particles by cells.

Overall, the SEM is a valuable tool for examining the surface features of cells and for understanding the interactions between cells and their environment. Its high-resolution imaging capabilities make it an essential tool for cell biology research.

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How did Avery's contributions to the understanding of heredity depend on the work of other scientists?

Answers

Avery's contributions to the understanding of heredity depended on the work of other scientists in several ways. First, Avery built on the work of Gregor Mendel, who discovered the basic principles of heredity through experiments with pea plants. Mendel's work showed that traits are passed down from parents to offspring in a predictable way, but he did not know what the physical basis of heredity was.

Second, Avery's work was based on the discovery of DNA by Friedrich Miescher in 1869. Miescher discovered a substance in the nuclei of cells that he called "nuclein," which was later identified as DNA. This discovery laid the foundation for Avery's work on the role of DNA in heredity.

Finally, Avery's work was influenced by the discovery of bacterial transformation by Frederick Griffith in 1928. Griffith showed that a non-virulent strain of bacteria could be transformed into a virulent strain by exposure to heat-killed virulent bacteria. Avery's experiments built on Griffith's work by showing that the transforming substance was DNA.

In summary, Avery's contributions to the understanding of heredity depended on the work of other scientists, including Mendel, Miescher, and Griffith. Avery's work built on their discoveries and helped to establish the role of DNA as the physical basis of heredity.

Answer:

Avery's contributions to the understanding of heredity depended on the work of other scientists, particularly Frederick Griffith. Griffith discovered that genetic material could be transferred between bacteria but did not know what that material was.

Avery and his colleagues expanded Griffith's work through experiments to identify the nature of the genetic material responsible for the transformation of bacteria. They purified various components of the bacteria and tested each one to see if it was responsible for the transfer of genetic information.

Their experiments showed that the genetic material responsible for transformation was DNA, not protein or RNA as some scientists had previously thought. Avery's work was groundbreaking because it provided the first direct evidence that DNA was the molecule responsible for transmitting genetic information from one generation to the next.

However, Avery's work depended on the contributions of other scientists. For example, Oswald T. Avery had previously conducted research on the bacterial transformation in the early 1940s. Avery and his colleagues had also benefited from the discovery of X-ray crystallography by Rosalind Franklin and Maurice Wilkins, which allowed them to examine the structure of DNA more closely.

In conclusion, Avery's contributions to the understanding of heredity were built on the work of other scientists who had made important discoveries before him. Without their work, Avery may not have conducted the experiments that led to the identification of DNA as the genetic material.

Explanation:

Examine the digestive system structures in the figure above. The highest rate of nutrient absorption occurs at location _____. 4 5 1 8.

Answers

Answer:

at the illeum

Explanation:

the illeum contains several villi and microvilli that increase surface area for absorption

Hemoglobin is the protein in red blood cells that binds oxygen. If a mutation occurs in the DNA that codes for hemoglobin, the structure of hemoglobin can change. The change in structure of hemoglobin can then change the shape of red blood cells, and some mutations can cause red blood cells to become sickle-shaped.


Sickled red blood cells carry less oxygen than normal red blood cells. What does this demonstrate about mutations in the DNA that codes for hemoglobin?
A.
These mutations can change the structure of oxygen so that it does not bind to hemoglobin.
B.
These mutations decrease the amount of oxygen available to bind with hemoglobin.
C.
These mutations are unable to affect the structure and function of hemoglobin.
D.
These mutations can change the structure and function of hemoglobin.

Answers

The fact that sickled red blood cells carry less oxygen than normal red blood cells demonstrates that the mutations in the DNA that codes for hemoglobin can change the structure and function of hemoglobin.

The correct option is D.

What is hemoglobin?

Hemoglobin is a protein that is found in red blood cells that carries oxygen from the blood to cells and tissues where they are needed.

The function of hemoglobin is related directly to its structure.

A mutation in the gene that codes for hemoglobin will result in adefor ation of the structure of hemoglobin, us rendering it unable to transport oxygen effieciently.

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How did scientists probably date the extrusion and intrusion?

Answers

The scientists probably date the extrusion and intrusion through dating a sample of that rock, Radioactive dating.

How do scientists date intrusions and extrusions?

Radioactive dating  can be  seen as one that is been used by the scientist and can be considered as one that provide the ages of particles,  however in this case not the sedimentary rock as a whole.

It should be noted that hrough dating a sample of that rock, thenthe extrusion can be known which can be250 million years old however the intrusion extends from the bottom layer  up to the earliest one.

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you are reading a scientific paper regarding the relationships of the anatomical and behavioral characteristics of chimpanzees and their implications for early hominid evolution. you note that the authors refer to human ancestors as hominids. this implies that the researchers are relying on group of answer choices cladistic classifications of chimpanzees and humans. nonevolutionary classification of chimpanzees and humans. traditional classifications of chimpanzees and humans. an incorrect classification of human ancestors.

Answers

The researchers are relying on traditional classifications of chimpanzees and humans, as they refer to human ancestors as hominids. Option (C) is correct.

Hominid is a traditional term used to refer to members of the family Hominidae, which includes humans and their extinct ancestors. This classification is based on shared anatomical and behavioral traits, such as bipedalism and increased brain size, that distinguish hominids from other primates.

While cladistic classifications based on genetic and morphological data have provided more detailed information about the relationships between chimpanzees and humans, the term hominid is still commonly used in scientific and popular literature. Option (C) is correct.

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The complete question is: 

'you are reading a scientific paper regarding the relationships of the anatomical and behavioral characteristics of chimpanzees and their implications for early hominid evolution. you note that the authors refer to human ancestors as hominids. this implies that the researchers are relying on group of answer choices 

A) cladistic classifications of chimpanzees and humans. 

B) non-evolutionary classification of chimpanzees and humans. 

C) traditional classifications of chimpanzees and humans. 

D) an incorrect classification of human ancestors.

Identify and describe patterns of how air masses interact and change over time

Answers

Air masses interact and change over time in a variety of ways. The interactions between air masses form the basis of weather systems and global weather patterns.

Air masses move in response to pressure differences, temperature differences, and other factors. As air masses interact, they can change in temperature, humidity, and other characteristics. Air masses can also mix, creating fronts and other weather systems. As air masses move, they can bring wet or dry conditions, warm or cold temperatures, and other changes in the atmosphere.

Over time, these interactions can create longer-term shifts in global weather patterns, such as El Niño or La Niña. By studying how air masses interact and change over time, meteorologists can better understand and predict global weather patterns.

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the following sequence of dna is part of the normal, wild-type gene. 3' atg cgg gta gtt agc cga tag 5' a deletion occurs during dna replication, causing the guanine shown in red to be removed from the nucleotide strand. what effect is this most likely to have on the final protein?

Answers

The sequence given is in the 5' to 3' direction and represents a segment of DNA that codes for a protein. The start codon "ATG" indicates the beginning of the coding region and the stop codon "TAG" indicates the end of the coding region.

The deletion of the guanine (G) from the sequence would result in a frameshift mutation since the deletion would shift the reading frame of the codons. This would cause all the codons downstream of the deletion to be different from the original sequence.

The new sequence would be: 3' atg cgg gta tta gcc gat ag 5'

The new codons downstream of the deletion would be different, which would result in a different amino acid sequence being translated. This could potentially alter the structure and function of the final protein. The effect of this frameshift mutation on the protein would depend on the specific location of the deletion and the resulting altered sequence of codons.

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can someone help me with this worksheet?

Answers

According to the punnett square, 1) Phenotype long hair and Tortoise shell. 2) Genotype Ll XBXb 3) Gametes: L XB, L Xb, l XB, l Xb.  4) Phenotype Short hair and Black. 5) Genotype ll XbY. 6) Gametes: l Xb, l Xb, l Y, l Y. 7) 4/16 = 1/4. 8) 4/16 = 1/4. 9) 2/16 = 1/8. 10) 2/16 = 1/8. 11) 0/16. 12) 2/16 = 1/8. 13) 2/16 = 1/8. 14) 1/8. 15) 1/8. 16) 1/8. 17) 1/8. 18) 0/8. 19) 0/8. 20) 1/8. 21) 1/8. 22) 1/8. 23) 1/8.

To answer this question, we will use a punnett square which is the best representation of a cross.

What is a Punnett square?

The Punnett square is a graphic representation that shows the different types of gamete combinations according to the alleles involved in a cross.

Punnett square shows the probabilities of getting offspring with different genotypes and their consequent phenotypes.

Let us also remember that,

Codominance is an inheritance pattern in which both alleles are expressedComplete dominance is the inheritance pattern in which the dominant alleles hides the expression of the recessive alleleAutosomal genes are those located in autosomal chromosomesX-linked genes are those located in the X chromosome.

In the exposed example, two genes code for two traits,

- Color ⇒ X linked gene ⇒ co-dominant

XB XB → organgeXb Xb → blackXB Xb → tortoise shell

- Length ⇒ Autosomal gene ⇒ complete dominance

LL and ll → longll → short

These genes are independent from each other.

Female

1) Phenotype

Long hairTortoise shell

2) Genotype ⇒ Ll XBXb

3) Gametes ⇒ L XB, L Xb, l XB, l Xb

Male

4) Phenotype

Short hairBlack

5) Genotype ⇒ ll XbY

6) Gametes ⇒ l Xb, l Xb, l Y, l Y

Cross:

Parentals)   Ll XBXb  x  ll XbY

Punnett square)    LXB              LXb            lXB             lXb

                lXb    LlXBXb       LlXbXb       llXBXb        llXbXb

                lXb    LlXBXb       LlXbXb       llXBXb        llXbXb

                lY       LlXBY         LlXbY           llXBY          llXbY

                lY       LlXBY         LlXbY           llXBY          llXbY

F1) 50% of the progeny are expected to be females

   50% of the progeny are expected tp be males

From the whole progeny,

1/8 are expected to be females with long hair and Tortoise shell color, LlXBXb.1/8 are expected to be females with long hair and black color, LlXbXb.1/8 are expected to be females with short hair and Tortoise shell color, llXBXb.1/8 are expected to be females with short hair and black color, llXbXb.

1/8 are expected to be males with long hair and orange color, LlXBY.1/8 are expected to be males with long hair and black color, LlXbY.1/8 are expected to be males with short hair and orange color, llXBY.1/8 are expected to be males with short hair and black color, llXbY.

7) long hair: 4/16 = 2/8 = 1/4 ⇒ LlXBXb + LlXbXb + LlXBY + LlXbY

8) short hair: 4/16 = 2/8 = 1/4 ⇒ llXBXb + llXbXb + llXBY + llXbY

9) tortoise shell female: 2/16 = 1/8 ⇒ LlXBXb, llXBXb

10) black female: 2/16 = 1/8 ⇒ LlXbXb, llXbXb

11) orange female: 0/16

12) black male: 2/16 = 1/8 ⇒ LlXbY, llXbY

13) orange male: 2/16 = 1/8 ⇒ LlXBY, llXBY

14) long tortoise female: 1/8 LlXBXb

15) short tortoise female: 1/8 llXBXb

16) long black female: 1/8 LlXbXb

17) short black female: 1/8 llXbXb

18) long orange female: 0/8

19) short orange female: 0/8

20) long black male: 1/8 LlXbY

21) short black male: 1/8 llXbY

22) long orange male: 1/8 LlXBY

23) short orange male: 1/8 llXBY

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During filtration, anything that is small enough to pass through all three layers of the filtration membrane will become part of the filtrate. Sometimes, the least porous layer of this membrane becomes clogged and then glomerulonephritis may occur. What is the name of the most porous layer of the filtration membrane?.

Answers

The most porous layer of the filtration membrane is called the fenestrated endothelium.

This layer is made up of endothelial cells that have small pores or fenestrae, which allow for the passage of small molecules such as water, ions, and nutrients. These pores are around 70-100 nanometers in diameter, making them smaller than red blood cells but larger than most proteins.

In glomerulonephritis, inflammation can cause damage to the fenestrated endothelium, leading to a decrease in the rate of filtration and an increase in the size of molecules that are able to pass through the membrane. This can result in the accumulation of larger molecules in the bloodstream, leading to symptoms such as swelling, high blood pressure, and proteinuria.

It is important to note that the glomerular filtration membrane is composed of three layers, including the fenestrated endothelium, the basement membrane, and the podocytes. Damage to any of these layers can affect the rate and quality of filtration, leading to various kidney diseases.

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While a lot of people died during the Spanish Flu Pandemic, many people were also infected and survived. Why do you think it is beneficial for a pathogen to work without killing the host?

Answers

From an evolutionary perspective, it is beneficial for a pathogen to work without killing the host because it allows the pathogen to continue to spread and infect new hosts. If a pathogen kills its host too quickly, it will not have the opportunity to spread to new hosts, and the pathogen will eventually die out.

By contrast, if a pathogen can infect a host and replicate within the host without causing too much harm, it can continue to spread to new hosts, increasing its chances of survival and propagation. This is why many pathogens have evolved to cause relatively mild symptoms or to be asymptomatic, allowing them to spread from host to host without being detected.

Of course, this does not mean that all pathogens are harmless or that they do not cause serious harm to their hosts. Some pathogens, like the Spanish Flu, can cause severe illness and death, and can be very difficult to control. However, from an evolutionary perspective, it is generally advantageous for a pathogen to work without killing the host, as this allows it to spread more effectively and persist in the population over time.

When did the first homo sapiens arrive in the americas?.

Answers

Answer:

18,000 years ago

Explanation:

Most archaeologists accept that humans were in the Americas 18,000 years ago

What is the Solution?

Answers

The answer is 2.

95%+4%+1+=100%

Which of the following are types of adaptations of desert plants that enable them to survive and reproduce? (Choose all that apply.)
Flower adaptations
Stem and leaf adaptations
Behavioral adaptations
Root adaptations

Answers

The types of adaptations of desert plants that enable them to survive and reproduce are stem and leaf adaptations and root adaptations

What is adaptation

By changing throughout time in response to external forces, organisms can better survive and reproduce in their particular habitat. This process is known as adaptation. Morphological, physiological, and behavioral adaptations can all be the result of natural selection, genetic drift, or other processes.

The biological process of reproduction is how organisms create children that receive their genetic make-up. Most species reproduce by joining their male and female gametes to create a zygote, which then grows into a new person. The continuation of a species and the transmission of genetic features from one generation to the next depend on reproduction. Reproduction can take place in a sexual or asexual way.

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Why do ferns not grow as tall as gymnosperms and angiosperms?.

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Ferns do not grow as tall as gymnosperms and angiosperms because they lack true vascular tissue and specialized support structures.

Vascular tissue, consisting of xylem and phloem, is responsible for transporting water and nutrients throughout the plant and providing structural support. Gymnosperms and angiosperms have evolved more efficient vascular tissue and specialized support structures such as lignified trunks, branches, and leaves, allowing them to grow taller and support more weight.

In contrast, ferns lack true vascular tissue and have a simpler structure that limits their ability to transport water and nutrients, as well as provide support. Ferns have underground stems called rhizomes that anchor the plant and absorb water and nutrients, but they are not as effective at supporting the plant's weight as the specialized structures found in gymnosperms and angiosperms.

Thus, ferns are typically smaller and grow closer to the ground, with few exceptions such as tree ferns, which have evolved specialized adaptations to support their height.

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Identified coping strategy, explain how the relevant can help in resolving an unhealthy relationship ,also give an example in your explanation

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Coping strategies are an important tool to help individuals navigate difficult situations and to improve an unhealthy relationship.

Coping strategies involve using problem-solving skills, communication skills, and other positive behaviors to resolve conflict and improve the relationship. For example, communication skills such as active listening, expressing empathy, and expressing needs can help to create a safe space for both parties to share their feelings and needs.

This can help to create a trusting and secure relationship by allowing all parties to feel heard and respected. Additionally, problem-solving skills can help to find solutions to issues, rather than just focusing on the problems.

By breaking down the issues into smaller parts and working through them, both parties can gain a better understanding of each other and the conflict. With these coping strategies, individuals can better understand their own emotions and the emotions of their partner, leading to a healthier and more fulfilling relationship.

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At rest, the tropomyosin molecule is held in place by:.

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At rest, the tropomyosin molecule is held in place by the troponin complex.

The troponin complex is made up of three subunits - troponin C, troponin I, and troponin T. Troponin C is the calcium-binding subunit, troponin I inhibits the interaction between myosin and actin, and troponin T anchors the troponin complex to the tropomyosin molecule.

When calcium ions bind to troponin C, a conformational change occurs in the troponin complex, causing troponin I to release its inhibition on the interaction between myosin and actin. This allows for the formation of cross-bridges between the myosin heads and the actin filaments, leading to muscle contraction.

In summary, the troponin complex plays a critical role in regulating muscle contraction by controlling the positioning of the tropomyosin molecule. Without this complex, the myosin heads would not be able to interact with the actin filaments, and muscle contraction would not be possible.

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Read the following sentences from the text. "But some creatures have just a single cell, like an amoeba. They are called unicellular organisms. Other creatures, like us human beings, are collections of cells. These are called multicellular organisms. Multicellular organisms can range in size from brown algae to large animals like elephants and whales, which have trillions of cells. "

What can be concluded about cells based on this information?

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The given text discusses the concept of cellular organization in living organisms. It explains that some organisms, such as amoebas, consist of just one cell, which are called unicellular organisms.

In contrast, more complex creatures like humans are made up of collections of cells and are called multicellular organisms.

The text also points out that multicellular organisms can range in size, from brown algae to large animals like elephants and whales.

This illustrates the diversity of living organisms and emphasizes the role of cells in building and sustaining life.

Overall, the text highlights the importance of cellular organization in the structure and function of living organisms.

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In Africa, elephant populations have declined due to poaching, which is illegally hunting elephants for their tusks. In the past, only about two percent of female elephants were born tuskless. A recent study found that 98 percent of the 174 female calves born in one national park had no tusks. Which of the following statements is supported by this mathematical representation?
A. Elephants without tusks are surviving and reproducing while elephants with tusks are not.
B. Elephants no longer need tusks because their habitats have been changing.
C. Female elephants do not need tusks to successfully rear their young.
D. Male elephants are growing tusks more quickly than female elephants are.

Answers

Natural selection selects beneficial alleles and and phenotypes, and increases their frequency in the population. Option A. Elephants without tusks are surviving and reproducing while elephants with tusks are not.

What is natural selection?

Natural selection is an evolutive force that favors an allele or act against it, depending on how the allele affects the fitness of individuals.      It selects beneficial alleles and increases their frequency in the population.

The phenotype that expresses the best fitness results in higher survival, fertility, and reproductive rates. Aptitude -fitness- must be significant to the natural selection act in its favor.

Adaptation, acchieved by natural selection, is closely related to selective pressures.

Selective pressure is applied by different organisms or conditions that influence the survival rate of a certain phenotype. It influences the probability of a genotype leaving its gametes to the following generations.

In the exposed example,

Selective pressure ⇒ poachingoriginal phenotype ⇒ tuskednew phenotype ⇒ tuskless

Being tuskless increased the individuals' fitness so natural selection favored this new phenotype and increased its frequency in  the population.

Option A. Elephants without tusks are surviving and reproducing while elephants with tusks are not.

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