Please see attached photo for problem from my homework set.

Please See Attached Photo For Problem From My Homework Set.

Answers

Answer 1

Answer:

see below  

Step-by-step explanation:

(7y +9 )(7y +9 )      or   (7y+9)^2         you ALMOST had it...just missed the parentheses !


Related Questions

Mary spends 2 2/3 hours on math homework everyday. She also spends 3 1/3 hours on art homework. How much time does Mary spend in total working on math and art homework?


It has to be like an actual fraction. All I know is that 24 is the whole number. Use that to solve the problem.

Answers

Answer:

6 hours

Step-by-step explanation:

2 2/3 +3 1/3= 5+1=6

Answer:

2 2/3+ 3 1/3 = 6. Multiply 6 by 4 weeks. 24 as your whole number.

Step-by-step explanation:

hope this helps

5 Four children are measuring their height.
Aisha
1.39 metres
Teddy
1.37 metres
Scott
1.4 metres
Kim
1.43 metres
Order the children from tallest to shortest.

Answers

Kim, Scott, Aisha, Teddy is the answer

Enrique estimates that his utilities will cost him $86.00 per month over the courses of the next 3 years. What is his total estimated cost for utilities over the next 3 year period??

Please help thank you !!!

Answers

Answer:

$3096

Step-by-step explanation:

There are 12 months in 1 year.

3 × 12 = 36

There are 36 months in 3 years.

$86 × 36 = $3096

Answer:

3096

Step-by-step explanation:

I just completed the quiz.

4x - 5y = 6
- 8x +10y = -12
gausse elimination

Answers

Step-by-step explanation:

4x−5y=6

−8x+10y=−12

Isolate x for 4x –5y = 6: x=6-5y/4

Substitute x= 6+5y/4

[-8 (6-5y/4) +10y=-12]

Simplify

[-12= -12 ]

The solutions to the system of equations are:

x=6+5y/4

Question #12: A department store has a discount on shoes based on a
percentage of the price. Suppose one pair of shoes is marked down from
$70 to $49. What is the price for a $110 pair of shoes after the discount is
applied?
a
O $89.00
O $77.00
O $73.33
O $33.00

Answers

Answer:

$77

Step-by-step explanation:

The answer is $77 because first you need to find how much money was discounted by doing 70-49 to get 21. Then you need to find how much percent 21 is of 70 by doing 21/70, then you would get 0.3 which is 30% since you have to multiply it by 100. This means that there is a 30% discount. Then you would do 0.3*110=33. This means that the 30% discount takes away $33. So 110-33=77. The answer is $77.

[tex] \displaystyle \rm\int_{0}^1 { ln }^{2k} \left \lgroup \frac{ ln \left \lgroup \dfrac{1 - \sqrt{1 - {x}^{2} } }{x} \right \rgroup }{ ln \left \lgroup \dfrac{1 + \sqrt{1 - {x}^{2} } }{x} \right \rgroup } \right \rgroup \: dx[/tex]​​

Answers

Substitute [tex]x\mapsto\sqrt{1-x^2}[/tex], which transforms the integral to

[tex]\displaystyle \int_0^1 \ln^{2k} \left(\frac{\ln\left(\frac{1-\sqrt{1-x^2}}x\right)}{\ln\left(\frac{1-\sqrt{1-x^2}}x\right)}\right) \, dx = \int_0^1 \ln^{2k}\left(\frac{\ln\left(\frac{1-x}{\sqrt{1-x^2}}\right)}{\ln\left(\frac{1+x}{\sqrt{1-x^2}}\right)}\right) \frac{x}{\sqrt{1-x^2}} \, dx[/tex]

and factoring [tex]\sqrt{1-x^2}=\sqrt{(1-x)(1+x)}[/tex] reduces this to

[tex]\displaystyle = \int_0^1 \ln^{2k}\left(\frac{\ln\left(\sqrt{\frac{1-x}{1+x}}\right)}{\ln\left(\sqrt{\frac{1+x}{1-x}}\right)}\right) \frac x{\sqrt{1-x^2}} \, dx[/tex]

The inner logarithms differ only by a sign, so that

[tex]\displaystyle = \int_0^1 \ln^{2k}(-1) \frac x{\sqrt{1-x^2}} \, dx[/tex]

Using the principal branch of the complex logarithm, we have

[tex]\ln(-1) = \ln|-1| + i\arg(-1) = i\pi[/tex]

and hence

[tex]\displaystyle \int_0^1 \ln^{2k} \left(\frac{\ln\left(\frac{1-\sqrt{1-x^2}}x\right)}{\ln\left(\frac{1-\sqrt{1-x^2}}x\right)}\right) \, dx = (i\pi)^{2k} \underbrace{\int_0^1 \frac x{\sqrt{1-x^2}} \, dx}_{=1} = \boxed{(-\pi^2)^k}[/tex]

where I assume k is an integer.

A candle's height, in inches, is a function of the number of hours it has been burning. After 4 hours the
candle's height is 10 inches, and after 16 hours the candle's height is 7 inches. The candle is burning at
constant rate.
Construct an equation that can be used to determine the candle's height, y, after x hours.
Enter your equation in the space provided. Enter only your equation.

Answers

The linear function that gives the candle's height, y, after x hours, is defined by:

y = -0.25x + 11.

What is a linear function?

A linear function is modeled by:

y = mx + b

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

In this problem, in 12 hours, the height decayed 3 inches, hence the slope is given by:

m = -3/12 = -0.25.

So:

y = -0.25x + b.

After 4 hours, the height was of 10 inches, hence we use this to find b:

10 = -0.25(4) + b

b = 11

Thus the equation is given by:

y = -0.25x + 11.

More can be learned about linear functions at https://brainly.com/question/24808124

#SPJ1

The length of a rectangle is five more than double the width. If the perimeter is 100 inches, find the dimensions.
width?
length?

Answers

(See photo)

If the length is 5 more than double the width, then if the width is ‘x’ the equation to represent length would be 2x + 5

The formula to find the perimeter of a rectangle is just all the sides added together.

Knowing that info, solve for x, then plug the answer you get (15) back into the equations to get your final answer

Pleas I need help this is so hard

Answers

I believe it is the second one

Answer:

Equation:

C = 1.75x + 5 25

A 22-mile ride costs $43.75.

Step-by-step explanation:

Because there is a flat fee of 5.25, only the first two equations could possibly be correct.

Then check with the examples given. If a 7 mile ride costs 17.50, the second equation cannot possibly be right. 7 miles times over $5 per mile will cost more than $35 not even including the flat fee.

Check:

1.75(7) + 5.25 = 17.50

and

12(1.75) + 5.25 = 26.25

So, the correct equation is

C = 1.75x + 5.25

Next use this equation to find the cost of the 22 mile ride.

1.75(22) + 5.25

= 43.75

5. Convert the rectangular equation x² + y² - 6y = 0 into a polar equation.
A. r = 6 sin theta
B. r = 6 cos theta
C. r = √6 sin theta
D. r = √6 cos thea​

Answers

Answer:

A. r = 6 sin theta

Step-by-step explanation:

Given equation is: [tex]x^2+y^2-6y=0[/tex]....(1)

Using the formulae that link Cartesian to Polar coordinates.

[tex]x=r\cos\theta \: and \: y = r\sin\theta[/tex]

Plugging the values of x and y in equation (1), we find:

[tex](r\cos\theta)^2+(r\sin\theta)^2-6(r\sin\theta)=0[/tex]

[tex]\implies r^2\cos^2\theta+r^2\sin^2\theta-6r\sin\theta=0[/tex]

[tex]\implies r^2(\cos^2\theta+\sin^2\theta)=6r\sin\theta[/tex]

[tex]\implies r^2(1)=6r\sin\theta[/tex]

[tex](\because \cos^2\theta+\sin^2\theta=1)[/tex]

[tex]\implies\frac{ r^2}{r}=6\sin\theta[/tex]

[tex]\implies\huge{\purple{ {r}=6\sin\theta}}[/tex]

Answernone

none

none

Step-by-step explanation:

Consider a triangle...

Answers

Answer:

1. Triangle: B = 47.0° , C = 103.05° , c = 2.53 cm

2. Lake: c = 1105.31 ft

Step-by-step explanation:

Law of Sine Formula:[tex]\frac{sin(A)}{A} = \frac{sin(B)}{B} = \frac{sin(C)}{C}[/tex]

Given: A = 30° , a = 1.3 cm , b = 1.9 cm

[tex]\frac{sin(30)}{1.3} = \frac{sin(B)}{1.9} = \frac{sin(C)}{C}[/tex]

Solving for sin(B). Cross Multiply.

[tex]\frac{sin(30)}{1.3} = \frac{sin(B)}{1.9}\\1.3*sin(B)=1.9*sin(30)\\sin(B)=\frac{1.9*sin(30)}{1.3} \\[/tex]

B = sin^-1( [tex]\frac{1.9*sin(30)}{1.3}[/tex] )

B ≈ 46.9509202

B = 47.0°

Solve for C°

A° + B° + C° = 180°

30° + 46.95° + C° = 180°

C° = 180° - 30° - 46.95°

C° = 103.05°

Solve for sin(C)

[tex]\frac{sin(30)}{1.3} = \frac{sin(103.05)}{C}\\[/tex]

Cross Multiply

[tex]C*sin(30)=1.3*sin(103.05)\\C=\frac{1.3*sin(103.05)}{sin(30)}[/tex]

C ≈ 2.532850806

C = 2.53 cm

Law of Cosine Formula: [tex]c^2=a^2+b^2-2*a*b*cos(C)[/tex]

Given: a = 850 ft , b = 960 ft ,  C=75°

Solve for c.

[tex]c^2=a^2+b^2-2*a*b*cos(C)\\c^2=(850ft)^2+(960ft)^2-2*(850ft)*(960ft)*cos(75)\\\\c=\sqrt{(850ft)^2+(960ft)^2-2*(850ft)*(960ft)*cos(75)\\} \\[/tex]

c ≈ 1105.308698

c = 1105.31 ft

Write a propotion that can be used to convert 50 meters into kilometers. Then solve

Answers

Answer:

0.05km

Step-by-step explanation:

There are 1000 meters in a single kilometer. Using some dimensional analysis, we get set up the following expression:

[tex]\frac{50}{1} \frac{meters}{1}\frac{1}{1000} \frac{kilometers}{meters}[/tex]

The meters will cancel leaving the units of kilometers:

[tex]\frac{50}{1000} km=0.05km[/tex]

jessica spent 20% of her money for snacks. She spent 25% of the remainder for school supplies. She has P30 left. How much money did Jessica start with?

Answers

Jessica spend 20%
Take away 20% and make p80 make make make make mark amesmamsksskmssjejsnebdss

When yara and her sister came home there was 3/4 of a pan of brownies left over yara and her sister ate 2/3 of the 3/4 pan of brownies how much of the entire pan of brownies did yara and her sister eat

Answers

Answer:

3/4_2/3 find the LCM= 1/12

Find the length of the third side . If necessary , round to the nearest tenth .

Answers

Answer:

umm 9?

Step-by-step explanation:

Bruce wants to make 50 ml of an alcohol solution with a 12% concentration. He has a 10% alcohol solution and a 15% alcohol solution. The equation 0.10x + 0.15(50 – x) = 0.12(50) can be used to find the amount of 10% alcohol solution Bruce should use.
How much of the 10% alcohol solution should Bruce use

Answers

Answer:

  30 mL

Step-by-step explanation:

You are being asked to solve the given equation for the value of x.

__

  0.10x +0.15(50 -x) = 0.12(50) . . . . given

  -0.05x = -0.03(50) . . . . . subtract 0.15(50), combine terms

  x = 30 . . . . . . . . . . . divide by -0.05

Bruce should use 30 mL of the 10% alcohol solution.

Suppose that $3^a = 2$ and $3^b = 5$. If \[3^x = 150,\]then write an expression for $x$ in terms of $a$ and $b$.

Answers

Use logarithms to solve for a.

[tex]3^a = 2 \implies \log_3(3^a) = a\log_3(3) = \log_3(2) \implies a = \log_3(2)[/tex]

Similarly, for b and x.

[tex]3^b = 5 \implies b = \log_3(5)[/tex]

[tex]3^x = 150 \implies x = \log_3(150)[/tex]

Factorize 150:

150 = 2 • 3 • 5²

Then we can expand log₃(150) using the product-to-sum and exponent property,

[tex]\log_3(150) = \log_3(2\times3\times5^2) = \log_3(2) + \log_3(3) + \log_3(5^2)[/tex]

[tex]\implies \log_3(15) = \log_3(2) + 1 + 2 \log_3(5) \iff \boxed{x = 1 + a + 2b}[/tex]

Suppose 3 and 8 are the only individual scores that can be made in a certain game. How many integer total scores are impossible to obtain?

Answers

Answer: 3

Step-by-step explanation:

3x8 = 24

24x2= 48!

8x12= 96!

Answers must be divisible by both numbers, and achievable by both inputs.

Hope This Helped


Maitri and Aabhas do a work in 12 hours.

Aabhas and Kavya do the work in 15 hours.

Kavya and Maitri do
work in 20 hours.

In how many hours will they finish it together and separately?

Pls help me

Answers

Answer:

See below ~

Step-by-step explanation:

Given

Maitri and Aabhas do a work in 12 hoursAabhas and Kavya do the work in 15 hoursKavya and Maitri do the work in 20 hours

Solving

Take Maitri, Aabhas, and Kavya to be x, y, z respectivelyx + y = 12 (1)y + z = 15 (2)x + z = 20 (3)

Take Equation 1 and rewrite it so that it is equal to x.

x = 12 - y

Take Equation 2 and rewrite it so that it is equal to z.

z = 15 - y

Now, substitute these values in Equation 3.

x + z = 2012 - y + 15 - y = 20-2y + 27 = 202y = 7y = 7/2 = 3.5 hours [Aabhas]

Substitute the value of y in Equation 1.

x + 3.5 = 12x = 8.5 hours [Maitri]

Substitute the value of y in Equation 2.

3.5 + z = 15z = 11.5 hours [Kavya]

Add the values of x, y, and z together.

x + y + z8.5 + 3.5 + 11.512 + 11.523.5 hours [together]

7. A sector of a circle has are length 2cm and central angle 0.4 radians. Find its
radius and and area?

Answers

12 is the factor n the bro 92 n minus 8

The base of S is the region enclosed by the parabola y = 8 − 8x2 and the x-axis. Cross-sections perpendicular to the x-axis are isosceles triangles with height equal to the base.

Answers

The base of a solid is the region in the first quadrant bounded by the y-axis, the x-axis, the graph of y=ex, and the vertical line x=1. For this solid, each cross section perpendicular to the x-axis is a square. What is the volume of the solid?

Step-by-step explanation:

Answer: Sometimes I dont want to be happy.

. What is the vertical asymptote(s) for y=x-5/x^2-4x-12​

Answers

Answer:

x = -2 and 6

Step-by-step explanation:

To find vertical asymptote, set the denominator equal to 0 and solve for x. See the guidelines below for determining VA

[tex]y=\frac{x-5}{x^{2} -4x-12}[/tex]

[tex]x^{2} -4x-12=0[/tex]

[tex]x^{2} -6x+2x-12=0[/tex]

[tex]x(x-6)+2(x-6)=0[/tex]

[tex](x+2)(x-6)=0[/tex]

[tex]x=-2,6[/tex]

Hope this helps and God bless!

Please help i have an assignment due TODAY i need to get this done
rules:
NO LINKS! im not getting myself a virus

Answers

Answer:

r = 50 degrees.

Step-by-step explanation:

r = 50 degrees ( vertical angles are congruent).

The answer is r=50 degrees

The sum of the two numbers is 40. One number is 3 times the other number. Find the 2 numbers

Answers

Answer:

10 and 30

Step-by-step explanation:

The sum of 10 and 30 is 40.

30 is three times ten (10 x 3 = 30).

hope this helps!

The question asks, "What's the sum?"

The answer is 10 and 30

10 times 3 is 30, meaning 10 will be the number times 3 they wanted. 10 + 30 is 40, therefore the answer is 10 and 30

Regan operates an orange juice stand. On Monday she used 1/3 of a bag of oranges. On
Tuesday she used 2/5 as many oranges as on Monday. How many bags of oranges did Reg
use on Tuesday?
Write your answer as a fraction or as a whole or mixed number.
Please help meee

Answers

Answer:

0.825 bags of oranges

Step-by-step explanation:

1/3 is 0.33 and 2/5 is 0.4 so 0.33/0.4 is 0.825

How many different three person relay teams can be chosen from six students?

Answers

There can be 20 different three person relay teams chosen from 6 students. Hope this helps!

The committee spent $372 on costumes for 20 people each costume cost the same amount of money, how much did each costume cost, in dollars ? PLEASE ANSWER I'LL GIVE 68 POINTS TO THE FIRST ONE THAT MAKES SINCE, AND I'LL MAKE UU BRAINLIEST, also I'm gonna ask 4 questions on my page and whoever answers them all first get 100 points I promise!

Answers

Answer:

$18.60

Step-by-step explanation:

The total amount spent is $372, and this can be divided by 20. Each costume would cost $18.60.

Find an equation for the graph

Answers

Answer:

y=6^x+0.612 - 4

Step-by-step explanation:

x = -4 ---> horizontal asymptote

m = 6 ---> use points (0, -1) and (1, 5)

Parent function of the graph: [tex]y=b^x[/tex]

Our equation: [tex]y=6^x[/tex]

Add alterations:

Reflections = N/AVertical & horizontal shifts = down 4Vertical & horizontal stretches = left approx 0.612

Final equation: y=6^x+0.612 - 4


Find the length of the arc.
120°
6ft

Answers

Answer:

The length of the arc is 8*pi cm. An arc that subtends a central angle of 120 degrees has a length of 120/360 = 1/3 the length of the total circumference of the circle. We know the entire circumference of the circle is 2πr, which in this case is 2π*12 = 24π.

Step-by-step explanation:

sorry I only have the 8

Solve for an angle in right triangles. Round to the nearest hundredths

Answers

Answer:

Use   SOH  CAH TOA  to rember how the trig function fit on the triangle

Step-by-step explanation:

we are given  the Hypotenuse and the Opposite  or   H and O   look for the trig function with each of those,  SOH is good

Sin Ф =  Opp /  Hyp,    or   SOH

now plug in what you are given

Sin Ф = 5 / 8

use inverse trig fuction to find the angle

arcSin ( Sin Ф) = arcSin ( 5/8)

trig functions cancel out

Ф = arcSin(5/8)

I'm using my calculator to find the arcSin(5/8)

Ф=38.6821...°

also make sure you know if your calculator is in degrees or radians.  

Ф=38.68°   to the nearest hundredth  :)

Answer:

∠A = 38.68°

Step-by-step explanation:

The side opposing ∠A and the hypotenuse are given.

Therefore, take the inverse sin function of ∠A.

sin∠A = 5/8∠A = sin⁻¹ (0.625)∠A = 38.6821875∠A = 38.68° (nearest hundredth)
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