please solve its due

Answer:

Range is (0, -5)

Step-by-step explanation:

[tex]{ \sf{f(x) = - {x}^{2} - 5}}[/tex]

when x is 0:

[tex]{ \sf{f(0) = - 5}}[/tex]

Answer:

40

Step-by-step explanation:

i need point so i am writing this sentence you have to do 4 times 10 (4×10) it is 40

Answer:

Step-by-step explanation:

[tex]\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\[/tex]

[tex]\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\[/tex]

Answer:

Hello I'm sorry but I have a question and I have to give ans and I can ask my question

Answer:

Step-by-step explanation:

Oi boa tarde tudo bem

Answer:

In order for the function to be discontinuous at an asymptote, the curve needs to exist on both sides of the asymptote. If the curve only exists on one side of the asymptote, then there's no discontinuity at that point.

Step-by-step explanation:

The correct answer would be -  between 30 to 40 ATPs per molecule of glucose.

In aerobic respiration macromolecules such as glucose break in the presence of oxygen to produce energy.  That occurs in mitochondria. The stages of aerobic respiration are glycolysis, the Krebs cycle and ETS.

Glycolysis is the first stage of cellular respiration that is a metabolic pathway of glucose that takes place in the cytosol. Here, the glucose molecule converts into two molecules of pyruvic acid or pyruvate that forms ATP and NADH as energy.

Two ATP molecules are produced by one molecule of FADH₂ and therefore the number of ATP produced from 2 FADH₂ is 4 ATP.

NADH produces three ATP molecules by each molecule and therefore the number of ATP produced from 8 NADH is 24 ATP.

The number of ATP produced from the one glucose molecule under aerobic respiration is given as follows:

From glycolysis = 6 ATP

From citric acid cycle = 2 ATP

From FADH₂ = 4 ATP

From NADH = 24 ATP

total 36 ATPs.

Under aerobic respiration 36 molecules of ATP are produced from one molecule of glucose thus, the correct answer would be - between 30 - 40.

Learn more about cellular respiration:

https://brainly.com/question/13721588

Answer:

147/20,7+2/5,7.407,7.41.

Step-by-step explanation:

147/20=7.35.

7+2/5=7.4.

7.407>7.4.

7.41>7.407.

Side note:

I changed everything into decimal form.

I think the answer is A and C!

Answer:

B) Keeping A constant and decreasing B

C) Increasing A and keeping B constant

Step-by-step explanation:

I did it on Khan Academy :)

Answer:

$56×2=$112 and $45×4=$180 so $112+$180= $291

Answer:

its either 2 or 4

Step-by-step explanation:

jet1 = 549 mi/h

jet2 = 620 mi/h

x= jet1

x + 71 = jet2

6 hours

6 * x

6 * x + 71

6x + 6x + 426 = 7014

12x = 7014 - 426

12x = 6588

x = 6588/12

x= 549

x + 71 = 620

wyzant

9514 1404 393

Answer:

  2)  3 pages per hour

  3)  4/29 km per minute

Step-by-step explanation:

Division by a fraction is the same as multiplication by the inverse of that fraction.

  [tex]\dfrac{\ \dfrac{9}{4}\ }{\dfrac{3}{4}}=\dfrac{9}{4}\times\dfrac{4}{3}=\dfrac{36}{12}=\boxed{3\text{ pages per hour}}[/tex]

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  [tex]\dfrac{2\text{ km}}{\dfrac{29}{2}\text{ min}}=2\times\dfrac{2}{29}\text{ km/min}=\boxed{\dfrac{4}{29}\text{ km/min}}[/tex]

Answer:

(0, 0)

Step-by-step explanation:

Each reference line is called a coordinate axis or just axis (plural axes) of the system, and the point where they meet is its origin, at ordered pair (0, 0).

Step-by-step explanation:

x intercept is 1

y intercept is 2

Hope it helps

Answer:

25 hours

Step-by-step explanation:

Answer: ITS E!!!

Step-by-step explanation:

Answer:

how to convert

Step-by-step explanation:

To convert a mixed number to an improper fraction, follow these steps: Multiply the denominator of the fractional part by the whole number, and add the result to the numerator. Use this result as your numerator, and place it over the denominator you already have. This method works for all mixed numbers

Answer:

Change the whole numbers

Step-by-step explanation:

For example

5 3/6

A whole number written as a fraction for this problem is 6/6.

If the problem was 7 4/9, it would 9/9

I'd the problem was 2 3/4, it would be 4/4.

So basically a whole number written as a fraction is when both the top and bottom number are the same. when divide by each other they equal one. 6 divided by 6 is 1, 9 divided by 9 is 1, 4 divide by 4 is 1.

First

Turn 5 3/6 into 5/1 + 3/6

Now add them to together

To add fractions together they have to have the same denominator or bottom number.

What is a number 1 and 6 have in common ?

6 because 1 can be multiplied with any number but 6 can never be multiplied to create 1.

5 is simple 5 whole numbers

so 5/1 × 6/6= 30/6

30/6 + 3/6 = 33/6

now it's an improper faction. There is no whole number, it been converted into a fraction where the top is bigger than the bottom hence why it is improper

Answer:

98 [tex]cm^{2}[/tex]

Step-by-step explanation:

The formula for the area of a square when given the diagonal is:

A = [tex]\frac{1}{2}[/tex] [tex]d^{2}[/tex] Where d is the value of the diagonal so it becomes:

0.5 × 14 × 14

This is equal to 98 [tex]cm^{2}[/tex].

HOPE THIS HELPED

Answer:

true, I hope this will help.

[tex]\boxed{\underline{\bf \: True}}[/tex]

[tex] \sf \: 6(10 + 5) = 6•10 + 6•5 [/tex]

Check with LHS = RHS rule method.

LHS

[tex]\sf6(10 + 5) \\ \sf = 6(15) \\ \sf = 6 \times 15 \\ \bf = 90[/tex]

RHS

[tex]\sf6•10 + 6•5 \\ \sf = 60 + 30 \\ \bf= 90[/tex]

We can see that both LHS & RHS give [tex]\boxed{\underline{\bf \: 90}}[/tex]as the solution. LHS = RHS. Hence proved.

Answer -> [tex]\boxed{\underline{\bf \: True}}[/tex]

_______________

Hope it helps.

RainbowSalt2222

Answer:

Yes the function is continuous f(5) = 13

Step-by-step explanation:

Replace the variable x with 5 in the expression

Simlify the results

f(5) = 3(5)-3

f(5) = 15=3

f(5) = 13

Plotting on a graph gives a coninous line with a positive gradient

y intercept (0,-2)

Please view the attached graph

Answer:

12000

Step-by-step explanation:

Check the hundreds digit if greater Han 5 increase the thousands digit by 1 and change the other digits to 0

Answer:

that is what I got as my answer

Answer:

The congruency of triangle is the statement that describes the relationship between two figures Step-by-step explanation:

9514 1404 393

Answer:

  (b)  6^10/7^6

Step-by-step explanation:

The applicable rules of exponents are ...

  (a/b)^c = (a^c)/(b^c)

  (a^b)^c = a^(bc)

__

This means you have ...

  [tex]\left(\dfrac{6^5}{7^3}\right)^2=\dfrac{(6^5)^2}{(7^3)^2}=\dfrac{6^{5\cdot2}}{7^{3\cdot2}}=\boxed{\dfrac{6^{10}}{7^6}}[/tex]

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Additional comment

I find it helpful to remember that an exponent signifies repeated multiplication. Then ...

  [tex]\left(\dfrac{6^5}{7^3}\right)^2=\left(\dfrac{6^5}{7^3}\right)\cdot\left(\dfrac{6^5}{7^3}\right)=\dfrac{6^5\cdot6^5}{7^3\cdot7^3}=\dfrac{6^{5+5}}{7^{3+3}}=\dfrac{6^{10}}{7^6}[/tex]  

Answer:

3,6

Step-by-step explanation:

Answer:

Additive inverse of -11/5 => + 11/5

hope that helps uh..☺

Answer:

If " a " represent any rational number then " a + ( - a ) = 0" or " ( - a ) + a = 0 ". Thus " a " and " - a " are additive inverse of each other. Hence " 11 / 5 " is the additive inverse of " - 11 / 5 " .

Step-by-step explanation:

Step-by-step explanation:

A 45° angle is complementary to angle

45°+x°=90°

I hope it helped U

stay safe stay happy

9514 1404 393

Answer:

  h = 3V/(πr²)

Step-by-step explanation:

The formula can be solved for h by multiplying both sides by the inverse of the coefficient of h.

  [tex]V=\dfrac{1}{3}\pi r^2h=\dfrac{\pi r^2}{3}h\\\\(\dfrac{3}{\pi r^2})V=(\dfrac{3}{\pi r^2})(\dfrac{\pi r^2}{3})h\\\\\boxed{\dfrac{3V}{\pi r^2}=h}[/tex]

_____

Additional comment

Whenever a variable has a coefficient you don't want, you can make that be 1 by multiplying the equation by the inverse of the coefficient. This is the same as dividing by the coefficient. This makes use of the fact that for any non-zero 'a', the ratio a/a has a value of 1. Anything multiplied by 1 is unchanged.

  V = ah   ⇒   V/a = (ah)/a = h(a/a) = h·1 = h

Note that we multiply the whole equation (both sides of the equal sign) by 1/a. The basic rule of equality is that you can do whatever you like to an equation, as long as you do it to both sides.

Answer:

1.5 pounds of apples are in each pie

Step-by-step explanation:

to show our work, lets multiply 1.5 by 2.

(this is the distributive property. the method shown in the image is long multiplication, but they follow the same idea)

for the sake of simplicity, we will write 1.5 as 15.

5×2=10

10×2=20

10+20=30

dont forget the decimal point! since we have one digit in the decimal place, we move the decimal behind one digit in 30.

30.0 --> 3.0 or simply, 3.

this proves that there are 1.5 pounds of apples in each pie. hope this goes more in depth !!! :)

Hi there!

The numbers you have written there are correct.

[tex]-5<x<0[/tex] is true for any value of x that is greater than -5 or less than 0.

When a number is less than 0, we know that it has to be negative.

However, it cannot be more negative than -5. It cannot be -5 either.

So, x could be -1, -2, -3, -4, -1/2, -2.3, -4.9, the list goes on.

I hope this helps!