PLSSS.the function : ℝ → ℝ, () = 2^, : (0; +∞) → ℝ, () = √4 + 1 + 1.show
that the graphs of the functions and intersect at the abscissa point x=2

Option D is the correct synthetic division of (x^2-4x+7) divided by (x-2)

Synthetic division is a shorthand procedure used to divide a polynomial by a linear factor of (x - a) form, in which "a" is constant. This method gives an expedient way to locate the quotient and remainder without carrying out long division.

x - 2 | x^2 - 4x + 7

            x^2 - 2x

           ---------

                 -2x + 7

                 -2x + 4

                 -------

                        3

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The expression can be simplified to get:

2.7^(1)*3.8^(5)

The correct option is C.

Remember that if we have the product of two powers with the same base, we only need to add the exponents.

Then we will get:

2.7^(-3) * 3.8^(2) * 2.7^(4) * 3.8^(3)

= (2.7^(-3)*2.7^(4)*3.8^(2)*3.8^(3))

= (2.7^(-3 + 4)*3.8^(2 + 3))

= 2.7^(1)*3.8^(5)

That is the expression simplified, we can see that the correct option is C.

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Answer:

C

Step-by-step explanation:

Positive numbers represent a positive situation. And negative numbers coincide with a negative situation.

 Ex: An increase in temperature corresponds to a positive number, and a decrease in temperature with a negative number.

The solution set for each rational inequality:

Case 1: - 9 ≤ x < - 5

Case 3: Every real number except x = 1.

In this problem we find two cases of rational inequality, whose solution sets can be found by using algebra properties and sign laws. Now we proceed to solve on each case:

Case 1

(3 · x + 7) / (x + 5) ≥ 5

(3 · x + 7) / (x + 5) - 5 ≥ 0

[(3 · x + 7) - 5 · (x + 5)] / (x + 5) ≥ 0

(- 2 · x + 18) / (x + 5) ≥ 0

- 2 · (x - 9) / (x + 5) ≥ 0

The inequality is positive for - 9 ≤ x < - 5.

Case 3

(- x² - 1) / (- x² + 2 · x - 1) > 0

[(- 1) · (x² + 1)] / [(- 1) · (x² - 2 · x + 1)] > 0

(x² + 1) / (x² - 2 · x + 1) > 0

(x² + 1) / (x - 1)² > 0

The inequality is positive for all real number except x = 1.

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1. Find the vertex (turning point) of the parabola by using the formula x = -b/2a, where a = 4 and b = 8. This gives x = -1, which is the x-coordinate of the vertex. To find the y-coordinate, substitute x = -1 into the equation: y = 4(-1)² + 8(-1) + 3 = -1.

2. Plot the vertex at the point (-1, -1).

3. To find the x-intercepts, set y = 0 in the equation and solve for x. This gives x = (-8 ± √(8² - 4(4)(3)))/(2(4)) = (-8 ± √16)/8 = -1/2 or -3. Plot these points on the x-axis.

4. To find the y-intercept, set x = 0 in the equation and solve for y. This gives y = 3, so the y-intercept is at the point (0, 3).

5. Since the coefficient of x² is positive, the parabola opens upwards. Sketch the curve passing through the points found above.

6. Label the points of intersection and the turning point on the graph.

Answer:

$12,276.24

Step-by-step explanation:

22000 / (1 + 0.105/12)^4*12

12276.24

The critical value that should be used in constructing the confidence interval is 2.132 (rounded to three decimal places).

What is Critical value ?

In statistics, a critical value is a threshold value that is used to determine whether to reject or fail to reject the null hypothesis in a statistical test. It is typically based on the significance level of the test, which is the probability of rejecting the null hypothesis when it is actually true.

To find the critical value for a 90% confidence interval with n = 5, we need to use a t-distribution with (n-1) degrees of freedom.

Using a t-distribution table or a calculator, we can find the critical value with a 90% confidence level and 4 degrees of freedom (n-1 = 5-1 = 4) to be approximately 2.132.

Therefore, the critical value that should be used in constructing the confidence interval is 2.132 (rounded to three decimal places).

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The integer values that make the statement true are x = -3, -2, -1, 1, 2, 3

We have,

We can start by multiplying both sides of the inequality by -3x to get rid of the denominators:

-3/x < -x/3

Multiplying by -3x on both sides.

-9 < -x²

Rearranging.

x² < 9

Taking the square root of both sides.

|x| < 3

This means that x can take any integer value between -3 and 3, excluding 0.

Thus,

The integer values are x = -3, -2, -1, 1, 2, 3

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There are 1100 many ways can be done that is when catering service offers 5 appetizers, 11 main courses, and 4 desserts.

Given that,

A catering service offers 5 appetizers, 11 main courses, and 4 desserts. A customer is to select 4 appetizers, 9 main courses, and 3 desserts for a banquet.

We have to find how many ways can this be done.

We know that,

Number of appetizers offered = 5

Number of appetizers customer is to select = 4

Number of main courses offered = 11

Number of main courses customer is to select = 9

Number of desserts offered = 4

Number of desserts the customer is to select = 3

So,

To determine the number of ways this can be selected,

By using the combination formula that is

[tex]^nC_r = \frac{n!}{r!(n-r)!}[/tex]
[tex]^nC_r = ^5C_4\times ^{11}C_9\times^4C_3[/tex]

[tex]^5C_4\times ^{11}C_9\times^4C_3 = \frac{5!}{4!(5-4)!} \times \frac{11!}{9!(11-9)!}\times \frac{4!}{3!(4-3)!}[/tex]

[tex]^5C_4\times ^{11}C_9\times^4C_3 = \frac{5!}{4!1!} \times \frac{11!}{9!2!}\times \frac{4!}{3!1!}[/tex]

[tex]^5C_4\times ^{11}C_9\times^4C_3 = \frac{5!}{4!} \times \frac{11!}{9!(2)}\times \frac{4!}{3!}[/tex]

[tex]^5C_4\times ^{11}C_9\times^4C_3 =[/tex] 5 × 11 × 5 × 4

[tex]^5C_4\times ^{11}C_9\times^4C_3 =[/tex] 1100

Therefore, There are 1100 many ways this can be done.

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Answer:

Expected number of times to roll a total of 5 = Probability of rolling a total of 5 x Total number of rolls

                                                      = (1/9) x 180

                                                      = 20

Step-by-step explanation:

The diagram is not visible in the question. However, I can provide a general method to solve the problem.

a) To find the probability of rolling a total of 5, we need to count the number of ways we can get a sum of 5 and divide it by the total number of possible outcomes. From the diagram, we can see that there are four ways to get a sum of 5: (1,4), (2,3), (3,2), and (4,1). Since each die has six equally likely outcomes, there are 6 x 6 = 36 possible outcomes in total. Therefore, the probability of rolling a total of 5 is:

Probability of rolling a total of 5 = Number of ways to get a total of 5 / Total number of possible outcomes

                                   = 4/36

                                   = 1/9 (in its simplest form)

b) If we rolled a pair of fair dice 180 times, the expected number of times we would roll a total of 5 can be calculated as follows:

Expected number of times to roll a total of 5 = Probability of rolling a total of 5 x Total number of rolls

                                                      = (1/9) x 180

                                                      = 20

a) A function for the amount of money in the account, B, after t months with an initial deposit of $100 isB(t) = [tex]100(1 + 0.002)^t[/tex]

b) The amount in the account increases by a factor of approximately 1.002 every month, approximately 1.025 every year and approximately 1.099 every five years.

a) The function for the amount of money in the account after t months with an initial deposit of $100 and an increase of 0.2% per month can be written as:

B(t) = [tex]100(1 + 0.002)^t[/tex]

where t is the number of months.

b) To determine the factor by which the amount in the account increases every month, year, and five years, we can calculate the value of the function for t = 1, t = 12, and t = 60, respectively, and then divide each value by the previous one.

For each month:

B(1) = 100(1 + 0.002) = $100.20

B(2) = 100(1 + 0.002)² = $100.40

B(2)/B(1) = $100.40/$100.20 = 1.001993

The amount in the account increases by a factor of approximately 1.002 every month.

For each year:

B(12) = 100(1 + 0.002)¹² = $102.44

B(24) = 100(1 + 0.002)²⁴ = $105.01

B(24)/B(12) = $105.01/$102.44 = 1.0249

The amount in the account increases by a factor of approximately 1.025 every year.

For every five years:

B(60) = 100(1 + 0.002)⁶⁰ = $110.41

B(120) = 100(1 + 0.002)¹²⁰ = $121.20

B(120)/B(60) = $121.20/$110.41 = 1.0991

The amount in the account increases by a factor of approximately 1.099 every five years. Therefore, the amount in the account increases by a small factor every month, a moderate factor every year, and a larger factor every five years.

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Step-by-step explanation:

To solve the inequality:

-3 > 5 - b

We can start by isolating the variable b on one side of the inequality. We can do this by subtracting 5 from both sides of the inequality:

-3 - 5 > -b

Simplifying the left-hand side of the inequality, we get:

-8 > -b

To isolate b, we can multiply both sides of the inequality by -1. When we do this, we need to reverse the inequality sign:

8 < b

So the solution to the inequality is:

b > 8

This means that b must be greater than 8 for the inequality to be true.

Answer:

----------------------

Use the following identities:

Apply the identities to the given expression:

The original price of this car is equal to $6,600.

In Mathematics, a percentage can be defined as any number that is expressed as a fraction of hundred (100). This ultimately implies that, a percentage indicates the hundredth parts of any given number.

Assuming the original price is represented by the variable x, we have the following:

12.5/100 × x = x - 5,775

0.125x = x - 5,775

5,775 = (x - 0.125x)

5,775 = 0.875x

x = 5,775/0.875

x = $6,600.

In conclusion, we can logically deduce that the percentage Pat Bain paid is 87.5%.

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Therefore , the solution of the given problem of unitary method comes out to be once more administer maths and science quizzes on the same day.

The well-known minimalist approach, current variables, and any crucial elements from the initial Diocesan tailored query can all be used to accomplish the work. In response, you can be granted another chance to utilise the item. If not, important impacts on our understanding of algorithms will vanish.

Here,

List the multiples of each integer until we discover a common multiple as one method to determine the least common multiple:

=> 8, 16, 24, 32, 40, 48, 56, 64, 72, and 80 are all multiples of 8.

=> 6, 12, 18, 24, 30, 36, 42, 48, 54, and 60 are multiples of 6.

As an alternative, we can use the prime factorization technique to identify the smallest common multiple:

=> 8's prime factors are 2 x 2 x 2

=> 6's prime factors are 2 x 3

=> 2 x 2 x 2 x 3 = 24

We can see that 24 is the smallest common multiple once more, and in 24 days,

Mrs Hopkins will once more administer maths and science quizzes on the same day.

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Answer:

Put your calculator in degree mode.

sin(35°) = 7/r

r sin(35°) = 7

r = 7/sin(35°) = 12.2 cm

In ΔFGH,  the length of h is 714.2 cm

Let us assume that in ΔFGH, f represents the opposite side to angle F, g represents the opposite side to angle G,  and h represents the opposite side to angle H.

Consider the following figure.

Using sine rule for triangle FGH,

sin F/f = sin G/g = sin H/h

Consider equation sin G/g = sin H/h

sin(98°) / 910 = sin(51°) / h

We solve this equation for h.

h = (sin(51°) × 910)/ sin(98°)

h =  (0.777 × 910)/ 0.99

h = 714.21

h = 714.2 cm

This is the required length of h.

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Answer:

[tex]y = -2(x - 1)^2 + 3[/tex]

Step-by-step explanation:

The given figure which is a quadratic is the shape of a parabola

The general vertex form equation of a parabola is
[tex]y = a(x - h)^2 + k[/tex]

where,
( h, k ) is the vertex and a is a constant

Looking at the figure we see the vertex is at [tex](1, 3)[/tex]

So the equation of the parabola is

[tex]y = a(x - 1)^2 + 3[/tex]

To compute the constant [tex]a[/tex] take a point (x, y) through which the parabola passes, plug in these x, y values into the above equation and solve

The parabola passes through point   [tex](3, -5)[/tex]

Plugging

[tex]x = 3, y = -5[/tex]

gives
[tex]- 5 = a(3-1)^2 + 3\\\\-5 = a\cdot 2^2 + 3\\\\-5 = 4a + 3\\\\-5-3=4a\\\\-8 = 4a\\\\a = -8/4 = -2\\\\[/tex]

Therefore the equation of the given quadratic(parabola) is

[tex]y = -2(x - 1)^2 + 3[/tex]

Unit fractions are the fraction in which the value of numerator is 1. The multiple of the given fraction are,

1/9 = 2/9, 3/9, 4/9,5/9         ......so on.

Here, we have,

To find the multiple of the fraction 1/9 we need to know about the multiple of fraction.

We have,

Multiple of fraction is the number which is n times of the original function. Here  can be any whole or fraction number.

The given number in the problem is the fraction number which is,

The above number is the unit fraction.

Unit fraction-

Unit fractions are the fraction in which the value of numerator is 1.

The multiple of unit fraction is in times the original function. For the given fraction the multiple fraction can be given as,

1/9 = 2/9, 3/9, 4/9,5/9            .......so on.

Hence the multiple of the given fraction are,

1/9 = 2/9, 3/9, 4/9,5/9             ......so on.

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The half-life of the particular compound is approximately 9.4 days. (Correct choice: B)

The statement indicates the decay function of a particular compound, which is an exponential function of the form:

y = a · exp(- λ · t)

Where:

The half-life of the particular compound is determined by the following expression:

t = ㏑ 2 / λ

Where t is the half-life.

If we know that λ = 0.0736, then the half-life of the particular compound is:

t = ㏑ 2 / 0.0736

t = 9.4 days

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Answer:

i believe 67 its somewhat hard to tell but the line seems to be in the middle between 150 and 140

Step-by-step explanation:

since it heats up to 212 then the person lets it cool down for 10 mins the temp goes to 145 (Answer is 67)

We know that cos(45) = sin(45) = √2/2.

Substituting these values, we can simplify the expression as follows:

4cos(45) - 2sin(45)

= 4(√2/2) - 2(√2/2) (substituting cos(45) and sin(45) values)

= 2√2 - √2

= √2

Therefore, the answer is √2.

The domain of the 1st piece is -10 < x < 0, for 2nd piece is 0 < x < 4, and for 3rd piece is 4 < x < 8.

A function is a particular kind of relationship where there is a set domain and range, and every input value in the domain is associated with a single output value in the range.

We have a piecewise function shown in the picture:

From the graph:

f(x) = -2, Domain: -10 < x < 0

f(x) = 2x + 1, Domain: 0 < x < 4

f(x) = (-1/2)x, Domaim: 4 < x < 8

Thus, the domain of the 1st piece is -10 < x < 0, for 2nd piece is 0 < x < 4, and for 3rd piece is 4 < x < 8.

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Answer:

198 ft^2

Step-by-step explanation:

l = 3

w = 3

h = 15

2(3*3) + 4(3*15) = 18 + 180

18 + 180 = 198 ft^2

needs more explanation

Step-by-step explanation:

y=m(x-x1)+y1

y=-2(x-4)+0

y=2x-8+0

y=2x-8

By the Principle of Mathematical Induction, 2ⁿ≥2n is true for all positive integers.

The given inequality is 2ⁿ≥2n.

Let n = 1

2^1 ≥ 2^1

2 ≥ 2 which is true

Inductive Step: Assume 2ⁿ≥2n is true for some arbitrary positive integer k.

We need to prove that 2^(k+1) ≥ 2^(k+1)

2^(k+1) ≥ 2*2^k (by the inductive hypothesis)

2^(k+1) ≥ 2*2^(k+1)

2^(k+1) ≥ 2^(k+1) which is true

Therefore, by the Principle of Mathematical Induction, 2ⁿ≥2n is true for all positive integers.

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The caloric content for ice cream C is 250 calories while the caloric content for ice cream B is 270 calories.

To determine the caloric content, we will assign algebraic notations to each of the dessert types.

1 Icecream + 2 Blueberry pie =   790 calories

3 icecream + 2 Blueberry pie = 1290 calories

Now the first equation will be subtracted from the second equation as follows:

2 icecream = 500 calories

So, 1 ice cream is 250 calories.

Also, since, 1 icecream serving equals 250 calories, 2 Blueberry pies = 790 - 250 = 540 calories, and 1 Blueberry pie equals 270 calories.

Complete question:

Johnny's cafe serves desserts. One serving of ice cream and two servings of blueberry pie provides 790 calories. Three servings of ice cream and two servings of blueberry pie provides 1290 calories. Find the caloric content of each item.

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Answer:

mt1= 995

mt2=975

Step-by-step explanation:

the line inside the box plot shows where the median is.