Plz, help me with this question!

Plz, Help Me With This Question!

Answers

Answer 1

Answer:

Rectangle

Step-by-step explanation:

If the base is a square that means the cross-section can also be a square.


Related Questions

Solve for x. Assume that lines which appear tangent

Answers

Answer:

Step-by-step explanation:

Join line EG with a straight edge.

Put a point in the middle of the circle.

Call it O.

GO and EO form a central angle.

GOE = 120 degrees

Any point on the circumference of a circle that is on the same side of EG as the peak of the central angle = 1/2 the central angle. It's much easier to do this with an example

Arc EOG = 120 degrees.       The Central angle = the arc.

EFG = 1/2 EOG

EFG = 1/2 120

EFG = 60

11x + 5 = 60                           Given

     -5       -5                           Subtract 5 from both sides.

11x        = 55                           Divide by 11

x = 55/11

x = 5

Please help will give brainliest

Answers

The answer will be A

Find the equation of the line that passes through (1,3) and is perpendicular to y=1−2x. Leave your answer in the form y=mx+c

Answers

Answer:

The equation of the line  that passes through (1,3) and is perpendicular to y=1−2x is y=1/2x+5/2

Step-by-step explanation:

We can rewrite the original equation as y=-2x+1

To find an equation's perpendicular slope, you take the reciprocal of it and negate it, therefore the perpendicular slope is -2 -> 1/-2 -> 1/2

So far, we have y=1/2x+b, but to find the y-intercept, b, we would need to plug in (1,3) and solve for b:

y=1/2x+b

3=1/2(1)+b

3=1/2+b

5/2=b

Therefore, your final equation is y=1/2x+5/2

is it positive, negative or is it zero​

Answers

Answer:

What do you mean?

Step-by-step explanation:

ILL BRAINLIEST YOU PLEASE HELP ME

Answers

Answer:

B

Step-by-step explanation:

Theorem: If a quadrilateral has 2 sets of opposite sides congruent, 2 sets of opposite angles congruent, and has consecutive angles which are supplementary, then it is a parallelogram.

Hope this helps!

hola me pueden ayudar es para hoy pliss doy coronita ✨​

Answers

Answer:

Step-by-step explanation:

A. 62

B. 58

C. -19

The answer is 622222

=D I have been stuck on this omg

Answers

Answer:

rectangular prism maybe

Step-by-step explanation:

Identifying Characteristics of an Exponential Function
Consider the function f(x) = (6). What is the value of the growth factor of the function?
02
06
O 18

Answers

The function be f(x) = (6) then growth factor for the given equation (b) = 6.

What is meant by exponential growth function?

Quantity grows exponentially over time. It happens when a quantity's instantaneous rate of change with regard to time is proportional to the quantity itself.

A function called exponential growth illustrates an expansion within a population that happens at the same pace across time. When a population's per capita growth rate remains constant across time, regardless of population size, exponential growth occurs, causing the population to grow exponentially as the population increases.

The general exponential growth function is given by :-

[tex]$f(t)=A b^t$[/tex] , where A is the initial amount , b is the growth factor and t is the time period.

The given function : [tex]$f(x)=(6)^x$[/tex]

When we compare it to the general exponential equation , we get

The growth factor for the given equation (b) = 6.

The complete question is:

Consider the function f(x) = (6)x. What is the value of the growth factor of the function?

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The function be f(x) = (6) then growth factor for the given equation (b) = 6.

What is meant by exponential growth function?

Quantity grows exponentially over time. It happens when a quantity's instantaneous rate of change with regard to time is proportional to the quantity itself.

A function called exponential growth illustrates an expansion within a population that happens at the same pace across time. When a population's per capita growth rate remains constant across time, regardless of population size, exponential growth occurs, causing the population to grow exponentially as the population increases.

The general exponential growth function is given by :-

F(t) = AB^t, where A is the initial amount , b is the growth factor and t is the time period.

The given function : f(t) = (6)^x

When we compare it to the general exponential equation , we get

The growth factor for the given equation (b) = 6.

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The complete question is:

Consider the function f(x) = (6)x. What is the value of the growth factor of the function?

which answer is this
A.43
B.38
C.61
D.81

Answers

it is 61 the angles should add up to 180
C.61

A triangle always has 180 degrees total so 81+38 = 119 and 180 - 119 = 61z

What are the 4 names of an angle?

Answers

The four names of an angle are acute angle, right angle, obtuse angle, and reflex angle.

An acute angle measures less than 90 degrees.

A right angle measures exactly 90 degrees.

An obtuse angle measures greater than 90 degrees but less than 180 degrees.

A reflex angle measures greater than 180 degrees but less than 360 degrees.

It's worth noting that these names are based on the measure of the angle, an acute angle is less than 90 degrees, a right angle is exactly 90 degrees, an obtuse angle is greater than 90 degrees but less than 180 degrees, and a reflex angle is greater than 180 degrees but less than 360 degrees.

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WAT IS GOOGOLPLEX PLZ HLP

Answers

Answer:

number

equivalent to ten raised to the power of a googol.

Step-by-step explanation:

A googolplex is the number 10, or equivalently, 10. Written out in ordinary decimal notation, it is 1 followed by 10¹⁰⁰ zeroes; that is, a 1 followed by a googol zeroes

The point N(-2,-3) is rotated 270° clockwise about the origin. What are the coordinates of N'?

A. (-3,-2)

B. (-3,2)

C. (3,-2)

Answers

The coordinate of N' is (2, -3)

Now, According to the question:

We have the point n (-2, -3) and we need to rotate it 270 degrees clockwise about the origin.

When rotating 270 clockwise about the origin you switch the x and y coordinate and use the opposite sign of the original y coordinate.

A(x, y) becomes A' (-y, x)

This means that point N becomes:

N (-2, -3) => N'(-(-2), (-3))

              => N'(2,- 3)

Hence, The coordinate of N' is (2, -3)

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Marla is four years less than twice as old as Darla. If the sum of their age is 47, how old is Marla?

Answers

According to the given algebra Darla is 17 years old and Maria is 30 years old.

What algebraic fundamentals are there?

Numbers, parameters, constants, expressions, equations, linear equations, and quadratic equations are all part of the fundamentals of algebra. Additionally, the algebraic expressions contain the fundamental arithmetic operations of addition, subtraction, multiplication, as well as division.

According to the given information.

Maria is 4 years younger than Don,

thus if Don is x years old, then Maria is x years younger. (2x-4)

If their ages added together equal 47,

then x + (2x-4) = 47

Solving for x, then determining Maria's age (2x-4)

3x=47+4

3x=51

x=51/3

x=17 years

Maria's age=2*17-4=30 years

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Each side of a square office is 8 yards long. It will cost $65.00 per square yard to replace the carpet in the office. What would be the total cost replace the carpet?

Answers

Answer:

520 because 65 x 8 is 520

Step-by-step explanation:

HELP ASAP!!!!


A person is standing 19 feet from the base of a tree and there is a bird's nest in the tree 10 feet above the groundWhat is the angle off elevation from the person to the bird's nest? Round to the nearest tenth of a degree

Answers

Answer:

do your own work don't ask any question

HELP ASAP WILL MARK BRAINLIEST AREA OF FIGURES

Answers

Answer:

1. 170.083 in³

2. 126π in³

3. 92.106 m³

4. 2412.74 in³

5. 612π m³ and 1922 m³

Step-by-step explanation:

1.

Cylinder:

[tex]V = \pi r^{2}h[/tex]               *Plug in numbers*

[tex](3.14)(2.5)^{2}(7)[/tex]         *Square 2.5*

[tex](3.14)(6.25)(7)[/tex]        *Solve*

≈ [tex]137.375in^{3}[/tex]

Sphere:

[tex]V = \frac{4}{3}\pi r^{3}[/tex]              *Plug in numbers*

[tex]\frac{4}{3} (3.14)(2.5)^{3}[/tex]         *Cube 2.5*

[tex]\frac{\frac{4}{3}(3.14)(15.625)}{2}[/tex]         *Divide by 2 and Solve*

≈ [tex]32.7083 in^{3}[/tex]

Add both volumes

[tex]137.375 + 32.7083[/tex] ≈ [tex]170.083in^{3}[/tex]

2.

Cylinder:

[tex]V = \pi r^{2}h[/tex]         *Plug in numbers*

[tex]\pi (3)^{2}(10)[/tex]            *Square 3*

[tex]\pi (9)(10)[/tex]             *Multiply*

[tex]90\pi[/tex]

Sphere:

[tex]V = \frac{4}{3}[/tex] π [tex]r^{3}[/tex]            *Plug in numbers*

[tex]\frac{4}{3}\pi (3)^{3}[/tex]                   *Cube 3*

[tex]\frac{4}{3} \pi (27)[/tex]                   *Multiply*

[tex]36\pi[/tex]

Add both Volumes to get total

[tex]90\pi + 36\pi = 126in^{3}[/tex]

3.

Sphere:

[tex]V = \frac{4}{3}\pi r^{3}[/tex]              *Plug in numbers*

[tex]\frac{4}{3} (3.14)(3)^{3}[/tex]            *Cube 3*

[tex]\frac{4}{3} (3.14)(27)[/tex]            *Multiply*

[tex]113.04m^{3}[/tex]

Cone:

[tex]V = \frac{\pi r^{2}h}{3}[/tex]             *Plug in numbers*

[tex]\frac{(3.14)(2)^{2}(5)}{3}[/tex]           *Square 2*

[tex]\frac{(3.14)(4)(5)}{3}[/tex]             *Solve*

[tex]20.93m^{3}[/tex]

Subtract the volumes to get the volume of the blue area

[tex]113.04 - 20.93 = 92.106m^{3}[/tex]

4.

Sphere:

[tex]V = \frac{4}{3} \pi r^{3}[/tex]            *Plug in numbers*

[tex]\frac{4}{3}\pi (8)^{3}[/tex]                 *Cube 8*

[tex]\\\frac{4}{3}\pi (512)[/tex]               *Multiply*

[tex]\\\\\pi (682.6)[/tex]              *Solve*

[tex]2133.66in^{3}[/tex]           *Divide by 2 since it's a hemisphere*

Cone:

[tex]V = \frac{\pi r^{2}h}{3}[/tex]            *Plug in numbers*

[tex]\frac{\pi (8)^{2}(20)}{3}[/tex]              *Square 8*

[tex]\frac{\pi (64)(20)}{3}[/tex]              *Multiply and Divide*

[tex]1340.41 in^{3}[/tex]

Add both volumes

[tex]1072.33 + 1340.41 = 2412.74in^{3}[/tex]

5.

Cylinder:

[tex]V = \pi r^{2}h[/tex]            *Plug in numbers*

[tex]\pi (6)^{2}(16)[/tex]              *Square 6*

[tex]\pi (36)(16)[/tex]             *Multiply*

[tex]576\pi[/tex]

Cone:

[tex]V = \frac{\pi r^{2}h}{3}[/tex]            *Plug in numbers*

[tex]\frac{\pi (6)^{2}3}{3}[/tex]                  *Square 6*

[tex]36\pi[/tex]

Add both volumes

[tex]576\pi + 36\pi = 612\pi m^{3}[/tex]

Alternative: *Multiply π*

[tex]1922m^{3}[/tex]

Answer:

1) 175 [tex]in^2[/tex]

2) 1st option

3) 92 [tex]m^2[/tex]

4) 2412 [tex]in^3\\[/tex]

5) 2nd option

Step-by-step explanation:

[tex]1)\ A = D * Pi = 5 * 3.14 = 15.7\\[/tex]

[tex]2)\ V_{1} = 15.7 * 7 = 109.9[/tex]

[tex]3)\ V_{2} = 4Pi*\frac{R^3}{3} = 12.56*\frac{15.625}{3} = 65.41(6)[/tex]

[tex]4)\ V_1 + V_2 = 65.4 + 109.9 = 175.3[/tex] which is close to 175

[tex]1)\ A = Pi * R^2 = 3.14 * (\frac{6}{2})^2 = 3.14 * 3^2 = 28.26\\[/tex]

[tex]2)\ V_1 = A * h = 28.26 * 10 = 282.6[/tex]

[tex]3)\ V_2 = \frac{4}{3} * Pi * R^3 = \frac{4}{3} * 3.14 * (\frac{6}{2})^3 = 113.04[/tex]

[tex]4)\ V_1 + V_2 = 282.6 + 113 = 395.6[/tex] which is very close to 396

[tex]5)\ 396 = 126 * pi[/tex]

[tex]1) V_1 = \frac{1}{3} * Pi * R^2 * h = \frac{1}{3} * 3.14 * 2^2 * 5 = 20.9(3)[/tex] =

[tex]2)\ V_2 = \frac{4}{3} * Pi * R^3 = \frac{4}{3} * 3.14 * 3^3 = 113.04\\[/tex]

[tex]3)\ V_2 - V_1 = 113.04 - 20.93 = 92.14[/tex] which is very close to 92

[tex]1)\ V_1 = \frac{\frac{4}{3} * Pi * R^3}{2} = \frac{\frac{4}{3} * 3.14 * 512}{2} = 1,071.786\\[/tex]

[tex]2)\ V_2 = \frac{1}{3} * Pi * R^2 * h = \frac{1}{3} * 3.14 * 64 * 20 = 1,339.733[/tex]

[tex]3)\ V_1 + V_2 = 1072 + 1340 = 2,411 = 2412[/tex]

[tex]1)\ A = Pi * R^2 = 36*Pi\\[/tex]

[tex]2)\ V_1 = 36*Pi * 16 = 576 * Pi\\[/tex]

[tex]3)\ V_2 = \frac{1}{3} * Pi * R^2 * h = \frac{1}{3} * Pi * 36 * 3 = 36 * Pi[/tex]

[tex]4) V_1 + V_2 = 576Pi + 36Pi = 612Pi[/tex]

Solve for x: 3(x + 1) = 2(x − 1)

Answers

Answer:

x= -5

Step-by-step explanation:

3x+3=2x-2

3x-2x=-3-2

x=-5

Answer:

x = -5

Step-by-step explanation:

First Expand the equation

3x+3 = 2x-2

Subtract 2x from both sides

x+3=-2

subtract 3 from both sides

x = -5

Hope this helps :)

Please help if you can ik it is Pythagorean theorem

Answers

Step-by-step explanation:

A = (1/2)bh ---> h = 2A/b = 2(12 cm^2)/(5 cm) = 4.80 cm

---> x^2 = h^2 + (b/2)^2

= (4.8 cm)^2 + (2.5)^2

= 23.04 cm^2 + 6.25 cm^2

or x = 5.41 cm

Therefore, the perimeter P is

P = 2x + b = 2(5.41 cm) + 5 cm = 15.8 cm

please no links or anything but the correct answer!

Answers

Answer:

sinD ≈ 0.44

Step-by-step explanation:

sinD = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{CE}{CD}[/tex] = [tex]\frac{39}{89}[/tex] ≈ 0.44 ( to the nearest hundredth )

Use the diagram to help you solve the equation 4x-12=16 how to do it

Answers

32 because if you -32+16 it would be 16

Find the nearest tenth

Answers

Answer:

8.6

Step-by-step explanation:

Mean = Sum of numbers/amount of numbers

= (11+13+8+9+4+8+7)/7

= 60/7

= 8.6

Can someone help me with this?

Answers

Answer:11 weekends

Step-by-step explanation:

it will take 11 weekends

A retailer is offering 5% off your total order, if you sign up for their email list. If your total is $254.20, how much will you save by signing up?

Answers

Answer:

$254.20 -  5%= 241.49 US$

so you will save up to 14

Which function is shown on the graph?
of(x) = 1/2cos x
of(x) = -1/2cos x
Of(x) = -1/2sin x
Of(x) = 1/2sin x

Answers

The reasons and responses to the graphs in the question are as follows:

Graph 1.

The amplitude of the first graph is (1/2) which is the height from the midline to the peak

The value of the function at x = 0 is -(1/2), where sin(0) = 0, therefore, the function is a cosine function

The period of the graph is 2·π, which is the period of the parent cosine function

Therefore, the correct option is

Graph 2: Please find attached the graph of the function g(x) = 2×cos(x)

Graph 3: The frequency of a sinusoidal function is given as follows;

The period of the graph = π

Therefore;

The frequency of the sinusoidal graph is 2

Graph 4.  Required:

To find the equation that represents the function of the graph

Solution;

The period of the function, T = π

The graph of the function has a maximum at x = 0, therefore, the graph is similar to a cosine function, y = cos(B·x)

Where;

B = 2·π/T

Therefore;

B = 2·π/π = 2

Therefore;

The equation that represent the function in the graph is f(x) = cos(2·x)

Question 5. The given function is f(x) = cos(2·x)

The frequency factor in the given function, B = 2

The period, T = 2·π/B

Therefore, T = 2·π/2 = π

The period of the function, f(x) = cos(2·x), is 2

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SinA + cosA = √2, prove that tanA + cotA = 2

Answers

[tex]sin(A)+cos(A)=\sqrt{2}\hspace{10em}tan(A)+cot(A)=2 \\\\[-0.35em] ~\dotfill\\\\ tan(A)+cot(A)=2\implies \cfrac{sin(A)}{cos(A)}+\cfrac{cos(A)}{sin(A)}=2 \\\\\\ \cfrac{sin^2(A)+cos^2(A)}{cos(A)sin(A)}=2\implies \boxed{\cfrac{1}{cos(A)sin(A)}=2} \\\\[-0.35em] ~\dotfill[/tex]

[tex]sin(A)+cos(A)=\sqrt{2}\implies (~~sin(A)+cos(A)~~)^2=(\sqrt{2})^2 \\\\\\ sin^2(A)+2sin(A)cos(A)+cos^2(A)=2 \\\\\\ 2sin(A)cos(A)+sin^2(A)+cos^2(A)=2\implies 2sin(A)+1=2 \\\\\\ 2sin(A)cos(A)=1\implies \boxed{2=\cfrac{1}{cos(A)sin(A)}}[/tex]

now, another way to look at this identity will  be as a unified system of equations

[tex]\begin{cases} (~~sin(A)+cos(A)~~)^2=2\\\\ ~~ ~tan(A)+cot(A)=2 \end{cases}\implies (~~sin(A)+cos(A)~~)^2=tan(A)+cot(A)[/tex]

and we'd end up with the same rigamarole.

⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ a(1)=20 a(n)=a(n−1)−17 ​ third term

Answers

The third term of the arithmetic sequence will be negative 14.

What is an arithmetic sequence?

A series of integers called an arithmetic succession or arithmetic chain of events has a fixed difference between the terms.

Let a₁ be the first term and d be a common difference.

Then the nth term of the arithmetic sequence is given as,

aₙ = a₁ + (n - 1)d

The first term is 20 and the common difference is calculated as,

aₙ = aₙ₋₁ - 17

aₙ - aₙ₋₁ = - 17

d = - 17

Then the third term is calculated as,

a₃ = 20 + (3 - 1) (-17)

a₃ = 20 + 2 (-17)

a₃ = 20 - 34

a₃ = - 14

The third term of the arithmetic sequence will be negative 14.

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a+ 1 1/6 = 11 7/9
...........................

Answers

Answer:

a = 191/81

Step-by-step explanation:

a+ 1 1/6 = 11 7/9

1 1/6 = 7/6

11 7/9 = 106/9

So, our equation is

a + 7/6 = 106/9

Subtract 7/6 from both sides

a = 191/81

So, the answer is

a = 191/81

Estimate how many times larger 1.9 • 10^-8 is than 4.2 • 10^-13

Answers

Answer:

Step-by-step explanation:

a.[tex]1.9[/tex]·[tex]10^{-8}[/tex]=190000·[tex]10^{-13}[/tex]

b.so 190000÷4.2=4523

c.finally, about 4523 times

To compare the two numbers, we need to compare the ratio of 1.9 • 10^-8 to 4.2 • 10^-13.

The first number, 1.9 • 10^-8, can be written as 0.00000019.
The second number, 4.2 • 10^-13, can be written as 0.000000000000042.

We can see that 1.9 • 10^-8 is much larger than 4.2 • 10^-13, as it has more trailing zeros. We can estimate that 1.9 • 10^-8 is about 45 times larger than 4.2 • 10^-13.

We can confirm this by counting the difference in the number of trailing zeros in both numbers. 1.910^-8 has 8 trailing zeroes and 4.210^-13 has 13 trailing zeroes, meaning 1.910^-8 is 8-13= -5 orders of magnitude larger than 4.210^-13

What is the area of the figure, pls hurry 100 points

Answers

Answer:

25 1/6 square yards

Step-by-step explanation:

I am assuming you mean the area of the shaded figure.

So, let's do it this way.

Let's subtract the total area from the unshaded area:

7 1/4 x 6 = 43 1/2

Area of non-shaded = 18 1/3

Area of shaded = 43 1/2 - 18 1/3 = 25 1/6

Hope that helps! :)

-Aphrodite

Someone please help with this! I’ll give brainliest.
With full working

Answers

Answer:

k = -2

Step-by-step explanation:

The value of k is -2

cuz the point D is marked at (1,-2)

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