Pythagorean theorem
1. a surveyor walked eight miles north, then three miles west. how far was she from her starting point?


2. a four meter ladder is one meter from the base of a building. how high up the building will the ladder reach?

3. what is the longest line you can draw on a paper that is 15 cm by 25 cm?

4. how long a guy wire is needed to support a 10 meter tall tower if it is faster
the foot of the tower?

5. the hypotenuse of a right triangle is twice as long as one of its legs.the other leg is nine inches long. find the length of the hypotenuse.

Answers

Answer 1

The distance traveled by the surveyor is √73 miles. The height of the building that the ladder reaches is √15 meters. The longest line that can be drawn is 5√34 cm. The length of the guy wire that is needed is 5√5 meters. The length of the hypotenuse of the given right triangle is 6√3 inches.

In a right-angled triangle that is a triangle with one of the angles with magnitude 90° following is true according to Pythogaras' Theorem:

[tex]A^2=B^2+C^2[/tex]

where A is the hypotenuse

B is the base

C is the height

1. According to the question,

the distance between the starting and the ending point is the hypotenuse of a right-angled triangle

B = 8 miles

C = 3 miles

A = √(64 + 9)

= √73 miles

2. Hypotenuse in the given question is the length of the ladder, thus,

A = 4 m

B = 1 m

16 = 1 + [tex]C^2[/tex]

C = √15 meters

3. The longest line that can be drawn on the paper is described as the hypotenuse of the triangle

C = √225 + 625

= 5√34 cm

4. The length of the guy wire is the hypotenuse of the triangle.

C = √100 + 25

= 5√5 meters

5. Let the base of the triangle be x

the hypotenuse be 2x

height = 9 inches

[tex]4x^2=x^2[/tex] + 81

[tex]3x^2[/tex] = 81

x = 3√3 inches

Hypotenuse = 2x = 6√3 inches

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Related Questions

Um need help this is so hard

Answers

Answer:Blue one.71.82

Step-by-step explanation:

6.3*11.4=71.82

Answer:

71.82 I think

Step-by-step explanation:

The Smith family goes to Happy Burger and orders 6 hamburgers and 3 fries for a total of $19. 50. The Jansen family also goes to Happy Burger and orders 8 hamburgers and 6 fries for a total of $29. 0. Write the system of equations that represents this situation and determine the cost of one hamburger and one order of fries. ​

Answers

The cost of one hamburger is $2.50 and the cost of one order of fries is $1.50.

Let's use h to represent the cost of one hamburger and f to represent the cost of one order of fries.

The Smith family's order can be represented by the equation:

6h + 3f = 19.50

The Jansen family's order can be represented by the equation:

8h + 6f = 29.00

We now have a system of two linear equations with two variables:

6h + 3f = 19.50

8h + 6f = 29.00

To solve for h and f, we can use the elimination method. We can start by multiplying the first equation by 2 to eliminate the variable f:

12h + 6f = 39.00

8h + 6f = 29.00

Subtracting the second equation from the first, we get:

4h = 10.00

Solving for h, we get:

h = 2.50

Now that we know the cost of one hamburger, we can substitute this value back into one of the original equations to solve for f. Using the first equation:

6h + 3f = 19.50

6(2.50) + 3f = 19.50

15 + 3f = 19.50

3f = 4.50

f = 1.50

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the line is parallel to the graph of 2x-3y=7 and contains the point (-3, -3)

Answers

The equation of the line that is parallel to the graph of 2x-3y=7 and contains the point (-3, -3) is expressed as: y = (2/3)x - 1.

What is the Equation of Parallel Lines?

To find the equation of a line that is parallel to the graph of 2x - 3y = 7, we need to determine the slope of the given line. We can rewrite the equation in slope-intercept form:

2x - 3y = 7

-3y = -2x + 7

y = (2/3)x - 7/3

This implies that the slope of this line is m = 2/3.

Thus, the equation of the line we are to find will take the following form:

y = (2/3)x + b

where b is the y-intercept of the line.

To find the y-intercept (b), substitute (x, y) = (-3, -3) and m = 2/3 into y = mx + b:

-3 = (2/3)(-3) + b

-3 = -2 + b

b = -1

Substitute m = 2/3 and b = -1 into y = mx + b:

y = (2/3)x - 1

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Check all that are inequalities.

-3 = y

t > 0

-4. 3 < a

g = 5 and one-half

k less-than Negative StartFraction 5 Over 7 EndFraction

x = 1



Anwer: B C E

Answers

The inequalities in the given options are: B) t > 0, C) 3 < a, E) k < -5/7, The correct option is B,C,E.

B) t > 0: This represents an inequality because the symbol ">" indicates "greater than." It states that the variable "t" is greater than zero. In other words, it means that "t" has to be a positive number and cannot be zero or negative.

C) 3 < a: This represents an inequality because the symbol "<" indicates "less than." It states that the number 3 is less than the variable "a." In other words, it means that "a" has to be greater than 3 for the inequality to hold true.

E) k < -5/7: This represents an inequality because the symbol "<" indicates "less than." It states that the variable "k" is less than -5/7. In other words, it means that "k" has to be a value smaller than -5/7 for the inequality to be true.

The other options, such as -3 = y, g = 5 and one-half, and x = 1, do not represent inequalities because they either show an equation (equality) or simply assign values to variables without any comparison.

Therefore the correct option is B,C,E.

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Joshua is building a model airplane that measures 45 inches. The measurements of the model can vary by as much as 0. 5 inches.



PART 2: Solve the equation to find the minimum and maximum measurements. Round to the nearest tenth if necessary

Answers

The minimum and maximum measurements taken by Joshua is 44.5 inches and 45.5 inches, under the condition that Joshua is building a model airplane that measures 45 inches.


Now in order to find the scale factor necessary to find the minimum and maximum measurements of Joshua's model airplane, we have to apply the given information.
The given information include that the difference in measurements of the model vary by 0. 5 inches.
Therefore,
Minimum measurement = 45 - 0.5 = 44.5 inches
Maximum measurement = 45 + 0.5 = 45.5 inches

Hence, the minimum measurement is 44.5 inches and the maximum measurement is 45.5 inches.

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Find < F:

(Round your answer to the nearest hundredth)

Answers

The length of the hypotenuse is approximately 7.21 ft.

To solve this problem, we can use the Pythagorean theorem, which states that in a right triangle, the sum of the squares of the two shorter sides (legs) is equal to the square of the longest side (hypotenuse). In mathematical terms, it looks like this:

a² + b² = c²

Where "a" and "b" are the lengths of the legs, and "c" is the length of the hypotenuse.

In your case, we can substitute the given values into the equation:

6² + 4² = c²

Simplifying:

36 + 16 = c²

52 = c²

To solve for "c," we need to take the square root of both sides of the equation:

√(52) = c

We can simplify the square root of 52 to be 2 times the square root of 13. Therefore:

c ≈ 7.21 ft

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Complete Question:

Find the value of hypotenuse of the given triangle by using the Pythagoras theorem.

What is the radius if you are given the diameter of 36 m?

Answers

Answer:

Radius = 18 m

Step-by-step explanation:

Given:

Diameter = 36 m

To find:

Radius

Explanation:

We know that,

Radius = Diameter/2 = 36/2 = 18 m

Final Answer:

18 m

Let C(t) be the carbon dioxide level in parts per million in the atmosphere where t is the time in years since 2000. Under two possible models the derivative functions are 1. C'(t) = 0.5 +0.025t II. C'(t) = 0.5e0.025 If the carbon dioxide level was 370 ppm in 2000, find C(t) for each model. Then find the carbon dioxide level in 2050 for each model. Using Model I., C(t) = and the carbon dioxide level in 2050 is C(50) = !!! ppm. Using Model II., C(t) = C(50) = and the carbon dioxide level in 2050 is !!

Answers

The carbon dioxide level in the atmosphere is modeled using two possible derivative functions. Using Model I, the level in 2050 is approximately 426.25 ppm, and using Model II, it is approximately 522.73 ppm.

Using Model I

We need to integrate the derivative function C'(t) = 0.5 + 0.025t to get C(t).

∫C'(t) dt = ∫0.5 + 0.025t dt

C(t) = 0.5t + (0.025/2)t^2 + C

Using the initial condition that C(0) = 370, we get

370 = 0 + 0 + C

C = 370

So, C(t) = 0.5t + (0.025/2)t^2 + 370

To find the carbon dioxide level in 2050 using Model I

C(50) = 0.5(50) + (0.025/2)(50)^2 + 370

C(50) = 25 + 31.25 + 370

C(50) = 426.25 ppm

Using Model II

We need to integrate the derivative function C'(t) = 0.5e^(0.025t) to get C(t).

∫C'(t) dt = ∫0.5e^(0.025t) dt

C(t) = (20e^(0.025t))/ln(10) + C

Using the initial condition that C(0) = 370, we get

370 = (20e^(0))/ln(10) + C

C = 370 - (20/ln(10))

So, C(t) = (20e^(0.025t))/ln(10) + (370 - (20/ln(10)))

To find the carbon dioxide level in 2050 using Model II

C(50) = (20e^(0.025(50)))/ln(10) + (370 - (20/ln(10)))

C(50) = 522.73 ppm (rounded to two decimal places)

Therefore, the carbon dioxide level in 2050 is approximately 426.25 ppm using Model I, and approximately 522.73 ppm using Model II.

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A school wants to rent out a laser tag arena the table shows the cost of renting the arena for different numbers of hours suppose the arena charges a constant hourly rate fill in the missing value in the table


hours _______ 5 9 -___________


cost (in dollars ) 500 1,250 __________ 3,500

Answers

The constant hourly rate using the given data points is  $100 per hour.

To calculate the constant hourly rate, we can use the given data points. For example, let's use the 5-hour rental for $500:

Hourly rate = Total cost / Number of hours
Hourly rate = $500 / 5 hours
Hourly rate = $100 per hour

Now, we can use this hourly rate to find the cost for the missing hour value in the table:

Cost = Hourly rate × Number of hours
Cost = $100 per hour × 9 hours
Cost = $900

So, the table will look like this:

Hours: _______ 5   |   9   |   _______
Cost (in dollars): 500 | 1,250 | 3,500

Now we can calculate the missing hours for the $3,500 cost:

Number of hours = Total cost / Hourly rate
Number of hours = $3,500 / $100 per hour
Number of hours = 35 hours

Now, the completed table is:

Hours: _______ 5   |   9   |   35
Cost (in dollars): 500 | 1,250 | 3,500

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Emilio saves 25% of the money he earns babysitting. he earns an average of $30 each week. which expression represents the change in emilio’s savings each week?

Answers

The expression that represents the change in Emilio's savings each week is $7.50.

How to find the Emilio savings?

Emilio saving 25% of the money he earns babysitting, which means that he saves a quarter of his earnings. This can be expressed mathematically as:

savings = 0.25 x earnings

where "savings" is the amount Emilio saves and "earnings" is the amount he earns each week.

Substituting the given value of Emilio's average weekly earnings of $30, we get:

savings = 0.25 x $30

savings = $7.50

Therefore, Emilio saves $7.50 each week.

Since the question asks for the change in Emilio's savings each week, the expression that represents this is simply:

$7.50

This means that Emilio's savings increase by $7.50 each week.

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please help me with this problem!! Image is attached, 20 points!!

Answers

The statement that must be true is the original prices of the refrigerator and the stove were the same. So the answer is option B.

Let x represent the original cost of the refrigerator and y represent the original cost of the stove. The refrigerator's sale price is 0.6x (40% off means paying 60% of the original price), while the stove's sale price is 0.8y (20% off means paying 80% of the original price).

To get the overall discount, multiply the total cost after the discount by the original total cost:

(0.6x + 0.8y) / (x + y)

We want this fraction to equal 0.7 (or 30% off), so we can set up the equation:

(0.6x + 0.8y) / (x + y) = 0.7

Simplifying this equation, we get:

0.6x + 0.8y = 0.7(x + y)

0.6x + 0.8y = 0.7x + 0.7y

0.1x = 0.1y

x = y

Therefore, the statement that must be true to conclude that Alfonso received a 30% overall discount on the refrigerator and stove together is: The original prices of the refrigerator and the stove were the same.

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Find the product. Assume that no denominator has a value of 0.
6r+3/r+6 • r^2 + 9r +18/2r+1

Answers

Answer:

Step-by-step explanation:

We can simplify the fractions first:

(3r + 9)(r+6) / (r+6) = 3r + 9

6r + 3 / (r + 6) = 3(2r + 1) / (r + 6)

(r^2 + 9r + 18) / (2r + 1) = (r^2 + 6r + 3r + 18) / (2r + 1) = [(r+3)(r+6)] / (2r + 1)

So the expression becomes:

[3(2r + 1) / (r + 6)] * [(r+3)(r+6) / (2r + 1)]

We can now cancel out the common factors:

[3 * (r+3)] = 3r + 9

Therefore, the simplified product is:

(3r + 9)(r+6) / (r+6) = 3r + 9

Match each angle description on the left with its possible angle measure, m, on the right.

Answers

Acute angle ⇒ 0⁰ < m < 90⁰

Straight angle ⇒  m = 180⁰

Obtuse angle ⇒ 90⁰ < m < 180⁰

Right angle ⇒ m = 90⁰

What is an obtuse angle?

An obtuse angle is an angle that measures greater than 90 degrees but less than 180 degrees. In other words, an obtuse angle is an angle that is wider than a right angle (90 degrees), but not as wide as a straight angle (180 degrees).

When two rays or line segments intersect at a point, they form an angle. If the angle formed is less than 90 degrees, it is called an acute angle. If the angle is exactly 90 degrees, it is called a right angle.

If the angle is greater than 90 degrees but less than 180 degrees, it is called an obtuse angle. Finally, if the angle measures exactly 180 degrees, it is called a straight angle.

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At Sugar Creek Middle School, there are two sizes of lockers for the students: one size for the sixth-grade and seventh-grade students and a larger size for the eighth-grade students. Both sizes of lockers are 5 feet tall and 1 foot wide. The lockers for the younger students each have a volume of 5 cubic feet, while the lockers for the eighth-grade students each have a volume of 7.5 cubic feet.

How much deeper are the lockers for the eighth-grade students than the lockers for the younger students?

Answers

I’m pretty sure the answer is 1.5

Find the area under the standard normal distribution curve between z=0 and z=0. 98

Answers

The area under the standard normal distribution curve between z = 0 and z = 0.98 is:

                         0.8365 - 0.5000 = 0.3365

To find the area under the standard normal distribution curve between z = 0 and z = 0.98, we can use a standard normal distribution table or a calculator that can compute normal probabilities.

Using a standard normal distribution table, we can look up the area corresponding to a z-score of 0 and a z-score of 0.98 separately and then subtract the two areas to find the area between them.

The area under the standard normal distribution curve to the left of z = 0 is 0.5000 (by definition). The area under the curve to the left of z = 0.98 is 0.8365 (from the standard normal distribution table).

So the area under the standard normal distribution curve between z=0 and z=0.98 is approximately 0.3365.

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Kenny decides he wants to buy Christmas presents for his mom and dad. He went to the mall with $150. At the mall, he bought his mom a watch for $68. 99 and arrows for his dad for $38. 99. He then bought himself lunch for $8. 99. Kenny wants to buy his parents one more gift for the both of them to share. Using an inequality, show how much money Kenny could spend on his last gift. What range of costs could he spend on his last gift?

Answers

The range of costs that Kenny could spend on his last gift would be any amount less than or equal to $33.03. So the range would be: $0 ≤ x ≤ $33.03

To determine the range of costs Kenny could spend on the last gift, we'll first calculate the total amount he has spent so far and subtract that from the $150 he started with.

Kenny has spent $68.99 (watch) + $38.99 (arrows) + $8.99 (lunch) = $116.97.

Now, let x represent the cost of the last gift. The inequality to represent the situation is:

116.97 + x ≤ 150

To find the range of costs for the last gift, subtract 116.97 from both sides of the inequality:

x ≤ 150 - 116.97
x ≤ 33.03

So, the range of costs Kenny could spend on the last gift is $0 to $33.03.

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The ratio of runners to walkers at the 10k fund-raiser was 5 to 7. if there
were 350 runners, how many walkers were there?

Answers

There were 490 walkers at the 10k fund-raiser.

The ratio of runners to walkers is 5:7, that means that the every five runners, there are 7 walkers so therefore we will use ratio formula.

If there have been 350 runners, we can use this ratio to discover what number of walkers there were:

5/7 = 350/x

Where x is the number of walkers.

To solve for x, we will cross-multiply:

5x = 7 * 350

5x = 2450

x = 490

Consequently, there were 490 walkers at the 10k fund-raiser.

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Use the given facts about the functions to find the indicated limit.


lim x->3 f(x)=0, lim x->3 g(x)=4 lim x->3 h(x)=2


lim x->3 6h/ 4f+g (x)



*there are no answer choices. Its a prompt*

Answers

The value of [tex]\lim_{x \to 3} \frac{6h}{4f+g} (x)[/tex] is 3

Given, [tex]\lim_{x \to 3} f(x)=0[/tex]

[tex]\lim_{x \to 3} g(x)=4[/tex]

[tex]\lim_{x \to 3} h(x)=2[/tex]

We have to find the value of [tex]\lim_{x \to 3} \frac{6h}{4f+g} (x)[/tex]

[tex]\lim_{x \to 3} \frac{6h}{4f+g} (x)=\lim_{x \to 3} \frac{6h(x)}{4f(x)+g(x)}[/tex]

[tex]= \frac{\lim_{x \to 3}6h(x)}{\lim_{x \to 3}4f(x)+\lim_{x \to 3}g(x)}[/tex]

[tex]=\frac{6\times 2}{4\times0+4}[/tex]

= 12/4

= 3

Hence, the value of [tex]\lim_{x \to 3} \frac{6h}{4f+g} (x)[/tex] is 3

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Use implicit differentiation to find the derivative of sin(y²)+x=eʸ

Answers

To find the derivative of sin(y²)+x=eʸ using implicit differentiation, we need to differentiate both sides of the equation with respect to x.

Starting with the left side, we use the chain rule and the derivative of sin(u), which is cos(u) times the derivative of u with respect to x:

d/dx(sin(y²)) = cos(y²) * d/dx(y²)

Using the power rule, we get:

d/dx(y²) = 2y * d/dx(y)

Putting it all together:

d/dx(sin(y²)) = 2y * cos(y²) * d/dx(y)

Now let's move on to the right side of the equation. The derivative of implicit function eʸ with respect to x is simply eʸ times the derivative of y with respect to x:

d/dx(eʸ) = eʸ * d/dx(y)

Putting it all together, we have:

2y * cos(y²) * d/dx(y) + 1 = eʸ * d/dx(y)

We can now solve for d/dx(y):

d/dx(y) = (1 - 2y * cos(y²)) / eʸ

Therefore, the derivative of sin(y²)+x=eʸ is:

d/dx(y) = (1 - 2y * cos(y²)) / eʸ.

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Madie and Clyde buy another circular plot of land, smaller than the first, on which to plant an orchard. They have set up coordinates as before, with the center of the orchard at (0, 0). They will plant trees at all points with integer coordinates that lie within the orchard, except at (0, 0).



In this orchard, the tree at (5, 12) is on the boundary. What are the coordinates of the other trees that must also be on the boundary? Explain your answer

Answers

The coordinates of the other trees that must also be on the boundary are (-5, 12), (5, -12), (-5, -12), (12, 5), (12, -5), (-12, 5), and (-12, -5).

The coordinates of the other trees that must be on the boundary of the circular orchard, given that the tree at (5, 12) is on the boundary and the center of the orchard is at (0, 0) can be determined as follows.

1. Calculate the radius of the orchard using the distance formula:

sqrt((x2-x1)^2 + (y2-y1)^2).

In this case, (x1, y1) = (0, 0) and (x2, y2) = (5, 12).

2. Radius = sqrt((5-0)^2 + (12-0)^2) = sqrt(5^2 + 12^2) = sqrt(25 + 144) = sqrt(169) = 13.

Now, we know the radius of the orchard is 13. To find the other boundary points, we can use the property of circles that states that the points on the boundary are equidistant from the center.

Since the coordinates are integers and symmetric, we can list the other points as follows:

3. The coordinates of the other trees on the boundary are:

(-5, 12), (5, -12), (-5, -12), (12, 5), (12, -5), (-12, 5), and (-12, -5).

These points are also 13 units away from the center, making them equidistant from the center and thus on the boundary of the circular orchard.

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Write your answers in percent form, rounded to the nearest tenth of a percent. Determine the probability of 3 rainy days in a row when the probability of rain on each single day is 56% Answer: % Determine the probability of 3 sunny days in a row when the probability of rain on each single day is 56% Answer: %

Answers

The probability of 3 rainy days in a row when the probability of rain on each single day is 56% ≈ 17.6%

The probability of 3 sunny days in a row when the probability of rain on each single day is 56% ≈ 8.5%

To determine the probability of 3 rainy days in a row, you need to multiply the probability of rain on each single day (56%). In percent form, this would be:

56% × 56% × 56% = 0.56 × 0.56 × 0.56 ≈ 0.175616

To express this as a percentage rounded to the nearest tenth, we have:

0.175616 × 100% ≈ 17.6%

Now, to determine the probability of 3 sunny days in a row, you first need to find the probability of a sunny day, which is the complement of the probability of rain:

100% - 56% = 44%

Next, multiply the probability of a sunny day (44%) for three days:

44% × 44% × 44% = 0.44 × 0.44 × 0.44 ≈ 0.085184

To express this as a percentage rounded to the nearest tenth, we have:

0.085184 × 100% ≈ 8.5%

So, the probability of 3 rainy days in a row is approximately 17.6%, and the probability of 3 sunny days in a row is approximately 8.5%.

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Cleo bought a computer for


$


1


,


495
. What is it worth after depreciating for


3


years at a rate of


16


%


per year?

Answers

After depreciating for 3 years at a rate of 16% per year, the computer is worth approximately $788.26.

To find the worth of the computer after depreciating for 3 years at a rate of 16% per year, we can use the formula for compound interest with depreciation.

Given:

Initial value (cost of the computer) = $1,495

Depreciation rate = 16% per year

Number of years = 3

1. Convert the depreciation rate to a decimal: 16% = 0.16.

2. Calculate the depreciation factor, which is (1 - depreciation rate):

Depreciation factor = 1 - 0.16 = 0.84.

3. Apply the formula for compound interest with depreciation:

Worth = Initial value * (Depreciation factor)^(Number of years).

Substituting the given values into the formula:

Worth = $1,495 * (0.84)^3.

Calculating the exponent:

Worth = $1,495 * 0.84 * 0.84 * 0.84.

Simplifying the expression:

Worth ≈ $788.26.

Therefore, after depreciating for 3 years at a rate of 16% per year, the computer is worth approximately $788.26.

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Find the critical points and the interval on which the given function is increasing or decreasing, and apply the First Derivative Test to each critical point. f(x) = ** + 5x 10x-60 (Use decimal notation)

Answers

The critical points of the given function f(x) = ** + 5x/ (10x-60) are x = 6 and x = -6/5. The function is decreasing on (-∞, -6/5) and increasing on (-6/5, 6) and (6, ∞). The First Derivative Test shows that x = -6/5 is a local maximum and x = 6 is a local minimum.

To find the critical points, we need to first find the derivative of the function. Using the quotient rule, we get:

f'(x) = (10x - 60)(**)' - **(10x - 60)' / (10x - 60)²

Simplifying, we get:

f'(x) = 50 / (10x - 60)²

The critical points occur where the derivative is zero or undefined. Here, the derivative is never undefined, so we only need to find where it is zero:

50 / (10x - 60)² = 0

This occurs when x = 6 and x = -6/5.

Next, we need to determine the intervals on which the function is increasing or decreasing. To do this, we can use the first derivative test. We test a value in each interval of interest to see if the derivative is positive or negative:

For x < -6/5, we choose x = -2:

f'(-2) = 50 / (10(-2) - 60)² = -5/81 < 0

Therefore, the function is decreasing on (-∞, -6/5).

For -6/5 < x < 6, we choose x = 0:

f'(0) = 50 / (10(0) - 60)² = 5/9 > 0

Therefore, the function is increasing on (-6/5, 6).

For x > 6, we choose x = 10:

f'(10) = 50 / (10(10) - 60)² = 5/81 > 0

Therefore, the function is increasing on (6, ∞).

Finally, we can use the First Derivative Test to determine the nature of the critical points.

For x = -6/5:

f'(-6/5 - ε) < 0 and f'(-6/5 + ε) > 0, for small values of ε.

Therefore, x = -6/5 is a local maximum.

For x = 6:

f'(6 - ε) < 0 and f'(6 + ε) > 0, for small values of ε.

Therefore, x = 6 is a local minimum.

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In the diagram below, DE is parallel to AB. If CE = 2,
AC = 3.6, AB = 4.2, and DC = 2.4, find the length of CB.
Figures are not necessarily drawn to scale.

Answers

The length of CB is 3 unit.

In the given figure ;

By SAS property of similar of triangles,

ΔCED and ΔCAB are similar.

Therefore,

CE/CB = DE/AB = DC/AC

⇒ CE/CB = DC/AC

⇒ 2/CB = 2.4/3.6

⇒ CB = (3.6/2.4)X2 = 3

Hence CB = 3

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A newspaper for a large city launches a new advertising campaign focusing on the number of digital subscriptions. The equation S(t)=31,500(1. 034)t approximates the number of digital subscriptions S as a function of t months after the launch of the advertising campaign. Determine the statements that interpret the parameters of the function S(t)

Answers

The parameters of the function S(t)=31,500(1.034)t are the initial number of digital subscriptions, which is 31,500, and the monthly growth rate, which is 3.4%.

How to find the parameters of the function?

The given function S(t)=31,500(1.034)t is a exponential growth function that models the number of digital subscriptions S as a function of t months after the launch of the advertising campaign. The parameters of the function are the initial number of digital subscriptions, which is 31,500, and the monthly growth rate, which is 3.4%.

The initial value of 31,500 represents the number of digital subscriptions at the start of the advertising campaign. This means that the campaign began with 31,500 digital subscribers.

The monthly growth rate of 3.4% represents the rate at which the number of digital subscriptions is increasing each month due to the advertising campaign. This means that for each month after the launch of the campaign, the number of digital subscribers is increasing by 3.4% of the previous month's total.

For example, after one month, the number of digital subscribers would be:

S(1) = 31,500(1.034)1 = 32,687

After two months, the number of digital subscribers would be:

S(2) = 31,500(1.034)2 = 33,912

And so on...

Therefore, the initial value and monthly growth rate are important parameters that help us understand how the number of digital subscriptions is changing over time due to the advertising campaign.

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how many different triangles can be formed by side lengths 2 cm, 7cm, and 70 degrees angle formed by these given sides?

Answers

It's not possible to form a triangle with side lengths of 2 cm, 7 cm, and a 70-degree angle formed by these sides. The length of the side opposite the 70-degree angle would need to be longer than the sum of the other two sides, which is not possible.

Rule: y is 8 less than 4 times x

Answers

Answer:

y = 8 - 4x

" is" is express the equal sighn

"less than" express - sighn so you will write the equestion as

y = 8 - 4x

Probability & Sampling:Question 1


Stephanie recorded the time, in minutes, she took to walk


from home to work.


{15, 16, 18, 20, 21)


She also recorded the time, in minutes, she took to walk


from work to home.


(14, 21, 21, 25, 27)


Based on the data she collected, what is the best


conclusion Stephanie can make?

Answers

"Based on the data Stephanie collected, the best conclusion she can make is that her commute time varies between walking from home to work and walking from work to home."

Stephanie recorded the time it took for her to walk from home to work and from work to home. The recorded times for walking from home to work are 15, 16, 18, 20, and 21 minutes. The recorded times for walking from work to home are 14, 21, 21, 25, and 27 minutes.

From the given data, we can see that Stephanie's commute time is not consistent. The time it takes for her to walk from home to work varies between 15 and 21 minutes, and the time it takes for her to walk from work to home varies between 14 and 27 minutes. There is no clear pattern or trend in the data.

Therefore, the best conclusion Stephanie can make is that her commute time fluctuates, and it is not fixed or predictable. The specific duration of her commute can vary from day to day.

In conclusion, Stephanie's commute time varies between walking from home to work and walking from work to home, as indicated by the range of recorded times for each direction.

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How much will the monthly payment be for a new car priced at $29,950 if the current finance rate is 36 months at 3. 16%? Include financing the 8% TT&L and make a 25% down payment.



I need the answer fast!!

Answers

The monthly payment for a new car priced at $29,950 with financing the 8% TT&L and making a 25% down payment at a current finance rate of 3.16% for 36 months is approximately $698.62.

How to find calculate the monthly payment?

To calculate the monthly payment for a new car priced at $29,950 with the current finance rate of 3.16% for 36 months, we need to consider several factors, including the down payment and taxes.

First, we need to calculate the total cost of the car, including the taxes, title, and license (TT&L) fees. We can do this by adding 8% of the car's price ($29,950) to the price of the car, which comes to $32,346 ($29,950 + 8% of $29,950).

Next, we need to calculate the amount of the down payment. A 25% down payment on $32,346 comes to $8,086.50 ($32,346 x 0.25).

Subtracting the down payment from the total cost of the car gives us the amount we need to finance, which is $24,259.50 ($32,346 - $8,086.50).

Now, we can use a loan calculator to determine the monthly payment. Based on these figures, the monthly payment would be approximately $698.62 per month for 36 months.

In summary, to calculate the monthly payment for a new car priced at $29,950 with the current finance rate of 3.16% for 36 months, we need to consider the total cost of the car, including taxes and fees, the down payment, and the amount to be financed. The monthly payment is then calculated using a loan calculator, which gives us a monthly payment of $698.62 for 36 months.

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Lindsey wears a different outfit every day. Her outfit consists of one top, one bottom, and one scarf.
How many different outfits can Lindsey put together if she has 3 tops, 3 bottoms, and 3 scarves from which to choose? (hint: the
counting principle)
A)3 outfits
B )9 outfits
C)24 outfits
D )27 outfits

Answers

Lindsey can put together 27 different outfits if she has 3 tops, 3 bottoms, and 3 scarves to choose from. The answer is (D) 27 outfits.

How to determine How many different outfits can Lindsey put together

To find the number of different outfits that Lindsey can put together, we need to use the counting principle, which states that if there are m ways to do one thing and n ways to do another thing, then there are m x n ways to do both things together.

In this case, there are 3 ways for Lindsey to choose a top, 3 ways to choose a bottom, and 3 ways to choose a scarf. To find the total number of outfits, we multiply these numbers together:

Total number of outfits = number of tops x number of bottoms x number of scarves

Total number of outfits = 3 x 3 x 3

Total number of outfits = 27

Therefore, Lindsey can put together 27 different outfits if she has 3 tops, 3 bottoms, and 3 scarves to choose from. The answer is (D) 27 outfits.

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