We know that when you have this data, you can proceed with calculating the confidence intervals to determine IMM Thai's lead.
Hi there! The survey results seem to indicate that IMM Thai is indeed ahead of the other Thai restaurants among the voters.
To determine a range of likely values for IMM Thai's true lead over Lucky House, Thai Temple, and Thai Basil combined, you would need to calculate confidence intervals.
Unfortunately, I cannot provide specific calculations without the necessary data (sample size, mean, standard deviation, etc.).
Once you have this data, you can proceed with calculating the confidence intervals to determine IMM Thai's lead.
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Evaluate the line integral JF. dr where F = (-2 sin x, 2 cos y, 6zx) and C is the path given by r(t) = (3t^3, -3t^2, -3t) for 0 <= t <= 1
To evaluate the line integral JF.dr, where F = (-2 sin x, 2 cos y, 6zx) and C is the path given by r(t) = (3t^3, -3t^2, -3t) for 0 <= t <= 1, we first need to parameterize F and r in terms of t.
For F, we have:
F = (-2 sin x, 2 cos y, 6zx) = (-2 sin (3t^3), 2 cos (-3t^2), 6(3t^3)(-3t)) = (-2 sin (3t^3), 2 cos (3t^2), -54t^4)
For r, we already have the parameterization:
r(t) = (3t^3, -3t^2, -3t)
Now we can use the formula for the line integral:
JF.dr = ∫(F dot dr)
= ∫(-2 sin (3t^3) dx + 2 cos (3t^2) dy - 54t^4 dz)
= ∫(-18t^2 cos (3t^2) + 18t^2 cos (3t^2) - 54t^4) dt
= ∫(-54t^4) dt
= -9t^5 + C
Evaluating this expression for t = 1 and t = 0, we get:
JF.dr = (-9(1)^5 + C) - (-9(0)^5 + C)
= -9 + 9
= 0
Therefore, the line integral JF.dr evaluated along the path given by r(t) = (3t^3, -3t^2, -3t) for 0 <= t <= 1 is equal to 0.
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A person standing on the ground throws a rock upward with an initial velocity of 16 feet per second. The person’s hand is 12 feet above the ground when the rock is released. This is modeled by the equation h = -16^2 + 16t + 12. How long does it take for the rock to hit the ground?
It will take the rock 1.5 seconds to hit the ground
How to determine how long it take for the rock to hit the ground?Since the situation is modeled by the equation h = -16t² + 16t + 12
The rock will hit the ground when height is zero i.e. h = 0. Thus, we have:
-16t² + 16t + 12 = 0 and we can then solve for the time (t) .
-16t² + 16t + 12 = 0 (divide through by -16)
t² - t - 3/4 = 0
Using factorization method:
(t + 1/2) (t - 3/2) = 0
t = -1/2 or 3/2
Since t cannot be negative. Thus, t = 3/2 = 1.5.
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A community center charges x dollars for a summer activity if individuals are signed up before the day of the activity. Individuals who sign up the day of the activity are charged a fee of x plus 0. 20 x dollars. Which expression also represents the fee for signing up the day of the activity, and what does it mean about the fee?.
The expression that represents the fee for signing up the day of the activity is x + 0.20x. This means that fee for signing up the day of the activity is original fee (x) plus an additional 20% of original fee (0.20x).
For example, if the community center charges $50 for signing up before the day of the activity, then the fee for signing up the day of the activity would be:
$50 + ($50 x 0.20) = $50 + $10 = $60
So, individuals who sign up the day of the activity are charged a higher fee than those who sign up before the day of the activity, because they are charged the original fee plus an extra 20% of the original fee. This is often used as an incentive for individuals to sign up early and to help the community center plan and prepare for the activity accordingly.
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Suppose an amusement park is being built in a city with a population of 100. Voluntary contributions are being solicited to cover the cost. Each citizen is being ask to give $100. The more people contribute, the larger the park will be and the greater the benefit to each citizen. But it is not possible to keep out the noncontributors; they get their share of this benefits anyway. Suppose that when there are n contributors in the population, where n can be any whole number between 0 and 100. The benefit to each citizen in monetary unit equivalents in n 2 dollars.
Required:
a. Suppose that initially no one is contributing. You are the mayor of the city. You would like everyone to contribute and can use persuasion on some people. What is the minimum number whom you need to persuade before everyone else will join voluntarily?
b. Find the Nash equilibria of the game where each citizen is deciding whether to contribute
The minimum number of people that need to be persuaded is two. When there are 0 contributor, 1 contributor, 2 or more contributor this is a the Nash equilibria.
a. Let's first calculate the benefit to each citizen when there are n contributors. According to the problem, the benefit is n^2 dollars. So when there are 0 contributors, the benefit to each citizen is 0 dollars. When there is 1 contributor, the benefit to each citizen is 1 dollar. When there are 2 contributors, the benefit to each citizen is 4 dollars. And so on, up to 10,000 dollars per citizen when all 100 citizens contribute.
Now let's think about the incentives of each citizen to contribute. If no one contributes, everyone gets 0 dollars of benefit. If one person contributes, that person gets 1 dollar of benefit, and everyone else gets 0 dollars. So each person has an incentive to free-ride, hoping that someone else will contribute.
But if two people contribute, each person gets 4 dollars of benefit, which is more than the 1 dollar cost of contributing. So once there are at least two contributors, it becomes rational for everyone else to contribute as well.
Therefore, the minimum number of people that need to be persuaded is two. Once two people contribute, it becomes rational for everyone else to contribute as well.
b. Let's consider the Nash equilibria of the game where each citizen is deciding whether to contribute. A Nash equilibrium is a situation where no one has an incentive to change their strategy, given the strategies of all the other players.
In this case, each citizen has two strategies: contribute or free-ride. Let's consider the case where n citizens are contributing. If everyone else is contributing, then it is rational to contribute as well, since the benefit of contributing is greater than the cost.
If everyone else is free-riding, then it is rational to free-ride as well, since the cost of contributing is greater than the benefit. However, if some people are contributing and some people are free-riding, then it may be rational to contribute, since the benefit of contributing may outweigh the cost, depending on the number of contributors.
Therefore, there are multiple Nash equilibria in this game, depending on the number of contributors. When there are 0 contributors, everyone is free-riding and this is a Nash equilibrium. When there is 1 contributor, that person is contributing and everyone else is free-riding, and this is a Nash equilibrium. When there are 2 or more contributors, everyone is contributing, and this is a Nash equilibrium.
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A cross section of the cylinder with the cone removed is a ring. To find the area of the ring, find the area of the outer circle and of the inner circle. Then subtract the area of the inner circle from the outer circle.
The area of the outer circle and of the inner circle is : πr² and, πx².
Then subtract the area of the inner circle from the outer circle is :
π (r - x) (r+x)
Here, we have,
Given:
Let the radius of outer circle i.e CA be r
Let the radius of inner circle i.e CB be x
The diagram is given below as attachment.
We know that,
area of circle = πR²
Then subtract the area of the inner circle from the outer circle is:
The area of the outer circle - area of the inner circle
= πr² - πx²
= π (r² - x²)
=π (r - x) (r+x)
So, we get
Then subtract the area of the inner circle from the outer circle is:
π (r - x) (r+x)
Hence, The area of the outer circle and of the inner circle is : πr² and, πx².
Then subtract the area of the inner circle from the outer circle is :
π (r - x) (r+x)
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Three vertices of parallelogram wxyz are w(-5,2), x(2,4), and z(-7, -3). find the coordinates of vertex y.
the coordinates of vertex y are
Coordinates of vertex y are (-12,-1).
How to find the coordinates of vertex Y?To find the coordinates of vertex y in parallelogram WXYZ, we can use the fact that opposite sides of a parallelogram are parallel. We can use this property to find the coordinates of y by first finding the vector between points X and Z, and then adding that vector to the coordinates of point W.
The vector between points X and Z is (-7-2,-3-4)=(-9,-7). Adding this vector to the coordinates of point W gives (-5-9, 2-7)=(-14,-5). Therefore, the coordinates of vertex Y are (-14,-5).
Hence, the coordinates of vertex Y in the parallelogram WXYZ are (-14, -5).
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11. a bird makes a dive off a cliff to catch a fish in a lake. the path of the dive follows a
parabolic curve of the given function f(x) = (x-7)2 - 1 where f(x) represents the height of
the bird in meters, and x represents the time in seconds. how far was the fish from the bird?
The fish has located a horizontal distance of 7 meters away from the cliff.
How to find the distance between the bird and the fish?
To find the distance between the bird and the fish, we need to find the horizontal distance traveled by the bird during the dive. We can do this by finding the x-coordinate of the vertex of the parabolic curve, which represents the highest point of the dive.
The vertex of the parabolic curve of the given function f(x) = (x-7)^2 - 1 is at the point (7, -1). This means that the highest point of the bird's dive is reached at 7 seconds, and the bird is at a height of -1 meters at this point.
To find the distance traveled by the bird during the dive, we need to find the horizontal distance between the bird's starting point (the cliff) and the highest point of the dive (the vertex). The distance is given by the horizontal coordinate of the vertex, which is 7 seconds.
Therefore, the fish has located a horizontal distance of 7 meters away from the cliff, assuming that the bird started the dive from the edge of the cliff.
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if f' * (x) = 2x - 1 and g(x) - x + 3 prove that f g(x) is a linear function
The composite function fg(x) is a linear function by the proof shown below
Proving that the function fg(x) is a linear functionFrom the question, we have the following parameters that can be used in our computation:
f(x) = 2x - 1
g(x) = -x + 3
The above functions are linear functions
This means that the function fg(x) will also be a linear function
To prove this, we have
f(g(x)) = 2(g(x)) - 1
substitute the known values in the above equation, so, we have the following representation
f(g(x)) = 2(-x + 3) - 1
So, we have
f(g(x)) = -2x - 7
Hence, the function is a linear function
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Peter picks one bill at a time from a bag and replaces it,
He repeats this process 100 times and records the results in
the table.
Peter's Experiment
Value Frequency
$1 28
14
$10 56
$20 2
Based on the table, which bill has an experimental
probability of 3 for being drawn from the bag next?
None of the bills have an experimental probability of 3, as all probabilities are between 0 and 1.
Based on the table, the experimental probability for each bill being drawn from the bag next can be calculated by dividing the frequency of each bill by the total number of draws (100). Using this formula, we can calculate the experimental probabilities for each bill:
1. For the $1 bill: Experimental probability = [tex]\frac{(Frequency of $1 bill)}{Total draws} = \frac{8}{100} = 0.28[/tex]
2. For the $10 bill: Experimental probability =[tex]\frac{(Frequency of $10 bill)}{Total draws} = \frac{56}{100} = 0.56[/tex]
3. For the $20 bill: Experimental probability =[tex]\frac{(Frequency of $20 bill)}{Total draws} = \frac{2}{100} = 0.02[/tex]
None of the bills have an experimental probability of 3, as all probabilities are between 0 and 1.
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The note below depict a triangle prism. What is the total surface area of the prism?
How do you set it up and solve?
The total surface area of the prism is 282
What is the total surface area of the prism?From the question, we have the following parameters that can be used in our computation:
The net of a triangle prism.
The total surface area of the prism is the sum of the individual shapes
So, we have
Surface area = 2 * 1/2 * 6 * 5 + 3 * 6 * 14
Evaluate
Surface area = 282
Hence. the total surface area of the prism is 282
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Answer:
The total surface area is 282
Let and be two ordered bases of , and consider a linear transformation. Suppose that the change of base matrix is given by and the coordinate matrix of with respect to is given by use this to determine coordinate matrix of with respect to.
The coordinate matrix of the linear transformation with respect to the second ordered basis is found by multiplying the change of basis matrix by the coordinate matrix of the linear transformation with respect to the first ordered basis is [tex]\left[\begin{array}{cc}0&2/5\\1&-1/5\end{array}\right][/tex]
Let V be a vector space with two ordered bases B and B', and let T be a linear transformation from V to V. Suppose that the change of basis matrix from B to B' is P, and the coordinate matrix of T with respect to B is A.
To find the coordinate matrix of T with respect to B', we can use the formula
A' = P⁻¹AP
where A' is the coordinate matrix of T with respect to B'.
To use this formula, we need to find the inverse of P. If P is invertible, then we have
P⁻¹ = 1/det(P) * adj(P)
where det(P) is the determinant of P and adj(P) is the adjugate of P.
Assuming that P is invertible, we can compute its inverse as follows
det(P) = 1*(-2) - 2*2 = -5
adj(P) =[tex]\left[\begin{array}{cc}-2&2\\-2&1\end{array}\right][/tex]
So, P⁻¹ = (-1/5)*[tex]\left[\begin{array}{cc}-2&2\\-2&1\end{array}\right][/tex] = [tex]\left[\begin{array}{cc}2/5&-2/5\\2/5&-1/5\end{array}\right][/tex]
Now, we can use the formula to find the coordinate matrix of T with respect to B'
A' = P⁻¹AP = *[tex]\left[\begin{array}{cc}-2&1\\-1&0\end{array}\right][/tex]*[tex]\left[\begin{array}{cc}-1&2\\2&1\end{array}\right][/tex]= [tex]\left[\begin{array}{cc}0&2/5\\1&-1/5\end{array}\right][/tex]
Therefore, the coordinate matrix of T with respect to B' is
[tex]\left[\begin{array}{cc}0&2/5\\1&-1/5\end{array}\right][/tex]
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--The given question is incomplete, the complete question is given
" Using change of base matrices to find coordinate matrices of linear transformations Let B and C be two ordered bases of R2, and consider a linear transformation T: R2 + R2. Suppose that the change of base matrix Ic, B is given by [0 -2 3 3] and the coordinate matrix Tc,c of T with respect to C is given by [ -1 -1 2 -1] Use this to determine coordinate matrix TB,B of T with respect to B. TB,B ? "--
A random sample of 155 observations results in 62 successes. [You may find it useful to reference the z table.]a. Construct the a 90% confidence interval for the population proportion of successes. (Round intermediate calculations to at least 4 decimal places. Round "z" value and final answers to 3 decimal places.)b. Construct the a 90% confidence interval for the population proportion of failures. (Round intermediate calculations to at least 4 decimal places. Round "z" value and final answers to 3 decimal places.)
For a random sample of 155 observations results in 62 successes.
a) A 90% confidence interval for the population proportion of successes is equals to the (0.335 , 0.465).
b) A 90% confidence interval for the population proportion of failure is equals to the (0.535 , 0.665).
We have a random sample of 155 observations results in 62 successes. So,
Observed value, x = 62
Sample size,n = 155
Population Proportion, p = x/n
= 62/155
= 0.4
a) We have to determine 90% confidence interval for the population proportion of successes. Using the distribution table, for 90% confidence interval, z-score value is equals to 1.6. Consider Confidence interval formula with proportion, CI [tex]= p ± z×\sqrt\frac{p(1-p)}{n}[/tex]
substitute all known values in above formula, [tex]= 0.4 ± 1.64\sqrt\frac{0.4(1- 0.4)}{155}[/tex]
= 0.4 ± 0.0645
= (0.4 - 0.0645 , 0.4 + 0.0645)
= (0.335 , 0.465)
b) Now, we have to determine a 90% confidence interval for the population proportion of failures.
Now consider, here failure observed values, x = 155 - 62
= 93
proportion, p = x/n
= 93/155 = 0.6
Consider the confidence interval formula, CI [tex]= p ± z×\sqrt\frac{p(1-p)}{n}[/tex]
substitute values, [tex]= 0.6 ±1.64×\sqrt\frac{0.6(1-0.6)}{155}[/tex]
= 0.6 ± 0.0645
= (0.6 - 0.0645 , 0.6 + 0.0645)
= (0.535 , 0.665)
Hence, required value is (0.535 , 0.665).
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Solve the following diamond problem by finding the answers that would go in box 1 and box 2
20x?
sot
box2
-9x
box 1 =
box 2 =
Answer:
Step-by-step explanation:
The missing numbers are: box 1 = -5x and box 2 = 4sot, A diamond problem is a type of math puzzle that involves finding two missing values in a diamond-shaped diagram.
The top and bottom numbers of the diamond represent a product, and the left and right sides represent two numbers that add up to a middle value. The goal is to find the two missing values that fit into the diamond.
To solve a diamond problem, we need to factor the product of the top and bottom numbers and look for two factors whose sum is equal to the middle value. This is because the product of two numbers can only be made up of factors that multiply together to form the product. Once we find the two factors, we can insert them into the left and right sides of the diamond.
In the given diamond problem, we have 20x? as the top and sot as the bottom. The product of these two numbers is 20x^2sot. To find the factors, we can list all the possible factor pairs of this product and check which of them adds up to -9x, which is the middle value in the diamond. We found that -5x and 4sot are the factors that add up to -9x.
Solving diamond problems can help improve factoring skills and problem-solving abilities. It requires logical thinking and an understanding of how factors and multiples work. Additionally, diamond problems can be used to introduce algebraic concepts to students in a visual and intuitive way, making them a useful tool for teaching math to learners of all ages.
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h(x)=|2x|-8 domain and range
For the function "h(x) = |2x| - 8", the domain is (-∞, ∞) and the range is [-8, ∞).
The function h(x) = |2x| - 8 is defined for all real numbers x, so the domain of h(x) is the set of all real-numbers, or (-∞, ∞).
To find the range of the function, we determine set of all possible output values of function. Since the function involves the absolute value of 2x, the output can never be less than -8.
When "2x" is positive, |2x| = 2x. When 2x is negative, |2x| = -2x. This means that the function h(x) will have two branches depending on whether 2x is positive or negative.
⇒ When 2x is positive, h(x) = |2x| - 8 = 2x - 8. This branch of the function will have all non-negative values.
⇒ When 2x is negative, h(x) = |2x| - 8 = -2x - 8. This branch of the function will have all non-positive values.
Combining the two , we get the range of the function h(x) as [-8, ∞).
Therefore, the domain of h(x) is (-∞, ∞) and the range of h(x) is [-8, ∞).
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PLEASE ANSWER!!! FOR BRAINLY!!! ASAP!!
A system of linear equations is shown on the graph.
The graph shows a line that passes through negative 10 comma 10, negative 5 comma 9, and 0 comma 8. The graph also shows another line that passes through negative 8 comma 12, negative 5 comma 9, and 0 comma 4.
What is the solution to the system of equations?
A There are infinitely many solutions.
B There is no solution.
C There is one unique solution (−5, 9).
D There is one unique solution (0, 8).
Answer:
(-1/5)x + 8 = -x + 4
(4/5)x + 8 = 4
(4/5)x = -4
x = -5, so y = 9
C. There is one unique solution (-5, 9).
Volume of a sphere with a radius of 41
Answer:
Volume = 288695.6 in³
Step-by-step explanation:
Volume of a sphere is given by
v=4/3πr^3
Where r is the radius of the sphere
From the question
radius = 41 in
Substitute the value into the above formula
We have
v=4/3 x 41^3π
=275684/3 π
= 288695.6097
We have the final answer as
Volume = 288695.6 in³ to the nearest tenth
Volume = 288695.6 in³ to the nearest tenth
Hope this helps you
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Let w = 2xy + y2 - 4x2, += st, y=,= Compute Bu (1.-3) - 88 -(1, -3)
To compute Bu(1.-3) - 88 - (1, -3), we need to substitute the values of u and v into the expression for w.
First, we need to find the values of u and v. Since u = 1.-3 and v = (1, -3), we have:
u = 1.-3 = 1 - 0.3 = 0.7
v = (1, -3)
Next, we can substitute these values into the expression for w:
w = 2xy + y^2 - 4x^2
= 2(1)(-3) + (-3)^2 - 4(1)^2 (substituting x = 1 and y = -3)
= -6 + 9 - 4
= -1
Finally, we can compute Bu(1.-3) - 88 - (1, -3) by multiplying the gradient of w by the vector (1, -3) and subtracting 88:
Bu(1.-3) - 88 - (1, -3) = (-8x + 2y, 2x + 2y) (1, -3) - 88
= (-8(1) + 2(-3), 2(1) + 2(-3)) (1, -3) - 88
= (-14, -4) (1, -3) - 88
= (-14)(1) + (-4)(-3) - 88
= -14 + 12 - 88
= -90
Therefore, Bu(1.-3) - 88 - (1, -3) = -90.
Since the question seems to have some typos or missing information, I'll assume you want to find the partial derivatives of w with respect to x and y, and evaluate them at the point (1, -3).
Given w = 2xy + y² - 4x², let's compute the partial derivatives:
∂w/∂x = 2y - 8x
∂w/∂y = 2x + 2y
Now, let's evaluate these partial derivatives at the point (1, -3):
∂w/∂x(1, -3) = 2(-3) - 8(1) = -6 - 8 = -14
∂w/∂y(1, -3) = 2(1) + 2(-3) = 2 - 6 = -4
Thus, the evaluated partial derivatives are ∂w/∂x(1, -3) = -14 and ∂w/∂y(1, -3) = -4.
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HELP ON MATH ASAPPP I NEED TO PASS
I think it might be C
HELP NEEDED ASAP!!!!
The table shows data from a survey about the number of times families eat at restaurants during a week. The families are either from Rome, Italy, or New York, New York:
High Low Q1 Q3 IQR Median Mean σ
Rome 18 1 3 7 4 6.5 6.4 4.3
New York 14 1 4.5 8.5 4 5.5 6.1 3.2
Which of the choices below best describes how to measure the center of these data?
a.Both centers are best described by the mean.
b.Both centers are best described by the median.
c.The Rome data center is best described by the mean. The New York data center is best described by the median.
d.The Rome data center is best described by the median. The New York data center is best described by the mean.
The choice which best describes the measure of center of these data is (d) Rome data center is "best-described" by median and data center of "New-York" is "best-described" by mean.
In the table provided below, we see that the "IQR" for Rome is relatively large compared to the IQR for New York, which suggests that that there may be some skewness in the distribution of the Rome data. So, the median would be a better-measure of center than the mean.
On the other hand, the IQR for "New-York" is relatively small, which indicates that the data is more symmetric and the mean would be a better measure of center.
Therefore, the correct answer is (d).
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The given question is incomplete, the complete question is
The table shows data from a survey about the number of times families eat at restaurants during a week. The families are either from Rome, Italy, or New York, New York:
High Low Q1 Q3 IQR Median Mean σ
Rome 18 1 3 7 4 6.5 6.4 4.3
New York 14 1 4.5 8.5 4 5.5 6.1 3.2
Which of the choices below best describes how to measure the center of these data?
(a) Both centers are best described by the mean.
(b) Both centers are best described by the median.
(c) The Rome data center is best described by the mean. The New York data center is best described by the median.
(d) The Rome data center is best described by the median. The New York data center is best described by the mean.
A cone has a radius of 3 inches and a slant height of 12 inches.
What is the exact surface area of a similar cone whose radius is 9 inches?
The surface area of the similar cone is 415.8 in²
What is surface area of a cone?A cone is a shape formed by using a set of line segments or the lines which connects a common point, called the apex or vertex.
The surface area of a cone is expressed as;
SA = πr( r+l) where r is the radius and l is the slant height.
The slant height of the original cone =
l= √h²+r²
l = √12²+3²
l = √144+9
l = √153
l = 12.4 in
SA= 3π( 3+12.4)
SA = 3 × 15.4
SA = 46.2 in²
The surface area of similar cone with radius 9 inches is calculated by;
(3/9)² = 46.2/x
= 9/81 = 46.2/x
x = 46.2 × 81/9
x = 415.8in²
Therefore the surface area of the similar cone is 415.8 in³
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Un terreno de forma rectangular tiene un perímetro de 105 metros. Si el ancho es la mitad del largo, ¿Cuáles son las medidas del terreno? *
Sea "l" la medida del largo del terreno y "a" la medida del ancho del terreno.
De acuerdo con el problema, el ancho es la mitad del largo, es decir, a = l/2.
El perímetro de un rectángulo se calcula sumando las longitudes de sus cuatro lados, por lo que en este caso:
Perímetro = 2l + 2a = 2l + 2(l/2) = 3l
Sabemos que el perímetro es de 105 metros, entonces:
3l = 105
l = 105/3 = 35
Por lo tanto, el largo del terreno es 35 metros. Y, como el ancho es la mitad del largo, entonces:
a = l/2 = 35/2 = 17.5
Por lo tanto, el ancho del terreno es de 17.5 metros.
En resumen, las medidas del terreno son 35 metros de largo y 17.5 metros de ancho.
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The line plot shows the ages of participants in the middle school play
Determine the appropriate measures of center and variation
The appropriate measures of center and variation are 13 and 4.
Measures of Center:
The appropriate measure of center for this data set is the median since there is no clear outlier present in the data. Hence, the value of median here is 13
Measures of Variation:
The appropriate measure of variation for this dataset is the range, which is the difference between the largest and smallest value in the dataset, Hence the value of range is 4
Since the data is small and there is no clear outlier present, the median is the appropriate measure of center. The range, which is the difference between the largest and smallest value in the dataset, is the appropriate measure of variation
Hence, the appropriate measures of center and variation are 13 and 4.
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Help Mr. Johnson has a swimming pool in the shape of a rectangular prism. The dimensions of the pool are 2. 5 meters by 4. 5 meters. He fills the pool with 1. 2 meters of water. What is the volume of water in Mr. Johnson's pool?
There are 13.5 cubic meters of water in Mr. Johnson's pool.
Volume is defined as the space occupied within the boundaries of an object in three-dimensional space.
To find the volume of water in Mr. Johnson's pool, we need to multiply the length, width, and depth of the pool. The length is 2.5 meters, the width is 4.5 meters, and the depth of water is 1.2 meters.
So, the volume of water in Mr. Johnson's pool is:
2.5 meters x 4.5 meters x 1.2 meters = 13.5 cubic meters
Therefore, there are 13.5 cubic meters of water in Mr. Johnson's pool.
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I seriously need help with this please anyone.
1. Complete the Pythagorean triple. (24,143, ___)
2. Given the Pythagorean triple (5,12,13) find x and y
3. Given x=10 and y=6 find associated Pythagorean triple
4. Is the following a possible Pythagorean triple? (17,23,35)
Answer:
no it is not possible
Step-by-step explanation:
In the last hour, Ellie observed 32 monarchs, 56 gulf fritillaries and 8 giant swallowtails visit her butterfly garden. If 48 butterflies visit her garden, how many can we expect be giant swallowtails
We can expect 4 giant swallowtails to visit Ellie's garden.
In total, there were 96 butterfly visits (32 monarchs + 56 gulf fritillaries + 8 giant swallowtails).
Now, we can calculate the probability of a giant swallowtail visit:
Probability
= (number of giant swallowtails) / (total butterfly visits)
= 8/96
= 1/12
Given that 48 butterflies visit her garden, we can expect the number of giant swallowtails to be:
Expected giant swallowtails
= (total butterflies) × (probability of giant swallowtails)
= 48 × (1/12)
= 4
So, we can expect approximately 4 giant swallowtails to visit Ellie's garden out of the 48 butterflies.
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The 15th question pls
The solution to the system of linear equations is x = 1, y = -3, and z = 8, which is option B: X=-1, y=-3, z=2.
How did we get the values?To solve this system of linear equations, we can use Gaussian elimination, which involves adding and subtracting equations to eliminate variables. Here are the steps:
x - 3y - 2z = 6
2x - 4y - 3z = 8
-3x + 6y + 8z = -5
Step 1: Add twice the first equation to the second equation to eliminate x:
x - 3y - 2z = 6
4y + z = 20
-3x + 6y + 8z = -5
Step 2: Add three times the first equation to the third equation to eliminate x:
x - 3y - 2z = 6
4y + z = 20
9y + 2z = 13
Step 3: Solve for z in the second equation:
4y + z = 20
z = 20 - 4y
Step 4: Substitute z into the third equation and solve for y:
9y + 2z = 13
9y + 2(20 - 4y) = 13
y = -3
Step 5: Substitute y into the second equation and solve for z:
4y + z = 20
4(-3) + z = 20
z = 8
Step 6: Substitute y and z into the first equation and solve for x:
x - 3y - 2z = 6
x - 3(-3) - 2(8) = 6
x = 1
Therefore, the solution to the system of linear equations is x = 1, y = -3, and z = 8, which is option B: X=-1, y=-3, z=2.
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The text format of the question in the picture:
15. The solution the system of linear equation of
x-3y-2z = 6
2x-4y-3z = 8
(-3x+6y+8z = -5 is
A) X=-1,y=-3, z=-2 B) X=-1,y=-3, z=2 C) X=1,y=-3, z=2 D) X = 1, y = 3, z=-2
How many outcomes are there in a 5 digit license plate if the first 2 digits must be letters and the last 3 digits are numbers?
The letters and numbers can be repeated.
100
B 260
676,000
D 1,757,600
without the addition of fertiliser, the annual crop from a potato farm would only be 80% of the previous years crop. a farm produced 15 tonnes of potatoes in its first year of production. assume that no fertiliser is used. give answers correct to two decimal places where necessary. list the size of the potato crop for each of the first four years
The crop sizes for first 4 years without using fertilisers are:
15 tonnes12 tonnes9.6 tonnes7.68 tonnes.What is the size each of the first 4 years?The size of the potato crop for each of the first four years is computed as follows:
For Year 1:
= 15 tonnes * 1
= 15 tonnes
For Year 2:
= 15 tonnes x 0.8
= 12 tonnes
For Year 3:
= 12 tonnes x 0.8
= 9.6 tonnes
For Year 4:
= 9.6 tonnes x 0.8
= 7.68 tonnes
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What is the perimeter of the triangle?
?? units.
Answer:
36 units
Step-by-step explanation:
You want to know the perimeter of the right triangle with leg lengths 9 units and 12 units.
PerimeterThe perimeter of the triangle is the sum of the lengths of its sides. We can count squares to find the lengths of the horizontal and vertical legs. The length of the hypotenuse can be found using the Pythagorean theorem:
c² = a² +b²
c² = 9² +12² = 81 +144 = 225
c = √225 = 15 . . . . length of the hypotenuse
Then the perimeter is ...
P = a +b +c = 9 +12 +15 = 36 . . . units
The perimeter of the triangle is 36 units.
__
Additional comment
The leg lengths have the ratio 9:12 = 3:4, telling you this is a 3:4:5 right triangle. This means you know the side lengths are 3:4:5 = 9:12:15, and their sum is 9+12+15 = 36.
It is handy to memorize a few of the Pythagorean triples that often show up in algebra, trig, and geometry problems: {3, 4, 5}, {5, 12, 13}, {7, 24, 25}, {8, 15, 17}.
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In circle M with m \angle LMN= 66m∠LMN=66 and LM=19LM=19 units find area of sector LMN. Round to the nearest hundredth
We can use the formula for the area of a sector to find the area of sector $LMN$
How to find the area of a sector with central angle $\theta$ in a circle with radius $r$?The area of a sector with central angle $\theta$ in a circle with radius $r$ is given by:
$A = \frac{\theta}{360^\circ} \pi r^2$
In this case, we know that $m\angle LMN = 66^\circ$ and $LM = 19$ units, so the radius of circle M is half of the diagonal of the rectangle formed by $LM$ and $MN$. Using the Pythagorean theorem, we can find the length of $MN$:
$MN^2 = LM^2 + LN^2 = LM^2 + LM^2 = 2LM^2$
$MN = \sqrt{2} LM = \sqrt{2} \cdot 19$
So the radius of circle M is $r = \frac{1}{2}MN = \frac{1}{2}\sqrt{2} \cdot 19$
Now we can use the formula for the area of a sector to find the area of sector $LMN$:
$A = \frac{m\angle LMN}{360^\circ} \pi r^2 = \frac{66^\circ}{360^\circ} \pi \left(\frac{1}{2}\sqrt{2} \cdot 19\right)^2 \approx \boxed{90.89}$ square units (rounded to the nearest hundredth).
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