The area of the quadrilateral can be found by dividing it into two triangles and finding the sum of their areas. The line connecting points B and D divides the quadrilateral into two triangles ABD and BCD. The area of triangle ABD is 1/2 * base * height = 1/2 * 6 * 6 = 18 square units. The area of triangle BCD is 1/2 * base * height = 1/2 * 3 * 8 = 12 square units. Therefore, the area of the quadrilateral is 18 + 12 = 30 square units.
What is the volume of a hemisphere with a radius of 8. 8 cm, rounded to the nearest
tenth of a cubic centimeter?
Please help
The volume of a hemisphere with a radius of 8. 8 cm, rounded to the nearest tenth of a cubic centimeter, is approximately 1436.8 cubic centimeters.
To find the volume of a hemisphere with a radius of 8.8 cm, you can use the formula:
Volume = (2/3)πr³
where r is the radius of the hemisphere. Plugging in the given radius:
Volume = (2/3)π(8.8)³ ≈ 1436.8 cubic centimeters
So, the volume of the hemisphere is approximately 1436.8 cubic centimeters, rounded to the nearest tenth of a cubic centimeter.
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Can someone please help me ASAP? It’s due tomorrow.
Answer:
There are 16 total outcomes for tossing 4 quarters
This is because each coin flip has 2 possibilities, so if you flip the coin 4 times it will equal
2x2x2x2.
7 Plot (6,2) on the grid.
My teacher never thought us this and this was on my homework I give you 59 points if you give me a answer
Answer:Go to the 6 number on the bottom line.Then go up until you reach 2
Step-by-step explanation:
|
|
|
|
| .
|______
Should look like that-ish
Answer:
Step-by-step explanation:
Put the point to the right 6 times and up two times
A florist sells flower bouquets. the table shows the prices for various amounts and kinds of bouquets.
total price
bouquets
2
flower
daisies
tulips
roses
$23.90
$60.80
2
1
2
a
the expression (23.90 - 2) - (60.80 – 2) represents that a bouquet of daisies is
$18.45 more than a bouquet of tulips.
b
the expression (60.80 - 2) - (23.90 + 2) represents that a bouquet of tulips is
$18.45 more than a bouquet of daisies.
с
the expression 23.90 - 60.80 represents that a bouquet of tulips is $36.90 more than a
bouquet of daisies.
d
the expression 60.80 - 23.90 represents that a bouquet of daises is $36.90 more than a
bouquet of tulips.
The latter expression gives a positive result of $36.90, which means that a bouquet of daisies is $36.90 more expensive than a bouquet of tulips.
The given table shows the prices for various amounts and kinds of bouquets sold by a florist. The prices depend on the number and type of flowers in the bouquet. The table shows prices for bouquets of 2 flowers with daisies, tulips, and roses.
The expression (23.90 - 2) - (60.80 – 2) represents that a bouquet of daisies is $18.45 more expensive than a bouquet of tulips. This is because the cost of a 2-flower bouquet of daisies is $23.90 and the cost of a 2-flower bouquet of tulips is $60.80, so the difference between them is $36.90.
However, we subtract 2 from each price to get the price of the actual flowers in the bouquet, which are the same for both daisies and tulips. Therefore, we get the difference of $18.45.
Similarly, the expression (60.80 - 2) - (23.90 + 2) represents that a bouquet of tulips is $18.45 more expensive than a bouquet of daisies. Here, we subtract the price of a 2-flower bouquet of daisies plus the cost of 2 flowers from the price of a 2-flower bouquet of tulips.
Again, the actual cost of flowers in both bouquets is the same, so we get the difference of $18.45.
The expressions 23.90 - 60.80 and 60.80 - 23.90 represent the price difference between bouquets of daisies and tulips, respectively. The former expression gives a negative result of $36.90, which means that a bouquet of tulips is $36.90 more expensive than a bouquet of daisies.
The latter expression gives a positive result of $36.90, which means that a bouquet of daisies is $36.90 more expensive than a bouquet of tulips.
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2 A model of (CH₂O)4 was created using colored beads. Carbon atoms were
represented by black beads, hydrogen atoms by red beads, and oxygen atoms
by blue beads. Which of the following combinations of beads shows an accurate
model of (CH₂O)4?
A 4 black, 8 red, and 4 blue
B 1 black, 2 red, and 1 blue
C 4 black, 6 red, and 4 blue
D
1 black, 8 red, and blue
The correct number of beads is; 4 black, 8 red, and 4 blue. Option A
What is a molecular model?A molecular model is a depiction of molecules or chemical compounds made physically, visually, or mathematically in order to comprehend their behavior and characteristics. These models can range from real models made of plastic or metal to computer-generated graphics or mathematical formulae, and they can be straightforward or sophisticated.
There are four carbon atoms, eight hydrogen atoms and four oxygen atoms.
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Malachi ask students in his class, “ how long does it take you to get to school?“ The histogram shows the data
Answer: C Distribution is symmetric
Step-by-step explanation:
HELP ME PLEASE I BEG YOU!!
Surface area of the box is 304 square inches
Step-by-step explanation:Two different methods:
Method 1: Sum of the parts
Method 2: General formula for the Surface Area of a box
Method 1: Sum of the parts
For a box, there are 6 sides, all of which are rectangles:
the front and backthe left and right sidesthe top and bottomEach of the above pairs has the same area.
The general formula for the area of a rectangle is [tex]A_{rectangle}=length*width[/tex]
As we look at different rectangles, the length of one rectangle may be considered the "width" of another rectangle, and that's okay as we calculate things separately. (We'll examine how to calculate everything at once in Method 2).
The area for the front/back side is 8in * 10in = 80 in^2
[tex]A_{front}=A_{back}=80~in^2[/tex]
The area for the left/right side is 4in * 8in = 32 in^2
[tex]A_{left}=A_{right}=32~in^2[/tex]
The area for the top/bottom side is 4in * 10in = 40 in^2
[tex]A_{top}=A_{bottom}=40~in^2[/tex]
So, the total surface area is
[tex]A_{Surface~Area} = A_{front} + A_{back} + A_{left} + A_{right} + A_{top} + A_{bottom}[/tex]
[tex]A_{Surface~Area} = (80in^2) + (80in^2) + (32in^2) + (32in^2) + (40in^2) + (40in^2)[/tex]
[tex]A_{Surface~Area} = 304~in^2[/tex]
Method 2: General formula for the Surface Area of a box
There is a formula for the surface area of a box:[tex]A_{Surface~Area~of~a~box} = 2(length*width + width*height + height*length)[/tex]
This formula calculates the area of one of each of the matching sides from the side pairs discussed in Method 1, adds those areas together (giving 3 of the sides), and doubles the result (bringing in the area for the matching missing 3 sides).
For clarity, let's decide that the "10 in" is the width, the "8 in" is the height, and the left over "4 in" is the length.
[tex]A_{Surface~Area~of~the~box} = 2((4in)(10in) + (10in)(8in) + (8in)(4in))[/tex]
[tex]A_{Surface~Area~of~the~box} = 2(40in^2 + 80in^2 + 32in^2)[/tex]
[tex]A_{Surface~Area~of~the~box} = 2(152in^2)[/tex]
[tex]A_{Surface~Area~of~the~box} = 304in^2[/tex]
A. The mean selling price (in $ thousands) of the homes was computed earlier to be $357. 0, with a standard deviation of $160. 7. Use the normal distribution to estimate the percentage of homes selling for more than $500. 0. Compare this to the actual results. Is price normally distributed? Try another test. If price is normally distributed, how many homes should have a price greater than the mean? Compare this to the actual number of homes. Construct a frequency distribution of price. What do you observe?
b. The mean days on the market is 30 with a standard deviation of 10 days. Use the normal distribution to estimate the number of homes on the market more than 24 days. Compare this to the actual results. Try another test. If days on the market is normally distributed, how many homes should be on the market more than the mean number of days? Compare this to the actual number of homes. Does the normal distribution yield a good approximation of the actual results? Create a frequency distribution of days on the market. What do you observe?
a) The mean is the midpoint of the distribution, the percentage of homes with a price greater than the mean is 19.7%.
b) The percentage of homes on the market for more than the mean number of days is 72.1%.
a) Firstly, the mean selling price of homes is $357.0 thousand, with a standard deviation of $160.7 thousand. To estimate the percentage of homes selling for more than $500.0 thousand, we can use the normal distribution. This assumes that the distribution of home prices is approximately normal. Using the standard normal distribution table, we can find the z-score for a price of $500.0 thousand.
z = (500.0 - 357.0) / 160.7 = 0.88
Using the z-score, we find that the percentage of homes selling for more than $500.0 thousand is approximately 19.7%.
b) Moving on to the days a home spends on the market, the mean is 30 days and the standard deviation is 10 days. To estimate the number of homes on the market for more than 24 days, we can again use the normal distribution. Assuming that the distribution of days on the market is approximately normal, we can find the z-score for 24 days as:
z = (24 - 30) / 10 = -0.6
Using the z-score, we find that the percentage of homes on the market for more than 24 days is approximately 72.1%.
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Room and board charges for on-campus students at the local college have increased 3.1% each year since 2000. In 2000, students paid $4,291for room and board.
Write a function to model the cost C after t years since 2000.
If the trend continues, how much would a student expect to pay for room and board in 2017? Express your answer as a decimal rounded to the nearest hundredth.
A student would expect to pay approximately $7,096.47 for room and board in 2017. Rounded to the nearest hundredth, this is $7,096.47 rounded to $7,096.50.
What is Function ?
In mathematics, a function is a rule that assigns each element in a set (the domain) to a unique element in another set (the range). The domain and range can be any sets, but they are typically sets of real numbers.
The cost of room and board after t years since 2000 can be modeled by the equation:
C(t) = 4291[tex](1 + 0.031)^{t}[/tex]
where C(t) is the cost after t years.
To find out how much a student would expect to pay in 2017, we need to plug in t = 17 (since 2017 is 17 years after 2000) into the equation:
C(17) = 4291[tex](1 + 0.031)^{17}[/tex]
≈ 7,096.47
Therefore, a student would expect to pay approximately $7,096.47 for room and board in 2017. Rounded to the nearest hundredth, this is $7,096.47 rounded to $7,096.50.
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If an inflatable ball with a volume of 96pi loses air until its radius is half of its original size, what is the new volume?
The new volume of the inflatable ball after the radius becomes half of the original one is 16π.
The original volume of the ball is given as 96π
The radius then becomes half of its original size which means if the radius of the ball is 'r' then the new radius becomes 'r/2'.
The formula for the volume of the ball is equal to, where 'r' is the radius of the ball. (4/3)π X r³
With this the original volume of the ball is
(4/3)π X r³
and the new volume of the ball after it's halved is
V₂ = (4/3)π X (r/2)³
After simplification
V₂ = (4/3)π X (r³/8)
The new volume of the ball is:
V₂ = (1/6) X πr³
So the new volume is (1/6) of the original volume. We can calculate this as
V₂ = (1/6) X 96π
= 16π
Therefore, the new volume of the inflatable ball is 16π.
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A particle moves on a coordinate line with acceleration a = d^2s/dt^2 = 15 sqrt(t) - (3/sqrt(t)), subject to the conditions that ds/dt = 4 and s = 0 when t = 1. Find a. the velocity y = ds/dt in terms of t. b. the position s in terms of t.
a.The velocity function is: v = ds/dt = (2/5)t^(5/2) - 6t^(1/2) + 16.
b. The position function is: s = (4/35)t^(7/2) - 8t^(3/2) + 16t - 12.
a. To find the velocity, we need to integrate the acceleration function. We get:
v = ds/dt = ∫a dt = ∫(15√t - 3/t^(1/2)) dt
Integrating the first term, we get (2/5)t^(5/2), and integrating the second term, we get -6t^(1/2) + C. Thus, the velocity function is:
v = ds/dt = (2/5)t^(5/2) - 6t^(1/2) + C
We can find the constant C using the initial condition that ds/dt = 4 when t = 1. Substituting these values into the equation, we get:
4 = (2/5)(1)^(5/2) - 6(1)^(1/2) + C
C = 4 + 12 = 16
Therefore, the velocity function is:
v = ds/dt = (2/5)t^(5/2) - 6t^(1/2) + 16
b. To find the position function, we need to integrate the velocity function. We get:
s = ∫v dt = ∫((2/5)t^(5/2) - 6t^(1/2) + 16) dt
Integrating the first term, we get (4/35)t^(7/2), integrating the second term, we get -8t^(3/2), and integrating the third term, we get 16t. Thus, the position function is:
s = ∫v dt = (4/35)t^(7/2) - 8t^(3/2) + 16t + C2
We can find the constant C2 using the initial condition that s = 0 when t = 1. Substituting these values into the equation, we get:
0 = (4/35)(1)^(7/2) - 8(1)^(3/2) + 16(1) + C2
C2 = -12
Therefore, the position function is:
s = (4/35)t^(7/2) - 8t^(3/2) + 16t - 12
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Q2) For the following exercises, write the first five terms of the indicated
sequence:
The first five terms of the sequence are: 3/5, 3/4, 9/7, 3/2, 15/9.
To find the first five terms of the sequence aₙ = 3n/(n+4)
we need to substitute the values of n from 1 to 5 and solve for .
a₁ = 3×1/(1+4) = 3/5
a₂ = 3×2/(2+4) = 3/4
a₃ = 3×3/(3+4) = 9/7
a₄ = 3×4/(4+4) = 12/8 = 3/2
a₅ = 3×5/(5+4) = 15/9
Hence, the first five terms of the sequence are: 3/5, 3/4, 9/7, 3/2, 15/9.
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The height of each cone and the cylinder is 5 (cm) centimeters. The radius of the base of each cone and the cylinder is 4 (cm). What is the volume of the composite figure?
Therefore, the volume of the composite figure is approximately 419.05 cubic cm.
What is volume?Volume is the amount of space occupied by a three-dimensional object or shape. It is measured in cubic units such as cubic centimeters, cubic inches, or cubic meters. The volume of an object can be calculated by multiplying the area of its base by its height, or by using specific formulas depending on the shape of the object. The volume of an object is an important parameter in many areas of science and engineering, such as physics, chemistry, fluid mechanics, and material science, as it allows us to determine how much space an object will occupy or how much material is needed to fill a container or build a structure.
Here,
The composite figure consists of a cylinder and two cones, so we need to find the volume of each of these shapes and add them together.
Volume of cylinder = πr²h
= π(4²)(5)
= 80π cubic cm
Volume of one cone = (1/3)πr²h
= (1/3)π(4²)(5)
= (1/3)(80π)
= 26.67π cubic cm
Volume of both cones = 2(26.67π)
= 53.34π cubic cm
Total volume of composite figure = Volume of cylinder + Volume of both cones
= 80π + 53.34π
= 133.34π
= 419.05 cubic cm (rounded to two decimal places)
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Kristen is excited for her first overnight camping trip with her scout troop. the troop needs to take some parent chaperones with the on the trip. for a trip with s scouts, they need at least s/5 chaperones. there are 15 scouts going on the camping trip.
They may choose to bring 4 chaperones or even more depending on their preferences and logistical constraints.
How many chaperones are needed for the camping trip with 15 scouts?For the camping trip with 15 scouts, they will need at least 15/5 = 3 chaperones.
However, it's possible that they may want to have more than the minimum number of chaperones for additional supervision and safety. The number of chaperones they choose to bring may also depend on the ratio of chaperones to scouts that they want to maintain.
So, they may choose to bring 4 chaperones (1 chaperone for every 3.75 scouts), 5 chaperones (1 chaperone for every 3 scouts), or even more depending on their preferences and logistical constraints.
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The captain of the baseball team hit a homerun 1 out of every 6 at-bats. What is the probability that the captain will hit a homerun on his next 2 at-bats?
Determine which simulation models the situation. Select Yes if the simulation can be used to model the situation or No if the simulation cannot be used to model the situation.
Yes No
OO
Using a six-sided number cube to model the situation, assign the number 1 to represent the captain hitting a homerun and the number 2 to represent not hitting a homerun.
Using a stre-sided number cube to model the situation, assign the number 1 to represent the captain hitting a homerun and the numbers 2 to 6 to represent not hitting a homerun
Using a coin flip to model the situation, assign heads to represent the captain hitting a homerun and tails for not hitting a homerun
O
Using a random number generator between 1 and 60 to model the situation, assign the numbers 1 to 10 to represent the captain hitting a homerun and the numbers 11 to 60 to represent not hitting a homerun.
The probability of the captain hitting a home run in his next two at-bats is 1/36, and the best simulations to model the situation are using a six-sided number cube or a random number generator between 1 and 60.
Determine the probability that the captain will hit a home run in his next two at-bats and find the best simulation to model the situation.
The probability of the captain hitting a home run in one at-bat is 1/6. To find the probability of hitting a home run in two consecutive at-bats, you can multiply the individual probabilities:
Probability = (1/6) * (1/6) = 1/36
Now let's evaluate the provided simulations:
1. Using a six-sided number cube: Yes, this can be used to model the situation because the probability of hitting a home run (1/6) and not hitting a home run (5/6) can be represented accurately by the numbers 1 and 2-6, respectively.
2. Using a three-sided number cube: No, this cannot be used to model the situation because the probability distribution is not accurately represented with only three sides.
3. Using a coin flip: No, this cannot be used to model the situation because the probability distribution is not accurately represented with only two outcomes (heads and tails).
4. Using a random number generator between 1 and 60: Yes, this can be used to model the situation because the probability of hitting a home run (1/6) and not hitting a home run (5/6) can be represented accurately by the numbers 1-10 and 11-60, respectively.
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4. Lana has a bag of marbles. The probability of picking a striped marble is 8%. If Lana picks a marble and then replaces it 320 times, predict about how many times she would pick a marble that is not striped.
Lana would pick a non-striped marble about 294 times.
The probability of picking a marble that is not striped is 100% - 8% = 92% = 0.92. This means that for each pick, the probability of getting a non-striped marble is 0.92.
If Lana picks a marble and replaces it 320 times, the number of times she would pick a non-striped marble can be predicted by multiplying the probability of getting a non-striped marble by the number of picks.
So, the number of times she would pick a non-striped marble is:
0.92 x 320 = 294.4
Rounding to the nearest whole number = 294.
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What is the solution for 11\31×38\33
Answer:
38/93
Step-by-step explanation:
11/31 x 38/33
11 x 38 = 418
31 x 33 = 1023
= 418/1023
Simplifying
The simplified form of 418/1023 is 38/93.
38/93 is your final answer.
Suppose you carry out a significance test of h0: μ = 8 versus ha: μ > 8 based on sample size n = 25 and obtain t = 2.15. find the p-value for this test. what conclusion can you draw at the 5% significance level? explain.
a the p-value is 0.02. we reject h0 at the 5% significance level because the p-value 0.02 is less than 0.05.
b the p-value is 0.02. we fail to reject h0 at the 5% significance level because the p-value 0.02 is less than 0.05.
c the p-value is 0.48. we reject h0 at the 5% significance level because the p-value 0.48 is greater than 0.05.
d the p-value is 0.48. we fail to reject h0 at the 5% significance level because the p-value 0.48 is greater than 0.05.
e the p-value is 0.52. we fail to reject h0 at the 5% significance level because the p-value 0.52 is greater than 0.05.
We can draw at the 5% significance level, the p-value is 0.02. we reject h0 at the 5% significance level because the p-value 0.02 is less than 0.05. The correct answer is a.
To find the p-value, we need to find the area to the right of t = 2.15 under the t-distribution curve with 24 degrees of freedom (df = n - 1 = 25 - 1 = 24). Using a t-table or a calculator, we find that the area to the right of t = 2.15 is approximately 0.02.
Since the p-value (0.02) is less than the significance level (0.05), we reject the null hypothesis H0: μ = 8 and conclude that there is sufficient evidence to support the alternative hypothesis Ha: μ > 8 at the 5% significance level. This means that we can say with 95% confidence that the true population mean is greater than 8.
Therefore the correct answer is a.
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In the figure, is tangent to the circle at point U. Use the figure to answer the question.
Hint: See Lesson 3. 09: Tangents to Circles 2 > Learn > A Closer Look: Describe Secant and Tangent Segment Relationships > Slide 4 of 8. 4 points.
Suppose RS=8 in. And ST=4 in. Find the length of to the nearest tenth. Show your work.
1 point for the formula, 1 point for showing your steps, 1 point for the correct answer, and 1 point for correct units.
If you do not have an answer please dont comment
The length of UX (the length of a tangent segment to a circle) is approximately 4.9 inches.
To find the length of UX, we can use the formula for the length of a tangent segment to a circle:
Length of tangent segment = √(radius² - distance from center²)
In this case, we don't know the radius or the distance from the center, but we can use the fact that RU is perpendicular to UT to find them:
RU = RS + ST = 8 + 4 = 12 in.
UT = radius = RU/2 = 12/2 = 6 in.
Now we can plug these values into the formula:
Length of tangent segment = √(6² - 4²) ≈ 4.9 in.
Therefore, the length of UX is approximately 4.9 inches.
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For security purposes I regularly change my six-digit passcode for internet banking. I always
choose a code that is made up of three different two-digit square numbers (i. E. Square numbers
between 10 and 99), with the sixth digit the same as the first digit.
-Which two digits never appear in any of my passcodes?
-How many different passcodes can I use?
The sum of the six digits of my current passcode is also a square number.
-What is my current passcode?
The two digit Combinations that never appear in any of the passcodes are 5 and 6.
There are 49 different passcodes that can be used. The sum of the six digits of the current passcode is 81, which is a square number. Therefore, the current passcode is made up of three different two-digit square numbers with the sum of their digits equal to 9.
The possible combinations are
(16, 25, 40),
(16, 49, 16),
(25, 36, 20),
(36, 49, 4),
(49, 64, 9),
(64, 81, 16), and
(81, 16, 64).
The only combination that has the same first and sixth digits is (16, 25, 40), so the current passcode is 162540.
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3. Use the definition of the Riemann Sum to evaluate S12(x3 – 2x)dx. + - 4. Evaluate: S2x2+x=2 5. Given the velocity in meters/second for v(t) = 8 – 2t, 1 st 56 a.) find the displacement of the particle over the given time interval; b.) find the distance traveled by the particle over the given time interval.
Evaluation of S12(x3 – 2x)dx is- 92.875
We can use the definition of the Riemann Sum to evaluate S12(x3 – 2x)dx as follows:
First, we need to choose the width of our intervals.
Let's choose Δx = 1/2, which means we will have 24 subintervals.
Now, we can use the formula for the Riemann Sum to calculate the sum of the areas of the rectangles.
S12(x3 – 2x)dx ≈ ∑[f(xi)Δx] from i=1 to i=24
where xi is the right endpoint of the ith subinterval,
f(xi) = x[tex]i^3[/tex] – 2xi is the height of the rectangle, and Δx = 1/2 is the width of the rectangle.
Evaluating this sum using the given formula, we get:
S12(x3 – 2x)dx ≈ [f(1/2) + f(1) + f(3/2) + ... + f(11)](1/2)
≈ [[tex](1/2)^3[/tex] – 2(1/2) + (1)^3 – 2(1) + (3/2[tex])^3[/tex] – 2(3/2) + ... + (11[tex])^3[/tex] – 2(11)](1/2)
≈ [- 2361/16](1/2)
≈ - 92.875
4) we can simply evaluate the given integral:
S2x2+x=2 = ∫(2[tex]x^2[/tex] + x)dx from 0 to 2
= [[tex]2/3 x^3 + 1/2 x^2[/tex]] from 0 to 2
= [[tex]2/3 (2)^3 + 1/2 (2)^2[/tex]] - [[tex]2/3 (0)^3 + 1/2 (0)^2[/tex]]
= 16/3
5), we can use the following formulas
to find the displacement and distance traveled by the particle over the given time interval:
Displacement = ∫v(t)dt from 1 to 5
Distance traveled = ∫|v(t)|dt from 1 to 5
where v(t) is the velocity function.
a) To find the displacement, we evaluate the integral:
∫v(t)dt = ∫(8 – 2t)dt from 1 to 5
= [8t – t^2] from 1 to 5
= [[tex]8(5) – (5)^2[/tex]] - [8(1) – [tex](1)^2[/tex]]
= 18 meters
b) To find the distance traveled, we evaluate the integral:
∫|v(t)|dt = ∫|8 – 2t|dt from 1 to 5
= ∫(8 – 2t)dt from 1 to 4 + ∫(2t – 8)dt from 4 to 5
= [8t – [tex]t^2[/tex]] from 1 to 4 + [-t^2 + 8t -16] from 4 to 5
= [8(4) – [tex](4)^2[/tex]] - [8(1) – [tex](1)^2[/tex]] + [[tex]-(5)^2[/tex] + 8(5) -16 -(-[tex](4)^2[/tex] + 8(4) -16)]
= 26 meters
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I absolutely hate IQR so can someone help pls
Answer:5
Step-by-step explanation: The median of the lower quartile is 23 and the median of the upper quartile is 28. 28-23=5. The IQR is 5.
If you flip a coin 4 times what is the best prediction possible for the number of times it will land on tails?
Answer:it would still be a 50/50 chance of it be tails
Step-by-step explanation:
a coin has 2 sides. The probability would be 1/2. That means if you flip it a even amount, there would be a 50/tip chance. Let me know if I’m correct.
Write the equation for the circle graphed below. Center = (-5, -5) Radius= 4
Answer:
(x + 5)^2 + (y + 5)^2 = 16.
Step-by-step explanation:
(x - a)^2 + (y - b)^2 = r^2 where (a, b) is the centre and r =- the radius.
Here (a, b) = (-5, -5) and r = 4, so:
(x - (-5))^2 + (y - (-5))^2 = 4^2
(x + 5)^2 + (y + 5)^2 = 16
Write 7.725666118 as a percentage
please show the method too.
The number written as a percentage is:
772.5666118%
How to write any number as a percentage?To do this, just multiply the number by 100%.
For example, for any number A, the percentage form of A is:
p = A*100%
Here the number is 7.725666118, then the percentage form of this number will be:
N = 7.725666118*100% = 772.5666118%
That is the number as a percentage.
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For evrey 500g of reactants, 3. 1 g of catalyst were required. How much catalyst was required for 900g of reactants
5.58g of catalyst is required for 900g of reactants.
How much catalyst for 900g reactants?If 500g of reactants require 3.1g of catalyst, then for 900g of reactants, we can use the following proportion:
500g reactants / 3.1g catalyst = 900g reactants / x
Where x is the amount of catalyst required for 900g of reactants.
To solve for x, we can cross-multiply:
500g reactants * x = 3.1g catalyst * 900g reactants
Then, we can divide both sides by 500g reactants to isolate x:
x = (3.1g catalyst * 900g reactants) / 500g reactants
Simplifying this expression gives:
x = 5.58g catalyst
Therefore, 5.58g of catalyst is required for 900g of reactants.
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Hello im new to brainly and i needed some help becuase i dont understand the question.
The number of customers surveyed were 15 customers.
The greatest number of items purchased by a customer was 11 items.
The customers purchased 9 items is 2 customers.
The customers purchased at least 5 items was 7 customers.
The median number of items purchased was 3.
How to interpret the line plots?How many customers were surveyed?
1 (0 items) + 1 (1 item) + 2 (2 items) + 4 (3 items) + 0 (4 items) + 2 (5 items) + 0 (6 items) + 2 (7 items) + 0 (8 items) + 2 (9 items) + 0 (10 items) + 1 (11 items) = 15 customers
The greatest number of items purchased by a customer is 11 items. 2 customers purchased 9 items.
How many customers purchased at least 5 items?
2 (5 items) + 0 (6 items) + 2 (7 items) + 0 (8 items) + 2 (9 items) + 0 (10 items) + 1 (11 items) = 7 customers
To find the median, we need to find the middle value of the data. Since there are 15 customers, the median will be the 8th value when the data is ordered.
0, 1, 2, 2, 3, 3, 3, 3, 5, 5, 7, 7, 9, 9, 11
The median number of items purchased is 3.
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Using Newton's Method, estimate the positive solution to the following equation by calculating x2 and using X0 = 1. x⁴ – x = 3 Round to four decimal places.
Answer:
To estimate the positive solution to the equation x⁴ – x = 3 using Newton's Method, we can start by taking the derivative of the equation, which is 4x³ - 1. Then we can use the formula X1 = X0 - f(X0) / f'(X0), where X0 = 1, f(X0) = 1⁴ - 1 - 3 = -3, and f'(X0) = 4(1)³ - 1 = 3. Plugging these values into the formula, we get:
X1 = 1 - (-3) / 3
X1 = 2
Now we can repeat the process using X1 as our new X0:
X2 = X1 - f(X1) / f'(X1)
X2 = 2 - (2⁴ - 2 - 3) / (4(2)³ - 1)
X2 ≈ 1.7708
Therefore, the positive solution to the equation x⁴ – x = 3, rounded to four decimal places, is approximately 1.7708.
Step-by-step explanation:
The positive solution to the equation x⁴ – x = 3, estimated using Newton's Method with x₀ = 1 and x₂ as the final estimate, is approximately 1.5329, rounded to four decimal places.
To use Newton's Method to estimate the positive solution to the equation x⁴ – x = 3, we need to find the derivative of the function f(x) = x⁴ – x. This is given by:
f'(x) = 4x³ - 1
We can then use the formula for Newton's Method:
x(n+1) = x(n) - f(x(n)) / f'(x(n))
where x(n) is the nth estimate of the solution.
Starting with x₀ = 1, we can plug this into the formula to get:
x₁ = 1 - (1^4 - 1 - 3) / (4(1^3) - 1) ≈ 1.75
We can then repeat this process using x₁ as the new estimate, to get:
x₂ = 1.75 - (1.75^4 - 1.75 - 3) / (4(1.75^3) - 1) ≈ 1.5329
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How many containers will it take fill the aquarium with water
A.13 containers
B. 14 containers
C. 15 containers
D. 16 containers
Answer:
for that first u should know that how much litres of water that aquarium can contain.
for that first u should know that how much litres of water that aquarium can contain.so that probably depends upon the size length and width of a container
for that first u should know that how much litres of water that aquarium can contain.so that probably depends upon the size length and width of a containera normal container can be filled with approximately 15 containers
solve this problem:
Suppose that you are headed toward a plateau 50 m high. If the angle of elevation to the top of the plateau is 20 , how far are you from the base of the plateau?
Answer:
Step-by-step explanation:
We can use trigonometry to solve this problem. Let's call the distance from the base of the plateau to our position "x". We can then use the tangent function to find x:
tan(20°) = opposite / adjacent
In this case, the opposite side is the height of the plateau (50 m) and the adjacent side is x. So we can write:
tan(20°) = 50 / x
To solve for x, we can rearrange this equation:
x = 50 / tan(20°)
Using a calculator, we get:
x = 143.45 meters (rounded to two decimal places)
Therefore, if the angle of elevation to the top of the plateau is 20 degrees, and the plateau is 50 meters high, we are approximately 143.45 meters away from the base of the plateau.
Answer:
The distance is 137.3739 feet.
Step-by-step explanation:
I hope this answer is right.