Question 6 (5 points)
Label each situation as metals, nonmetals, or metalloids. Label each with numbers.
Usually conducts electricity
& heat well
at room temperature these
are gases or liquids
Will lose valance electrons
to form compounds.
can be used as
semiconductors
Will gain valance electrons
to form compounds.
1. a metal
2. a nonmetal
3. a metalloid
Answers
Answer:
Explanation:
Here are the labels for each situation:
1.Usually conducts electricity & heat well - Metal (1)
2.At room temperature these are gases or liquids - Nonmetal (2)
3.Will lose valance electrons to form compounds - Metal (1)
4.Can be used as semiconductors - Metalloid (3)
5.Will gain valance electrons to form compounds - Nonmetal (2)
Related Questions
What is the molarity of a solution that has 2.0 moles of solute in 3.0 L of solution?
Answers
The molarity of the solution that has 2.0 moles of solute in 3.0 L of solution is 0.67 mol/L
What is molarity?Molarity is described as a measure of the concentration of a chemical species, in particular of a solute in a solution, in terms of amount of substance per unit volume of solution.
Molarity = moles of solute / liters of solution
we then substitute the given values, and have
Molarity = 2.0 moles / 3.0 L
Molarity = 0.67 mol/L
Molarity is very important because the ration used to express the concentration of any solution.
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Calculate standard cell potential of an electrochemical cell powered by these half-reactions. (Write values to two decimal places. If a value is less than 1, be sure to write a 0 before the decimal.)
Pb4+ + 2e− → Pb2+
Co3+ + e− → Co2+
E°cell = V
Is the reaction spontaneous
Answers
The standard cell potential is found as +1.95 V and is a spontaneous reaction.
What is standard cell potential ?The standard cell potential (E°cell) of an electrochemical cell is given by the difference between the standard reduction potentials of the two half-cells involved.
E°cell = E°reduction (cathode) - E°reduction (anode)
The half-reactions given are:
Pb4+ + 2e− → Pb2+ (reduction)
Co3+ + e− → Co2+ (reduction)
The standard reduction potentials for these half-reactions are:
E°reduction(Pb4+/Pb2+) = -0.13 V
E°reduction(Co3+/Co2+) = +1.82 V
We then calculate as:
E°cell = E°reduction (Co3+/Co2+) - E°reduction (Pb4+/Pb2+)
E°cell = (+1.82 V) - (-0.13 V)
E°cell = +1.95 V
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17. An artist took two photographs of the Moon that were several days apart. Images that look like his photographs are shown above. The light part of the Moon appeared to get smaller over time. Why did this happen?
Answers
According to the information, we can infer that the difference between photographs 1 and 2 originate from the translation of the Moon around the earth (option C).
How do we explain the differences between the two images?To explain the difference between both images we must take into account the movement patterns of the earth and the moon. In the case of the earth, it has 2 main movements, which are rotation on its own axis and translation around the sun.
On the other hand, the moon has a translational movement around the earth, which is what causes the different lunar phases. This motion causes the moon to appear partially shadowed from the earth because the earth blocks the sunlight.
Based on the above, we can infer that the correct answer is option C because this phenomenon is caused by the translation of the moon.
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Write the complete equation for neutralization reactions for LiOh + HNO2
Answers
The complete equation for the neutralization reactions for the LiOH + HNO₂ is as :
LiOH + HNO₂ ----> LiNO₂ + H₂O
The Neutralization reaction is the reaction as in the chemical reaction in which the acid will reacts with the base and to produce the salt and the water molecule. The general equation of the chemical reaction is as :
HX + BOH --> BX + H₂O
The reaction with the LiOH and the HNO₂ is :
LiOH + HNO₂ ----> LiNO₂ + H₂O
There is the combination of the H⁺ ions and OH⁻ ions that will form the water.
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PLEASE ACTUALLY ANSWER THE WHOLE ASSIGNMENT FOR BRAINLIEST
Answers
The results of the lab activity showed that the larger the mass of the sun, the more likely at least one planet will fall into the habitable zone.
What effect does the mass of the Sun have on the orbits of Planets?The mass of the sun affects the orbits of planets in a solar system. When the mass of the sun is larger, the gravitational force between the sun and the planets is stronger, causing the planets to move at a slower pace around the sun.
Conversely, when the mass of the sun is smaller, the gravitational force is weaker, causing the planets to move at a faster pace.
Additionally, when Earth is closer to the sun, the gravitational force is stronger, causing its orbit to become faster, while a farther distance from the sun results in a slower orbit.
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If the reaction A (aq) + B (aq) C(aq) has a Ka value equal to 4.26 x 10-6, what is the G value at 25 °C if the concentrations are as follows:
[A] = 1.50 M
[B] = 1.00 M
[C] = 5.00 x 10-5 M
Answers
The ΔG value for the reaction A (aq) + B (aq) → C(aq) at 25 °C and the given concentrations is -8.35 kJ/mol.
The relationship between ΔG and K is given by the following equation:
ΔG = -RTln(K)
where R is the gas constant (8.314 J/(mol·K)), T is the temperature in Kelvin (25 °C = 298.15 K), and ln denotes the natural logarithm.
To calculate K, we need to use the equilibrium expression and the given concentrations:
[tex]K = [C]/([A][B])[/tex]
[tex]K = (5.00 * 10^{-5} M)/((1.50 M)(1.00 M))[/tex]
[tex]K = 3.33 x 10^{-5}[/tex]
Now we can substitute the values for R, T, and K into the equation for ΔG:
ΔG = -RTln(K)
ΔG = [tex]-(8.314 J/(mol.K))(298.15 K)ln(3.33 x 10^{-5})[/tex]
ΔG = -8.35 kJ/mol
Therefore, the ΔG value for the reaction A (aq) + B (aq) → C(aq) at 25 °C and the given concentrations is -8.35 kJ/mol.
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Help please! I'll give brainliest and 5 stars if you show work!
Answers
To solve this problem, we can use the formula:
q = m × c × ΔT
where q is the heat absorbed or released, m is the mass of the substance, c is its specific heat, and ΔT is the change in temperature.
First, let's calculate the mass of water:
m = 225.0 g
Next, let's calculate the heat absorbed by the water:
q_water = m × c × ΔT
q_water = 225.0 g × 4.184 J/(g·°C) × (24.60°C - 20.53°C)
q_water = 3749.8 J
Since the metal released 4274 J of heat, the heat absorbed by the calorimeter can be calculated by subtracting the heat absorbed by the water from the total heat released by the metal:
q_calorimeter = - (q_water + q_metal)
q_calorimeter = - (3749.8 J + 4274 J)
q_calorimeter = - 8023.8 J
Therefore, the heat absorbed by the calorimeter is -8023.8 J, which is approximately equal to -8000 J or -8.0 kJ. The answer is (c) -339 J, since it is the closest to the calculated value when rounded to the nearest integer. Note that the negative sign indicates that the calorimeter absorbed the heat, which is expected since the reaction involved a release of heat.
You react 0.017 mol of solid metal with HCl in a coffee cup calorimeter (reaction shown below). The calorimeter has 100 mL of water in it, and the temperature of the water increases by 3.81°C. The calorimeter has a heat capacity of 40.4 J/°C. What is the enthalpy of the reaction in terms of kJ per mol of the metal (your answer should be NEGATIVE, remember to convert from J to kJ, specific heat capacity of water is 4.184 J/g-°C)?
M(s) + 2 HCl (aq) MCl2 (aq) + H2 (g)
M = metal
Answers
q = -mCΔT
where q is the heat absorbed by the water and the calorimeter, m is the mass of the water, C is the heat capacity of the calorimeter, and ΔT is the change in temperature of the water.
First, we need to calculate the heat absorbed by the water and the calorimeter:
q = (100 g) x (4.184 J/g-°C) x (3.81°C) + (40.4 J/°C) x (3.81°C)
q = 1657.4 J
Next, we need to calculate the moles of HCl used in the reaction. From the balanced chemical equation, we can see that 2 moles of HCl react with 1 mole of the metal, so:
moles of HCl = 2 x moles of metal = 2 x 0.017 mol = 0.034 mol
Finally, we can calculate the enthalpy of the reaction per mole of the metal:
ΔH = -q / moles of metal
ΔH = -(1657.4 J) / (0.017 mol)
ΔH = -97,494 J/mol
To convert to kJ/mol, we divide by 1000:
ΔH = -97.494 kJ/mol
Therefore, the enthalpy of the reaction is -97.494 kJ/mol of the metal. Note that the negative sign indicates that the reaction is exothermic (i.e. heat is released).
A 210.00 g sample of water with an initial temperature of 29.0°C absorbs 7,000.0 J of heat. What is the final temperature of the water?
Note: Use C (capital C) for degrees Celsius when typing units. So it might look like 35C or 2.03 J/gC. Give your answer in 3 sig figs.
Answers
The 210.00 g sample of the water with the initial temperature of the 29.0°C absorbs the 7,000.0 J of heat. The final temperature of the water is the 36.9 °C .
The mass of the water = 210 g
The initial temperature = 29.0 °C
The final temperature = ?
The heat energy = 7000 J
The specific heat capacity = 4.184 J/g °C
The heat energy is expressed as :
Q = m c ΔT
Where,
The m is mass of water = 210 g
The c is specific heat of water = 4.184 J/g °C
The ΔT is change in temperature = final temperature - initial temperature
The ΔT is change in temperature = T - 29.0 °C
7000 = 210 × 4.184 ( T - 29.0 )
7000 = 878.64 ( T - 29.0 )
( T - 29.0 ) = 7.966
T = 36.9 °C
The final temperature is 36.9 °C .
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Question 8 of 21
Which nucleus completes the following equation?
Answers
The nucleus completing the following equation is option C: ₂₄⁵⁰Cr.
This reaction is a type of radioactive nuclei decay.
What is radioactive decay?Radioactive decay is the process by which unstable atomic nuclei undergo spontaneous transformations in order to achieve a more stable state. This is accomplished by the emission of particles and/or electromagnetic radiation from the nucleus. The decay may occur by several mechanisms, including alpha decay, beta decay, gamma decay, and electron capture.
In alpha decay, the nucleus emits an alpha particle, which consists of two protons and two neutrons, resulting in a daughter nucleus that has two fewer protons and two fewer neutrons than the original nucleus.
In beta decay, a neutron in the nucleus is converted into a proton and an electron, and the electron is then emitted from the nucleus as a beta particle. This results in the daughter nucleus having one more proton and one fewer neutron than the original nucleus.
In gamma decay, the nucleus emits a gamma ray, which is a high-energy electromagnetic radiation, without changing the number of protons or neutrons in the nucleus.
In electron capture, an electron from the inner shell of the atom is captured by the nucleus, and a proton in the nucleus is converted into a neutron. This results in the daughter nucleus having one fewer proton and one more neutron than the original nucleus.
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A 0.4856 g sample of solid silver oxide is heated. Find the volume of O2 that can be released at STP.
Answers
The volume of O2 that can be released at STP from the given sample of silver oxide is 23.45 mL.
To solve this problem
Creating the balanced chemical equation for the breakdown of silver oxide is the first step in tackling this issue:
2Ag2O(s) → 4Ag(s) + O2(g)
We can deduce from the equation that 2 moles of AgO will result in 1 mole of O2. Since Ag2O has a molar mass of 231.735 g/mol, 0.4856 g of Ag2O is equivalent to:
0.4856 g Ag2O x (1 mol Ag2O/231.735 g Ag2O) = 0.002095 mol Ag2O
Therefore, the number of moles of O2 that can be produced from 0.4856 g of Ag2O is:
0.002095 mol Ag2O x (1 mol O2/2 mol Ag2O) = 0.0010475 mol O2
1 mole of any gas takes up 22.4 L of space at STP As a result, 0.4856 g of Ag2O can generate the following amount of O2 at STP:
0.0010475 mol O2 x 22.4 L/mol = 0.02345 L or 23.45 mL
Therefore, the volume of O2 that can be released at STP from the given sample of silver oxide is 23.45 mL.
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what is the pH of a solution prepared.by dissolving 4.0 g of HCL in water to make 475mL of a solution
Answers
To find the pH of the solution, we need to first calculate the concentration of H+ ions in the solution using the following equation:
[H+] = (moles of HCl) / (volume of solution in liters)
First, let's convert the mass of HCl to moles:
moles of HCl = mass / molar mass = 4.0 g / 36.46 g/mol = 0.1096 moles
Next, let's convert the volume to liters:
475 mL = 0.475 L
Now we can calculate the concentration of H+ ions:
[H+] = 0.1096 moles / 0.475 L = 0.2306 M
Finally, we can calculate the pH using the equation:
pH = -log[H+]
pH = -log(0.2306) = 0.637
Therefore, the pH of the solution is approximately 0.637.
What is volume of 12.0 g of carbon dioxide at stp?
Answers
Answer: 6.11 L
Explanation:
STP= 1atm, 273.15K
Molar mass of CO2=44.01g/mol so n= (12.0/44.01)
PV=nRT
V=(nRT)/P
V=((12.0/44.01)(0.0821)(273.15))/1
V=6.11L
Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answers
Answer:
The Correct answer is option 3
Step by Syep Explanation:
4Fe+3O2---->rust
formula for rust----->Fe2O3
4Fe+3O2---->Fe2O3
Balancing the Chemical Equation
both the reactant and product side
we have that;
4Fe+3O2------->2FeO3
the equation is Chemically Balanced
therefore 4Fe+3O2------->2×rust
Answer:
2Fe₂O₃ (Option 3)Explanation:
Given that,
4Fe + 3O2 → rust.Law of conservation of mass states that " Mass of reactants is equal to the mass of products".
Also we know that In a balanced equation the total number of atoms in the reactants equals the total number of atoms in the product.
We are given with 4Fe + 3O₂ i.e the reactant.
First Let's calculate the number of atoms in the reactant.
No. of atoms in Fe = 4 No. of atoms in O = 3 × 2 = 6Now, Let's find the product .
Also, We can see 2Fe₂O₃ (Product)
No. of atoms in Fe = 2 × 2 = 4 No. of atoms in O = 2 × 3 = 6.4Fe + 3O₂ → 2Fe₂O₃
Number of atoms in the reactants = the total number of atoms in the product.
Therefore, 2Fe₂O₃ (Option 3) will the required answer .
bromsted-lowry acids and bases
find out the acids and bases
Answers
Johannes Brsted and Thomas M. Lowry, two chemists, identified the Bromsted-Lowry acids and bases as a particular kind of acid-base reaction in 1923.
Acids are substances that give a base a proton (H+), whereas bases are substances that take a proton from an acid. In a Bromsted-Lowry acid-base reaction, the acid gives the base a proton in order to create the conjugate base and the conjugate acid, two new compounds.
Nitric acid (HNO3), sulfuric acid (H2SO4), and hydrochloric acid (HCl) are a few examples of acids. Sodium hydroxide (NaOH), ammonium hydroxide (NH4OH), and potassium hydroxide (KOH) are a few examples of bases.
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8. The compound C2H4 has van der Waals constants a = 4.612 atm•L2/mol2 and b = 0.0582 L/mol. Using both the ideal gas law and van der Waals’s equation, calculate the pressure expected for 30 mol of C2H4 gas in a 6.00-L container at 20 °C.
Answers
Using the Ideal Gas Law, the pressure expected for 30 mol of [tex]C_2H_4[/tex] gas in a 6.00-L container at 20 °C is 1210.07 atm, and using the van der Waals equation, the pressure is 1179.71 atm.
To calculate the pressure expected for 30 mol of [tex]C_2H_4[/tex] gas in a 6.00-L container at 20 °C, we will use both the Ideal Gas Law and van der Waals equation.
Ideal Gas Law: PV = nRT
P = pressure
V = volume (6.00 L)
n = moles (30 mol)
R = ideal gas constant (0.0821 L•atm/mol•K)
T = temperature (20 °C + 273.15 = 293.15 K)
Solve for P (pressure):
P = nRT / V
P = (30 mol)(0.0821 L•atm/mol•K)(293.15 K) / 6.00 L
P = 1210.07 atm
Van der Waals equation:
(P + a(n/V)²)(V - nb) = nRT
a = 4.612 atm•L²/mol²
b = 0.0582 L/mol
Solve for P (pressure):
(P + (4.612)(30/6)²) (6 - 0.0582 * 30) = (30)(0.0821)(293.15)
P = 1179.71 atm
Using the Ideal Gas Law, the pressure is 1210.07 atm, and using the van der Waals equation, the pressure is 1179.71 atm.
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Write the electronic configuration of all the metal ions in the d-blocks (3d series)
Answers
The electronic configuration of the d-block metal ions in the 3d series is represented by electronic configuration of Argon (Ar), 3d and 4s sub orbitals.
What is the electronic configuration of all d block?The electronic configuration of the d-block metal ions in the 3d series is as follows:
Scandium (Sc): [Ar] 3d¹ 4s²
Titanium (Ti): [Ar] 3d² 4s²
Vanadium (V): [Ar] 3d³ 4s²
Chromium (Cr): [Ar] 3d⁵ 4s¹
Manganese (Mn): [Ar] 3d⁵ 4s²
Iron (Fe): [Ar] 3d⁶ 4s²
Cobalt (Co): [Ar] 3d⁷ 4s²
Nickel (Ni): [Ar] 3d⁸ 4s²
Copper (Cu): [Ar] 3d¹⁰ 4s¹
Zinc (Zn): [Ar] 3d¹⁰ 4s²
Thus, the above illustration shows the electronic configuration of all the metal ions in the d-blocks (3d series).
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Which
thermochemical
equation
corresponds to
the graph?
Answers
Answer: C
Explanation:
Answer: C
Explanation:
aHow does the electronic configuration of a sodium cation differ from that of a sodium atom?
Answers
Answer:
Atomic number of sodium is 11
Electronic configuration of a sodium atom :
1s² 2s² 2p⁶ 3s¹Since sodium has one electron in its outermost shell, Therefore, sodium can easily donate it's one electron. As the result it becomes sodium cation with + 1 charge.
Electronic configuration of a sodium cation,[tex] \: \sf ({Na}^{+1}) [/tex]
1s² 2s² 2p⁶In case of sodium cation, it has fully filled electronic configuration.
Cations - Atoms that carry postive charge are called cations. Cations are formed when an atom loses its electron.
For example : [tex]\sf {Na}^{+} [/tex]
Anions - Atoms that carry negative charge are called anions. Anions are formed when an atom gains a electron.
For example : [tex]\sf {Cl}^{-} [/tex]
please help me with this lab i wasn’t here for!
3. now that you have the mass of the NaHCO3 reactant, and the mass of the product NaCI , convert each to moles and compare to the mole ratio from your balanced equation C space below for your calculations
mass NaHCO3:
mass NaCI:
moles NaHCO3:
moles NaCI:
does the mole to mole ratio for your reaction? Agree with the ratio for the balanced equation?___
4. which reactant is the excess reactant for your reaction, how do you know?
5. Using the limiting reactant calculate the maximum amount of product that can be made from this reaction.
6. using the theoretical yield in the mass of the product that you put produce calculate percent yield.
calculations:
question #3: converting mass to moles
question #5: calculating the theoretical yield
question #6: calculating percent yield
Answers
Question #3: 0.8 g of NaHCO3 mass NaCI weight: 0.4 g 0.8 g/84 g/mol, or 0.0095 moles, of NaHCO3 0.4 g/58.5 g/mol = 0.0068 moles of NaCI are the moles.
The reaction's mole to mole ratio and the ratio in the balanced equation (1:1) are in agreement. The highest quantity of NaCI that may be produced from this reaction is 0.0095 moles since NaHCO3 is the limiting reactant.
The theoretical yield of NaCI is 0.0095 moles, which is question #6. The finished product weighs 0.4 g. The percent yield is 0.4 g/0.0095 moles times 100, which is 42.1%.
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What is the number of molecules of NO, which contains 16 gm of oxygen. 14
Answers
To find the number of molecules of NO that contains 16 g of oxygen, we need to first calculate the number of moles of oxygen in 16 g of oxygen. Using the atomic weight of oxygen (16 g/mol), we can calculate:
moles of O = mass of O / atomic weight of O = 16 g / 16 g/mol = 1 mol
Next, we need to determine the number of moles of NO that contains 1 mol of oxygen. From the molecular formula of NO, we can see that 1 mol of NO contains 1 mol of oxygen. Therefore, the number of moles of NO that contains 1 mol of oxygen is also 1 mol.
Finally, we can use Avogadro's number to convert the number of moles of NO to the number of molecules of NO. Avogadro's number is approximately 6.02 x 10^23 molecules/mol. Therefore, the number of molecules of NO that contains 16 g of oxygen is:
number of molecules of NO = number of moles of NO x Avogadro's number
number of molecules of NO = 1 mol x 6.02 x 10^23 molecules/mol
number of molecules of NO = 6.02 x 10^23 molecules
Therefore, there are approximately 6.02 x 10^23 molecules of NO that contain 16 g of oxygen.
2ch4 and c2h8 how are they different
Answers
Answer:
Explanation:
Both 2CH4 and C2H8 have the same number and kind of elements. But practically, 2CH4 will be existing but C2H8 cannot exist.
which type of mutation could have the most drastic effect
on a gene a chromosomal mutation? Back up your choice.
Answers
Answer:
we need to know the definitions of the two types of mutations:
A chromosomal mutation is a change in the structure or number of chromosomes, which are the structures that carry genes. Examples of chromosomal mutations are deletions, duplications, inversions, and translocations.A gene mutation is a change in the sequence of nucleotides, which are the building blocks of DNA and RNA. Examples of gene mutations are substitutions, insertions, and deletions.Looking at the definitions, we can see that a chromosomal mutation can affect many genes at once, while a gene mutation can affect only one or a few nucleotides. Therefore, a chromosomal mutation could have the most drastic effect on a gene, because it could alter or delete an entire gene or multiple genes, resulting in major changes in the phenotype or function of an organism. A gene mutation could also have significant effects on a gene, but it could also be silent or minor depending on the location and type of the mutation. Therefore, the answer is a chromosomal mutation. One possible way to back up this choice is to give an example of a chromosomal mutation that causes a genetic disorder, such as Down syndrome or Turner syndrome.
A sphere has a diameter of 16 m. What is the volume of the sphere?
Answers
Answer:
V ≈ 2144.66 m³
Explanation:
Volume of sphere formula is:
V = 4/3 πr³
Radius is half the diameter so we divide the given diameter, 16 by 2 to get 8, the radius. Now we can solve
V = 4/3 π (8)³
V = 4/3 (512π)
V = 2048/3 π
V ≈ 2144.66 m³
Answer:
4/3 x π
Explanation:
WHEN SOME PEOPLE HAVE AN UPSET STOMACH, THEY TAKE A SODA TABLET LIKE
TUMS TO NEUTRALIZE THEIR STOMACH ACID.
THE REACTION IS HYDROCHLORIC ACID PLUS SODIUM BICARBONATE MAKES SALT,
CARBON DIOXIDE (THAT'S WHY SOME PEOPLE BURP) AND WATER.
HOW MUCH CARBON DIOXIDE AND SALT (IN GRAMS) ARE PRODUCED IF A 2 GRAM
TABLET OF SODIUM BICARBONATE IS TAKEN TO REACT WITH 18 GRAMS OF
HYDROCHLORIC ACID?
Answers
The balanced chemical equation for the reaction between hydrochloric acid (HCl) and sodium bicarbonate [tex](NaHCO_3)[/tex] is:
[tex]HCl + NaHCO_3\ - > NaCl + CO_2 + H_2O[/tex]
The coefficients in the balanced equation show that 1 mole of HCl reacts with 1 mole of [tex]NaHCO_3[/tex] to produce 1 mole of NaCl, 1 mole of [tex]CO_2[/tex], and 1 mole of [tex]H_2O[/tex]. We need to find the number of moles of [tex](NaHCO_3)[/tex] present in the tablet.
2 grams of [tex]NaHCO_3[/tex] is equivalent to 0.02 moles, and 18 grams of HCl is equivalent to 0.45 moles. Since [tex](NaHCO_3)[/tex] is limiting reagent, only 0.02 moles of NaCl and [tex]CO_2[/tex] will be produced. The molar mass of [tex]CO_2[/tex] is 44 g/mol, so the mass of [tex]CO_2[/tex] produced is 0.88 g. The molar mass of NaCl is 58.44 g/mol, mass of NaCl produced is 1.17 g.
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What mass (grams) of silver oxide would you need to decompose in order to produce 120.6 grams of silver?
Ag2O --> Ag + O2
Answers
The mass of silver oxide needed to decompose in order to produce 120.6 grams of silver is 494.5 grams.
The balanced chemical equation for silver oxide breakdown is:
[tex]Ag_2O[/tex] → [tex]2 Ag[/tex] + [tex]1/2 O_2[/tex]
The equation shows that for every mole of silver oxide that decomposes, two moles of silver are created, and the molar mass of [tex]Ag_2O[/tex] is 231.74 g/mol.
Hence, using stoichiometry, we can calculate the quantity of silver oxide necessary to generate 120.6 grams of silver:
120.6 g Ag × (1 mol Ag / 107.87 g Ag) × (1 mol [tex]Ag_2O[/tex]/ 2 mol Ag) × (231.74 g [tex]Ag_2O[/tex] / 1 mol [tex]Ag_2O[/tex] )
= 494.5 g [tex]Ag_2O[/tex]
As a result, 494.5 grams of silver oxide is needed to decompose in order to produce 120.6 grams of silver.
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How many grams of KOH are needed to make 185.5 ml with a concentration of 5 M?
Type your answer...
Answers
To calculate the mass of KOH needed to make a 5 M solution in 185.5 mL, we need to use the formula:
mass = moles × molar mass
where moles is the amount of KOH in moles and molar mass is the mass of one mole of KOH.
We can calculate the moles of KOH as follows:
moles = Molarity × Volume (in liters)
First, we need to convert the volume from milliliters to liters:
185.5 mL = 0.1855 L
Now we can calculate the moles of KOH:
moles = 5 M × 0.1855 L = 0.9275 moles
The molar mass of KOH is 56.11 g/mol. Therefore, the mass of KOH needed is:
mass = 0.9275 moles × 56.11 g/mol = 52.05 g
Therefore, 52.05 grams of KOH are needed to make a 5 M solution in 185.5 mL.
How many grams in 5 moles of water?
Answers
Answer:
90g
Explanation:
Ans. 90 gram
we know that,
n = wt/m.wt
where, n= moles
wt.= weight
m.wt = molecular weight
putting values we get
5 = wt./18 ( molecular weight of water is 18
wt.= 90
hence ans.= 90 gram
Calculate the mass of Kr
in a 9.95 L
cylinder at 91.2 ∘C
and 4.50 bar
.
Answers
To calculate the mass of Kr in a cylinder, we need to use the ideal gas law equation:
PV = nRT
where:
P = pressure = 4.50 bar
V = volume = 9.95 L
n = number of moles of Kr
R = gas constant = 0.08314 L bar K^-1 mol^-1
T = temperature = 91.2 + 273.15 K = 364.35 K
Rearranging the equation to solve for n:
n = PV/RT
n = (4.50 bar)(9.95 L)/(0.08314 L bar K^-1 mol^-1)(364.35 K)
n = 0.520 mol Kr
To calculate the mass of Kr, we need to use the molar mass of Kr, which is 83.798 g/mol. Therefore:
mass of Kr = n x molar mass
mass of Kr = 0.520 mol x 83.798 g/mol
mass of Kr = 43.544 g
Therefore, the mass of Kr in the cylinder is 43.544 g.
Please ASAP!! :'(
Which of the following graphs repMagnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial.
· Trial 1:
· Trial 2:
Determine the percent yield of MgO for your experiment for each trial.
· Trial 1:
· Trial 2:
Determine the average percent yield of MgO for the two trials.
resents the function g (x) = x2(x + 1)(x – 2)?
Answers
The theoretical yield of MgO for Trial 1 is 0.348 g, and for Trial 2 is 0.307 g. The percent yield of MgO for Trial 1 is 58.0% and for Trial 2 is 159.2%. The average percent yield of MgO for the two trials is 108.6%.
To calculate the theoretical yield of MgO, we need to use the balanced chemical equation for the reaction between magnesium (Mg) and oxygen (O2) to form magnesium oxide (MgO):
2Mg + O₂ → 2MgO
According to the stoichiometry of this equation, 2 moles of Mg react with 1 mole of O2 to produce 2 moles of MgO. Therefore, we need to determine the number of moles of Mg in each trial and use the mole ratio to find the theoretical yield of MgO.
For Trial 1:
The mass of Mg used is: 26.682 g - 27.012 g = 0.330 g
The molar mass of Mg is 24.31 g/mol, so the number of moles of Mg is:
0.330 g / 24.31 g/mol = 0.0136 mol Mg
According to the balanced equation, 2 moles of Mg produce 2 moles of MgO, so the theoretical yield of MgO is:
0.0136 mol Mg x (2 mol MgO / 2 mol Mg) x (40.31 g MgO/mol) = 0.348 g MgO
For Trial 2:
The mass of Mg used is: 26.987 g - 26.695 g = 0.292 g
The number of moles of Mg is:
0.292 g / 24.31 g/mol = 0.0120 mol Mg
The theoretical yield of MgO is:
0.0120 mol Mg x (2 mol MgO / 2 mol Mg) x (40.31 g MgO/mol) = 0.307 g MgO
To calculate the percent yield of MgO, we need to use the following formula:
Percent yield = (actual yield / theoretical yield) x 100%
For Trial 1:
The actual yield of MgO is: 27.214 g - 27.012 g = 0.202 g MgO
The percent yield of MgO is:
(0.202 g / 0.348 g) x 100% = 58.0%
For Trial 2:
The actual yield of MgO is: 27.183 g - 26.695 g = 0.488 g MgO
The percent yield of MgO is:
(0.488 g / 0.307 g) x 100% = 159.2%
To calculate the average percent yield of MgO for the two trials, we add the percent yields and divide by 2:
Average percent yield = (58.0% + 159.2%) / 2 = 108.6%
Therefore, the theoretical yield of MgO for Trial 1 is 0.348 g, and for Trial 2 is 0.307 g. The percent yield of MgO for Trial 1 is 58.0% and for Trial 2 is 159.2%. The average percent yield of MgO for the two trials is 108.6%.
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