What is the percent of 1 - 3√(5/35) ?
Answer:
1 - 3√(5/35) = 1 - 3√(1/7) = 1 - 3*(1/sqrt(7)) ≈ 0.0755
0.0755 * 100 = 7.55%
Step-by-step explanation:
To find the percentage of 1 - 3√(5/35), we need to first evaluate the expression.
1 - 3√(5/35) = 1 - 3√(1/7) = 1 - 3*(1/sqrt(7)) ≈ 0.0755
To convert this decimal to a percentage, we simply multiply by 100:
0.0755 * 100 = 7.55%
How many boys are there in an introductory Chinese course if 352 students are enrolled and there are nine boys to every seven girls?
17x = 425
x = 25
8x = 200 boys
9x = 225 girls
Use the formulas to answer this question.
One leg of a right triangle has length 11 and all sides are whole numbers. Find the lengths of the other two sides.
The other leg = and the hypotenuse =
The lengths of the other two sides of the right triangle are 36 and 85, respectively.
To find the lengths of the other two sides of a right triangle when one leg has a length of 11, we can use the Pythagorean theorem.
The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
Let's denote the lengths of the other leg and the hypotenuse as x and y, respectively.
According to the Pythagorean theorem, we have:
x² + 11² = y²
To find the values of x and y, we need to find a pair of whole numbers that satisfy this equation.
We can start by checking for perfect squares that differ by 121 (11^2). One such pair is 36 and 85.
If we substitute x = 36 and y = 85 into the equation, we have:
36² + 11² = 85²
1296 + 121 = 7225
This equation is true, so the lengths of the other two sides are:
The other leg = 36
The hypotenuse = 85
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Pls help I’m stuck Tysm I can’t thank any more
Using the concept of perimeter of polygon, the perimeter of figure C is 27cm shorter than total perimeter of A and B
How much shorter is the perimeter of C than the total perimeter of A and B?To solve this problem, we have to know the perimeter of the polygon C.
The perimeter of a polygon is the sum of all the lengths of the outer edges of the figure, that is, we must find the length of all the edges of the polygon, and then add these lengths to obtain the perimeter.
The perimeter of the figures are;
Using the concept of perimeter of a rectangle;
a. figure A = 2(4 + 11) = 30cm
b. figure B = 2(8 + 4) = 24cm
c figure C = 11 + 4 + 8 + 4 = 27cm
Now, we can add A and B and then subtract c from it.
30 + 24 - 27 = 27cm
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What is the name of the Platonic solid below
The name of the Platonic solid that resembles a cuboid is the hexahedron, or more commonly known as a cube.
The correct answer is option C.
The name of the Platonic solid that resembles a cuboid is the hexahedron, also known as a cube. The hexahedron is one of the five Platonic solids, which are regular, convex polyhedra with identical faces, angles, and edge lengths. The hexahedron is characterized by its six square faces, twelve edges, and eight vertices.
The term "cuboid" is often used in general geometry to describe a rectangular prism with six rectangular faces. However, in the context of Platonic solids, the specific name for the solid resembling a cuboid is the hexahedron.
The hexahedron is a highly symmetrical three-dimensional shape. All of its faces are congruent squares, and each vertex is formed by three edges meeting at right angles. The hexahedron exhibits symmetry under several transformations, including rotations and reflections.
Its regularity and symmetry make the hexahedron an important geometric shape in mathematics and design. It has numerous applications in architecture, engineering, and computer graphics. The cube, as a special case of the hexahedron, is particularly well-known and widely used in everyday life, from dice and building blocks to cubic containers and architectural structures.
Therefore, the option which is the correct is C.
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The question probable may be:
What is the name of the Platonic solid which resembles a cuboid?
A. Dodecaheron
B. Tetrahedron
C. Hexahedron
D. Octahedron
a) A club uses email to contact its members. The chain starts with 3 members who
each contact three more members. Then those members each contact 3 members, and
so the contacts continue.
The exponential function that represents the number of members contacted after x days is given as follows:
[tex]N(x) = 3(3)^x[/tex]
How to define an exponential function?An exponential function has the definition presented according to the equation as follows:
[tex]y = ab^x[/tex]
In which the parameters are given as follows:
a is the value of y when x = 0.b is the rate of change.The parameter values for this problem are given as follows:
a = 3 -> the chain starts with 3 members.b = 3 -> each new member contacts 3 members.Hence the function is given as follows:
[tex]N(x) = 3(3)^x[/tex]
Missing InformationThe problem asks for the exponential function that represents the number of members contacted after x days.
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What is the sum of the series?
∑k=14(2k2−4)
Enter your answer in the box.
Answer:
44
Step-by-step explanation:
The sum of the series [tex]\sum_{k=1}^4[/tex] (2k²−4) is 44.
The series is: [tex]\sum_{k=1}^4[/tex] (2k²−4)
Let's find the value of each term for k=1, k=2, k=3, and k=4, and then add them up:
For k=1:
2(1)² - 4 = 2(1) - 4 = 2 - 4 = -2
For k=2:
2(2)² - 4 = 2(4) - 4 = 8 - 4 = 4
For k=3:
2(3)² - 4 = 2(9) - 4 = 18 - 4 = 14
For k=4:
2(4)² - 4 = 2(16) - 4 = 32 - 4 = 28
Now, let's add all the terms:
-2 + 4 + 14 + 28 = 44
So, the sum of the series [tex]\sum_{k=1}^4[/tex] (2k²−4) is 44.
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……………and ………… are appropriate x-axis and y-axis unit scales given the coordinates (50, 40).
OA. 50; 10
B. 10; 5
C. 10; 50
OD. 50; 1
10 and 5 are appropriate x-axis and y-axis unit scales given the coordinates (50, 40). Option B.
To determine the appropriate x-axis and y-axis unit scales given the coordinates (50, 40), we need to consider the relationship between the units on the axes and the corresponding values in the coordinate system.
The x-axis represents the horizontal dimension, while the y-axis represents the vertical dimension. The x-coordinate (50) represents a position along the x-axis, and the y-coordinate (40) represents a position along the y-axis.
To determine the appropriate scales, we need to consider how many units on the x-axis are needed to span the distance from 0 to 50 and how many units on the y-axis are needed to span the distance from 0 to 40.
In this case, the x-coordinate is 50, which means we need the x-axis to span a distance of 50 units. However, we don't have enough information to determine the scale for the x-axis accurately. Therefore, options A (50; 10) and D (50; 1) cannot be definitively chosen.
Similarly, the y-coordinate is 40, which means we need the y-axis to span a distance of 40 units. Considering the given options, option B (10; 5) would be a suitable scale, as it allows for the y-axis to span the necessary distance of 40 units.
In summary, given the coordinates (50, 40), the appropriate unit scales would be 10 units per increment on the x-axis and 5 units per increment on the y-axis (Option B).
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Algebra Question
68% Oppose year round school
32% Favor year round school
Error +/- 5%
The error given in the graph represents the actual percent could be 5% more or 5% less than the percent reported by the survey.
A. Write and solve an absolute value equation to determine the least and greatest percent of students who could be in favor of year-round school.
B. A classmate claims that ⅓ of the student body is actually in favor of year-round school. Does this conflict with the survey data? Explain.
*can't add graph for some reason
A. To determine the least and greatest percentage of students who could be in favor of year-round school, we can use the error given in the survey, which is +/5%. Let's denote the actual percentage of students in favor of year-round school as x.
The least percentage can be found by subtracting 5% from the reported percentage of 32%:
32% - 5% = 27%
So, the least percentage of students in favor of year-round school is 27%.
The greatest percentage can be found by adding 5% to the reported percentage of 32%:
32% + 5% = 37%
Therefore, the greatest percentage of students in favor of year-round school is 37%.
Hence, the least percentage is 27% and the greatest percentage is 37%.
B. A classmate claiming that ⅓ of the student body is actually in favor of year-round school conflicts with the survey data. According to the survey, the reported percentage in favor of year-round school is 32%, which is not equal to 33.3% (⅓). Therefore, the classmate's claim contradicts the survey results.
It's important to note that the survey provides specific data regarding the percentages of students in favor and opposed to year-round school. The claim of ⅓ being in favor does not align with the survey's findings and should be evaluated separately from the survey data.
Which shows 2 products that both result in negative values
These are two instances where the product of two numbers yields a negative result.
To demonstrate two products that both result in negative values, we can choose two numbers with opposite signs and multiply them together. Here are two examples:
Example 1:
Let's consider the numbers -3 and 4. When we multiply these numbers, we get:
(-3) * (4) = -12
The product -12 is a negative value.
Example 2:
Let's consider the numbers 5 and -2. When we multiply these numbers, we get:
(5) * (-2) = -10
Once again, the product -10 is a negative value.
In both examples, we have chosen two numbers with opposite signs, and the multiplication of these numbers results in a negative value. Therefore, these are two instances where the product of two numbers yields a negative result.
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NO LINKS!! URGENT HELP PLEASE!!
Answer:
a. 36.65 in
b. 14.14 km²
Step-by-step explanation:
Solution Given:
a.
Arc Length = 2πr(θ/360)
where,
r is the radius of the circleθ is the central angle of the arcHere Given: θ=150° and r= 14 in
Substituting value
Arc length=2π*14*(150/360) =36.65 in
b.
Area of the sector of a circle = (θ/360°) * πr².
where,
r is the radius of the circleθ is the central angle of the arcHere θ = 45° and r= 6km
Substituting value
Area of the sector of a circle = (45/360)*π*6²=14.14 km²
Answer:
[tex]\textsf{a)} \quad \overset{\frown}{AC}=36.65\; \sf inches[/tex]
[tex]\textsf{b)} \quad \text{Area of sector $ABC$}=14.14 \; \sf km^2[/tex]
Step-by-step explanation:
The formula to find the arc length of a sector of a circle when the central angle is measured in degrees is:
[tex]\boxed{\begin{minipage}{6.4 cm}\underline{Arc length}\\\\Arc length $= \pi r\left(\dfrac{\theta}{180^{\circ}}\right)$\\\\where:\\ \phantom{ww}$\bullet$ $r$ is the radius. \\ \phantom{ww}$\bullet$ $\theta$ is the angle measured in degrees.\\\end{minipage}}[/tex]
From inspection of the given diagram:
r = 14 inchesθ = 150°Substitute the given values into the formula:
[tex]\begin{aligned}\overset{\frown}{AC}&= \pi (14)\left(\dfrac{150^{\circ}}{180^{\circ}}\right)\\\\\overset{\frown}{AC}&= \pi (14)\left(\dfrac{5}{6}}\right)\\\\\overset{\frown}{AC}&=\dfrac{35}{3}\pi\\\\\overset{\frown}{AC}&=36.65\; \sf inches\;(nearest\;hundredth)\end{aligned}[/tex]
Therefore, the arc length of AC is 36.65 inches, rounded to the nearest hundredth.
[tex]\hrulefill[/tex]
The formula to find the area of a sector of a circle when the central angle is measured in degrees is:
[tex]\boxed{\begin{minipage}{6.4 cm}\underline{Area of a sector}\\\\$A=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2$\\\\where:\\ \phantom{ww}$\bullet$ $r$ is the radius. \\ \phantom{ww}$\bullet$ $\theta$ is the angle measured in degrees.\\\end{minipage}}[/tex]
From inspection of the given diagram:
r = 6 kmθ = 45°Substitute the given values into the formula:
[tex]\begin{aligned}\text{Area of sector $ABC$}&=\left(\dfrac{45^{\circ}}{360^{\circ}}\right) \pi (6)^2\\\\&=\left(\dfrac{1}{8}\right) \pi (36)\\\\&=\dfrac{9}{2}\pi \\\\&=14.14\; \sf km^2\;(nearest\;hundredth)\end{aligned}[/tex]
Therefore, the area of sector ABC is 14.14 km², rounded to the nearest hundredth.
Charimaya is running a race around a square track of length 75 m. Find the distance covered by her at the end of her fifth round.
At the end of her fifth round, Charimaya would have covered a distance of 1500 meters.
To find the distance covered by Charimaya at the end of her fifth round, we need to calculate the total distance covered in one round and then multiply it by five.
Given that the track is square-shaped with a length of 75 m, we know that all four sides of the track are equal in length.
To calculate the distance covered in one round, we need to find the perimeter of the square track. Since all sides are equal, we can simply multiply the length of one side by 4.
The length of one side of the square track is 75 m. Therefore, the perimeter of the track is:
Perimeter = 4 × 75 m = 300 m
So, Charimaya covers a distance of 300 m in one round.
To find the distance covered at the end of her fifth round, we multiply the distance covered in one round by 5:
Distance covered in 5 rounds = 300 m × 5 = 1500 m
Therefore, at the end of her fifth round, Charimaya would have covered a distance of 1500 meters.
It's worth noting that since the track is square-shaped, each round consists of running along all four sides of the track.
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y = 1/3x -1
x-intercept (3,0)
How did they get this answer? Somebody please help
Answer:
Step-by-step explanation:
x-intercept is where the line cuts the x-axis. That is, when y=0.
Substitute y=0 and we get:
[tex]0=\frac{1}{3} x-1[/tex]
[tex]1=\frac{1}{3} x[/tex]
[tex]x=3[/tex]
So x-intercept is the point (3,0).
what is the answer to the question it’s geometry
Answer:
127
Step-by-step explanation:
Angle C+Angle D=Angle ABC
Since C+D+CBD=180 and ABC+CBD=180
subtract getting C+D-CBD=0 and C+D=CBD
so 67+60=127 which is your answer
*Just to clarify, when i said C and D, i meant angle C and angle D
True or false: f(x) is a function.
0
3
6
9
f(x)
0
1
3
Answer:
Step-by-step explanation:
If {0, 3, 6, 9} are are your x's or domain or input and there are no repeats, then yes TRUE it is a function.
b) Calculate the following using the order of operations and emphasizing factors of one.
2-(-7)+(-8)-(13) +-4-5
Answer:
-21
Step-by-step explanation:
2+7-8-13-4-5
9-30
-21
Hope it's helpful.
87,959 →
round to nearest hundred
pls help help needed rn asap
Step-by-step explanation:
87,959 ==> 88,000 is the nearest hundred
The answer is:
87.96Work/explanation:
When rounding to the nearest hundredth, round to 2 decimal places (DP).
Which means we should round to 5.
5 is followed by 9, which is greater than or equal to 5. So, we drop 9 and add 1 to 5 :
87. 96
Therefore, the answer is 87.96.If a pound of rolled oats costs $4
, how many ounces can be bought for $1.95
?
Answer:
7.80 ounces can be bought for $1.95
Step-by-step explanation:
Step 1: Determine how many ounces is in a pound:
Because we want our final answer to be in ounces, we first need to determine how many ounces is in a pound. 1 pound is equal to 16 ounces.Thus, 16 ounces cost $4.
Step 2: Create a proportion to determine how many ounces can be bought for $1.95.
Since you can get 16 ounces for $4, we can create a proportion to determine how many ounces can be bought for $1.95:
16 ounces / $4 = x ounces / $1.95
Step 3: Simplify on the left-hand side of the equation:
16/4 = x/1.95
4 = x/1.95
Step 4: multiply both sides by 1.95 to determine how many ounces can be bought for $1.95:
(4 = x/1.95) * 1.95
7.80 = x
Thus, 7.80 ounces can be bought for $1.95.
DC=x-2
Height=4
AB=2x+4
The area of the trapezoid ABCD shown above is 70 square units. Calculate x.
Answer:
Step-by-step explanation:To calculate the value of x, we can use the formula for the area of a trapezoid:
Area = (1/2) * (sum of the parallel sides) * height
Given that the area of the trapezoid ABCD is 70 square units, we can set up the equation as follows:
70 = (1/2) * (AB + DC) * Height
Substituting the given values:
70 = (1/2) * ((2x + 4) + (x - 2)) * 4
Simplifying the equation:
70 = (1/2) * (3x + 2) * 4
Multiplying both sides by 2 to remove the fraction:
140 = (3x + 2) * 4
Dividing both sides by 4:
35 = 3x + 2
Subtracting 2 from both sides:
33 = 3x
Dividing both sides by 3:
x = 11
Therefore, the value of x is 11.
3,20,110 _1715 This is an mathematics question
The pattern between the numbers 3, 20, 110, and 1715 can be found using a mathematical method. In order to get the following number from each, there is a sequence that must be applied.Let's take a look at the sequence that was used to generate these numbers:
The first number is multiplied by 2 and then increased by 14 to get the second number. For example:
3 x 2 + 14 = 20
Then, the second number is multiplied by 3 and 20, and 110 is added.
20 x 3 + 110 = 170
The third number is multiplied by 4 and then increased by 110.
110 x 4 + 110 = 550
Finally, the fourth number is multiplied by 5 and then increased by 110.
550 x 5 + 110 = 2825
Therefore, using the above formula, the next number in the sequence can be calculated:
1715 x 6 + 110 = 10400
As a result, the sequence of numbers 3, 20, 110, 1715, 10400 can be calculated using the mathematical formula stated above.
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Seventy-Two Inc., a developer of radiology equipment, has stock outstanding as follows: 80,000 shares of cumulative preferred 3% stock, $20 par and 410,000 shares of $25 par common. During its first four years of operations, the following amounts were distributed as dividends: first year, $31,000; second year, $73,000; third year, $80,000; fourth year, $120,000. Determine the dividends per share on each class of stock for each of the four years. Round all answers to two decimal places. If no dividends are paid in a given year, enter "0.00". 1st Year 2nd Year 3rd Year 4th Year Preferred stock (dividends per share) $fill in the blank 1 $fill in the blank 2 $fill in the blank 3 $fill in the blank 4 Common stock (dividends per share)
Find the area of the shaded portion if we know the outer circle has a diameter of 4 m and the inner circle has a diameter of 1.5 m.
A. 43.2 m2
B. 10.8 m2
C. 12.6 m2
D. 1.8 m2
de un grupo de 75 alumnos se sabe que 20 estudian mate y física determina la probabilidad que al escoger un alumno estudie a) estudie solo mate b) estudie mate o fisica c) que no estudié ninguna de las dos d) que estudie mate y fisica
A) The probability that a randomly selected student studies only mathematics would be 20/75.
B) The probability that a randomly selected student studies mathematics or physics would be (20 + X) / 75.
C) The probability that a randomly selected student does not study either of the two subjects would be (75 - (20 + X)) / 75.
D) The exact probability that a student studies mathematics and physics cannot be determined without knowing the number of students who study both subjects.
To determine the requested probabilities, we will use the information provided about the group of 75 students.
a) Study only mate:
We know that there are 20 students studying mathematics and physics, so the number of students studying only mathematics would be the total number of students studying mathematics (20) minus the number of students studying both subjects. Since no information is provided on the number of students studying both subjects, we will assume that none of the students study both subjects. Therefore, the number of students studying only mathematics would be 20 - 0 = 20.
The probability that a randomly selected student studies only mathematics would be 20/75.
b) Study math or physics:
To determine this probability, we need to add the number of students who study mathematics and the number of students who study physics, and then subtract the number of students who study both subjects (we again assume that none of the students study both subjects).
Number of students studying mathematics = 20
Number of students studying physics = X (not given)
Number of students studying both subjects = 0 (assumed)
Therefore, the number of students studying mathematics or physics would be 20 + X - 0 = 20 + X.
The probability that a randomly selected student studies mathematics or physics would be (20 + X) / 75.
c) That he does not study either:
The number of students not studying either subject would be the complement of the number of students studying mathematics or physics. So it would be 75 - (20 + X).
The probability that a randomly selected student does not study either of the two subjects would be (75 - (20 + X)) / 75.
d) To study math and physics:
Since no information is provided on the number of students studying both subjects, we cannot determine the exact probability that a student will study mathematics and physics.
In summary:
a) The probability that a randomly selected student studies only mathematics would be 20/75.
b) The probability that a randomly selected student studies mathematics or physics would be (20 + X) / 75.
c) The probability that a randomly selected student does not study either of the two subjects would be (75 - (20 + X)) / 75.
d) The exact probability that a student studies mathematics and physics cannot be determined without knowing the number of students who study both subjects.
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NO LINKS!! URGENT HELP PLEASE!!
Find each indicated measure
Answer:
b. 160°
d. 55°
Step-by-step explanation:
The Inscribed Angle Theorem states that an inscribed angle is half of the central angle that subtends the same arc.
In other words, if an angle is inscribed in a circle and it intercepts an arc, then the measure of the inscribed angle is equal to half the measure of the central angle that also intersects that arc.
For question:
b.
By using above theorem:
m arc XW=2* m arc XYW
m arc XW= 2*80=160°
d.
m arc WV=125°
The Inscribed Angle Diameter Right Angle Theorem states that any angle inscribed in a circle that intercepts a diameter is a right angle.
By using this theorem:
m arc WV+m arc XV =180°
Now
m arc XV =180°-m arc WV
m arc XV=180°-125°
n arc XV=55°
Answer:
[tex]\text{b.} \quad m\overset{\frown}{XW}=160^{\circ}[/tex]
[tex]\text{d.} \quad m\overset{\frown}{XV}=55^{\circ}[/tex]
Step-by-step explanation:
An inscribed angle is the angle formed (vertex) when two chords meet at one point on a circle.
An intercepted arc is the arc that is between the endpoints of the chords that form the inscribed angle.
[tex]\hrulefill[/tex]
Part bFrom inspection of the given circle:
The inscribed angle is m∠WRX = 80°The intercepted arc is arc XW.According to the Inscribed Angle Theorem, the measure of an inscribed angle is half the measure of the intercepted arc. Therefore:
[tex]m \angle WRX = \dfrac{1}{2}\overset{\frown}{XW}[/tex]
[tex]80^{\circ}= \dfrac{1}{2}\overset{\frown}{XW}[/tex]
[tex]\boxed{m\overset{\frown}{XW}=160^{\circ}}[/tex]
[tex]\hrulefill[/tex]
Part dFrom inspection of the given circle:
The inscribed angle is m∠WVX = 90°The intercepted arc is arc WX.According to the Inscribed Angle Theorem, the measure of an inscribed angle is half the measure of the intercepted arc. Therefore:
[tex]m \angle WVX= \dfrac{1}{2}\overset{\frown}{WX}[/tex]
[tex]90^{\circ}= \dfrac{1}{2}\overset{\frown}{WX}[/tex]
[tex]m\overset{\frown}{WX}=180^{\circ}[/tex]
The sum of the measures of the arcs in a circle is 360°.
[tex]m\overset{\frown}{VW}+m\overset{\frown}{WX}+m\overset{\frown}{XV}=360^{\circ}[/tex]
Therefore, so find the measure of arc XV, substitute the found measures of arcs VW and WX, and solve for arc XV:
[tex]125^{\circ}+180^{\circ}+m\overset{\frown}{XV}=360^{\circ}[/tex]
[tex]305^{\circ}+m\overset{\frown}{XV}=360^{\circ}[/tex]
[tex]\boxed{m\overset{\frown}{XV}=55^{\circ}}[/tex]
what is the 20th term of the sequence that begins -4, 8, -16, 32...?
Answer:
-2097152 is the 20th term
Step-by-step explanation:
Write geometric sequence as an explicit formula
[tex]-4,8,-16,32\rightarrow-4(-2)^0,-4(-2)^1,-4(-2)^2,4(-2)^3\\a_n=a_1r^{n-1}\rightarrow a_n=-4(-2)^{n-1}[/tex]
Find the n=20th term
[tex]a_{20}=-4(-2)^{20-1}=-4(-2)^{19}=4(-524288)=-2097152[/tex]
A right circular cone is intersected by a plane that passes through the cone's
vertex and is perpendicular to its base, as in the picture below. What is
produced from this intersection?
OA. A pair of parallel lines
B. A single line
OC. A point
OD. A pair of intersecting lines
Answer:
D. A pair of intersecting lines
Step-by-step explanation:
A conic section is a fancy name for a curve that you get when you slice a double cone with a plane. Imagine you have two ice cream cones stuck together at the tips, and you cut them with a knife. Depending on how you cut them, you can get different shapes. These shapes are called conic sections, and they include circles, ellipses, parabolas and hyperbolas. If you cut them right at the tip, you get a point. If you cut them slightly above the tip, you get a line. If you cut them at an angle, you get two lines that cross each other. That's what happened in your question. The plane cut the cone at an angle, so the curve is two intersecting lines. That means the correct answer is D. A pair of intersecting lines.
I hope this helps you ace your math question.
what is 34.6285 rounded to the nearest hundreds
Answer:
34.63
Step-by-step explanation:
The 2 in 34.6285 marks the hundredths place
We can round by seeing what number is to the right of it which is 8.
Since 8 is larger than 5, we round up by 1.
Thus, 34.63 is our answer
The answer is:
34.63
Work/explanation:
Rounding to the nearest hundredth means rounding to 2 decimal places (DP).
So we have 2 decimal places, and the 3rd one matters too because it will determine the value of the 2nd DP.
The third DP is 8. Since it's greater than 5, then the value of the 2nd DP will be rounded up. I will add 1 to it.
Remember that we round up when the digit that we're rounding to is followed by another digit that is greater than or equal to 5.
So we round :
[tex]\bf{34.6285 =\!=\!\!\! > 34.63}[/tex]
Therefore, 34.6286 rounded to the nearest hundredth is 34.63.Solve the system of equations.
y=x+5y=x2+5x−7
Enter your answers in the boxes.
Here's the answer for you guys if you need it (:
Answer:
(2, 7) and (-6, -1)
Step-by-step explanation:
y = x + 5
y = x² + 5x − 7
Equatig the above,
x² + 5x − 7 = x + 5
⇒ x² + 4x −12 = 0
⇒ x² + 6x - 2x - 12 = 0
⇒ x(x + 6) - 2(x + 6) = 0
⇒ (x - 2)(x + 6) = 0
⇒ x = 2 or x = -6
Eq(1) : y = x + 5 (given)
When x = 2
y = 2 + 5 = 7
Point : (2, 7)
When x = -6
y = -6 + 5 = -1
Point: (-6, -1)
Predict the number of sales in month 5
The predicted sales in month 5 is -2778.
Obtaining the linear equation which models the data :
y = bx + cb = slope = (y2-y1)/(x2-x1)
b = (926-7408)/(4-1)
b = -2160.67
c = intercept ;
taking the points (x = 2 and y = 3704)
Inserting into the general equation:
3704 = -2160.67(2) + c
3704 = -4321.33 + c
c = 3704 + 4321.33
c = 8025.33
General equation becomes : y = -2160.67x + 8025.33
To obtain sales in month 5:
y = -2160.67(5) + 8025.33
y = -2778
Hence, the predicted sales in month 5 is -2778.
Learn more on linear regression: https://brainly.com/question/25987747
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I’ll give lots of points to help me because I need this answer
Answer:
| x | -7
---------------
x | x² | -7x
-4 | -4x | 28
x² - 11x + 28 = (x - 4)(x - 7)