real answers only pls

Real Answers Only Pls

Answers

Answer 1

Answer:

1. it spins

2. falls in a curve

3. falls flat on the floor


Related Questions

Compare and contarst the difference between saturated and unsaturated solutions and supersaturated

Answers

Answer:

Unsaturated Solution: Less amount of salt in water, clear solution, no precipitation. Saturated Solution: The maximum amount of salt is dissolved in water, Colour of the solution slightly changes, but no precipitation. Supersaturated Solution: More salt is dissolved in water, Cloudy solution, precipitation is visible

please help me
7. If microsecound = 0.5, how much force must be applied to a spring (spring constant of 0.8 N/m) which is attached to a block of wood (mass = 4.0 kg) in order to just begin to move the block?​

Answers

Answer:

Explanation:

Your question is quite confusing, particularly the information about microsecond = 0.5.

I'm going to ASSUME that you mean coefficient of static friction μs = 0.5

unfortunately typing a subscript "s" is very difficult and probably leads to such confusion.

I will also ASSUME that the block, and spring, and force vector are all horizontal.

If the force is slowly increased until the block slips, the spring will compress until the force on each end equals the maximum static friction force. As we are not concerned with the compression distance, only the force, we can ignore the spring constant information and simply find the maximum available static friction force.

F = μN

F = μmg

F = 0.5(4.0)(9.8)

F = 19.6 N

Not that it matters, but the spring will have extended or compressed 19.6/0.8 = 24.5 m, which is a very long and very light spring

Suppose a ball is dropped from a building. What is the change of velocity between the first and fifth seconds of its flight

Answers

Answer: 39.2m/s

Explanation:

Due to the free falling body, the acceleration of the ball is 9.8 m/s^2, and its initial velocity is 0 m/s.

V(t) = g*t

The change of velocity from t=1 to t=5:

Delta V = 9.8*(5-1) = 39.2 m/s

When converted to a household measurement, 9 kilograms is approximately equal to a

Answers

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

Does static electricity light our homes? True or false

Answers

Answer:

No, false.

Explanation:

You may use it to power a light bulb if you desired. The reason it isn't is because it's inconsistent not predictable.

The static electricity light our homes. This statement is false.

What is static electricity?

When two objects are rubbed, they get charged by friction present into it. Object can also be charged by induction.

The charge gets accumulated on them, due to which spark occurs.

This spark cannot light our homes. As, this has very less magnitude and no continuous flow. There is no complete circuit to get the continuous flow of electricity.

Thus, static electricity can't light our homes.

Learn more about  static electricity.

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How 2cos theta ×sin theta is =sin2theta

Answers

Answer:

Can you rewrite that sorry

Explanation:

Computes average speed when a person walk for 1 minute at speed of 1.5 m/s and another 1 minute at speed of 3.5 m/s along a straight road

Answers

Answer:

2.5 m/s

Explanation:

(60*1.5+60*3.5)/120=2.5

or

(1.5+3.5)/2=2.5

Tell me any 5 importance of medicinal plants​

Answers

Answer:

Aloe, Tulsi, Neem, Turmeric, and Ginger are medicinal plants that can help with a variety of diseases. Ginger, green tea, walnuts, aloe, pepper, and turmeric are just a few of these plants. Some plants and their derivatives are key sources of active compounds used in aspirin and toothpaste, among other things.

Explanation:

Plant name:                                    Uses:

1. Marshmallow:      ////  Relief from aching muscles and pain in muscle, Heals insect bite.             ////

2.California poppy ////  Relieves tension, Removes nervous system

3. Tulsi                ////   Cures sore throat, Cures fever and asthma

4. Neem               ////       Cures skin diseases, Cures diabetics

5. Aloevera      ////             Heals burns, Relieves constipation

(Hope this helps can I pls have brainlist (crown)☺️)

What particles are considered to be the basic building blocks of elements?

Answers

Answer:

Atoms.

Explanation:

The fundamental structure obstructs that make matter are called molecules. What are the various particles found in iotas? (Reply: electrons, protons and neutrons) Where are they found? (Reply: Protons and neutrons are found in the core, and electrons are found in shells around the outside of the core.)

Really hope this helps! :D

Explanation:

The basic components of matter are called atoms. What are the various particles present in an atom?

(Answer: electrons, protons, neutrons) Where are they? (Answer: Protons and neutrons are in the nucleus, and electrons are in the shell around the nucleus.)

A normal atom is electronically ** (positive/negative/neutral) because the number of ** (protons/neutrons/electrons), each with a positive charge, equals the number of ** (protons/neutrons/electrons), each with a negative charge.

The answers to multiple choice questions are in parentheses​

Answers

Answer:

(neutral)

(protons)

(electrons)

Explanation:

Electrons have a negative charge (-) while protons have a positive (+) charge.

Atoms will usually be neutral, which means that there will be no charge.

For an atom to have a neutral charge, protons and electrons must "cancel" each other out. For this to happen, you need to have the same amount of each.

Positive will "cancel" out the negative.

David drives and slows to a stop when he sees a stop sign. A graph of his velocity over time is shown below.
Velocity
20-
P6
15+
As:
10+
MY
5+
Time (s)
Col
t
5
10
15
20
MY
Pro
What is his average acceleration from 10 to 20 seconds?
Pro

Answers

Answer:

-2.0

Explanation:

Two spherically symmetric planets with no atmosphere have the same average density, but planet B has twice the radius of planet A. A small satellite of mass mA has period TA when it orbits planet A in a circular orbit that is just above the surface of the planet. A small satellite of mass mB has period TB when it orbits planet B in a circular orbit that is just above the surface of the planet.

Answers

A period of a satellite is the time taken by the satellite to travel round a

body.

The comparison between the periods  [tex]T_B[/tex], and [tex]T_A[/tex] is [tex]\underline {T_B = \dfrac{\sqrt{2} }{4 } \cdot T_A}[/tex]

Reason:

The period, T, of a satellite is given as follows;

[tex]T = 2 \cdot \pi \cdot \sqrt{\dfrac{r^3}{G \cdot M} }[/tex]

Volume of the planet A = [tex]\dfrac{4}{3} \cdot \pi \cdot r^3[/tex]

Mass of planet A, [tex]m_A[/tex] = [tex]\dfrac{4}{3} \cdot \pi \cdot r^3 \times \rho[/tex]

Volume of the planet B = [tex]\dfrac{4}{3} \cdot \pi \cdot (2 \cdot r)^3 = \dfrac{32}{3} \cdot \pi \cdot r^3[/tex]

Mass of planet B, [tex]m_B[/tex] = [tex]\dfrac{32}{3} \cdot \pi \cdot r^3 \times \rho[/tex]

Period of the satellite on planet A, [tex]T_A[/tex], is given as follows;

[tex]T_A = 2 \cdot \pi \cdot \sqrt{\dfrac{r^3}{G \times \dfrac{4}{3} \cdot \pi \cdot r^3 \times \rho} } = 2 \cdot \pi \cdot \sqrt{\dfrac{1}{G \times \dfrac{4}{3} \cdot \pi \times \rho} }[/tex]

Period of the satellite on planet B, [tex]T_B[/tex], is given as follows;

[tex]T_B = 2 \cdot \pi \cdot \sqrt{\dfrac{r^3}{G \times \dfrac{32}{3} \cdot \pi \cdot r^3 \times \rho} } = 2 \cdot \pi \cdot \sqrt{\dfrac{1}{G \times \dfrac{32}{3} \cdot \pi \times \rho} }[/tex]

Therefore, get;

[tex]\dfrac{T_A}{T_B} = \dfrac{ 2 \cdot \pi \cdot \sqrt{\dfrac{3}{G \times 4 \cdot \pi \times \rho} }}{ 2 \cdot \pi \cdot \sqrt{\dfrac{3}{G \times 32 \cdot \pi \times \rho} }} = \sqrt{\dfrac{32}{4} } = \sqrt{8} = 2 \cdot \sqrt{2}[/tex]

Therefore, [tex]T_A[/tex] = (2·√2)·[tex]T_B[/tex]

[tex]T_B = \dfrac{T_A}{2 \cdot \sqrt{2} } = \dfrac{\sqrt{2} \cdot T_A}{4 }[/tex]

The comparison between [tex]T_A[/tex] and  [tex]T_B[/tex] is therefore;

[tex]\underline {T_B = \dfrac{\sqrt{2} }{4 } \cdot T_A}[/tex]

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Which theory of emotion explains the startle response

Answers

Answer:

In the present study, the startle blink reflex is used as a measure of emotion regulation to effective picture stimuli. Based on the aphasic theory of emotion, it is hypothesized that the startle response will be largest in magnitude in the presence of negative emotional stimuli (Varanasi, Spence, & Lang, 1988).

What is the net force on a cart being pushed with an applied force of 23 N with a frictional force of 23 N?​

Answers

Answer:  

1N  

Explanation:

Pretty simple Divide 23 by 23 which gives you 1.

23N ÷ 23N = 1N

Answer:

[tex]\sf \longmapsto \: 1 \: N[/tex]

Explanation:

[tex]\sf \longmapsto \frac{23N}{23N} [/tex]

[tex]\sf \longmapsto1 \: N[/tex]

Based on your observations, what can you say about your prediction in Parts A and B above concerning the potential and kinetic energy?

Answers

Answer:

Explanation:

My perdiction was correct. I predicted in Part A that the Kinetic Energy would increase. In Part B I predicted that the potential energy would decrease due to the kinetic energy increasing.

Which of the following statement describes a nonpolar molecule

Answers

Answer:

?

Explanation:

what are the statements

Can you show us a picture please

You throw a rock up into the air as hard as you can. It stays in the air a total of 6.0 s. What
was the velocity of the rock when you threw it?

Answers

Answer:

5.9 x 10

Explanation:

PHYSICISTS NEEDED, THANK YOU, (10 POINTS)

Answers

Answer:

would it be 2.66666666667 or 2.7

Explanation:

Technician a says that the piston engine starts and stops several times per 2nd technician B says that with the rotary engine each rotor has 3 working chambers so it acts like a 3 cylinder engine while it is at operating

Answers

Answer:

Explanation:

trfbehherebgqerfherbfhyqerwbfvhrbhferhgvr

When converted to a household measurement, 9 kilograms is approximately equal to a

Answers

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

1. What does the term monecious mean?

Answers

Answer:

Monecious is a plant or invertebrate animal having both the male and female reproductive organs in the same individual; hermaphrodite.

ounces is In the apothecary system of measurement, equal to one apothecary pound. a) eight b) 16 c) 12 d) four

Answers

the answer is one apothecary pound = 12 ounces

What is the kinetic energy of a 36N toy car which is moving at 5 m/s?

Answers

Answer : I think the answer is 45 J
Explanation: in the picture

A car’s velocity as a function of time is given by Vx (t) = α.t + β.t 2 , where α= 3m/s and β= 0.1m/s 3 . Calculate the average acceleration for the time interval

b) t= 5 to t = 10 s

Answers

The definition of average acceleration allows to find the result for the average acceleration in the given time interval is:

          [tex]a_{average}= 1.5 \ \frac{m}{s^2}[/tex]

Instantaneous acceleration is defined as the derivative of velocity with respect to time.

           a =   [tex]\frac{dv}{dt}[/tex]

Where a is the acceleration, v the velocity and t the time.

They indicate that the speed of the car is given by the relation.

          v = α t + β t²

With α = 3 m / s and β = 0.1 m / s³

Let's make  the derivative.

           a = α + 2β t

Let's substitute

            a = 3 + 2 0.1 t

Average acceleration is the change in velocity in the time interval.  

          [tex]a_{average} = \frac{\Delta v}{\Delta t }[/tex]

Let's find the velocity at the indicated time.

For t = 5 s

         v₅ = 3 + 0.1 5²

         v₅ = 5.5 m / s

For t = 10 s

          v₁₀ = 3 + 0.1 10²

          v₁₀ = 13 m / s

Let's calculate the average acceleration.

           [tex]a_{average} = \frac{13 - 5.5 }{ 10 - 5 }\\[/tex]

           [tex]a_{average}= 1.5 \ m/s^2[/tex]

In conclusion using the definition of mean acceleration we can find the result for the mean acceleration in the given time interval is:

           [tex]a_{average} =[/tex]  1.5 m / s²

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how long untill the semester is done

Answers

Vvvbbnnnjjbbhxbdbehhehdbdbdbdh

THE BEST ANSWER WILL BE MARKED THE BRAINLIEST!

While driving your car at a fast constant speed, you have to press down hard on your gas pedal than you do while driving at a slower constant speed.

In both cases, the net force on your car is zero. Explain why you have to apply a greater pressure to your gas pedal.

Answers

Answer:

You have to apply more pressure to the pedal so more gas runs through the car allowing it to reach higher speeds

To move, a car or any other object must be accelerated from rest to the desired speed; this necessitates that the engine force be greater than the friction force. The net force must be zero once the car is moving at constant velocity; otherwise, the car will accelerate (gain speed).

What forces act on a car at constant speed?All forces acting on a car moving at a constant speed (uniform motion) are balanced. In this case, the two opposing backward forces (air resistance and friction) perfectly balance the applied force of the wheels on the road.When we say constant speed, we mean that a body or object moves at a constant change in distance over time. For example, if we are walking in a straight line at 1 step per second, we can say we are moving at a constant speed. Our acceleration is equal to zero in this case.

To learn more about : Speed

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Discuss How are the acceleration, the net force, and the mass of
an object related? SC.6.P.13.3
13 SEBS

Answers

According to Newton's second law

[tex]\\ \sf\longmapsto Force=Mass\times Acceleration[/tex]

[tex]\\ \sf\longmapsto Mass=\dfrac{Force}{Acceleration}[/tex]

[tex]\\ \sf\longmapsto Acceleration=\dfrac{Force}{Mass}[/tex]

- The rocket now has a thruster that malfunctions and is now pushing the rocket in the wrong direction. What is the new net force on the rocket if it is now accelerating at 12mls²​

Answers

From your previous question

Mass=30kg

Acceleration=12m/s^2

[tex]\\ \sf\longmapsto F=ma[/tex]

[tex]\\ \sf\longmapsto F=30(12)[/tex]

[tex]\\ \sf\longmapsto F=360N[/tex]

Given,

Acceleration = 12 m/s²

According to your previous question you posted,

Mass = 30 KG

Solution:

We know that the formula of force according to the Newton's second law is:

[tex]\longmapsto \sf \red{f = m \times a}[/tex]

[tex]\sf \longmapsto \ 30 \times 12[/tex]

[tex]\sf \longmapsto \: \boxed {\sf \blue3 \red60}[/tex]

Answer:

[tex]\sf \boxed{ \bf \: force = 360\: N}[/tex]

name a substance which will undergo change E​

Answers

Answer:

Water

Explanation:

At 0 degrees it's solid...Then it melts into a liquid and at 100 degrees it's gas Simple

Indicate whether each of the following statements about car collisions is true or false. Select all that are True.

a. If two identical cars with identical speeds collide head on, the magnitude of the impulse received by each car and each driver is the same as if one car at the same speed had collided head on with a concrete wall.
b. Car 1 has mass m, and car 2 has mass 2m. In a head-on collision of these cars while moving at identical speeds in opposite directions, car 1 experiences a bigger acceleration than car 2.
c. The essential safety benefit of crumple zones (parts of the front of a car designed to receive maximum deformation during a head-on collision) is due to their absorbing kinetic energy, converting it into deformation, and lengthening the effective collision time, thus reducing the average force experienced by the driver.
d. Car 1 has mass m, and car 2 has mass 2m. In a head-on collision of these cars while moving at identical speeds in opposite directions, car 1 receives an impulse of bigger magnitude than that received by car 2. If car 1 has mass m and speed v, and car 2 has mass 0.5m and speed 1.5v, then both cars have the same momentum.

Answers

Answer:

True statements a, b, and c

Explanation:

Answer d is false because in any collision, each object receives the same impulse. Also the momentum of car 1 is mv, while the momentum of car 2 is 0.5m(1.5v) = 0.75mv

The impulse of collision of cars depends on the mass and velocity of the cars. The statements which are true about the car collisions are option a, b, c.

What is impulse?

Impulse is a physical quantity expressed as the product of force and time. The change in momentum mΔV is numerically equals to the impulse F t.

If two identical cars with identical speeds collide head on, the magnitude of the impulse received by each car and each driver is the same as if one car at the same speed had collided head on with a concrete wall. Because they have equal mass and velocity.

The bigger acceleration is experienced by the one which have lighter mass thus car 1 with lower mass experience higher acceleration .

The essential safety benefit of crumple zones (parts of the front of a car designed to receive maximum deformation during a head-on collision) is due to their absorbing kinetic energy.

Converting this energy into deformation, and lengthening the effective collision time, thus reducing the average force experienced by the driver.

The momentum change is proportional to the velocity. The one which have higher velocity is having the higher momentum. Thus car 2 have higher velocity. Thus option d is false.

Therefore, the statements which are true are a, b and c.

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