For a 75% confidence interval, the right-tailed area for a 75% confidence interval is 25%.
To calculate the right-tailed area with a 75% confidence interval, you need to understand the Z-score and the standard normal distribution.
The confidence interval represents the range within which a certain percentage (in this case, 75%) of the data points are expected to fall. Since you are looking for a right-tailed area, you will be interested in the area beyond the 75% confidence interval to the right.
To determine this right-tailed area, you first need to find the Z-score corresponding to the 75% confidence interval. Using a Z-table or a calculator, you'll find that the Z-score for 75% confidence interval is approximately 0.674.
Now, you can calculate the right-tailed area by subtracting the area under the curve up to the Z-score from the total area under the standard normal distribution, which is equal to 1.
Right-tailed area = 1 - 0.75 = 0.25 or 25%
So, the right-tailed area for a 75% confidence interval is 25%.
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Laura is driving to Los Angeles. Suppose that the remaining distance to drive (in miles) is a linear function of her driving time (in minutes). When graphed, the function gives a line with a slope of -0.85. See the figure below. Laura has 52 miles remaining after 41 minutes of driving. How many miles were remaining after 33 minutes of driving?
The remaining distance after 33 minutes of driving = 58.8 miles.
Here, the slope of a linear function the remaining distance to drive (in miles) is -0.85
For this situation, we can write a linear equation as,
remaining distance = (slope)(drive time) + (intercept)
remaining distance = -0.85(drive time) + (intercept)
y = -0.85x + c ..........(1)
where y represents the remaining distance
x is the drive time
and c is the y-intercept
Here, Laura has 52 miles remaining after 41 minutes of driving.
i.e., x = 41 and y = 52
Substitute these values in equation (1)
52 = -0.85(41) + c
c = 52 + 34.85
c = 86.85
So, equation (1) becomes,
y = -0.85x + 86.85
Now, we need to find the remaining distance after 33 minutes of driving.
i.e., the value of y for x = 33
y = -0.85(33) + 86.85
y = -28.05 + 86.85
y = 58.8
This is the remaining distance 58.8 miles.
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If Franco's Pizza Parlor knows that the marginal cost of the 500th pizza is $3.50 and that the average total cost of making 499 pizzas is $3.30, then
a. average total costs are falling at Q = 500.
b. average variable costs must be falling.
c. average total costs are rising at Q = 500.
d. total costs are falling at Q = 500.
If Franco's Pizza Parlor knows that the marginal cost of the 500th pizza is $3.50 and that the average total cost of making 499 pizzas is $3.30, then Average total costs are rising at Q = 500. The correct answer is (c)
The marginal cost is the additional cost of producing one more unit. In this case, the marginal cost of the 500th pizza is $3.50.
The average total cost is the total cost of producing all units up to a certain level, divided by the number of units produced. In this case, the average total cost of making 499 pizzas is $3.30.
If the marginal cost of producing the 500th pizza is greater than the average total cost of making the first 499 pizzas, then the average total cost will increase when the 500th pizza is produced.
Therefore, the correct answer is (c) average total costs are rising at Q = 500.
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A particle moves along the x-axis with velocity given by v(t) = 3t2 + 6t for time t ≥ 0. If the particle is at position x = 2 at time t = 0, what is the position of the particle at t = 1?
The position of the particle at time t = 1 is x = 4 units.
What is the position of a particle that moves along the x-axis with velocity v(t) = [tex]3t^2[/tex] + 6t at time t = 1 if it is at position x = 2 at time t = 0?To find the position of the particle at time t = 1, we need to integrate the given velocity function v(t) with respect to time from 0 to 1:
x(t) = ∫v(t)dt (from t = 0 to t = 1)
= ∫([tex]3t^2[/tex]+ 6t)dt (from t = 0 to t = 1)
= ([tex]t^3 + 3t^2[/tex]) (from t = 0 to t = 1)
[tex]= (1^3 + 3(1^2)) - (0^3 + 3(0^2))[/tex]
= 4
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Solve each system by substitution
Y=-2x+4
y=-3x+3
Answer: x = -1, y = 6
Step-by-step explanation:
lets substitute the value of y from the first equation into the y in the second equation.
-2x + 4 = -3x + 3
4 - 3 = -3x + 2x
1 = -1x
x = -1
we know from before that y = -2x + 4
so y = -2(-1) + 4
y = 6
A license plate is made of three letters and three numbers, how many different license plates are possible?
There are 17,576,000 different license plates possible, considering 26 letters (A-Z) and 10 numbers (0-9).
There are 26 options for each of the three letters and 10 options for each of the three numbers. Therefore, using the multiplication principle, the total number of possible license plates is 26 x 26 x 26 x 10 x 10 x 10 = 17,576,000.
Alternatively, we can use the permutation formula to calculate the number of arrangements: P(26,3) x P(10,3) = 15,600 x 720 = 11,251,200.
However, since order does not matter in a license plate, we need to divide by the number of permutations of three letters and three numbers, which is 3! x 3! = 36, resulting in 11,251,200 / 36 = 17,576,000 possible license plates.
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What’s the answer? I need help please
Answer: 10/12
Step-by-step explanation:
since they give you adjacent to angle m and hypotenuse use
cos x = opp/hyp
cos M = 10/12
A company manufactures to types of cabinets, type 1 and type 2. It produces 110 total cabinet’s each week.
Last week, the number of type 2 cabinets produced exceeded twice the number of type 1 cabinets produced by 20. If x is the number of type 1 cabinets produced and y is the number of type 2 cabinets produced, the system of equations that represent this situation is x + y = 110 and y = 2x+20
The number of type 2 cabinets produced last week is ____. This number exceeds the number of type 1 cabinets produced durin the week by ______.
The number of type 2 cabinets produced last week is 80. The number of type 2 cabinets produced last week exceeded the number of type 1 cabinets produced during the week by 50.
Using the system of equations given, we can solve for the number of type 1 and type 2 cabinets produced.
x + y = 110 represents the total number of cabinets produced, where x is the number of type 1 cabinets and y is the number of type 2 cabinets produced.
y = 2x + 20 represents the relationship between the number of type 1 and type 2 cabinets produced. This equation tells us that the number of type 2 cabinets produced exceeds twice the number of type 1 cabinets produced by 20.
To solve for y, we substitute the value of y from the second equation into the first equation:
x + (2x + 20) = 110
Simplifying this equation:
3x + 20 = 110
3x = 90
x = 30
Therefore, the number of type 1 cabinets produced last week is 30.
To find the number of type 2 cabinets produced, we substitute x = 30 into the second equation:
y = 2x + 20 = 2(30) + 20 = 80
The number of type 2 cabinets produced last week exceeds the number of type 1 cabinets produced during the week by:
80 - 30 = 50.
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a gambler is going to play a gambling game. in each game, the chance of winning $3 is 2/10, the chance of losing $2 is 3/10, and the chance of losing $1 is 5/10. suppose the gambler is going to play the game 5 times. (a) write down the box model for keeping track of the net gain. (you already did this in a previous lab.) (b) now write down the box model for keeping track of the number of winning plays. (c) calculate the expected value and standard error for the number of winning plays. (d) would it be appropriate to use the normal approximation for the number of winning plays? why or why not?
The expected value and standard error for the number of winning plays is $3.1 and $ 2.21.
The population mean's likelihood to differ from a sample mean is indicated by the standard error of a mean, and simply standard error.
It reveals how much what the sample mean will change if a study were to be repeated with fresh samples drawn from a single population.
Chance of winning $3 = 2/10
chance of losing $2 = 3/10
chance of losing $1 = 5/10
Average of tickets. = - $2.50
SD of tickets = $1.80.
The box model for net gain has 2 tickets labeled $3, 3 tickets labeled $2, 5 tickets labeled
a) Expected value for the net gain.
The Expected value for net = ∑ x.p(x)
Here
can take value $1, $2 and $3
Here p(x) us the probability of winning respectively.
So, Now, Expected gain is,
(2 x 3 x 2/10) + (3 x -2 x 7/10) + (5 x -1 x 5/10)
= 12/10 - 18/10 - 25/10
= -31/10 = -$3.1.
b) Standard error of the net gain,
S.D = [tex]\sqrt{E(x^2) - [E(x)]^2}[/tex]
Now E(x²) = (2 x 3² x 2/10) + (3 x -2² x 7/10) + (5 x -1² x 5/10)
= 36/10 + 84/10 + 25/10 = 145/10
= $ 14.5
SD = [tex]\sqrt{14.5 - 3.1}\\[/tex]
SD = $ 2.21
c) Chance that the net gain is $15
P(X=15) = (z = 15-(-2.50)/1.80
= P(z=9.72) = 0.99.
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Help me please first correct answer get branliest and please no essay
Answer:
6cm
Step-by-step explanation:
all the sides of a square are identical so we can assume the missing side as x
since all four sides are the same and the perimeter is the sum of all sides, we can write
x+x+x+x=24cm
4x=24cm
x=24/4
x=6cm
Flo ate
3
2
of a sandwich and Arnie ate- of a sandwich. If Arnie ate more, what
3
must be true?
A Flo's sandwich is bigger.
B Arnie's sandwich is bigger.
C) The sandwiches are the same size.
D) It doesn't matter which sandwich is bigger.
Flo ate more of the sandwich than Arnie.
Option A is the correct answer.
We have,
We need to compare the values 3/4 and 2/3 to determine which fraction represents a larger amount of sandwiches eaten.
To make the fractions comparable, we need to find a common denominator.
The least common multiple of 4 and 3 is 12.
So we can rewrite 3/4 and 2/3 with 12 as the denominator:
3/4 = 9/12
2/3 = 8/12
Comparing these fractions, we see that 9/12 (or 3/4) is greater than 8/12
(or 2/3).
Therefore,
Flo ate more of the sandwich than Arnie.
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Find f'(4) for f(x) = ln (2x^3"). Answer as an exact fraction or round to at least 2 decimal places.
To find f'(4) for the function f(x) = ln(2x^3), we first need to find the derivative f'(x) using the chain rule.
The chain rule states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function.
For f(x) = ln(2x^3), the outer function is ln(u) and the inner function is u = 2x^3.
The derivative of the outer function, ln(u), is 1/u.
The derivative of the inner function, 2x^3, is 6x^2 (using the power rule).
Now, apply the chain rule: f'(x) = (1/u) * 6x^2 = (1/(2x^3)) * 6x^2.
Simplify f'(x): f'(x) = 6x^2 / (2x^3) = 3/x.
Now, find f'(4): f'(4) = 3/4.
So, f'(4) for f(x) = ln(2x^3) is 3/4 or 0.75 when rounded to 2 decimal places.
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Describe the end behavior of
f(x)= -x² -1
show steps
As the x-values go to either positive or negative infinity, the function decreases towards negative infinity.
Step 1: Identify the degree and leading coefficient.
In f(x) = -x² - 1, the degree is 2 (the highest power of x), and the leading coefficient is -1.
Step 2: Determine the end behavior based on the degree and leading coefficient.
Since the degree is even (2) and the leading coefficient is negative (-1), we know that both ends of the graph will point in the same direction.
Step 3: Identify the specific end behavior.
Because the leading coefficient is negative, the graph of the function will open downward. As x approaches positive infinity, f(x) will decrease towards negative infinity. Similarly, as x approaches negative infinity, f(x) will also decrease towards negative infinity.
Step 4: Write the end behavior in a concise format.
The end behavior of f(x) = -x² - 1 can be written as:
As x → ±∞, f(x) → -∞.
In summary, the function f(x) = -x² - 1 has a downward-opening parabola due to its even degree and negative leading coefficient.
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Find an angle \thetaθ coterminal to -497^{\circ}−497 ∘
, where 0^{\circ}\le\theta<360^{\circ}0 ∘
≤θ<360 ∘
The correct answer for an angle coterminal to -497° within the interval 0°≤θ≤360° is 223°.
What are Coterminal angles?
Coterminal angles are angles that share the same initial and terminal sides when drawn in the standard position (starting from the positive x-axis) on the coordinate plane. In other words, coterminal angles are angles that differ by an integer multiple of 360° or 2π radians.
To find an angle coterminal to within the interval use the fact that to add or subtract a multiple of to an angle does not change its position on the unit circle.
To make the angle positive, add 360° repeatedly until an angle within the desired interval is obtained:
= -497° +360°
= -137°
adjust this angle to be within the interval 0°≤θ≤360°, and add another 360°:
= -137° + 360°
= 223°
The required angle is 223°.
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An angle θ coterminal to -497 degrees, where 0 ≤ θ < 360 degrees, is 223 degrees.
Given that; the angle is, -497 degrees.
Now, for an angle coterminal to -497 degrees within the range 0≤θ<360 degrees, add or subtract multiples of 360 degrees until we get an angle within the desired range.
Now, add multiples of 360 degrees until we get a positive angle:
-497 + 360 = -137
Now we have an angle of - 137 degrees, but it is still not within the desired range of 0 ≤ θ < 360 degrees.
To adjust the angle, add 360 degrees to it:
-137 + 360 = 223
Now an angle of 223 degrees, which is within the desired range.
Therefore, an angle θ coterminal to -497 degrees, where 0 ≤ θ < 360 degrees, is 223 degrees.
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Find an angle in each quadrant with a common reference angle with 306°, from 0°≤θ<360°
The angle in each quadrant with a common reference angle with 306° are
Quadrant 1 is 126°Quadrant 2 is 54°Quadrant 3 is 306°Quadrant 4 is 234°To find angles in each quadrant with a common reference angle with 306°, we first need to determine the reference angle for 306°.
Reference angle is the acute angle between the terminal side of an angle and the x-axis. We can find the reference angle for any angle θ by subtracting the nearest multiple of 180° from θ and taking the absolute value of the result. In this case:
|306° - 180°| = 126°
So, the reference angle for 306° is 126°.
Now, we can find an angle in each quadrant with a common reference angle of 126°:
1st quadrant: The angle with a reference angle of 126° in the 1st quadrant is simply 126°.
2nd quadrant: To find the angle with a reference angle of 126° in the 2nd quadrant, we need to subtract the reference angle from 180° (since all angles in the 2nd quadrant are between 90° and 180°).
180° - 126° = 54°
So, an angle with a reference angle of 126° in the 2nd quadrant is 54°.
3rd quadrant: To find the angle with a reference angle of 126° in the 3rd quadrant, we need to subtract the reference angle from 180° and then add 180° (since all angles in the 3rd quadrant are between 180° and 270°).
180° + 126° = 306°
So, an angle with a reference angle of 126° in the 3rd quadrant is 306°.
4th quadrant: To find the angle with a reference angle of 126° in the 4th quadrant, we need to subtract the reference angle from 360° (since all angles in the 4th quadrant are between 270° and 360°).
360° - 126° = 234°
So, an angle with a reference angle of 126° in the 4th quadrant is 234°.
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Which statement is true considering a significance level of 5%?
A. The result is statistically significant, which implies that wearing a watch does not help people manage their time better.
B. The result is not statistically significant, which implies that this result could be due to random chance.
C. The result is statistically significant, which implies that wearing a watch helps people manage their time better.
D. The result is not statistically significant, which implies that wearing a watch does not help people manage their time better.
Given the scenerio in the picture about corn, the statement that is true looking at a significance level of 5% is The result is not statistically significant which implies that spraying the corn plants with the new type of fertilizer does increase the growth rate.
What is the does the 5% significance level mean in the context provided?Looking at the statement "The result is not statistically significant,"this means that the p-value (probability value) of the test was greater than 0.05. It could have 0.15 oe 0.2.
When a test is greater than 0.05 or 5 % significance level, it shows that the what is happening to the corn (increase in growth rate) could have been as a result of chance alone.
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The base and all three faces of a triangle pyramid are equilateral triangles with side lengths of 3ft. the height of each triangle is 2.6ft. what are the lateral area and the total surface area of the triangular pyramid?
The lateral area of the triangular pyramid is 11.7 sq ft and the total surface area is 15.6 sq ft.
To find the lateral area and total surface area of the triangular pyramid with base and faces as equilateral triangles, we can follow these steps:
1: Find the area of one equilateral triangle.
To find the area of an equilateral triangle with side length 3 ft and height 2.6 ft, we can use the formula:
Area = (1/2) × base × height
Area = (1/2) × 3 × 2.6 = 3.9 sq ft
2: Calculate the lateral area.
Since the pyramid has three equilateral triangles as faces, we can multiply the area of one triangle by 3 to find the lateral area:
Lateral Area = 3 × 3.9 = 11.7 sq ft
3: Calculate the total surface area.
The total surface area includes both the lateral area and the base area. Since the base is also an equilateral triangle with the same dimensions, we can simply add the area of the base to the lateral area to find the total surface area:
Total Surface Area = Lateral Area + Base Area = 11.7 + 3.9 = 15.6 sq ft
In conclusion, the lateral area is 11.7 sq ft and the total surface area is 15.6 sq ft.
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pls help <3 Triangle QRS has side lengths q = 11, r = 17, and s = 23. What is the measure of angle R
a.44.5°
b.59.3°
c.27.0°
d.108.6
Using the cosine law, the measure of angle R is calculated as approximately: a. 44.5°.
How to Use the Cosine Law to Solve a Triangle?The cosine law is expressed as follows:
cos R = [s² + q² – r²]/2sq
Given the following side lengths of triangle QRS:
Side q = 11,
Side r = 17,
Side s = 23.
Plug in the values into the cosine law formula:
cos R = [23² + 11² – 17²]/2 * 23 * 11
cos R = 361/506
Cos R = 0.7134
R = cos^(-1)(0.7134)
R ≈ 44.5°
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Find the volume of the cone to the nearest whole number. Use 3. 14
for it.
Cone
Radius Height
Volume
varrh
Worms
3in.
6in.
Tree
Gum
The volume of the cone is 57 cubic inches. To find the volume of the cone, we use the formula: V = (1/3)π[tex]r^{2}[/tex]h, where r is the radius of the cone, h is the height of the cone, and π is approximately 3.14.
Given that the radius of the cone is 3 inches and the height is 6 inches, we can substitute these values into the formula and solve for V: V = (1/3)π([tex]3^{2}[/tex])(6), V = (1/3)π(9)(6), V = (1/3)(3.14)(54), V = 56.52 cubic inches
Rounding to the nearest whole number, the volume of the cone is 57 cubic inches.
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Solve for x WILL MAKE BRAINLIEST QUESTION IN PHOTI ALSO
The measure of x in the intersected chord is 16.
How to find the angle in an intersected chord?If two chords intersect in a circle, then the measure of the angle formed is one half the sum of the measure of the arcs intercepted by the angle and its vertical angle.
Using the chord intersection angle theorem,
5x - 7 = 1 / 2 (119 + 27)
5x - 7 = 1 / 2 (146)
5x - 7 = 73
add 7 to both sides of the equation
5x - 7 = 73
5x - 7 + 7 = 73 + 7
5x = 80
divide both sides of the equation by 5
x = 80 / 5
x = 16
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There were three ant hills in Mrs. Brown's yard. The first ant hill had 4,867,190 ants. The second ant hill had 6,256,304 ants, and the third ant hill had 3,993,102 ants. Choose the best estimate of the number of ants in Mrs. Brown's yard
The best estimate of the number of ants in Mrs. Brown's yard is 15,116,596.
What is arithmetic sequence?
An arithmetic sequence is a sequence of numbers in which each term after the first is found by adding a fixed constant number, called the common difference, to the preceding term.
Mrs. Brown's yard has three ant hills, each with a different number of ants. To estimate the total number of ants in the yard, we simply add up the number of ants in each hill.
The first hill has 4,867,190 ants, the second has 6,256,304, and the third has 3,993,102. When we add these numbers together, we get a total of 15,116,596 ants in Mrs. Brown's yard. Of course, this is just an estimate, as there may be other ant hills or individual ants scattered around the yard.
However, this calculation gives us a good approximation of the number of ants in the yard based on the information given.
To estimate the total number of ants in Mrs. Brown's yard, we can add up the number of ants in each of the three ant hills:4,867,190 + 6,256,304 + 3,993,102 = 15,116,596.
Therefore, the best estimate of the number of ants in Mrs. Brown's yard is 15,116,596.
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Prove that the value of the expression: (36^5−6^9)(38^9−38^8) is divisible by 30 and 37.
_x30x37
Don't answer if you don't know
To prove that the expression (36^5−6^9)(38^9−38^8) is divisible by 30, we need to show that it is divisible by both 2 and 3.
First, we can factor out a 6^9 from the first term:
(36^5−6^9)(38^9−38^8) = 6^9(6^10-36^5)(38^9-38^8)
Notice that 6^10 can be written as (2*3)^10, which is clearly divisible by both 2 and 3. Also, 36 is divisible by 3, so 36^5 is divisible by 3^5. Thus, we can write:
6^9(6^10-36^5) = 6^9(2^10*3^10 - 3^5*2^10) = 6^9*2^10*(3^10 - 3^5)
Since 2^10 is divisible by 2, and 3^10 - 3^5 is clearly divisible by 3, the whole expression is divisible by both 2 and 3, and therefore divisible by 30.
To prove that the expression is divisible by 37, we can use Fermat's Little Theorem. Fermat's Little Theorem states that if p is a prime number and a is any positive integer not divisible by p, then a^(p-1) is congruent to 1 modulo p, which can be written as a^(p-1) ≡ 1 (mod p).
In this case, p = 37, and 36 is not divisible by 37. Therefore, by Fermat's Little Theorem:
36^(37-1) ≡ 1 (mod 37)
Simplifying the exponent gives:
36^36 ≡ 1 (mod 37)
Similarly, 38 is not divisible by 37, so:
38^(37-1) ≡ 1 (mod 37)
Simplifying the exponent gives:
38^36 ≡ 1 (mod 37)
Now we can use these congruences to simplify our expression:
(36^5−6^9)(38^9−38^8) ≡ (-6^9)(-1) ≡ 6^9 (mod 37)
We know that 6^9 is divisible by 3, so we can write:
6^9 = 2^9*3^9
Since 2 and 37 are relatively prime, we can use Euler's Totient Theorem to simplify 2^9 (mod 37):
2^φ(37) ≡ 2^36 ≡ 1 (mod 37)
Therefore:
2^9 ≡ 2^9*1 ≡ 2^9*2^36 ≡ 2^(9+36) ≡ 2^45 (mod 37)
Now we can simplify our expression further:
6^9 ≡ 2^45*3^9 ≡ (2^5)^9*3^9 ≡ 32^9*3^9 (mod 37)
Notice that 32 is congruent to -5 modulo 37, since 32+5 = 37. Therefore:
32^9 ≡ (-5)^9 ≡ -5^9 ≡ -1953125 ≡ 2 (mod 37)
So:
6^9 ≡ 2*3^9 ≡ 2*19683 ≡ 39366 ≡ 0 (mod 37)
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Help right now Asapppppp
The angles that belongs to the right angles category are:
∠KER∠AREWhat makes a right angle in a circle?KER must be a right angle because it is an angle formed between a tangent (KE) and a radius (AK) at the point of tangency (K). By the Tangent-Secant Theorem, it follows that the measure of the intercepted arc KR is equal to the measure of the angle ∠KER plus 90 degrees. Since KR is a diameter (and therefore a semicircle), its measure is 180 degrees. Therefore, ∠KER + 90 = 180, which implies that ∠KER = 90 degrees.
∠ARE must be a right angle because it is an inscribed angle that intercepts the diameter KR. By the Inscribed Angle Theorem, the measure of an inscribed angle is half the measure of its intercepted arc. Since KR is a diameter, the intercepted arc is the entire circle, which has a measure of 360 degrees. Therefore, ∠ARE = 360/2 = 180 degrees. Moreover, a diameter and a chord that contains the diameter must form a right angle at the point where they meet (in this case, point A). Hence, ∠ARE is a right angle.
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Image transcribed:
The figure below shows a circle with center A, diameter KR, and secants RE and RI. Which of the angles must be right angles? Select all that apply.
Q
E
R
K
D
∠KIR
∠ARD
∠KER
∠ARE
∠ERI
6 Which graph best represents a quadratic function with a range of all
real numbers greater than or equal to 3?
F
G
H
H
P
J
The fourth graph best represents a quadratic function with a range of all real numbers greater than or equal to 3
The graph that best represents a quadratic function with a range of all real numbers greater than or equal to 3 is a graph that opens upward and has a vertex at the point (h, k), where k is the minimum value of the function.
Since the range is all real numbers greater than or equal to 3, the minimum value occurs at or above 3.
Therefore, the vertex of the quadratic function lies on or above the horizontal line y = 3.
Hence, the fourth graph best represents a quadratic function with a range of all real numbers greater than or equal to 3
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In ΔVWX, w = 4.7 inches, v = 2.4 inches and ∠V=8°. Find all possible values of ∠W, to the nearest 10th of a degree.
The value of W to the nearest tenth of degree is 15.8°
What is sine rule?The sine rule states that if a, b and c are the lengths of the sides of a triangle, and A, B and C are the angles in the triangle; with A opposite a, etc., then a/sinA=b/sinB=c/sinC.
Sine rule can be used to find unknown side or angle In a triangle.
w/sinW = v/sinV
4.7/sinW = 2.4 / sin8
2.4sinW = 4.7 sin8
2.4sinW = 0.654
sinW = 0.654/2.4
sinW = 0.273
W = sin^-1( 0.273)
W = 15.8° ( nearest tenth)
therefore the value of W is 15.8°
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Every line segment used to make this hospital logo is 3 meters long. What is the total area of the logo in square meters?
What is the area of the shaded part of the circle?
And also, I am so confused about how to do it so can someone help me pls?
The required area of the shaded part of the circle is 50.24 sq. cm
What is area of a circle?A circle of radius r has an area of r2 in geometry. Here, the Greek letter denotes the constant ratio of a circle's diameter to circumference, which is roughly equivalent to 3.14159.
According to question:Given data:
Radius of small circle = 6/2 = 3 cm
Radius of big circle = 10/2 = 5 cm
then.
Area of shaded part = area of big circle - area of small circle
Area of shaded part = π(5)² - π(3)²
Area of shaded part = 25π - 9π
Area of shaded part = 16π
Area of shaded part = 50.24 sq. cm
Thus, required area of the shaded part of the circle is 50.24 sq. cm
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ruby can assemble 2 22 gift baskets by herself in 7 77 minutes. emma can assemble 4 44 gift baskets by herself in 15 1515 minutes. ruby begins assembling gift baskets at 1 : 00 p.m. 1:00p.m.1, colon, 00, start text, p, point, m, point, end text, and emma begins assembling gift baskets at 1 : 15 p.m. 1:15p.m.1, colon, 15, start text, p, point, m, point, end text if they continue to work at the above rates, at what time will they finish the 5 4 th 54 th 54, start superscript, start text, t, h, end text, end superscript basket?
Ruby and Emma can assemble one gift basket in 0.1818 minutes, together. They will finish the 54th basket at 7:27 PM.
To solve the problem, we first need to find how many gift baskets Ruby and Emma can assemble in one minute.
Ruby can assemble 2/22 = 1/11 gift basket in one minute.
Emma can assemble 4/44 = 1/11 gift basket in one minute.
Together, they can assemble 1/11 + 1/11 = 2/11 = 0.1818 (rounded to four decimal places) gift baskets in one minute.
To assemble the 54th gift basket, they need to assemble 53 gift baskets before that.
53 gift baskets / 0.1818 gift baskets per minute = 291.8181 minutes
Since they start at 1:00 p.m. and Emma starts 15 minutes later, they will finish 291.8181 minutes after 1:15 p.m., which is approximately 7:27 p.m.
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Use matrices A, B, C and D. A = Find CD a. 2 3 0 -5 b. 27 -29 -7 31.0 -384-1 2 6 -6 -6 4 -2 -27 18 -9 -12 8 -4 2 Mark this and return C = 9 and D= [-3 2 -1] C. Please select the best answer from the choices provided | ** - 16 24 -8 0 -40 32 Save and Evil
The product of matrices C and D is:
[tex]CD = \left[\begin{array}{ccc}-6&18&-4\\\end{array}\right][/tex]
The best answer is option b.
How to find the product of two matrices?A matrix (plural matrices) is a set of numbers arranged in rows and columns so as to form a rectangular array.
The number of rows of a matrix can be determined by counting from top to bottom and the number of columns can be determined by counting from left to right.
The product (multiplication) of matrices C and D is:
CD = C * D
[tex]CD = \left[\begin{array}{ccc}2\\9\\4\end{array}\right] * \left[\begin{array}{ccc}-3&2&-1\\\end{array}\right][/tex]
To get the product, multiply each row by the column. That is:
2 * (-3) = -6
9 * 2 = 18
4 * (-1) = -4
[tex]CD = \left[\begin{array}{ccc}-6&18&-4\\\end{array}\right][/tex]
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What is the mean absolute deviation of 10 10 9 8 10 5 6 4 8 4
The mean absolute deviation of the given data set is approximately 2.16.
To find the mean absolute deviation (MAD), we first need to calculate the mean of the data set:
Mean = (10 + 10 + 9 + 8 + 10 + 5 + 6 + 4 + 8 + 4) / 10 = 7.4
Next, we calculate the absolute deviation of each data point from the mean:
|10 - 7.4| = 2.6
|10 - 7.4| = 2.6
|9 - 7.4| = 1.6
|8 - 7.4| = 0.6
|10 - 7.4| = 2.6
|5 - 7.4| = 2.4
|6 - 7.4| = 1.4
|4 - 7.4| = 3.4
|8 - 7.4| = 0.6
|4 - 7.4| = 3.4
Then, we find the average of these absolute deviations:
MAD = (2.6 + 2.6 + 1.6 + 0.6 + 2.6 + 2.4 + 1.4 + 3.4 + 0.6 + 3.4) / 10 ≈ 2.16
Therefore, the mean absolute deviation of the given data set is approximately 2.16.
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Andrew went deep sea diving with some friends. If he descends at a rate of 4 feet per minute, what integer represents Andrews depth in ¼ of an hour?
The integer that represents Andrews depth in ¼ of an hour is 60 feet.
How to determine what integer represents Andrews depth in 1/4 of an hour?Word problems are sentences describing a 'real-life' situation where a problem needs to be solved by way of a mathematical calculation e.g. calculation of length and depth.
If Andrew descends at a rate of 4 feet per minute and we want to find his depth in ¼ of an hour.
1/4 of an hour = (1/4 * 60) minutes = 15 minutes
Thus, the integer that represents Andrews depth in ¼ of an hour will be:
(4 feet per minute) * (15 minutes) = 60 feet
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