please help me I’ll make u brainliest please
A 1 liter jar contains 0.5 moles of gas at a pressure of 2 atm. What is the temperature of the gas?
What is the volume of a
container of 4 moles of gas at 200 K with a pressure of 3 atm?
Your scientist friend is trying to figure out how many molecules of gas are in a container. They know that the container has a volume of 5 liters, and they measured the pressure and temperature to be 3.5 atm and 275 K. From this information, what do you tell them the mole measurement should be?
Answer:
See below ( Ideal gas law)
Explanation:
A) PV = n RT P = 2 * 760 = 1520 mm
1520 ( 1) = .5 (8.314)(T) T is in Kelvin
T = 365.64 K
B) PV = nRT
3 ( 760) V = 4 ( 8.314)(200)
V = 2.92 Liters
C) PV = nRT
3.5 (760) (5) = n (8.314)(275) n = 5.8 moles
A force of 36N acts at an angle of 55 degrees to the vertical. The force moves its point of application by 64 cm in the direction of the force calculate work done by:
(A)the horizontal component of force
(B)the vertical component of the force
The work done by the horizontal component of force is 18.89 Joules while the vertical component of the force is 13.22 Joules.
WORKThe work done on an object, is the product of the force F and the distance S in the direction of the force. That is,
W = F x S
The S.I unit of work is Joule
Given that a force of 36N acts at an angle of 55 degrees to the vertical. The force moves its point of application by 64 cm in the direction of the force
To calculate work done by:
(A) the horizontal component of force;
Force F = 36Sin55 = 29.489N
W = 29.489 x 64/100
W = 18.87 J
(B) the vertical component of the force;
Force F = 36Cos55 = 20.649
W = 20.649 x 64/100
W = 20.649 x 0.64
W = 13.22 J
Therefore, the work done by the horizontal component of force is 18.89 Joules while the vertical component of the force is 13.22 Joules.
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A spring with a spring constant of 5.25N/m applies a force of 8.50N when it is stretched. How much was the spring compressed?
Answer:
1.62
Explanation:
F = kx
8.5 = 5.25 * x
8.5/5.25 = 1.62
Carbon -14 is used to date a palm fossil that originally contained 0.24 grams of carbon -14. The half life is 5700 years. If the fossil is found to be 17,100 years old, how much carbon -14 does it contain now?
Please make sure to show all of your work/process so I can learn how to do it on my own!! thank you
Answer:
Exactly 0.03042 carbon-14 is remaining.
Roughly 0.03 Carbon-14 is remaining. (When/If Multiple Choice)
Explanation:
Not a physics question, this is chemistry, but I'll answer.
First, divide 17,000/5700 to find the t, or time.
t = 2.98245614 or 2.98.
If it originally contained .24 grams, and a half life means x/2,
you would use the formula x/2^p, with p being the number of half lives
(these variables are made up, you can use any you would like)
In 17,000 years, the palm fossil experienced 2.98 half lives.
Thus meaning, using our equation, we would find (.24)/2^2.98
This equals 0.030418784 carbon-14 remaining to be exact.
(For Multiple Choice, it may be required to round to For Multiple Choice, it may be required to round to 3, so .24/2/2/2 or .24/2=.12 then .06 then it equals : .03 Carbon-14)
Carbon -14 is used to date a palm fossil that originally contained 0.24 grams of carbon -14. The half life is 5700 years. If the fossil is found to be 17,100 years old then 0.0303 g of carbon -14 does it contain now.
What is radioactive decay ?The process by which an unstable atomic nucleus loses energy through radiation is known as radioactive decay (also known as nuclear decay, radioactivity, radioactive disintegration, or nuclear disintegration). A radioactive substance is one that contains unstable nuclei. Alpha decay, beta decay (-decay), and gamma decay (-decay) are three of the most prevalent forms of decay, all of which entail the emission of one or more particles. The mechanism responsible for beta decay is the weak force, while the other two are regulated by electromagnetism and nuclear force. Electron capture is a fourth form of common decay in which an unstable nucleus grabs an inner electron from one of the electron shells.
According to decay formula,
N(t) = N₀ e^(-λt)
Given,
N₀ = 0.24g
t = 17100 years
λ = 0.693/T
Where T is half life.
λ = 0.693/5700 = 1.21 × 10⁻⁴
Putting all the values in the equation,
N(t) = 0.24g e^(-1.21 × 10⁻⁴ ×17,100)
N(t) = 0.0303 g
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Daily Task $18.3: Homework/Classwork 1. 1.1 The speed of sound in air is about 330 m-s'. A lightning bolt strikes a tree that is 1,5 km away from you. Calculate the time from the moment that you see the lightning flash until you hear the thunder that accompanies it.
Answer:
sup cuh, the answer is, 15 5/8 mm3
Explanation: i did the math.
Three liquids are at temperatures of 2°C, 21°C, and 34°C, respectively. Equal masses of the first two liquids are mixed, and the equilibrium temperature is 5 C. Equal masses of the second and third are then mixed, and the equilibrium temperature is 30.1°C.
Find the equilibrium temperature when equal masses of the first and
third are mixed.
Answer In units of 'C.
Answer:
m - mass of each liquids (all masses are equal )
C_1C 1 - specific heat of the first third C_2C 2 - specific heat of the second liquid
C_3C 3- specific heat of the third liquid
Temperature of liquids: T_1=7 ◦C,T_2=20◦C, T_3=34◦CT
1 =7◦C,T 2 =20◦C,T 3=34◦C
Temperature of 1+2 liquids mix: T_{12}=11^oCT
12 =11 oC
Temperature of 2+3 liquids mix: T_{23}=22.6^oCT
23=22.6 oC
Temperature of 1+3 liquids mix: T_{13} - ?T 13 −?
When the first two are mixed:
m C₁ (T₁ − T_{12}) + m C₂ (T₂ − T_{12}) = 0 \\ C₁ (7− 11) + C₂ (20 − 11) = 0\\ 4C_1=9C_2\\ C_1=2.25C_2mC₁(T₁−T 12)+mC₂(T₂−T 12 )=0C₁(7−11)+C₂(20−11)=04C \1=9C 2C 1 =2.25C 2
When the second and therd are mixed:
m C_2 (T_2 − T_{23}) + m C_3 (T_3 − T_{23}) = 0 \\ C_2 (20−22.6) + C₂ (34 −22.6) = 0\\ 2.6C_2=11.4C_3\\ C_2=4.38C_3mC 2 (T 2 −T 23 )+mC 3 (T 3 −T 23 )=0C 2(20−22.6)+C₂(34−22.6)=02.6C 2 =11.4C 3C2 =4.38C 3
When the first and therd are mixed:
m C_1 (T_1 − T_{13}) + m C_3 (T_3 − T_{13}) = 0 \\ C_1 (7−T_{13}) + C_3 (34 −T_{13}) = 0\\ C_1=2.25C_2=2.25(4.38C_3)=9.86C_3\\ 9.86C_3 (7−T_{13})=-C_3(34 −T_{13})\\ 9.86 (7−T_{13})=-(34 −T_{13})\\ T_{13}=9.5^oCmC 1(T1 −T13)+mC 3(T3−T13 )=0C1 (7−T13 )+C 3(34−T 13 )=0C1 =2.25C2=2.25(4.38C3 )=9.86C39.86C3 (7−T13 )=−C3(34−T13 )9.86(7−T13)=−(34−T13 )T13 =9.5 oCT_{13}=9.5^oCT 13 =9.5 o C:
The greatest variation in size, mass, and luminosity occurs in:.
The greatest variation in size, mass, and luminosity occurs in elliptical galaxies.
What is Variation?
This is defined as the difference from the norm which is exhibited by objects.
In the solar system, variation in features such as size, mass, and luminosity occurs mostly in elliptical galaxies due to presence of array of stars thereby making it the most appropriate choice.
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A ball of play-doh with a mass of 1 kg is thrown at 5 m/s against a wall. The wall causes the play-doh to smash and come to a stop in 0.13 s. What force does the wall apply to the play-doh to make it stop?"
Provide the magnitude of the force applied by the wall (number only).
The magnitude of the force applied by the wall on the ball while smashed is 38.462 newtons.
How to determine the required impact force to stop a ball of Play-Doh(TM)
After a quick reading of the statement we conclude that the impact theorem shall be useful to determine the dynamic force required to stop the ball when smashed. The impulse theorem results from the combination of the Newton's laws of motion, principle of energy conservation and work-energy theorem:
[tex]m \cdot v_{o} = F\cdot \Delta t[/tex] (1)
Where:
m - Mass of the ball, in kilograms.[tex]v_{o}[/tex] - Initial speed of the ball, in meters per second.Δt - Impact time, in seconds. F - Impact force, in newtons.If we know that m = 1 kg, [tex]v_{o} = 5\,\frac{m}{s}[/tex] and Δt = 0.13 s, then the impact force is:
F = (1 kg) · (5 m/s)/(0.13 s)
F = 38.462 N
The magnitude of the force applied by the wall on the ball while smashed is 38.462 newtons. [tex]\blacksquare[/tex]
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The wavelength of a sound wave in this room is 4. 13 m and the frequency is 75 Hz. What is the speed of the wave in the room?
if you double the frequency of the sound wave but keep the wavelength the same, determine the new speed of the wave.
Let's see
#1
[tex]\\ \rm\Rrightarrow v=f\lambda[/tex]
f is frequencylambda is wavelength[tex]\\ \rm\Rrightarrow v=75(4.13)[/tex]
[tex]\\ \rm\Rrightarrow v=309.75ms^{-1}[/tex]
#2
New frequency:-
2(75)=150[tex]\\ \rm\Rrightarrow v=150(4.13)[/tex]
[tex]\\ \rm\Rrightarrow v=619.5ms^{-1}[/tex]
Which statement describes a chemical property related to the particles that make up a material
Answer:
Salt crystals are hard and brittle because they are made up of atoms that combine by ionic bonding.
Explanation:
help me PLEASE, it's physical science D:
Answer:
90
Explanation:
The bottom number on the element is the number of protons and the top number is the total of the protons + neutrons
______is the change from a liquid to a gas at a temperature below boiling point
The uncertainty principle applies not only to momentum and position, but also to energy and time.
a. True
b. False
Answer:
(a) that is a true statement
If a spring has a spring constant of 0. 5 N/m and it is stretched 0. 5 m, what is the force
of the spring?
Answer:
0.25N
Explanation:
k=0.5N/m
e=0.5m
f=?
were k=spring constant
e=extension
F=force
According to hooks law,
f=ke
f=0.5x0.5 =0.25 N
which of the following is an example of wernickes aphasia?
An example of wernickes aphasia is someone making a speech which does not make sense.
It majorly caused by loss of flow of blood to the brain. Other causes include
Head injuryBrain inflammationBrain infectionStroke. e.t.cWhat is wernickes aphasia?Wernickes aphasia can simply be defined as a language disorder that makes it very difficult for an individual to understand words and communicate with other people.
So therefore; an exam of wernickes aphasia is someone making a speech which does not make sense.
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How long will it take a car to accelerate from 20m/s to 26m/s at a rate of 1.4m/s2?
• 2.2 s
• 4.6 s
• 2.7 s
• 4.3 s
Answer:
4.3s
Explanation:
a=v-u/t
t=v-u/a
t=26-20/1.4=4.28
=4.3
If a fossil contains 60% of its original carbon, how old is the fossil
Particle A and particle B, each of mass M, move along the x-axis exerting a force on each other. The potential energy of the system of two particles assosicated with the force is given by the equation U=G/r 2, where r is the distance between the two particles and G is a positive constant
Speed of particle B is 2v₀/3 m/s to the left. Particle A and particle B will always have equal speed since they experience equal forces.
Conservation of energyThe speed and direction of the particle B is determined by applying the principle of conservation of energy as follows;
K.E₁ + P.E₁ = K.E₂ + P.E₂
[tex]\frac{1}{2} Mv^2_A + \frac{G}{r^2} = \frac{1}{2} Mv^2_B + \frac{G}{r^2} \\\\ \frac{1}{2} Mv^2_A = \frac{1}{2} Mv^2_B\\\\v^2_A = v^2_B\\\\v_A = v_B[/tex]
[tex]v_B = \frac{2v_0}{3} \ m/s \ to \ the \ left[/tex]
At any given position, the speed of particle A and particle B will be equal, since they experience equal force and they have equal masses.
The complete question is below:
Particle A and particle B, each of mass M, move along the x-axis exerting a force on each other. The potential energy of the system of two particles assosicated with the force is given by the equation U=G/r 2, where r is the distance between the two particles and G is a positive constant. At time t=T1 particle A is observed to be traveling with speed 2vo/3 to the left. The speed and direction of motion of particle B is ?
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Answer:
Explanation:
the linear momentum is conserved MiVi=MaVa+MbVb
MV0=2V0M/3+MVb
Vb=V0/3
A 42.0-cm-diameter wheel, consisting of a rim and six spokes, is constructed from a thin, rigid plastic material having a linear mass density of 25.0 g/cm. this wheel is released from rest at the top of a hill 69.0 m high.
For a 42.0-cm-diameter wheel, consisting of a rim and six spokes,the angular speed is mathematically given as
w=118.6 rad/s
What is the angular speed?
Generally, the equation for the Conservation of energy is mathematically given as
K1+U1=K2+U2
Therefore
Mgh+0=0+(1/2)MV2+(1/2)Iω2
Where
M=m+6m
M=2rλ(π+3)
Therefore
[tex]2r \lambda (\pi+3)gh=0.52r \lambda (\pi+3)(rw)2+(1/2)[(2 \pi \lambda r)r2+6( \lambda r)r2/3]w2[/tex]
[tex]w=\sqrt{[(\pi+3)*9.8*53/(0.42/2)2*(\pi+2)[/tex]
w=118.6 rad/s
In conclusion, The angular speed is
w=118.6 rad/s
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Because sound waves vibrate longitudinally, what can result?
A Disruptions of fixed waves
B. Changes in the density of air
C. Pressure differences where compressions are rarefied
D Regions of high pressure and low pressure
HELp!!!!!!!!
Answer:
I think its D.
Explanation:
I think this because sound waves move up and down im pretty sure but i might have that mixed with radio waves
A force of 4,500 N acts on a car. The
acceleration of the car is 3 m/s/s. What
is the mass of the car? Show your work
below.
Answer:
1500 kg is mass of car
Explanation:
F = ma
F/a = m
4500n / 3 m/s^2 = 1500 kg
Who ran faster? The turtle or the rabbit?
(A) The rabbit
(B) The turtle
Answer:
the turtle was finished faster but the rabbit was faster
Explanation:
What is the origin of all stars? supernova dwarfs protostars nebulae
Answer:
Nebulae
Explanation:
Hope this helps!
Answer:
D nebulae
Explanation:
Please Help! 20 BRAIN POINTS
An astronaut (m = 95 kg) and her tool box (m = 21 kg) is drifting through deep space at a speed of 0.4 m/s [FWD]. In order to change the direction of travel, the astronaut throws her tool box forward. What is the minimum speed of the thrown tool box necessary, so that the astronaut changes direction?
Answer:
The Speed of the throw that is required to create enough impulse, to change the direction of the momentum is: -1.81m/s
Explanation:
m1=95kg
m2=21kg
V1=.4m/s
V2=?
V'=<0 or -.01 at lowest.
for the Impulse formula, I found: m1 x V1 + m2 x V2 = <0
so,
(95) x (.4) + (21) x (V2)=<0
38kgm/s+(21kg x V2)=<0 or -0.01m/s
I found that V2 was equivalent to -1.81, and when you plugin the value, you get the equation
(95) x (.4) + (21) x (-1.81) = -0.01m/s
I WILL MARK BRAINLIEST
EXPERIMENT: MIXTURES
OBJECTIVES
Utilize a filter to separate a mixture of sand and water.
Summarize your findings.
Many tasks in chemistry involve separating mixtures. For example, crude oil by itself has very few uses, but many important substances are separated from crude oil. In this investigation we will attempt to separate sand from salt water, and salt from water. If you do not have access to sand, you can use small pebbles or BBs.
Before you begin the experiment, hypothesize whether or not you can separate sand from salt water using filter paper. After the experiment summarize your findings in a scientific report. Upload your report below in question 1.
These supplies are needed:
salt
water
sand
a measuring cup
a balance
filter paper
funnel
plastic spoon
two beakers or glasses
Measure 5 grams of salt and 10 grams of sand using the balance.
Mix together the salt and sand in a beaker or glass.
Add one half-cup of water to the salt-sand mixture.
Stir the mixture with the plastic spoon until all the salt is completely dissolved.
To filter the mixture fold the filter in half to form a semi-circle. Fold it again which creates the shape of a triangle. Place the filter paper in the funnel and open one layer of the filter paper and spread it out onto one side of the funnel, and the other three layers onto the other side of the funnel. You may want to wet the filter paper with water so that the filter paper lays flat against the sides of the funnel. Carefully pour the salt water -sand mixture into the funnel and drain the liquid into a beaker or glass.
Remove the filter paper from the funnel and lay it out flat to allow the sand to dry.
Answer:
I found out that you could separate the sand because the filterstion and all the materials uses their elements to filter it out
Findings say that one could separate the sand using the filtration and all the materials uses their elements to filter it out.
What is filtration?Filtration is the technique of segregating the components from a mixture.
In the given experiment, the filter is used to separate a mixture of sand and water.
This experiment can be successfully completed through the filtration process.
Thus, one could separate the sand using the filtration and all the materials uses their elements to filter it out.
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⚠️PLEASE HELP!!⚠️ Which two statements describe how convection currents transfer thermal energy in earths oceans?
Answer:
The answer is D & B
Answer: B and D
Explanation:
A red, 400Kg bumper car is moving to the right at 2m/s. The red bumper car collides head on with a blue bumper car with a combined driver/car mass of 600kg and a velocity of 1m/s. The collision was elastic. If the blue car bounced backwards at a velocity of 0.25m/s, what was the final velocity of the red car?
Based on the principle of the conservation of linear mometum, the recoil velocity of the bliue car is 3.1 m/s.
Principle of conservation of linear momentumThe principle of conservation of linear momentum states that; the total mometum before collsion is equal to the total momentum after collision.
Now;
m1u1 + m2u2 = m2v2 + m2v2
(400Kg * 2m/s) + (600kg * 1m/s) = (600kg * 0.25m/s) + (400Kg * v)
800 + 600 = 150 + 400v
800 + 600 - 150 = 400v
v = 800 + 600 - 150/400
v = 3.1 m/s
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Which statement about natural selection on early earth is correct?.
Answer:
wheres the statements
Explanation:
where its incomplete
Natural selection could act on a population of proto-cells on early Earth, selecting for those that were stable and had self-replicating, catalytic RNA that allowed them to grow and divide to produce similar daughter proto-cells. The correct option is option (B).
Natural selection could act on a population of proto-cells on early Earth. Proto-cells were early, simpler forms of cells that lacked DNA but had self-replicating, catalytic RNA. Through natural selection, those proto-cells that were more stable and had RNA molecules capable of self-replication and catalytic functions would have had a reproductive advantage.
These traits would allow them to grow, divide, and produce similar daughter proto-cells. Over time, this selection process could have led to the development of more complex and stable cellular structures, eventually leading to the emergence of cells that utilize DNA as their genetic material.
Therefore the correct option is option B.
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The complete question is:
Which statement about natural selection on early Earth is correct?
A. Natural selection could only act on populations of living organisms that had DNA as their genetic material.
B. Natural selection could act on a population of proto-cells on early Earth, selecting for those that were stable and had self-replicating, catalytic RNA that allowed them to grow and divide to produce similar daughter proto-cells.
C. Natural selection acted on populations of proto-cells on early Earth in order to make them more like modern living cells that have DNA as their genetic material.
HELP ME PLEASE!!!!
Do some research on digital vs. analog recording, and decide which you think gives the most accurate and best quality sound. State the advantages and disadvantages of each in a paragraph. Be sure to back up your opinions with facts, and state your sources.
Answer:
The question of analog vs. digital audio is one of the more hotly debated questions in the world of music, film, and media today. Does digital sound better? Does analog sound better? Is there even a noticeable difference?
It’s impossible to understand the difference completely without understanding what distinguishes analog audio from digital audio. A full discussion of these terms is best left to your curriculum and discussions with your mentor in the studio. For now, though, here’s a brief explanation of what these two words mean, and the differences between them.
Explanation:
Like diomedes and patroclus before him, achilles fights against a god during his aristeia in iliad books 20-22. Which god?.
The god that Achilles fought in the Illiad was the god Hector and he ended up killing him.
Who is achilles?He was a warrior that fought in the Trojan war. After the death of Patroclus. Achilles had to fighty the Trojan Army singlehandedly.
It was the war that saw the end of Hector and also he joined the war for the avenging of the death of Petroclus.
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