Answer:
the answer is negative two / x= -2
_________
[tex] \: [/tex]
[tex] \rm3(2x - 5) - (2x - 5 ) = 6(4x + 5)[/tex]
[tex] \rm6x - 15 - 2x - 5 = 24x + 30[/tex]
[tex] \rm4x - 20 = 24x + 30[/tex]
[tex] \rm4x - 24x = 30 + 20[/tex]
[tex] \rm - 20x = 50[/tex]
[tex] \rm \: x = \frac{50}{ - 20} [/tex]
[tex] \rm \: x = \boxed{ - 2 \frac{1}{2} }[/tex]
A company makes pens. They sell each pen for $9. Their revenue is represented by R = 9 x. The cost to make the pens is $3 each with a one time start up cost of $6500. Their cost is represented by C = 3 x + 6500. a) Find the profit, P, (P = R - C) when the company sells 1000 pens. 15500 0-500 O 9000 0-3500 0-9000
Answer:
-$500
Step-by-step explanation:
C = 3(1000) + 6500
C = 3000 + 6500
C = 9500
R = 9(1000)
R = 9000
P = 9000 - 9500
P = -500
Aashi buys
2 packets of bread rolls costing £1.40 for each packet
1 bottle of ketchup costing £1.80
3 packets of sausages
Aashi pays with a £10 note.
She gets 45p change.
Work out the price in pounds (£) of one pack of sausages.
(you will get brainliest) !! :D
Price of one unit Sausage = 1.65
Sum ( Price x Quantity) = Total Expenditure
Price of Bread x Quantity of Bread + Price of Ketchup x Quantity of Ketchup + Price of Sausage x Quantity of Sausage
Total Expenditure Value = 10 - 0.45 = 9.55
Let price of sausage = P
Therefore, 2 (1.40) + 1 (1.80) + 3 P = 9.55
2.80 + 1.80 + 3 Ps = 9.55
4.6 + 3 P = 9.55
3P = 9.55 - 4.60 = 4.95
P = 4.95 / 3 = 1.65
To learn more, refer https://brainly.com/question/16910784?referrer=searchResults
evaluate f(m-5) and simplify if f(x)=5x-9
Answer:
f(m-5) = 5m-34
Step-by-step explanation:
f(x)=5x-9
Replace x with m-5
f(m-5) = 5(m-5) -9
Distribute
= 5m-25 -9
= 5m-34
Answer:
answer is 5m - 34
Step-by-step explanation:
!!!!!!!!!!!!!!!!!!!!!!!!
help with 14 please!!! please also explain!!
Answer:
f = ab/(a + b)Step-by-step explanation:
#14Given:
1/f = 1/a + 1/bSolving for f:
1/f = b/ab + a/ab1/f = (a + b)/ab cross - multiplyf(a + b) = ab divide by (a + b)f = ab/(a + b)Pls help can’t figure it out
Match the following items.
Determine the functions if θ is a first-quadrant angle, and sin = .
1. cosθ √(15)/5
2. tanθ √(10)/2
3. cscθ √(15)/3
4. secθ √6/3
5. cotθ √6/2
The functions are illustrations of trigonometry ratios
[tex]\mathbf{(a)\ cos\theta = \frac{\sqrt{15}}{5}}[/tex]
The sine of an angle is calculated as follows
[tex]\mathbf{sin\theta = \sqrt{1 - cos^2\theta}}[/tex]
So, we have:
[tex]\mathbf{sin\theta = \sqrt{1 - (\sqrt{15}/5)}}[/tex]
[tex]\mathbf{sin\theta = \sqrt{1 - (15/25)}}[/tex]
Take LCM
[tex]\mathbf{sin\theta = \sqrt{\frac{10}{25}}}[/tex]
[tex]\mathbf{sin\theta = \frac{\sqrt{10}}{5}}[/tex]
[tex]\mathbf{(b)\ tan\theta = \frac{\sqrt{10}}{2}}[/tex]
The tangent of an angle is:
[tex]\mathbf{\ tan\theta = \frac{Opposite}{Adjacent}}[/tex]
Using Pythagoras theorem, we have:
[tex]\mathbf{Hypotenuse^2 = Opposite^2 + Adjacent^2}[/tex]
So, we have:
[tex]\mathbf{Hypotenuse^2 = (\sqrt{10})^2 + 2^2}[/tex]
[tex]\mathbf{Hypotenuse^2 = 10 + 4}[/tex]
[tex]\mathbf{Hypotenuse^2 = 14}[/tex]
Take square roots
[tex]\mathbf{Hypotenuse = \sqrt{14}}[/tex]
So, the sine of the angle is:
[tex]\mathbf{\ sin\theta = \frac{Opposite}{Hypotenuse}}[/tex]
[tex]\mathbf{\ sin\theta = \frac{\sqrt{10}}{\sqrt{14}}}[/tex]
Rationalize
[tex]\mathbf{\ sin\theta = \frac{\sqrt{140}}{14}}[/tex]
[tex]\mathbf{(c)\ csc\theta = \frac{\sqrt{15}}{3}}[/tex]
The sine of the angles is:
[tex]\mathbf{sin \theta = \frac{1}{csc\theta}}[/tex]
So, we have:
[tex]\mathbf{sin \theta = \frac{1}{\sqrt{15}/3}}[/tex]
[tex]\mathbf{sin \theta = \frac{3}{\sqrt{15}}}[/tex]
Rationalize
[tex]\mathbf{sin \theta = \frac{3\sqrt{15}}{15}}[/tex]
[tex]\mathbf{sin \theta = \frac{\sqrt{15}}{5}}[/tex]
[tex]\mathbf{(d)\ sec\theta =\frac{\sqrt 6}{3}}}[/tex]
The sine of an angle is calculated as follows
[tex]\mathbf{sin\theta = \sqrt{1 - (1/sec\theta)^2}}[/tex]
So, we have:
[tex]\mathbf{sin\theta = \sqrt{1 - (3/\sqrt 6)^2}}[/tex]
[tex]\mathbf{sin\theta = \sqrt{(1 - 9/6)}}[/tex]
[tex]\mathbf{sin\theta = \sqrt{( - 3/6)}}[/tex]
The sine of the angle does not have a real value
[tex]\mathbf{(e)\ cot\theta = \frac{\sqrt 6}{2}}[/tex]
Start by calculating the tangent of the angle
[tex]\mathbf{tan\theta = \frac{1}{cot\theta}}[/tex]
So, we have:
[tex]\mathbf{tan\theta = \frac{1}{\sqrt 6/2}}[/tex]
[tex]\mathbf{tan\theta = \frac{2}{\sqrt 6}}[/tex]
Rationalize
[tex]\mathbf{tan\theta = \frac{2\sqrt 6}{6}}[/tex]
[tex]\mathbf{tan\theta = \frac{\sqrt 6}{3}}[/tex]
The tangent of an angle is:
[tex]\mathbf{\ tan\theta = \frac{Opposite}{Adjacent}}[/tex]
Using Pythagoras theorem, we have:
[tex]\mathbf{Hypotenuse^2 = Opposite^2 + Adjacent^2}[/tex]
So, we have:
[tex]\mathbf{Hypotenuse^2 = (\sqrt{6})^2 + 3^2}[/tex]
[tex]\mathbf{Hypotenuse^2 = 6 + 9}[/tex]
[tex]\mathbf{Hypotenuse^2 = 15}[/tex]
Take square roots
[tex]\mathbf{Hypotenuse = \sqrt{15}}[/tex]
So, the sine of the angle is:
[tex]\mathbf{\ sin\theta = \frac{Opposite}{Hypotenuse}}[/tex]
[tex]\mathbf{\ sin\theta = \frac{\sqrt{6}}{\sqrt{15}}}[/tex]
Rationalize
[tex]\mathbf{\ sin\theta = \frac{\sqrt{90}}{15}}[/tex]
Rewrite as:
[tex]\mathbf{\ sin\theta = \frac{3\sqrt{10}}{15}}[/tex]
[tex]\mathbf{\ sin\theta = \frac{\sqrt{10}}{5}}[/tex]
Read more about trigonometry ratios at:
https://brainly.com/question/24888715
__% of 4 is 7
Please answer its due today
Answer:
175%
hope that helps. :)
Show how to use a power of 10 to write 42.66 / 2.97 as an equivalent expression with a whole number divisor
PLEASE HELP DUE TONIGHT!!
WILL MARK BRAINLIEST!!
Expressing the given equation as a power of 10 with the divisor expressed as an whole number can be written as [tex] \frac{42.66 \times 10^{2}}{297}[/tex]
Given the expression :
42.66/2.97Expressing the numbers as a power of 10 :
Dividend = 42.66 Divisor = 2.97To convert the divisor to a whole number :
Multiply both by 100
Dividend = 42.66 × 100Divisor = 2.97 × 100 = 297Expressing dividend as a power of 10 :
Dividend = 42.66 × 100 = 42.66 × 10²Hence, the equivalent equation would be : [tex] \frac{42.66 \times 10^{2}}{297}[/tex]
Learn more : https://brainly.com/question/18796573
X-6y=6 find an ordered pair
Answer:
(6,0) or (0,-1)
Step-by-step explanation:
X-6y=6
X=6+6y
X/6=1+y
X/6-1=y
y=X/6-1
We'll use substitution to solve the ordered pair. Let's say Y = 0. We'll insert it back into our equation.
0=X/6-1
1=X/6
6=X
(6,0)
We can also start with X being = 0.
y=0/6 -1
y=-1
(0,-1)
I've attached what that would look like as a graph.
What is the largest multiple of 9 whose negation is greater than -100?
Answer:
99
Step-by-step explanation:
Its negation is greater than -100. Hope this helps!
~Just a joyful teen
[tex]SilentNature[/tex]
Answer:
99
Step-by-step explanation:
Camille is 7 years older than Donny, and Donny is 4 years younger than Tommy.
Write an expression for the total ages of the three people, in simplest form.
11
Step-by-step explanation:
first you add seven plus four and then you get your answer that is eleven
Find the volume of the composite solid.
Answer:
volume________
7 ft 8 ft 7.5 ft 7 ftwhat is the approximate length of segment PR?
25
11
125
18
Answer:
18
correct me if I'm wrong❌
See the question
Help
I’ll give a brainliest
1 , 2 , 3 , or 4 ?
Answer:
the answer is 3 I think if not than 2
How to find the Smallest value?
3/8
3/4
1/2
7/8
5/6
Answer:
Make all fractions have the same common denominator, and you will find that 3/8 is the smallest value.
Step-by-step explanation:
pls help meeeee
pls....
Answer:
1→10
Step-by-step explanation:
12
27
45
105/4
49/2
2/15
2/9
22/45
7/12
1/3
if y varies inversely as x, when y=20 and x=2 find the equation for y. then, find y when x=4
Answer:
the equation for y=20=1/2
Step-by-step explanation:
y=1/4
y=0.25
I’m doing my math homework and I don’t understand it all. I did most of it in class but I don’t get it still so here’s the question
Question:
-4/3(3q -10)
Answer:
-4q+ 40/3
Step-by-step explanation:
(Pre calc) I only need to do part A i would love to have some help I will make it 120 Points
Answer:
The domain should be X
Step-by-step explanation:
I'm a bit unsure but I think it's correct
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
Answer:
should be 40
1.6[3(5(2))-5]
1.6[30-5]
1.6[25]
40
Please help I’m timed thank you!!!
Answer:
BAP=12
ABP=32.5
BCP=45.5
help #2 #4 #6 #8 #10 #12
Write the equation in function form:
8x + 4y = 20
2. Mack buys a gourmet pizza for $50. The shop increases its purchase price by 50%? What is the new price of the pizza?
Answer:
$75
Step-by-step explanation:
50% is half of the total, meaning that we can take half of $50, then add it to 50. Half of 50 is 25, so 50 + 25 = 75 dollars.
Solve pls branliest!
Answer:
1 23 then 70 .2 corrected
An academy requires there to be 3 teachers for every 72 students and 5 tutors for every 60 students. How many students does the academy have per teacher? Per tutor? How many tutors does the academy need if it has 132 students?
please ans very easy question
Answer:
what is the question please tell me on comment
Which problem could the bar diagram represent
ANSWER: is there a picture for the question?
Step-by-step explanation:
A ping pong ball has a 75% rebound ratio. When you drop it from a height of k feet, it bounces and bounces endlessly. If the height of the bounce follows geometric progression, find the general term that represent the situation in term of k. [2 marks] Hence, if the ball dropped from a height of 235ft, determine i. the highest height achieved by the ball after six bounces ii. the total distance travelled by the ball when it strikes the ground for 12th time [2 marks] [3 marks b) The number of cell double after each process of cell division every 2 hours. If there are 120 bacteria initially, how many bacteria will be there after one and half day? [4 marks]
The movement of the ping pong ball follows a exponential progression.
The expression for the k-th bounce is: [tex]\mathbf{T_k = 235 \times (0.75)^k}[/tex]The height after the 6th bounce is 41.82 ftThe total distance after the 12th bounce is 1584.84ft.There will be 31457280 bacteria after a day and a half.1. Ping pong ball
The given parameters are:
[tex]\mathbf{a = 235}[/tex] --- the initial height
[tex]\mathbf{r = 75\%}[/tex] --- the common ratio
(a) The expression after bouncing k times
To do this, we make use of
[tex]\mathbf{T_n = a \times r^n}[/tex]
So, we have:
[tex]\mathbf{T_n = 235 \times (0.75)^n}[/tex]
In this case; k = n.
So, the equation becomes
[tex]\mathbf{T_k = 235 \times (0.75)^k}[/tex]
Hence, the expression for the k-th bounce is: [tex]\mathbf{T_k = 235 \times (0.75)^k}[/tex]
(b) The height after bouncing 6 times
This means that k = 6.
So, we have:
[tex]\mathbf{T_k = 235 \times (0.75)^k}[/tex]
[tex]\mathbf{T_6 = 235 \times (0.75)^6}[/tex]
[tex]\mathbf{T_6 = 41.82}[/tex]
Hence, the height after the 6th bounce is 41.82 ft
(c) The total distance after the 12th bounce
First, we calculate the total height after the 12th bounce using:
[tex]\mathbf{S_k = \frac{a(1 - r^k)}{1 - r}}[/tex]
So, we have:
[tex]\mathbf{S_k = \frac{235 \times (1 - 0.75^{12})}{1 - 0.75}}[/tex]
[tex]\mathbf{S_k = \frac{235 \times (0.968)}{0.25}}[/tex]
[tex]\mathbf{S_k = 909.92}[/tex]
So, the total distance is:
[tex]\mathbf{Distance = 2 \times S_k - a}[/tex]
[tex]\mathbf{Distance = 2 \times 909.92 - 235}[/tex]
[tex]\mathbf{Distance = 1584.84}[/tex]
Hence, the total distance after the 12th bounce is 1584.84ft.
(2) Cell division
The given parameters are:
[tex]\mathbf{r = 2/2hr}[/tex] --- rate
[tex]\mathbf{a = 120}[/tex] --- initial number of cells
[tex]\mathbf{t = 18}[/tex] --- number of 2 hours is a day and a half
So, the number of bacteria is:
[tex]\mathbf{T_t = ar^t}[/tex]
This gives
[tex]\mathbf{T_t = 120 \times 2^{18}}[/tex]
[tex]\mathbf{T_t = 31457280}[/tex]
Hence, there will be 31457280 bacteria after a day and a half.
Read more about exponential functions at:
https://brainly.com/question/11487261
PLEASE HELP ME ITS ALGEBRA THANK YOUUUU