solve for variable (image attached)

Answer:

D

Step-by-step explanation:

We will need to use the compound interest formula:

A = P(1 + r)ⁿ

A = final amount

P = Initial amount

r = rate

n = time applied

Our equation will then look like this

A = 500(1.05)⁸

A = 738.72772

Answer:

the equation you would use: y = 30x + 50

(x= months)

(y= cost)

then you would plug in the cost, 260, for y to get

260 = 30x + 50 --> 7 months

Step-by-step explanation:

I got the equation from the slope intercept form y = mx +b.

The 30 is the m, or slope, because you end up paying the same amount every month. The b value would be the 50 that he initially pays because that never changes.

Since you're given the y-value of 260, you just plug it in to your new equation of y = 30x + 50 to solve for x.

when solving the equation with the plugged in numbers, (260 = 30x + 50) first subtract 50 from both sides to get 210 = 30x,

then divide by 30 on both sides (to keep the equations equal to each other and find x) --> you should get 7

Therefore, Paul has been at the gym seven months if he has paid $260.

Answer:

9/79/169%

Step-by-step explanation:

16/169×100%=9/79/169%

Answer:

9 + y < 21

Step-by-step explanation:

Step-by-step explanation:

In box, write 170.

Hope it helps.

Step-by-step explanation:

Hypotneuse²=Base²+Height²

C²=11²+7²

C²=121+49

C²= 170

C=√170

C=13.08

hope it is help full

Step-by-step explanation:

Step-by-step explanation:

1. ∠SPQ

2. ∠b and ∠c both are supplementary of ∠a

3. ∠BFG

4. ∠GFH

5. ∠ECB

6. ∠DCB

7. (i) ∠ABX and ∠BCZ

(ii) ∠DCZ and ∠CBX

(iii) ∠ABW and ∠BCY

(iv) ∠DCY and ∠CBW

Answer:

-2

Step-by-step explanation:

=-3 2/5 * 5/34

=-17/5 * 5/34

=-1/2

multiplicative inverse of -1/2 is -2

Given:

City's population= 785,000.

Calculating of city's population:

[tex]\to \bold{785000 \cdot 8.5 \% = 785000 \cdot \frac{8.5}{100}=785000 \cdot \frac{\frac{85}{10}}{100}}[/tex]

Calculating the complex fraction:

[tex]\to \bold{\frac{\frac{85}{10}}{100}, \text{write as 100 like} \ \frac{100}{1}}[/tex]

[tex]\to \bold{785000 \cdot \frac{ \frac{85}{10}}{100}=785000 \cdot \frac{\frac{85}{10}}{\frac{100}{1}}=785000 \cdot \frac{85}{1000}=66725}[/tex]

Therefore, [tex]\bold{8.5\% \ of\ 785000\ is\ {66725}}[/tex]

Calculating [tex]\bold{9.4\%}[/tex] of the city's population:

[tex]\to \bold{9.4\% (\frac{9.4}{100})}:\\\\\to \bold{785000 \cdot 9.4\% = 785000 \cdot \frac{9.4}{100}=785000 \cdot \frac{\frac{64}{10}}{100}}[/tex]

Calculating the complex fraction:

[tex]\to \bold{ \frac{\frac{94}{10}}{100}\ \text{write 100 as} \ \frac{100}{1}}\\\\\to \bold{785000 \cdot \frac{\frac{94}{10}}{100}=785000 \cdot \frac{\frac{94}{10}}{\frac{100}{1}}=785000 \cdot \frac{94}{1000}=73790}\\\\[/tex]

Therefore, [tex]\bold{9.4\%\ of\ 785000\ is\ {73790}}[/tex]

So, the final answer is "Between 66725 and 73790 people use the transit system daily".

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Answer:

-7/2,-2.1,✓5,✓9,3.5

Step-by-step explanation:

✓5=2.23

✓9=3

-7/2=-3.5

Answer:

136

Step-by-step explanation:

Substitute the values for the variables.

[tex]10(-3)^2+3(5)-5(-3)-(-3)^2+5(5)\\\\90+15+15-9+25\\\\136[/tex]

Answer: Choice C.  f(x) and g(x) have a common x intercept.

Explanation:

The graph of f(x) shows it has an x intercept at x = 2, since this is one location where the curve crosses the x axis.

The g(x) table shows that x = 2 and y = 0 pair up together. This is the location (2,0). This location is the exact same x intercept as described earlier.

This is the common x intercept the two functions share. This means the two functions cross or intersect at this location.

[tex]\\ \rm\longmapsto a^3-a+b^3-b[/tex]

[tex]\\ \rm\longmapsto a(a^2-1)+b^3-b[/tex].

Take out b common

[tex]\\ \rm\longmapsto a(a^2-1)+b(b^2-1)[/tex]

[tex]\\ \rm\longmapsto (a+b)(a^2-1)(b^2-1)[/tex]

Step-by-step explanation:

a^3-a+b^3-b = a³+b³-a-b

= a³+b³ - (a+b)

= (a+b)(a²-ab+b²) - (a+b)

= (a+b) (a²-ab+b²-1)

Answer: 100,000

Step-by-step explanation: 1,000,000 divided by 10.

Answer:

a=15

Step-by-step explanation:

5(a−1)−15=3(a+2)+4

Use the distributive property to multiply 5 by a−1.

5a−5−15=3(a+2)+4

Subtract 15 from −5 to get −20.

5a−20=3(a+2)+4

Use the distributive property to multiply 3 by a+2.

5a−20=3a+6+4

Add 6 and 4 to get 10.

5a−20=3a+10

Subtract 3a from both sides.

5a−20−3a=10

Combine 5a and −3a to get 2a.

2a−20=10

Add 20 to both sides.

2a=10+20

Add 10 and 20 to get 30.

2a=30

Divide both sides by 2.

a=230

Divide 30 by 2 to get 15.

a=15

Answer:

-10

Step-by-step explanation:

the answer to the question is-10

Answer:

If it's addition then the answer is

-10

Answer:

+9 yards

Step-by-step explanation:

Sacked for 7 then another 2 for a total of 9 yards.

Then he gains 18 yards.

18 - 9 = 9

Answer:

answer is 2

Step-by-step explanation:

can you mark me brainlist

Answer:

4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76,80

Answer:

3 1/3 ÷ 4/5 = 25/6 =4 1/6

Result in decimals: 4.1666666666667

Answer:

The answer is 5/4

For the first expression, 3 multiplies 3 plus 1 divided by the denominator 3

= 3×3 +1÷3

=10/3

then with the second expression, the division sign changes to a multiplication sign . Immediately it changes,4/5 turns to become 5/4

so now it will be

10/3×5/4

=15/12

=5/4

Answer:

h(2) or h(g(4)) = -28

Step-by-step explanation:

g(t) = t - 2,

g(4) = 4 - 2,

g(4) = 2

h(t) = -3t³ - 2t,

h(2) = -3(2)³ - 2(2),

h(2) = -24 - 4,

h(2) or h(g(4)) = -28

Answer:

C. 4.

Step-by-step explanation:

Multiply by the LCD of 2 and 4 which is 4.

Tenemos un problema sobre energía potencial gravitatoria.

Econtraremos la expresión general: U = M*h*(H - h')

Lamentablemente no tenemos ninguna información sobre este problema, por lo que tendre que utilizar una expresión general. Sabemos que la energía potencial de un objeto de masa M que está a una altura H sobre el suelo, está dada por: U = M*g*H

Donde g es la aceleración gravitatoria; g = 9.8m/s^2

Si en lugar de querer definir la energia potencial con respecto al suelo, la queremos definir con respecto a otra cosa, entonces debemos conocer la altura de esa cosa con respecto al suelo. Por ejemplo, si en este caso el techo está a una altura h' del suelo, entonces la energía potencial gravitatoria con respecto al techo será: U = M*h*(H - h')

Algo muy interesante que podemos ver en la ecuación de arriba, es que si: h' ≥ H, entonces tendremos una energía potencial negativa, lo cual tiene sentido, pues deberemos agregar energía a la lampara si queremos que esta tenga un potencial igual a cero (lo que seria equivalente a tener la lampara en el techo)

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