Solve (t^2 + 4) dx/dt = (x^2 + 36), using separation of variables, given the inital condition 2(0) = 6.

Approximate APR = (205 ÷ 24)(12)(987) = 0.1025 or 10.3%. Rounding to the nearest tenth, the answer is 10.4%.

To calculate Wally's approximate APR, we'll use the provided formula and given information:

Approximate APR = (Finance Charge ÷ #Months) * (12) ÷ Amount Financed

Plugging in the given values:

Approximate APR = ($205 ÷ 24) * (12) ÷ $987

Approximate APR = (8.5417) * (12) ÷ $987

Approximate APR = 102.5 ÷ $987

Approximate APR ≈ 0.1038

To express the result as a percentage and round to the nearest tenth, we'll multiply by 100:

Approximate APR ≈ 0.1038 * 100 = 10.38%

Rounded to the nearest tenth, Wally's approximate APR is 10.4%.

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The length of segment SR is 90x - 4s, which can be determined by analyzing the given expression for units RT and QT: 2x + 88x - 4s.

Step 1: Identify the segment
In this problem, we need to find the length of segment SR.

Step 2: Understand the given information
We are given the lengths of two segments, RT and QT, as follows:
- RT = 2x
- QT = 88x - 4s

Step 3: Analyze the relationship between segments
Since SR is the segment that includes both RT and QT, we can express the length of segment SR as the sum of the lengths of RT and QT.

Step 4: Add the lengths of RT and QT
To find the length of segment SR, add the lengths of RT and QT:
SR = RT + QT
SR = (2x) + (88x - 4s)

Step 5: Simplify the expression
Combine like terms in the expression:
SR = 90x - 4s

The length of segment SR is 90x - 4s.

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Answer:

Step-by-step explanation:

a. To find the time it takes for the stone to hit the floor, we can use the formula t = sqrt(2h/g), where h is the height of the table and g is the acceleration due to gravity. Plugging in the values, we get:

t = sqrt(2(1.5 m)/9.8 m/s^2) = 0.55 seconds.

b. To find the horizontal distance traveled by the stone, we can use the formula d = vt, where v is the initial velocity of the stone and t is the time it takes to hit the floor. Plugging in the values, we get:

d = (0.80 m/s) * (0.55 s) = 0.44 meters.

Therefore, the stone will hit the floor after 0.55 seconds and will travel 0.44 meters from the table.

Answer:

Sure, I can help you with that.

To find the area of the gazebo floor, we can think of the decagon as being composed of ten congruent triangles. Each triangle has a base of 10 feet and a height of 192 feet. The area of a triangle is equal to (1/2)bh, so the area of each triangle is (1/2)(10)(192) = 960 square feet. The area of the decagon is equal to 10 times the area of each triangle, or 960*10 = 9600 square feet.

Therefore, the area of the gazebo floor is 9600 square feet.

Here is a diagram of the decagon, with the ten congruent triangles labeled:

[Image of a decagon with ten congruent triangles labeled]

I hope this helps! Let me know if you have any other questions.

Step-by-step explanation:

I'm so grateful for your help. I would be honored if you would give me a Brainlyness award."

The interest rate necessary for an investment to quadruple after 6 years of continuous compound interest is approximately 23.105%.

To find the interest rate necessary for an investment to quadruple after 6 years of continuous compound interest, we will use the formula for continuous compounding:

A = P * e^(rt)

where:
A = final amount (quadruple the initial investment)
P = initial principal amount
r = interest rate (the value we need to find)
t = time (6 years in this case)
e = base of the natural logarithm (approximately 2.718)

Since the investment needs to quadruple, we have A = 4P. Now, we can substitute the values into the formula:

4P = P * e^(r * 6)

Divide both sides by P:

4 = e^(6r)

To solve for r, take the natural logarithm (ln) of both sides:

ln(4) = ln(e^(6r))

Using the property of logarithms, we can rewrite this as:

ln(4) = 6r

Now, divide by 6 to isolate r:

r = ln(4) / 6

Using a calculator, we find:

r ≈ 0.231049 (or 23.105% when expressed as a percentage)

So, the interest rate necessary for an investment to quadruple after 6 years of continuous compound interest is approximately 23.105%.

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Answer: a) To find the speed of Train A, we need to divide the distance traveled by the time taken:

Speed = Distance / Time

Speed = 520.4 km / 4.8 h

Speed ≈ 108.42 km/h

Rounding to the nearest whole number, we get:

Train A is traveling at 108 km/h (approximately).

b) To find the speed of Train B, we need to divide the distance traveled by the time taken:

Speed = Distance / Time

Speed = 72.1 km / 0.8 h

Speed ≈ 90.13 km/h

Rounding to the nearest whole number, we get:

Train B is traveling at 90 km/h (approximately).

Step-by-step explanation:

Answer:

Constant

Step-by-step explanation:

What is an exponential function?

An exponential function is a function with the general form y = abx, a ≠ 0, b is a positive real number and b ≠ 1. In an exponential function, the base b is a constant. The exponent x is the independent variable where the domain is the set of real numbers.

In this case, y=ab^x

where 0.983 is in our b term, which gives the meaning that number is our constant in this exponential function.

Answer:

The order from smallest to largest price per package is: December, April, February.

Step-by-step explanation:

For the sale in February:

- Price per package = $4.49 ÷ 3 = $1.50 per package

For the sale in April:

- Price per package = $7.39 ÷ 5 = $1.48 per package

For the sale in December:

- Price per package = $5.88 ÷ 4 = $1.47 per package

An equivalent function of the form G'(t) = abt for the given function G(t) = 15(4)+3 is: G'(t) = 63 * 1.

An equivalent function refers to a mathematical function that has the same output values or behavior as another function but may have a different mathematical expression or representation. In other words, two functions are considered equivalent if they produce the same results for the same inputs, even though they may be expressed differently in terms of mathematical notation, variables, or parameters.

According to the given information:

To write an equivalent function of the form G'(t) = abt, we need to rearrange the given function G(t) = 15(4)+3 into a format that matches the form G'(t) = abt.

The given function G(t) = 15(4)+3 can be simplified as follows:

G(t) = 60 + 3

G(t) = 63

Now, we can see that G(t) is a constant function with a constant value of 63. To express it in the form G'(t) = abt, we can rewrite it as:

G'(t) = 63 * 1

So, an equivalent function of the form G'(t) = abt for the given function G(t) = 15(4)+3 is:

G'(t) = 63 * 1

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Using the Maclaurin polynomial of degree 6, the approximation for the integral ∫³√(1+x²)dx from 0 to 0.4 is ≈ 0.41721.

To find the Maclaurin polynomial of degree 6 for the function g(x) = ³√(1+x²), we will use the binomial series expansion:

(1+x)^(n) = 1 + nx + (n(n-1)x²)/2! + (n(n-1)(n-2)x³)/3! + ...

In our case, n = 1/3, and x = x²:

g(x) = (1+x²)^(1/3) = 1 + (1/3)x² - (1/9)(2/3)x⁴/2! + (1/27)(2/3)(-1/3)x⁶/3! + ...

Now, we can write the Maclaurin polynomial of degree 6:

g(x) ≈ 1 + (1/3)x² - (1/27)x⁴ + (2/729)x⁶

To approximate the integral, we can integrate the polynomial from 0 to 0.4:

∫(1 + (1/3)x² - (1/27)x⁴ + (2/729)x⁶)dx from 0 to 0.4 ≈ [x + (1/9)x³ - (1/135)x⁵ + (1/2187)x⁷] evaluated from 0 to 0.4

Now, plug in the limits:

≈ [0.4 + (1/9)(0.4³) - (1/135)(0.4⁵) + (1/2187)(0.4⁷)] - [0 + (1/9)(0³) - (1/135)(0⁵) + (1/2187)(0⁷)]

≈ 0.4 + 0.01778 - 0.00059 + 0.00002

≈ 0.41721

Thus, using the Maclaurin polynomial of degree 6, the approximation for the integral ∫³√(1+x²)dx from 0 to 0.4 is ≈ 0.41721.

This can be evaluated using basic integration techniques to get an approximate value of the integral. This method is useful for approximating integrals that cannot be solved exactly, and the accuracy of the approximation can be improved by using higher degree Maclaurin polynomials.

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The workers would have traveled a total of 32 km while erecting the fence over 40 days.

To determine the total distance the workers traveled while erecting the fence, we can use the following terms: daily distance, number of days, and total distance.

Step 1: Determine the daily distance traveled.
The workers erect 0.8 km of new fence each day.

Step 2: Determine the number of days it takes to erect the fence.
It takes 40 days to erect the fence.

Step 3: Calculate the total distance traveled.
To find the total distance, multiply the daily distance (0.8 km) by the number of days (40).

Total distance = Daily distance × Number of days
Total distance = 0.8 km × 40

Total distance = 32 km

So, the workers would have traveled a total of 32 km while erecting the fence over 40 days.

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The solution to the system is x = 94/9 and y = 22/9.

There is a unique solution, we classify the system as consistent and independent.

Part 1: Solve the system using linear combination or substitution. Show all work. (4 points)
System: 3x - 12y = 2, y = x - 8
Part 2: Classify the system as consistent independent, inconsistent, or coincident. (2 points)

Part 1: Let's solve the system using substitution:
Since y = x - 8, we can substitute this expression for y in the first equation:
3x - 12(x - 8) = 2

Now, we'll solve for x:
3x - 12x + 96 = 2
-9x + 96 = 2
-9x = -94
x = 94/9

Now that we have the value of x, we can substitute it back into y = x - 8 to find the value of y:
y = (94/9) - 8
y = (94 - 72)/9
y = 22/9

So, the solution to the system is x = 94/9 and y = 22/9.

Part 2: Since there is a unique solution, we classify the system as consistent and independent.

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The function is increasing for all real values of x where x < –4.

The statement that is true about the function is: "The function is decreasing for all real values of x where x < -4."

In order to determine the behavior of the function, we look at the given options. Among the options, the only statement that aligns with the function being decreasing is the one that states the function is decreasing for all real values of x where x < -4.

If a function is decreasing, it means that as the value of x decreases, the value of the function also decreases. In this case, it indicates that as x becomes more negative, the function's values decrease.

Therefore, the statement that correctly describes the behavior of the function is that it is decreasing for all real values of x where x < -4.

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The function 1/[tex]r^2[/tex] can be expressed in terms of the spherical Bessel functions of the first kind, which are a family of solutions to the spherical Bessel differential equation.

The expansion involves a combination of the delta function and the first two spherical Bessel functions, j_0(r) and j_1(r). Specifically, the expansion can be written as (1/2)*[pi * delta(r) + (1/r)*d/d(r)(r * j_0(r)) + (1/[tex]r^2[/tex])*d/d(r)[[tex]r^2[/tex] * j_1(r)]]. This expansion is valid for all values of r except for r=0, where the first term dominates. The spherical Bessel functions are commonly used in physics, particularly in the context of scattering problems and wave propagation.

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The detail that adds tension to the rising action of the story is when Mother Wolf tells Mowgli that some day he will have to kill Shere Khan.

This statement introduces a sense of conflict and foreshadows a significant challenge that Mowgli must face in the future. The idea of Mowgli, a young boy raised by wolves, confronting and defeating the powerful and dangerous Shere Khan adds suspense to the story, as readers anticipate the eventual showdown between these two characters.

Other details, such as Mowgli growing stronger and learning life lessons, or Mowgli forgetting his mother's advice, are relevant to his character development, but do not contribute as directly to the story's tension. Similarly, Mowgli considering himself a wolf and lacking the ability to speak like a human reflects his unique upbringing, but does not add tension in the same way as the impending confrontation with Shere Khan.

In conclusion, Mother Wolf's warning about Mowgli's future encounter with Shere Khan adds tension to the rising action of the story, as it sets up an exciting and challenging conflict for the protagonist to face, capturing the reader's interest and anticipation.

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If lea wants to divide the canvas into sections that contain an area of 3 then Lea can create 81 sections on the canvas.

To find the number of sections Lea can create on the painting canvas, given the length is 3^5 mm, the width is 3^7 mm, and each section has an area of 3^8 mm^2 we should follow the steps given below:

Step 1: Calculate the total area of the canvas by multiplying the length and the width.
[tex]Total area = (3^5 mm) * (3^7 mm)[/tex]

Step 2: Use the property of exponents that states a^m * a^n = a^(m+n) to simplify the total area.
Total area = 3^(5+7) mm^2
Total area = 3^12 mm^2

Step 3: Divide the total area of the canvas by the area of each section to find the number of sections.
Number of sections = (3^12 mm^2) / (3^8 mm^2)

Step 4: Use the property of exponents that states a^m / a^n = a^(m-n) to simplify the number of sections.
Number of sections = 3^(12-8)
Number of sections = 3^4

Step 5: Calculate the numerical value of 3^4.
Number of sections = 81

Lea can create 81 sections on the canvas.

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To evaluate the integral ∫√5+x/5-x dx, we first need to simplify the integrand. We can do this by multiplying the numerator and denominator of the fraction by the conjugate of the denominator, which is 5+x. This gives us:

∫√(5+x)(5+x)/(5-x)(5+x) dx

Simplifying further, we get:

∫(5+x)/(√(5-x)(5+x)) dx

We can now make a substitution by letting u = 5-x. This gives us du = -dx, and we can substitute these values into the integral to get:

-∫(4-u)/(√u(9-u)) du

To simplify this expression, we can use partial fraction decomposition to break it up into simpler integrals. We can write:

(4-u)/(√u(9-u)) = A/√u + B/√(9-u)

Multiplying both sides by √u(9-u), we get:

4-u = A√(9-u) + B√u

Squaring both sides and simplifying, we get:

16 - 8u + u^2 = 9A^2 - 18AB + 9B^2

From this equation, we can solve for A and B to get:

A = -B/3
B = 2√2/3

Substituting these values back into the partial fraction decomposition, we get:

(4-u)/(√u(9-u)) = -√(9-u)/3√u + 2√2/3√(9-u)

We can now substitute this expression back into the integral to get:

-∫(-√(9-x)/3√x + 2√2/3√(9-x)) dx

This integral can be evaluated using standard integral formulas, and we get:

(2/3)√(5+x)(9-x) - (2/9)√(5+x)^3 + C

where C is the constant of integration.

In summary, to evaluate the integral ∫√5+x/5-x dx, we simplified the integrand by multiplying the numerator and denominator by the conjugate of the denominator, made a substitution to simplify the expression further, used partial fraction decomposition to break it up into simpler integrals, and evaluated the integral using standard integral formulas. The final answer is (2/3)√(5+x)(9-x) - (2/9)√(5+x)^3 + C.

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To use Lagrange multipliers, we need to define the Lagrangian function:

L(x, y, z, λ) = xyz + λ(x + y + z - 9)

Now, we need to find the partial derivatives of L with respect to x, y, z, and λ and set them equal to 0:

∂L/∂x = yz + λ = 0
∂L/∂y = xz + λ = 0
∂L/∂z = xy + λ = 0
∂L/∂λ = x + y + z - 9 = 0

From the first three equations, we can see that:

yz = -λ
xz = -λ
xy = -λ

Multiplying these equations together, we get:

(xyz)^2 = (-λ)^3

Substituting λ = -yz into the fourth equation, we get:

x + y + z - 9 = 0

Substituting λ = -yz into the first equation and solving for x, we get:

x = -λ/yz = (yz)^2/(-yz) = -y^2z^2

Similarly, we can solve for y and z:

y = -x^2z^2
z = -x^2y^2

Substituting these expressions into the constraint equation, we get:

(-y^2z^2) + (-x^2z^2) + (-x^2y^2) - 9 = 0

Simplifying and solving for xyz, we get:

xyz = sqrt(9/(x^2 + y^2 + z^2))

To maximize xyz, we need to minimize x^2 + y^2 + z^2. Therefore, we can set:

x^2 + y^2 + z^2 = 3

Substituting this into the expressions for x, y, and z, we get:

x = -y^2z^2
y = -x^2z^2
z = -x^2y^2

Substituting these expressions into xyz, we get:

xyz = sqrt(9/3) = 3

Therefore, the maximum value of f(x, y, z) = xyz subject to the constraint x + y + z - 9 = 0 is 3.
To solve this problem using Lagrange multipliers, we first set up the Lagrangian function L(x, y, z, λ) with the constraint function g(x, y, z) = x + y + z - 9.

L(x, y, z, λ) = f(x, y, z) - λ(g(x, y, z))

L(x, y, z, λ) = xyz - λ(x + y + z - 9)

Now we take the partial derivatives with respect to x, y, z, and λ, and set them equal to 0:

∂L/∂x = yz - λ = 0
∂L/∂y = xz - λ = 0
∂L/∂z = xy - λ = 0
∂L/∂λ = x + y + z - 9 = 0 (the constraint)

From the first three equations, we get:

yz = xz = xy

Since x, y, and z are positive, we can divide the first two equations:

y/z = x/z => y = x
x/z = y/z => x = y

So x = y = z. Now we can use the constraint equation:

x + x + x - 9 = 0 => 3x = 9 => x = 3

Thus, x = y = z = 3. Now we can find the maximum value of f(x, y, z):

f(3, 3, 3) = 3 * 3 * 3 = 27

So the maximum value of f(x, y, z) = xyz subject to the constraint x + y + z - 9 = 0 is 27, and this occurs at the point (3, 3, 3).

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The marked point under (x, y) are (-4,-6), (-3,-5), (-2,-4), (-1,-3), (0,-2), (1,-3), (2,-4), (3,-5) and (4,-6), under the condition that (A) y=x-2, (B) y=-x-2, (C) y=|x|-2.
Point A
where y=x-2.
This projects that for every x value, y will be 2 less than that x value. So if we place in x=0, we get y=-2. If we plug in x=1, we get y=-1 and so on. So we could plot these points on the coordinate plane as (0,-2), (1,-1), (2,0), (3,1) .

Then, similarly point B
where y=-x-2.
This projects that for every x value, y should be 2 less than the negative of that x value. So if we place in x=0, we get y=-2. If we place in x=1, we get y=-3 and .
Then, we can place these points on the coordinate plane as (0,-2), (1,-3), (-1,-1), (2,-4) .

Finally let's proceed on to point C where y=|x|-2. This projects that for every positive x value, y will be 2 less than that x value and for every negative x value, y will be 2 less than the negative of that x value. So if we plug in x=0, we get y=-2. If we plug in x=1, we get y=-1 and so on.
So we can place these points on the coordinate plane as (0,-2), (1,-1), (-1,-1), (2,0), (-2,0) and so on.

So all the evaluated points are (-4,-6), (-3,-5), (-2,-4), (-1,-3), (0,-2), (1,-3), (2,-4), (3,-5) and (4,-6).

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Minimizing the sum of squared residuals.

The OLS (Ordinary Least Squares) estimator is derived by minimizing the sum of squared residuals. This method aims to find the line of best fit that minimizes the vertical distance between the observed data points (Yi) and the predicted values on the regression line. The residuals represent the differences between the observed values and the predicted values.

By minimizing the sum of squared residuals, the OLS estimator ensures that the line fits the data as closely as possible. This approach is based on the principle of least squares, which seeks to find the parameters that minimize the overall discrepancy between the observed data and the predicted values.

Connecting the Yi corresponding to the lowest Xi observation with the Yi corresponding to the highest Xi or ensuring that the standard error of the regression equals the standard error of the slope estimator are not the steps involved in deriving the OLS estimator. The OLS method specifically focuses on minimizing the sum of squared residuals.

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"IF THERE BASES ARE SAME POWER WILL BE ADD"

4^6+2=4^8 THAT IS AN ERROR

The area of the surface generated by revolving the curve y=4x+2 on [0,4] about the x-axis is S =4π/3 (3√17 + 2) .

To find the surface area generated by revolving the curve y=4x+2 about the x-axis on [0,4], we need to use the formula:

S = 2π∫[a,b] y ds

where ds = \sqrt(1 + (dy/dx)²) dx is the arc length element.

First, we find dy/dx: dy/dx = 4

Then, we can find the arc length element: ds = \sqrt(1 + (dy/dx)²) dx = \sqrt(1 + 16) dx = \sqrt(17) dx

The integral for surface area becomes: S = 2π∫[0,4] y ds = 2π∫[0,4] (4x+2)√17 dx

Evaluating this integral, we get:

S = 2π(2/3)√17 [ (4x+2)^(3/2) ]_0^4

S = 4π/3 (3√17 + 2)

Therefore, the area of the surface generated is 4π/3 (3√17 + 2) square units.

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Answer:

68in

Step-by-step explanation:

square: 3x3=9

9+9= 18

trapezoid (centre area) : 7x3x5=25

25x2=50

50+18=68

not entirely sure abt this

Answer: x² - 2x - 3

Step-by-step explanation:

      What is FOIL? The FOIL method is used to multiply two binomials.

F ➜ First
O ➜ Outer
I ➜ Inner
L ➜ Last

      Let us break it down into each piece by multiplying, following the pattern.

F ➜ x * x ➜ x²
O ➜ x * 1 ➜ x
I ➜ x * -3 ➜ -3x
L ➜ -3 * 1 ➜ -3

      Lastly, we add these pieces together.

x² + x - 3x - 3 = x² - 2x - 3

The distance between the airplane and the tower is approximately 1864.5 meters.

To solve this problem, we can use trigonometry. Let's draw a diagram to help us visualize the situation:

```
   T
  /|
 / |
/  | 500m
/a  |
--------
  x
```

In this diagram, "T" represents the control tower, "a" represents the airplane, and "x" represents the distance between them. We know that the height of the airplane is 500m, and the angle of depression from the tower to the airplane is 15 degrees. This means that the angle between the horizontal ground and the line from the tower to the airplane is also 15 degrees.

Using trigonometry, we can set up the following equation:

```
tan 15 = 500 / x
```

We can solve for "x" by multiplying both sides by "x" and then dividing by tan 15:

```
x = 500 / tan 15
```

Using a calculator, we can find that tan 15 is approximately 0.2679. Therefore:

```
x = 500 / 0.2679
x ≈ 1864.5m
```

So the distance between the airplane and the tower is approximately 1864.5 meters.

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To find three positive integers x, y, and z that satisfy the given conditions, we need to use the concept of maximizing a function subject to certain conditions. Solving for y and z, we have y = 15 and z = 16.

In this case, we want to maximize the function P= xy^2z, subject to the condition that the sum of x, y, and z is 32.
To maximize P, we need to find the values of x, y, and z that make P as large as possible. One way to do this is to use the method of Lagrange multipliers, which involves finding the critical points of a function subject to a constraint.
In this case, we have the function P= xy^2z and the constraint x+y+z=32. Using Lagrange multipliers, we can set up the following equations:
∂P/∂x = λ∂(x+ y+ z)/∂x
y^2z = λ
∂P/∂y = λ∂(x+ y+ z)/∂y
2xyz = λ
∂P/∂z = λ∂(x+ y+ z)/∂z
xy^2 = λ
x+y+z=32
Solving these equations simultaneously, we get:
y^2z/x = 2xyz/y = xy^2/z = λ
Simplifying, we get:
y^2z/x = 2yz = xy^2/z
Rearranging, we get:
x = 2y^3/z
y = (x/2z)^(1/3)
z = (x/4y^2)^(1/3)
Substituting these expressions for x, y, and z into the constraint x+y+z=32, we get:
2y^3/z + (x/2z)^(1/3) + (x/4y^2)^(1/3) = 32
Solving this equation for x, y, and z, we get:
x = 16
y = 4
z = 2
Therefore, the three positive integers x, y, and z that satisfy the given conditions are x=16, y=4, and z=2. These values make P= xy^2z a maximum, since any other values of x, y, and z that satisfy the constraint x+y+z=32 would yield a smaller value of P.

To find three positive integers x, y, and z that satisfy the given conditions, we need to consider the following:
1. The sum of x, y, and z is 32: x + y + z = 32
2. The product P = xy^2z is a maximum.
First, let's express z in terms of x and y using the sum condition:
z = 32 - x - y
Now, substitute this expression for z into the product P:
P = xy^2(32 - x - y)
To maximize P, we should make y as large as possible, since it has the largest exponent in the product formula. Let's allocate the majority of the remaining sum to y. For example, if x = 1, we get:
1 + y + z = 32
Solving for y and z, we have y = 15 and z = 16. Now let's check the product:
P = (1)(15^2)(16) = 3600
This is one possible solution for x, y, and z that gives a maximum product P with the given conditions. The three positive integers are x = 1, y = 15, and z = 16, and the maximum product P = 3600.

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Check the picture below.

The radius of ⊙P is also 12, so ⊙Q and ⊙P have the same size. Therefore, they are similar circles.

1. To construct a circle circumscribed about triangle △DEF, we need to find its circumcenter, which is the point where the perpendicular bisectors of the sides of the triangle intersect.

To do this, we first draw the three perpendicular bisectors of the sides of the triangle. The point where these three bisectors intersect is the circumcenter, which we label as C. We then draw a circle with center C and radius equal to the distance between C and any of the vertices of the triangle, such as D.

2. To show that ⊙O and ⊙P are similar, we can use a similarity transformation such as a dilation. We can start by translating ⊙O and ⊙P so that their centers are both at the origin. We can then scale ⊙O by a factor of 12/5 to get a new circle ⊙Q with the same center as ⊙O and a radius of 12.

The radius of ⊙P is also 12, so ⊙Q and ⊙P have the same size. Therefore, they are similar circles. We can then translate ⊙Q back to its original position centered at (−2, 7) to show that ⊙O and ⊙P are similar circles with similarity center at (−2, 7).

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The expression for the calculation of adding 8 to the sum of 23 and 10 is 8 + (23 + 10)

To calculate expression parentheses the sum of 23 and 10, we add them together, which gives us 33. Then, we add 8 to that result, giving us a final answer of 41. So, the expression 8 + (23 + 10) equals 41.

This expression follows the order of operations, which states that we should first perform the addition inside the parentheses and then add the result to 8.

expressions are made up of numbers and symbols, and they represent a mathematical relationship or operation. In this case, the expression includes addition and parentheses, which tell us to perform the addition inside them first. The parentheses clarify which numbers should be added together first before adding 8.

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