Answer:
[tex]v = \frac{rk}{2} + h[/tex]
Step-by-step explanation:
Given the equation, [tex]r = \frac{2(v - h)}{k}[/tex], in order to solve for v:
Start by multiplying both sides by k:
[tex](k)r = \frac{2(v - h)}{k} (k)[/tex]
rk = 2(v - h)
Divide both sides by 2:
[tex]\frac{rk}{2} = \frac{2(v-h)}{2}[/tex]
[tex]\frac{rk}{2} = v - h[/tex]
Add h to both sides to isolate v :
[tex]\frac{rk}{2} + h = v - h + h[/tex]
[tex]\frac{rk}{2} + h = v[/tex]
solve 7f + 6 = 27 show working out
Answer:
f = 3
Step-by-step explanation:
7f + 6 = 27 ( subtract 6 from both sides )
7f = 21 ( divide both sides by 7 )
f = 3
7f+6=27
7f=27-6
7f=21
Divide both sides by 7 to isolate f:
f=3
Hope this helps!
#HaveAnAmazingDay
[tex]GraceRosalia[/tex]
Translate the blue shape to the pink shape...
help me quick please
Answer:
I can't help you if there's no picture lol
A coordinate plane with 2 lines. The first line is labeled y equals f(x) and passes through (negative 1, 2), (0, 2), and (2, 2). The second line is labeled y equals g(x) and passes through (negative 0.5, negative 2), points at (0, negative 1), and (1, 1). The lines intersect at (1.5, 2).
Use the graph to determine the input value for which f(x) = g(x) is true.
x = 0.5
x = 1
x = 1.5
x = 2
Answer:
1.5 Or C :)
Step-by-step explanation:
[tex]f(x)=\frac{2x}{x-1}[/tex]
[tex]f(a); f(a+h); \frac{f(a+h)-f(a)}{h}[/tex]
 Use trigonometric identities to solve each equation within the given domain
sec(x) cos(3x) = 0 from [- x /2 , x /2]
Answer:
Either [tex]x = (-\pi / 6)[/tex] or [tex]x = (\pi / 6)[/tex].
Step-by-step explanation:
Angle sum identity for cosine:
[tex]\cos(a + b) = \cos(a)\, \cos(b) - \sin(a) \, \sin(b)[/tex].
Double-angle identity for cosine and sine:
[tex]\begin{aligned}& \cos(2\, a)\\ &= \cos^{2}(a) - \sin^{2} (a) \\ &= (\cos^{2}(a) + \sin^{2}(a) - 2\, \sin^{2}(a) \\ &= 1 - 2\, \sin^{2}(a)\end{aligned}[/tex].
[tex]\sin(2\, a) = 2\, \cos(a) \, \sin(a)[/tex].
The secant of an angle is the inverse reciprocal of the cosine of that angle:
[tex]\displaystyle \text{$\sec(x) = \frac{1}{\cos(x)}$ if $\cos(x) \ne 0$}[/tex].
Apply these identities to rewrite the left-hand side of the equation.
[tex]\begin{aligned} & \sec(x) \, \cos(3\, x) \\ =\; & \frac{1}{\cos(x)} \cdot \cos(3\, x) \\ =\; & \frac{1}{\cos(x)} \cdot (\cos(x)\, \cos(2\, x) - \sin(x)\, \sin(2\, x)) \\ =\; &\cos(2\, x) \\ & - \frac{1}{\cos(x)} \cdot (\sin(x)\, \sin(2\, x)) \\ =\; & \cos(2\, x)\\ & - \frac{1}{\cos(x)} \cdot (\sin(x) \cdot (2\, \sin(x)\, \cos(x))) \\ =\; & \cos(2\, x) - 2\, \sin^{2}(x) \\ =\; & (1 - 2\, \sin^{2}(x)) - 2\, \sin^{2}(x) \\ =\; &1 - 4\, \sin^{2}(x) \end{aligned}[/tex].
Solve the rewritten equation:
[tex]\displaystyle \sin^{2}(x) = \frac{1}{4}[/tex].
Either [tex]\sin(x) = (1/2)[/tex] or [tex]\sin(x) = (-1/2)[/tex].
The question required that [tex](-\pi / 2) \le x \le (\pi / 2)[/tex]. The sine function is one-to-one over this range. In other words, for each [tex]y[/tex] between [tex](-1)[/tex] and [tex]1[/tex], there is exactly one [tex]x[/tex] between [tex](-\pi / 2)[/tex] and [tex](\pi / 2)[/tex] such that [tex]\sin(x) = y[/tex].
If [tex]\sin(x) = (-1/2)[/tex] and [tex](-\pi / 2) \le x \le (\pi / 2)[/tex], then [tex]x = (-\pi / 6)[/tex].
Otherwise, if [tex]\sin(x) = (1/2)[/tex] and [tex](-\pi / 2) \le x \le (\pi / 2)[/tex], then [tex]x = (\pi / 6)[/tex],
Verify that [tex]\cos(x) \ne 0[/tex] for either of the two [tex]x[/tex] values, such that the [tex]\sec(x)[/tex] in the original equation takes a real value.
Cuantos lugares sobran de acuerdo con el número de las mesas y de los invitados que te tienen?
Answer:la cantidad de invitados y la cantidad de mesas que no nos dio por favor agréguelo para que pueda ayudarlo :))
Step-by-step explanation:
3 sss, aas, sas, or not enough information
Answer:
AAS
Step-by-step explanation:
I'm pretty sure its this, but im sorry if im wrong!
PLEASE ANSWER RIGHT NOW HELP ME
Answer:
y - 4 = -5(x + 1)
Step-by-step explanation:
Slope = m = -5
(-1, 4)
y - y1 = m(x - x1)
y - 4 = -5(x - [-1])
y - 4 = -5(x + 1)
A lab technician has 40 gallons of a 15% iodine solution. How many
gallons of a 40% iodine solution must he add to make a 20% iodine solution?
Please show work!!
The quantity of a 40% iodine solution that must be added to 40 gallons of a 15% iodine solution to make a 20% iodine solution is: 10 gallons.
According to the question;
We are required to determine how many gallons of a 40% iodine solution must he add to make a 20% iodine solution.Let gallons of a 40% iodine solution to be added be; x gallons.
Therefore, the total gallons of a 20% iodine solution obtained is; (40+x) gallons.
By mass balance of iodine in each solution;
(15% of 40) + (40% of x) = (20% of (40 + x))(0.15 × 40) + 0.4x = 0.2x + 80.2x = 2x = 10 gallons.In essence; 10 gallons of a 40% iodine solution must be added to make a 20% iodine solution.
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4/8+2/4= pls help you get 20 points if you do
Answer:
1
Step-by-step explanation:
use BEDMAS here:
4 divided by 8 is 1/2 or 0.5
2 divided by 4 is 1/2 or 0.5
now adding these two gives you:
1/2 + 1/2 = 1
Write the expression 44(4-7)(4) using a single
exponent.
O
4-28
044
X
4-3
O 4-2
RETRY
___________
[tex] \: [/tex]
[tex] {4}^{4} ( {4}^{ - 7} )(4) = ...[/tex]
[tex] = {4}^{4 + ( - 7) + 1} [/tex]
[tex] = {4}^{ - 3 + 1} [/tex]
[tex] = \bold{{4}^{ - 2} } \to({ \sf{d.}})[/tex]
Please help me translate this Hindi Grammar Notes into English
Step-by-step explanation:
kind of sentencesIndia is a great countryLakshmi was bitten by Rahmankind of sentencebasis of their meaningsbasis of their constructionsbasis of their construction sentences are three typessimple sentencefor example the sky is bluecompound sentencefor example the plane which I take in that is blue in colourcomplex sentencefor example the pain which I take in tomorrow that is blue in that colour is blue in type......
Two farms begin the year with $1,500 of extra saving in case they lose money at the year’s end.
And???? What are we computing, you just gave me a fact.
2-h=6-k - solve for k
help please
Answer:
k=4+h
...................
Cup o’ Coffee buys its coffee for $1.25 a cup. The coffee shop then sells each cup for $3.75. What is the percent markup for a cup of coffee?
Answer:
47%
Step-by-step explanation: 375 × .125 = .046875
rounding up, 5 keeps the 7 as is, 7 is greater than 5, therefore the 8, becomes a 9, 9 is greater than 5, so the 6 becomes a 7, .047.
move the decimal three digits to the left and you get, 47%.
Please solve... I will mark you brainliest
Answer:
x = 5
Step-by-step explanation:
[tex]6x - 20 = 2x \\ - 20 = 2x - 6x \\ - 20 = - 4x \\ \frac{ - 20}{ - 4} = x = 5[/tex]
Anna challenges Sarah to a game where Sarah flips a fair coin and then randomly chooses a card from a small deck of cards that includes only 111 jack, 111 queen, 111 king, and 111 ace.The only way Sarah can win is by flipping heads and then choosing either the jack or the queen.If XXX is a random variable that represents Sarah's outcome, drag the bars to graph the probability distribution for all possible values of XXX.
The probability distribution for all possible values of X are given in the discrete probability table ;
X : ____ winning ____ not winning P(X) : ____ 0.25 ________ 0.75Fair coin = {H, T}
card = {J, Q, K, A}
Sample space :
__ H ___ TJ | HJ __ TJQ| HQ __TQK| HK __ TKA| HA __ TATotal possible outcomes = sample space = 8 Winning selection = {HJ, HQ}Probability of winning ; P(Winning) = 2/8 = 1/4 = 0.25
Probability of not winning ;
1 - P(wininng) = 1 - 1/4 = 3/4 = 0.75
X : ____ winning ____ not winning
P(X) : ____ 0.25 ________ 0.75
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At 9 AM,one share of Starbucks stock was $26. By 2 PM the price was $29. The rate the Starbucks stock value was changing is ___ per hour.
Answer:
60 cents per hour
Step-by-step explanation:
final price minus starting price is 3 divide by 5 hours to get .60
HELP ME PLEASE!
Haddad purchases a new surround sound system with a store credit card. If Haddad pays the
minimum monthly payment, he will have his balance paid off in 41 months. If he pays an
additional $15.00 each month, he will have his balance paid off in 27 months. What percent
of time will Haddad save by paying the extra $15.00 per month?
O 15%
O 34%
O 29%
O 66%
The sum of the first n terms of a sequence is Sn = n(n + 1)(n + 2).
What is the 4th term of the sequence?
O 48
O 120
O 60
O 396
Answer:
60
Step-by-step explanation:
S₄ = 4(4+1)(4+2) = 120
S₃ = 3(3+1)(3+2) = 60
4th term = 120-60=60
maths help me maths giving 10 point
pls help me on this thank you
Answer:
C) y+6=-2(x-4)
Step-by-step explanation:
3. What is the function of a Golgi complex? What
is the function of the endoplasmic reticulum?
Answer:
Step-by-step explanation:
Gogli complexes packages proteins, while endoplasmic reticulums transport proteins made by the gogli complexes around the cell.
There are 3 boxes. One of them contains gold.
In each box, there is a message, and one of them is true.
Box 1. "The gold is not in Box 2".
Box 2: "The gold is in this box".
Box 3: "The gold is not in this box".
Which box has the gold?
Since only one box contains gold, then the gold must be in Box 2.
Let's analyze the statements in each box:
Box 1 says, "The gold is not in Box 2." If this statement is true, it means the gold cannot be in Box 2.
Box 2 says, "The gold is in this box." If this statement is true, it means the gold must be in Box 2.
Box 3 says, "The gold is not in this box." If this statement is true, it means the gold cannot be in Box 3.
Now, let's consider the possibilities:
If Box 1 is true, then the gold is not in Box 2 (as stated in Box 1), and it is also not in Box 3 (since Box 3 would be false, and only one box contains the gold).
As per Box's 1 statement, the gold is not in Box 2.
If Box 3 is true, then the gold is not in Box 3 (as stated in Box 3), and it is also not in Box 2 (since Box 2 would be false, and only one box contains the gold).
Therefore, the gold must be in Box 1.
To learn more about the puzzle tests;
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#SPJ3
Rebecca is playing a video game that involves planting and cutting down trees. She moves up an energy level for each tree she plants, and she moves down a level for each tree she cuts. If Rebecca reaches energy level 10, she will earn bonus points. Rebecca is currently at energy level 4. The results of her next 3 turns are: Turn 1: 6 trees cut Turn 2: 8 trees planted Turn 3: 1 tree cut Answer the questions to find out whether Rebecca earned bonus points in the next 3 turns. Use the number line to help you add.
Using only addition, write an expression that represents Rebecca's score after these three turns. (Remember that she starts at an energy level of 4.).
Answer:
After turn one she will have 0 points !
Step-by-step explanation:
After turn one she will have 0 points
After turn 2 she will have 8 points
After turn 3 she will have 7 points
She will not earn bonus points because she could not reach ten points
(Hope this helps can I pls have brainlist (crown)☺️)
please help me lol !!!!!!!!!!!!!
Answer:
Sale kute bhan के lole
Tera baap aya ajju(^bhai 94
real world examples of:
-scalene triangle
-isosceles triangle
-perpendicular lines
Answer:
-Scalene
Nacho chipsSails on sailing boats- Isosceles
Pizza sliceRoof-Perpendicular lines
Stairs/StepsThe corner on the inside of shelves
[tex] \sf \: please \: answer \: and \: do \: not \: spam[/tex]
¢αяσυѕєℓ :)
It's based on integrals....
Hello Carousel!
[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]
Solve the integral.[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]
[tex] \tt \:\int \: \frac{ x + 2 }{( {x}^{2} + 3x + 3) \sqrt{x + 1}} \: dx \\ [/tex]
First, let's take I as ⇨ [tex]\tt \:\int \: \frac{ x + 2 }{( {x}^{2} + 3x + 3) \sqrt{x + 1}} \: dx \\ [/tex].
[tex]\tt \:I = \int \: \frac{ x + 2 }{( {x}^{2} + 3x + 3) \sqrt{x +1}} \: dx \\\tt \: I =\int \: \frac{ x + 2 }{( {x}^{2} + 2x + 1 + x + 2) \sqrt{x + 1}} \: dx \\ \tt \:I =\int \: \frac{ x + 2 }{( ({x + 1}^{2}) + x + 2) \sqrt{x + 1}}[/tex]
Let, x + 1 = m² => dx = 2mdm.
[tex]\tt \:I =\int \: \frac{ {m}^{2} + 1}{ {m}^{4} + {m}^{2} + 1 \cdot \: m} 2mdm \\ \tt \:I =\int \: \frac{ {m}^{2} + 1}{ {m}^{4} + {m}^{2} + 1 \cdot \: \bcancel{ m}} 2 \bcancel{m}dm \\ \tt \: I = \: \int \: \frac{ {m}^{2} + 1}{ {m}^{4} + {m}^{2} + 1 } 2dm[/tex]
Now, divide the numerator & denominator by m²....we'll get it as...
[tex]\tt \:I =2\int \: \frac{ 1 + \frac{1}{ {m}^{2} } }{ {m}^{2} + 1 + \frac{1}{ {m}^{2} } } \: dm \\\tt \: I =2\int \: \frac{ 1 + \frac{1}{ {m}^{2} } }{( {m}^{2} + \frac{1}{ {m}^{2} } - 2) + 3} \: dm \\\tt \: I =2\int \: \frac{ (1 + \frac{1}{ {m}^{2} }) \: dm }{ ({m} - \frac{1}{ m } ) ^{2} + 3} [/tex]
Now, let m - 1/m be t => (1 + 1/m²) dm = dt
[tex]\tt \:I =2\int \: \frac{ dt}{ {t}^{2} + 3 } \\ \tt \:I = 2\int \: \frac{ dt}{ {t}^{2} + ( \sqrt{3}) ^{2} }[/tex]
We know, [tex]\tt \:\int \: \frac{dx}{ {x}^{2} + a ^{2} } = \frac{1}{a} tan ^{ - 1} (\frac{x}{a} ) + c[/tex]...therefore...
[tex]\tt \:I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{t}{ \sqrt{3} } ) + c \: \rightarrow \boxed{ \tt \: eq. \: 1}[/tex]
Now, substitute the value of 't' in eq. 1..we'll get..
[tex]\tt \:I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{m - \frac{1}{m} }{ \sqrt{3} } ) + c \: \rightarrow \boxed{ \tt \: eq. \: 2}[/tex]
Now, substitute the value of 'm' in eq. 2...we'll get...
[tex] \tt \: I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{ \sqrt{x + 1} - \frac{1}{ \sqrt{x - 1} } }{ \sqrt{3} } ) + c \\ \tt \:I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{x + 1 - 1}{ \sqrt{3} \sqrt{x - 1} } ) + c \\ \boxed{\boxed{ \bf \: I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{x }{ \sqrt{3 (x - 1} )} ) + c }}[/tex]
The correct answer is Option B.__________________
The question is really long & tricky but once you get the hang of it you'll be good. Good luck!__________________
Hope it'll help you!
ℓu¢αzz ッ
Find the range of the function f (x) = 2x - 1 with the given domain -1, 0, 1, 2
I will give Brainliest!
Answer:2x-1
Step-by-step explanation:
explain how and solve please asap !
Answer:
x=14
y=41
x+y= 55
Step-by-step explanation:
Since a and b are parallel you know that 123° and 3y are the same degree, so 123 divided by 3 because its 3×y= 41 so y=41
the line123° and 4x+1 are on has to equal 180 because its a straight line, 180-123= 57. 57- 1 because its not with the x= 56. 56÷4 because its 4×x/its with the x= 14. Hope thsi helps :)