Solve the problem.


A pollster wishes to estimate the true proportion of U. S. Voters that oppose capital punishment. How many voters should be surveyed in order to be 96 percent confident that the true proportion is estimated to within 0. 02?


A)2627


B)53


C)2626


D)1

Answer:

68in

Step-by-step explanation:

square: 3x3=9

9+9= 18

trapezoid (centre area) : 7x3x5=25

25x2=50

50+18=68

not entirely sure abt this

Answer: a) To find the speed of Train A, we need to divide the distance traveled by the time taken:

Speed = Distance / Time

Speed = 520.4 km / 4.8 h

Speed ≈ 108.42 km/h

Rounding to the nearest whole number, we get:

Train A is traveling at 108 km/h (approximately).

b) To find the speed of Train B, we need to divide the distance traveled by the time taken:

Speed = Distance / Time

Speed = 72.1 km / 0.8 h

Speed ≈ 90.13 km/h

Rounding to the nearest whole number, we get:

Train B is traveling at 90 km/h (approximately).

Step-by-step explanation:

The total number of gifts is given as follows:

439 gifts.

The Fundamental Counting Theorem states that if there are m ways to do one thing and n ways to do another, then there are m x n ways to do both.

This can be extended to more than two events, where the number of ways to do all the events is the product of the number of ways to do each individual event, according to the equation presented as follows:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

For a single gift, the number of options is given as follows:

10 + 4 + 7 = 21 gifts.

For two gifts, the number of options is given as follows:

10 x 4 + 10 x 7 + 7 x 4 = 138 gifts.

For three gifts, the number of options is given as follows:

10 x 4 x 7 = 280 gifts.

Hence the total number of gifts is obtained as follows:

280 + 138 + 21 = 439 gifts.

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let's recall that two tangent lines to the same circle meeting outside it, will have the same length, so all those pair of tangent lines are equal in length.

Check the picture below.

The solution to the system is x = 94/9 and y = 22/9.

There is a unique solution, we classify the system as consistent and independent.

Part 1: Solve the system using linear combination or substitution. Show all work. (4 points)
System: 3x - 12y = 2, y = x - 8
Part 2: Classify the system as consistent independent, inconsistent, or coincident. (2 points)

Part 1: Let's solve the system using substitution:
Since y = x - 8, we can substitute this expression for y in the first equation:
3x - 12(x - 8) = 2

Now, we'll solve for x:
3x - 12x + 96 = 2
-9x + 96 = 2
-9x = -94
x = 94/9

Now that we have the value of x, we can substitute it back into y = x - 8 to find the value of y:
y = (94/9) - 8
y = (94 - 72)/9
y = 22/9

So, the solution to the system is x = 94/9 and y = 22/9.

Part 2: Since there is a unique solution, we classify the system as consistent and independent.

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The number 175 in Annie's equation represents the cost per hour per semester for classwork.

This means that for every additional hour of classwork a college student takes per semester, their fee increases by $175. It is important to note that this cost does not include the cost for housing, which is represented by the constant term of the equation, 3375. Therefore, the equation allows us to calculate the total fee a college student would pay for a semester based on the number of hours of classwork they take and the cost per hour.

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The area of the surface generated by revolving the curve y=4x+2 on [0,4] about the x-axis is S =4π/3 (3√17 + 2) .

To find the surface area generated by revolving the curve y=4x+2 about the x-axis on [0,4], we need to use the formula:

S = 2π∫[a,b] y ds

where ds = \sqrt(1 + (dy/dx)²) dx is the arc length element.

First, we find dy/dx: dy/dx = 4

Then, we can find the arc length element: ds = \sqrt(1 + (dy/dx)²) dx = \sqrt(1 + 16) dx = \sqrt(17) dx

The integral for surface area becomes: S = 2π∫[0,4] y ds = 2π∫[0,4] (4x+2)√17 dx

Evaluating this integral, we get:

S = 2π(2/3)√17 [ (4x+2)^(3/2) ]_0^4

S = 4π/3 (3√17 + 2)

Therefore, the area of the surface generated is 4π/3 (3√17 + 2) square units.

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The function 1/[tex]r^2[/tex] can be expressed in terms of the spherical Bessel functions of the first kind, which are a family of solutions to the spherical Bessel differential equation.

The expansion involves a combination of the delta function and the first two spherical Bessel functions, j_0(r) and j_1(r). Specifically, the expansion can be written as (1/2)*[pi * delta(r) + (1/r)*d/d(r)(r * j_0(r)) + (1/[tex]r^2[/tex])*d/d(r)[[tex]r^2[/tex] * j_1(r)]]. This expansion is valid for all values of r except for r=0, where the first term dominates. The spherical Bessel functions are commonly used in physics, particularly in the context of scattering problems and wave propagation.

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The results suggest that the mean tar content of filtered 100 mm cigarettes is significantly lower than 21.1 mg, which is the mean for unfiltered king size cigarettes. This indicates that the filters are effective in reducing the tar content of cigarettes.

Null hypothesis: The mean tar content of filtered 100 mm cigarettes is greater than or equal to 21.1 mg.

Alternative hypothesis: The mean tar content of filtered 100 mm cigarettes is less than 21.1 mg.

The test statistic to use is the t-statistic, since the population standard deviation is not known.

t = (19.8 - 21.1) / (3.21 / sqrt(25)) = -2.03

Using a t-table with degrees of freedom of 24 and a significance level of 0.05, the critical t-value is -1.711. Since our test statistic is less than the critical t-value, we reject the null hypothesis.

The p-value can also be calculated using the t-distribution with degrees of freedom of 24 and the t-statistic of -2.03. The p-value is 0.029, which is less than the significance level of 0.05. Therefore, we reject the null hypothesis.

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The expression 6\cdot6\cdot6\cdot6\cdot66\cdot6\cdot6\cdot6\cdot66 is equivalent to 60534416.

The given expression is:

6\cdot6\cdot6\cdot6\cdot66\cdot6\cdot6\cdot6\cdot66

To simplify this expression we can first simplify the factors that are multiples of 6:

6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot11\cdot11

Next, we can use the commutative property of multiplication to group the factors of 6 together:

(6\cdot6\cdot6\cdot6\cdot6\cdot6)\cdot(6\cdot6\cdot6\cdot6)

Simplifying each of these groups of factors separately, we get:

46656\cdot1296

Multiplying these two numbers together, we get the final result:

60534416

Let's break down the given expression and simplify it step by step.

The expression is:

6\cdot6\cdot6\cdot6\cdot66\cdot6\cdot6\cdot6\cdot66

We can start by simplifying the factors that are multiples of 6:

6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot11\cdot11

Next, we can use the commutative property of multiplication to group the factors of 6 together:

(6\cdot6\cdot6\cdot6\cdot6\cdot6)\cdot(6\cdot6\cdot6\cdot6)

Simplifying each of these groups of factors separately, we get:

6\cdot6\cdot6\cdot6\cdot6\cdot6 = 46656

6\cdot6\cdot6\cdot6 = 1296

Now we can substitute these values back into the expression:

46656\cdot1296

We can multiply these two numbers together to get the final result:

60534416

The given expression is:

6\cdot6\cdot6\cdot6\cdot66\cdot6\cdot6\cdot6\cdot66

To simplify this expression, we can first simplify the factors that are multiples of 6:

6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot11\cdot11

Next, we can use the commutative property of multiplication to group the factors of 6 together:

(6\cdot6\cdot6\cdot6\cdot6\cdot6)\cdot(6\cdot6\cdot6\cdot6)

Simplifying each of these groups of factors separately, we get:

46656\cdot1296

Multiplying these two numbers together, we get the final result:

60534416

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Andrew and his mother will have wrapped the same number of candy pieces in 21.6 minutes.

We need to find out how many minutes (s) Andrew and his mother wrapped the same number of candy pieces.

Given data:

The number of pieces that Andrew’s mother can wrap is y = 73.

Andrew wraps at a rate of y = 3x + 8.

To find the number of minutes (s) at which Andrew and his mother have wrapped the same number of candy pieces, we need to equate both equations and then find the value of x the equation is given as,

73 = 3x + 8

65 = 3x

x = 21.6

Therefore, Andrew and his mother will have wrapped the same number of candy pieces after 21.6 minutes.

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The absolute maximum value of the function f(x) is 222.

To find the absolute minimum value of the function f(x), we need to first find the critical points within the given interval -6 ≤ x ≤ 5. To do this, we take the derivative of f(x) and set it equal to zero:

f'(x) = 6x² + 12x - 144
0 = 6(x² + 2x - 24)
0 = 6(x+6)(x-4)

The critical points are x=-6, x=-4, and x=4. To determine which of these points correspond to a minimum value, we evaluate f(x) at each of these points and at the endpoints of the interval:

f(-6) = -880, f(-4) = -184, f(4) = -136, f(-6) = -880, f(5) = 222

Therefore, the absolute minimum value of the function f(x) is -880.

To find the absolute maximum value of the function f(x), we follow the same process. The critical points are still x=-6, x=-4, and x=4, but now we need to evaluate f(x) at each of these points and at the endpoints of the interval to determine which corresponds to a maximum value:

f(-6) = -880, f(-4) = -184, f(4) = -136, f(-6) = -880, f(5) = 222

Therefore, the absolute maximum value of the function f(x) is 222.

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Check the picture below.

Answer:

60°

Step-by-step explanation:

A hexagon has 6 angles

The sum of the measures of the exterior angles of a hexagon is equal to 360°

So, measure of each exterior angle = 360∘ / 6 = 60∘

The total area of the wrapping paper is 72.5 in².

In the given figure (attached below), we have two shapes one is a triangle and the other one is a rectangle. To find the total area of the wrapping paper we have to add the area of the rectangle part and the area of the trianglular part.

Total area = Area of the rectangular part + area of the triangular part.

Area of the rectangular part = length x breadth

from the below figure, length = 15 in

                                     breadth = 4 in

So, area of the rectangular part = 15 in x 4 in = 60 in²

Similarly, area of the triangular part = 1/2 x base x height

from the below figure, base of the triangle = 15 in -10 in = 5 in

                                      height of the triangle = 9 in - 4 in = 5 in

So, area of the triangular part = 1/2 x 5 in x 5in =  12.5 in²

Now, the total area of the wrapping paper = area of the rectangular part + area of the triangular part = 60 in² + 12.5 in² = 72.5 in².

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Answer:

Sure, I can help you with that.

To find the area of the gazebo floor, we can think of the decagon as being composed of ten congruent triangles. Each triangle has a base of 10 feet and a height of 192 feet. The area of a triangle is equal to (1/2)bh, so the area of each triangle is (1/2)(10)(192) = 960 square feet. The area of the decagon is equal to 10 times the area of each triangle, or 960*10 = 9600 square feet.

Therefore, the area of the gazebo floor is 9600 square feet.

Here is a diagram of the decagon, with the ten congruent triangles labeled:

[Image of a decagon with ten congruent triangles labeled]

I hope this helps! Let me know if you have any other questions.

Step-by-step explanation:

I'm so grateful for your help. I would be honored if you would give me a Brainlyness award."

Answer: 5

2.75+(2.45x5) = 15

The complete factorization of the expression is  (m+n)(x-y).

The complete factorization of the expression is determined as follows;

To factorize the expression (m+n)(2x-y)-x(m+n), we can first factor out the common factor (m+n):

(m+n)(2x-y)-x(m+n) = (m+n)(2x-y-x)

Next, we will factorize completely as follows;

2x - x - y = x - y

(m+n)(2x-y-x)  = (m+n)(x-y)

Therefore, the fully factorized form of the expression is (m+n)(x-y).

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Jhon bought a rectangular door mat that was 1/2 meter long and 3/10 meter wide. The area of the rectangular door mat is 3/20 square meters.

Find the area of John's rectangular door mat that is 1/2 meter long and 3/10 meter wide, you'll need to multiply the length by the width.
Identify the length and width.
Length = 1/2 meter
Width = 3/10 meter
Multiply the length and width to find the area.
Area = Length × Width
Area = (1/2) × (3/10)
Calculate the multiplication.
Area = 3/20 square meters
The area of the rectangular door mat is 3/20 square meters.

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An equivalent function of the form G'(t) = abt for the given function G(t) = 15(4)+3 is: G'(t) = 63 * 1.

An equivalent function refers to a mathematical function that has the same output values or behavior as another function but may have a different mathematical expression or representation. In other words, two functions are considered equivalent if they produce the same results for the same inputs, even though they may be expressed differently in terms of mathematical notation, variables, or parameters.

According to the given information:

To write an equivalent function of the form G'(t) = abt, we need to rearrange the given function G(t) = 15(4)+3 into a format that matches the form G'(t) = abt.

The given function G(t) = 15(4)+3 can be simplified as follows:

G(t) = 60 + 3

G(t) = 63

Now, we can see that G(t) is a constant function with a constant value of 63. To express it in the form G'(t) = abt, we can rewrite it as:

G'(t) = 63 * 1

So, an equivalent function of the form G'(t) = abt for the given function G(t) = 15(4)+3 is:

G'(t) = 63 * 1

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Answer:

The order from smallest to largest price per package is: December, April, February.

Step-by-step explanation:

For the sale in February:

- Price per package = $4.49 ÷ 3 = $1.50 per package

For the sale in April:

- Price per package = $7.39 ÷ 5 = $1.48 per package

For the sale in December:

- Price per package = $5.88 ÷ 4 = $1.47 per package

Answer:

In triangle ABC, m∠BAC = 50°. If m∠ACB = 30°, then the triangle is triangle. If m∠ABC = 40°, then the triangle is triangle. If triangle ABC is isosceles, and AB = 6 and BC = 4, then AC =

Answer:

52 degrees

Step-by-step explanation: because i looked and they looked the same so i put 52 and it was right

The possible values of x that satisfy the equation |x+5| = c are x = c - 5 and x = -c - 5.

what is algebra?

Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas.

Assuming you meant to write |x+5|= some value, I can give you a general method to solve equations involving absolute values.

If |a| = b, then either a = b or a = -b. Thus, to solve the equation |x+5| = c, where c is some given value, we can split it into two cases:

Case 1: x+5 = c

Solving for x, we get x = c - 5.

Case 2: -(x+5) = c

Solving for x, we get x = -c - 5.

So, the possible values of x that satisfy the equation |x+5| = c are x = c - 5 and x = -c - 5.

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If lea wants to divide the canvas into sections that contain an area of 3 then Lea can create 81 sections on the canvas.

To find the number of sections Lea can create on the painting canvas, given the length is 3^5 mm, the width is 3^7 mm, and each section has an area of 3^8 mm^2 we should follow the steps given below:

Step 1: Calculate the total area of the canvas by multiplying the length and the width.
[tex]Total area = (3^5 mm) * (3^7 mm)[/tex]

Step 2: Use the property of exponents that states a^m * a^n = a^(m+n) to simplify the total area.
Total area = 3^(5+7) mm^2
Total area = 3^12 mm^2

Step 3: Divide the total area of the canvas by the area of each section to find the number of sections.
Number of sections = (3^12 mm^2) / (3^8 mm^2)

Step 4: Use the property of exponents that states a^m / a^n = a^(m-n) to simplify the number of sections.
Number of sections = 3^(12-8)
Number of sections = 3^4

Step 5: Calculate the numerical value of 3^4.
Number of sections = 81

Lea can create 81 sections on the canvas.

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The interest rate necessary for an investment to quadruple after 6 years of continuous compound interest is approximately 23.105%.

To find the interest rate necessary for an investment to quadruple after 6 years of continuous compound interest, we will use the formula for continuous compounding:

A = P * e^(rt)

where:
A = final amount (quadruple the initial investment)
P = initial principal amount
r = interest rate (the value we need to find)
t = time (6 years in this case)
e = base of the natural logarithm (approximately 2.718)

Since the investment needs to quadruple, we have A = 4P. Now, we can substitute the values into the formula:

4P = P * e^(r * 6)

Divide both sides by P:

4 = e^(6r)

To solve for r, take the natural logarithm (ln) of both sides:

ln(4) = ln(e^(6r))

Using the property of logarithms, we can rewrite this as:

ln(4) = 6r

Now, divide by 6 to isolate r:

r = ln(4) / 6

Using a calculator, we find:

r ≈ 0.231049 (or 23.105% when expressed as a percentage)

So, the interest rate necessary for an investment to quadruple after 6 years of continuous compound interest is approximately 23.105%.

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The detail that adds tension to the rising action of the story is when Mother Wolf tells Mowgli that some day he will have to kill Shere Khan.

This statement introduces a sense of conflict and foreshadows a significant challenge that Mowgli must face in the future. The idea of Mowgli, a young boy raised by wolves, confronting and defeating the powerful and dangerous Shere Khan adds suspense to the story, as readers anticipate the eventual showdown between these two characters.

Other details, such as Mowgli growing stronger and learning life lessons, or Mowgli forgetting his mother's advice, are relevant to his character development, but do not contribute as directly to the story's tension. Similarly, Mowgli considering himself a wolf and lacking the ability to speak like a human reflects his unique upbringing, but does not add tension in the same way as the impending confrontation with Shere Khan.

In conclusion, Mother Wolf's warning about Mowgli's future encounter with Shere Khan adds tension to the rising action of the story, as it sets up an exciting and challenging conflict for the protagonist to face, capturing the reader's interest and anticipation.

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The probability that a student chosen randomly from the class passed the test or completed the homework is 20/27.

The probability that a student chosen randomly from the class passed the test or completed the homework is calculated as follows:

Let the probability that a student completed the homework be P(B).

Also, let the probability that a student passed the test be P(A)

P(A or B) = P(A) + P(B) - P(A * B)

From the data table:

The number of students who passed the test = 18

The number of students who completed the homework = 17

The number of students who both passed the test and completed the homework = 15.

Total number of students = 27

P(A) = 18/27

P(B) = 17/27

P(A*B) = 15/27

Therefore,

P(A or B) = 18/27 + 17/27 - 15/27

P(A or B) = 20/27

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The variance of the actuary's wait time is 36 / 121.

From the information, at the airport, there are three counters for checking the luggage. the employees at each counter work independently with the time for each customer modeled as an exponential distribution. the average time is one minute for one counter, two for the next, and three minutes for the third. an actuary, who is next in line, will take the next available counter,

From the complete question, the variance of the actuary's wait time will be:

= 1 / (11/6)²

= (6/11)²

= 36 / 121

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The value of k = 2

Substituting into the integral:

k ∫₀^(π/2k) sec²(u) du

= k [tan(u)]₀^(π/2k)

= k [tan(π/2k) - tan(0)]

= k [∞ - 0]

= ∞

This means that the integral diverges unless k = 0.

∫₀^(π/2k) sec²(x/k) dx

= ∫₀^(π/2k) (1 + tan²(x/k)) dx

= [x + k tan(x/k)]₀^(π/2k)

= π/2

So we have:

π/2 = [π/2k + k tan(π/2k)] - [0 + k tan(0)]

= π/2k + k tan(π/2k)

Multiplying through by k:

π/2 = π/2 + k² tan(π/2k)

Subtracting π/2 from both sides:

0 = k² tan(π/2k)

The only way for this equation to hold for k > 0 is if tan(π/2k) = 0. This occurs when π/2k is an integer multiple of π/2, i.e., when k is an even integer.

Therefore, the value of k that satisfies the original integral is k = 2.

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