Solve the system of equations algebraically show all work.

Y=-x^2+8x+11

Y=5x-7

Answer:

4968

Step-by-step explanation:

4500 x (1-4%) x (0.15 + 1) = 4500 x 0.96 x 1.15

(4500 x 0.96) x 1.15 = 4320 x 1.15

4320 x 1.15 = 4968

Hope this helps!

Answer:

f=2×12k⁴-6

Step-by-step explanation:

root(f+6/2)=12k²

take the root away f+6/2=12k²

f+6/2=12k⁴

f=2×12k⁴-6

Answer:

3^9

2^12

5^11

Step-by-step explanation:

if you don't get it I'll be there to help

Answer:

167.283525618[tex]in^{3}[/tex] or 53.248[tex]\pi[/tex][tex]in^{3}[/tex]

Step-by-step explanation:

first divide the diameter by 2 to get the radius and you'll get 1.6 and since the formula for finding the volume of a cylinder is [tex]\pi r^{2} h[/tex] you then square 1.6 and get 2.56 multiply that by the height and get 13.312 then multiply by pie to get 41.8208814046 and then multiply that by the number of jars you have which is four to get the total 167.283525618

or 53.248[tex]\pi[/tex] the problem did not specify how it wanted the answer to be

the answer is cubed because the volume is 3 dimentional

Answer:

x = 21

Step-by-step explanation:

The sum of interiro angles in atriangle is equal to 180:

x - 4 + 100 + 3x = 180 add like terms

4x + 96 = 180 subtract 96 from both sides

4x = 84 divide both sides by 4

x = 21

Answer:

The answer is x = 21.

Step-by-step explanation:

i am from afghanistan and you all gus

The trigonometric relation is solved and distance of the plane from the runway is D = 18,818.52 feet

Trigonometry is the study of the relationships between the angles and the lengths of the sides of triangles

The six trigonometric functions are sin , cos , tan , cosec , sec and cot

Let the angle be θ , such that

sin θ = opposite / hypotenuse

cos θ = adjacent / hypotenuse

tan θ = opposite / adjacent

tan θ = sin θ / cos θ

cosec θ = 1/sin θ

sec θ = 1/cos θ

cot θ = 1/tan θ

Given data ,

An airplane is flying 4,000 feet above the ground

A person is standing on the runway looking up at the plane. And the angle of elevation is 12°

So , from the trigonometric relation , we get

tan 12° = 4000 / D

On simplifying , we get

D = 4000 /  0.21255656167

D = 18,818.52 feet

Hence , the distance is D = 18,818.52 feet

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Answer:

6g quarts

Step-by-step explanation:

three is a factor and multiple of 6

Answer:

f(x) = 1/2(4 - x)(x - 1)(x - 2)

Step-by-step explanation:

Considering zero's and a coefficient, the function is:

f(x) = a(x - 4)(x - 1)(x - 2)

Considering y-intercept:

f(0) = a(0 - 4)(0 - 1)(0 - 2)

4 = a(-4)(-1)(-2)

4 = -8a

a = -1/2

So the function is:

f(x) = -1/2(x - 4)(x - 1)(x - 2) = 1/2(4 - x)(x - 1)(x - 2)

[tex]\large \mathbb\purple {✒✨ANSWER ✨⚘ }[/tex]

⊱─━━━━━━━━━⊱༻●༺⊰━━━━━━━━━─⊰

➝ the absolute value of a number is its distance from 0 on the number line.

⊱─━━━━━━━━━⊱༻●༺⊰━━━━━━━━━─⊰

Answer:

2 1/3

Step-by-step explanation:

if you ate a whole box, (1) and your friend ate 1/3 MORE than you, it would be: 1 + 1 1/3. hope this helped :)

The ratio of the sum of the values of a data set to the total number of values in the data set is that data set's mean.The mean of the considered data set (2, 6, 7, 9, 9, 9) is given by: Option B: 7

Mean is the ratio of the sum of the values of the data set to the total number of values available in the data set.

Thus, we get;

[tex]\rm Mean = \dfrac{\text{Sum of the observations of the data set}}{\text{Total number of observations}}[/tex]

For this case, we're given the data set 2, 6, 7, 9, 9, 9

There are total 6 observations in this data set.

The sum of these observations is:

2+6+7+9+9+9 =42

Thus, we get:

[tex]\rm Mean = \dfrac{\text{Sum of the observations of the data set}}{\text{Total number of observations}} = \dfrac{42}{6} = 7[/tex]

Thus, the ratio of the sum of the values of a data set to the total number of values in the data set is that data set's mean.The mean of the considered data set (2, 6, 7, 9, 9, 9) is given by: Option B: 7

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Answer:

b. 7

Step-by-step explanation:

Answer:

Step-by-step explanation:

Formula

P = s1 + s2 + s3

Givens

s1 = 7x - 4

s2 = x + 3

s3 = 3y + 2

Solution

P = 7x - 4 + x+3 + 3y + 2

P = 8x + 3y + 3 + 2 - 4

Answer

P = 8x + 3y + 1

Note: I can't read the choices well enough to tell which answer it is. To me, it looks like A

Answer:

c. 11.7

Step-by-step explanation:

Distance

Step-by-step explanation:

Btw The one on the upper right hand side is Right angle

Answer:

The answer is the image.

Step-by-step explanation:

Sorry for messy writing.

Answer:

Step-by-step explanation:

[tex]\underline{\text{SOLUTION:}}[/tex]

To isolate the term of x from one side of the equation, you must multiply by a polynomial.

[tex]\underline{\text{GIVEN:}}[/tex]

[tex]:\Longrightarrow: \sf{(x+3)(3x^2 - 5x - 10)}[/tex]

You have to solve with parentheses first.

[tex]:\Longrightarrow \sf{x\cdot \:3x^2+x\left(-5x\right)+x\left(-10\right)+3\cdot \:3x^2+3\left(-5x\right)+3\left(-10\right)}[/tex]

Solve.

[tex]\sf{x*3x=3x^3}[/tex]

x(-5x)=-5x²

[tex]\sf{x(-10)=-10x}[/tex]

3*3x²=9x²

3(-5x)=-15x

3(-10)=-30

Then, rewrite the problem down.

[tex]\sf{3x^3-5x^2-10x+9x^2-15x-30}[/tex]

Combine like terms.

[tex]\Longrightarrow: \sf{3x^3-5x^2+9x^2-10x-15x-30}[/tex]

Add/subtract the numbers from left to right.

-5x²+9x²=4x²

[tex]\Longrightarrow: \sf{3x^3+4x^2-10x-15x-30}[/tex]

Solve.

[tex]\sf{-10x-15x=-25x}[/tex]

Then rewrite the problem.

[tex]\Longrightarrow: \boxed{\sf{3x^3+4x^2-25x-30}}[/tex]

I hope this helps! Let me know if you have any questions.

Answer:

[tex]3x^2 + 4x^2 - 25x - 30[/tex]

Step-by-step explanation:

Step 1:  Distribute

[tex](x + 3)(3x^2 - 5x - 10)[/tex]

[tex](x * 3x^2) + (x * (-5x)) + (x * (-10)) + (3 * 3x^2) + (3 * (-5x)) + (3 * (-10))[/tex]

[tex]3x^3 - 5x^2 - 10x + 9x^2 - 15x - 30[/tex]

Step 2:  Combine like terms

[tex]3x^3 - 5x^2 + 9x^2 - 15x - 10x - 30[/tex]

[tex](3x^2) + (-5x^2 + 9x^2) + (-15x - 10x) + (-30)[/tex]

[tex]3x^2 + 4x^2 - 25x - 30[/tex]

Answer:  [tex]3x^2 + 4x^2 - 25x - 30[/tex]

Answer:

your second choice

Step-by-step explanation:

Answer:

B. 6 < s < 12.8

Step-by-step explanation:

I just took the test

The scatter plot is given below. The linear model best fits the data and the equation of the linear model is y = 0.2667 + 0.7333.

A Linear system is a system in which the degree of the variable in the equation is one. It may contain one, two, or more than two variables.

The following table represents the annual sales of a bakery for the last 7 years since the grand opening.

(a) Create a scatter plot using the data in the table. The table is given below.

[tex]\begin{matrix}\rm Year&1 &2 &3 &4 &5 &6 &7 \\\\\rm Sales (in millions)&1 &1.2 &1.5 &1.8 &2 &2.2 &2.4\end{matrix}[/tex]

(b) The linear model type best fits the data.

(c) Use a graphing calculator or other technology to determine the regression model. Graph the model on the scatter plot and write the equation of the model on the plot. Then the equation will be

[tex]\rm y=\left(\dfrac{2.4-1}{7-1}\right)\left(x-1\right) + 1\\\\y = 0.2667 (x - 1) + 1\\\\y = 0.2667x - 0.7333[/tex]

The graph is given below.

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Answer:

B

Step-by-step explanation:

It made more machines per hour than the other ones

Step-by-step explanation:

[tex]\sf x = \sqrt{a^{sin^{-1} \ t}}\\\\\\Derivative \ rule:\boxed{\dfrac{d(\sqrt{x})}{dx}=\dfrac{1}{2}*x^{\frac{-1}{2}}=\dfrac{1}{2\sqrt{x}}}[/tex]

[tex]\sf \dfrac{d(\sqrt{a^{sin^{-1} \ t}}}{dt}=\dfrac{1}{2\sqrt{a^{sin^{-1} \ t}}}*\dfrac{d(a^{sin^{-1} \ t})}{dt}\\\\\\Derivative \ rule: \boxed{\dfrac{d(a^{x})}{dx}=log \ a *a^{x}}[/tex]

                      [tex]\sf = \dfrac{1}{2\sqrt{a^{sin^{-1}} \ t}}*a^{sin^{-1} \ t}* log \ a *\dfrac{d(Sin^{-1} \ t)}{dt}\\\\[/tex]

[tex]Derivative \ rule:\boxed{\dfrac{d(sin^{-1} \ x}{dx}=\dfrac{1}{\sqrt{1-x^2}}}[/tex]

                       [tex]\sf = \dfrac{1}{2\sqrt{a^{sin^{-1} \ t}}}*a^{Sin^{-1} \ t}*log \ a*\dfrac{1}{\sqrt{1-x^2}}}}}\\\\ = \dfrac{a^{Sin^{-1} \ t}*log \ a}{2\sqrt{a^{sin^{-1} \ t}}*\sqrt{1-x^2}}[/tex]

[tex]\boxed{ \dfrac{a^{sin^{-1} \ t}}{\sqrt{a^{sin^{-1} \ t}}}=\dfrac{\sqrt{a^{sin^{-1} \ t}}*\sqrt{a^{sin^{-1} \ t}}}{\sqrt{a^{sin^{-1} \ t}}} = \sqrt{a^{sin^{-1} \ t}}}[/tex]

                         [tex]\sf = \dfrac{a^{sin^{-1} \ t}*log \ a}{2\sqrt{1-x^2}}[/tex]

[tex]\sf \dfrac{dy}{dt}=\dfrac{d(a^{cos^{-1} \ t})}{dt}[/tex]

     [tex]= \dfrac{1}{2\sqrt{a^{cos^{-1} \ t}}}*a^{cos^{-1} \ t}*log \ a *\dfrac{-1}{\sqrt{1-x^2}}}\\\\\\=\dfrac{(-1)*a^{cos^{-1} \ t}*log \ a}{2*\sqrt{a^{cos^{-1} \ t}}*\sqrt{1-x^2}}[/tex]

    [tex]\sf = \dfrac{(-1)*\sqrt{a^{Cos^{-1} \ t}}* log \ a }{2\sqrt{1-x^2}}\\\\[/tex]

                     [tex]\sf \bf \dfrac{dy}{dx}=\dfrac{dy}{dt} \div \dfrac{dx}{dt}\\[/tex]

                            [tex]\sf \bf = \dfrac{(-1)*\sqrt{a^{cos^{-1} \ t}}*log \ a}{2*\sqrt{1-x^2}} \ \div \dfrac{\sqrt{a^{sin^{-1} \ t}} *log \ a}{2*\sqrt{1-x^2}}\\\\\\=\dfrac{(-1)*\sqrt{a^{cos^{-1} \ t}}*log \ a}{2*\sqrt{1-x^2}} \ * \dfrac{2*\sqrt{1-x^2}}{\sqrt{a^{sin^{-1} \ t}} *log \ a}\\\\= \dfrac{(-1)* \sqrt{a^{cos^{-1} \ t}} }{\sqrt{a^{sin^{-1} \ t}}}\\\\= \dfrac{-y}{x}[/tex]  

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: x = \sqrt{ {a}^{sin {}^{ - 1}t } } [/tex]

here, let's differentiate it with respect to t ~

[tex]\sf   \dashrightarrow \: \dfrac{dx}{dt} = \dfrac{1}{2 \sqrt{a {}^{sin {}^{ - 1}t } } } \times a {}^{sin {}^{ - 1}t } \sdot ln(a) \times \dfrac{1}{ \sqrt{1 - {x}^{2} } }[/tex]

[tex]\sf  \dashrightarrow \: \dfrac{dx}{dt} = \dfrac{ \sqrt{ {a}^{sin {}^{ - 1}t } } \sdot ln(a)}{2 \sqrt{1 - {x}^{2} } } [/tex]

[tex]\sf \dashrightarrow \: \cfrac{dt}{dx} = \dfrac{2 \sqrt{1 - {x}^{2} } }{ \sqrt{a {}^{sin {}^{ - 1} t} \sdot ln(a)} }[/tex]

Smililarly,

[tex]\sf  \dashrightarrow \: \dfrac{dy}{dt} = \dfrac{1}{2 \sqrt{a {}^{cos{}^{ - 1}t } } } \times a {}^{cos {}^{ - 1}t } \sdot ln(a) \times \dfrac{ - 1}{ \sqrt{1 - {x}^{2} } }[/tex]

[tex]\sf  \dashrightarrow \: \dfrac{dy}{dt} = - \dfrac{ \sqrt{ {a}^{cos {}^{ - 1}t } } \sdot ln(a)}{2 \sqrt{1 - {x}^{2} } }[/tex]

Now : Lets get Required result ~

[tex]\sf \dashrightarrow \: \dfrac{dy}{dx} = \dfrac{dy }{dt} \times \dfrac{dt}{dx} [/tex]

[tex]\sf \dashrightarrow \cfrac{dy}{dx} = - \dfrac{\sqrt{ {a}^{cos {}^{ - 1}t } \sdot \cancel{ ln(a)}}}{ \cancel{2 \sqrt{1 - {x}^{2}}}} \sdot \dfrac{ \cancel{2 \sqrt{1 - {x}^{2}} } }{ \sqrt{a {}^{sin {}^{ - 1} t} }\sdot \cancel{ln(a)}}[/tex]

[tex]\sf \dashrightarrow \cfrac{dy}{dx} = - \dfrac{\sqrt{ {a}^{cos {}^{ - 1}t } }}{ \sqrt{a {}^{sin {}^{ - 1} t} }}[/tex]

[tex]\sf \dashrightarrow \cfrac{dy}{dx} = - \dfrac{y}{x} [/tex]

[ since y = [tex]\sf{\sqrt{a^{cos^{-1}t}} } [/tex] and x = [tex]\sf{\sqrt{a^{sin^{-1}t}} } [/tex] ]

Answer:B

its B on edg 2022

Step-by-step explanation:

Answer:

The table of values for a quadratic function g is shown below.x= -3, -2, -1, 0, 2, 3, 4, 6 g(x)= 48, 30, 16, 6, -2, 0, 6, 30 if 1 is a solution ...

1 answer

 ·  5 votes: try with 6 !!!!!!!!!!!!

Step-by-step explanation:

Answer:

FACT CHECK THE ANSWERS!! they are based of mild research and could be wrong!!))

both questions come back as true from the best of my ability and understanding

Step-by-step explanation:
1) In metaphysics and philosophy of language, the correspondence theory of truth states that the truth or falsity of a statement is determined only by how it relates to the world and whether it accurately describes (i.e., corresponds with) that world.

2) Some philosophers view the concept of truth as basic, and unable to be explained in any terms that are more easily understood than the concept of truth itself. Most commonly, truth is viewed as the correspondence of language or thought to a mind-independent world. This is called the correspondence theory of truth.

both exlanations are snippets from Wikipedia

Answer:

105 square feet

Step-by-step explanation:

First of all, find the area of the rectangle (length x width). 7*12 = 84. Now, find the area of the triangle [(base x height)/2]. 6*7 = 42. 42/2 = 21.

Add both of these areas together: 84 + 21 = 105. The area is 105 square feet.

Answer:

105 square feet

Step-by-step explanation:

There are two shapes in this figure, a rectangle and a triangle. We have to find the area of the two shapes separately.

l x w is the rectangle area formula.

12 x 7 = 84.

The area of the rectangle is 84 square feet

[tex]\frac{l * w}{2}[/tex] is the triangle area formula

[tex]\frac{7* 6}{2}[/tex] = 21

84 + 21 = 105 square feet.

The area of the considered regular hexagon which has got 14.7 inches of apothem and a perimeter of 101.8 inches is 748.2 sq. inches.

Apothem for a regular polygon is a line segment which originates from the center of the regular polygon and touches the mid of one of the sides of the regular polygon. It is perpendicular to the regular polygon's side it touches.

Regular polygons have all side same and that apothem bisects the side in two parts, (provable by symmetry).

Consider the diagram attached below.

The area of the regular hexagon considered = 6 times (area of triangle ABC) (because of symmetry).

Also, we have:

Area of triangle ABC = 2 times (Area of triangle ABD).

Thus, we get:
Area of the considered hexagon = 6×2×(Area of triangle ABD)

Area of the considered hexagon = 12×(Area of triangle ABD)

Perimeter of a closed figure = sum of its sides' lengths.

There are 6 equal sides in a regular hexagon (due to it being regular).

Thus, if each side is of 'a' inch length, then:

Perimeter = 6×a inches

[tex]101.8 = 6a\\\\\text{Dividing both the sides by 6, to get 'a' on one side}\\\\a = \dfrac{101.8}{6} \approx 16.967 \: \rm inches[/tex]

This is bisected by the apothem.

Thus, we get:
Length of the line segment BD = |BD| = a/2 ≈ 8.483 inches

Since it is given that the length of the apothem = |AD| = 14.7 inches, therefore, we get:

[tex]\text{Area of ABD} = \dfrac{1}{2} \times \rm base \times height \approx \dfrac{14.7 \times 8.483}{2} \approx 62.35 \: \rm in^2[/tex]

Thus, we get:

Area of the considered hexagon = 12×(Area of triangle ABD)

Area of the considered hexagon [tex]\approx 12 \times 62.35 = 748.2 \: \rm in^2[/tex]

Thus, the area of the considered regular hexagon which has got 14.7 inches of apothem and a perimeter of 101.8 inches is 748.2 sq. inches.

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Answer:

748.23

Step-by-step explanation:

On edge