Someone Help please!!

Answer:

5

Step-by-step explanation:

You have to divide 35 by 7.

35/7 is 5.

So, he puts 5 stickers on each paper.

Answer:

Loss = Rs. 198

Step-by-step explanation:

[tex]{ \sf{\%loss = \frac{loss}{cost \: price} \times 100\%}} \\ \\ { \sf{10 = \frac{loss}{1980} \times 100}} \\ \\ { \sf{loss = \frac{10 \times 1980}{100} }} \\ \\ { \sf{loss = 198}}[/tex]

The insurance company expects the interest rate to be around 4.16%.

To find the expected interest rate, we can use the formula for present value of an annuity:

PV = PMT x (1 - (1 + r)^(-n)) / r

Where:

PV = present value of the annuity, which is the amount the insurance company needs to deposit

PMT = payment per period, which is $45,000

r = interest rate per period, which is what we need to find

n = total number of periods, which is unknown

We know that the insurance company needs to deposit $2,500,000 to make the payments, so we can set:

PV = $2,500,000:

$2,500,000 = $45,000 x (1 - (1 + r)^(-n)) / r

To solve for r, we can use trial and error or an iterative method. Here, we'll use trial and error.

Let's assume n = 20, which is a reasonable number of years for an insurance policy. Then we can solve for r:

$2,500,000 = $45,000 x (1 - (1 + r)^(-20)) / r

$2,500,000r = $45,000 x (1 - (1 + r)^(-20))

(1 + r)^(-20) = 1 - ($45,000 / $2,500,000) x r

1 + r = (1 - ($45,000 / $2,500,000) x r)^(-1/20)

r ≈ 0.0416 or 4.16%

Therefore, the insurance company expects the interest rate to be around 4.16%.

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Answer: 250,000 > .00000042

Step-by-step explanation:

2.5 times 10^5 means move the decimal to the right 5 times.

2.5

1. 25.

2. 250.

3. 2,500.

4. 25,000.

5. 250,000.

250000 __  4.2 times 10^-7

10^-7 would mean move the decimal to the left that many times.

4.2

1. .42

2. .042

3. .0042

4. .00042

5. .000042

6. .0000042

7. 00000042

250,000 > .00000042

The equation that represents f(x) is f(x) = [tex]3x^2[/tex] + 3x + 4. To determine the equation that represents the function f(x) based on the given points, we can use the general form of a quadratic function:

f(x) =[tex]ax^2[/tex]+ bx + c

where a, b, and c are constants that we need to determine. We can use the given points to form a system of equations:

[tex]a(0)^2[/tex] + b(0) + c = 4 -- Equation 1

[tex]a(1)^2[/tex] + b(1) + c = 10 -- Equation 2

[tex]a(2)^2[/tex] + b(2) + c = 25 -- Equation 3

Simplifying each equation, we get:

c = 4 -- Equation 1a

a + b + c = 10 -- Equation 2a

4a + 2b + c = 25 -- Equation 3a

Substituting Equation 1a into Equation 2a and Equation 3a, we get:

a + b = 6 -- Equation 2b

4a + 2b = 21 -- Equation 3b

Solving for b in terms of a in Equation 2b, we get:

b = 6 - a

Substituting b = 6 - a into Equation 3b, we get:

4a + 2(6 - a) = 21

Simplifying and solving for a, we get:

a = 3

Substituting a = 3 into b = 6 - a, we get:

b = 3

Substituting a = 3 and b = 3 into Equation 1a, we get:

c = 4

Therefore, the equation that represents f(x) is:

f(x) = [tex]3x^2[/tex] + 3x + 4

This quadratic function passes through the given points {(0,4), (1,10), (2,25)}, as can be verified by plugging in the x-values of each point into the equation and checking that the y-values match.

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Answer:

she would have to go 30 miles per hour or less to make this possible

Step-by-step explanation:

if it went over 35 31 miles per hour they would run out of gas before they got there

Answer:

Step 1: Simplify the exponents on both sides of the equation. Recall that (a^b)^c = a^(b*c), so we can write:

(1/216)^(3v-1) = (1/6)^(2v-2)

= (6^-1)^(2v-2) (since 1/6 = 6^-1)

= 6^(-(2v-2)) (since (a^-b) = 1/(a^b))

= 6^(2-2v) (since -(2v-2) = -2v + 2)

Step 2: Rewrite 1/216 as a power of 6. We have:

1/216 = 6^(-3)

Substituting this into our equation gives:

6^(-3(3v-1)) = 6^(2-2v)

Step 3: Use the property that if a^x = a^y, then x = y. Since both sides of the equation have the same base (6), we can equate the exponents:

-3(3v-1) = 2-2v

Step 4: Solve for v. First, simplify the left-hand side of the equation:

-3(3v-1) = -9v + 3

Now we can rewrite the equation as:

-9v + 3 = 2 - 2v

Step 5: Solve for v. Add 9v to both sides and subtract 2 from both sides:

-7v = -1

Finally, divide both sides by -7 to obtain:

v = 1/7

Therefore, the solution to the equation is v = 1/7.

To verify that v = 1/7 is the solution to the equation:

(1/216)^(3v-1) = (1/6)^(2v-2)

We can substitute v = 1/7 into the equation and simplify both sides to see if they are equal:

Left-hand side:

(1/216)^(3v-1) = (1/216)^(3(1/7)-1) = (1/216)^(2/7)

Right-hand side:

(1/6)^(2v-2) = (1/6)^(2(1/7)-2) = (1/6)^(-10/7) = (6/1)^10/7

Simplifying:

(1/216)^(2/7) = (6/1)^(10/7)

Taking the seventh root of both sides:

1/6 = 1/6

Since both sides of the equation are equal, we have verified that v = 1/7 is the solution to the equation.

Answer:

36

Angle LON is a right angle so it equals 90 degrees.

The answer is in the picture below

The number of people in the stadium whose favorite stadium food is nachos is 10000.

What is random sample space?

The set of all potential outcomes for an experiment is referred to as the sample space S in a random experiment. The results of a random experiment, also known as sample points, are incompatible (i.e., they cannot occur simultaneously).

Here, we have

Given: You ask 120 randomly chosen people at a stadium to name their favorite stadium food. There are about 50,000 people in the stadium.

We have to estimate the number of people in the stadium whose favorite stadium food is nachos.

24/120 = x/50,00

x = 1200000/120

x = 10000

Hence, the number of people in the stadium whose favorite stadium food is nachos is 10000.

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The number of students enrolled in the Spanish class who are also enrolled in the French class is 0.

Let the number of students enrolled in French class be F

Let the number of students enrolled in Spanish class be S

Let the number of students enrolled in German class be G

From the given information, we have

S + F + G = Total number of students...... (1)

Total number of students = 34S = 34 - F - G...... (2)

Now, we need to find out how many students are enrolled in both Spanish and French classes. So, let us assume that x students are enrolled in both Spanish and French classes.

So, the total number of students in Spanish and French classes will be S + F - x (as x students are enrolled in both the classes).

But we are given that there are 34 students enrolled in the Spanish class. Hence, the above expression will be equal to 34.

Therefore, S + F - x = 34

Now, substituting the value of S from equation (2) we get,

34 - F - G + F - x = 34 or, - G - x = 0 or, x = - G

But x represents the number of students enrolled in both Spanish and French classes, which cannot be negative.

Hence, there are no students enrolled in the Spanish class who are also enrolled in the French class.

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After answering the provided question, we can conclude that triangle  2(AD² + DC²) = 2(58 + 26) = 168

A triangle is a locked, double-symmetrical target made up of 3 line segments known as sides that interlock at three points known as vertices. Triangles are distinguished by their sides and angles. Triangles can be rectangular prism (all factions equal), ellipse, or scalene based on their sides. Triangles are classified as acute (all angles are under 90 degrees), okay (one angle is equal to 90 degrees), or orbicular (all angles are greater than 90 ° c) (all angles greater than 90 degrees). The continent of a triangle can be calculated using the formula A = (1/2)bh, where an is the suburb, b is the triangle's base, and h is the triangle's height.

(a) The distance formula is:

d = √[(x₂ - x₁)² + (y₂ - y₁)²]

Length of AB:

AB = √[(2 - (-6))² + (5 - 3)²] = √64 = 8

Length of AC:

AC = √[(0 - (-6))² + (-5 - 3)²] = √100 = 10

Length of BC:

BC = √[(2 - 0)² + (5 - (-5))²] = √144 = 12

Midpoint of BC:

D = [(0 + 2)/2, (-5 + 5)/2] = (1, 0)

Length of AD:

AD = √[(1 - (-6))² + (0 - 3)²] = √58

Length of DC:

DC = √[(1 - 0)² + (0 - (-5))²] = √26

Now we can find the values of AC², AB², AD², and DC²:

AC² = AC² = 100

AB² = AB² = 64

AD² = AD² = 58

DC² = DC² = 26

(b) AC² + AB² = 2(AD² + DC²).

AC² + AB² = 100 + 64 = 164

2(AD² + DC²) = 2(58 + 26) = 168

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The value for the given expression is 60.

The quadratic function can represent a quadratic equation in the Standard form: ax²+bx+c=0 where: a, b and c are your respective coefficients. In the quadratic function, the coefficient "a" must be different than zero (a≠0) and the degree of the function must be equal to 2.

The exercise asks the value of the given expression a²-4a, for a=10. Thus, you should replace the variable a with the number 10. See below.

a²-4a

10²-4*10

100-40=60

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Each of the expressions has been simplified by using properties of exponents as shown below.

In Mathematics, an exponent refers to a mathematical operation that is typically used in conjunction with an algebraic expression in order to raise a quantity to the power of another.

This ultimately implies that, an exponent is represented by the following mathematical expression;

bⁿ

Where:

the variables b and n are numerical values (numbers) or an algebraic expression.

n is referred to as a superscript or power.

By applying the multiplication and division law of exponents for powers to each of the expressions, we have the following:

(1.25 × 10⁷) + 63,000,000 = (1.25 × 10⁷) + (6.3 × 10⁷) = (1.25 + 6.3) × 10⁷ = 7.55 × 10⁷

12,000 + 7 × 10⁴ = 1.2 × 10⁴ + 7 × 10⁴ = (1.2 + 7) × 10⁴ = 8.2 × 10⁴

5.88 × 10⁵ - 3.44 × 10⁵ = (5.88 - 3.44) × 10⁵ = 2.44 × 10⁵

6 × 10⁸ ÷ 120 = 6 × 10⁸ ÷ 1.2 × 10² = (6 ÷ 1.2) × 10⁸⁻² = 5 × 10⁶

9 × 10¹² ÷ 4.5 × 10⁴ = (9 ÷ 4.5) × 10¹²⁻⁴ = 2 × 10⁸

1.3 × 10³ · 2,200 = 1.3 × 10³ × 2.2 × 10³ = (1.3 × 2.2) × 10³⁺³ = 2.86 × 10⁶

(6.3 × 10⁴) + 1.3 × 10⁴ = (6.3 + 1.3) × 10⁴ = 7.6 × 10⁴

3,400 · 2 × 10⁴ = 3.4 × 10³ × 2 × 10⁴ = (3.4 × 2) × 10³⁺⁴ = 6.8 × 10⁷

9.78 × 10⁵ - 732,000 = (9.78 - 7.32) × 10⁵ = 2.46 × 10⁵

3.5 × 10² · 2 × 10⁴ = (3.5 × 2) × 10²⁺⁴ = 7 × 10⁶

1.1 × 10⁸ ÷ 22,000 = 1.1 × 10⁸ ÷ 2.2 × 10⁴ = (1.1 ÷ 2.2) × 10⁸⁻⁴ = 0.5 × 10⁴ = 5 × 10³.

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Answer:

1 4/6 as an improper fraction is 5/3

Step-by-step explanation:

What is an improper fraction?

An improper fraction is a fraction where the numerator is greater than or equal to the denominator.

How do you convert a mixed number to an improper fraction?

To convert a mixed number to an improper fraction, you multiply the whole number by the denominator and add the numerator. Then, you put that sum over the denominator.

For example, 1 4/6 can be converted to an improper fraction as follows:

1 x 6 + 4 = 10

10/6 = 5/3

So, 1 4/6 as an improper fraction is 5/3.

Answer:

The value of the book after 11 years is $103.11

The equation should be 258*0.92, 11 times repeating.

The answer should be 103.106443494, but if you round it the answer is 103.11

[tex]\qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{current amount}\\ P=\textit{initial amount}\dotfill &258\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ t=years\dotfill &11\\ \end{cases} \\\\\\ A = 258(1 - 0.08)^{11} \implies A=258(0.92)^{11}\implies A \approx 103.11[/tex]

Answer:

Step-by-step explanation:trisha is running a marathon race  she runs th erace at a steady pace she makes a graph to show how far from the finsh line she will be as she runs the race

=2

Answer: 30 mil

Step-by-step explanation:

Answer:

1.49m

Step-by-step explanation:

Trigonometry:

cosθ = adjacent/hypotenuse

cos(74) = adjacent/(5.39)

adjacent = 5.39 × cos(74)

adjacent = 2.3125974152

1.49 (to 2 d.p.)

The supplied data collection has a periodic period of 4 and an amplitude of 25.

Let's study data points with a 4-day gap;

Data point 2 is [tex](2, 76)[/tex]

Data point 6 is[tex](6, 74)[/tex]

Data point 10 is[tex](10, 75)[/tex]

Every four day intervals, the readings are within the typical range. The points[tex](3, 91), (7, 88),[/tex] and (114) all support this same 4-day timeframe [tex](11, 92).[/tex]

As the data points at intervals of 4 days follow a pattern, we may infer that the period is 4 and the amplitude is around 25.

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Answer:

periodic with a period of 4 and an amplitude of about 30

Step-by-step explanation:

The total number of words with 5 or les sletters is  1,364

We want to see how many words of 5 or less letters can be done with 4 different characters.

There are 4 words with one letter.

Now words with two letters, suppose that the word is represented by:

_,_

Each blank represents a letter, so we have 4 options per blank, then the number of words with two letters is 4*4 = 16

And with 3 is 4*4*4 = 64

And with 4 is 4*4*4*4 = 256

And finally,with 5 is: 4*4*4*4*4 = 1,024

The total sum gives:

4 + 16 + 64 + 256 + 1,024 = 1,364

These is the number of words.

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The weight of the compact car, which is approximately 1,354 kilograms, can be converted to 1,354,000 grams.

In the metric system, "kilo" means thousand, so 1 kilogram is equal to 1000 grams. To convert from kilograms to grams, we simply multiply the weight in kilograms by 1000.

In this case, the weight of the compact car is given in kilograms as 1,354. To convert to grams, we multiply by 1000 to get:

1,354 kg x 1000 g/kg = 1,354,000 g

Therefore, the weight of the compact car in grams is approximately 1,354,000 grams.

The weight of an object is a measure of the force with which gravity pulls on the object. The unit of weight in the metric system is the newton (N), but kilograms (kg) are commonly used as a unit of mass and weight in everyday life. The conversion between mass and weight depends on the local acceleration due to gravity, which is approximately 9.81 m/s^2 at the Earth's surface.

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The most accurate estimate of the distance on the ground between the wall and the bottom of the ladder is 2 meters.

One approach to tackle this problem is to apply trigonometry to establish the connection between the angle, height, and distance. Specifically, we can utilize the cosine function, which relates the adjacent side and the hypotenuse of a right triangle. In this case, the adjacent side represents the distance between the wall and the ladder, and the hypotenuse corresponds to the ladder's length. The given angle is 72 degrees.

By employing the formula cos(angle) = adjacent/hypotenuse, we can input the known values and determine the unknown distance:

cos(72) = distance/6

distance = 6 * cos(72)

distance is approximately 1.9 m

Thus, the most accurate estimation for the ground distance from the ladder's bottom to the wall is 2 m.

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Answer:2m

Step-by-step explanation:

i took the test

Answer:

Step-by-step explanation:

The difference between a sample statistic and the corresponding population parameter is known as the sampling error.

     Sampling error is the disparity between a statistic from a sample and a corresponding parameter from a population. Statistic and parameter are two crucial words in inferential statistics that are used to describe data. A statistic is used to calculate a parameter, which is a calculated value from the population, which is a large group of people or objects.

    The variance between the mean of the population and the sample's mean is known as sampling error. The sample statistic that is used to estimate the population parameter may not be the same as the population parameter.

    The discrepancy between these two values is referred to as sampling error. When a small sample is chosen from a larger population, a sampling error is created.

   Therefore, The sampling error is the discrepancy between a sample statistic and the equivalent population parameter.

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The frequency with the largest amplitude is `w ≈ 2.303` (rtol=0.01, atol=1e-08).

The question asks us to find the frequency w for which the particular solution to the differential equation [tex]dạy dy 2- + dt2 + 2y = eiwt dt[/tex]has the largest amplitude.

We can assume a positive frequency w > 0.

Let's find out how to solve this problem:

We need to find the particular solution in the form Aeiwt, and then minimize the modulus of the denominator of A over all frequencies w. It means the denominator of A will have a maximum amplitude if we minimize the modulus. The amplitude of the solution is given by the value of |A|.

Let us assume the particular solution to be `[tex]y = Aeiwt`.[/tex]

Substitute the above solution in the given differential equation.

Then, we get:[tex]`d^2(A e^(iwt))/dt^2 + 2(A e^(iwt)) = e^(iwt)`[/tex]Applying the differential operator on the above equation,

we get: [tex]`(iwt)^2 A e^(iwt) + 2A e^(iwt) = e^(iwt)`Therefore, `A = 1 / (1 - (w^2) + 2i)`.[/tex]

Thus, the amplitude of the particular solution is:

[tex]`|A| = 1 / sqrt((1 - w^2)^2 + 4w^2)`[/tex]

Now, we need to minimize the above expression to get the frequency w at which the amplitude of the particular solution is maximum. This can be done by minimizing the modulus of the denominator of A over all frequencies w.To minimize the above expression, we take the derivative of the expression with respect to w and equate it to zero, which gives us: [tex]`(8w^2) / ((w^2 - 1)^2 + 4w^2)^(3/2) - (2(w^2 - 1)) / ((w^2 - 1)^2 + 4w^2)^(3/2) = 0`[/tex]

Simplifying the above expression, we get: `

[tex]2w^2 = w^4 - 3w^2 + 1`[/tex]

Therefore, [tex]`w^4 - 5w^2 + 1 = 0`.[/tex]

Solving the above equation gives us:

`[tex]w^2 = (5 ± sqrt(21)) / 2`[/tex].Since we know that w > 0, we choose the positive value of w.

Thus, the value of w is: [tex]`w = sqrt((5 + sqrt(21)) / 2)` or `w ≈ 2.303[/tex]`.

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NR = QR: This statement is true. In a rhombus, the diagonals bisect each other, so NR is equal in length to QR.

What is Rhombus ?

A rhombus is a quadrilateral with four equal-length sides. The opposite angles of a rhombus are equal to each other, and the diagonals bisect each other at right angles. This means that the diagonals of a rhombus are perpendicular to each other and divide the rhombus into four congruent right triangles.

From the given information, we know that MNPQ is a rhombus, and that NQ and PM are diagonals that intersect at point R.

NQ is perpendicular to MP: This statement is false. In a rhombus, the diagonals are perpendicular bisectors of each other, so we know that NQ is perpendicular to PM at point R, but not necessarily to the entire diagonal MP.

NP is perpendicular to QP: This statement is also false. In a rhombus, opposite sides are parallel and congruent, but not necessarily perpendicular to each other.

NR = QR: This statement is true. In a rhombus, the diagonals bisect each other, so NR is equal in length to QR.

Angle MNQ is congruent to angle PNQ: This statement is false. While we know that NQ is perpendicular to PM at point R, we cannot conclude that angle MNQ is congruent to angle PNQ. In fact, there is not enough information given to determine the measure of either angle.

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For isosceles triangle we have proved a) ∆AHB = AHC b) AH is the median of ∆ABC c) BC = 2AD

a) To prove that ∆AHB = AHC, we need to show that the two triangles have equal sides and angles. Since ABC is an isosceles triangle at A, we know that AB = AC. Also, since AH is the altitude of the triangle, we know that it is perpendicular to BC. Therefore, angle AHB and angle AHC are both right angles.

Now, to prove that the triangles have equal sides, we need to show that HB = HC. Since AB = AC, we have:

[tex]AB^{2} = AC^2\\AB^2 - AH^2 = AC^2 - AH^2\\BH^2 = CH^2[/tex]

Therefore, HB = HC, and we have proved that ∆AHB = AHC.

From this, we can deduce that angle BHA = angle CHA, as they are opposite angles in congruent triangles. Also, we know that angle ABC = angle ACB, as it is an isosceles triangle. Therefore, angle ABH = angle ACH, and we have proved that ∆ABH = ∆ACH.

b) To prove that A, G, and H are collinear, we need to show that AH is the median of ∆ABC. Since ∆AHB = AHC, we know that HB = HC. Therefore, BG and CG are medians of the triangle, and they intersect at G.

Now, to prove that ∆GBC is equal, we can use the fact that medians of a triangle divide it into six equal triangles. Therefore, we have:

Area(∆GBC) = 2/3 * Area(∆BGC)

Area(∆GBC) = 2/3 * Area(∆ACG)

Area(∆GBC) = 2/3 * Area(∆ABG)

Since ∆ABH = ∆ACH, we know that the altitude from A to BC passes through H, which is the midpoint of BC. Therefore, AH is also the median of ∆ABC.

c) Let E be the midpoint of BC. Since AE is the median of the triangle, we know that it divides BC into two equal parts, so EC = EB. Let X be the midpoint of AD. Since M is the midpoint of HD, so:

HX = (1/2) * HD

HX = (1/2) * (2AD)

HX = AD

AX is parallel to DE so:

AB/AD = AE/AX

2 = AE/AX

Since EC = EB and HX = AD, so:

AE = EC + HX

AE = EB + HX

AE = 2HX

Therefore, substitute, simplify:

2 = 2HX/AX

2AX = 2HX

AX = HX

Since AX = HX, DX is also equal to HX, so:

AD = DX

Also, since AE = 2HX, so:

BC = 2AE

Substitute in HX = AD and AE = 2HX, so:

BC = 2AE

BC = 2(2HX)

BC = 4HX

BC = 4AD

Therefore, we have proved that BC = 2AD.

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The cost of one adult tickets would be $12.5 and the cost of one youth tickets would be $8.75 .Therefore the cost of six adult tickets and eight youth tickets would be 6(12.5) + 8(8.75) = $145.

Let the cost of adult tickets be x.

Let the cost of youth tickets be y.

So, from the given condition given in question the equations are :-

For The Jefferson family,

2x + 2y = 42.50

x + y = 21.25 —---------- equation(1)

and for The Mendoza family,

4x + 3y = 76.25 —------ equation(2)

To solve above equation 4 × equation(1) - equation(2).

y = 8.75

and x = 12.5

Hence the cost of one adult tickets would be $12.5 and the cost of one youth tickets would be $8.75 .

Therefore the cost of six adult tickets and eight youth tickets would be 6(12.5) + 8(8.75) = $145.

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—-------- Correct question format is given below —--------

(Q). Two families go to a movie on Saturday night. The Jefferson family purchases 2 adult tickets and 2 youth tickets for $42.50. The Mendoza family purchases 4 adult tickets and 3 youth tickets for $76.25. How much would it cost to purchase six adult tickets and eight youth tickets?