Answer:
............................
draw a diagram to show what happened to the particle, when a liquid cools to a solid?
And do follow if you appreciate it
Please help thank you (15 points)
Answer:
A. Complete one revolution around the sun
how much energy is contained in 3moles of chlorine
Answer:
1 mol of cl2 contains 71 g
3 mol of cl2 will contain÷
3×71=213 g
Explanation:
There ;3
Answer:
213 g
Explanation:
multiply 3 moles by relative atomic mass of chlorine which is 35.45×2 because its two chlorines and your answer will be 213g
Can someone help me pls, I do not know how to do this. i am trying to help a friend as well
Answer:
Your answer is 5 x 10⁵
I hope it's helps you
Answer:
[tex]thank \: you[/tex]
An certain element Y has two naturally occurring isotopes, 6Y (isotopic mass = 6.015123 amu) and 7Y (isotopic mass = 7.016005 amu). If the atomic mass of the element is 6.9412 amu. What is the percent abundance of 6Y?
Do not include the symbol "%" in your answer.
Report the correct answer to three significant figures
The percentage abundance of 6Y is 0.102.
An Isotope refers to two or more atoms that has the same atomic number but different mass numbers.
We have been informed from the question that the atomic mass of the element is 6.9412 amu.
Let the abundance of isotope 6Y be x
Let the abundance of isotope 7Y be 1-x
Hence;
6.9412 = 6.015123x + 7.016005(1 - x)
6.9412 = 6.015123x + 7.016005 - 7.016005x
6.9412 - 7.016005 = 6.015123x - 7.016005x
-0.102 = -1x
x = -0.102/-1
x = 0.102
Hence the percentage abundance of isotope 6Y is 0.102.
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The percentage abundance of 6Y is 7.47%
Isotopy is the phenomenon whereby two or element have the same atomic number but different mass number due to the difference in their neutron number.
We'll begin the solving as follow:
Let A represent isotope 6Y
Let B represent isotope 7Y
From the question given above, the following data were obtained:
For isotope A (6Y):Mass of A = 6.015123 amu
Abundance of A (A₀) =…? For isotope B (7Y):Mass of B = 7.016005 amu
Abundance of B (B₀) = (100 – A₀%
Relative Atomic mass of Y = 6.9412 amu
The abundance of 6Y can be obtained as follow:
[tex]RAM = \frac{MassA * A_{0} }{100} + \frac{MassB * B_{0} }{100}\\\\6.9412 = \frac{6.015123 * A_{0}}{100} + \frac{7.016005 (100 - A_{0})}{100}\\\\6.9412 = 0.06015123 A_{0} + \frac{701.6005 - 7.016005A_{0}}{100}\\\\6.9412 = 0.06015123 A_{0} + 7.016005 - 0.07016005A_{0}[/tex]
Collect like terms
[tex]6.9412 - 7.016005 = 0.06015123A_{0} - 0.07016005A_{0}\\-0.074805 = -0.01000882A_{0}[/tex]
Divide both side by –0.0100882
[tex]A_{0} = \frac{-0.074805}{-0.01000882}\\\\[/tex]
A% = 7.47%Therefore, the abundance of 6Y is 7.47%
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Given six molecules, identify the molecules with polar bonds and the molecules that are polar.CCl4, CH3Cl, H20, CO2, O2
Answer:
polar bonds- H2O, CO2, CH3CL,
The molecules that have polar bonds are CH₃Cl, and H₂O.
What are polar bonds?A polar bond is a type of covalent bond where the electron is unequally distributed.
This unequal distribution is due to the electronegativity difference of the attached atoms in the molecule.
A lewis structure of the molecule is studied to determine whether the compounds are polar and non-polar.
The molecule CCl₄: has one carbon atom at the center and the chlorine surrounds the carbon from all four sides, so even if there is a difference in the electronegativity the net dipole movement gets balanced from all four sides, so it is not a polar bond.
The molecule CH₃Cl
Similar to the CCl₄, hydrogen, and chlorine is surrounding the carbon, the three sides are hydrogen and one side is chlorine, so there is a net dipole movement and so it is a polar bond.
The molecule H₂O: The dipole movement of Hydrogen and oxygen are both in opposite directions and of different magnitude hence it will have a net dipole movement and so it is polar.
The molecule CO₂ and O₂ have net dipole movements as zero so are not polar compounds.
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What is the molecular formula of sulphuric acid and ammonia compound by criss cross method
Answer:
H2SO4 AND NH3
Explanation:
I hope it will help you
Answer:
Explanation:
H2SO4 AND NH3
Which methods separate a mixture according to the size of the particles?
A. distillation and evaporation
B. filtration and chromatography
C. filtration and evaporation
D. distillation and chromatography
Answer:
Only one of these methods separates compontents based on size.
The answer is filiration and chromatography.
Explanation:
Which family of metals is the most reactive?
Rare Earth metals
Transition metals
Alkaline Earth metals
Alkali metals?
Answer:
Alkali metals
Explanation:
Hope you like my answer and my answer helped youPlllsssss hel pls help
what is stoichiometry?
Answer:
the relationship between the relative quantities of substances taking part in a reaction or forming a compound, typically a ratio of whole integers.
Explanation:
G o o g l e
Explanation:
Stoichiometry is the calculation of reactants and products in chemical reactions in chemistry.
If I have a bottle of compound X at a pressure of 45 atm and temperature of 100 °C, what will happen if I raise the temperature to 400 °C?*
Answer:
55/350
Explanation:
because the answer is in the middle of 50and 400
calculate mass of MnO2 if 1 mole of KMnO4 completely burnt. 2KMnO4 -> K2MnO4+MnO2+O2
Answer: 80 grams
Explanation:
2KMnO4 -> K2MnO4+MnO2+O2
2 moles of KMnO4 would produce 1 mole of MnO2, so 1 mole of KMnO4 would produce 0.5 moles of MnO4. The molar mass of MnO4 is 160 g/mole. 1/2 mole of KMnO4 would therefore be (160 g/mole)*(0.5 moles) = 80 grams.
9. SI base units used in chemistry include
A. kilograms, liters, inches, and moles.
B. pounds, gallons, moles, and Fahrenheit.
C. kilograms, seconds, moles, and Kelvin.
D. pounds, gallons, moles, and Celsius.
Answer:
C. kilograms, seconds, moles, and Kelvin
explain dehydrogenation
Answer:
Dehydrogenation is the process by which hydrogen is removed from an organic compound to form a new chemical (e.g., to convert saturated into unsaturated compounds).
In what state of matter is carbon dioxide normally found on Earth?
Answer:
Gas
Explanation:
I believe that it is usually a gas on Earth.
Enumerate seven commonly encounter functional group in organic compound
Answer:
-COOH
-CHO
-CO
-NH2
-X(-Cl, -Br, -I)
-RCOOR(R= Alkyl group)
-C6H5
I need help please Which is the proper conversion factor for converting a mass expressed in pounds (lb) to the same mass expressed in grams (g)?
Answer:
C
Explanation:
There are roughly 454 grams for every pound. The conversion factor would look like this for converting 2 lbs of a sample into grams:
2lbs sample (454g sample/1lb sample) = sample in grams.
Rain soaks into the soil or runs off into oceans, rivers, and lakes. ___________ which process is this
Answer:
The water falls to the earth as precipitation, such as rain, hail, sleet, and snow. When precipitation reaches the earth's surface, some of it will flow along the surface of the land and enter surface water like lakes, streams, and rivers, as runoff. The rest of it soaks or percolates into the soil, called
write on the principle and other application of a named instrument employed in unlocking frozen joints.
We have that the bone file from our research below
The is a very important tool in unlocking frozen joints by using its
Pull stroke
Serrated edges etc
And its also used in the field of dentistry.
Before we pick an instrument to focus on we first have to under stand what a frozen joints is
Frozen Joint,
Frozen Joint, which is also refereed to as adhesive capsulitis, is a situation whereby ones joints are stiff and they experience pain in the joint.
We focus on the
Bone file( principle)
It is made of a pull stroke which is designed to aid the removal of bones,they are also designed with serrated edges which are used in many different ways one of which is to smooth bones out in order to disinfect a given area
Bone file
This can also be used in the field of dentistry.
it puts into use it variant functions to make the work of a dentist easy
In conclusion
The Bone file is a very important tool in unlocking frozen joints by using its
Pull stroke
Serrated edges etc
And its also used in the field of dentistry.
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Iron has a density of 7.86 g/cm3. Calculate the volume (in dL) of a piece of iron having a mass of 4.59 kg .
4-hydroxyl and 5- hydroxyl aldehydes exist primarily as a cyclic hemiacetals.draw the structures formed from 4-hydroxyl butanal
Which of the following is NOT a density formula?
Density = mass/volume
Density = volume/mass
mass = density x volume
volume = mass/density
4) A sample of sodium bromide, NaBr, has a mass percentage of sodium of 22.34%.
a) If the sample of sodium bromide were contaminated with sodium chloride, NaCl, would the mass percentage of Na in the sample be higher or lower than the pure sample? Justify your claim.
b) If the sample of sodium bromide were contaminated with sodium iodide, NaI, would the mass percentage of Na in the sample be higher or lower than the pure sample? Justify your claim
Explanation:
The trick here is to realize the every sample of sodium bromide, regardless of its mass, will contain
22.34
%
sodium by mass.
This is true because sodium and bromide always combine in definite proportions, i.e. stable ratios by mass, to form sodium bromide.
Now, a
22.34
%
percent concentration by mass means that every
100 g
of sodium bromide will contain
22.34 g
of sodium and
100 g
−
22.34 g
=
77.66 g Br
Therefore, you can say that the mass ratio that exists between sodium and bromine in any sample of sodium bromide will be
22.34 g Na
77.66 g Br
=
22.34
77.66
You can thus use this definite proportion to say that a
5.69 g
sample of sodium bromide will contain
5.69
g NaBr
⋅
22.34 g Na
100
g NaBr
=
1.271 g Na
=
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
∣
∣
a
a
1.27 g Na
a
a
∣
∣
−−−−−−−−−−−−−
The answer is rounded to three sig figs.
You can use the known definite proportion to find the mass of bromide present in the sample
1.271
g NaBr
⋅
77.66 g Br
22.34
g NaBr
=
4.42 g Br
This checks out because
mass of NaBr sample
5.69 g
−
mass of Na
1.27 g
=
mass of Br
4.42 g
The answers to your questions are ;
a) The mass percentage of Na in the sample will be higher in the sample
b) The mass percentage of Na in the sample will be be lower in the sample
Given that:
Mass percentage of sodium contained in sodium Bromide = 22.34%
a) Determine if the mass percentage of Na will be higher or lower when sodium Bromide is contaminated with sodium chloride
mass percentage of Na in sodium bromide
= ( mass of Na / mass of NaBr )*100
The mass of sodium in NaBr and NaCl is the same while the mass of Br is not same ( greater than ) as the mass of Cl. hence when NaBr is contaminated with NaCl the total mass of in percentage NaBr will decrease. and This decrease in mass of NaBr will lead to a decrease/lower mass percentage of Na in the sample
b) When NaBr is contaminated with NaI
The mass of Na is the same in NaBr and NaI while the mass of I is not the same ( greater than ) as the mass of Br, therefore the total mass will increase and the increase in the Total mass in percentage will lead to an increase/higher value of Na in the given sample.
hence the mass percentage of Na will decrease when NaBr is contaminated with NaCl while the mass percentage of Na will increase when NaBr is contaminated with NaI
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which statement correctly contrasts science and psuedoscience
Answer:
The correct answer is Science is objective, whereas pseudoscience is subjective. Pseudoscience includes beliefs, theories, or practices that have been or are considered scientific, but have no basis in scientific fact. This could mean they were disproved scientifically, can't be tested or lack evidence to support them.
Explanation:
hope its help
thank you
Please help me answer this question
Answer:
d=m/v d=0.94
Explanation:
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Which of the following can be referred to as a d7 ion? * O Cu4+ o Mn 4+ O O O Ni4+ O None of the above .
Transition metals are known to have incompletely filled d- orbitals. For this reason, they are commonly referred to as the d- block. Cu4+ is a d7 ion.
An ion is formed when electrons are lost from or gained in a neutral atom.
An ion is a positively or negatively charged chemical specie. Chemical species form ions by loss or gain of electrons.
An atom is neutral if it has equal number of protons and electrons. When an atom has lost electrons, it forms a positive ion.
Copper has electronic configuration; 1s2 2s2 2p6 3s2 3p6 4s2 3d9. When four electrons are lost, its electronic configuration now becomes;
1s2 2s2 2p6 3s2 3p6 3d7.
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Element X forms the ion X22- What is the formula of the covalent compound X forms with chlorine?
A XCI
B XCl2
C XCl3
D XCl4
Answer:
the answer is mostly option a)XCl
Explanation:
Alkanes are chains of carbon atoms surrounded by hydrogen atoms. Which alkane has the weakest dispersion attractive force?
How does the electronic configuration of an element give information about the period and the group it belongs to
Answer:
Electronic configuration of an element gives the information of valence electrons and number of shell present in the element.
Explanation:
Electronic configuration of an element gives the information of valence electrons and number of shell present in the element. We get the information of group number after knowing valence electrons.
The number of shells present in an element is equal to the period number. Thus, by knowing electronic configuration we know the group number and period number of an element, and the position of an element in the periodic table.
An element's electronic configuration, which identifies both its period and group, gives important details regarding its place within the periodic table.
The major energy level (shell) where the outermost electrons are found determines the period. In the electrical arrangement, the period number corresponds to the greatest energy level. The number of valence electrons, which are the electrons at the highest energy level, which are present in an element determines its group or family. Because they have the same valence electron configurations, elements in the same group exhibit comparable chemical characteristics. In conclusion, the electronic configuration helps us comprehend an element's chemical behavior and interactions with other elements by revealing an element's period based on energy levels and its group based on valence electrons.
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