technician a says that play in the steering gear is the probable cause of a shimmy. technician b says that it could be loose steering linkage. who is correct?

To answer the question about a system that is not determinate:

1. A system is not determinate if it lacks a unique and predictable solution or outcome. This could be due to insufficient constraints, inconsistent information, or the presence of multiple solutions that satisfy the given conditions.

2. To make a non-determinate system determinate, you should add elements to the precedence relation. The precedence relation defines the order in which tasks or events must occur. By introducing new constraints or relationships between the elements, you can reduce ambiguity and ensure a unique solution or outcome. Follow these steps:

  a. Identify the elements in the system that are causing indeterminacy.
  b. Determine the necessary constraints or relationships that will provide a clear order or hierarchy among these elements.
  c. Add the new constraints or relationships to the precedence relation, ensuring that they do not contradict any existing information.
  d. Verify that the modified system now has a unique and predictable solution or outcome, making it determinate.

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Answer:

all you have to do is describe the features of it

Explanation:

just look at it pic on the right and wright down what you see

The minimum number of filters needed to treat a flow rate of 2 m³/s if the design loading rate is 200 m³/day-m²,

The key factors that must be considered when designing a filtration system are:

Flow rate - the flow rate of water passing through the filter should be determined. Water passes through a filter more quickly if it has a higher flow rate.

Loading rate - the loading rate of the filter is the volume of wastewater that is treated in a specific period. It must be calculated because it has a significant impact on the efficiency of the filter.

Filter media - The appropriate filter media should be selected depending on the impurities to be removed from the water. Sand, gravel, activated carbon, and diatomaceous earth are some of the media that can be used in a filter.

Size of the filter - A filter's size is determined by the flow rate and loading rate. The filter's surface area and depth are both important.

Length to width ratio - This ratio is important because it determines the filter's shape, which affects the uniformity of flow and filtration performance.

The minimum number of filters needed to treat a flow rate of 2 m³/s if the design loading rate is 200 m³/day-m², the maximum filter length is 10 m, and the length to width ratio is 1.25 to 1 is 4 filters.

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Answer:

periscopes, microscopes, telescopes, and cameras.

Answer:

   1. Keep it clean: Use a soft, lint-free cloth or a specialized lens cleaning cloth to clean the lenses of the optical instrument. Avoid using rough materials or paper towels as they can scratch the lenses. Also, be careful when cleaning as some lenses are coated and can be damaged if they come into contact with liquids or certain cleaning solutions.

   2. Store it properly: When not in use, store the optical instrument in a protective case or bag. This will protect it from dust, scratches, and other potential damage. Avoid leaving the instrument in direct sunlight or extreme temperatures, as this can cause the lenses to warp or crack.

   3. Handle it with care: When using the instrument, handle it with care to avoid dropping or knocking it. Many optical instruments are fragile and can be damaged easily. Be particularly careful with any moving parts or delicate mechanisms.

   4. Regular maintenance: Depending on the type of optical instrument, it may require periodic maintenance, such as calibration or alignment. Follow the manufacturer's instructions for maintenance, or consult a professional if you are unsure of how to properly maintain the instrument. Regular maintenance can help to prolong the life of the instrument and ensure that it performs accurately.

Answer:

  short circuit

Explanation:

You want to know what type of circuit fault is characterized by current bypassing all or some of the electrical load in the circuit.

When the current in a circuit follows a shorter (or lower-impedance) path than the one intended, bypassing some or all of the intended load, the circuit is said to suffer from a "short circuit."

Answer:Overflowing drains are often caused by sanitary products, paper towels or other hard to flush materials which can clog pipes and obstruct drains. Wipes, tissues, and even hair can also be the culprits

Explanation:

29,430 J of work is required to raise a mass of 500 kg to a height of 6 m in 30 seconds (Joules).

F = m 9.8 m/s2 is the formula for computing weight, where m is the object's mass in kilogrammes and N is the object's weight in Newtons (N). The SI unit for weight is the Newton, and one Newton is equal to 0.225 pounds.

work = force x distance

weight = mass x gravity

weight = 500 x 9.81

weight = 4905 N

Now, we can calculate the work done:

work = force x distance

work = weight x height

work = 4905 x 6

work = 29,430 J

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The correct answer is  I do not have access to any figure or visual representation of the building plan you mentioned. Hence, I am unable to provide an accurate calculation for the required square footage of waterproofing material.

However, I can provide you with a general idea of the steps you need to take to calculate the required square footage. Firstly, you need to determine the total perimeter of the building by adding the length of all sides together. Then, subtract the openings such as doors and windows from the total perimeter.  Next, you need to determine the height of the wall section that needs to be waterproofed. Measure the distance from the top of the wall down to the top of the footing. Once you have the total perimeter and height of the wall section, you can calculate the square footage required for waterproofing. Simply multiply the perimeter by the height of the wall section to get the total square footage. It's also important to consider any additional factors such as overlaps and waste that may affect the amount of waterproofing material needed. Always remember to add a little extra material to ensure adequate coverage and avoid running short during installation.

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The technician B is correct in this case since a turbocharger should not be operated at an engine oil pressure lower than 30 psi.

A turbocharger is a device that increases the efficiency of an engine by forcing air into it at a higher pressure. It increases the engine's power and efficiency by supplying it with additional oxygen.Turbochargers are used in both petrol and diesel engines. They are most commonly found in large diesel engines.

It is also used in motorsports, where it is used to improve engine efficiency and power output.Turbochargers are lubricated by engine oil, and most turbochargers have their lubrication system. A turbocharger cannot be operated at an engine oil pressure lower than 30 psi, which can cause damage to the engine's parts.

A turbocharger's lifespan is determined by how well it is maintained, as well as the quality of the oil being used. It is advised to keep your vehicle serviced and your oil changed regularly to keep your turbocharger running smoothly.

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The aim of the content planning process is to create a content strategy that aligns with your organization's goals and objectives. This process involves developing information and ideas through research, analysis, and creative thinking.

The process typically includes the following steps:
1. Define your audience: In this step, you need to identify the audience you want to target with your content. This can be done by analyzing your existing customer base or by conducting market research to understand the needs and interests of your target audience.
2. Set goals and objectives: You need to establish clear goals and objectives for your content marketing efforts. These goals should be specific, measurable, achievable, relevant, and time-bound (SMART). For instance, your goal may be to increase brand awareness, generate leads, or boost sales.
3. Develop a content strategy: Once you have identified your audience and set your goals, you need to develop a content strategy that will help you achieve these objectives. This involves identifying the types of content you will create, the channels you will use to distribute it, and the key messages you want to communicate.
4. Create a content calendar: A content calendar is a schedule that outlines the topics, formats, and channels you will use to distribute your content over a specified period. This helps ensure that your content is timely, relevant, and consistent.
5. Execute your plan: Once you have developed your content plan, you need to execute it by creating and publishing your content. You should also track your progress and adjust your strategy as needed to ensure that you are meeting your goals.

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Answer: To find the total real, reactive, and apparent power used by the facility, we need to calculate the power consumption of each individual load first.

Explanation:

a. The power consumed by the 50hp motor is given by:

P = (50 hp) / (0.86 × 0.70) = 83.63 kW

The reactive power consumed by the motor is given by:

Q = P × tan(cos⁻¹(0.70)) = 57.63 kVAR

b. The power consumed by the 100hp motor is given by:

P = (100 hp × 0.82) / 0.89 = 91.01 kW

The reactive power consumed by the motor is given by:

Q = P × tan(cos⁻¹(0.80)) = 54.72 kVAR

c. The power consumed by each of the two 20hp motors is given by:

P = (20 hp) / (0.92 × 0.85) = 25.08 kW

The reactive power consumed by each motor is given by:

Q = P × tan(cos⁻¹(0.85)) = 14.07 kVAR

d. The power consumed by the 300hp motor is given by:

P = (300 hp × 0.75) / 0.92 = 245.11 kW

The reactive power consumed by the motor is given by:

Q = P × tan(cos⁻¹(0.84)) = 160.89 kVAR

e. The power consumed by the incandescent lighting is given by:

P = 50 kW

The reactive power consumed by the lighting is zero, since it is a resistive load.

Now we can find the total real, reactive, and apparent power used by the facility:

Total real power = 83.63 kW + 91.01 kW + 2 × 25.08 kW + 245.11 kW + 50 kW = 529.91 kW

Total reactive power = 57.63 kVAR + 54.72 kVAR + 2 × 14.07 kVAR + 160.89 kVAR + 0 kVAR = 301.98 kVAR

Total apparent power = √(529.91² + 301.98²) = 609.57 kVA

The total power factor is given by:

cos(θ) = 529.91 kW / 609.57 kVA = 0.8691

θ = cos⁻¹(0.8691) = 29.59 degrees

Therefore, the total power factor is 0.869 lagging. The real power used by the facility is 529.91 kW, the reactive power used is 301.98 kVAR, and the apparent power is 609.57 kVA.

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Explanation:

The calculation is as follows:

The general lighting load is 10,000 VA.

The voltage used in homes is typically 120 volts.

Dividing the general lighting load by the voltage gives us the amperage: 10,000 VA / 120 volts = 83.33 amps

According to the National Electrical Code (NEC), a 15-amp branch circuit can handle a maximum of 15 amps.

To determine the number of 15-amp branch circuits required, we divide the amperage by the maximum allowed on one circuit: 83.33 amps / 15 amps = 5.55

Therefore, we need at least 6, 15-amp branch circuits to handle the general lighting load of 10,000 VA.

The answer is (D) 6.

To determine the percentage of the moment that is resisted by the web of the beam, we need to find the moment of inertia of the entire cross-section of the beam, as well as the moment of inertia of just the web. The moment of inertia of the web represents the portion of the total moment that is resisted by the web.

Assuming a rectangular beam with dimensions b (width), h (height), and t (thickness of the web), the moment of inertia of the entire cross-section can be calculated as:

I_total = (1/12) * b * h^3

The moment of inertia of just the web can be calculated as:

I_web = (1/12) * t * h^3

The moment of the applied load is 15 kip-ft. To determine the percentage of this moment that is resisted by the web, we can use the formula:

% resisted by web = (I_web / I_total) * 100%

Substituting the expressions for I_web and I_total, we get:

% resisted by web = [(1/12) * t * h^3 / (1/12) * b * h^3] * 100%

Simplifying the expression, we get:

% resisted by web = (t/b) * 100%

Therefore, the percentage of the moment that is resisted by the web of the beam is equal to the ratio of the thickness of the web to the width of the beam, multiplied by 100%.

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Here's the code that will create a 50 x 50 grid of nodes and an output function that displays the row and column of each node in the grid after it is created:

```
#include

using namespace std;

struct node {
   int row;
   int col;
   node* up;
   node* down;
   node* left;
   node* right;
};

node* createGrid() {
   // Create head node
   node* head = new node;
   head->row = 0;
   head->col = 0;
   head->up = NULL;
   head->down = NULL;
   head->left = NULL;
   head->right = NULL;

   // Create first row
   node* row1 = head;
   for (int i = 1; i <= 50; i++) {
       node* p = new node;
       p->row = 1;
       p->col = i;
       p->up = NULL;
       p->down = NULL;
       p->left = row1;
       p->right = NULL;
       row1->right = p;
       row1 = p;
   }

   // Reset row1 to head of grid
   row1 = head;

   // Create rows 2-50
   for (int i = 2; i <= 50; i++) {
       // Create first node in row and link it up/down
       node* row2 = new node;
       row2->row = i;
       row2->col = 1;
       row2->up = row1;
       row2->down = NULL;
       row2->left = NULL;
       row2->right = NULL;
       row1->down = row2;
       row1 = row2;

       // Create rest of nodes in row
       node* prev = row2;
       for (int j = 2; j <= 50; j++) {
           node* p = new node;
           p->row = i;
           p->col = j;
           p->up = prev->up->right;
           p->down = NULL;
           p->left = prev;
           p->right = NULL;
           prev->right = p;
           prev = p;
       }
   }

   return head;
}

void displayGrid(node* head) {
   node* curr = head;

   while (curr != NULL) {
       node* row = curr;
       while (row != NULL) {
           cout << "Row: " << row->row << ", Col: " << row->col << endl;
           row = row->right;
       }
       curr = curr->down;
   }
}

int main() {
   node* head = createGrid();
   displayGrid(head);

   return 0;
}
```

The `createGrid` function uses the pseudocode provided to create a 50 x 50 grid of nodes. Each node has a `row` and `col` value to track its position in the grid, as well as pointers to its up, down, left, and right neighbors.

The `displayGrid` function uses nested loops to iterate through each row and column of the grid and output the row and column values.

In the `main` function, we call `createGrid` to create the grid and store its head node in the `head` variable. Then we call `displayGrid` to output the row and column values of each node in the grid.

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a. The normal reaction force(R) is 40N

b. The value of the frictional force is 133N

c. The net force is 123.33N

d. The acceleration of the box is 2.5m/s²

Coefficient of static friction is the maximum ratio of applied force to normal force with no motion. Thus the coefficient of kinetic friction is with motion.

a. Normal reaction force= mg

where m is the mass of the object

R = 4 × 10

R = 4 × 10

R = 40N

b. coefficient of friction = normal reaction/ frictional force

frictional force = 40/0.3

= 133.33N

c. The net force= 133.33N -10N

= 123.33N

d. The acceleration of the box = f/m

= 10/4

= 2.5m/s²

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The Delivery Truck class is designed to manage a collection of Mail objects. It has a single member variable called mail_list, which is an array of length 10 that holds the Mail objects.

The load method takes a Mail object as an argument and stores it in the mail_list array at the next available spot. It does this by checking the current value of a member variable called next_available_spot, which keeps track of the index of the next available spot in the array. If there is space in the array, the Mail object is stored at the index indicated by next_available_spot, and next_available_spot is incremented. If the array is full, the load method does not add the Mail object and returns an error message or raises an exception.

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Technician B is correct. Leather gloves should be worn over the high-voltage rubber gloves when working on or near the HV circuits or components of a hybrid electric vehicle. This is because leather gloves are more durable and provide better insulation than rubber gloves rated at 1,000 volts or higher. Leather gloves can help protect the worker from shocks, cuts, and burns caused by the electric current.

The statement of Technician A and Technician B regarding the rubber gloves and leather gloves that should be worn while working on or near the HV circuits or components of a hybrid electric vehicle are both correct. Therefore, both Technician A and Technician B are correct.

How do hybrid electric vehicles work?

A hybrid electric vehicle (HEV) is a kind of car that combines an electric motor with an internal combustion engine. The goal of the electric motor is to assist the gasoline engine in driving the car while also recharging the battery. In an electric vehicle, an electric motor drives the vehicle's wheels. The electric power that propels the vehicle comes from a battery. A battery is a storage device that converts chemical energy into electrical energy. Hence, it is important that the TECNICIAN working on or near the HV circuits or components of a hybrid electric vehicle must wear rubber gloves that are rated at 1,000 volts or higher. The gloves must fit well and cover the cuffs of the sleeves so that no skin is visible. This is done in order to keep the worker safe from the high voltage electric shock.

The leather gloves, on the other hand, should be worn over the high-voltage rubber gloves.

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The given statement "an engineering notebook is used for documenting all research, proving the origin of an idea, keeping sketches in one place, and a personal calendar" is true because an engineering notebook is a type of journal or logbook used by engineers.

It is often used to track the evolution of a project or to prove the origin of a particular concept or invention. In addition to keeping sketches in one place and serving as a personal calendar, an engineering notebook is also useful for maintaining accurate records and staying organized.

An engineering notebook is a written record of an engineer's ideas, observations, designs, and experiments. It serves as a legal document that provides evidence of the engineer's work.

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Elevation drawings are side views that show height. On a building drawing there are standard names for different elevations. so Option C would be the correct answer.

An elevation drawing shows a building from one side. It is a flat, two-dimensional depiction of a single facade. It shows the heights of the development's major features in relation to a fixed point, like the actual ground level.

A building or structure's height, length, width, and appearance are all depicted in an elevation. Elevations give the viewer an idea of how the finished building will look because they are drawn as if looking at a building from the front or side (as opposed to floor plans, which are drawn looking at a building from above).

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Answer: point A[{-40i + 0j + 45k}], B[{0i + 0j + 60k}], C[{ 60i + 0j + 60k}] from there you can now find the Magnitudes then The unit vectors multiplied by the forces provided 425lb AB and 510lb AC.

Explanation:

To prevent aliasing, the anti-aliasing filter's cutoff frequency should be less than half of the sampling frequency (Nyquist frequency). Therefore, for a signal to be sampled at 1 kHz, the cutoff frequency of the anti-aliasing filter should be less than 500 Hz.

When sampling an analog signal, it is important to ensure that the resulting digital signal accurately represents the original signal. Aliasing can occur when the signal is not properly sampled, resulting in distortion or errors in the digital signal.

To prevent aliasing, an anti-aliasing filter is used to remove any frequency components above the Nyquist frequency, which is half the sampling rate. In this case, the signal is to be sampled at 1 kHz, so the Nyquist frequency is 500 Hz.

Therefore, the cutoff frequency of the anti-aliasing filter should be set at or below 500 Hz to prevent any frequency components above the Nyquist frequency from being sampled and causing aliasing. A good rule of thumb is to set the cutoff frequency at about 70% of the Nyquist frequency, so a cutoff frequency of around 350 Hz would be appropriate in this case.

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A gravitational force of 4.93 10-12 N in the positive x-direction is applied by the copper sphere to the steel sphere.

Along the line connecting the centres of the two objects, the force is applied. Coulomb's law has an undesirable effect if the two charges have opposing signs. This indicates that there is an attractive force acting on the particles.

[tex]F = G * m1 * m2 / r^2[/tex]

[tex]m = rho * (4/3) * pi * r^3[/tex]

r = 65 mm = 0.065 m

a = 3.7r = 0.241 m

b = 2.1r = 0.137 m

c = 0.6r = 0.039 m

m_copper = rho_copper [tex]* (4/3) * pi * r^3[/tex]

[tex]= 8,960 kg/m^3 * (4/3) * pi * (0.065 m)^3[/tex]

= 0.0138 kg

m_steel = rho_steel [tex]* (4/3) * pi * r^3[/tex]

= [tex]7,860 kg/m^3 * (4/3) * pi * (0.065 m)^3[/tex]

= 0.0119 kg

F = G  m_copper  m_steel / [tex]r^2[/tex]

= [tex]6.674 × 10^-11 N·(m/kg)^2 * 0.0138 kg * 0.0119 kg / (0.065 m)^2[/tex]

[tex]= 4.74 × 10^-11 N[/tex]

u = (0.241 - 0.137)i + 0j + 0k

= 0.104i + 0j + 0k

So the gravitational force F can be expressed as:

[tex]= 4.74 × 10^-11 N[/tex]

[tex]= 4.74 × 10^-11 N[/tex]

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The chemical manufacturer should choose to build 2 million units of capacity in each of the two locations, as it has a higher NPV

It should be noted that to make a decision, the chemical manufacturer needs to calculate the present value of each option over the next three years, considering the variable costs of production, exchange rate uncertainty, and discount factor.

Option 1: Building 4 million units of capacity in North America

The total variable cost of production in North America is $10/kg x 2 million kg x 3 years = $60 million. Assuming a 50% probability of a 10% strengthening of the dollar and a 50% probability of a 5% weakening of the dollar over the next three years, the expected exchange rate in three years will be 1.33 x (1 + 0.5 x 0.1 - 0.5 x 0.05) = 1.481175. The total revenue in North America will be 2 million kg x 3 years x $10/kg x 1.481175 = $88.87 million. The net present value (NPV) of building 4 million units of capacity in North America is:

NPV = -Initial investment + PV of net cash flows over three years

NPV = -4 million units x $10/kg x 1.33 + ($88.87 million - $60 million)/(1+0.1)^1 + ($88.87 million - $60 million)/(1+0.1)^2 + ($88.87 million - $60 million)/(1+0.1)^3

NPV = -$53.2 million + $22.8 million + $19.7 million + $17 million

NPV = $6.3 million

Option 2: Building 2 million units of capacity in each of the two locations

The total variable cost of production in Europe is 9 euro/kg x 1.33 x 2 million kg x 3 years = $71.85 million. The net revenue in Europe will be 2 million kg x 3 years x 9 euro/kg = 54 million euro, which is equivalent to $71.82 million at the expected exchange rate in three years. The NPV of building 2 million units of capacity in each of the two locations is:

NPV = -Initial investment + PV of net cash flows over three years

NPV = -2 million units x $10/kg x 1.33 x 2 - $2 million + ($71.82 million - $71.85 million)/(1+0.1)^1 + ($71.82 million - $71.85 million)/(1+0.1)^2 + ($71.82 million - $71.85 million)/(1+0.1)^3

NPV = -$31.92 million - $2 million + $25.46 million + $21.92 million + $18.83 million

NPV = $29.45 million

The chemical manufacturer should choose to build 2 million units of capacity in each of the two locations, as it has a higher NPV of $29.45 million compared to the NPV of $6.3 million for building 4 million units of capacity in North America.

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A safety committee is a group of staff members and management who work together to discover, assess, and control workplace risks as well as to encourage worker awareness of and adherence to safety procedures.

To help establish and maintain a safe workplace, management and employees collaborate on a safety committee. Any factory or industrial facility with 50 or more employees is required by law to have one.

Safety committees and meetings serve the objective of bringing management and employees together in a non-competitive, cooperative endeavour to advance safety and health. You may keep improving your safety and health programme by using safety committees and meetings.

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When capacitors are connected in series, the total capacitance is given by:

1/C_total = 1/C_1 + 1/C_2 + 1/C_3 + 1/C_4

Substituting the values given, we get:

1/C_total = 1/14 + 1/14 + 1/14 + 1/14
1/C_total = 4/14
C_total = 3.5 μF

Therefore, the minimum capacitance that can be obtained by connecting four 14- μf capacitors in series is 3.5 μF.

When capacitors are connected in parallel, the total capacitance is simply the sum of the individual capacitances. Therefore, the minimum capacitance that can be obtained by connecting four 14- μf capacitors in parallel is:

C_total = 4 * 14 μF
C_total = 56 μF

Therefore, the minimum capacitance that can be obtained by connecting four 14- μf capacitors is 3.5 μF in series and 56 μF in parallel.

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In most metals, the deformation brought on by the applied stress is totally recoverable up to the yield point, hence the unloading curve is parallel to the elastic component of the loading curve.

Metal wires have identical loading and unloading curves as long as their elastic limit is not exceeded. indicating that after being discharged, the wire stretches back to its initial length. The unloading line, on the other hand, is parallel to the loading line when it reaches the elastic limit.

As a rubber band is unloaded, it can stretch back to its original length. However the loading curve is always followed by the unloading curve.

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In two-position control, the area between the high and low limits where there is no change in the position of the final control element is called the Deadband.

Two-position control is the most basic kind of process control. A process is controlled by two-position control if it is possible to operate the final control element in only two positions: fully open or fully closed. It's also known as on-off control. When the process variable goes above a specific setpoint, the controller actuates the final control element to the fully open position, and when the process variable goes below a specific setpoint, the controller actuates the final control element to the fully closed position.

Deadband is the region between the upper and lower limits where the final control element doesn't move. It is a kind of threshold region that prevents the final control element from rapidly switching on and off. Deadband is frequently used to avoid oscillations, reduce system wear and tear, and extend system life. It is usually specified as a percentage of the range, and it is represented by the symbol Hysteresis in the block diagram for two-position control. The deadband also serves as a way to reduce the sensitivity of a system to fluctuations in the measurement.

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A method statement for site setup and temporary works in construction should include the following steps:

1. Identify the scope of work and establish the project requirements for site setup and temporary works. This includes the location, size, and nature of the project, as well as any specific regulatory or safety requirements.

2. Develop a detailed plan for site setup and temporary works, including timelines, resources, and responsibilities. This should include a list of all temporary works required, such as access roads, fencing, and scaffolding.

3. Identify potential hazards and risks associated with site setup and temporary works, and develop a risk assessment and mitigation plan. This should include measures to ensure the safety of workers and the public, as well as measures to protect the environment.

4. Obtain all necessary permits and approvals, including building permits, environmental permits, and safety certifications.

5. Develop a site-specific safety plan and ensure all workers are properly trained and equipped to carry out the work safely. This should include safety procedures for working at heights, using heavy equipment, and handling hazardous materials.

6. Monitor the progress of site setup and temporary works, and make adjustments as necessary to ensure the work is completed on time, within budget, and to the required quality standards.

7. Conduct regular inspections and audits to ensure that all site setup and temporary works are in compliance with regulatory and safety requirements.

8. Document all site setup and temporary works activities, including any incidents or accidents that occur, and use this information to improve future projects.

Overall, the method statement for site setup and temporary works in construction should be a detailed plan that outlines all the necessary steps, resources, and safety measures required to ensure the successful completion of the project. It should be regularly reviewed and updated as necessary to ensure that the work is carried out safely and efficiently.

A vector is a quantity or phenomenon that has two independent properties: magnitude and direction. The term also denotes the mathematical or geometrical representation of such a quantity.

It is claimed that two vectors are equal if their magnitude and direction are the same. The study of mathematics, physics, and engineering are all dependent on it. The basic ideas of vector algebra may be used to add one vector to another vector head to tail.

As follows

|v⃗ |=|v1→+v2→|

one which is held

|v| = v21 + v22 + 2 v1 v 2 cos,

angle that the two vectors make with one another. cognizant of

v22 = 144 and v21 = 81 correspondingly.

2(9)(12)cosθ=216(−7,591×10−3)=−1639,656×10−3

so that we have

144+81−1,639656=223,360344

√=14,94524486=|v⃗ |

The angle being taken

θ=(90−63)+(90−α) \s,

In order for the angle we compute to be the angle that really results, for instance, an angle where is the angle between the positive axe-y and the v1.

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