[tex]0.2(10-5c) = 5c - 16[/tex]

Solve for c,...
Thanks,...

Answers

Answer 1

We are given,

[tex] \longrightarrow 0.2(10 - 5c) = 5c - 16 [/tex]

Solving the parenthesis

[tex]{ \longrightarrow 0.2 \times 10 - 0.2 \times 5c = 5c - 16 }[/tex]

[tex]{ \longrightarrow 2 - 1c = 5c - 16 }[/tex]

[tex]{ \longrightarrow 2 + 16 = 5c + 1c }[/tex]

[tex]{ \longrightarrow 18 = 6c }[/tex]

Dividing both sides by 6

[tex]{ \longrightarrow 3 = c }[/tex]

Hence c = 3.


Related Questions

Can someone please help me I don’t get this (Due today)

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Answer:

Which grade's book exercise is this?

which numbers are equivalent to 3 tenths ? Choose all that apply. ​

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a and d (0.30 and 0.3)

>

PQ and RS are in the same plane and do not intersect. What geometric term describes PQ and RS?
perpendicular lines
complementary lines
skew lines
parallel lines

Answers

Answer:

Parallel lines

Step-by-step explanation:

Show 713.65 in expanded notation

Answers

Answer:

713.65 = (7 x 100) + (1 x 10) + (3 x 1) + (6/10) + (5/100)

Step-by-step explanation:

write the 3 terms of ( 2a+ax)^5 given the first terms in the expansion (b +2x) (2+ ax)^5 are 96 - 176x+cx^2. find the values of a,b,c

Answers

Answer:

a^5x^5, 10a^5x^4, 40a^5x^3

Step-by-step explanation:

Use pascal's triangle for the first one

(2+x)^5 * a^5

= x^5a^5 + 5*2^1*x^4*a^5 + 10*2^2*x^3*a^5 ...

= a^5x^5 + 10a^5x^4+ 40a^5x^3 ...

-6, 20, 4.3, -59/-9
Order from least to greatest

Answers

-59 -9 -6 4.3 20 there

PLEASE HELP I NEED HELP!!!!!! 30 POINTS

Figure B is a scaled copy of Figure A.
What is the scale factor from Figure A to figure B?

Answers

Answer:

1/3

Step-by-step explanation:

The left side of Figure A is 6 units long

The left side of Figure B is 2 units long

6 * what = 2

Divide each side by 6

what = 2/6

what = 1/3

The scale factor is 1/3

Answer:

[tex]\frac{1}{3}[/tex]

Step-by-step explanation:

Figure A has a base of [tex]6[/tex] units.

Figure B has a base of [tex]2[/tex] units.

So, 6 * [tex]x[/tex] (the scaled factor) = 2 which simplified is [tex]6x=2[/tex].

Now, we divide 6 on both sides giving us [tex]x = \frac{2}{6}[/tex] which can be further simplified into [tex]\frac{1}{3}[/tex]

At a charity​ fund-raiser, adult tickets were sold for ​$10 each and​ children's tickets were sold for $4 each. Write an algebraic expression for the total amount of money raised from the sale of tickets. How much money was raised if the fundraiser sold 244 adult tickets and 387 ​children's tickets?

Answers

Answer:

the all adult tickets made out 2440$

the all children tickets made out 1548

Can someone help me on this?? Im really struggling

Answers

[tex]Question \: please.[/tex]

Determine the largest integer value of xx in the solution of the following inequality.[tex]2x-2\leq 11[/tex]

Answers

Answer:

6

Step-by-step explanation:

Add 2 to both sides, then divide both sides by 2.

[tex]2x \leq 13 \\x \leq 13/2[/tex]

x is less than or equal to 13/2, So the largest value is 13/2, or 6.5. Meaning the largest integer value is 6

at a certain certain point in time the sun of an alien world is directly overhead that
world's equator

Answers

I do not understand, but I’d like the points.

Given the function g of x is equal to the quantity 2 x squared plus 3 x plus 5 end quantity over the quantity x plus 3 end quantity determine the equation for the slant asymptote.

y = –2x + 3
y = 2x + 3
y = 2x – 3
y = 2x + 9

Answers

Answer: 2x-3

Step-by-step explanation:

2x-3

---------------

X+3 /2x^2+3x+5

( - )2x^2+6x Multiply x • 2x^2

______. and subtract it from 2x^2

-3x+5. Multiply x • -3 and subtract it

(-)-3x-9 from -3x

______

14

Answer:

y=2x-3

Step-by-step explanation:

what property is being used in 2a+5a=(2+5)a

Answers

Answer:

distributive property

finish 9 and 10 (giving lots of points!!!!)

Answers

Answer:

#9

Rule for rotation 90 clockwise about the origin:

(x, y) → (y, -x)

Apply to the given points:

S(1, -4) → S'(-4, -1)W(1, 0) → W'(0, -1)J(3, -4) → J'(-4, -3)#10

Rule for rotation 180 about the origin:

(x, y) → (-x, -y)

Apply to the given points:

V(-5, -3) → V'(5, 3)A(-3, 1) → A'(3, -1)G(0, -3) → G'(0, 3)

Find the distance between the points.

(9.7, -2.1), (-3.2, 8.1)

Answers

The answer you are going to be looking for with this question is 16.4. Hope this helps you out a little :)

John's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs John $5.95 per pound, and type B coffee costs $4.65 per pound. This month's blend used three times as many pounds of type B coffee as type A, for a total cost of $656.70. How many pounds of type A coffee were used?

Answers

Answer:

Let x = the number of lbs of Type A coffee.

We know that this month's blend used 3 times as many pounds of type B coffee as type A coffee.

Total lbs of coffee = x + 3x

The total cost then is:

($ cost for Type A)(x) + ($ cost for Type B)(3x) = $717.60

$5.65x + $4.25(3x) = $717.60

$5.65x + $12.75x = $717.60

$18.40x = $717.60

x = 39 lbs

5x-4[7+(2x-4)], for x=-3

Answers

Answer:

-3

Step-by-step explanation:

Plug in x = -3

5(-3) - 4[7+(2(-3)-4)]

We'll use order of operations (PEMDAS) from here on out.

Evaluate what is in the innermost parentheses first (2(-3) - 4: the parentheses inside of the brackets). We first multiply 2 * -3, then subtract -4.

2(-3) - 4 = -6 - 4 = -10

So the whole expression becomes

5(-3) - 4[7+ -10]

Now evaluate what is in brackets.

5(-3) - 4[-3]

Multiplication next, before addition.

-15 + 12

Finally, addition

-3

Hope my answer helped u :)

write 2.5 repeating as a mixed number in simplest form.

Answers

Answer:

2 5/9

Step-by-step explanation:

2.5 repeating is 2 5/9 as a fraction (mixed number) or 23/9 (fraction)

The repeating decimal 2.5 can be written as the mixed number 2 5/9 in simplest form.

Here, we have,

To convert the repeating decimal 2.5 to a mixed number in simplest form, we can follow these steps:

Step 1:

Let's assume x = 2.5

Step 2:

Multiply both sides of the equation by 10 to shift the decimal point one place to the right: 10x = 25.5

Step 3:

Subtract the original equation from the one obtained in Step 2 to eliminate the repeating part:

10x - x = 25.5- 2.5

9x = 23 (since the repeating part subtracts to zero).

Step 4: Solve for x by dividing both sides by 9:

x = 23 / 9.

Step 5: Express the fraction 23/9 as a mixed number:

23 ÷ 9 = 2 remainder 5.

Therefore, x = 2 remainder 5/9.

so, we get,

Thus, the repeating decimal 2.5 can be written as the mixed number 2 5/9 in simplest form.

To learn more on number click:

brainly.com/question/17429689

#SPJ6

Name the pair of opposite rays with endpoint N.

Answers

Answer:

Possible Answers: NA and NX or NM and NC.

Step-by-step explanation:

PLS MARK ME BRAINLEIEST AND FLW ME

A street map uses a scale of 1 cm: 200 m.

a) Simplify this ratio.

B) Find the actual distance, in kilometres, represented by each scaled distance.
i) 7 cm
ii) 9.5 cm
iii)12.4 cm

C) Find the scaled distance, in centimetres, used to represent each actual distance,
i) 18 km
ii) 1500 m
iii) 9.6 km

Answers

Answer:

B)

1400m

1900m

2480m

C)

90cm

7.5cm

4.8cm

Add.
-1 3/4 + (-3/5) + (-1/4)
Enter your answer as a simplified mixed number in the box.

Answers

Answer:

-2 3/5

Step-by-step explanation:

that is the answer yep

Express cos9x cos3x as a sum of two trigonometry function ​

Answers

Step-by-step explanation:

the answer is in the image above

102 A marathon is 26.2 miles long. There is a water station every 1 1/4 miles along the race route. How many water stations are needed for this marathon? tills​

Answers

Answer:

21 stations

Step-by-step explanation:

1 1/4 = 5/4

26.2 / 5/4 = 20.96

rounded up to 21

Order the numbers from least to greatest.
A) 3.41%, 0.31, 0.314, 0.3333
B) 0.3333, 0.31, 0.314, 3.41%
C) 3.41%, 0.314, 0.3333, 3.51%
D) 0.31, 0.314, 0.333, 3.41%

Answers

Answer:

a) 3.41%, 0.31, 0.314, 0.3333

Find the midpoint in geometry.

Answers

(3,6)(3,-2)

[tex]\\ \rm\longmapsto (x,y)=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)[/tex]

[tex]\\ \rm\longmapsto (x,y)=\left(\dfrac{3+3}{2},\dfrac{6-2}{2}\right)[/tex]

[tex]\\ \rm\longmapsto (x,y)=\left(\dfrac{6}{2},\dfrac{4}{2}\right)[/tex]

[tex]\\ \rm\longmapsto (x,y)=(3,2)[/tex]

what is the solution to the compound inequality in interval notation​

Answers

Answer:

First choice is the right answer (-∞, -9] or (2, ∞)

Step-by-step explanation:

I. Solve 1st problem 2(2x - 1)  > 6

                 4x-2 > 6

                 4x > 6+2

                  x > 2

II. Solve 2nd problem x + 3 <=  -6

                 x <= -6-3

                 x <= -9

III. Prove the answer

         if x > 2 then x = 3

          2( 2(3)-1 ) > 6

          2(5) > 6

           10 > 6  so the answer is true

     

         if x <= -9 then x = -9

           -9 + 3 <= -6

                  -6 <= -6 so the answer is true

Hope that help :D

IXL PLEASE HELP

Ayana bought new equipment for her bowling alley, including a ball return machine. There is a 55% chance that the machine returns a bowling ball with the finger holes facing up.
If the machine returns 4 bowling balls, what is the probability that exactly 3 will have the finger holes facing up?
Write your answer as a decimal rounded to the nearest thousandth.

Answers

The answer would be .090

10-7X-5+12x=0

Explain

Answers

10-7x-5+12x=0 Combine like terms
10-5 is 5 and -7x+12x is 5x so that makes
5x+5=0 Subtract 5 from both sides
5x=-5 Divide both sides by 5
x=-1

Answer:

x = -1

Step-by-step explanation:

[tex]10 - 7x - 5 + 12x = 0[/tex]

➡️ [tex]5 - 7x + 12x = 0[/tex]

➡️ [tex]5 + 5x = 0[/tex]

➡️ [tex]5 + 5x - 5 = 0 - 5[/tex]

➡️ [tex]5x = 0 - 5[/tex]

➡️ [tex]5x = - 5[/tex]

➡️ [tex]5x \div 5 = - 5 \div 5[/tex]

➡️ [tex]x = - 5 \div 5[/tex]

➡️ [tex]x = - 1[/tex]

plzzzz help (wrong answers will be deleted )...(100 points!!)

16x^4−24x^3+3 / 4x^2+3 fill in the boxes(spaces lol) = x^2 - x - + /

Answers

[tex]\boxed{\sf \dfrac{a^m}{a^n}=a^{m-n}}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{16x^4-24x^3+3}{4x^2+3}[/tex]

Take 4x^2+3 common out

[tex]\\ \rm\Rrightarrow 4x^2+3\left(\dfrac{4x^2-24x+1}{1}\right)[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{4x^2-24x+1}{1}[/tex]

[tex]\\ \rm\Rrightarrow 4x^2-24x+1[/tex]

Answer:

4x² - 24x + 1

Step-by-step explanation:

[tex]\frac{16x^{4}-24x^{3}+3}{4x^{2}+3}[/tex]

~Factor out the denominator and apply quotient rule [ a^b / a^c = a^b-c ]

[tex]4x^{2}+3 (\frac{\frac{16}{4} x^{4-2}-24x^{3-2}+\frac{3}{3} }{1})[/tex]

[tex]\frac{4x^{2}-24x+1}{1}[/tex]

~Divide everything by 1

[tex]4x^{2} -24x+1[/tex]

Best of Luck!

When a new cellphone is put on the market, the demand each month can be described by the function C of t is equal to negative square root of the quantity t squared plus 4 times t minus 12 end quantity plus 3 where C (t) represents the demand of the cellphone (measured in millions of people) and the time, t, is measured in months. Which of the following solution(s) are valid for a positive demand?

Answers

A function is positive where it is above the x-axis

The valid solution for positive demand are; t = 3, and t = 2

The reason the above values are correct is as follows:

Known parameters:

The given function of the demand is; [tex]C(t) = \mathbf{ -\sqrt{t^2 + 4 \times t - 12} +3}[/tex]

Where;

C(t) = The demand of the cellphone (in millions of people)

t = The number of months

The condition positive demand is C(t) ≥ 0

Therefore;

[tex]-\sqrt{t^2 + 4 \times t - 12} +3 \geq 0[/tex]

[tex]-\sqrt{t^2 + 4 \times t - 12} \geq -3[/tex]

[tex]\sqrt{t^2 + 4 \times t - 12} \leq 3[/tex]

t² + 4·t - 12 ≤ 9

t² + 4·t - 12 - 9 ≤ 0

t² + 4·t - 21 ≤ 0

(t - 3) × (t + 7) ≤ 0

∴ t ≤ 3, or t ≥ -7

At t = 2 < 3, we have;

C(2) = -√(2² + 4×2 - 12) + 3 = 3

At t = 1 < 3, the function is; C(1) = -√(1² + 4×1 - 12) + 3 (Is undefined)

Therefore, the valid solution for positive demand are;

t = 3, and t = 2

Learn more about the functions here:

https://brainly.com/question/24249596

Answer:

3,3

Step-by-step explanation:

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