The car did not travel at a constant speed during the entire trip. Option d is the correct choice.
Option d is the correct answer. The graph shows that the car's velocity is not constant during the trip, indicating that the car did not travel at a constant speed. The car changes its velocity multiple times, which means it either speeds up, slows down or changes direction. Therefore, the car did not travel at a constant speed during the entire trip.
Option a is incorrect because the graph doesn't provide any information about the total time of the trip. Option b is incorrect because the graph clearly shows that the car slows down multiple times during the trip. Option c is also incorrect because the graph doesn't indicate that the car returned to its starting point.
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--The complete question is, The driver of a car completes a trip. the graph displays data about the car's motion during the trip. which of the following statements about the car's motion is true?
a. the total time for the car trip was 50 minutes.
b. the car did not slow down during the trip.
c. the car returned to where it had started the trip at the end of the trip.
d. the car did not travel at a constant speed during the entire trip.--
There is a spinner with 15 equal areas, numbered 1 through 15. If the spinner is spun one time, what is the probability that the result is a multiple of 4 or a multiple of 6?
Answer:
To solve this problem, we need to first find the numbers that are multiples of 4 or 6 between 1 and 15, inclusive.
Multiples of 4: 4, 8, 12
Multiples of 6: 6, 12
The number 12 is a multiple of both 4 and 6, so we only count it once.
So, there are a total of 4 possible outcomes that meet the condition of being a multiple of 4 or 6.
Therefore, the probability of getting a multiple of 4 or 6 is:
P(multiple of 4 or 6) = 4/15
Answer: 4/15.
Hope This Helps!
The Russell family just bought 6 crates of eggs, and each crate had 12 eggs. The family already had 9 eggs in their refrigerator. How many eggs do they have now?
Answer:
81 eggs
Step-by-step explanation:
already had 9 eggs
6 crates x 12 eggs in each crate
= 72 eggs
72+9=81
Y=-x+1
Y= 2/3x-4
How many solutions does it have?
Answer:
x = -5
Y = -22/3
Step-by-step explanation:
Y= 2/3x - 4 Y = -x + 1
We put -x + 1 in for y to solve for x
-x + 1 = 2/3x - 4
-5/3x + 1 = -4
-5/3x = -5
x = -5
Now put -5 in for x and solve for y
Y= 2/3(-5) - 4
Y = -10/3 - 4
Y = -22/3
So, there are only one solution x = -5 and y = -22/3
Find the height of the basketball hoop
Answer: 13.51 (not in inches format)
Step-by-step explanation:
tan(x) = 4.384/12
x = tan^-1 (4.384/12)
x = 20.068°
tan(20.068) = y/(12+25)
tan(20.068) = y/37
20.068 = tan^-1 (y/37)
y = 13.51
Answer:
Step-by-step explanation:
To solve this with similar triangles - you need to set up a proportion.
I changed it all to inches.
12 ft = 144 in
4.384 ft = 51. 84 inches
12 + 25 (you need to add the base of the triangle) = 37 ft = 444 inches
set up smaller triangle in proportion to bigger triangle
51.84"/144" = x/444
cross mulitply then divide
51.84 times 444 = 23016.96
23016.96 ÷ 144 = 159.84 inches
Change back to feet by dividing by 12
159.84 ÷ 12 = 13.32 ft
the test scores for the students in two classes are summarized in these box plots. the 17 students in class 1 each earned a different score.the 13 students in class 2 each earned a different score.what is the difference between the number of students who earned a score of 90 or less in class 2 and the number of students who earned less than 75 in class 1?the test scores for the students in two classes are summarized in these box plots. the 17 students in class 1 each earned a different score.the 13 students in class 2 each earned a different score.what is the difference between the number of students who earned a score of 90 or less in class 2 and the number of students who earned less than 75 in class 1?
The number of students who earned a score of 90 or less in class 2 is 7, and the number of students who earned less than 75 in class 1 is 3. The difference between the two is 4.
The given problem presents two box plots representing the test scores for two different classes. Class 1 has 17 students, while class 2 has 13 students. It is required to find the difference between the number of students who earned a score of 90 or less in class 2 and the number of students who earned less than 75 in class 1.
By analyzing the box plots, we can see that 7 students in class 2 earned a score of 90 or less, while only 3 students in class 1 earned less than 75. Therefore, the difference between the two is 4. It is important to understand box plots and their interpretation to solve such problems.
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Find the area and perimeter 20 12
. Explain how to convert a measurement of 165 in to a measurement in yards, feet, and inches.
Answer:
Step-by-step explanation:
write down a polynomial of degree exactly 5 that interpolates the four points (1, 1), (2, 3), (3, 3), (4, 4).
The required polynomial of exact degree 5 which interpolates the four given points is equals to p(x) = x^3/2 -4x^2 + 63x/6 -6.
Polynomial of degree exactly 5 that interpolates the four points (1, 1), (2, 3), (3, 3), (4, 4).
Apply Lagrange interpolation.
Standard form of the Lagrange interpolation polynomial of degree n passing through n+1 distinct points (x0, y0), (x1, y1), ..., (xn, yn) is,
L(x) = Σ [yi × Π (x - xj) / (xi - xj)], for i = 0, 1, ..., n
where Π is the product operator and j takes all values different from i.
For the given four points, we have n = 3, so the polynomial has degree n+1 = 4.
Using the formula, we have,
L(x) = (1× (x - 2)(x - 3)(x - 4) / ((1 - 2)(1 - 3)(1 - 4)))
+ (3× (x - 1)(x - 3)(x - 4) / ((2 - 1)(2 - 3)(2 - 4)))
+ (3× (x - 1)(x - 2)(x - 4) / ((3 - 1)(3 - 2)(3 - 4)))
+ (4× (x - 1)(x - 2)(x - 3) / ((4 - 1)(4 - 2)(4 - 3)))
Simplifying this expression, we get,
⇒L(x) = (-x^3 + 9x^2 - 26x + 24)/6 + (3x^3/2 - 12x^2 + 57x/2 - 18) +(-3x^3/2 + 21x^2 /2- 21x + 12) + (2x^3/3 - 4x^2 + 22x/3 - 4)
⇒L(x) = x^3/2 -4x^2 + 63x/6 -6
Therefore, the polynomial of degree exactly 5 that interpolates the four points (1, 1), (2, 3), (3, 3), (4, 4) is p(x) = x^3/2 -4x^2 + 63x/6 -6.
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5. Heidi's family is trying to decide on the shorter
of two routes for a trip from Georgetown to
Cypress City. One route begins in Georgetown
and goes 53 miles to Cycle City, then 28 miles
to Aspen and 98 miles to Cypress City. The
second route also begins in Georgetown and
goes 28 miles to Canon City, then 49 miles to
Grover and 85 miles to Cypress City. Which
route is shorter and by how much?
Answer: We can find the total distance of the first route by adding the individual distances:
53 + 28 + 98 = 179 miles
Similarly, we can find the total distance of the second route:
28 + 49 + 85 = 162 miles
Therefore, the second route is shorter by (179 - 162) = 17 miles.
Step-by-step explanation:
what is the average voter turnout during an election? a random sample of 38 cities was asked to report the percent of registered voters who actually voted in the most recent election.
A random sample of 38 cities was asked to report their voter turnout percentages, which can be used to estimate the average voter turnout in those cities. However, caution should be taken when making generalizations about the larger population of cities, since the sample size is relatively small.
The average voter turnout during an election can be calculated by taking the percentage of registered voters who actually voted in a sample of cities and finding the mean. In this case, a random sample of 38 cities was asked to report the percent of registered voters who voted in the most recent election. To calculate the average voter turnout, follow these steps:
1. Obtain the reported voter turnout percentages from each of the 38 cities in the random sample.
2. Add up all the percentages of voter turnout from the 38 cities.
3. Divide the sum of voter turnout percentages by the number of cities (38) to find the average voter turnout.
By following these steps, you will find the average voter turnout for the most recent election, based on the random sample of 38 cities. Keep in mind that the average voter turnout can vary depending on the election and location, as factors such as political climate, awareness, and accessibility can impact voter participation. This calculated average represents an estimation of the overall turnout and may not be completely representative of the entire population, but it provides a useful measure to understand voter engagement during elections.
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a candy distributor needs to mix a 10% fat-content chocolate with a 50% fat-content chocolate to create 100 kilograms of a 14% fat-content chocolate. how many kilograms of each kind of chocolate must they use?
The candy distributor needs to use 30 kilograms of 10% fat-content chocolate and 70 kilograms of 50% fat-content chocolate to create 100 kilograms of a 14% fat-content chocolate.
To solve this problem, we can use the method of mixture problems, which involves setting up a system of equations. Let x be the number of kilograms of the 10% fat-content chocolate and y be the number of kilograms of the 50% fat-content chocolate.
We have two equations based on the fat content and the total weight of the mixture:
0.1x + 0.5y = 0.14(100) (equation for fat content)
x + y = 100 (equation for total weight)
We can solve this system of equations using substitution or elimination. Using substitution, we can solve for x in terms of y from the second equation and substitute it into the first equation:
x = 100 - y
0.1(100 - y) + 0.5y = 0.14(100)
10 - 0.1y + 0.5y = 14
0.4y = 4
y = 10
Then we can substitute y = 10 back into the equation for x and get:
x = 100 - y = 100 - 10 = 90
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The preimage shown below is dilated by a scale factor of 1/4 about the point (2,2). If the distance from the center of dilation to point A is 5.7 units, what is the distance from the center of dilation to point A'.
Round your answer to the nearest tenth please :)))
For given dilation of the figure, the distance from the center of dilation to point A' is approximately 1.414 units.
What exactly is dilation in mathematics?
In mathematics, dilation is a transformation that changes the size of a figure but not its shape. It is also known as scaling, enlargement, or reduction.
To perform a dilation, a figure is multiplied or divided by a scale factor, which is a positive number greater than zero. If the scale factor is greater than 1, the figure is enlarged, while if it is less than 1, the figure is reduced. If the scale factor is equal to 1, the figure remains the same size.
Now,
To find the distance from the center of dilation to point A', we need to use the fact that the distance between the center of dilation and any point on the preimage is multiplied by the scale factor to get the corresponding distance on the image.
First, let's find the distance from the center of dilation to point A:
distance from center to A = √((6-2)² + (-2-2)²) = √(4² + (-4)²) = √32 ≈ 5.657 units (rounded to three decimal places)
Next, we can use the fact that the scale factor is 1/4 to find the distance from the center of dilation to point A':
distance from center to A' = (scale factor) x (distance from center to A)
= (1/4) x 5.657
= 1.414 units (rounded to three decimal places)
Therefore, the distance from the center of dilation to point A' is approximately 1.414 units.
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HELP have no idea how to do this
Answer:
use SSS
Step-by-step explanation:
Given two congruent chords AB and BC in circle O, you want to prove ∆AOB is congruent to ∆COB.
Statement . . . . Reason1. circle O, AB≅BC . . . . given
2. OB ≅ OB . . . . reflexive property of congruence
3. OA ≅ OC . . . . definition of a circle
4. ∆AOB ≅ ∆COB . . . . SSS postulate
__
Additional comment
Your erased statement 2 shows you know exactly how to do this.
All the radii of a circle are the same length, so it is easy to show congruence by SSS, given that AB≅BC.
19 3/5 × 20 2/5 secial product patterns to find the product
Answer: 19 3/5 x 20 2/5 = 9996/25 = 399 21/25
Given circle E with diameter CD and radius EA. AB is tangent to E at A. If AC = 9 and AD = 4, solve for CD. Round your answer to the nearest tenth if necessary. If the answer cannot be determined, click "Cannot be determined."
Since AB is tangent to circle E at A, we know that angle CAB is a right angle (tangent is perpendicular to the radius at the point of tangency). Therefore, triangle ADC is a right triangle.
Let's use the Pythagorean theorem to find the length of CE:
CE^2 = AC^2 + AE^2 (using Pythagorean theorem in triangle ACE)
CE^2 = 9^2 + EA^2 (since AE = EA, by definition of radius)
CE^2 = 81 + EA^2
We still need to find EA. Let's use the fact that EA is half the length of CD:
EA = CD/2
Now we can substitute this expression into the previous equation:
CE^2 = 81 + (CD/2)^2
CE^2 = 81 + CD^2/4
Next, let's use the Pythagorean theorem in triangle ADC:
AD^2 + DC^2 = AC^2
4^2 + DC^2 = 9^2
DC^2 = 9^2 - 4^2
DC^2 = 65
Now we can substitute this expression into the previous equation:
CE^2 = 81 + 65/4
CE^2 = 99.25
Taking the square root of both sides, we get:
CE ≈ 9.96
Therefore, CD = 2CE ≈ 19.9.
Answer: CD ≈ 19.9
(Using trig to find an angle)
Solve for x. Round to the nearest tenth of a degree, if necessary.
Angle B is approximately 53.15 degrees using trigonometry.
EquationsWe can use trigonometry to solve for angle B in the right triangle BCD. We know that angle CBC is 37 degrees, and BD is 64.
First, we can use the Pythagorean theorem to find the length of BC, which is the hypotenuse of the right triangle:
[tex]BC^{2}[/tex] = [tex]BD^{2}+CD^{2}[/tex]
[tex]BC^{2}[/tex] = 64² + [tex]CD^{2}[/tex]
Since CD is opposite angle B, we can use trigonometry to relate CD to angle B. Specifically, we can use the tangent function:
tan(B) = CD/BD
Rearranging, we have:
CD = BDxtan(B)
Taking the square root of both sides, we have:
BC = 64[tex]\sqrt{(1+tan^{2}B)}[/tex]
Now we can use the fact that BC is the hypotenuse of the right triangle to relate it to angle CBC, which is 37 degrees. Specifically, we can use the sine function:
sin(CBC) = BD/BC
Substituting our expression for BC, we have:
sin(37) = 64/64√(1 + tan²(B))
Simplifying, we get:
sin(37) = 1/[tex]\sqrt{(1+tan^{2}B)}[/tex]
Squaring both sides, we have:
sin²(37) = 1/[tex](1+tan^{2}B)}[/tex]
Substituting the identity cos²(θ) + sin²(θ) = 1, we have:
cos²(37) = cos²(B)
Taking the square root of both sides, we have:
cos(37) = ±cos(B)
Since angle B is acute (it is less than 90 degrees because it is in a right triangle), we know that cos(B) is positive. Therefore, we can take the positive square root:
cos(B) = cos(37)
B = 53.15 degrees (rounded to two decimal places)
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If a stone is thrown upward with a speed of 110 feet per second from a height of 500 feet above the surface of a planet, the equation h = 500 + 110t - 5.5t² approximates the height of the stone, in feet, at t seconds. When will the stone be 698 feet above the planet's surface?
We can solve for the time when the stone will be 698 feet above the planet's surface by setting h = 698 and solving for t in the equation h = 500 + 110t - 5.5t²:
698 = 500 + 110t - 5.5t²
Rearranging, we get:
5.5t² - 110t + 198 = 0
Dividing both sides by 5.5, we get:
t² - 20t + 36 = 0
This is a quadratic equation that we can solve using the quadratic formula:
t = (-(-20) ± sqrt((-20)² - 4(1)(36))) / (2(1))
Simplifying, we get:
t = (20 ± sqrt(64)) / 2
t = 10 ± 4
So the possible values of t are t = 14 or t = 6. We can check which value is correct by plugging each value into the original equation and seeing if it gives a height of 698:
When t = 14:
h = 500 + 110(14) - 5.5(14)²
h = 500 + 1540 - 1078
h = 962
When t = 6:
h = 500 + 110(6) - 5.5(6)²
h = 500 + 660 - 198
h = 962
So both values of t give a height of 698. Therefore, the stone will be 698 feet above the planet's surface at t = 6 seconds or t = 14 seconds.
One of the sides of a parallelogram has the length
of 5 in. Can the lengths of the diagonals be
4 in. and 6 in.?
Answer:
Yes they can.
The only time they would have to be different lengths is if it was a square
Identify the slope and y-intercept of the following equations:
a. y = 4x + 1
b. y = x - 2
c. y = 1/3x
It'd be so helpful if even one of these were answered. Thank you!
Therefore, the slope is 1/3 and the y-intercept is 0.
a. The equation is in slope-intercept form, y = mx + b, where m is the slope and b are the y-intercept. In this case, the slope is 4, and the y-intercept is 1. Therefore, the slope is 4 and the y-intercept is 1.
b. This equation is also in slope-intercept form, y = mx + b, where m is the slope and b are the y-intercept. In this case, the slope is 1, and the y-intercept is -2. Therefore, the slope is 1 and the y-intercept is -2.
c. This equation is already in slope-intercept form, y = mx + b, where m is the slope and b are the y-intercept. In this case, the slope is 1/3, and the y-intercept is 0 (since there is no constant term). Therefore, the slope is 1/3 and the y-intercept is 0.
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URGENT PLEASE HELP ME !!!!!!
What are the coordinates of the point on the directed line segment from (-10,10) to (2,-8) that partitions the segment into a ratio of 2 to 1?
The coordinate of the segment in the ratio is (-2,-2).
What is ratio?
When two numbers are compared, the ratio between them shows how often the first number contains the second. As an illustration, the ratio of oranges to lemons in a dish of fruit is 8:6 if there are 8 oranges and 6 lemons present.
Partitions the line segment in the ratio A to B... then,
=> x-coordinate is : x1 +[tex]\frac{ A(x2-x1)}{(A+B)}[/tex]
=> y-coordinate is: y1 + [tex]\frac{A(y2-y1)}{(A+B)}[/tex]
Here A = 2 , B = 1 and [tex](x_1,y_1)=(-10,10)[/tex] , [tex](x_2,y_2)=(2,-8)[/tex] .
x-coordinate = -10+[tex]\frac{2(2+10)}{(2+1)}[/tex] = -10 + [tex]\frac{2(12)}{3}[/tex] = -10 + 2(4) = -10+8 = -2
y-coordinate = 10+[tex]\frac{2(-8-10)}{(2+1)}=10+\frac{2(-18)}{3}[/tex] = 10+2(-6) = 10-12 = -2.
Hence the coordinate of the segment in the ratio is (-2,-2).
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Find the measures of each exterior angle of a regular 66-gon, the round to the nearest tenth.
Angles: 5.4,6.4,173.6,9720
The correct angle measure in degrees for each exterior angle is 5.5. The other values provided in the question, 6.4, 173.6, and 9720, are not relevant to the problem.
What is Exterior angles ?
In a polygon, an exterior angle is an angle formed by a side and an extension of an adjacent side. The measure of an exterior angle of a regular polygon with n sides is given by 360/n degrees.
To find the measure of each exterior angle of a regular polygon, we use the formula:
Measure of each exterior angle = 360 degrees / number of sides
In this case, the polygon is a regular 66-gon, so the number of sides is 66. Thus,
Measure of each exterior angle = 360 degrees / 66 = 5.454545...
Rounding to the nearest tenth, we get:
Measure of each exterior angle ≈ 5.5 degrees
Therefore, the correct angle measure in degrees for each exterior angle is 5.5. The other values provided in the question, 6.4, 173.6, and 9720, are not relevant to the problem.
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Mary invests $200 in a high-interest savings account. In the first year, the value of her savings increases by 8%. In the second year, there is a further increase of 8%. What is the total value of her investment after two years? Round your answer to the nearest dollar.
The total value of Mary's investment after two years is $233.
Your father uses text messaging to communicate with his employees. If he sends an average of 17 text messages each day, how many more text messages does he send than you? Write an equation that contains the unknown value, x, and solve for the unknown value
HURRY THIS IS A PROJECT QUESTION
17-x
Because he sends more than you we subtract your value,x,from his 17,mostly because we are unaware of the number of texts you send.Which means 17 minus x will give you the amount of texts he sends more.
The cost of a pair of boots was $84 the sales tax rate is 5% of the purchase what is the sales tax 
Answer: $4.20
Step-by-step explanation:
To answer this question, we will find 5% of $84.
First, a percent divided by 100 becomes a decimal.
5% / 100 = 0.05
Next, we are finding 5% of $84. In mathematics, "of" means multiplication.
0.05 * $84 = $4.20
Rachel has a large pond on her property. The pond contains many different kinds of fish including bass. She knows that the population of the bass is increasing exponentially each year at a rate of 4.8%. She also knows that there are currently between 250 and 275 bass in the pond.
If P represents the actual population of the bass in the pond and t represents the elapsed time in years, then which of the following systems of inequalities can be used to determine the possible number of bass in the pond over time?
The inequalities that can be used to determine the possible number of bass in the pond over time are:
[tex]P > =250e^{0.048t} , P < =275e^{0.048t}.[/tex]
Rachel has a large pond on her property. The pond contains many different kinds of fish including bass. She knows that the population of bass is increasing exponentially each year at a rate of 4.8%. She also knows that there are currently between 250 and 275 basses in the pond.
Inequalities
Given:
r=4.8/100=0.048
Initial amount:
Lower end=250
Upper end=275
Using this equation to determine the inequalities
A=p×e^rt
Where:
A=Amount
P=Population
r=Growth rate
t=Time
Let's plug in the formula
Inequalities:
[tex]P > =250e^{0.048t}P < =275e^{0.048t}[/tex]
Therefore the inequalities are : [tex]P > =250e^{0.048t} , P < =275e^{0.048t}.[/tex]
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est.
nas
ge
5. In a survey, of the students at one
25
school said they wanted to become
doctors and 16% of the students
at
the same school said they wanted to
become teachers. The rest of the
students were undecided. Which of
the following represents the students
who were undecided?
Percentage of students who were undecided is 59% of the students were undecided about their future careers.
what is Percentage?
A percentage is a fraction or ratio expressed as a fraction of 100. It is a way of expressing a part of a whole as a proportion of the whole. It is denoted by the symbol '%'. For example, if there are 100 students in a class and 20 of them are girls, then the percentage of girls in the class is 20%.
In the given question,
To solve the problem, we need to first find out the percentage of students who were undecided. We know that 25% of the students wanted to become doctors and 16% wanted to become teachers. The percentage of students who were undecided can be found by subtracting the sum of the percentages of those who wanted to become doctors and teachers from 100%:
Percentage of students who were undecided = 100% - (25% + 16%) = 59%
Therefore, 59% of the students were undecided about their future careers.
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I need help, I wasn't in school for 2 weeks because of vacation and nobody is helping me in class!
(a) Since M is the midpoint of DE, we have ME = (1/2)b.
Also, CXE is a straight line, so C, X, and E are collinear.
Therefore, we have CX + XE = CE, or a - b + FE = b + (2a - b), which simplifies to FE = a.
(b) n = a/b - 1.
How do we calculate?X is the point on FM such that
FX:XM =n:1,
we have FX = nX and XM = X.
Since M is the midpoint of DE, we have ME = (1/2)b,
so that DX = DE - EX = b - (n + 1)X.
Using the fact that CXE is a straight line,
we have CX + XE = CE, or a - b + FE = b + (2a - b),
which simplifies to FE = a.
Therefore, we have FX + FE = AX, or nX + a = a + b + (n + 1)X.
Simplifying, we get b = (n + 1)X - nX = X.
We know that DX = b - (n + 1)X = 0, so X = b/(n + 1).
Therefore, we have n/(n + 1) = FX/X = (a-b)/b.
Calculating for n, we have n = a/b - 1.
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you have 40 scarves and 55 hats to make identical donation bags. you make the greatest amount of donation bags with no clothing left over. how many scarves and hats are in each donation bag?
To create identical donation bags, you will need 55 hats and 40 scarves. You produce the most donation bags without any extra apparel. Each donation package contains 11 hats and 8 scarves.
To make the greatest amount of donation bags with no clothing left over, we need to find the greatest common factor (GCF) of 40 and 55. We can do this by finding the prime factors of both numbers:
[tex]40 = 2 * 2 * 2 * 5[/tex]
55 = 5 x 11
The GCF is the product of the common prime factors, which is 5. This means we can make 5 identical donation bags.
To find out how many scarves and hats are in each donation bag, we can divide the total number of scarves and hats by the number of donation bags:
Number of scarves per bag = 40 / 5 = 8 scarves
Number of hats per bag = 55 / 5 = 11 hats
Therefore, each donation bag will contain 8 scarves and 11 hats.
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Find an for each geometric sequence.
a₁= 3r= 1/10 n=8
O a. 3
Ob. 2 4/10
Oc.
3
10,000,000
Od. 2 1/10
The geometric sequence for the value of a₁= 3 r= 1/10 n=8 is [tex]a_{8} = \frac{3}{10000000}[/tex] i.e option c is correct.
What does the term "geometric sequence" mean?
A geometric sequence is a set of integers where the ratio between each pair of succeeding terms is fixed. The geometric sequence's general ratio is the name of this constant.
We can use the following algorithm to determine the nth term (an) of a geometric sequence:
[tex]a_{n} = a_{1} * r^{n-1}[/tex]
where a1 is the first term in the series, r represents the common ratio, and n denotes the term's number.
Since a1 = 3, r = 1/10, and n = 8, we get:
[tex]a_{8} = 3 * (\frac{1}{10})^{8-1} = 3 *( \frac{1}{10})^{7}[/tex]
[tex]= 3 * \frac{1}{10^{7} }[/tex]
Now, we can condense this equation to get the solution:
a₈ = [tex]\frac{3}{10000000}[/tex]
The solution is therefore [tex]\frac{3}{10000000}[/tex] that option c.
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If Triangle CFE is congruent to triangle PTR, Complete each of the following statements.
(37 points)
"Triangle CFE is congruent to triangle PTR" is true.
If Triangle CFE is congruent to triangle PTR, we can make the following statements:
The corresponding sides of the triangles are congruent:
This means that CF = PT, FE = TR, and CE = PR.
The corresponding angles of the triangles are congruent:
This means that angle CFE is congruent to angle PTR, angle FCE is congruent to angle PRT, and angle ECF is congruent to angle TPR.
The triangles are equal in area: Since the triangles are congruent, they have the same shape and size. Therefore, they will have the same area.
The triangles can be superimposed on each other: This means that we can place triangle CFE on top of triangle PTR in such a way that their corresponding sides and angles overlap.
If we know the measurements of the sides and angles of one triangle, we can find the measurements of the sides and angles of the other triangle: Since the triangles are congruent, we know that their corresponding sides and angles are equal.
Therefore, if we know the measurements of the sides and angles of one triangle, we can find the measurements of the sides and angles of the other triangle by using the congruence criteria.
In conclusion, if Triangle CFE is congruent to triangle PTR, we can make several statements about their corresponding sides and angles, their areas, and their ability to be superimposed on each other.
We can also use the congruence criteria to find the measurements of the sides and angles of one triangle if we know the measurements of the sides and angles of the other triangle.
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