Using the concepts of relative minimum and relative maximum, it is found that a relative minimum is most likely to occur between 1 and 3.
--------------------------------------------
A relative minimum occurs when the function is decreasing, then it starts to increase.A relative maximum occurs when the function is increasing, then it starts to decrease.--------------------------------------------
Over the interval -2 and 0, the function is increasing the whole time, which means that a relative minimum is not likely to occur.Over the interval -1 and 1, the function is increasing, then it starts to decrease, which means that a relative maximum is likely to occur.Over the interval 0 and 2, the function is decreasing the whole time, which means that a relative minimum is not likely to occur.Over the interval 1 and 3, the function is decreasing, then it starts to increase, which means that a relative minimum is likely to occur. This is the correct option.A similar problem is given at https://brainly.com/question/9839310
Answer:
x | -2 | -1 | 0 | 1 | 2 | 3
g(x) |-14| -2 | 0 |-4| -6| 2
Between which two values would a relative minimum most likely occur?
-2 and 0
-1 and 1
0 and 2
1 and 3
the correct answer is 1 and 3
There are 12 girls and 14 boys in class today. What is the ratio of girls
to boys? whats the answer
Answer:
12:14
Step-by-step explanation:
185 for 4 tickets whats the price per ticket
what is the arithmetic sequence of a1=228 n=28 sn=2982
Answer:
use the formula sn= n(a1+an)/2
Step-by-step explanation:
2982=28(228+an)/2
5964=28(228+an)
5964/28=228+an
213=228+an
an=-15(last term)
to find difference use formula
an = a+(n-1)d
-15=228+(28-1)d
-243=27d
d=-243/27
d=-9
arithmetic sequence can be found be keep on subtracting 9 from 228
hence the arithmetic sequence is
228, 219, 210, 201, 192, 183, 174........-15
(01.02 MC)
The distance, d(t), in feet, a bug has traveled is shown in the graph.
A coordinate plane with a function d of t consisting of a line starting at 0 comma 1 rising to 1 comma 2, a horizontal line from 1 comma 2 to 2 comma 2, a line falling from 2 comma 2 to 3 comma 1, and a line falling from 3 comma 1 to 6 comma 0.
Estimate the rate of change in the distance of the bug at time t = 4 seconds.
negative one third ft/s
the limit as t approaches 4 of the function d of t feet per second
d(4) ft/s
0.7 ft/s
When we have a given function f(x), the rate of change in a given value x₀ is given by:
[tex]\frac{df(x_0)}{dx} = \lim_{h \to 0} \frac{f(x_0 + h) - f(x_0)}{h}[/tex]
We will find that the rate of change at t = 4s is:
r = -1/3
Now we can't do this if we do not have the function and we only have a text description of the graph, but what we can do is find the average rate of change.
For a function f(x), the average rate of change in an interval (a, b) such that a < b is given by:
[tex]r = \frac{f(b) - f(a)}{b - a}[/tex]
Something really nice is that the average rate of change is equal to the exact rate of change if f(x) is a linear equation.
If we want to find the rate of change at t = 4, then we need to find the smallest interval that contains t = 4.
Here we know that the graph passes through the points:
(3,1) to (6, 0)
Because of the statement "a line falling from (3, 1) to (6, 0)" we know that in this segment we have a line, which implies that the average rate of change will be equal to the exact rate of change.
Using the equation of the average rate of change we get:
[tex]r = \frac{d(6) - d(3)}{6 - 3} = \frac{0 - 1}{3} = - 1/3[/tex]
Then the rate of change in the distance at the time t = 4s is -1/3.
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1.6 lbs. = __ gal
how many gallons are in 1.6lbs?
Solve for a: 7a = 63
Answer:
a = 9
Step-by-step explanation:
7a = 63
Divide 7 on both sides,
=> 7a/7 = 63/7
=> a = 9
Find the equation of a line that contains the points (3,7) and (-6, 4). Write the equation in slope-intercept form, using
fractions when required.
Answer:
[tex]y=\frac{1}{3} x+6[/tex]
Step-by-step explanation:
[tex](3,7)(-6,4)[/tex]
Step 1. Find the slope (by using the slope-formula)
m = slope
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m=\frac{4-7}{-6-3}[/tex]
[tex]m=\frac{-3}{-9}[/tex]
[tex]m=\frac{3}{9}[/tex]
[tex]m=\frac{1}{3}[/tex]
Step 2. Write the equation (using the slope and the points)
Here's how to do it:
Slope-intercept Formula [tex]y=mx+b[/tex] whrere m = slope and b = y-intercept
Plug in the slope into the Slope-intercept Formula
[tex]y=\frac{1}{3} x+b[/tex]
Find the y-intercept (b) by using a point and substituting their x and y values
[tex]y=\frac{1}{3} x+b[/tex]
Point: (3, 7)
[tex]7=\frac{1}{3} (3)+b[/tex]
[tex]7=1+b[/tex]
[tex]b=7-1[/tex]
[tex]b=6[/tex]
Step 3. Write the equation in Slope-intercept form
[tex]y=mx+b[/tex]
[tex]y=\frac{1}{3} x+6[/tex]
Find the area of the shaded region.
Step-by-step explanation:
find the area of the big semicircle and the small semicircle.minus the area of the small semicircle from the big semicircle.
now find the area of the other semicircle on top of the big semicircle.
add your results
area of semicircle=1/2(pir^2)
write 45 as a product of prime numbers
Answer:
3²×5
Step-by-step explanation:
Product of its prime numbers its more like having the number in its simplest form by factorising it
The One-to-One Property of natural logarithms states that if ln x = ln y, then _____
Answer:
x=y
Step-by-step explanation:
There is exactly one value of x for a value of the function by the one-to-one property.
help pls, i dont get this :(
Answer:b. a deposit of $278 followed by a withdrawal of $278
Step-by-step explanation:
use a calculator
10 employees only eat
vegetables and 25 employees
eat meat. What is the ratio of
the employees who only eat
vegetables to employees who
eat meat?
let x^4+y^4=16 and consider y as a function of x. use the implicit differentiation to find y"
Answer:
[tex] \frac{dy}{dx} = - \frac{ {x}^{3} }{ {y}^{3} } [/tex]
Step-by-step explanation:
Differentiate both sides of the equation (consider y as a function of x).
[tex] \frac{d}{dx} ( {x}^{4} + {y}^{4} (x)) = \frac{d}{dx} (16)[/tex]
the derivative of a sum/difference is the sum/difference of derivatives.
[tex]( \frac{d}{dx} ( {x}^{4} + {y}^{4} (x))[/tex]
[tex] = ( \frac{d}{dx} ( {x}^{4} ) + \frac{d}{dx} ( {y}^{4} (x)))[/tex]
the function of y^4(x) is the composition of f(g(x)) of the two functions.
the chain rule:
[tex] \frac{d}{dx} (f(g(x))) = \frac{d}{du} (f(u)) \frac{d}{dx} (g(x))[/tex]
[tex] = ( \frac{d}{du} ( {u}^{4} ) \frac{d}{dx} (y(x))) + \frac{d}{dx} ( {x}^{4} )[/tex]
apply the power rule:
[tex](4 {u}^{3} ) \frac{d}{dx} (y(x)) + \frac{d}{dx} ( {x}^{4} )[/tex]
return to the old variable:
[tex]4(y(x) {)}^{3} \frac{d}{dx} (y(x)) + \frac{d}{dx} ( {x}^{4} )[/tex]
apply the power rule once again:
[tex]4 {y}^{3} (x) \frac{d}{dx} (y(x)) + (4 {x}^{3} )[/tex]
simplify:
[tex]4 {x}^{3} + 4 {y}^{3} (x) \frac{d}{dx} (y(x))[/tex]
[tex] = 4( {x}^{3} + {y}^{3} (x) \frac{d}{dx} (y(x)))[/tex]
[tex] = \frac{d}{dx} ( {x}^{4} + {y}^{4} ))[/tex]
[tex] = 4( {x}^{3} + {y}^{3} (x) \frac{d}{dx}(y(x))) [/tex]
differentiate the equation:
[tex]( \frac{d}{dx} (16)) = (0)[/tex]
[tex] = \frac{d}{dx} (16) = 0[/tex]
derivative:
[tex]4 {x}^{3} + 4 {y}^{3} \frac{dy}{dx} = 0[/tex]
[tex] \frac{dy}{dx} = - \frac{ {x}^{3} }{ {y}^{3} } [/tex]
Determine the 1st and 2nd degree Taylor polynomials L(x,y) and Q(x,y) for
f(x, y) = tan^−1(xy) for (x, y) near the point (1,1).
Answer:
Step-by-step explanation:
[tex]f(x,y)=arctan(xy)\\\\\dfrac{ \partial f}{ \partial x}=\dfrac{y}{1+x^2y^2} \\\\\dfrac{ \partial f}{ \partial y}=\dfrac{x}{1+x^2y^2} \\\\\dfrac{ \partial ^2 f}{ \partial x^2}=\dfrac{-2xy^3}{(1+x^2y^2)^2} \\\\\dfrac{ \partial ^2 f}{ \partial y^2}=\dfrac{-2x^3y}{(1+x^2y^2)^2} \\\\\dfrac{ \partial ^2 f}{ \partial x\ \partial y}=\dfrac{1-x^2y^2}{(1+x^2y^2)^2} \\[/tex]
[tex]f(x,y)= f(1,1)+(x-1)\dfrac{\partial f}{\partial x} (1,1)+(y-1)\dfrac{\partial f}{\partial y} (1,1)+\dfrac{(x-1)^2}{2} \dfrac{\partial^2 f}{\partial x^2} (1,1)+(x-1)(y-1)\dfrac{\partial^2 f}{\partial x\ \partial y} (1,1)+\dfrac{(y-1)^2}{2} \dfrac{\partial^2 f}{\partial y^2} (1,1)+...\\\\=\dfrac{\pi}{4}+\dfrac{(x-1)}{2} +\dfrac{(y-1)}{2} -\dfrac{(x-1)^2}{4} +(x-1)(y-1)*\dfrac{0}{4}-\dfrac{(y-1)^2}{4} \\\\[/tex]
[tex]\boxed{f(x,y)=\dfrac{\pi}{4}+\dfrac{(x-1)}{2} +\dfrac{(y-1)}{2} -\dfrac{(x-1)^2}{4} -\dfrac{(y-1)^2}{4} }\\\\[/tex]
SUBTRACT. -18- (-12)
O
30
O
6
Answer: -6
Step-by-step explanation:
-18 - (-12)
= -6
none of them
it's actually-6.
12 63 x 42 is equivalent to 216 x 16. True or False?
Answer:
False
Step-by-step explanation:
63 x 42= 2646
216 x 16= 3456
have a great day
-5 - (-14)
Which expressions are equivalent to the given expression?
A. -5 - 14
B. -5 + 14
C. -14-(-5)
D. -14 +5
E. -14 - 5
F. 14 - (-5)
G. 14 + 5
H. 14 - 5
7th grade math
Answer:
[tex]b) h) \\ - 5 - ( - 14) \\ = - 5 - - 14 \\ = - 5 + 14( - \times - = + )-5+14=14-5 \\ thank \: you[/tex]
Answer:
-5 + 14
14 - 5
Step-by-step explanation:
Use the appropriate method to find the quotient and the remainder when 8x³+4x+3 is divided by 2x-1
The perimeter of a right-angled triangle is 96 cm.
The lengths of its sides are in the ratio 6: 8:10
Work out the area of the triangle in cmp.
Perimeter = the sum of all the sides. In this case, we know the ratio but not what each would be multiplied by, hence the variable.
6x + 8x + 10x = 96
24x = 96
x = 4
6(4) = 24
8(4) = 32
10(4) = 40
Check:
24 + 32 + 40 = 96 cm
Area = (base * height) / 2
Base = 32
Height = 24
(The base and height are interchangeable here, as we just have to make sure we're multiplying the legs of the triangle together and avoiding the hypotenuse.)
(32 * 24) / 2
768 / 2
384
Area = 384 cm^2
Hope this helps!
The width of a rectangle measures (2p - 9q) centimeters, and its length measures
(7p - 10q) centimeters. Which expression represents the perimeter, in centimeters,
of the rectangle?
Given Data : Length = (7p - 10q) and Breadth = (2p - 9q)
Calculation :
⟹ Perimeter = 2(Length + Breadth)
⟹ Perimeter = 2(7p - 10q + 2p - 9q)
⟹ Perimeter = 2(9p - 19q)
⟹ Perimeter = 18p - 38q centimetres
Answer : 18p - 38q centimetresThe required perimeter of the rectangle is 18p - 38q centimeters.
It is required to find the required perimeter of the rectangle.
What is rectangle?A rectangle is a type of quadrilateral, whose opposite sides are equal and parallel. It is a four-sided polygon that has four angles, equal to 90 degrees. A rectangle is a two-dimensional shape.
Given:
width of a rectangle = (2p - 9q) centimeters,
length measures= (7p - 10q) centimeters.
We know that
⟹ Perimeter = 2(Length + Breadth)
By put the value width and length in perimeter we get,
⟹ Perimeter = 2(7p - 10q + 2p - 9q)
⟹ Perimeter = 2(9p - 19q)
⟹ Perimeter = 18p - 38q centimeters
Therefore, the required perimeter of the rectangle is 18p - 38q centimeters.
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how do i solve a·a²·a³
Answer:
a^(1+2+3) so a^6
Step-by-step explanation:
Pls answer this question! I will mark as brainliest!!!
Answer:
1/8
Step-by-step explanation:
There is a 1/2 probability for each of the three flips to result in the desired outcome. To get 3 desired outcomes in a row, we multiply each of the probabilities together
(1/2)³ = 1/8
Answer: it is D) 2/3
True or False
No links
Answer:
False
Brainliest, please!
Step-by-step explanation:
+ + = +
- - = +
+ - = -
- + = -
Answer:
False
Step-by-step explanation:
The question doesn't specify whether you are adding positive or negative integers. If you have add 2 positive integers, your answer will be positive. If you add 2 negative integers, the answer will be negative. Here is an example;
1 + 1 = 2
-1 + (-1) = -1 - 1 = -2
Best of Luck!
ANSWER PLEASE NO FAKE ANSWERS ILL GIVE BRAINLIEST: Jaxson did the following problem incorrectly. Choose the option that correctly identifies what Jaxson did
wrong
Jaxson's work: 8 3/5 + 7 1/8 = 15 4/3
1. Jaxson forgot to simplify his answer.
2. Jaxson should have changed the mixed numbers to improper fractions.
3. Jaxson added the denominators instead of finding a common denominator and leaving it alone,
4. Jaxson did not make a mistake. He did everything right.
Answer:
3. Jaxson added the denominators instead of finding a common denominator and leaving it alone
Step-by-step explanation:
8 3/5 + 7 1/8 = 15 4/3
Get a common denominator
8 3/5 *8/8 + 7 1/8 *5/5
8 24/40 + 7 5/40
15 29/40
Note: Enter your answer and show all the steps you use to solve this problem in the space provided. 6 × 5 + 3 × 8
Make it simple, please
Answer:
54
Step-by-step explanation:
6x5=30
3x8=24
30+24=54
I need help solving this question please with an explanation.
Answer:
if he work 3 hours and earn 40.50
then the money he earn per hour is 40.50/3=13.5 ans
This car traveled 3 miles per 1 min. Tell me how far the car will travel at 6 mins. Use a table to show your work .
Answer:
min | miles
———|———
1 | 3
2 | 6
3 | 9
4 | 12
5 | 15
6 | 18
Step-by-step explanation:
try putting this into a T-chart like I kind of did here or some other kind of other table.
13. State the restrictions
and then simplify
8x2 +14x-49 /
2x²+x-21
Answer:
Whenever the denom is 0, that's where it's undefined -- or in your case "restrictions"
So factoring 2x^2 + x - 21 gets you (x-3)(2x+7). That means 3 and -7/2 are the restricted values.
To simplify, I'm going to factor it. (Assuming what you wrote is 8x^2 for the numerator)
[(4x-7)(2x+7)] / (x-3)(2x+7)
You can cancel 2x+7 out,
so you get 4x-7/x-3
the value of the power 4⁴=
Answer:
256
Step-by-step explanation:
4⁴
= 4 × 4 × 4 × 4
= 16 × 16
= 256
272 students enrolled in a freshman-level chemistry class. By the end of the semester, 7 times the number of students passed as failed. Find the number of students who passed, and the number of students who failed.
The number of students who passed is 234 and the number of students who failed is 39.
To find number of students who passed, and the number of students who failed.
What is arithmetic?The branch of mathematics dealing with the properties and manipulation of numbers.
Given that:
students enrolled in a freshman-level chemistry class=272
By the end of the semester, 7 times the number of students passed as failed.
Let x is number of students failed.
Then 6x is number of students passed.
So, 6x + x = 273
7x = 273,
∴x = 39
number of students passed= 273 - 39 = 234
So, the number of students who passed is 234 and the number of students who failed is 39.
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