The marginal cost function for a company is given by C'(q) = q^2 - 17q + 70 dollars/unit;
where q is the quantity produced. If C(0) = 650, find the total cost of producing 20 units. What is the fixed cost and what is the total variable cost for this quantity? Fixed cost = Variable Cost of producing 20 units =
Total cost of producing 20 units =

The angle measure of L in the triangle is approximately 75°.

Based on the given table, we can see that the ratio of the opposite leg length to the adjacent leg length for an angle measure of 75° is approximately 3.73. Looking at the triangle in the question, we can see that the side opposite to angle L is the hypotenuse and the adjacent leg is LK.

Therefore, the ratio of the opposite leg length to the adjacent leg length for angle L is equal to the ratio of the hypotenuse length to the length of segment LK.

From the figure, we can see that the length of segment LK is approximately 3.2 units. Therefore, the length of the hypotenuse is approximately 3.73 times the length of segment LK, or:

hypotenuse length ≈ 3.73 × 3.2 ≈ 11.9

Therefore, the angle measure of L is approximately 75°.

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Option A The diameter and circumference of a circle have a proportional relationship is True .

Diameter

The diameter is the length acrοss the circle at its widest pοint, measured frοm center tο center . The radius, a related measurement, is a line that extends frοm the circle's centre tο its edge. The diameter is equivalent tο twice the radius. (A chοrd is a line that crοsses the circle but is nοt at the widest pοint.)

Circumference

The circle's perimeter, οr the distance arοund it, is knοwn as its circumference. Imagine encircling a circle with a string. Imagine taking the string οut and extending it in a straight line. This string's length, if measured, wοuld represent yοur circle's circumference.

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The value of Q, taking into account the significant figures is 30.8.

To work out the value of Q given the value of p, we can substitute the value of p into the equation Q = (1/6) × p².

Given p = 13.6, we can calculate Q as follows:

Q = (1/6) × (13.6)²

Q = (1/6) × 184.96

Q = 30.826666...

Now, let's consider the significant figures of the given value of p, which is 13.6 (3 significant figures).

Since the value of p has 3 significant figures, we should round our final answer for Q to 3 significant figures as well.

Considering the value of Q to a suitable degree of accuracy, we can round our answer to three significant figures, which gives us:

Q = 30.8

Therefore, the value of Q, taking into account the significant figures, is  30.8.

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Answer:

Step-by-step explanation:

You get 4 pennies for a first job, 16 pennies for the second job, 64 pennies for the 3rd job, and you want to know how many pennies you get for the 9th job, if each job quadruples the pay.

We can write the number of pennies as a power of 4:

You will get 4^9 pennies for the 9th job.

That is 262144 pennies.

<95141404393>

a. There are 1000 mice in the neighborhood initially.

b.  The population of mice never quadruple

c. After 5 weeks there are 18 mice in the neighborhood.

d. It takes 0 weeks for there to be 1000 mice.

e. The P' (5) is -96.86, indicates that after 5 weeks, the number of mice is declining at a pace of about 96.86 mice per week.

a. The initial number of mice in the neighborhood can be found by evaluating P(0):

P(0) = 2000/(1 + 10⁰/₁₀) = 2000/(1+1) = 1000

b. To find how long it takes for the population of mice to quadruple, we need to solve the equation:

P(t) = 4P(0)

2000/(1 + 10^(t/10)) = 4*1000

1 + 10^(t/10) = 1/4

10^(t/10) = -3/4

This equation has no real solutions, so the population of mice never quadruples.

c. To find how many mice are in the neighborhood after 5 weeks, we simply evaluate P(5):

P(5) = 2000/(1 + 10^(5/10)) = 2000/(1+100) = 18.18 (rounded to two decimal places)

Therefore, there are approximately 18 mice in the neighborhood after 5 weeks.

d. To find how long it takes until there are 1000 mice, we need to solve the equation:

P(t) = 1000

2000/(1 + 10^(t/10)) = 1000

1 + 10^(t/10) = 2

10^(t/10) = 1

t = 0

Therefore, there are 1000 mice in the neighborhood initially, so it takes 0 weeks for there to be 1000 mice.

e. To find P'(5), we first find the derivative of P(t):

P'(t) = -2000ln(10)/10 * 10^(t/10) / (1 + 10^(t/10))^2

Then we evaluate P'(5):

P'(5) = -2000ln(10)/10 * 10^(1/2) / (1 + 10^(1/2))^2 ≈ -96.86

This means that the population of mice is decreasing at a rate of approximately 96.86 mice per week after 5 weeks.

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The type of transformation shown is a vertical transformation

In mathematics, a vertical translation refers to a transformation of a function or graph that involves moving it up or down along the y-axis without changing its vertical transformation.

From the attached figure, we can see that the polygons are moved up or down to map them to one another

This means that the transformation is a vertical transformation

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Complete question

Use the image to determine the type of transformation shown.

Image of polygon ABCD and a second polygon A prime B prime C prime D prime below.

Vertical translation

Reflection across the x-axis

180° counterclockwise rotation

Horizontal translation

Answer:

12.8

Step-by-step explanation:

First, we can simplify each fraction separately:

64e^2/5e = 64/5e^(1-1) = 64/5

3e/8e = 3/8

Now we can multiply:

(64/5) * (3/8) = 12.8

Therefore, the product is 12.8.

Step-by-step explanation:

Expressions are collection of algebric equetion and equal sighn and used for expresion of mankind problems like items, money and other mankind problem.

to know length by using degree but most of the time for the archtechture. soon

The area of the squares are;

1.  9x²ft². Option D

2.  6x² - 7x - 3 in². Option C

The formula for calculating the area of a square is expressed as;

A = a²

Such that the parameters of the formula are;

From the information given, we have that;

Area = (3x)²

Find the square of the expression, we have that;

Area = 9x²ft²

2. Substitute the values, we have that;

Area = (2x -3)(3x + 1)

expand the bracket, we have;

Area = 6x² + 2x - 9x - 3

collect the like terms

Area = 6x² - 7x - 3

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6. The probability that all 5 couples will have a baby of the preferred gender is 0.2373.

7. The probability that at least 4 of the 5 couples will have a baby of the preferred gender is 1 - 0.3672 = 0.6328.

Probability is a way to gauge how likely something is to happen. Many things are difficult to predict with absolute certainty.

Answer: The probability that one couple will have a baby of the preferred gender is 0.75. Assuming the gender of each baby is independent of the others, the probability that all 5 couples will have a baby of the preferred gender is 0.75⁵ = 0.2373.

Numeric value: 0.2373

In words: The probability that all 5 couples will have a baby of the preferred gender is 0.2373.

Answer: There are two ways to approach this problem. One way is to calculate the probability of each possible outcome (0 to 5 couples having a baby of the preferred gender) and then add up the probabilities for the outcomes where at least 4 couples have a baby of the preferred gender. Another way is to use the complement rule and subtract the probability that fewer than 4 couples have a baby of the preferred gender from 1.

Using the first method, we can calculate the probabilities as follows:

- 0 couples: 0.25⁵ = 0.0009766

- 1 couple: 5 x 0.75 x 0.25⁴ = 0.01465

- 2 couples: 10 x 0.75² x 0.25³ = 0.08789

- 3 couples: 10 x 0.75³ x 0.25² = 0.2637

- 4 couples: 5 x 0.75⁴ x 0.25 = 0.3955

- 5 couples: 0.75⁵ = 0.2373

The probabilities for the outcomes where at least 4 couples have a baby of the preferred gender are 0.3955 and 0.2373, so the total probability is 0.3955 + 0.2373 = 0.6328.

Using the second method, we can calculate the probability that fewer than 4 couples have a baby of the preferred gender as follows:

- 0 couples: 0.25⁵ = 0.0009766

- 1 couple: 5 x 0.75 x 0.25⁴ = 0.01465

- 2 couples: 10 x 0.75² x 0.25³ = 0.08789

- 3 couples: 10 x 0.75³ x 0.25² = 0.2637

The probability that fewer than 4 couples have a baby of the preferred gender is the sum of these probabilities: 0.0009766 + 0.01465 + 0.08789 + 0.2637 = 0.3672.

Therefore, the probability that at least 4 of the 5 couples will have a baby of the preferred gender is 1 - 0.3672 = 0.6328.

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The TWO statements that represent the relationship between y = 5x and y = log5 x are:

1. They are the exponential and logarithmic form of the same equation.

2. They are inverses of one another.

The two equations are related because they represent the same relationship between x and y, but in different forms. The first equation is an exponential equation, where y is a power of 5 raised to the x power. The second equation is a logarithmic equation, where y is the exponent to which 5 must be raised to get x.

Because the two equations represent the same relationship, they are inverses of one another. If we take the logarithm of both sides of the exponential equation, we get the logarithmic equation. If we raise 5 to both sides of the logarithmic equation, we get the exponential equation. Therefore, the two equations are inverses of one another.

The slant height of the given cone is 16.36 cm.

The length from the base to the peak along the "center" of a lateral face of an object (like a frustum or pyramid) is its slant height.

It is, in other words, the height of the triangle that a lateral face is a part of (Kern and Bland 1948, p.

So, calculate the slant height as follows:

614π = πr√h²+r²

614 = 16.2√h²+16.2²

614 = 262.44√h²

614/262.44 = h

2.33

Height = 2.33 cm

Then, slant height formula:

s=√(r² + h²)

s=√(16.2² + 2.33²)

s=√267.8689

s=16.36 cm

Therefore, the slant height of the given cone is 16.36 cm.

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The best inequality that represents the relationship between the amount of hydrochloric acid (x) and the amount of distilled water (y) in the given graph is 3y - 2x > 0, option D is correct.

The graph shows a straight line with a negative slope passing through the origin. As the amount of hydrochloric acid, x, increases, the amount of distilled water, y, decreases

To see why, let's use a point on the line, such as (2, 3), and plug it into the inequality. We get:

3(3) - 2(2) > 0

9 - 4 > 0

This is true, so the point (2, 3) is a solution to the inequality. Any point on the line will also satisfy this inequality since it represents all possible combinations of x and y that Corrine can use in her experiment.

Alternatively, we can rewrite the inequality in slope-intercept form:

y < (2/3)x

This means that the y-values on the line are less than the corresponding values of (2/3)x. So as x increases, y must decrease to stay below the line. This confirms that 3y - 2x > 0 is the correct inequality.

Hence, option D is correct.

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The correct question is:

For a science experiment, Corrine is adding hydrochloric acid to distilled water. The relationship between the amount of hydrochloric acid, x, and the amount of distilled water, y, is graphed below. Which inequality best represents this graph?

A. 2y - 3x < 0

B. 3y - 2x < 0

C. 2y - 3x > 0

D. 3y - 2x > 0

Answer:

2(x - 3) < -24

x - 3 < -12

x < -9

The inequality that represents the given statement is 2(x-3) ≤ -24, where x is the unknown number.

The given statement can be translated into an inequality as "twice the difference of a number (x) and 3 is at most -24". Mathematically, this can be represented as 2(x-3) ≤ -24. Simplifying this inequality, we get 2x - 6 ≤ -24, or 2x ≤ -18, which gives x ≤ -9. Therefore, any number less than or equal to -9 satisfies the given statement.

For example, x = -10 satisfies 2(-10-3) = -26, which is less than or equal to -24. However, any number greater than -9 does not satisfy the given statement. For example, x = -8 gives 2(-8-3) = -22, which is greater than -24. Therefore, the solution set for the given inequality is x ≤ -9.

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Answer:

Slope= -1/3

Step-by-step explanation:

The slope is found using (y₂ - y₁) / (x₂ - x₁)

(y₂ - y₁)

So let's do the numerator first with the y. -52-(-32). The two negative signs  make 32 positive so -52 + 32= -20

(x₂ - x₁)

Now the denominator, x. -10-(-70). Same thing here, the two negative signs  make 70 positive so -10 + 70 = 60

(y₂ - y₁) / (x₂ - x₁)

Now put them together so -20/60 which equals -1/3 which the slope

The derivative of s with respect to t is:

ds/dt = 10(sec² t - tan t) * (tan² t - sec² t)⁴

To find the derivative of s with respect to t, we will use the chain rule and the power rule of differentiation.

Let u = (tan² t - sec² t). Then, s = u⁵.

Using the chain rule, we have:

ds/dt = (du/dt) * (ds/du)

Now, we need to find du/dt and ds/du.

Using the chain rule again, we have:

du/dt = d/dt(tan² t - sec² t) = 2tan t * sec² t - 2sec t * tan t * sec t = 2sec² t * (tan t - sec t)

To find ds/du, we can simply apply the power rule:

ds/du = 5u⁴

Substituting these into the original equation for ds/dt, we get:

ds/dt = (2sec² t * (tan t - sec t)) * (5(tan² t - sec² t)⁴)

Therefore, the derivative of s with respect to t is:

ds/dt = 10(sec² t - tan t) * (tan² t - sec² t)⁴

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The possible value of <J is 78 degrees

It is important to note that the different trigonometric identities are;

Also, the law of sines in a triangle is expressed as;

sin A/a = sin B/b = sin C/c

Given that the angles are in capitals and the sides are in small letters.

From the information given, we have that;

sinI/i = sin J/j

Substitute the values, we get;

sin 72 /70 = sin J/72

cross multiply the values, we have;

sin J = 68. 476/70

divide the values

sin J = 0. 9782

Find the inverse of sin

<J = 78 degrees

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(a) The value of the constant is 1/24, (b) P(X<=1,Y<=1)  is 5/48 and (c)  P(X + Y <= 1) is also 5/48

(a) The constant C can be found by using the fact that the total probability of the joint density function over the entire space is equal to 1. Therefore, we integrate the joint density function over the region where it is defined and set it equal to 1:

∫∫f(x,y) dA = 1

∫[0,2]∫[0,4] Cx(1+y) dy dx = 1

C∫[0,2]x[(y+(y²)/2)] [0,4] dx = 1

C(24/5) = 1

C = 5/24

(b) To find P(X <= 1, Y <= 1), we integrate the joint density function over the region where X <= 1 and Y <= 1:

P(X<=1,Y<=1) = ∫[0,1]∫[0,1] (5/24) x(1+y) dy dx

= (5/24) ∫[0,1] x(1+(1/2)) dx

= (5/24) [(1/2) + (1/6)]

= 5/48

(c) To find P(X + Y <= 1), we integrate the joint density function over the region where X + Y <= 1:

P(X+Y<=1) = ∫[0,1]∫[0,1-x] (5/24) x(1+y) dy dx

= (5/24) ∫[0,1] x(1+(1-x)/2) dx

= (5/24) [(1/2) - (1/12)]

= 5/48

Therefore, P(X + Y <= 1) = 5/48.

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After one month, Betty will owe $407.02 on her credit card.

The amount Betty will owe after one month depends on how much of the stability she will pay off in the course of that point.

Assuming she does not make any payments in the course of the first month, here is how to calculate her balance:

The cash-withdrawal price is a one-time fee, so it does no longer affect the stability after one month.

Betty withdrew $400, so her starting balance is $406 ($400 for the lawnmower plus $6 cash-withdrawal price).

The interest rate is 3%, that's an annual price. To calculate the monthly charge, divide with the aid of 12: three% / 12 = 0.25%.

To calculate the interest charged for the first month, multiply the stability through the monthly interest rate: $406 * 0.25% = $1.02.

Add the interest to the balance: $406 + $1.02 = $407.02. that is Betty's balance after one month.

Consequently, after one month, Betty will owe $407.02 on her credit card.

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Answer:

Step-by-step explanation:

I assume the question is what trig function do you use to find x?  If that's correct then answers, from TOP to BOTTOM, are:

tan

cos

sin

Answer:

Triangle 1: tangent

Triangle 2: cosine

Triangle 3: sine

Step-by-step explanation:

First, some definitions before working the problem:

The three standard trigonometric functions, cosine, tangent, and sine, are defined as follows for right triangles:

[tex]sin(\theta)=\dfrac{opposite}{hypotenuse}[/tex]

[tex]tan(\theta)=\dfrac{opposite}{adjacent}[/tex]

[tex]cos(\theta)=\dfrac{adjacent}{hypotenuse}[/tex]

One memorization tactic is "Soh Cah Toa" where the first capital letter represents one of those three trigonometric functions, and the "o" "a" and "h" represent the "opposite" "adjacent" and "hypotenuse" respectively.

The triangle must be a right triangle, or there wouldn't be a "hypotenuse", because the hypotenuse is always across from the right angle.  

Triangle 1

For the first triangle, the known acute angle is in the bottom left.  The two sides of the triangle that are known or are a "goal to find" are not the hypotenuse, so they are the "opposite" & "adjacent".

Specifically, the side of length "13" is touching the known acute angle AND the right angle, so it is the adjacent side.  The unknown side of length "x" is is touching the right angle but is NOT touching the known acute angle, so it is the "opposite" (across from the angle).

Out of "Soh Cah Toa," the part that uses o & a is "Toa".  The "T" in "Toa" stands for Tangent.  So, the desired function to use for the first triangle is the Tangent function.

Triangle 2

For the second triangle, the known acute angle is in the top left.  This time, the "adjacent" side is unknown, labeled as x, so it is the "goal to find" side.  The "hypotenuse" is known.

Therefore, the two sides of the triangle that are known or are a "goal to find" are the "adjacent" & "hypotenuse".

Out of "Soh Cah Toa," the part that uses "a" & "h" is "Cah".  So, the desired function to use for the first triangle is the Cosine function.

Triangle 3

For the third triangle, the known acute angle is in the top right.

This time, the side (at the bottom) across from the angle (at the top right) is known -- the "opposite" leg.  Additionally, the "hypotenuse" is unknown and is our "goal to find" side.  

Therefore, the two sides of the triangle that are known or are a "goal to find" are the "opposite" & "hypotenuse".

Out of "Soh Cah Toa," the part that uses "o" & "h" is "Soh".  So, the desired function to use for the first triangle is the Sine function.

The number of students in each bus is 15, and the number of students in each van is 28.

To find the number of students in each van and bus for the field trip to Yellowstone National Park, we can set up a system of equations using the given information. Let x represent the number of students in each van and y represent the number of students in each bus.

For high school A, we have:
2x + 8y = 254

For high school B, we have:
6x + 11y = 398

Now, we can solve this system of equations using the substitution or elimination method. We will use the elimination method:

Step 1: Multiply the first equation by 3 to make the coefficients of x the same in both equations:
6x + 24y = 762

Step 2: Subtract the second equation from the new first equation:
(6x + 24y) - (6x + 11y) = 762 - 398
13y = 364

Step 3: Divide both sides by 13 to find the value of y:
y = 364 / 13
y = 28

Now that we have the number of students in each bus, we can find the number of students in each van:

Step 4: Substitute y back into the first equation:
2x + 8(28) = 254
2x + 224 = 254

Step 5: Subtract 224 from both sides to find the value of x:
2x = 30

Step 6: Divide both sides by 2 to find x:
x = 15

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For the function,

-number of complex zeros: four

-possible # of imaginary zeros: two pairs

-possible # of positive real zeros: zero

-possible # negative real zeros: 0 or 2

-possible rational zeros:  ±1, ±3, ±5, ±9, ±15, ±45

-factors to: (x + 3i)(x - 3i)(x + √5i)(x - √5i)

-zeros: x = ±3i, x = ±√5i.

The function is: F(x) = x⁴ +14x²+45.

Number of complex zeros: By the Fundamental Theorem of Algebra, the function has at most four complex zeros.

Possible number of imaginary zeros: If the complex zeros are not real, then there are at most two pairs of imaginary zeros.

Possible number of positive real zeros: The function has no positive real zeros since F(x) is always positive for x>0.

Possible number of negative real zeros: By Descartes' Rule of Signs, the function has either 0 or 2 negative real zeros.

Possible rational zeros: The rational zeros can be found using the Rational Root Theorem. They are of the form ±(a factor of 45) / (a factor of 1), which gives the following possible rational zeros: ±1, ±3, ±5, ±9, ±15, ±45.

To factor the polynomial:

F(x) = x⁴ +14x²+45

= (x² + 9)(x² + 5)

So the factors to linear factors are: (x + 3i)(x - 3i)(x + √5i)(x - √5i), where i is the imaginary unit.

Therefore, the zeros are: x = ±3i, x = ±√5i.

Note that all zeros are complex since there are no real roots.

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The simplified expression [tex](3.05 * 10^-7) (8.67 * 10^4)[/tex] in standard form to 3 decimal places is approximately 0.026

To simplify the expression[tex](3.05 * 10^-7) (8.67 *  10^4)[/tex] and provide the answer in standard form to 3 decimal places.

Step 1: Multiply the coefficients (3.05 and 8.67).
3.05 * 8.67 = 26.4445

Step 2: Use the properties of exponents to multiply the powers of 10.
[tex]10^{-7} * 10^4 = 10^{(-7+4)} = 10^-3[/tex]

Step 3: Multiply the results from Step 1 and Step 2.
[tex]26.4445 * 10^-3 = 0.0264445[/tex]

Step 4: Round the result to 3 decimal places.
0.0264445 ≈ 0.026

So, the simplified expression (3.05 x 10^-7) (8.67 x 10^4) in standard form to 3 decimal places is approximately 0.026.

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we can simplify |x + 3| to x + 3 when x is greater than 5.

The absolute value function |x| is defined as the distance of x from zero on the number line. This means that |x| is always non-negative, so it can be expressed as a non-negative number.

In this case, we are given that x > 5, which means that x is greater than 5. If we add 3 to both sides of this inequality, we get:

x + 3 > 5 + 3

x + 3 > 8

This tells us that x + 3 is also greater than 8. Therefore, when x is greater than 5, the expression |x + 3| represents the distance of x + 3 from zero, which is equal to x + 3 itself because x + 3 is positive.

As a result, we can simplify |x + 3| to x + 3 when x is greater than 5.

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a) The demand function is 134.33e^-0.693p

b) At P = $3, we have elasticity is  0.83, at P = $4, we have elasticity is  1.05, at P = $5, we have elasticity is 1.34.

c) We should sell the cheese at a price of $3.84 per pound to maximize monthly revenue.

d) We should sell the cheese at a price of $4.22 per pound to generate the highest revenue within the timeframe of one month.

a) To construct a demand function of the form q = Ae^-bp, we can use the sales figures for the prices $3 and $5 per pound. First, we calculate the values of A and b:

A = q/p = 403/3 ≈ 134.33

b = ln(q/Ap) / p = ln(403/134.33) / (3-5) ≈ 0.693

Using these values, the demand function becomes:

q = 134.33e^-0.693p

b) To find the price elasticity of demand at each of the prices listed, we can use the formula:

E = (dq/dp) * (p/q)

At P = $3, we have:

E = (dq/dp) * (p/q) = (-134.33 * -0.693 * 3) / 403 ≈ 0.83

At P = $4, we have:

E = (dq/dp) * (p/q) = (-134.33 * -0.693 * 4) / 284 ≈ 1.05

At P = $5, we have:

E = (dq/dp) * (p/q) = (-134.33 * -0.693 * 5) / 225 ≈ 1.34

c) To find the price that will maximize monthly revenue, we can use the formula:

p = (1/b) * ln(A/b)

Plugging in the values of A and b that we calculated earlier, we get:

p = (1/0.693) * ln(134.33/0.693) ≈ $3.84

d) If we only have 200 pounds of cheese and it will spoil in one month, we need to sell it at a price that will generate the highest revenue within that timeframe. To do this, we can use the formula:

R = pq

where R is the revenue, p is the price per pound, and q is the quantity sold. We can express q in terms of p using our demand function:

q = 134.33e^-0.693p

Substituting this into the revenue equation, we get:

R = p * 134.33e^-0.693p

To find the price that will maximize revenue, we can take the derivative of R with respect to p and set it equal to zero:

dR/dp = 134.33e^-0.693p - 93.13pe^-0.693p = 0

Solving this equation numerically, we get:

p ≈ $4.22

This price is different from the price calculated in part (c) because we have a limited quantity of cheese that will spoil, so we need to balance the price and quantity sold to maximize revenue within the given timeframe.

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To estimate your paycheck, a good percentage to multiply your earning by would be 0.75 or 75%. When calculating your paycheck, it's important to account for taxes, deductions, and other withholdings that may be taken out of your gross pay.  

This accounts for taxes, deductions, and other withholdings that are typically taken out of your paycheck before you receive your net pay. For example, if you earn $1,000 per pay period, multiplying by 0.75 would give you an estimated net pay of $750. However, keep in mind that this is just an estimate and your actual net pay may vary depending on your specific tax situation and other factors.

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The distance which this light travel per second is equal to 3 × 10⁸ meters per seconds.

In Mathematics and Science, speed is the distance covered by a physical object per unit of time.

In Mathematics and Science, the speed of any a physical object can be calculated by using this formula;

Speed = distance/time

By making distance the subject of formula, we have:

Distance, d(t) = speed × time

Distance = (9.45 × 10¹⁵ meters per year) × (1 year/ 3.15 × 10⁷ seconds)

Distance = 3 × 10⁸ meters per seconds.

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Complete Question:

Light travels 9.45 × 10¹⁵ meters in a year. There are about 3.15 × 10⁷ seconds in a year. How far does light travel per second?

Answer:

True (I think)

Step-by-step explanation:

Same pattern.

A -> B -> C.

D -> E -> F.

Would be false if either one didn't share the same pattern.

Answer:

C

Step-by-step explanation:

first fine the nth term

a+(n-1)d

509+7n+7

516-7n

then equate the ans to the nth term

495=516-7n

7n=516-495

7n= -21

n= -3

The magnitude of the force of the car against the hill is approximately 13690 pounds.

a. To find the magnitude of the force required to keep the car from sliding down the hill, we need to calculate the force component perpendicular to the hill (the normal force) and the force component parallel to the hill (the force of friction). The force of friction must be equal and opposite to the component of the weight of the car parallel to the hill to keep the car from sliding.

First, we need to calculate the weight of the car in Newtons:

3100 pounds = 1406.13 kg

Weight = mg = 1406.13 kg * 9.81 m/s^2 = 13791.68 N

The force component perpendicular to the hill is equal to the weight of the car multiplied by the cosine of the angle of inclination:

F_perpendicular = Weight * cos(5.6°) = 13791.68 N * cos(5.6°) = 13689.55 N

The force component parallel to the hill is equal to the weight of the car multiplied by the sine of the angle of inclination:

F_parallel = Weight * sin(5.6°) = 13791.68 N * sin(5.6°) = 1275.02 N

The force of friction is equal to the force parallel to the hill, so:

F_friction = F_parallel = 1275.02 N

Therefore, the magnitude of the force required to keep the car from sliding down the hill is equal to the force component perpendicular to the hill plus the force of friction:

F_required = F_perpendicular + F_friction = 13689.55 N + 1275.02 N = 14964.57 N

Rounded to the nearest whole number, the magnitude of the force required to keep the car from sliding down the hill is approximately 14965 pounds.

b. To find the magnitude of the force of the car against the hill, we just need to calculate the force component perpendicular to the hill (the normal force):

F_normal = F_perpendicular = 13689.55 N

Rounded to the nearest whole number, the magnitude of the force of the car against the hill is approximately 13690 pounds.

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