The number of air conditioner units that 10 sales representatives sold last year are:

{6, 8, 10, 11, 12, 16, 17, 21, 32, 36}

How is the mean effected if the representative who sold the lowest number of units left the department, causing his sales to cancel out?

Responses:


The mean would increase.

The mean would remain the same.

The mean would decrease.

Answer:

To subtract −5x² − 9x − 5 from 4x² − 5x + 3, we need to subtract the coefficients of each term with the same degree.

(4x² - 5x + 3) - (-5x² - 9x - 5)

4x² - 5x + 3 + 5x² + 9x + 5

9x² + 4x + 8

To subtract -5x² - 9x - 5 from 4x² - 5x + 3, you subtract each corresponding term, which results in 9x² + 4x + 8.

If you would like to subtract -5x² - 9x - 5 from 4x² - 5x + 3, you need to subtract every term separately. So, the steps will look like the following:

So, 4x² - 5x + 3 - (-5x² - 9x - 5) = 9x² + 4x + 8.

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The interval estimate for the population mean, μ, is 65 ± 3.38 mph, or 61.62 to 68.38 mph.

The z-value for a 96.6% confidence level is 2.58. This value is used to determine the margin of error for a sample mean in a population. The formula for margin of error is ME = z*σ/√n, where σ is the population standard deviation, n is the sample size, and z is the z-value for the desired confidence level. In this case, ME = 2.58*22/√121 = 3.38 mph.Therefore, the interval estimate for the population mean, μ, is 65 ± 3.38 mph, or 61.62 to 68.38 mph.

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Answer: 3/3 +4/2=3

Step-by-step explanation:

given: 3/3 + 4/2

 3/3+ 4/2 =1 +2

    =3

Answer:

3/3+4/2=3

Step-by-step explanation:

3/3+4/2

=1+2

=3

After answering the presented question, we can conclude that Hence, fat  expression accounts for around 28.2 pounds of the individual's weight.

An expression in mathematics is a collection of representations, digits, and conglomerates that mimic a statistical correlation or regularity. A real number, a mutable, or a combination of the two can be used as an expression. Mathematical operators include addition, subtraction, rapid spread, division, and exponentiation. Expressions are often used in arithmetic, mathematics, and form. They are employed in the representation of mathematical formulas, the solving of equations, and the simplification of mathematical relationships.

To establish how many pounds of an individual's weight are made up of fat, we must first determine the individual's body fat weight.

We may accomplish this by multiplying the individual's weight by the percentage of body fat (in decimal form):

Body fat weight = 163 pounds x 0.173 = 28.199 pounds

Hence, fat accounts for around 28.2 pounds of the individual's weight.

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Check the picture below.

so the cars are 276 miles apart, let's say the southbound car is going "r" mph fast, that means the northbound car is going "r + 12" mph fast as you see in the picture, so at some time they meet, hmmm wait, we know they're 3 hours apart from passing each other, so that means by the time they meet, 3 hours have passed, so by the time that happens, the northbound car has been traveling for 3 hours and the southbound car has been traveling for 3 hours as well.

Since we know they're 276 miles apart, let's say by the time they meet the southbound car has covered "d" miles, so the northbound car has covered the slack then, that is "276 - d" miles.

[tex]{\Large \begin{array}{llll} \underset{distance}{d}=\underset{rate}{r} \stackrel{time}{t} \end{array}} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Southbound&d&r&3\\ Northbound&276-d&r+12&3 \end{array}\hspace{5em} \begin{cases} d=(r)(3)\\\\ 276-d=(r+12)(3) \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{using the 1st equation}}{d=3r}\hspace{5em}\stackrel{\textit{substituting on the 2nd equation}}{276-(3r)~~ = ~~3(r+12)} \\\\\\ 276-3r=3r+36\implies 240-3r=3r\implies 240=6r \\\\\\ \cfrac{240}{6}=r\implies \stackrel{ Southbound~car }{40=r}\hspace{5em}\underset{ Northbound~car }{\stackrel{ 40~~ + ~~12 }{\text{\LARGE 52}}}[/tex]

The amount of paint needed in cubic centimeters to apply a coat of paint 0.03 cm thick to a hemispherical dome with a diameter of 30 meters is 1.413737 × 10¹⁰ cm³.

To estimate the amount of paint needed to apply a coat of paint 0.03 cm thick to a hemispherical dome with a diameter of 30 meters, we will use linear approximation.

The volume of a hemisphere with a diameter of 30 meters is given by:

V = (2/3)πr³Where r = 30/2 = 15 meters

We need to find the amount of paint required for a thickness of 0.03 cm.

We convert this to meters as:

0.03 cm = 0.0003 m

The linear approximation formula is given by:

ΔV ≈ dV/dx × Δx

where Δx = 0.0003 is the change in thickness, and

dV/dx is the rate of change of the volume with respect to thickness x.

We have:

V = (2/3)πr³ = (2/3)π(15)³ = 14137.2 m³

dV/dx = 4πr² = 1800π m²

Now, we can estimate the change in volume:

ΔV ≈ dV/dx × Δx = 1800π × 0.0003 = 0.1696 m³

The total amount of paint needed is:

V + ΔV = 14137.2 + 0.1696 = 14137.37 m³

We can convert this to cubic centimeters as:

1 m³ = 10⁶ cm³

So, the amount of paint needed in cubic centimeters is:

V = 14137.37 * 10⁶ cm³ = 1.413737 × 10¹⁰ cm³

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If we know that f(7) = 0, we can say that:

x - 7 is a factor of the function f(x).

This is because when we substitute x = 7 into the function, we get:

f(7) = 7^3 - 7(7)^2 + 25(7) - 175 = 0

This means that (x - 7) is one of the factors of the function.

Now we can use polynomial division or synthetic division to find the other factors. If we divide the function f(x) by (x - 7), we obtain:

           x^2 - 4x + 25

Therefore, we can say that:

f(x) = (x - 7)(x^2 - 4x + 25)

The quadratic term, x^2 - 4x + 25, has no real roots because the discriminant is negative. Therefore, we can write the factorization of f(x) in terms of complex numbers as:

f(x) = (x - 7)(x - 2 + 5i)(x - 2 - 5i)

Thus, the complete factorization of f(x) is:

f(x) = (x - 7)(x - 2 + 5i)(x - 2 - 5i)

Si nous savons que f(7) = 0 alors,

x - 7 est un facteur de la fonction f(x).

on substitue x = 7 dans la fonction

f(7) = 7^3 - 7(7)^2 + 25(7) - 175 = 0

donc  (x - 7) est l’un des facteurs de la fonction.

Maintenant, on utilise division polynomiale ou la division synthétique pour avoir les autres facteurs. Si on divise la fonction f(x) par (x - 7), on obtient:

x^2 - 4x + 25

Du coup peut dire que :

f(x) = (x - 7)(x^2 - 4x + 25)

Le terme quadratique, x^2 - 4x + 25, n’a pas de racines réelles car le discriminant est négatif. Par conséquent, nous pouvons écrire la factorisation de f(x) en termes de nombres complexes comme:

f(x) = (x - 7)(x - 2 + 5i)(x - 2 - 5i)

la factorisation complète de f(x) est:

f(x) = (x - 7)(x - 2 + 5i)(x - 2 - 5i)

1. Ben's mistake in solving the area of circle is, he has taken the value of diameter at the place of radius in formula.

2. Luna's mistake is, he did the incorrect squaring of radius 4.5.

The formula makes use of the diameter. The units are squared at all times. When the diameter is known, the area can be calculated by first determining the radius. The radius of the circle is the area. You can use circumference to determine area.

area of circle A =  πr²

where, π = 3.14 and r is the radius of circle

r = diameter /2 = 9/2 = 4.5 cm

A = πr²

A = 3.14*(4.5)²

A = 3.14*20.25

A = 63.585 cm² (correct area)

Thus,

1. Ben's mistake in solving the area of circle is, he has taken the value of diameter at the place of radius in formula.

2. Luna's mistake is, he did the incorrect squaring of radius 4.5.

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Answer:

about 1 cubic ft i think

Step-by-step explanation:

The system of inequalities that represents Irene's constraints is:

c + v ≥ 25 (She needs to make at least 25 dinners) 8.75c + 5.50v ≤ 250.

The problem presents two types of dinners: chicken and vegetarian. Irene needs to make at least 25 dinners, so the total number of dinners must be greater than or equal to 25. The cost of chicken dinners and vegetarian dinners is also given, along with the total budget of $250. These constraints can be translated into mathematical inequalities using variables c and v to represent the number of chicken and vegetarian dinners, respectively.

The first inequality represents the constraint that the total number of dinners must be greater than or equal to 25:

c + v ≥ 25

The second inequality represents the constraint that the cost of the dinners cannot exceed the total budget of $250:

8.75c + 5.50v ≤ 250

Together, these two inequalities form a system of inequalities that represents Irene's constraints. The solution to this system will give the possible values of c and v that satisfy both constraints.

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Answer:

Step-by-step explanation:

A) 6 inches. ( if the equation for the area of a triangle is

Answer:

48

Step-by-step explanation:

first multiply 60 by 0.80 the decimal version of the percentage then you get 48.00 or 48 as your anser

Answer:

ANSWER IS PROVIDED BELOW

hope this helps and good luck on your assignment

The area of the circle is 63.585 sq. cm.

An object's area is how much space it takes up in two dimensions. It is the measurement of the quantity of unit squares that completely cover the surface of a closed figure. The square unit, which is frequently expressed as square inches, square feet, etc., is the accepted unit of area. Each shape's area may be calculated by counting how many unit squares will fit inside of it.

Given that the diameter of the circle is 9 cm

The radius = 9/2 = 4.5 cm

The area of the circle is:

A = πr²

Substitute the values:

A = (3.14)(4.5)²

A = 63.585 sq. cm.

Hence, the area of the circle is 63.585 sq. cm.

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The complete question is:

The answer of the given question based on the finding the area of rectangle is  QRST is approximately 116.56 square units.

Area is a measure of the size or extent of a two-dimensional surface, like a shape or a region on a flat surface. It is typically measured in square units, like square meters (m²), square feet (ft²), or square centimeters (cm²).

To calculate the area of a shape, you need to know its dimensions and shape. The formula for finding the area of a shape depends on its shape. Area is an important concept in mathematics and geometry, and it is used in many real-life applications, such as measuring the size of land, determining the amount of material needed for a project, and calculating the volume of a container or room.

To find the area of the rectangle, we can use the distance formula to find the lengths of its sides. Then, we can use the formula for the area of a rectangle, which is the product of its length and width.

Length QR = √[(6 - (-4))² + (3 - (-3))²] = √[10² + 6²] = √(136)

Length ST = √[(9 - (-1))² + (-2 - (-8))²] = √[10² + 6²] = √(136)

Width QS = √[(6 - (-1))² + (3 - (-8))²] = √[7² + 11²] = √(170)

Width RT = √[(-4 - 9)² + (-3 - (-2))²] = √[13² + 1] = √(170)

Therefore, the area of the rectangle is:

Area = Length x Width = √(136) x √(170) = 116.56 (rounded to two decimal places)

So, the area of the rectangle QRST is approximately 116.56 square units.

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The solution is the factor 4y - 6x:. 2(2y - 3x) = 2(2y - 3x). 8 = 2• 4 =. 2(2y - 3x)

8. 2• 4

cancel the common factor: 2

= 2y - 3x. the answer is 2y - 3x

4 4

The level of service for the urban freeway is level E, and the density is 61.25 vehicles per mile.

To determine the level of service for the urban freeway, we can use the Highway Capacity Manual (HCM) method, which considers factors such as traffic volume, speed, and density.

Based on the given traffic flow of 2500 vehicles per hour and a design speed of 60 mph, the capacity of the four-lane freeway can be calculated as 8000 vehicles per hour. Using this value, along with the interchange spacing of 0.33 miles, we can determine the density of the freeway, which is 61.25 vehicles per mile.

Using the HCM method, the level of service is determined by comparing the freeway density to the capacity, which results in a level of service of E. Level E indicates that the freeway is operating at or near its capacity, and delays are frequent.

In conclusion, the urban freeway has a level of service classified as E, and density of the freeway, which is the number of vehicles per mile, is calculated to be 61.25.

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When x = 11, the value of y is approximately 8.276. We are given that the relationship between x and y is given by [tex]y = Ax^n[/tex]where A and n are constants.

We are also given the values of A and n:

[tex]A = e^0.5[/tex]

n = 3/8

We can substitute these values into the equation to get:

[tex]y = e^0.5 x^(3/8)[/tex]

Now, we are asked to find the value of y when x = 11. To do this, we substitute x = 11 into the equation:

[tex]y = e^0.5 x^(3/8)[/tex]

[tex]y = e^0.5 (11)^(3/8)[/tex]

We can use a calculator to evaluate this

First, we evaluate the exponent (3/8) using the exponent rules:

[tex](11)^(3/8) = (11^(1/8))^3 = 1.706[/tex]

Next, we substitute this value back into the equation:

[tex]y = e^0.5 x^(3/8)[/tex]

[tex]y = e^0.5 (11)^(3/8)[/tex]

[tex]y = e^0.5 (1.706)[/tex]

Using a calculator, we can evaluate this expression to get:

y ≈ 8.276

Therefore, when x = 11, the value of y is approximately 8.276.

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The perimeter of ABCDEFGH is 8s, with s = 3, so the perimeter of ABCDEFGH is 8x3 = 24 units.

The perimeter of a regular octagon can be calculated using the formula P = 8s, where s is the length of each side. To solve for the perimeter of ABCDEFGH, we need to first calculate the length of each side.We can use the distance formula to calculate the length of AH. The distance formula is [tex]d = √((x2-x1)^2 + (y2-y1)^2).[/tex] In this case, x1 = 4, y1 = 5, x2 = 7, and y2 = 5. Plugging these values into the formula, we get [tex]d = √((7-4)^2 + (5-5)^2) = √(3^2 + 0) = √9 = 3[/tex] units.Since each side of a regular octagon is equal, we can use the length of AH, 3 units, to calculate the perimeter of the octagon. The perimeter of ABCDEFGH is 8s, with s = 3, so the perimeter of ABCDEFGH is 8x3 = 24 units.

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The probability that the next 4 science fair winners will all be seventh grade students is approximately 0.316

Assuming that the probability of winning the science fair is independent of grade level, the probability of a seventh grade student winning the science fair is 12/16 or 3/4, and the probability of a student of any other grade level winning is 1/4.

If Mona placed 3 red marbles (representing seventh grade winners) and 1 green marble (representing winners from other grade levels) in the bag, then the probability of drawing a red marble (representing a seventh grade winner) is 3/4, and the probability of drawing a green marble (representing a winner from another grade level) is 1/4.

Since the events of each science fair winner are independent, we can apply the multiplication rule of probability to determine the probability that the next 4 winners will all be seventh grade students

P(4 seventh grade winners) = (3/4)^4 = 81/256 or approximately 0.316.

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Check the picture below.

so going on the 1st revolution from 0 to 2π, we get those two angles  you see in the picture, the cosine is positive on I and IV Quadrants, whilst negative on the II and III Quadrants, so any angles with that negative cosine will be only on those two Quadrants.

when getting an angle or a trig function, make sure your calculator is in the correct mode, because plugging in cos(-0.89) in Degree mode, it's going to assume you mean to find the cosine of -0.89 Degrees, and same will happen the other way around, so make sure your mode is correct, so the input is understood correctly.

the cos⁻¹ function has a range of 0 to π, so any angles it's going to spit out will be on those Quadrants, we get the one in the III Quadrant in the picture by simply using the reference angle from the II Quadrant, the reference angle is about 0.47359 radians, so if we add that to π, we get that many radians.

now, if we want to include All revolutions around the circle, we can say

[tex]\approx ~~ \begin{cases} 2.668+2\pi n\\\\ 3.615+2\pi n \end{cases}\qquad n\in \mathbb{Z};n\geqslant 0[/tex]

Step-by-step explanation:

We can simplify each equation to determine which one is true:

61 x 5 = 305

10381 x 27 = 279,387

1143 ÷ 9854 x 63 = 0.00736 x 63 = 0.46368

562 x 42 = 23,604

Therefore, the only equation that is true is 562 x 42 = 23,604.

Starting with 110mg of a radioactive substance, after 21 hours, 55mg remains. Using the exponential decay model, after 31 hours,  39.3mg of the substance will remain.

We can use the formula for exponential decay, which is:

N(t) = N0 * e^(-λt)

where:

N0 is the initial amount of the substance

N(t) is the amount remaining after time t

λ is the decay constant

To solve for λ, we can use the fact that after 21 hours, 55 mg remains:

55 = 110 * e^(-λ*21)

Simplifying:

0.5 = e^(-λ*21)

Taking the natural logarithm of both sides:

ln(0.5) = -21λ

Solving for λ:

λ = ln(0.5) / (-21) ≈ 0.033

Now we can use this value of λ to find the amount remaining after 31 hours:

N(31) = 110 * e^(-0.033*31) ≈ 39.3 mg

Therefore, approximately 39.3 milligrams of the substance will remain after 31 hours.

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The equation describes a linear relationship between two variables, where the output of the equation, y, is equal to two fifths of the input, x.

To calculate the value of y in the equation y=2/5x, we need to start by identifying the value of x. Once that is known, the value of y can be calculated by substituting x into the equation. For example, if x=10, then we can substitute 10 into the equation to get y=2/5 x 10. To solve this, we can multiply 2/5 by 10 to get 2x10/5, which simplifies to 20/5. Since dividing by 5 is the same as multiplying by 1/5, we can simplify this to 20/5 = 4. Therefore, when x=10, y=4.

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the complete question is

What is the verbal description of y=2/5x  and identify the value of x

Answer:

B i think

Step-by-step explanation:

b

In conclusion there are 33 ways to distribute seven identical balls into three distinct boxes so that each box contains at least one ball.

How to solve?

This is a combinatorics problem known as distributing identical objects into distinct boxes with the condition that each box has at least one object.

There are three such cases: when the first box is empty, when the second box is empty, and when the third box is empty. Each of these cases can be represented by a single bar that is placed at the beginning or end of the line of stars. For example, the case where the first box is empty can be represented as:

|****|

There are three ways to place this single bar, so we need to subtract three from our previous count of 36 to get the final answer:

36 - 3 = 33

Therefore, there are 33 ways to distribute seven identical balls into three distinct boxes so that each box contains at least one ball.

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Answer:

The two numbers are 4 and -6. Since -6 is less than 4, the lesser of these two numbers is -6.

The lesser number is -6.

Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a statement. It's possible to multiply, divide, add, or subtract with this mathematical operation.

Let's call the two numbers x and y. We know that:

We can solve this system of equations using substitution. Solving the first equation for x, we get:

x = -2 - y

We can substitute this expression for x in the second equation:

-2 - y + 2y = -8

Simplifying this equation, we get:

y = -6

Now we can use the first equation to find x:

x + y = -2

x + (-6) = -2

x = 4

So the two numbers are -6 and 4, and the lesser of the two numbers is -6.

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