the period of a pendulum may be decreased by

Answers

Answer 1

Answer:

shortening its length.

Answer 2

The period of a pendulum is not dependent on the mass of the ball, but only on the length of its string. The period of a pendulum may be decreased by shortening the length of pendulum

The shortening of the pendulum length often affect its period.  The length of the string do influence the pendulum's period making it to be like the longer the length of the string, the longer the pendulum's period.

A pendulum that has a longer string often has a lower frequency. That is, it will swings back and forth in little times in a given amount of time than when the pendulum is with a shorter string length.

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Related Questions

Why is a control group generally very important in an experiment?

Answers

Answer: The control group is the part where you see what happens when you change a variable you want to study/examine. Basically, you need the control group because you need something to see what happens when you change something.

Hope this Helps! :))))

PLEASE HELP!! Salmon often jump waterfalls to reach their
breeding grounds.
Starting downstream, 3.41 m away from a
waterfall 0.397 m in height, at what minimum
speed must a salmon jumping at an angle of
28.4° leave the water to continue upstream?
The acceleration due to gravity is 9.81 m/s2
Answer in units of m/s.

Answers

Answer:

7.13781 m/s

Explanation:

X-direction             | Y-direction

[tex]x=v_{xo}t+\frac{1}{2}a_{x}t^2[/tex]      | [tex]y=v_{yo}t+\frac{1}{2}a_{y}t^2[/tex]

[tex]3.41=v_{o}cos(28.4)t[/tex]  | [tex]0.397=v_{yo}sin(28.4)t+\frac{1}{2} (-9.81)t^2[/tex]

[tex]3.41=v_{o}(0.87964)t[/tex]  | [tex]0.397=v_{yo}sin(28.4)(\frac{3.87658}{v_{o} })+\frac{1}{2} (-9.81)(\frac{3.87658}{v_{o} })^2[/tex]

[tex]\frac{3.41}{0.87964}=v_{o}t[/tex]             | [tex]0.397=1.84379-\frac{73.71171}{v^2}[/tex]

[tex]\frac{3.87658}{v_{o} } =t[/tex]                | [tex]7.13781=v[/tex]

Marie curie investigation method

Answers

Answer: To isolate the unknown substances, of which only tiny amounts were present, the Curies were the first to use a new method of chemical analysis. They employed various standard (but sometimes demanding) chemical procedures to separate the different substances in pitchblende.

Explanation:

 explain why earths acceleration is usually very small compared to the acceleration of the object the earth interact with

Answers

Answer:

F-ma

Explanation:

If you are speaking of objects like satellites, etc. then their mass is much less than that of the Earth. A good approximation is Newton's first law of motion:

Force = Mass ×  Acceleration

often written:

F = m a

The gravitational force is the same between the Earth and the object - only the mass differs. So the acceleration is inversely proportional to the mass.

Three vectors, one of 74 km at 30°, the second of 54 km at 135°, and the final of 62 km due South. What is the sum of the three vectors?
- will give brainliest -

Answers

Answer:

The sum of the three vectors are 63.18 km.

Explanation:

Given that,

One vector = 74 km at 30°

Second vector = 54 km at 135°

Third vector = 62 km

We need to calculate the sum of the three vectors

Using given data

[tex]R=\vec{A}\sin\theta+\vec{B}\sin\theta+\vec{C}[/tex]

Put the value into the formula

[tex]R=-74\sin30+54\sin135+62[/tex]

[tex]R=63.18\ km[/tex]

Hence, The sum of the three vectors are 63.18 km.

You are piloting a General Aviation aircraft (e.g. Cessna 172) over the Georgia Tech campus in level flight at 3000 ft altitude. Your airspeed indicator shows that the true airspeed is 100 knots. You have trimmed the aircraft to have no sideslip and pitch angle at a 3 degree angle of attack. Your magnetic compass (which is uncorrected for magnetic variation) indicates that you are flying in the direction of local magnetic East. A local weather forecast predicted the winds to be steady at 10 knots coming exactly from the northeast direction at the time you took off.
a. Using the information provided above and any additional information you may require (state what it is), determine your aircraft's north and east velocity components, Vn and ve, in knots. Starting from Tech Tower at t = 0, you continue in this direction and you are planning to fly directly over a local VOR beacon exactly 10 minutes later. However, you note that you don't pass directly over the beacon and after 10 minutes and 15 seconds have elapsed you are exactly 300 meters away from the VOR beacon in the Easterly direction.
b. Assuming the discrepancy is attributable only to wind speed, estimate the actual average wind speed components, Vwind-n and Vwind-e in knots. Use a flat Earth approximation.
c. Based on the instruments you are using, describe 3 common causes of measurement error that could affect the output of either sensor.

Answers

Answer:

a)  vₓ = 100 + 7.07 = 107.07 knot     (East) ,   v_{y} = 7.07 knot            (North)

b) v_wind_ North = 0 ,   v_wind_West = 61.12 knot      (West)

Explanation:

a) This is a vector velocity addition problem, they tell us that the plane goes East at 100 Knots and the wind goes North East at 10 Knots

the components ask the total speed of the plane.

For this we decompose the wind speed

            cos 45 = v₂ₓ / V₂

            sin 45 = [tex]v_{2y}[/tex] / v₂

            v₂ₓ = v₂ cos 45

           v_{2y} = v₂ sin 45

            v₂ₓ = 10 cos 45 = 7.07 m / s

            v_{2y} = 10 sin45 = 7.07 m / s

the speed of the plane is

            vₓ = v_plane + v₂ₓ

            v_{y} = v_{2y}

            vₓ = 100 + 7.07 = 107.07 knot     (East)

            v_{y} = 7.07 knot            (North)

speed is

            v = (107.07 i ^ + 7.07 j ^) knot

b) Estimated time for Target VOR t = 10 min

for a time of t = 10 min and 15 s, it is at a distance of d = 300 m from the VOR in an easterly direction

find the average speed of time on the ride

in the North direction there is no deviation so the average wind speed is zero

            v_wind_ North = 0

In the east direction

as the estimated time was 10 min and the real time for the distance is 10 min 15 s

the time difference is t = 15 s to travel d = 300 m

with these data we can calculate the speed of the plane

              v = x / t

              v = 300/15

              v = 20 m / s

let's reduce this speed to knot

             v_real = 20 m / s (1knot / 0.5144 m / s) = 38.88 knots

therefore the wind speed is

              v_tral = v_plane + v_wind_Este

              v_wind_Este = v_real - v_avión

               v_wind_Este = 38.88 - 100

                v_wind_Este = -61.12 knot

the negative sign indicates that the wind is going west

                v_wind_West = 61.12 knot (West)

3)

* The compass is not calibrated, to correct the magnetic deviation, therefore it gives an appreciable error in the direction

* The wind speed is taken when leaving, but there is no constant monitoring, so a change in direction or wind speed in the trajectory can significantly affect the results.

* The aircraft may noir throughout the trajectory at level, due to pitch errors

Which of the following does not affect gas pressure

Answers

Answer:

I NEED OPTIONS

Explanation:

You would like to know whether silicon will float in mercury and you know that can determine this based on their densities. Unfortunately, you have the density of mercury in units of kilogrammeter3kilogrammeter3 and the density of silicon in other units: 2.332.33 gramcentimeter3gramcentimeter3. You decide to convert the density of silicon into units of kilogrammeter3kilogrammeter3 to perform the comparison. By which combination of conversion factors will you multiply 2.332.33 gramcentimeter3gramcentimeter3 to perform the unit conversion?

Answers

Answer:

The conversion factors you will use to multiply is 1/0.001 or simply 1000 to perform the unit conversion.

Explanation:

To convert from gram/centimeter³ to kilogram/meter³

First,

NOTE:

1 kilogram = 1000 gram, that is 1 gram = 0.001 kilogram; and

1 meter = 100 centimeter, that is 1 centimeter = 0.01 meter

then,

1 meter³ = 1000000 centimeter³, that is

1 centimeter³ = 0.000001 meter³

Now, we can write that

1 kilogram/meter³ = 1000 gram / 1000000 centimeter³

= 0.001 gram/centimeter³

If 1 kilogram/meter³ = 0.001 gram/centimeter³

Then, 1 gram/centimeter³ = 1/0.001 kilogram/meter³  = 1000 kilogram/meter³

Hence, 1 gram/centimeter³  = 1000 kilogram/meter³

∴The conversion factors you will use to multiply is 1/0.001 or simply 1000 to perform the unit conversion.

That is,

2.33 gram/centimeter³ will be 2.33 × 1000 kilogram/meter³

= 2330 kilogram/meter³

Experiments need to be repeated by the scientist and also replicated by other scientists.

true
false

Answers

Answer:

false

Explanation:  because the other scientists could've missed something in there experiment

what is 100+10000000000000000000

Answers

Answer:

200000000000000000000000

Explanation:

Answer:

10000000000000000100

Explanation:

Which action will cause the induced current to decrease or remain constant?
A. Moving the magnet faster B. Increasing the strength of the magnet
C. Adding more turns to coil. D. Reversing polarity of the magnet.

Answers

Answer:

Its Reversing the polarity of the magnet :)

Explanation:

The action that cause the induced current for reduce or be same is when the polarity is reverse with respect to the magnet.

The following actions should not induced the current:

In the case when the magnet moved in the fastest way. When the magnet strength is increased. And, when the more turns to coil is added.

Therefore we can conclude that the action that cause the induced current for reduce or be same is when the polarity is reverse with respect to the magnet.

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A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 3.54 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 2230 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 5.25 V/m, (b) in the negative z direction and has a magnitude of 5.25 V/m, and (c) in the positive x direction and has a magnitude of 5.25 V/m

Answers

Answer:

(a). The magnitude of the net force is [tex](2.1\times10^{-18}\ N)k[/tex]

(b). The magnitude of the net force is [tex](4.23\times10^{-19}\ N)k[/tex]

(c). The magnitude of the net force is [tex](8.4\times10^{-19}\ N)i+(12.6\times10^{-19}\ N)k[/tex]

Explanation:

Given that,

Magnetic field [tex]B=-3.54\times10^{-3}i\ T[/tex]

Velocity = 2230j m/s

We know that,

The net force acting on the proton is equal to the sum of electric and magnetic force.

[tex]F=F_{e}+F_{B}[/tex]

(a). If the electric field is in the positive z direction and has a magnitude of 5.25 V/m,

We need to calculate the magnitude of the net force acting on the proton

Using formula of net force

[tex]F_{net}=e(E+v\times B)[/tex]

Put the value into the formula

[tex]F_{net}=1.6\times10^{-19}(5.25k+2230\times-3.54\times10^{-3}(j\times i))[/tex]

[tex]F_{net}=1.6\times10^{-19}(5.25k+2230\times-3.54\times10^{-3}(-k))[/tex]

[tex]F_{net}=(2.1\times10^{-18}\ N)k[/tex]

(b). If the electric field is in the negative z direction and has a magnitude of 5.25 V/m,

We need to calculate the magnitude of the net force acting on the proton

Using formula of net force

[tex]F_{net}=e(E+v\times B)[/tex]

Put the value into the formula

[tex]F_{net}=1.6\times10^{-19}(-5.25k+2230\times-3.54\times10^{-3}(j\times i))[/tex]

[tex]F_{net}=1.6\times10^{-19}(-5.25k+2230\times-3.54\times10^{-3}(-k))[/tex]

[tex]F_{net}=(4.23\times10^{-19}\ N)k[/tex]

(c). If the electric field is in the positive x direction and has a magnitude of 5.25 V/m

We need to calculate the magnitude of the net force acting on the proton

Using formula of net force

[tex]F_{net}=e(E+v\times B)[/tex]

Put the value into the formula

[tex]F_{net}=1.6\times10^{-19}(5.25i+2230\times-3.54\times10^{-3}(j\times i))[/tex]

[tex]F_{net}=(8.4\times10^{-19}\ N)i+(12.6\times10^{-19}\ N)k[/tex]

Hence, (a). The magnitude of the net force is [tex](2.1\times10^{-18}\ N)k[/tex]

(b). The magnitude of the net force is [tex](4.23\times10^{-19}\ N)k[/tex]

(c). The magnitude of the net force is [tex](8.4\times10^{-19}\ N)i+(12.6\times10^{-19}\ N)k[/tex]

according to newton’s first law a moving object acted on by a net force of zero....

Answers

Answer:

Newton's first law says that if the net force on an object is zero ( Σ F = 0 \Sigma F=0 ΣF=0\Sigma, F, equals, 0), then that object will have zero acceleration. That doesn't necessarily mean the object is at rest, but it means that the velocity is constant.

Explanation:

According to Newton’s first law of motion, a moving object acted on by a net force of zero will continue in motion.

Newton's first law of motion states that an object in state of rest or uniform motion in a straight line will continue in that state unless it is acted upon by an external force.

This first is also known as the law of inertia because it is the reluctance of an object in motion to stop moving or reluctance of an object at rest to start moving which depends on the mass of the object.

Thus, we can conclude that according to Newton’s first law of motion, a moving object acted on by a net force of zero will continue in motion.

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Which statement describes the direction of the current and the magnetic field when the left hand rule is being used?

Answers

Answer:

They are perpendicular.

Explanation:

In the equation, y = A sin( wt - kx ), obtain the dimensional formula ' w ' and ' k.​

Answers

Answer:

In the given equation y=Asin(ωt−kx)

Since, trigonometric function is a dimensionless quantity. So, (ωt−kx)is also dimensionless quantity.

So,

(ωt−kx)=1

ωt=1

[ω]= 1=[T] ^−1

[T]

kx=1

[k]= 1=[L]^ −1

[L]

A monarchy is the type of government that the colonist do not want true or false

Answers

Answer:

Monarchy is rule from kings and queens

Explanation:

A cell contains 20% solute. If it is placed in a solution with 35% solute, what will happen to the cell?

Answers

i think it will shrink because it will loose or is loosing the water. I am not very sure but i have done my research

An object is moving at 2.50 m/s [E]. At a time 3.00 seconds later the object is traveling at 1.50 m/s
[E]. What was the displacement during this 3.00 second time interval?

Answers

Given parameters:

First velocity  = 2.50m/s

Time of travel = 3s

Second velocity  = 1.50m/s

Unknown:

The displacement during the first interval = ?

Velocity is the displacement of a body with time. Displacement is a distance move in a specific direction by a body.

    Velocity  = [tex]\frac{Displacement}{Time taken}[/tex]

So;

      Displacement  = Velocity x Time taken

Now input the parameter for the first velocity and time of travel;

      Displacement  = 2.5 x 3  = 7.5m

The displacement id 7.5m

Can someone please help me out?

Answers

Explanation:

If you want to get speed, u have to divided distance over time

The lowest speed will lose

To find the speed of each dog you divide the distance by the time.
1st dog- 0.23
2nd dog- 0.27
3rd dog- 0.25
4th dog- 0.22

The 2nd dog will be the fastest because it has the fasted speed/ meter per second of all the dogs

which of the following units is part of the international system of units, or SI?
Pounds meters

ounces inches

Answers

it is meters and ounces

The mass of proton is 1.67x10 kg. How many protons will make a mass of
1,00kg?
1011

Answers

Answer: 938

Explanation:

1.67x10^-27kg (938V/c2)

A car of mass 500kg travelling at 60m/s has it speed reduced to 40m/s by a constant breaking force over a distance of 200m. find car initial kinetic energy. the final kinetic energy​

Answers

Answer:

Ek1 = 900000 [J]

Ek1 = 400000 [J]

Explanation:

In order to solve this problem we must remember that kinetic energy is defined as the product of mass by velocity squared by a medium. Therefore using the following equation we have:

[tex]E_{k1}=\frac{1}{2}*m*v1^{2}[/tex]

where:

m = mass = 500 [kg]

v1 = 60 [m/s]

So we have:

Ek1 = 0.5*500*(60^2)

Ek1 = 900000 [J]

and:

Ek2 = 0.5*500*(40^2)

Ek2 = 400000 [J]

what will happen if a low massive main sequence star runs out of hydrogen fuel?​

Answers

Answer:

Low mass stars are: hydrogen burning in the core while on the Main Sequence. As the hydrogen fuel runs out, extreme pressure raises the temperature to 100 million degrees, where helium burning becomes possible.

The speed of light is 300,000 kilometres per second. This number isn't easy to get a feel for but it's good it's so fast because it allows us to see things instantly on Earth without waiting for the light to arrive.
The Sun is far enough away that light takes an appreciable time to travel to us. Assuming the sun is 150,000,000 kilometres away, how long would it take us to realize if the sun suddenly stopped shining?

Answers

Answer:

499 seconds or a little over 8 minutes

Explanation:

~150 million km/ 300,000 km per second = 500 seconds

What is a point of view with regard to motion called in physics?
O reference grid
O displacement
O distance
O frame of reference

Answers

Answer:

Frame of reference

In 2006, NASA’s Mars Odyssey orbiter detected violent gas eruptions on Mars, where the acceleration due to gravity is 3.7 m/s2. The jets throw sand and dust about 62.0 m above the surface. Scientists estimate that the jets originate as high-pressure gas speeds through vents just underground at about 130 km/h. How much energy per kilogram of material is lost due to nonconservative forces as the high-speed matter forces its way to the surface and into the air? (Express your answer to two significant figures.)

Answers

Answer:

The unit energy losses due to nonconservative forces is 881.40 joules per kilogram.

Explanation:

We can estimate the unit energy losses of gas eruption by Principle of Energy Conservation and Work-Energy Theorem:

[tex]U_{g,1} + K_{1} = U_{g,2}+K_{2}+W_{loss}[/tex] (Eq. 1)

Where:

[tex]U_{g,1}[/tex] - Gravitational potential energy of gas eruptions at surface, measured in joules.

[tex]U_{g,2}[/tex] - Gravitational potential energy of gas eruptions at highest height, measured in joules.

[tex]K_{1}[/tex] - Translational kinetic energy of gas eruptions at surface, measured in joules.

[tex]K_{2}[/tex] - Translational kinetic energy of gas eruptions at highest height, measured in joules.

[tex]W_{loss}[/tex] - Energy losses due to nonconservative forces, measured in joules.

We clear the component associated with energy losses in (Eq. 1):

[tex]W_{loss} = U_{g,1}-U_{g,2}+ K_{1}-K_{2}[/tex]

And we expand it afterwards:

[tex]W_{loss} = m\cdot g\cdot (z_{1}-z_{2}) + \frac{1}{2}\cdot m \cdot (v_{1}^{2}-v_{2}^{2})[/tex] (Eq. 2a)

[tex]w_{loss} = g\cdot (z_{1}-z_{2})+\frac{1}{2}\cdot (v_{1}^{2}-v_{2}^{2})[/tex] (Eq. 2b)

Where:

[tex]W_{loss}[/tex] - Energy losses due to nonconservative forces, measured in joules.

[tex]w_{loss}[/tex] - Unit energy losses due to nonconservative forces, measured in joules per kilogram.

[tex]g[/tex] - Gravitational acceleration, measured in meters per second.

[tex]z_{1}[/tex], [tex]z_{2}[/tex] - Bottom and top height, measured in meters.

[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Gas eruption speeds at surface and highest heights, measured in meters per second.

If we know that [tex]g = 3.7\,\frac{m}{s^{2}}[/tex], [tex]z_{1} = 0\,m[/tex]. [tex]z_{2} =62\,m[/tex]. [tex]v_{1} = 36.111\,\frac{m}{s}[/tex] and [tex]v_{2} = 0\,\frac{m}{s}[/tex], the unit energy losses are:

[tex]w_{loss} = \left(3.7\,\frac{m}{s^{2}} \right)\cdot (62\,m-0\,m)+\frac{1}{2} \cdot \left[\left(36.11\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right][/tex]

[tex]w_{loss} = 881.40\,\frac{J}{kg}[/tex]

The unit energy losses due to nonconservative forces is 881.40 joules per kilogram.

I WILL GIVE YOU BRANILEST!

If a car hits a tree, the tree pushes back on the car. Damage to the car and/or the tree depends on what factors?

Answers

Answer:

Acceleration and mass.

Explanation:

Depends on how heavy the car is and how fast it is going.

F=MA

A train travels 600 km in 4 hours. What is the speed of the train?
0.007 km/h
O 604 km/h
O 150 km/h
O 2,400 km/h

Answers

The speed of the train is 150 Km/h.

Speed can be defined as the distance travelled over a period of time. Mathematically, it can be expressed as:

Speed = Distance / Time

With the above formula, we can obtain the speed of the train as shown below:

Distance = 600 KmTime = 4 hours Speed =?

Speed = Distance / Time

Speed = 600 / 4

Speed = 150 Km/h

Therefore, the speed of the train is 150 Km/h.

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Which platform has touch controls?

A.
consoles
B.
arcades
C.
personal computers
D.
mobiles

Answers

Answer:

I think it's D

Explanation:

Most mobiles have touch screens

Protons have ___charge; they have equal amounts of positive and negative ____charges?

Answers

Protons have positive charges
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