It is true that the slope of titration curve near equivalence point is steep.
How is the slope of the titration curve near the equivalence point?The slope of the titration curve near the equivalence point is steep because there is a rapid change in pH with the addition of small amount of titrant. At the equivalence point, all the analyte has reacted with titrant, and the solution contains only salt and water. Any further addition of titrant causes a rapid increase in pH . The steepness of slope depends on the strength of acid and base involved, as well as their concentrations.
The point at which chemically equivalent quantities of reactants have been mixed is known as equivalence point of a chemical reaction .
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predict the major organic product formed on thermal decarboxylation of the following compound.
The compound given is 3-methyl-2-pentenoic acid.
Thermal decarboxylation of 3-methyl-2-pentenoic acid is a reaction in which the carboxylic acid group is removed from the molecule, resulting in the formation of an alkene.
In this reaction, the acid group is first protonated and then the bond between the alpha carbon and the carboxyl oxygen is broken. The major organic product formed on thermal decarboxylation of 3-methyl-2-pentenoic acid is 2-methyl-1-pentene.
The initial step of the reaction involves the protonation of the carboxylic acid group of 3-methyl-2-pentenoic acid by a strong acid, typically sulfuric acid. This protonation activates the carboxyl group and makes it more susceptible to decarboxylation.
The subsequent step involves the breaking of the bond between the alpha carbon and the carboxyl oxygen, resulting in the loss of carbon dioxide and the formation of the alkene. The formed alkene in this reaction is 2-methyl-1-pentene.
Therefore, the major organic product formed on thermal decarboxylation of 3-methyl-2-pentenoic acid is 2-methyl-1-pentene.
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what is the balanced equation acetic acid and sodium hydroxide ?
The balanced equation for the reaction between acetic acid and sodium hydroxide is
CH3COOH + NaOH → CH3COONa + H2O. This reaction is an example of a neutralization reaction, where an acid and a base react to produce a salt and water.
Acetic acid is an organic compound with the formula CH3COOH. It is a weak acid that dissolves in water to produce a sour or tart flavor. Sodium hydroxide, on the other hand, is a highly reactive compound with the formula NaOH. It is a strong base that reacts with acids to produce salt and water. When acetic acid and sodium hydroxide are mixed, a reaction occurs. The equation for this reaction is given below:
CH3COOH + NaOH → CH3COONa + H2O
In this equation, CH3COOH represents acetic acid, NaOH represents sodium hydroxide, CH3COONa represents sodium acetate, and H2O represents water. The equation is balanced, meaning that the same number of atoms of each element is present on both the reactant and product sides of the equation. The balanced equation above shows that acetic acid reacts with sodium hydroxide to form sodium acetate and water. The reaction between acetic acid and sodium hydroxide is an example of a neutralization reaction. This type of reaction occurs when an acid and a base react to form a salt and water.
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what is the partial pressure of argon gas in a mixture of gases that contains 0.50 moles of helium, 1.5 moles of argon, and 2.5 moles of neon? the total pressure of the mixture is 1.6 atm.
When answering questions on the Brainly platform, it is important to always be factually accurate, professional, and friendly. It is also important to be concise and not provide extraneous amounts of detail, while using the relevant terms from the student question.Here is the answer to the student's question:
To calculate the partial pressure of argon gas in a mixture of gases, we can use the following formula:Partial pressure of gas = (Moles of gas / Total moles of gas) x Total pressure of mixture Given that the mixture of gases contains 0.50 moles of helium, 1.5 moles of argon, and 2.5 moles of neon and the total pressure of the mixture is 1.6 atm, we can find the partial pressure of argon as follows:Total moles of gas = 0.50 + 1.5 + 2.5 = 4.5 moles Moles of argon gas = 1.5 moles Partial pressure of argon gas = (1.5 / 4.5) x 1.6 atm= 0.5 x 1.6 atm= 0.8 atm Therefore, the partial pressure of argon gas in the given mixture of gases is 0.8 atm.
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write the formula and name of a compound formed from the ionic interaction between a ion and ion. both ions are isoelectronic with the atoms of a chemically unreactive period element.
The compound formed from the ionic interaction between a ion and ion is CsF (Cesium Fluoride). Both ions are isoelectronic with the atoms of a chemically unreactive period element. The Cs+ ion is isoelectronic with Xe while the F− ion is isoelectronic with Ne.
An isoelectronic species refers to atoms, molecules, or ions that have the same number of electrons. Isoelectronic species can include ions and neutral atoms that share the same number of electrons. The number of protons in the nucleus may be different for isoelectronic species, but the number of electrons is the same.
An ionic compound refers to a chemical compound formed by the combination of oppositely charged ions. In general, ionic compounds are formed between metallic and non-metallic elements. In ionic compounds, cations and anions combine to form a crystal lattice structure. These compounds are held together by strong electrostatic forces between oppositely charged ions. The resulting ionic bond is a strong bond, which makes ionic compounds quite stable.
CsF is the chemical formula for Cesium Fluoride. It is an ionic compound formed by the combination of cesium cation (Cs+) and fluoride anion (F-). CsF is a white crystalline solid at room temperature with a melting point of 684°C. It is commonly used in the synthesis of fluorinated organic compounds.
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How do you calculate % transmission
Answer:
you will have to use T = 1/10
Select the chemical equation that most likely represents the reaction between the vinegar and the dolomite.
Answer:
Explanation: Hello Sonic, the explanation and answer to your question is that When vinegar (acetic acid) is mixed with dolomite (a mineral composed of calcium magnesium carbonate), a chemical reaction occurs. The acetic acid reacts with the calcium and magnesium ions in the dolomite, causing them to dissolve into the vinegar solution. This results in the formation of calcium acetate and magnesium acetate, which are soluble in water. The chemical equation for this reaction is: CaMg(CO3)2 + 2CH3COOH → Ca(CH3COO)2 + Mg(CH3COO)2 + H2O + CO2 In this equation, CaMg(CO3)2 represents dolomite, CH3COOH represents acetic acid, Ca(CH3COO)2 represents calcium acetate, Mg(CH3COO)2 represents magnesium acetate, H2O represents water, and CO2 represents carbon dioxide gas. The reaction also produces bubbles of carbon dioxide gas, which can be seen as the mixture fizzes and bubbles. Overall, the reaction between vinegar and dolomite is an example of an acid-base reaction, where the acetic acid acts as the acid and the dolomite acts as the base. This reaction can be used to dissolve dolomite rocks or to create calcium and magnesium acetate solutions for various applications. Hope this helps :)
Calculate the energy required to melt 40.3 g of ice at 0 oC.
The molar heat of fusion for ice is 6.02 kJ/mol.
the energy required to melt 40.3 g of ice at 0 oC.The molar heat of fusion for ice is 6.02 kJ/mol. the energy required to melt 40.3 g of ice at 0 oC is 13.5 kJ.
The energy required to melt a substance is given by the formula:
q = nΔH_fus
where q is the heat absorbed or released during the phase change, n is the number of moles of the substance undergoing the phase change, and ΔH_fus is the molar heat of fusion of the substance.
To apply this formula to the melting of 40.3 g of ice at 0 oC, we first need to calculate the number of moles of ice present:
moles of ice = mass of ice / molar mass of ice
moles of ice = 40.3 g / 18.015 g/mol
moles of ice = 2.235 mol
Next, we can use the formula for q to calculate the energy required to melt the ice:
q = nΔH_fus
q = 2.235 mol × 6.02 kJ/mol
q = 13.5 kJ
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classify the radicals into the appropriate categories. Primary. Secondary. Tertiary. Allylic.
The classification of radicals are :
(CH₃)CHCH₂CH₂ = The Secondary radical
(CH₃)CHCHCH₃ = The Tertiary radical
H₂C = The Primary radical
The radical is the atom or the molecule with the unpaired electron. The unpaired electron will gives the radical the chemical reactivity, as it is the highly reactive because of the unpaired electron.
The Primary free radicals: When the radical is attached to the two H-atoms.
The Secondary free radicals: When the radical is attached to the one H-atoms.
The Tertiary free radicals: When the radical is not attached to the any Hydrogen atoms.
The unpaired electron in the free radical is the highly reactive, the leading to the radical reactions that can be the important in the many chemical processes.
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This question is incomplete, the complete question is :
classify the radicals into the appropriate categories. Primary. Secondary. Tertiary. Allylic.
(CH₃)CHCH₂CH₂, (CH₃)CHCHCH₃, H₂C
Determine the volume of a concentrated solution needed for dilution Question A stock solution has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L. What was the volume of the stock solution? • Your answer should have two significant figures. Provide your answer below: FEEDBACK MORE INSTRUCTION SUBMIT Content attribution
The volume of the stock solution needed for dilution is 0.065 L.
How to find the volume of concentrated solution needed for dilution?
To determine the volume of the stock solution needed for dilution, we can use the dilution formula: C1V1 = C2V2, where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Given:
C1 = 1.5 M (concentration of the stock solution)
C2 = 0.54 M (final concentration after dilution)
V2 = 0.18 L (final volume)
We need to find V1, the volume of the stock solution.
Using the formula: C1V1 = C2V2, we can solve for V1:
V1 = (C2V2) / C1
V1 = (0.54 M × 0.18 L) / 1.5 M
Now, calculate the value:
V1 ≈ 0.065 L
With two significant figures, the volume of the stock solution needed for dilution is 0.065 L.
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explain the importance of lignin decomposition on the rise and fall of o2 levels during the carboniferous
Lignin decomposition played a crucial role in the rise and fall of oxygen levels during the Carboniferous period.
During the Carboniferous period, forests covered vast areas of the Earth, and the growth of trees and plants led to the accumulation of lignin in soils and sediments. Lignin is a complex organic polymer that is resistant to decomposition, and its buildup in the soil prevented the complete decay of organic matter.
As a result, oxygen was continually produced and released into the atmosphere through photosynthesis, while the carbon that was not decomposed was stored in the form of coal.
However, as the amount of lignin increased over time, the rate of oxygen production eventually reached a plateau, and the oxygen levels in the atmosphere began to decline. As lignin-rich organic matter accumulated in the soil and was buried over time, the oxygen levels continued to fall, and the carbon in the soil was converted into coal through heat and pressure.
Overall, lignin decomposition played a critical role in shaping the atmospheric conditions during the Carboniferous period, and its buildup and eventual burial had a significant impact on the rise and fall of oxygen levels on Earth.
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which indicator would be the best to use for a titration between 0.30 m c6h5cooh with 0.30 m naoh? you will probably need to consult the appropriate table in the book.
The best indicator to be used is Phenolphthalein.
Phenolphthalein changes color from colorless to pink as the solution becomes basic, which is ideal for this titration as the endpoint is when all the benzoic acid has reacted with the sodium hydroxide to form sodium benzoate, which is basic.
It is important to note that the equivalence point for this titration is not at a pH of 7, as it would be for the titration of a strong acid with a strong base. Instead, the equivalence point for the titration of a weak acid with a strong base is above a pH of 7, closer to a pH of 8-10.
Hence, Phenolphthalein would be the best indicator to use for a titration between 0.30 M [tex]C_6H_5COOH[/tex] with 0.30 M NaOH.
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calculate the ph for each case in the titration of 50.0 ml of 0.200 m hclo(aq) with 0.200 m koh(aq). use the ionization constant for hclo. what is the ph after the addition of 40.0 ml koh? g
The pH of the solution in case of titration after the addition of 40.0 ml KOH is 21.07.
The given balanced chemical equation is HClO (aq) + KOH (aq) → KClO (aq) + H2O (l).Calculate the pH for each case in the titration of 50.0 ml of 0.200 M HClO (aq) with 0.200 M KOH (aq). The ionization constant for HClO is given asKa = 3.0 × 10-8. To calculate the pH of the solution, we use the following formula:
pH = - log10[H+], The number of moles of HClO is: Moles = Molarity × Volume, Moles = 0.200 mol/L × 50.0 mL × 1 L/1000 mL = 0.010 mol. The number of moles of HClO decreases by the number of moles of KOH. Therefore, the number of moles of HClO left in the solution is0.010 mol - 0.008 mol = 0.002 mol. The number of moles of KClO formed is equal to the number of moles of KOH added, which is0.008 mol.
The number of moles of HClO that has reacted is also equal to the number of moles of KClO formed, which is0.008 mol. The number of moles of HClO remaining in the solution is 0.010 mol - 0.008 mol = 0.002 mol. The concentration of HClO is 0.002 mol/60.0 mL = 0.033 M. The concentration of KOH is0.008 mol/90.0 mL = 0.089 M. Using the ionization constant, we can calculate the pH for the titration of HClO with KOH, pH = pKa + log([A-]/[HA])
The H+ concentration is calculated as follows:[H+] = Ka × [HA] / [A-][H+] = (3.0 × 10-8) × 0.002 mol / 0.008 mol[H+] = 7.5 × 10-9 mol/L. The pH of the solution after the addition of KOH is pH
= 14.00 - pOHpOH
= - log10[OH-]pOH
= - log10(0.089)pOH = 1.05pH = 14.00 - 1.05 - log10[H+]pH = 12.95 - log10(7.5 × 10-9)pH = 12.95 + 8.12pH = 21.07
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What is borohydride reduction of vanillin to vanillyl alcohol ?
Identify the type of symbiotic relationship described in each scenario.
Some wasps lay their eggs on caterpillars called tomato hornworms. When the eggs hatch, the young wasps burrow
into the caterpillar's body and eat it alive. The adult wasps then fly away. This is an example of
The described scenario is an example of parasitism.
Parasitism is a type of symbiotic relationship in which one species benefits while the other is harmed. In this case, the wasps benefit by using the caterpillar as a host for their young, which ultimately leads to the death of the caterpillar.
The caterpillar, on the other hand, is harmed as its body is used as a food source for the developing wasp larvae, ultimately leading to its death. This type of interaction is common in nature, with many species relying on others as a source of food or shelter, even if it comes at the cost of the host's well-being.
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name the compound so2 using the stock system.PLS HELPP ASAPP
Answer:SO2 is a covalent compound made up of sulfur and oxygen atoms, so the stock system is not applicable here as it is used for naming compounds that contain metal ions with different oxidation states.Instead, the IUPAC (International Union of Pure and Applied Chemistry) name for SO2 is sulfur dioxide.
Explanation:So I helped you help me please
The compound SO₂ is named sulfur dioxide using the Stock system.
In the Stock system, the names of chemical compounds are based on the oxidation states of the elements involved. The oxidation state refers to the charge that an atom carries when it forms a compound.
Sulfur (S) has an oxidation state of +4, and oxygen (O) has an oxidation state of -2. The compound's name reflects these oxidation states.
Combining the elements and their oxidation states, the compound is named "sulfur(IV) oxide" using the Stock system. However, it is more commonly known as sulfur dioxide, which is the traditional name for the compound.
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Arrange these species by their ability to act as an oxidizing agent. Best oxidizing agent Au3+ Fe2+ 2+ Na+ Poorest oxidizing agent Answer Bank
AlthoughNa⁺ and Fe²⁺ are typically weaker oxidising agents than Au³⁺ , this may not always be the case in every process.
An oxidizing agent is a species that causes oxidation by accepting electrons or donating oxygen, and therefore it is characterized by having a high oxidation state. In general, the ability to act as an oxidizing agent increases as the oxidation state of the species increases. Based on this, we can arrange the given species in order from best to poorest oxidizing agent as follows:
Au³⁺ > Fe²⁺ > Na⁺
Among these species, Au³⁺ has the highest oxidation state and therefore the strongest ability to act as an oxidizing agent. Fe²⁺ has a lower oxidation state than Au³⁺, but it is still capable of acting as an oxidizing agent in certain reactions. Na⁺ has the lowest oxidation state of the three and is therefore the poorest oxidizing agent among them.
It's important to note that the ability to act as an oxidizing agent also depends on other factors, such as the nature of the other reactants involved and the reaction conditions.
Therefore, while Au³⁺ is generally a stronger oxidizing agent than Fe²⁺ and Na⁺, this may not always be the case in every reaction.
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which compound will exhibit hydrogen bonding with itself in the liquid state? question 9 options: a) ch3och3 b) h2co c) ch3coch3 d) ch3ch2nh2 e) ch3f
The compound that will exhibit hydrogen bonding with itself in the liquid state is CH3CH2NH2.
What is hydrogen bonding?Hydrogen bonding is a special kind of dipole-dipole attraction in which hydrogen is bonded to an element like oxygen, nitrogen, or fluorine. Hydrogen bonding is stronger than Van der Waal's forces but weaker than covalent, ionic or metallic bonds.
An explanation for the given alternatives:
a) CH3OCH3 will not exhibit hydrogen bonding with itself in the liquid state.
b) H2CO will not exhibit hydrogen bonding with itself in the liquid state.
c) CH3COCH3 will not exhibit hydrogen bonding with itself in the liquid state.
d) CH3CH2NH2 will exhibit hydrogen bonding with itself in the liquid state.
e) CH3F will not exhibit hydrogen bonding with itself in the liquid state.
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how does having waters of hydration affect the enthalpy for dissolving?
The presence of waters of hydration can affect the enthalpy of a substance when it is dissolved. Hydration occurs when a substance is surrounded by or interacts with water molecules.
When a substance is dissolved, the attraction between the solute molecules and the water molecules can cause an increase in the enthalpy of the reaction. This is because more energy is needed to separate the molecules and allow them to interact with the solvent. When hydrated, how does water affect the enthalpy for dissolving?The addition of waters of hydration increases the enthalpy of dissolving.The enthalpy change of dissolving a compound refers to the heat energy absorbed or released when the compound dissolves in water
. Hydration water is present in most solids. This water exists as coordinated water molecules that are bound to the ions present in the solid. As a result, when a compound dissolves in water, hydration water is also present. As a result, when a substance dissolves in water, it consumes energy to break the water's hydrogen bonds and dissolve the compound's particles. The enthalpy change of dissolving a compound is affected by the number of water molecules consumed in the hydration process. The enthalpy of dissolving a compound rises as the number of hydration water molecules increases.
Hence, when water is used to hydrate a substance, it raises the enthalpy of dissolution.The enthalpy of hydration is the energy required to hydrate a mole of ions. The hydration energy is released when the ions and water molecules interact, and the hydration shells form around the ions. The enthalpy change of dissolving a compound, like the enthalpy of hydration, is influenced by the hydration process. The enthalpy of hydration, on the other hand, is negative because it is a release of energy. The hydration energy offsets some of the energy needed to dissolve the compound's particles, resulting in a lower enthalpy of dissolving.
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two conformations of the same disaccharide are shown on the right. the top conformation has a much lower free energy than the conformation on the bottom. why do you think this is the case?
The two conformations of the same disaccharide shown on the right likely differ in their free energy levels due to the arrangement and interactions of their constituent molecules. The top conformation, with a lower free energy, is likely more stable because of the formation of favorable interactions, such as hydrogen bonding, between the mono saccharide units, and a more optimal orientation of their functional groups.
In addition, the lower free energy conformation could be attributed to a reduced level of steric hindrance, where the spatial arrangement of the atoms in the disaccharide allows for minimal clashes and more efficient packing of the molecule. This can lead to a more stable and energetically favorable structure.
Moreover, the stability of the top conformation may be further enhanced by the presence of intramolecular forces, such as van der Waals interactions and hydrophobic effects. These interactions can significantly contribute to the overall stability of the molecule and subsequently result in a lower free energy state.
In summary, the top conformation of the disaccharide likely has a lower free energy due to a combination of factors, including favorable interactions between the monosaccharide units, optimal orientation of functional groups, reduced steric hindrance, and the presence of intramolecular forces. These factors collectively contribute to a more stable and energetically favorable molecular structure.
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consider the molecule h79br and its isotopic exchanged molecules, deuterated molecule d79br and bromine exchanged molecule h81br. using the bond length of h79br calculated in previous question, compute the change in rotational constant for the other two molecules. briefly comment on how isotopic exchange changes the rotational spectra. does the exchange of 1 h or 79br have a greater effect?
The rotational constant, B, of a molecule depends on its deuterated molecule mass and bond length. Isotopic exchange can change both of these parameters and therefore alter the rotational spectra of a molecule.
For the deuterated molecule, D79Br, the reduced mass will increase because the mass of the hydrogen atom is replaced with the heavier deuterium atom. The bond length is not expected to change significantly. The increased reduced mass will result in a decrease in the rotational constant, B, compared to H79Br.
For the bromine exchanged molecule, H81Br, the reduced mass is expected to be similar to that of H79Br, but the bond length will be longer due to the larger size of the 81Br isotope. The longer bond length will result in a decrease in the rotational constant, B, compared to H79Br.
Isotopic exchange generally decreases the rotational constant, B, because it increases the reduced mass or changes the bond length. The exchange of 1H or 79Br has a greater effect on the rotational spectra of a molecule depends on their relative contribution to the reduced mass and bond length of the molecule. In the case of H79Br, the bond length is largely determined by the H-Br bond, so the exchange of 79Br has a greater effect on the rotational spectra than the exchange of 1H. However, the effect of isotopic exchange on the rotational spectra can be complex and may also depend on other factors, such as the electronic structure of the molecule.
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Add formal charges to each resonance form of HCNO. (Feedback The number of valence electrons in each free atom is H = 1,C =4 N = 5,and 0 = 6. The number of nonbonding electrons on an atom is equal t0 the number of dots around the atom: The number of bonding electrons is equal to twice the number of bonds t0 the atom Resonance structure A Resonance structure For example, in the arrangement {C=j carbon has two nonbonding electrons and six bonding electrons (three bonds) The formal charge on this carbon atom is Incorrect formal charge C = 4 - 2
The formal charges ought to add up to the molecule's overall charge, which for HCNO is zero. The genuine electronic circulation in HCNO is a cross breed of the two reverberation structures displayed here.
What is HCNO?Isocyanic acid, which is a small, unstable molecule made up of hydrogen, carbon, nitrogen, and oxygen atoms, has the chemical formula HCNO. It has the construction HNCO or H-O=C=N, where the nitrogen particle is clung to both the carbon and oxygen iotas through twofold bonds. At room temperature, isocyanic acid is a colorless gas that is very reactive, making it difficult to isolate and study. Numerous organic compounds, including ureas, carbamates, and biurets, are synthesized using this important intermediate. The thermal decomposition of urea also has the potential to produce it.
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you are given 0.725 grams of a white powder and told that it is a mixture of potassium carbonate and sodium carbonate. you are asked to determine the percent composition by mass of the sample. you add some of the sample to 10.00 ml of 0.9947 m nitric acid until you reach the equivalence point. when you have added enough carbonate to completely react with the acid, you reweigh your sample and find that the mass is 0.171 g. calculate the mass of the sample that reacted with the nitric acid. calculate the moles of nitric acid that reacted with the sample.
The moles of nitric acid that reacted with the sample is 0.09947 mol.
The given problem requires you to determine the percent composition by mass of the sample which is a mixture of potassium carbonate and sodium carbonate. To do this, you must first calculate the mass of the sample that reacted with the nitric acid and the moles of nitric acid that reacted with the sample.
Given:
Mass of white powder = 0.725 g
Mass of sample after reaction = 0.171 g
Volume of nitric acid = 10.00 ml
Molarity of nitric acid = 0.9947 M
Step 1: Calculate the mass of the sample that reacted with the nitric acid.
Mass of sample that reacted with nitric acid = Mass of white powder – Mass of sample after reaction
Mass of sample that reacted with nitric acid = 0.725 g – 0.171 g
Mass of sample that reacted with nitric acid = 0.554 g
Step 2: Calculate the moles of nitric acid that reacted with the sample.
Moles of nitric acid that reacted with the sample = (Volume of nitric acid x Molarity of nitric acid)/1000
Moles of nitric acid that reacted with the sample = (10.00 ml x 0.9947 M)/1000
Moles of nitric acid that reacted with the sample = 0.09947 mol
Therefore, the mass of the sample that reacted with the nitric acid is 0.554 g and the moles of nitric acid that reacted with the sample is 0.09947 mol.
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After determining the amount of moles required for one of the reactants, it was shown that was the limiting reactant and was the excess reactant.
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You can identify the limiting reactant and the surplus reactant in a chemical reaction if you know how many moles are needed for one of the reactants.
To do this, compare the number of moles of the necessary reactant to that of the accessible reactant. The limiting reactant is the one that results in the smallest quantity of product, and the excess reactant is the one that results in the most significant amount of product.
StepsConsider a reaction where 4 moles of the product are produced from 2 moles of reactant A and 3 moles of reactant B. The following calculation can be used to identify the limiting reactant if you have 4 moles of reactant A and 6 molecules of reactant B:
4 moles of reactant A / 2 moles required of reactant A equals 2.
6 moles of reactant B divided by 3 molecules of reactant B needed equals 2.
There is no surplus because both reactants yield the same amount of product, meaning they are both fully utilized. One reactant would be limiting and the other would be in excess of the computations that had yielded a different result.
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Answer:
After determining the amount of moles required for one of the reactants, it was shown that ✔ copper was the limiting reactant and ✔ sulfur was the excess reactant.
Explanation:
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which of these pairs of elements is least likely to combine to form an ionic bond?a. carbon and oxygen
b. sodium and fluorine
c. sulfur and hydrogen
d. phosphorus and oxygen
Answer:(part a) Lithium and Chlorine, (part c) Potassium and Oxygen are likely to form an ionic compound.
Explanation:
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Calculate (a) the moles and (b) the mass of magnesium carbonate at the start if 0. 200 moles of sulfuric acid is added to the magnesium carbonate and the excess sulfuric acid made up to a 250 cm3 solution. 25. 0 cm3 of this solution required 0. 0300 moles of sodium hydroxide for neutralisation
The number of moles of MgCO₃ is also 0.200 moles and the mass of magnesium carbonate at the start was 16.86 g.
The balanced chemical equation for the reaction between sulfuric acid (H₂SO₄) and magnesium carbonate (MgCO₃) is:
H₂SO₄ + MgCO₃ → MgSO₄ + CO₂ + H₂O
From the balanced equation, we can see that one mole of sulfuric acid reacts with one mole of magnesium carbonate to produce one mole of magnesium sulfate, one mole of carbon dioxide, and one mole of water.
The moles of magnesium carbonate at the start can be calculated from the number of moles of sulfuric acid that reacted with it, using the mole ratio from the balanced equation:
1 mole of MgCO₃ will reacts with 1 mole of H₂SO₄
Therefore, the number of moles of MgCO₃ is also 0.200 moles.
The mass of magnesium carbonate at the start can be calculated using its molar mass and the number of moles:
molar mass of MgCO₃ = 24.31 g/mol (for Mg) + 12.01 g/mol (for C) + 3(16.00 g/mol) (for 3 O) = 84.31 g/mol
mass of MgCO₃ = number of moles × molar mass
mass of MgCO₃ = 0.200 moles × 84.31 g/mol
mass of MgCO₃ = 16.86 g
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there are two naturally occuring isotopoes of silver-107 and silver-109 what is the approximate ratio of isotopes in a naturally occuring sample of silver?
12a. sigma complexes are the intermediates for electrophilic aromatic substitution (eas). what are the intermediate complexes for nucleophilic aromatic substitution (snar) called
Sigma complexes are the intermediates for electrophilic aromatic substitution (eas). The intermediate complexes for nucleophilic aromatic substitution (SNAR) are called: pi complexes.
Pi complexes form when a nucleophile, or electron-rich species, attacks an electron-deficient atom in an aromatic ring. This attack displaces the electron-deficient atom, and a pi bond is formed between the nucleophile and the aromatic ring. The displacement of the electron-deficient atom results in the formation of an intermediate pi complex.
The pi complex is a key intermediate in SNAR reactions. The pi complex can then be attacked by another nucleophile, resulting in the formation of a new aromatic compound. During this reaction, the aromaticity of the ring is maintained and the stability of the pi complex is increased.
The pi complex is a key intermediate in the EAS mechanism. In order for the reaction to take place, the pi complex must be stable. This means that the electrons must be properly distributed around the ring and the nucleophile must be strongly bound to the electron-deficient atom.
This stability helps to ensure that the reaction will proceed efficiently and that the desired product is formed. In conclusion, the intermediate complexes for nucleophilic aromatic substitution (SNAR) are called pi complexes. Pi complexes form when a nucleophile attacks an electron-deficient atom in an aromatic ring.
The displacement of the electron-deficient atom results in the formation of an intermediate pi complex, which is then attacked by another nucleophile, resulting in the formation of a new aromatic compound. The stability of the pi complex is essential for the successful completion of the reaction.
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Why was it necessary to build and use WIPP
Answer:
The Waste Isolation Pilot Plant, or WIPP, is the world's first underground repository licensed to safely and permanently dispose of transuranic radioactive waste left from the research and productions of nuclear weapons.
a sample of hydrogen gas at 273 k has a volume of 4.4 l at 4.9 atm pressure. you may want to reference (pages 227 - 230) section 8.5 while completing this problem part a what is the volume if the pressure is increased to 11.1 atm ? express your answer using two significant figures.
With a pressure rise to 11.1 atm, the hydrogen gas volume is 2.03 L.
To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas. The equation for the combined gas law is:
P₁V₁/T₁ = P₂V₂/T₂
Where P₁, V₁, and T₁ are the initial pressure, volume, and temperature, respectively, and P₂, V₂, and T₂ are the final pressure, volume, and temperature, respectively.
We can rearrange this equation to solve for V₂:
V₂ = (P₁V₁T₂)/(P₂T₁)
We are given that the initial volume (V₁) is 4.4 L, the initial pressure (P₁) is 4.9 atm, and the final pressure (P₂) is 11.1 atm. We are asked to find the final volume (V₂) when the pressure is increased to 11.1 atm.
We can assume that the temperature (T₁) is constant, since it is not specified otherwise. Therefore, we can substitute the values into the equation and solve for V₂:
V₂ = (P₁V₁T₂)/(P₂T₁)
V₂ = (4.9 atm)(4.4 L)(273 K)/(11.1 atm)(273 K)
V₂ = 2.03 L
Therefore, the volume of the hydrogen gas is 2.03 L when the pressure is increased to 11.1 atm.
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which of the following pairs of elements are likely to form ionic compounds? check all that apply. which of the following pairs of elements are likely to form ionic compounds?check all that apply. chlorine and bromine sodium and potassium potassium and sulfur magnesium and chlorine helium and oxygen nitrogen and iodine
Answer:
Magnesium and Chlorine
Potassium and Sulfur
Explanation:
Ionic compounds form between a metal and a non-metal
Magnesium & Chlorine and Potassium & Sulfur will form ionic compounds due to Magnesium and Potassium being metals while Chlorine and Sulfur are non metals.
Elements also have to have a large difference in electronegativity as one atom has to lose its electron to the other atom.