The snow globe below is formed by a hemisphere and a cylinder on a cylindrical
base. The dimensions are shown below. The base is slightly wider than the globe
with a diameter of 10cm and height of 1cm.
10 cm
4cm
3cm
Part C: If each globe is individually packaged into a box, what are the minimum
dimensions of the box?

The circumference of a circle with a diameter of 8.7 units is approximately 27.318 units, calculated using the formula Circumference = πd. So, the correct answer is D).

The formula for the circumference of a circle is given by

Circumference = πd

where d is the diameter of the circle.

Substituting the given value of the diameter of circle a, we get:

Circumference = π x 8.7

Using the approximation of π = 3.14, we get

Circumference = 3.14 x 8.7

Circumference = 27.318 units (rounded to three decimal places)

Therefore, the circumference of the circle with a diameter of 8.7 units is approximately 27.318 units. So, the correct option is D).

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--The given question is incomplete, the complete question is given

" The diameter of circle a is 8.7 units. find the circumference of the circle.

a. 17.4 units

b. 75.69 unit

c. 8.7 units

d. 27.318 units "--

The actual length of the truck is 15.6 meters and the actual width is 3.24 meters.

The actual length of the truck can be calculated by multiplying the length of the model by the scale factor:

Similarly, the actual width of the truck can be calculated as:

Therefore, the actual length of the truck is 15.6 meters and the actual width is 3.24 meters.

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If the vertex of a parabola is at (5,0) and it opens UPWARD, it will have one solution.

Since the parabola opens upward, its vertex is the minimum point, and therefore, it will have only one solution.

A parabola is a U-shaped curve in mathematics that can be formed by the graph of a quadratic function. It is a type of conic section, along with circles, ellipses, and hyperbolas.

Mathematically, a parabola can be defined as the set of all points in a plane that are equidistant from a fixed point called the focus and a fixed line called the directrix. The focus lies on the axis of symmetry of the parabola, and the directrix is perpendicular to the axis of symmetry.

If the vertex of a parabola is at (5,0) and it opens UPWARD, it will have one solution.

Your answer: one

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If for "c" tickets, Suzie paid an amount of $324, then the cost of each ticket is represented by "324/c".

The number of tickets that Suzie bought is = c tickets, and

Let "x" be the cost of "each-ticket for "rock-festival".

The total amount spent for "c" tickets is = $324,

Therefore, we can write the cost-equation as;

⇒ c × x = 324,

To find the value of "x", we solve for it by dividing both sides of the equation by "c":

⇒ x = 324/c,

So, the cost of each ticket is $324 divided by the number of tickets "c" that Suzie bought.

Therefore, Each tickets cost is 324/c.

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Part A: The equation to represent this situation is: 0.50x + 3 = 18.50
Part B: The equation to represent this situation is: 0.75x + 3 - 0.10x = 21.00
Part C: The equations differ in the following ways:
1. Sydney's equation involves only the price per cup and the tip, while Daria's equation also considers the cost of the plastic cups.
2. The price per cup for Sydney and Daria are different.

Part A: The equation to represent this situation is:

18.50 = 0.50x + 3

Where x represents the number of cups of lemonade sold.

Part B: The equation to represent this situation is:

21.00 = 0.75x + 3 - 0.10x

Where x represents the number of cups of lemonade sold.

Part C: The equations from Part A and Part B differ in that Part B takes into account the cost of each plastic cup used to serve the lemonade, while Part A only considers the revenue from selling each cup of lemonade and the tip received. This means that the profit in Part B is calculated after deducting the cost of each plastic cup from the revenue earned, while the profit in Part A does not account for any costs incurred.

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If the largest single rough diamond ever found, the Cullinan diamond, weighed 3106 carat, it weighs approximately 621,200 milligrams and 1.37 pounds.

The Cullinan Diamond, the largest single rough diamond ever found, weighed 3,106 carats. To convert its weight to milligrams and pounds, we'll use the conversion factor of 1 carat = 0.2 grams.

First, convert carats to grams:
3,106 carats * 0.2 grams/carat = 621.2 grams

Next, convert grams to milligrams:
621.2 grams * 1,000 milligrams/gram = 621,200 milligrams

Lastly, convert grams to pounds:
621.2 grams * 0.00220462 pounds/gram ≈ 1.37 pounds

So, the Cullinan Diamond weighs approximately 621,200 milligrams and 1.37 pounds.

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The cost of a flight from Hong Kong to Tokyo with Galois Airways is 1429.99 HKD.

We start by calculating the Porson's product-moment correlation coefficient between the distance and airfare data. The value of the correlation coefficient ranges from -1 to +1. A value of -1 indicates a perfect negative correlation, 0 indicates no correlation, and +1 indicates a perfect positive correlation.

In this case, the correlation coefficient between distance and airfare for Galois Airways flights is 0.948, indicates a strong positive correlation between the distance and airfare.

The regression line is expressed as:

y = a + bx

where y is the dependent variable (airfare), x is the independent variable (distance), a is the intercept (the value of y when x is zero), and b is the slope (the change in y for a one-unit change in x).

The regression equation for Galois Airways flights is:

y = 553.51 + 0.292x

Now, we can use the regression equation to estimate the cost of a flight from Hong Kong to Tokyo, which is 2900 km away.

y = 553.51 + 0.292(2900) = 1429.99 HKD

Therefore, we estimate that the cost of a flight from Hong Kong to Tokyo with Galois Airways is 1429.99 HKD.

Finally, we need to explain why it is valid to use the regression equation to estimate the airfare between Hong Kong and Tokyo. We can do this by examining the assumptions of linear regression. The two main assumptions are that there is a linear relationship between the variables, and that the residuals (the differences between the actual and predicted values) are normally distributed with constant variance.

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Complete question is  Galois Airways has flights from Hong Kong International Airport to different destinations. The following table shows the distance, x kilometres, between Hong Kong and the different destinations and the corresponding airfare, y, in Hong Kong dollars (HKD) Destination Bali, Sydney, Bengaluru. Auckland, Bangkok, Indonesia Australia India Singapore New Thailand Zealand 3400 7400 4000 2600 9200 1700 Distance x, (km Airfare y, (HKD) 1550 3600 2800 1300 4000 1400 The Porson's product-moment correlation coefficient for this data is 0.948, correct to three significant figures. Use your prophio display calculator to find the equation of the regression line y on x.  b. The distance from Hong Kong to Tokyo is 2900 km. Use your regression equation to estimate the cost of a flight from Hong Kong to Tokyo with Calois Airways. c. Explain why it is valid to use the regression equation to estimate the airfare between Hong Kong and Tokyo.

-3.8 is the slope of the secant line connecting (1, f(1)) and (9, f(9)).

To get the slope of the secant line, we must first compute the values of f(1) and f(9):

f(1)

= 1² - 5(1)

= -4

f(9)

= 9² - 5(9)

= 36 - 45

= -9

The formula for the slope of the secant line running between these two locations is:

slope = (y-change)/(x-change)

= (f(9)-f(1))/(9-1)

Substituting f(1) and f(9) values and simplifying yields slope ,

= (-9-(-4))/(9-1)

= -5/8

= -0.625

When we round this to two decimal places, we get:

slope = -0.63

The slope of the secant line connecting (1, f(1)) and (9, f(9)) is thus -0.63.

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The best prediction possible for the number of times you will roll a one number when a 6-sided die is rolled 12 times = (0.167)¹²

Events occur as the outcome of an experiment. But one cannot be satisfied with these events until a degree of measurement of the likeliness of its occurrence is not provided. Probability is a statistical tool used widely to obtain predictive value.

Here, 6-sided die rolled 12 times.

If a 6-sided die is rolled, possible outcomes are {1, 2, 3, 4, 5, 6}

So, total number of outcomes = 6

So, number of favorable outcomes = 1

Probability of getting 1 is 1/6 = 0.167

The best prediction possible for the number of times you will roll a one number when a 6-sided die is rolled 12 times = (0.167)¹²

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The calculations for break even point is 5000 customers, and the solution to the system of equations were shown. Mr. Bro's Chick-fil-A franchise would be more profitable as it required less initial borrowing, broke even sooner and generated more income than Ms. Kramer's Popeye's franchise.

To solve this problem, we need to set up a system of equations. Let's use "b" to represent the amount each owner had to borrow to open their restaurant, "x" to represent the number of customers, and "y" to represent the total profit.

For Mr. Bro's Chick-fil-A

After 500 customers: y = -4000

After 3000 customers: y = 1000

We can use these two equations to find the slope of the line: m = (1000 - (-4000)) / (3000 - 500) = 1.8

Using the point-slope form of a line y - (-4000) = 1.8(x - 500)

Simplifying, we get: y = 1.8x - 3400

For Ms. Kramer's Popeye's

After 2000 customers: y = -6000

After 4500 customers: y = 1500

We can use these two equations to find the slope of the line: m = (1500 - (-6000)) / (4500 - 2000) = 1.4

Using the point-slope form of a line: y - (-6000) = 1.4(x - 2000)

Simplifying, we get: y = 1.4x - 5400

Now, we can set the two equations equal to each other to find the break-even point

1.8x - 3400 = 1.4x - 5400

0.4x = 2000

x = 5000

This means that both restaurants need to serve 5000 customers to break even.

To compare the total income of the two restaurants, we can find the y-value for both equations when x = 5000

Chick-fil-A: y = 1.8(5000) - 3400 = $5,000

Popeye's: y = 1.4(5000) - 5400 = $1,000

From this analysis, it is clear that owning Chick-fil-A is more profitable than owning Popeye's.

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When the pretax financial income is negative (indicating a loss), the taxable income will also be negative. This means that the company can use the loss to offset future profits and reduce its tax liability.

To calculate the taxable income (loss) for each year, we need to apply the corresponding tax rate to the pretax financial income (or loss) figures. Here's the breakdown:

2017:

Taxable income = Pretax financial income * Tax rate

Taxable income = $77,000 * 0.25

Taxable income = $19,250

2018:

Taxable income = Pretax financial income * Tax rate

Taxable income = ($38,000) * 0.20

Taxable income = ($7,600)

2019:

Taxable income = Pretax financial income * Tax rate

Taxable income = ($33,000) * 0.20

Taxable income = ($6,600)

2020:

Taxable income = Pretax financial income * Tax rate

Taxable income = $122,000 * 0.20

Taxable income = $24,400

2021:

Taxable income = Pretax financial income * Tax rate

Taxable income = $90,000 * 0.20

Taxable income = $18,000

Please note that when the pretax financial income is negative (indicating a loss), the taxable income will also be negative. This means that the company can use the loss to offset future profits and reduce its tax liability.

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Therefore, the equation in the form of y = mx + b that represents this linear function is: y = -3.2x + 0.1

To write an equation in the form of y = mx + b for a linear function, we need to find the slope (m) and the y-intercept (b).

We can use any two points from the given set of points to find the slope:

m = (y2 - y1) / (x2 - x1)

Let's use the first and second points:

m = (-5.5 - 2.5) / (1.75 - (-0.25))

m = -8 / 2.5

m = -3.2

Now, we can use the slope and one of the points to find the y-intercept:

y = mx + b

-5.5 = (-3.2)(1.75) + b

b = -5.5 + 5.6

b = 0.1

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Shown that if f has no local minima nor local maxima on i, then f is either increasing or decreasing on i.

Since f has no local minima nor local maxima on i, it means that for any point x in i, either f is increasing or decreasing in a small interval around x. In other words, either f'(x) > 0 or f'(x) < 0 for all x in i.

Now suppose there exist two points a and b in i such that a < b and f(a) < f(b). We want to show that f is increasing on i.

Consider the interval [a,b]. By the Mean Value Theorem, there exists a point c in (a,b) such that f'(c) = (f(b) - f(a))/(b - a). Since f(a) < f(b), we have (f(b) - f(a))/(b - a) > 0, which implies f'(c) > 0. Since f'(x) > 0 for all x in i, it follows that f is increasing on [a,c] and on [c,b]. Therefore, f is increasing on i.

A similar argument can be made if f(a) > f(b), which would imply that f is decreasing on i.

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The radius of the lake is approximately 17.89 feet.

To find the radius of the lake, we can use the information given and apply the properties of tangents to circles.

Since point B is the point of tangency, the line segment AB is tangent to the circle. A radius drawn to the point of tangency, in this case from the center of the lake (point O) to point B, will be perpendicular to the tangent line (line AB).

Now, let's use the given measurements. The distance from the duck (point C) to the point of tangency (point B) is 16 feet, and the distance from the duck (point C) to the edge of the lake in the direction of A (line AC) is 8 feet. We can form a right-angled triangle OBC with the given information.

Since OB is perpendicular to AB, we have a right-angled triangle with legs CB and OC. Using the Pythagorean theorem, we can find the length of the hypotenuse, which is the radius of the lake:

OC^2 + CB^2 = OB^2
(8 feet)^2 + (16 feet)^2 = OB^2
64 + 256 = OB^2
320 = OB^2
OB = √320
OB ≈ 17.89 feet

So, the radius of the lake is approximately 17.89 feet.

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The value of   logarithm log5 5/3 is approximately equal to 0.3174.

Using the approximation of ≈ 0.4307 for log5 2 and ≈ 0.6826 for log5 3, we can approximate the value of log5 5/3 by subtracting the two approximations.

log5 5/3 = log5 5 - log5 3 ≈ 1 - 0.6826 ≈ 0.3174


To explain further, logarithms are a way to express the relationship between exponential growth or decay and the input values. In this case, we are using the base of 5 to represent the exponent and trying to find the logarithm of 5/3.

By using the approximation values of log5 2 and log5 3, we can estimate the value of log5 5/3 by subtracting the two approximations. This approximation is useful in situations where we need a quick estimate of a logarithmic function without having to do complex calculations.

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Start with the base graph: y = |x|

Translate the graph one unit to the right: y = |x - 1|

---We use a minus/negative/subtraction sign when dealing with horizontal translations because it is the opposite of the way we want to go. If the translation occurs within parenthesis/absolute value bars, we always do the opposite of what we think we should.

Translate the graph one unit down: y = |x - 1| - 1

---If the translation occurs to the y-value/vertically, we use the expected operation/sign. If the translation occurs outside of parenthesis, we use the same operation/sign as the translation (+ for up, - for down).

Answer: y = |x - 1| - 1

Hope this helps!

Answer:

y=|x-1|-1

Step-by-step explanation:

The function for a v shaped graph is an absolute value function: y=|x|

Subtracting 1 from the absolute value y=|x|, we move the graph 1 unit right of the x axis

Subtracting 1 from the whole equation, y=|x-1|, we move the graph 1 unit down the y axis

So, the equation would be y=|x-1|-1

The scale of the drawing is 1:33 1/3, because the actual size of each grid square in the kitchen floor tile is 33 1/3 times larger than its size in the drawing.

The scale of a architectural drawing represents the proportional relationship between the size of an object in the drawing and its actual size in real life.

In this case, the floor tiles in the Jackson family's kitchen are square with a length of 8 3/4 inches on each side, while each grid square in the drawing measures 1/4 inch on each side.

To determine the scale of the drawing, we need to find the ratio between the actual size of a grid square and its size in the drawing.

Using proportions, we can set up an equation to solve for the scale. Let x be the scale of the drawing, then we have:

8 3/4 inches / (1/4 inch) = x

Simplifying the left side of the equation gives us:

35 inches = x

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To solve the equation 8 x five sixths, we first convert the fraction to a decimal by dividing the numerator (5) by the denominator (6), which gives us 0.83.

We then multiply 8 by 0.83 to get the final answer of 6.64. Therefore, 8 x five sixths = 6.64.

In general, to multiply a whole number by a fraction, we can convert the fraction to a decimal and then multiply the whole number by the decimal.

Alternatively, we can convert the whole number to a fraction with a denominator of 1 and then multiply the two fractions by cross-multiplying and simplifying.

In this case, we could also write 8 as 8/1 and multiply it by 5/6 to get (8 x 5)/(1 x 6) = 40/6, which simplifies to 6 and 4/6 or 6.67 (rounded to two decimal places). However, converting the fraction to a decimal is often simpler and more practical.

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Bob's minimum monthly credit card payment needs to be B) $129.00 to reach his dti goal of 36%.

Bob's total monthly debt payments are $1,947.00 ($1,250.00 mortgage + $349.00 auto loan + $348.00 credit cards). To achieve a dti ratio of 36%, his total monthly debt payments should be no more than $1,728.00 ($4,800.00 * 36%).

Therefore, he needs to reduce his monthly credit card payment by $219.00 ($1,947.00 - $1,728.00). Since his current minimum monthly credit card payment is $348.00, he needs to reduce it to d) $129.00 ($348.00 - $219.00) to reach his dti goal.

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The perimeter of the shaded region is approximately 85.67 cm The area of the shaded region is approximately 91.84 cm² (rounded to the nearest tenth).

To calculate the perimeter and area of the shaded region, we first need to find the radius of each circle.

The larger circle has a diameter of 21 cm, which means its radius is 10.5 cm (half of the diameter). The smaller circle has a diameter of 10 cm, so its radius is 5 cm.

To find the perimeter of the shaded region, we need to add the circumference of both circles and subtract the overlap (the length of the shared segment). The circumference of the larger circle is 2π(10.5) ≈ 65.97 cm, and the circumference of the smaller circle is 2π(5) ≈ 31.42 cm.

To find the length of the shared segment, we can use the Pythagorean theorem. The distance between the centers of the circles is 15 cm (the sum of the radii), so we can form a right triangle with legs of 10.5 cm and 5 cm. Using the Pythagorean theorem, we get:

c² = a² + b²
c² = 10.5² + 5²
c² ≈ 137.25
c ≈ 11.72

So the length of the shared segment is approximately 11.72 cm.

Therefore, the perimeter of the shaded region is approximately 65.97 + 31.42 - 11.72 = 85.67 cm (rounded to the nearest tenth).

To find the area of the shaded region, we need to subtract the area of the smaller circle from the area of the larger circle, and then subtract the area of the overlap (the area of the shared segment).

The area of the larger circle is π(10.5)² ≈ 346.36 cm², and the area of the smaller circle is π(5)² ≈ 78.54 cm².

To find the area of the shared segment, we can use the formula for the area of a sector of a circle:

A = (θ/360)πr²

where θ is the central angle of the sector. In this case, the sector has a central angle of 2cos⁻¹(5/10.5) ≈ 105.2°, so:

A = (105.2/360)π(10.5)²
A ≈ 91.84 cm²

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Answer:

Step-by-step explanation:

tried my best as the first two got me stuck

wouldn't recommend trying my answer and Id wait for another answer

The probability of a passengers waiting at the stop less than 5 minutes and more than 10 minutes is equal to 1/6 and 2/3 respectively.

Probability that the passenger waits less than 5 minutes for the train,

Area under the probability density function (PDF) of the arrival time distribution from 7:00am to 7:05am.

Distribution is uniform,

PDF is a constant function over the interval [7:00am, 7:30am] .

With height 1 / (30 minutes - 0 minutes) = 1/30.

Area under the PDF from 7:00am to 7:05am is,

Probability of waiting less than 5 minutes

= area under PDF from 7:00am to 7:05am

= (1/30) ×(5 - 0) minutes

= 1/6

Probability that the passenger waits less than 5 minutes for the train is 1/6.

Probability that the passenger waits more than 10 minutes for the train is

= Area under the PDF from 7:00am to 7:30am -  area under the PDF from 7:00am to 7:10am.

Area under PDF from 7:00am to 7:30am

= (1/30) × (30 - 0) minutes

= 1

Area under PDF from 7:00am to 7:10am

= (1/30) × (10 - 0) minutes

= 1/3

Area under PDF from 7:10am to 7:30am

= 1 - 1/3

= 2/3

Probability of waiting more than 10 minutes

= area under PDF from 7:10am to 7:30am

= (1/30) × (30 - 10) minutes

= 2/3

Probability that the passenger waits more than 10 minutes for the train is 2/3.

Therefore, the probability of waiting less than 5 minutes and waiting more than 10 minutes is equal to 1/6 and 2/3 respectively.

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The numbers that are less than 3/7 are 1/8 and 3/10, while the numbers that are greater than 3/7 are 1/2 and 2/3. The decimal 0.102, which is equivalent to 51/500 as a fraction, is also less than 3/7.

To determine which of the given numbers are less than 3/7, we can convert them to fractions and compare them to 3/7.

12.5% is equivalent to 0.125 as a decimal or 1/8 as a fraction. To compare 1/8 and 3/7, we can convert them to a common denominator. The least common multiple of 8 and 7 is 56, so we can rewrite 1/8 as 7/56 and 3/7 as 24/56. Therefore, 1/8 is less than 3/7.

0.3 is equivalent to 3/10 as a fraction. To compare 3/10 and 3/7, we can also convert them to a common denominator. The least common multiple of 10 and 7 is 70, so we can rewrite 3/10 as 21/70 and 3/7 as 30/70. Therefore, 3/10 is less than 3/7.

50% is equivalent to 0.5 as a decimal or 1/2 as a fraction. To compare 1/2 and 3/7, we can convert 3/7 to a fraction with a denominator of 2. Multiplying the numerator and denominator of 3/7 by 2 gives us 6/14. Therefore, 1/2 is greater than 3/7.

2/3 is already a fraction, and we can compare it directly to 3/7. Multiplying the numerator and denominator of 3/7 by 3 gives us 9/21, and we can see that 2/3 is greater than 3/7.

0.102 is a decimal that is less than 1, but it can also be written as a fraction. To do so, we can place the decimal over 1 followed by the appropriate number of zeros. This gives us 102/1000, which can be simplified to 51/500. To compare 51/500 and 3/7, we can convert them to a common denominator. The least common multiple of 500 and 7 is 3500, so we can rewrite 51/500 as 357/3500 and 3/7 as 1500/3500. Therefore, 51/500 is less than 3/7.

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Loss on disposal of plant assets = $46400 - $32550

Loss on disposal of plant assets = $13850

Date Account titles and Explanation Debit Credit

Jan. 01 Accumulated depreciation-Equipment $81000

Equipment  $81000

June 30 Depreciation expense (1) $4000

Accumulated depreciation-Equipment  $4000

(To record depreciation expense on forklift)  

June 30 Cash $13000

Accumulated depreciation-Equipment (2) $28000

Equipment  $40000

Gain on disposal of plant assets (3)  $1000

(To record sale of forklift)  

Dec. 31 Depreciation expense (4) $5425

Accumulated depreciation-Equipment  $5425

(To record depreciation expense on truck)  

Dec. 31 Accumulated depreciation-Equipment (5) $32550

Loss on disposal of plant assets (6) $13850

Equipment  $46400

(To record sale of truck)  

Calculations :

(1)

Depreciation expense = (Book value - Salvage value) / Useful life

Depreciation expense = ($40000 - $0) / 5 = $8000 per year

So, for half year = $8000 * 6/12 = $4000

(2)

From Jan. 1, 2019 to June 30, 2022 i.e 3.5 years.

Accumulated depreciation = $8000 * 3.5 years = $28000

(3)

Gain on disposal of plant assets = Sale value + Accumulated depreciation - Book value

Gain on disposal of plant assets = $13000 + $28000 - $40000

Gain on disposal of plant assets = $1000

(4)

Depreciation expense = (Book value - Salvage value) / Useful life

Depreciation expense = ($46400 - $3000) / 8

Depreciation expense = $5425 per year

(5)

From Jan. 1, 2017 to Dec. 31, 2022 i.e 6 years.

Accumulated depreciation = $5425 * 6 years = $32550

(6)

Loss on disposal of plant assets = Book value - Accumulated depreciation

Loss on disposal of plant assets = $46400 - $32550

Loss on disposal of plant assets = $13850

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To solve the given question, we need to use the distributive property and collect like terms. In summary, the distributive property is a useful tool in simplifying expressions.

First, we need to distribute the fraction 4/5 to the expression inside the parenthesis, which gives us 4/5 x 1/4c - 4/5 x 5. Then, we can simplify the expression by multiplying the two fractions and combining the terms. This gives us (1/5)c - 4.

Therefore, the simplified expression is (1/5)c - 4. We can use this expression to evaluate the given expression for any value of c. For example, if c = 15, then the expression becomes (1/5) x 15 - 4 = 3 - 4 = -1.

In summary, the distributive property is a useful tool in simplifying expressions.

By distributing a term to each term inside a set of parentheses, we can collect like terms and simplify the expression. In this case, we used the distributive property to simplify a fraction and a constant and then combined the like terms to obtain the final answer.

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Since t > 0, the time when the particle has a velocity of 20 m/s is approximately t ≈ 4.27 seconds.

A particle has a position function s(t) = t^3 - 4t^2 - 20t + 2 + 20t, t > 0. To find the time when the particle has a velocity of 20 m/s, we first need to find the velocity function by taking the derivative of the position function with respect to time:

v(t) = ds/dt = 3t^2 - 8t - 20.

Now set v(t) equal to 20 and solve for t:

20 = 3t^2 - 8t - 20.

40 = 3t^2 - 8t.

Now solve the quadratic equation for t:

t ≈ 4.27, -3.10.

To find the time when the acceleration is 0, we need to find the acceleration function by taking the derivative of the velocity function with respect to time:

a(t) = dv/dt = 6t - 8.

Now set a(t) equal to 0 and solve for t:

0 = 6t - 8.

t = 8/6 = 4/3.

So, the acceleration is 0 at t = 4/3 seconds.

The variance in acceleration signifies a change in the motion dynamics of the particle. When the acceleration is 0, it indicates that the particle is neither speeding up nor slowing down at that moment, resulting in a constant velocity.

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The inequality which is used to represent normal "temperature-range" for  "human-body", is (d) |t − 98.6| ≤ 1.8.

The "average-temperature" of body is = 98.6° F, and it can vary by 1.8°F.

The inequality |t − 98.6| ≤ 1.8 indicates that the absolute difference between the body temperature and the average temperature is less than or equal to 1.8° F.

This means that the body temperature t can vary within a range of 1.8° F from the average temperature of 98.6° F.

Which means, the temperature cam range from :

⇒ 98.6-1.8 ≤ t ≤ 98.6+1.8,

⇒ 96.8 ≤ t ≤ 100.4;

Therefore, the correct inequality is (d) |t − 98.6| ≤ 1.8.

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The given question is incomplete, the complete question is

The average human body temperature is 98.6° F, but it can vary by as much as 1.8° F. Write an inequality to represent the normal temperature range of the human body, where t represents body temperature.

(a) |t − 1.8| ≥ 98.6

(b) |t − 1.8| ≤ 98.6

(c) |t − 98.6| ≥ 1.8

(d) |t − 98.6| ≤ 1.8

Answer: |t − 98.6| ≤ 1.8

Step-by-step explanation: If takes then takes then takes then takes then takes.

The minimum value of 9y – 45x^2 is 0, which occurs when y = 5x^2/3, so the range of V is all non-negative real numbers:

Range of V: [0, ∞)

To find the domain and range of the function V(x, y) = 9√(9y – 45x^2), we need to consider the values of x and y that make the expression under the square root non-negative, since we cannot take the square root of a negative number.

So, we have:

9y – 45x^2 >= 0

Dividing both sides by 9 and rearranging, we get:

y >= 5x^2/3

This means that the domain of V is all points (x, y) such that y is greater than or equal to 5x^2/3:

Domain of V: {(x, y) | y >= 5x^2/3}

To find the range of V, we note that the square root is always non-negative, so V(x, y) will be non-negative whenever 9y – 45x^2 is non-negative. The minimum value of 9y – 45x^2 is 0, which occurs when y = 5x^2/3, so the range of V is all non-negative real numbers:

Range of V: [0, ∞)

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